In what direction and at what point does the buoyant force on a body due to liquid act?

Answers

Answer 1

At the center of buoyancy, the buoyant force operates in an upward, vertical direction.

What kind of force is buoyant, for instance?

Here are a few real-world instances of the buoyant force. Iceberg drifting on the sea, a boat traveling down a river An individual wearing a life jacket floating in the water, a ship sailing the seas, a helium balloon soaring into the sky, etc. The density has a direct relationship with the buoyant force.

What generates the force of buoyancy?

The fluid's pressure on the object is what creates the buoyant force. The net upward force results from the fact that the pressure on the bottom of an item is always greater than the force on the top since pressure rises as depth increases. Whether an object sinks or floats, the buoyant force always exists.

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Related Questions

a mass of 20kg is held stationary by a rope passing over a frictionless pally. what is the tension T in the rope?

Answers

The tension in the rope is 196.2 N. The rope is exerting a force of 196.2 N on the object to keep it stationary.

Assuming that the mass is not accelerating, the tension in the rope must be equal to the weight of the mass. The weight of the mass can be found using the formula:

weight = mass x acceleration due to gravity

where acceleration due to gravity is approximately 9.81 m/s².

Therefore, the weight of the mass is:

weight = 20 kg x 9.81 m/s² = 196.2 N

Since the mass is held stationary, the tension in the rope must be equal to the weight of the mass, which is 196.2 N. So the tension T in the rope is 196.2 N.

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61. A telescope can be used to enlarge the diameter of a laser beam and limit diffraction spreading. The laser beam is sent through the telescope in opposite the normal direction and can then be projected onto a satellite or the Moon. (a) If this is done with the Mount Wilson telescope, producing a 2.54-m-diameter beam of 633-nm light, what is the minimum angular spread of the beam

Answers

Answer:

8.87

Explanation:

Which scientist first proposed physical laws to mathematically describe the effect of forces on the motions of bodies?

Answers

Answer:

Sir Issac Newton

Explanation:

These are the effects of gravity.

Is lava a matter if yes how if not how

Answers

Answer:

Yes, lava is a liquid, that cools into rock, which is a solid.

A 0.0780 kg lemming runs off a
5.36 m high cliff at 4.84 m/s. What
is its potential energy (PE) when it
lands?

Answers

The potential energy of the lemming when it lands is 0.9108672 J.

To determine the potential energy (PE) of the lemming when it lands, we need to consider the conservation of energy. The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.

Given:

Mass of the lemming (m) = 0.0780 kg

Height of the cliff (h) = 5.36 m

First, let's calculate the potential energy when the lemming is on the cliff. Using the given formula, we have:

PE = mgh

PE = 0.0780 kg * 9.8 m/s² * 5.36 m

PE = 0.413616 J

Next, we need to determine the final kinetic energy of the lemming just before it lands. We can use the equation for kinetic energy (KE) given by KE = (1/2)mv², where v is the velocity of the lemming.

Given:

Velocity of the lemming (v) = 4.84 m/s

Calculating the kinetic energy, we have:

KE = (1/2) * 0.0780 kg * (4.84 m/s)²

KE = 0.9108672 J

According to the conservation of energy, the potential energy at the top of the cliff is equal to the kinetic energy just before landing.

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Mr.lizard limps 40 meters in 8 seconds. What is his speed?

Answers

Mr.Lizard limps 5 meters per sec
So u divid 40/8 which gives u 5

The "seeing" ability, or resolution, of radiation is determined by its wave length

The mass of an electrons is 9.10939 * 10^-31 kg and Planck's constant is 6.62607 * 10^-34 Js

If the size of an atom is an the order of 0.08 nm, how fast must an electron travel to have a wavelength small enough to "see" an atom? Answer in the units of m/s

Answers

ANSWER: 0.08nm !
Have a good night/day

density is never uniform even when the cross sectional area is uniform and the potential difference across the conductor is maintained

Answers

No, density is not always uniform even when the cross sectional area is uniform and the potential difference across the conductor is maintained.

What is conductor?

A conductor is a material or device that allows electric current to pass through it. It is also used to transmit electric energy from one point to another. Conductors are commonly made of materials such as copper, aluminum, silver, and gold, and are used in electric circuits, wiring, and power grids. Conductors are essential for the transmission of electric power, and are used in a variety of applications, from electric motors and transformers to solar cells and electrical appliances. Conductors also act as a medium for transmitting electric signals, such as radio waves, and are used in telecommunications and broadcasting.

