In which scenario is the least amount of work done on a crate?
A force of 120 N moves it 25 m.
A force of 115 N moves it 26 m.
A force of 130 N moves it 22 m.
A force of 125 N moves it 27 m.

Answer:

The answer is False......

Answer:

true

it is equal but opposite

The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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Writing in an online journal is different from writing in a paper one in the following way: it is easier to communicate online (option B).

A journal is a newspaper or magazine dealing with a particular subject.

A journal is an efficient medium to communicate the findings or results of an investigation to the public.

However, a journal can be virtual (online) or paper (hard copy). In this 21st century, it is easier to communicate to the masses online because more audience will be captured.

Therefore, writing in an online journal is different from writing in a paper one in the following way: it is easier to communicate online.

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The primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

A primary difference between an electromagnetic wave and a mechanical wave is the medium through which they propagate.

Electromagnetic waves can propagate through a vacuum or empty space without requiring a material medium. They are generated by the oscillation and interaction of electric and magnetic fields.

Examples of electromagnetic waves include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These waves can travel through space, air, or other materials, as they do not rely on physical particles to transmit energy.

On the other hand, mechanical waves require a physical medium to propagate. They are disturbances that travel through a material medium, transferring energy from one location to another. Mechanical waves rely on the interaction and displacement of particles within the medium to transmit energy.

Examples of mechanical waves include sound waves, water waves, seismic waves, and waves on a string. These waves cannot travel through a vacuum as they depend on the physical presence and interaction of particles within the medium.

In summary, the primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

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Answer:

Researchers use a wide range of technologies today to help gather data, depending on the field of study and the type of data they need to collect. Here are some examples:

   Sensors: Sensors are devices that can detect and measure physical quantities such as temperature, pressure, and motion. Researchers use sensors to collect data on the environment, human behavior, and other phenomena.

   Drones: Drones or unmanned aerial vehicles (UAVs) are aircraft that are remotely controlled or can fly autonomously. Researchers use drones to collect data from hard-to-reach or dangerous areas, such as remote forests, volcanoes, or disaster zones.

   Satellites: Satellites are spacecraft that orbit the Earth and can collect data on a wide range of environmental and climatic factors, such as temperature, rainfall, and ocean currents. Researchers use satellite data to study climate change, natural disasters, and other global phenomena.

   Imaging technologies: Imaging technologies such as magnetic resonance imaging (MRI) and computed tomography (CT) scans are used to collect detailed images of the body's internal structures. Researchers use these images to study the human brain, diagnose diseases, and develop new medical treatments.

   Social media and online platforms: Social media and online platforms provide researchers with access to large amounts of data on human behavior, opinions, and attitudes. Researchers use this data to study social trends, political movements, and public opinion.

   Wearable technology: Wearable technology such as fitness trackers and smartwatches collect data on physical activity, heart rate, and other health metrics. Researchers use this data to study human health and behavior.

These are just a few examples of the many technologies researchers use today to help gather data. The use of advanced technology has revolutionized the way researchers collect and analyze data, allowing them to make new discoveries and gain a deeper understanding of the world around us.

Answer:

The correct answer to the following question will be "12.0 N/C".

Explanation:

As we know,

Charged from the inside of the sphere throughout consideration of the electrical field or inside sphere.  

⇒  \(E_0=\frac{KQ}{r_0^{2}}\)

Now,

⇒  \(Q=\frac{E_0r_0^{2}}{k}\)

On putting the values in the above formula, we get

⇒      \(=\frac{6.00\times 80.0}{9\times 10^9}(\frac{10^{-2}}{2})^2\)

⇒      \(=4.267\times 10^{-10} \ C\)

Electric field within the sphere at that same distance of 20.0 cm from either the core.

⇒  \(E_i=\frac{kQr_i}{R^3}\)

On putting the values, we get

⇒      \(=\frac{(9\times 10^9)(4.267\times 10^{-10})(20.0)}{(80.0)^3(\frac{10^{-2}}{1} )^2}\)

⇒      \(=12.0 \ N/C\)

Chemicals that are toxic to life are considered to be poisons. It is frequently specifically defined and used in a variety of scientific and industrial domains. Also, it has a broad connotation and can be used symbolically or informally.

The United States Drug Enforcement Administration (DEA) has five schedules of controlled substances.

The five groups of controlled substances according to the DEA are: narcotics, depressants, stimulants, hallucinogens, and anabolic steroids.

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Answer:

1. No

2. A = Cool. B = Room Temp

3. Unknown

Explanation:

1. No because by definition convection is within a fluid.

2. The colder something is it'll keep getting colder. Hotter one should get to room temperature due to diversion of temps.

The particle displacement in a transverse wave is parallel to the direction of wave propagation.

Transverse waves are those in which the velocity of the wave is perpendicular to the direction in which the medium's particles vibrate.

In longitudinal mechanical waves, the medium's particles move (or oscillate) in cycles that are perpendicular to the way the wave energy moves. Particles in a medium move transverse to the direction the wave's energy is travelling in transverse mechanical waves.

