In the zoo, there are 12 elephants, 8 giraffes, 9 lions, 10 seals, and 16 otters.
What is the ratio of elephants to all the animals at the zoo?
Thank yous

A relation ~ on R' is defined as a relation where (a,b) ~ (c,d) if and only if a3+b3=c3+d3. This relation is transitive but not symmetric.

Transitivity of the relation states that if (a, b) ~ (c,d) and (c, d) ~ (e, f) then (a, b) ~ (e, f). This means that if a3+b3=c3+d3 and c3+d3=e3+f3 then a3+b3=e3+f3, thus, the relation is transitive.

Symmetry of the relation means that if (a, b) ~ (c, d) then (c, d) ~ (a, b). This, however, does not hold in this relation since it is possible for a3+b3=c3+d3 and yet c3+d3≠a3+b3. For example, (1,2) ~ (8,4), this is true since 13+23=83+43, however, this does not mean that (8,4) ~ (1,2) since 83+43≠13+23. Therefore, this relation is not symmetric.

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Answer:

15_789(0)

Step-by-step explanation:

Answer:

19 throws.

Step-by-step explanation:

For her success rate to be 80% in 37 throws she must make  0.8 * 37

= 29.6 throw - that is 30 to nearest throw.

So for the next 20 throws she must make  30 - 11 = 19 throws.

Answer:

S = 3

S = 5

S = 7

S = 9

Step-by-step explanation:

t = 3s + 2

when t = 11

11 = 3s + 2

11 – 2 = 3s

9 = 3s

s = 3

t = 3s + 2

when t = 17

17 = 3s + 2

17 – 2 = 3s

15 = 3s

s = 5

t = 3s + 2

when t = 23

23 = 3s + 2

23 – 2 = 3s

21 = 3s

s = 7

t = 3s + 2

when t = 29

29 = 3s + 2

29 – 2 = 3s

27 = 3s

s = 9

I HOPE ALL THIS HELPS

RATE AS BRAINLIEST PLS

Answer:

66.66%

Step-by-step explanation:

The first model is the one you should use here as 24 and 18 are multiples of 3, this means that there is eight students in each group

That means that 18/24 is equal to 2/3 so the percentage of students that like to dance is 66.66%

the tax estimated to be collected by the government during the financial year 2020/21 is 666.9 billion rands.

why it is and what is a financial year?

The tax estimated to be collected by the government during the financial year 2020/21 is not explicitly given in the table. However, the total revenue collected by the government during the financial year 2020/21 is given, which is:

666.9 billion rands

Therefore, the tax estimated to be collected by the government during the financial year 2020/21 is 666.9 billion rands.

A financial year (also known as fiscal year) is a period of 12 months that a company or government uses for financial reporting and accounting purposes. It does not necessarily correspond to the calendar year, which is a period of 12 months starting on January 1st and ending on December 31st.

The financial year is important because it helps organizations to keep track of their financial performance over a consistent period of time, which facilitates comparison of financial results from year to year. The financial year is often chosen to align with a company's operational cycle, which may be seasonal or have other considerations that affect the timing of revenues and expenses.

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When a\(_{n}\) = \(2^{n}\)+ n,  a₀ = 1,  a₁ = 3,  a₂ = 6, and a₃ = 11  

When a\(_{n}\) = n^(n+1)!,  a₀ = 0,  a₁ = 2,  a₂ = 2⁶, and a₃ = 3²⁴  

When a\(_{n}\) =  [n/2], a₀ = 0,  a₁ = 1/2,  a₂ = 1, and a₃ = 3/2      

When a\(_{n}\) = [n/2] + [n/2], a₀ = 0,  a₁ = 1,  a₂ = 2, and a₃ = 3/2  

Number sequence

A number sequence is a progression or a list of numbers that are directed by a pattern or rule.

Here,

a₀, a₁, a₂, and a₃ are terms of a sequence

from option a, a\(_{n}\) = \(2^{n}\)+ n

⇒ a₀  = 2⁰+ 0 = 1+0 = 1

⇒ a₁  = 2¹+ 1 = 2+1 = 3

⇒ a₂, = 2²+ 2 = 4+2 = 6

⇒ a₃  = 2³+ 3 = 8 +3 = 11  

from option b, a\(_{n}\) = n^(n+1)!

⇒ a₀  = 0^(0+1)! = 0

⇒ a₁  = 1^(1+1)! = 2² = 2

⇒ a₂, = 2^(2+1)! = 2^(3)! = 2⁶          [ ∵ 3! = 6 ]

⇒ a₃  = 3^(3+1)! = 3^(4)! = 3²⁴         [ ∵ 4! = 24 ]

from option c, a\(_{n}\) =  [n/2]          

⇒ a₀  = [0/2] = 0

⇒ a₁  = [1/2] = 1/2

⇒ a₂, = [2/2] = 1

⇒ a₃  = [3/2] =  3/2  

from option d, a\(_{n}\) = [n/2] + [n/2]

⇒ a₀  =  [0/2] + [0/2] = 0

⇒ a₁  =  [1/2] + [1/2] = 1/2 + 1/2 = 1

⇒ a₂, = [2/2] + [2/2] = 1 + 1 = 2

⇒ a₃  =  [3/2] + [3/2] = 6/4 = 3/2

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The Complete Question is -

What are the terms a₀, a₁, a₂, and a₃ of the sequence {a\(_{n}\)}, where a\(_{n}\) is where a\(_{n}\) equals

a. \(2^{n}\) + n                    b. n^(n+1)!

c. [n/2]                      d. [n/2] + [n/2]

The correct answer is OD. 8x + 1.