This is because density is a measure of the number of particles per unit volume, which can be affected by temperature and pressure. As the temperature or pressure changes, the number of particles contained in a given volume will also change. This means that even if the cross sectional area and potential difference across the conductor remain constant, the density of particles will not necessarily be uniform.

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Please help me in questions 4_5_6

Please help me in questions 4_5_6

Answers

Yes, the force of the engine does work on the car as it accelerates the car forward. Work is defined as the transfer of energy that occurs when a force is applied over a distance, and in this case, the force of the engine is causing the car to move, so it is doing work.

How to explain the force

As the car gains speed, its kinetic energy increases, which means it has more energy of motion. Kinetic energy is defined as one-half of the mass of an object times its velocity squared, so as the car's speed increases, so does its kinetic energy.

The gravitational potential energy of the car will remain constant as long as it stays on a horizontal road, assuming there is no change in elevation. Gravitational potential energy is the energy an object possesses due to its position in a gravitational field, and since the car's position relative to the ground is not changing, its gravitational potential energy will remain constant.

The tractive force of the engine may change depending on the speed of the car and the resistance to motion that the car is encountering. As the car speeds up, the air resistance acting on the car will increase, which will require more force from the engine to maintain the same acceleration. Additionally, if the road surface is rough or there are inclines, the tractive force required to maintain the same speed or acceleration will also increase.

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a sound wave traveling through a certain freshwater lake has a frequency of 257.2hz and a wavelength of 3.25m. if the water conditions are held constant, all sound waves will travel at the save speed through water. use this fact to calculate the wavelength of a sound wave with a frequency of 415.3hz. (show work pls<3)

Answers

The wavelength of the sound wave with a frequency of 415.3 Hz is approximately 3.565 m.

How to determine wavelength?

The speed of sound in water is approximately 1482 m/s. Use the formula v = f × λ, where v = velocity (speed of sound), f = frequency, and λ = wavelength.

Given:

Frequency of the first sound wave (f₁) = 257.2 Hz

Wavelength of the first sound wave (λ₁) = 3.25 m

Velocity of sound in water (v) = 1482 m/s

Rearrange the formula to solve for λ₂ (wavelength of the second sound wave):

v = f × λ

λ = v / f

Substituting the values:

λ₂ = v / f₂

= 1482 m/s / 415.3 Hz

Calculating:

λ₂ ≈ 3.565 m

Therefore, the wavelength of the sound wave with a frequency of 415.3 Hz is approximately 3.565 m.

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Can someone find the answer and explain part b of this problem? Please provide me with the equation, too.

Can someone find the answer and explain part b of this problem? Please provide me with the equation,

Answers

a.The direction of the magnetic field at point P, located above a long straight wire carrying current, is perpendicular to the wire and depends on the direction of the current, as determined by the right-hand rule, and b.the magnitude of the magnetic field at point P is 0.01 Tesla.

A magnetic field is a physical field that is created by electric charges in motion, such as an electric current or a moving magnet. It exerts a force on other moving charges and magnetic objects and is an essential component of many modern technologies including electric motors, generators, and magnetic storage devices.

a. Using the right-hand rule for the magnetic field around a straight wire, we can determine that the direction of the magnetic field at point P is perpendicular to both the direction of the current and the vector pointing from the wire to point P. Specifically, the magnetic field points out of the plane of the paper (or screen) if the current is flowing from left to right, and into the plane of the paper (or screen) if the current is flowing from right to left.

b. We can use the formula for the magnetic field around a straight wire to calculate the magnitude of the magnetic field at point P:

B = μ₀I/(2πr)

where B is the magnetic field, μ₀ is the vacuum permeability constant (4π x 10^-7 T m/A), I is current, and r is the distance from the wire to the point of interest. In this case, I = 50 A and r = 2.5 mm = 0.0025 m. Substituting these values into the formula, we get:

B = (4π x 10^-7 T m/A)(50 A)/(2π x 0.0025 m) ≈ 0.01 T

So, the magnitude of the magnetic field at point P is approximately 0.01 Tesla.

