Answer:
Answer:
from right
Explanation:
right
Answer:
Left
Explanation:
Finger Grasp Process thingy
A magnetic field can deflect a beam of electrons. What is the sign of the work done on the electrons by magnetic field
Answer:
That rule describes how a charged particle (our electron) moving in a magnetic field will be deflected by that field at a right angle to both the field and to the direction of the particle. ... The electrons in the cathode rays would deflect toward the positively charged plates, and away from the negatively charged plates.
Explanation:
ur welcome
The frequency of a wave is 2 Hz and the wavelength is 4 m. What is the wave speed?
Answer:
4/2=2m/s
Explanation:
Which type of current occurs because of differences in salinity and temperat
deep water current
surface current
Answer:
What is deep water current
Explanation:
When the water molecules of the ocean become heated, they expand. ... Since warmer water thus can hold more salt and other molecules than cold water; it can have a higher salinity. To relate this to ocean currents, the higher the salinity of ocean water, the more dense it becomes.
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Why is it that a whole orange will float on water but a peeled one will sink
The peeled orange is much heavier than the water and hence it sinks and the whole orange is float as it is less denser than water.
The objects that float or sink depend on the buoyancy. Buoyancy is the tendency of the object to float in the liquids or fluids. When an object is immersed in a fluid, the object experience an upward force called buoyancy.
When the object sinks, its weight is less than the upward force or buoyancy. When the object floats, its weight is greater than the upward force.
The whole orange has a rind and the rind have tiny air pockets. When the orange is immersed in water, the water enters into the tiny air pockets and makes the orange less weight than the upward force and hence it floats.
When the rind is removed from the orange, the water can not enter the orange. Thus, the weight of the orange is greater than the upward force. Hence, it sinks.
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the reason the sun's radiant energy is of shorter wavelengths than the earth's is because the sunquestion 12 options:is an energy source while the earth is primarily an energy receiver.all of thesehas a higher temperature than the earth.has much more internal energy
The sun's radiant energy is of shorter wavelengths than the earth's is because the sun has higher temperature than the earth.
What is Planck's curve ?As the temperature of a blackbody radiator increases, the total energy emitted increases and the peak of the radiation curve shifts to shorter wavelengths. Calculating the maximum from the Planck radiation formula shows that the product of peak wavelength and temperature is constant.
Because the Sun is hotter than the Earth, it emits radiation at shorter wavelengths, and the hot Planck curve peaks at shorter wavelengths. For this reason, the Earth's radiation is called long-wave, and the Sun's is called short-wave.
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The acceleration due to gravity of Mars is 3.71 m/s2. What is the weight of the Curiosity rover on Mars?
Two dimensions. In Figure 13-34, three point particles are fixed in place in an xy plane. Particle A has mass mA = 3 g, particle B has mass 2.00mA, and particle C has mass 3.00mA. A fourth particle D, with mass 4.00mA, is to be placed near the other three particles. What (a) x coordinate and (b) y coordinate should particle D be placed so that the net gravitational force on particle A from particles B, C, and D is zero (d = 22 cm)?
To make the net gravitational force on particle A from particles B, C, and D zero, particle D should be placed at the x coordinate of -11 cm and the y coordinate of 0 cm.
The net gravitational force on particle A from particles B, C, and D can be calculated using the formula for gravitational force:
F = G * (m₁ * m₂) / r²
Where F is the gravitational force, G is the gravitational constant, m₁ and m₂ are the masses of the two particles, and r is the distance between them.
Since the net gravitational force on particle A should be zero, we can set up an equation:
FAB + FAC + FAD = 0
Using the given information that the distance d is 22 cm and the masses of particles B, C, and D are known in terms of mA, we can calculate the x and y coordinates for particle D.
By applying the principle of superposition, we can calculate the net gravitational force on particle A from particles B, C, and D at the x coordinate and y coordinate of particle D. By adjusting the position of particle D, we can find the coordinates that result in a net gravitational force of zero on particle A.
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The speed of sound in air at 20 C is 344m/s.
(A)What is the wavelength of a sound wave with a frequency of 784 Hz, corresponding to the note G5on a piano?
(B)How many milliseconds does each vibration take?
(C)What is the wavelength of a sound wave one octave higher than the note in part A?
A) The wavelength of the sound wave corresponding to the note G5 on a piano is approximately 0.439 meters.
B) Each vibration of the sound wave takes approximately 1.28 milliseconds.
C) The wavelength of the sound wave one octave higher than the note in part A is approximately 0.219 meters.