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The equivalent temperature in Celsius scale is (86°F − 32) × 5/9 = 30°C

Take the °F temperature and subtract 32

Multiply this number by 5.

Divide this number by 9 to obtain your answer in °C.

The formula to convert °F to °C is:

T(°C) = (T(°F) - 32) × 5/9

converting 86 degrees Fahrenheit into degrees Celsius:

T(°C) = (86°F - 32) × 5/9

T(°C) = 30 °C

(86°F − 32) × 5/9 = 30°C

When doing the temperature conversion, one quick way to make certain you did the conversion right is to remember Fahrenheit temperatures are higher than the corresponding Celsius scale until you get down to -40°, which is where the Celsius and Fahrenheit scales meet. Below this temperature, degrees Fahrenheit are lower than degrees Celsius.

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Answer: 3m

Explanation: If he is already 2m away from the mirror then if he walks away 1m then it would equal out to 3. You could also add 1 to 2 so you could get the same results.

The magnitude of the masses in planes B and E is 40 kg, and their positions are 120° and 240°, respectively, from the reference point on the shaft to achieve complete rotating balance.

To achieve complete rotating balance, the sum of the moments of the masses in planes A, C, D, B, and E should be equal to zero. Let's determine the magnitude of the masses in planes B and E and their positions.

Consider the moments of the masses in planes A, C, and D. The moment of a mass is given by the product of its magnitude and the sine of the angle between the mass and a reference line. The moments of masses A, C, and D are:

Moment of A = 50 kg * sin(0°) = 0 kg·m,

Moment of C = 40 kg * sin(90°) = 40 kg·m,

Moment of D = 80 kg * sin(135°) = -80 kg·m.

Since the moments of A, C, and D are known, we can use the principle of complete rotating balance to determine the magnitude and position of the masses in planes B and E.

Let's assume the magnitude of the masses in planes B and E as M. The moments of masses B and E can be represented as:

Moment of B = M * sin(120°) = M * √(3)/2,

Moment of E = M * sin(240°) = -M * √(3)/2.

Using the principle of complete rotating balance, the sum of the moments should be zero. Thus, we have:

Moment of A + Moment of C + Moment of D + Moment of B + Moment of E = 0.

0 + 40 kg·m + (-80 kg·m) + M * √(3)/2 + (-M * √(3)/2) = 0.

Simplifying the equation:

40 kg·m - 80 kg·m + M * √(3)/2 - M * √(3)/2 = 0,

-40 kg·m = 0.

From the equation, we can deduce that M must be equal to 40 kg to satisfy the condition of complete rotating balance.

Finally, we determine the positions of masses B and E. Since planes A, C, D, B, and E are equidistant from one another, and the angle between A and C is 90°, we divide the circle into 360°/5 = 72° sections. Thus, the positions of masses B and E are:

Position of B = 0° + 2 * 72° = 144°,

Position of E = 0° + 4 * 72° = 288°.

Therefore, the magnitude of the masses in planes B and E is 40 kg, and their positions to put the shaft in complete rotating balance are 144° and 288°, respectively, from the reference point on the shaft.

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Answer:

10.5 g/cm^3

Explanation:

d = mass/volume

V= 1cm x 3cm x 7cm = 21 cm^3

d = (220,5g) / (21cm^3)

d = 10.5 g / cm^3

The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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From the diagram, the angular speed will increase clockwise, the sign of the angular acceleration will be negative and the direction of rotation will be clockwise direction and the sign of the angular acceleration is negative. The correct answer is option B

Given that two objects of masses m1 and m2 are attached to a seesaw. The seesaw is made of a bar that has length l and is pivoted so that it is free to rotate in the vertical plane without friction. Counterclockwise is considered the positive rotational direction.

If m1 is 24 kilograms, m2 is 12 kilograms, and mbar is 10 kilograms, The moment of object m1 will be equal to the moment of object m2 without the Mbar

Let assume that the length L of the seesaw is 9 cm.

Anticlockwise moment = 24 x 9/3 = 72Nm

Clockwise moment = 12 x 2(9/3) = 72 Nm

With the consideration of mass of the bar Mbar, this will add to clockwise moment of the seesaw.

Therefore, the direction of rotation will be clockwise direction.

Angular acceleration is positive when object is speeding up and negative when slowing down. Also, angular acceleration is positive when speed increases in an anticlockwise direction and negative when speed increases in the clockwise direction.

From the diagram, since the angular speed increase clockwise, the sign of the angular acceleration will be negative.

We can conclude that the direction of rotation will be clockwise direction and the sign of the angular acceleration is negative.

The correct answer is option B

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Answer:

B, and D

Explanation:

The two benefits of this model is it specify a process that is very complex. It can represent changes that occur very slowly. Thus option B and D is correct.

The water cycle is defined as a cycle of events that involves precipitation as rain and snow, drainage in streams and rivers, and return to the atmosphere by evaporation and transpiration. Water moves through this cycle between the earth's oceans, atmosphere, and land.

It can also be defined as the route all water takes as it travels around Earth in various conditions.

There are basically six stages of water cycle.