Therefore, According to the right-hand rule, the magnetic field at point P, which is placed above a long, straight wire carrying current, is perpendicular to the wire and depends on the direction of the current. Its strength is also 0.01 Tesla.

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Three point charges are fixed in place in a right triangle, as shown in the figure.
What is the magnitude of the electric force on the +1.00-C charge due to the other two charges?
What angle does the force make with the -x-axis? A positive angle is counterclockwise from the -x-axis.

Three point charges are fixed in place in a right triangle, as shown in the figure.What is the magnitude

Answers

For the three-point charges fixed in a right triangle, we have:

1. The magnitude of the electric force on the +1.00 μC charge is 1.79 N.

2. The force does an angle of 21.68° with the x-axis.

1. Magnitude of the electric force

First, let's denote the charges as is shown in the picture below:

q₁: is the charge 1 = +0.800 μC = +0.800x10⁻⁶ Cq₂: is the charge 2 = +1.00 μC = +1.00x10⁻⁶ Cq₃: is the charge 3 = -0.600 μC = -0.600x10⁻⁶ C

                                                                       

The magnitude of the electric force on the charge 2 (+1.00 μC) is given by:  

\(|F_{net}| = \sqrt{(\Sigma\vec{F}_{x})^{2} + (\Sigma\vec{F}_{y})^{2}}\)  (1)    

Where:  

\(\Sigma\vec{F}_{x}\): is the sum of the forces acting on the x-axis\(\Sigma\vec{F}_{y}\): is the sum of the forces acting on the y-axis

We can calculate the electrical forces with Coulomb's law:

\(\vec{F} = \frac{Kq_{1}q_{2}}{d^{2}}\)

Where:

K is the Coulomb's constant = 9.00x10⁹ Nm²/C²  q₁ and q₂ are the chargesd is the distance between the charges

     

Forces in the x-axis (\(\Sigma\vec{F}_{x}\))

The forces in the x-component are given by:

\(\Sigma\vec{F}_{x} = \vec{F}_{21}_{x} + \vec{F}_{23}_{x}\)

\(\Sigma\vec{F}_{x} = \vec{F}_{21}_{x}cos(\theta) + \vec{F}_{23}_{x}\)

\(\Sigma\vec{F}_{x} = \frac{Kq_{1}q_{2}}{d_{12}^{2}}cos(\theta) + \frac{Kq_{2}q_{3}}{d_{23}^{2}}\)   (2)

Where:              

θ: is the angle of the force F₂₁ with the x-axisd₁₂ = z = 9.60 cm = 0.0960 m  d₂₃ = x

We can calculate the angle θ with the following trigonometric function:

\(sin(\theta) = \frac{y}{z}\)

\(\theta = sin^{-1}(\frac{y}{z}) = sin^{-1}(\frac{8.10 cm}{9.60 cm}) = 57.5 ^\circ\)

To find the distance x (d₂₃), we need to use Pythagoras:

\(x = \sqrt{z^{2} - y^{2}} = \sqrt{(0.0960 m)^{2} - (0.0810 m)^{2}} = 0.051 m\)

 

After entering θ and x (d₂₃) into equation 2, we have:

\(\Sigma\vec{F}_{x} = \frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}cos(57.5) + \frac{9.00 \cdot 10^{9}Nm^{2}C^{-2}(1.00 \cdot 10^{-6} C)(-0.600 \cdot 10^{-6} C)}{(0.051 m)^{2}}\)

\(\Sigma\vec{F}_{x} = [0.78*cos(57.5) + (-2.08) N] = -1.66 N\)

Hence, the x-component of the force is -1.66 N.

Forces in the y-axis (\(\Sigma\vec{F}_{y}\))

The only force acting on the y-axis is the y-component of the force F₂₁, so:

\(\Sigma\vec{F}_{y} = -\vec{F}_{21}_{y} = -\vec{F}_{21}sin(\theta)\)

The minus sign is because the vector is pointing in the negative y-direction (see the picture below).

\(\Sigma \vec{F}_{y} = -\frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}sin(57.5) = -0.66 N\)

Hence, the y-component of the force is -0.66 N.

Finally, the magnitude of the electric force on the charge +1.00 μC is (eq 1):  

\(|F_{net}| = \sqrt{(-1.66 N)^{2} + (-0.66 N)^{2}} = 1.79 N\)                                  

Therefore, the magnitude of the electric force on the +1.00 μC charge is 1.79 N.