(A) The formula to calculate the wavelength (λ) of a sound wave is:
λ = v/f
where v is the speed of sound and f is the frequency of the sound wave.
Substituting v = 344 m/s and f = 784 Hz, we get:
λ = 344 m/s / 784 Hz ≈ 0.439 m
(B) The time period (T) of a sound wave is the time taken for one complete vibration or cycle. It is related to the frequency (f) by the formula:
T = 1/f
Substituting f = 784 Hz, we get:
T = 1 / 784 Hz ≈ 0.00128 seconds
To convert seconds to milliseconds, we multiply by 1000:
T ≈ 1.28 milliseconds
(C) One octave higher than the note G5 on a piano would have a frequency of 1568 Hz (i.e., double the frequency of G5). Using the same formula as in part A, we can calculate the wavelength of the corresponding sound wave:
λ = 344 m/s / 1568 Hz ≈ 0.219 m
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A student slides a rock along the flat surface of a frozen pond. The rock starts to slow down after several seconds. Construct an explanation using Newton's Laws that describes why the rock begins to decelerate.
Answer:
When the student slides the rock along the flat surface of the frozen pond, according to Newton's second law of motion, the rock is given an initial velocity of motion. According to Newton's first law of motion, the rock will continue to slide indefinitely unless it is slowed or stopped by an opposite force. According to Newton's third law, the rock experiences a reaction force from the force of friction of the ice which slows it down at a rate given by Newton's second law of motion and the rock is seen to decelerate
Explanation:
Newton's first law of motion, states that an object will remain at rest or maintain a uniform motion in a straight line, unless impressed upon by an external force
Newton's second law states that an applied force is equal to the rate of change of momentum it produces
Newton's third law states action and reaction are equal and opposite.
Which of the best describes a solution
A constant force of 12 N acts for 5 s on a 5 kg object. What is the change in object’s velocity?
Answer:
"solve: given that F -12 N and time 4 seconds and let we have to find out the P.
F = 12 N
t = 4 s
p = ?
F = m×( v - u ) / t
12 = m×v / 4
m×v = 12× 4
p = 48 kg m/s
Linear momentum will be 48 kg m/s.
Explanation:
You pull a sled with a package on it across a snow-covered flat lawn. If you
apply a force of 65.1 N to the sled, it accelerates at 1.24 m/s2. What is the
combined mass of the package and the sled? (Assume there is no friction.)
Answer:52.5
Explanation:
You pull a sled with a package on it across a snow-covered flat lawn. If you apply a force of 65.1 N to the sled, it accelerates at 1.24 m/s2. The combined mass of the package and the sled m = 52.50 kg
The given data to find Mass,
The force applied to the sled, F = 65.1 N
Acceleration of the sled, a = 1.24 m/s²
What is force?Forces are defined by both strength and direction.
Force is a vector quantity. It is a quantity that is described by Magnitude and Direction. The strength of a force is its magnitude and the direction, well it is the direction the magnitude is applied on the object.
We need to find the combined mass of the package and the sled. Let it is m. Using definition of force as follows :
F = ma
m = F/a
m = 65.1 /1.24
Mass, m = 52.5 Kg.
If you apply a force of 65.1 N to the sled, it accelerates at 1.24 m/s2. The combined mass of the package and the sled m = 52.50 kg
Hence, Option C is the correct answer.
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Which best describes the surface of a concave mirror? It is flat. It is textured. It curves outward. It curves inward.
The concave mirror is a spherical-shaped mirror that has an inner curved surface. Hence, option (4) is correct.
What is a concave mirror?
The concave mirrors are spherical-shaped mirrors that are painted on the outward surface. It is also known as the converging mirror, having the recessed inner reflecting surface.
The concave mirrors are generally used for the purpose to focus the light. For that, they might have a reflecting surface, curved inwards, and the reflection of light is limited to the single focal point. The reflecting surface of the concave mirror has its vertex or midpoint lying farther away from the objects than the edges.Thus, we can conclude that the surface of the concave mirror is curved inward. Hence, option (4) is correct.
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Answer:
D. It curves inward
Explanation:
As a vehicle approaches a stop sign, the driver applies the brakes and brings the vehicle to a stop. How is this action explained using Newton’s Second Law?
HELP ASAP PLEASE ! Which terms best describe what happened to the light in the image below?
Select all that apply.