Thus, the two benefits of this model is it specify a process that is very complex. It can represent changes that occur very slowly. Thus option B and D is correct.

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Answer:

F' = 162 units

Explanation:

The gravitational force of attraction between the two objects is given by Newton's Gravitational law through the following formula:

\(F = \frac{Gm_{1}m_{2}}{r^{2}}\\\\\)

where,

F = gravitational force = 18 units

G = Gravitational Constant

m₁ = mass of object 1

m₂ = mass of object 2

r = distance between objects

Therefore,

\(18 = \frac{Gm_{1}m_{2}}{r^{2}}------ eqn (1)\\\\\)

Now, if we change the value of distance to one-third of original value, then:

r' = r/3

\(F' = \frac{Gm_{1}m_{2}}{(\frac{r}{3})^{2}}\\\\F' = (9)(\frac{Gm_{1}m_{2}}{r^{2}})\)

using eqn (1):

F' = 9(18 units)

F' = 162 units

An astronaut measure the period of a mass spring system on Earth.

The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.

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The law of conservation of mass as it states shows that mass is conserved at the end of chemical reaction because it changes from one state to another.

Mass is defined as the fundamental property of matter which can be measured in Kilograms (kg).

To explain how mass is being conserved, water cycle is used as an example.

The water cycle follows the conservation of mass because just like matter, it changes its state but not destroyed.

It can be observed that water can change its state from solid, liquid or gas in various phase transitions. These include the following:

Sublimation: Water changes from solid to gas

Deposition: Water changes from gas to solid.

Condensation: Here, water chanhes from Gas

to liquid.

Evaporation: Here, water changes from Liquid to gas.

Melting: Here, water changes from Solid to liquid.

Freezing: Here, water changes from liquid to solid.

Therefore, the water cycle follows the conservation of mass because just like matter, it changes its state but not destroyed.

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Answer:

The law of conservation of mass as it states shows that mass is conserved at the end of chemical reaction because it changes from one state to another.

Explanation:

Answer:

C.

Explanation:

Answer:A

Explanation:ap3x

Answer:

W = F * S = 300 N * 30 m = 9000 Joules

This is the work out of the system regardless of how the pulleys are arranged

Conservation of energy tells that

Work Out = Work In - Work done by friction

So Work In = 9000 J + 2000 J = 11000 J      The work input to the system

Answer:

Explanation:

We are expected to solve for the velocity with no slip condition

we know that the expression that relate coefficient of friction and velocity is given as

μs = v^2/rg

Given

coefficient of friction μs = 0.3

radius r= 0.15

assume g=9.81m/s^2

substituting into the expression we have

0.3= v^2/0.15*9.81

v^2=0.3*0.15*9.81

v^2=0.44145

v=√0.44145

v=0.66

therefore the velocity is 0.66m/s

Using the dimensional analysis, the values of x, y and z are 0, 0, and -1/2 respectively.

Starting with the given equation:

T = Kdx^r s^z

We can find the dimensions of each term:

[T] = T

[d] = M L⁻³

[r] = L

[s] = M T⁻²

[K] = 1 (dimensionless constant)

Now we can equate the dimensions of both sides of the equation:

[T] = [K] [d]^x [r]^y [s]^z

Simplifying:

[T] = [M]^x [L]^{-3x} [L]^y [M]^{z} [T]^{-2z}

Equating dimensions, we get the following system of equations:

x = 0

-3x + y = 0

z - 2z = 1

Solving for x, y, and z:

x = 0

y = 0

z = -1/2

Therefore, the values of x, y, and z are 0, 0, and -1/2, respectively.

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Answer:

people who had a hard time to help other people because they feel that if they help

that the work of the person is much harder than his own work

Individuals who find it difficult to help others because they believe that if they do, the person's job will be much tougher than their own.

A group of people working together to achieve a shared purpose.

Collaboration, cooperation, and coordination are all words that come to mind when thinking of teaming.

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Answer:

10 N to the left.

Explanation:

Since the forces are acting in opposite directions, you need to calculate the difference.

20 N - 10 N = 10 N

More force is being exerted to the left. Therefore, the net force is 10 N to the left.

Answer:

a = -1/10 m/s2

Explanation:

F = m*a

-10N = 100*a

a = -10/100

a = -1/10 m/s2

Answer:

-10

Explanation:

What you had to do to get this answer was first line up your force,mass,and acceleration.Then,put your 100kg on your m=,then put you -10nin your force f=,from there you have to divide than multiply because of your negative.

F=-10N

M=100kg

A=-10

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The momemtum is not conserved in scenario d.

Momentum of an object is the product of its mass and velocity.

To determine in which of the conditions in which momentum is not conserved, we need to know the law of conservation of momentum.

The law of conservation of momentum states that as long as no external force acts on a system, the total momentum of the system of two colliding objects is conserved.

If we consider scenarios a, b and c, we see that no external force acts on the system of two objects in the three instances so, the total momentum is conserved.

In scenario d, an external force acts on the system, so total momentum is not conserved since according to the law of conservation of momentum, total momentum is only conserved when there is no external force acting on a system.

So, the momemtum is not conserved in scenario d.

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