2. Direction of the force with the x-axis

According to the picture below, the angle of the force with respect to the x-axis is given by:  

\(tan(\beta) = \frac{\Sigma\vec{F}_{y}}{\Sigma\vec{F}_{x}}\)

\(\beta = tan^{-1}(\frac{-0.66 N}{-1.66 N}) = 21.68 ^\circ\)

Therefore, the force does an angle of 21.68° with the x-axis.

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Three point charges are fixed in place in a right triangle, as shown in the figure.What is the magnitude

2. Which process is used by plants to cycle water from the ground, through the roots, and out the leaves as water vapor?
sublimation
O perspiration
O transpiration
O runoff

Answers

Answer:

The answer is transpiration

Perspiration is the answer

What is SeaWorld?
What is this
What is that

Answers

SeaWorld is a chain of theme parks and oceanariums that showcase marine life through educational exhibits, live shows, and thrilling rides. While it has faced criticism for its treatment of animals, SeaWorld has made changes to prioritize conservation and phased out its orca breeding program.

SeaWorld is a chain of theme parks and oceanariums that primarily focuses on marine life and entertainment. The company operates various parks across the United States, including SeaWorld parks in Orlando, San Diego, and San Antonio, as well as Busch Gardens parks in Tampa and Williamsburg. SeaWorld offers a combination of educational exhibits, live shows, and thrilling rides, with a special emphasis on marine animals such as dolphins, whales, sea lions, penguins, and sharks.

SeaWorld parks provide visitors with opportunities to observe and interact with marine creatures up close, while also offering educational programs that aim to raise awareness about marine conservation and preservation. The parks feature captivating shows featuring trained animals, where they perform impressive behaviors and stunts, showcasing their intelligence and natural abilities.

Over the years, SeaWorld has faced criticism from animal rights activists and environmentalists, who argue that the captivity and use of marine animals for entertainment purposes is unethical and harmful to the animals' well-being. These concerns have led to significant changes in the company's practices, including the phasing out of its orca breeding program and the introduction of more educational and conservation-focused initiatives.

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A hot air balloon is rising upward with a constant speed of 3.80m/s. When the balloon is 4.25m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground

Answers

We can calculate the time taken by the compass to hit the ground by using kinematic equations of motion. The motion of the compass is a free-fall motion since it is only under the influence of gravity. When the compass is dropped, it is initially at rest.

After that, it falls down to the ground with the acceleration due to gravity. Given that the balloon is rising upward with a constant speed of 3.80m/s. Hence, the velocity of the compass when it is dropped will be equal to the velocity of the balloon, which is 3.80m/s. The acceleration due to gravity is 9.81m/s². We can use the following kinematic equation of motion to calculate the time taken by the compass to hit the ground: `y = vi * t + 0.5 * a * t²`, where `y` is the height, `vi` is the initial velocity, `a` is the acceleration, and `t` is the time taken.We know that the initial height of the compass is 4.25m, the initial velocity is 3.80m/s, and the acceleration due to gravity is 9.81m/s². We need to find the time taken by the compass to hit the ground. Using the above kinematic equation, we get:`0 = 3.80t + 0.5 * 9.81 * t²`Simplifying the equation, we get:`4.905t² + 3.80t = 0`Factorizing the equation, we get:`t(4.905t + 3.80) = 0`Solving for `t`, we get:`t = 0` (since time cannot be negative)`t = -3.80/4.905 = -0.776s`We ignore the negative value of time since time cannot be negative. Hence, the time taken by the compass to hit the ground is `t = 0.776s`.Answer: `0.776s`

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I NEEDDD HELP LIKE RIGHT NOW ITS SIMPLE

What is the best description of originality?

nonobvious

special or interesting

convergent

having a low probability, unique

Answers

Answer: a

Explanation:


If you live in the southern hemisphere, what season would you be experiencing in position C this diagram?
A)
Fall
B)
Summer
C)
Winter
D)
Spring

If you live in the southern hemisphere, what season would you be experiencing in position C this diagram?A)FallB)SummerC)