A dispersion
B reflection
C diffraction
D refraction
Answer: A) and D)
Explanation:
hello I need help with this question. I started it but am confused
Given:
The mass on the table is,
\(m=1.0\text{ kg}\)The hanging mass is,
\(M=1.5\text{ kg}\)THe coefficient of friction is,
\(\mu=0.20\)let the acceleration of the whole system is a (for the hanging mass it is downward and for the mass on the table it is rightward). the tension towards The fixed point of the pulley is T.
we can write,
\(Mg-T=Ma\ldots.\ldots..\ldots\ldots.(1)\)\(ma=T-\mu mg\ldots.\ldots.\ldots..\ldots..(2)\)Adding these equations we get,
\(\begin{gathered} (M+\mu m)g=(M+m)a \\ a=\frac{(M+\mu m)g}{M+m} \end{gathered}\)Substituting the values we get,
\(\begin{gathered} a=\frac{(1.5+0.20\times1.0)9.8}{1.5+1.0} \\ =6.67m/s^2 \end{gathered}\)Hence the acceleration is 6.66 m/s^2.
Look at the circuit diagram. Which of these components is part of the circuit?
A. voltmeter
B. switch
C. AC power source
D. capacitor
Answer:
b ac power source
Explanation:
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Answer: B.
switch
Explanation: edmentum
Imagine that someone is walking across a carpeted room and then touches a metal doorknob. Describe what happens when a doorknob is touched if there’s a buildup of static electricity.
Answer: if the door knob is metal the static electricity will exit your body, but shock you in the process
Explanation:
A freight train has a mass of 270, 700 kg and has an acceleration of 40 m/s2. How much force is acting on the train? Formula:
Answer:
1.08 x 10⁷N
Explanation:
Given parameters:
Mass of freight train = 270700kg
Acceleration = 40m/s²
Unknown:
Force acting on the train = ?
Solution:
From Newton's second law of motion, we know that:
Force = mass x acceleration
So;
Force = 270700 x 40 = 1.08 x 10⁷N
A student records the feather colors and beak shapes of every bird observation in a park. What kind of data is the student recording? A. Qualitative B. Quantitive C. Empirical D. Theoretical
Answer:
The correct option is C
Explanation:
Emperical data is a data that is collected or recorded during the course of an experiment by means of observation. In the case of the question, all the birds that came to the park were said to have had there feather colors and beak shapes recorded during the course of a student's observation.
Answer:
A qualitive
Explanation:
What happens when light is allowed to pass through a suspension
Answer:
When light is passed through a true solution, the dissolved are too small to deflect light. suspensions may scatter light, but if the number of suspended particles is sufficiently large, the suspension may simply be opaque, and the light scattering would not occur.
a mass weighing stretches a spring . suppose the mass is displaced an additional in the positive (downward) direction and then released with an initial upward velocity of . the mass is in a medium, that exerts a viscuouse resistance of when the mass has a velocity of . assume is the gravitational acceleration. (a) find the mass ( in ). (b) find the damping coefficient (in ). (c) find the spring contant (in ). (d) set up a differential equation that describes this system. let to denote the displacement, in feet, of the mass from its equilibrium position, and give your answer in terms of . (e) enter the initial conditions: , (f) is this system under damped, over damped, or critically damped?
The mass : 0.125 lb⋅\(s^2\)/ft.
The damping coefficient : 3 lb⋅s/ft.
The spring constant : 2 lb/ft.
The initial conditions are given as x(0) = 20 in = 20/12 ft and dx/dt(0) = 4 ft/s.
(a) Finding the mass:
The mass can be calculated using the equation m = weight / g, where weight is given as 4 lb and g is the gravitational acceleration of 32 ft/\(s^2\). Therefore, m = 4 lb / (32 ft/\(s^2\)) = 0.125 lb⋅\(s^2\)/ft.
(b) Finding the damping coefficient:
The damping coefficient, denoted by c, can be calculated using the relationship between the viscous resistance and the damping coefficient. In this case, the damping coefficient c = viscous resistance / velocity. Given that the viscous resistance is 3 lb and the velocity is 4 ft/s, we have c = 3 lb⋅s/ft.
(c) Finding the spring constant:
The spring constant, denoted by k, can be calculated using Hooke's Law: k = force / displacement. The force exerted by the spring is equal to the weight of the mass, which is 4 lb. The displacement is given as 24 in = 2 ft. Therefore, k = 4 lb / 2 ft = 2 lb/ft.
(d) Setting up the differential equation:
The differential equation that describes the system can be set up using Newton's second law: m(\(d^{2x}\)/\(dt^2\)) + c(dx/dt) + kx = 0. Substituting the known values, we have (0.125 lb⋅\(s^2\)/ft)(\(d^{2x}\)/\(dt^2\)) + (3 lb⋅s/ft)(dx/dt) + (2 lb/ft)x = 0.
(e) Initial conditions:
The initial conditions are given as x(0) = 20 in = 20/12 ft and dx/dt(0) = 4 ft/s.
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The complete question is : A mass weighing 4 lb stretches a spring 24 in. Suppose the mass is displaced an additional 11 in in the positive downward) direction and then released with an initial upward velocity of 4 ft/s. The mass is in a medium, that exerts a viscuouse resistance of 3 lb when the mass has a velocity of 4 ft/s. Assume g=32 ft/s is the gravitational acceleration (a) Find the mass m (in lb - s2 /ft). m = (b) Find the damping coefficient c in lb.s/ft). c= (c) Find the spring contant k (in lb/ft). ka (d) Set up a differential equation that describes this system. Let to denote the displacement, in meters of the mass from its equilibrium position, and give your answer in terms of ,',". (e) Enter the initial conditions: 20 = 2'0) =
What is the illuminance on an object that is 1.50 m away from a light source with a luminous flux of 665 lumens?
The illuminance on the object is approximately 23.52 lux.
The illuminance on an object can be calculated using the formula:
Illuminance = Luminous Flux / Area
In this case, the luminous flux is given as 665 lumens. To find the illuminance, we need to determine the area.
Since the object is 1.50 m away from the light source, we can imagine a sphere centered on the light source with a radius of 1.50 m. The surface area of this sphere can be calculated using the formula:
Surface Area = 4πr²
Plugging in the value of the radius (1.50 m) into the formula, we get:
Surface Area = 4π(1.50)² = 4π(2.25) ≈ 28.27 m²
Now we can calculate the illuminance:
Illuminance = Luminous Flux / Area = 665 lumens / 28.27 m² ≈ 23.52 lux
So, the illuminance on the object that is 1.50 m away from the light source with a luminous flux of 665 lumens is approximately 23.52 lux.
The illuminance on the object is approximately 23.52 lux.
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on the ride spindletop at the amusement park six flags over texas, people stood against the inner wall of a hollow vertical cylinder with radius 2.5 m . the cylinder started to rotate, and when it reached a constant rotation rate of 0.60 rev/s , the floor dropped about 0.5 m . the people remained pinned against the wall without touching the floor.
The minimum value of the coefficient of static friction for which the person does not slide is 0.276.
The individuals positioned against the wall do not move while the cylinder rotates. So, we can observe the balanced forces operating on the individual's body if we make a free-body diagram of the person.
Given that, the rate of rotation = 0.60 rev/s
The radius of the cylinder = 2.50m
Friction against the person's body = µN
\(F_{friction}\) = µN
where N is the normal reaction and µ is the coefficient of static friction.
Also, the gravitational force acting against the body = mg
\(F_{gravitation\\}\) = mg
where m is the mass of the body and g is the acceleration due to gravity.
Therefore,
µN = mg
µ = mg/N
The centrifugal force acting on the person's body = m\(\frac{mg}{mω²r}\)
Since normal force is balanced by the centrifugal force,
N = mω²r
Substituting the value of N in the above equation,
µ = mg/mω²r
= g/ω²r
= 9.81/2π × Revolutions × 2.5
= 9.81/2π × 0.6 × 2.5
= 0.276
Therefore, The minimum value of the coefficient of static friction for which the person does not slide is 0.276.
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A 235 gg mass attached to a horizontal spring oscillates at a frequency of 1.60 HzHz. At tt = 0 ss, the mass is at xx = 6.20 cmcm and has vxvx = -40.0 cm/scm/s.
Determine the period.
Determine the angular frequency.
Determine the amplitude.
Determine the phase constant.
The period (T) of the oscillation is approximately 0.625 seconds.
The angular frequency (ω) of the oscillation is approximately 10.03 radians per second.
The amplitude (A) of the oscillation is 6.20 cm.
The phase constant (φ) of the oscillation is π radians (or 180 degrees).
To find the period (T) of the oscillation, we use the formula:
T = 1 / frequency
Frequency (f) = 1.60 Hz
Substituting the value:
T = 1 / 1.60 Hz
T ≈ 0.625 s
Therefore, the period of the oscillation is approximately 0.625 seconds.
To determine the angular frequency (ω), we use the formula:
ω = 2πf
Given:
Frequency (f) = 1.60 Hz
Substituting the value:
ω = 2π * 1.60 Hz
ω ≈ 10.03 rad/s
Therefore, the angular frequency of the oscillation is approximately 10.03 radians per second.
To determine the amplitude (A), we use the given position (x) at t = 0:
x = 6.20 cm
Therefore, the amplitude of the oscillation is 6.20 cm.