Answers

I think it’s C HOPE ITS RIGHT
The answer to this question is B

You need to load a crate of mass m onto the bed of a truckon earth. One possibility is just to lift the crate straight up over a height h, equal to height of the truck's bed. Theforce exert in this case is F1 and the work done in this case is W1. The other possibility is to slide the crate up the frictionless ramp of length L.. In this case you exert force F2 and perform work W2. Which statement is true?

a. F1 > F2 and W1 > W2
b. F1 = F2 and W1 > W2
c. F1 = F2 and W1 = W2
d. F1 > F2 and W1< W2
e. F1 > F2 and W1 = W2

Answers

Answer:

The correct answer is - option E. e. F1 > F2 and W1 = W2

Explanation:

Case 1 - F1 = mg, m= mass and g = gravitational force

Work done W1 = F1h= mgh (h - height of bed of truck)

Case 2 - F2 = mgsinθ

work done W2 = mgsinθ×L (L=length of ramp ans sin θ angle of ramp)

sinθ = h/l, then W2 = mg(h/L)L

W2 = mgh

By comparing both,

F2 = mgsinθ and F1 = mg therefore,

F2>F1

now, W2 = mgh, and W1 = mgh

therefore, W2 = W1.

Provided that velocity is constant,
doubling the frequency of a wave
should...
A. double the wavelength
as well
B. have no affect on the
wavelength
C. reduce the wavelength
by half

Answers

Answer:so that's C

Explanation:

Wave speed equals frequency*wavelength. So doubling the frequency must halve the wavelength in order for wave speed to remain the same

Josh starts his sled at the top of a 3.5-m high hill that has a constant slope of 25∘
. After reaching the bottom, he slides across a horizontal patch of snow. The hill is frictionless, but the coefficient of kinetic friction between his sled and the snow is 0.08.

Answers

If the coefficient of kinetic friction between Josh's sled and the snow is 0.08, he slides 6.97 meter from the base of the hill.

To find how far from the base of the hill Josh's sled ends up, we need to first find the speed of the sled at the bottom of the hill using the conservation of energy principle,

mgh = (1/2)mv², plugging in the values given in the problem, we get,

m(9.81 m/s²)(3.5 m) = (1/2)mv²

Simplifying and solving for v, we get,

v = √(2gh)

v = √(2(9.81 m/s²)(3.5 m))

v = 8.29 m/s

Now we can use the kinematic equation,

d = vt - (1/2)at, to find how far the sled slides on the horizontal patch of snow before coming to a stop, where d is the distance traveled, v is the initial velocity (8.29 m/s), a is the acceleration due to friction (-μg), and t is the time it takes to come to a stop (which we can find by setting v = 0 and solving for t),

0 = 8.29 m/s - μg*t

t = 8.29 m/s / μg

Substituting this value of t back into the kinematic equation, we get,

d = (8.29)(8.29/μg) - (1/2)μg(8.29/μg)²

d = 6.97 m

Therefore, Josh's sled ends up 6.97 meters from the base of the hill.

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Sample Question: 4
A 5 kg mass is lifted from the ground to
a height of 10m.
The gravitational potential energy of
the mass is increased approximately
by

Answers

The gravitational potential energy of the mass in increased approximately by 490 J

Gravitational Potential energy formula is

P=mgh

where mass is given my m= 5 Kg

g is the gravitational force i.e. 9.8 \(m/s^{2}\)

h is the height above the ground that is given by 10 m

P = 5*9.8*10

P = 490 J

What is gravitational potential energy?

The potential energy that a huge item has in relation to another massive object due to gravity is known as gravitational energy or gravitational potential energy. When two objects descend toward one another, the potential energy associated with the gravitational field is released (transformed into kinetic energy).

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calculate the force on an object with mass of 50kg and gravity of 10​

Answers

Answer: 500 N

Explanation:

The formula to find the force exerted by a mass, we may use F = mg, where g, the gravity, and a, the acceleration, can be interchangeable in the formula.

1) F = 50 x 10
2) F = 500 N

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What happens to the body’s immune system when attacked by HIV ?

Answers

Answer:

HIV attacks a specific type of immune system cell in the body. It's known as the CD4 helper cell or T cell. When HIV destroys this cell, it becomes harder for the body to fight off other infections.

Explanation:

if i release one steel ball from the top of a ramp and the other ball from the 40cm mark will they have the same velocity?

Answers

Answer:

Yes.

Explanation:

Assuming that the balls weigh the same, then they would have the same velocity. Velocity is the term used to describe the speed at which an object is traveling.

A carpenter lifts a 20kg piece of wood to his shoulder 1.5m above the ground. He then sets the wood on his truck at 1.0 m above the ground and makes his delivery going 10 m/s What is the wood's potential energy on the carpenter's shoulder? Show all work, the rubric is included for this problem.

Answers

Answer:

10kg

Explanation:

it is 10kg bc  the energy is false kenetic. The greater mass a moving object has, the more kinetic energy it has it has has kinetic energy because of its position Friction causes some mechanical energy to change to thermal energy. Doubling an object's velocity will double its kinetic energy

Based on your graph, predict the length of pendulum that will give you a
period of 2.00s.

Based on your graph, predict the length of pendulum that will give you aperiod of 2.00s.

Answers

Answer:

About 1 meter

Explanation:

Base on your image, when the period is 2 (horizontal variable), the length of the pendulum is about 1 meter.

1. Is the image projected on a movie screen real or virtual? What about the image of yourself seen in a bathroom mirror?


2. Hold a shiny spoon in front of you. What differences do you notice about the image of your face seen in the convex and concave sides?


3. Where are the images formed by each side of the spoon? In front or behind the spoon? (Try the parallax method. Look at the image of an overhead light. Hold the tip of a pencil where you think the image is. Move your head from side to side. If the image and pencil tip appear to move relative to each other, adjust the position of the pencil back and forth until they appear as one)

Answers

Answer: 1. The movie one is virtual and the bathroom mirror is real

2. The image is distorted in a way

3. Behind the spoon

Explanation:

The movie one is virtual and the bathroom mirror is real and The image is distorted in a way and Behind the spoon.

What is virtual screen?

In virtual desktops, the desktop environment is segregated from the physical device being used to access it. They are preloaded images of operating systems and apps. Over a network, users can remotely view their virtual desktops.

A virtual desktop can be accessed from any endpoint device, including a laptop, smartphone, or tablet. The user interacts with the client software that was installed on the endpoint device by the virtual desktop provider.

A virtual desktop mimics the appearance and feel of a real workstation. Because robust resources, like storage and back-end databases, are easily accessible, the user experience is frequently even better than that of a physical workstation.

Therefore, The movie one is virtual and the bathroom mirror is real and The image is distorted in a way and Behind the spoon.

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How much work is done when 425 N of force is applied for 60.0m

Answers

Answer:

Workdone = 25500Nm

Explanation:

Given the following data

Force = 425N

Distance = 60m

To find the workdone

Workdone = force *distance

Substituting into the equation, we have

Workdone = 425*60

Workdone = 25500Nm

Given A = (0.210 + 0.41) (1.10 x 102). Show the result for A in correct number of
significant figures.

Answers

Answer:

69

Explanation:

Perform addition first as;

(0.210 + 0.41) = 0.62 -------{2 significant figures}

Perform product

(1.10 x 102) = 112 -------------- {3 significant figures}

The combined product

0.62 x 112 =69.44

                 = 69 ----------2 significant figures

Rule

The least number of significant figures in the numbers performing the operation determines the number of significant figures in the answer.

An ambulance is traveling east at 62.4 m/s. Behind it a car travels along the same direction at 34.5 m/s. The ambulance driver hears his siren with a wavelength of 0.47 m. What wavelength would a stationary observer behind the ambulance measure for the sound? The velocity of sound in air is 343 m/s.

Answers

Answer:

The answer is "0.5555 m"

Explanation:

Where the reference leaves the list and the viewer is at rest:

\(\lambda'=\frac{v-v_s}{v} \times \lambda\\\\\)

   \(=\frac{343 \frac{m}{s} - (-62.4 \frac{m}{s})}{343 \frac{m}{s}} \times 0.47 \ m\\\\ =\frac{343 \frac{m}{s} + 62.4 \frac{m}{s}}{343 \frac{m}{s}} \times 0.47 \ m\\\\ =\frac{405.4 \frac{m}{s}}{343 \frac{m}{s}} \times 0.47 \ m\\\\ =\frac{405.4 \frac{m}{s}}{343 \frac{m}{s}} \times 0.47 \ m\)

   \(=0.5555 \ m\)

Other Questions
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