To determine the phase constant (φ), we use the given velocity (vx) at t = 0:
vx = -40.0 cm/s
The phase constant is related to the initial phase of the motion. Since the velocity is negative at t = 0, it suggests that the object is moving in the negative x-direction. As a result, the phase constant (φ) is π radians (or 180 degrees).
Therefore, the phase constant of the oscillation is π radians (or 180 degrees).
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A capacitor is formed from two identical conducting parallel plates separated by a distance d One plate is charged Q. the other plate is charged -Q. A dielectric slab fills the space between the two plates. Where is the energy stored in this capacitor? A) On the outsides of the metal plates. B) On the insides of the metal plates. C) On the outside su face of the dielectric slab D) Inside the dielectric slab,
The energy in a capacitor is stored inside the dielectric slab. Therefore, the correct answer is D) Inside the dielectric slab.
A capacitor is a device that stores electrical energy in an electric field. It is made up of two conductive plates separated by a dielectric material. When a voltage is applied across the plates, an electric field is created between them, and the energy is stored in this field.
In the case of the capacitor described in the question, the energy is stored inside the dielectric slab that fills the space between the two plates. This is because the electric field is strongest in the region between the plates, where the dielectric material is located. The energy is stored in the form of an electric field within the dielectric material, and this is where the energy is stored in the capacitor.
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suppose that 15 years from now, dr. currie directly images an earth-like planet around tau ceti, a nearby star with a mass equal to that of the sun and concludes that its semimajor axis is about 1.4 au. according to kepler's 3rd law of motion, the planet's orbital period is closest to ...
Super-Earth-sized exoplanet Tau Ceti e revolves around a G-type star. It is 0.538 AU away from its star, with a radius of 0.538 AU, has a mass of 3.93 Earth masses, has a mass of 3.93 Earth masses, has a mass of 3.93 Earth masses, has a mass 3.93 In 2017, word of its finding spread.
What's a planet, exactly?A celestial body that (a) circles around the Sun, (b) has sufficient mass to dissipate rigid body forces and assume a hydrostatic equilibrium shape (nearly round), and (c) has cleared the space inside and surrounding its orbit is considered a planet.The distance a planet is from the Sun tends to result in colder surface temperatures on planets. The exception is Venus, which is the hottest planet in our solar system due to its close closeness to the Sun and its thick atmosphere. The results of calculations and simulations show that Mercury is, on average, the planet that is closest to Earth and to every other planet in the solar system.To learn more about planet, refer to:
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Calculate the potential energy of a 1200 kg boulder on a cliff 45 m above the ground.
Explanation:
Given mass of the object is 1200kg and it's placed at a height of 45m above the ground. As we know that potential energy is ,
\(\longrightarrow PE = mgh \)
where,
m is the mass of the body .g is acceleration due to gravity.h is the height above the ground .Substituting the respective values ,
\(\longrightarrow P.E. = 1200kg * 10m/s^2* 45m\)
Multiply ,
\(\longrightarrow P.E. = 540000J \)
Hence the potential energy is 540000J .
I hope this helps.
The magnitude of the acceleration of a planet in an orbit around the sun is proportional to
A. The mass of the planet
B. The mass of the sun
C. The reciprocal of the distance between the planet and the sun
D. The product of mass of the planet and mass of the sun
C. The magnitude of the acceleration of a planet in an orbit around the sun is proportional to the reciprocal of the distance between the planet and the sun.
The reciprocal of the distance between the planet and the sun ,This is known as Kepler's third law. The farther a planet is from the sun, the weaker the gravitational force between them and the slower the planet's acceleration.
The magnitude of the acceleration of a planet in an orbit around the sun is proportional to: C. The reciprocal of the distance between the planet and the sun.
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A truck has a momentum of 5,000 units. What happens to the truck's momentum if the mass is cut in half?
If the truck is moving with the same velocity, if the mass is cut in half then the momentum of the truck will also reduce to half.
What is momentum?The momentum of a body can be described as the function of the object's mass and velocity. Momentum (p) can be determined as kinetic energy and is the product of velocity (v) and mass (m).
The momentum of an object can be determined from the mathematical formula:
p = m×v
The momentum of an object is conserved and can be equal to zero if the object is stationary and its velocity of an object is zero.
Given, the truck has a momentum, p = 5000 units
Given that the mass of the truck is reduced to half. Then the new mass of the truck is equal m/2. If the truck is still moving with the same velocity then the momentum is equal to:
p' = m' ×v
p' = (m/2) ×v
p' = mv/2
p' = p/2
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