To divide 8x³ + x² - 32x - 4 by x² - 4, we can use polynomial long division.

The dividend is 8x³ + x² - 32x - 4, and the divisor is x² - 4.

We start by dividing the highest degree term, which is 8x³, by x². This gives us 8x.

Next, we multiply the divisor x² - 4 by the quotient 8x. The result is 8x³ - 32x.

Subtracting 8x³ - 32x from the dividend, we get x² - 32x.

Now, we divide x² - 32x by x² - 4. This gives us 1.

Multiplying the divisor x² - 4 by the quotient 1, we get x² - 4.

Subtracting x² - 4 from the remaining dividend, which is -32x, we get -32x + 4.

Since we can no longer divide, the final result is the quotient we obtained: 8x + 1.

Therefore, the correct answer is:

OD. 8x + 1.

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The inputs that are solutions for the inequality are:

x = 2

x= 1

Here we have the following inequality:

-5x < 2

We want to see which of the given inputs is a solution for this.

First we can isolate the variable in our inequality, so we get:

-5x < 2

-2 < 5x

-2/5 < x

-0.4 < x

So any value larger than -0.4 is a solution, from the given options, the two that are solutions are:

x = 1

x = 2.

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The results of the operation of multiplication between two functions are, respectively:

According to function theory, there are five operations between two functions to create resulting functions:

In this problem we must use the operation of multiplication between two functions.

Case 1

(f · g)(x) = (2 · x + 4) · (x² + 4 · x + 4)

(f · g)(x) = (2 · x + 4) · x² + 4 · (2 · x + 4) · x + 4 · (2 · x + 4)

(f · g)(x) = 2 · x³ + 4 · x² + 8 · x² + 16 · x + 8 · x + 16

(f · g)(x) = 2 · x³ + 12 · x² + 24 · x + 16

Case 2

(h · g)(x) = (x² - 4) · (x² + 4 · x + 4)

(h · g)(x) = (x² - 4) · x² + (x² - 4) · (4 · x) + (x² - 4) · 4

(h · g)(x) = x⁴ - 4 · x² + 4 · x³ - 16 · x + 4 · x² - 16

(h · g)(x) = x⁴ + 4 · x³ - 16 · x - 16

Case 3

(f · h)(x) = (2 · x + 4) · (x² - 4)

(f · h)(x) = 2 · x³ - 8 · x + 4 · x² - 16

(f · h)(x) = 2 · x³ - 4 · x² - 8 · x - 16

(f · h)(2) = 2 · 2³ - 4 · 2² - 8 · 2 - 16

(f · h)(2) = - 32

Case 4

(g · f)(x) = (x² + 4 · x + 4) · (2 · x + 4)

(g · f)(x) = 2 · x³ + 12 · x² + 24 · x + 16

Case 5

(g · h)(x) = (x² + 4 · x + 4) · (x² - 4)

(g · h)(x) = x⁴ + 4 · x³ - 16 · x - 16

Case 6

(f · h)(x) = (2 · x + 4) · (x² - 4)

(f · h)(x) = 2 · x³ - 4 · x² - 8 · x - 16

Case 7

(h · g)(x) = (x² - 4) · (x² + 4 · x + 4)

(h · g)(x) = x⁴ + 4 · x³ - 16 · x - 16

(h · g)(1) = 1⁴ + 4 · 1³ - 16 · 1 - 16

(h · g)(1) = - 27

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Answer:

(−12.5) (11.5) = −143.75 Or -12.5 < 11.5

Step-by-step explanation:

hope this helps

Answer:

|-12.5|>|11.5|

Step-by-step explanation:

When you take the absolute value of a number you're essentially measuring the scalar value or magnitude of that number. "How big is that number as a number not as in + or -".

In other words the number becomes positive

|-12.5|=12.5

|11.5|=11.5

since 12.5>11.5

we can then say

|-12.5|>|11.5|

Answer:

All of the above

Step-by-step explanation:

d ≥ 1 means that d is greater than or equal to 1. So, d could be number 1 or anything greater than that. Therefore, d could equal 2, d could equal 11, d could equal 9, and d could equal 7.

Did this help you?

After 5,730 years, 10 grams of carbon-14 would be present.

Scientists often use a process called carbon dating to estimate the age of archaeological finds. The process measures the amount of carbon-14, a: radioactive isotope with a half life of 5,730 years. If a sample of wood from an ancient artifact had 20 grams of carbon-14 initially, the amount remaining, in grams, is given by :

A(t)=20(1/2) ^ (t/5,730)

Substituting t = 5,730 in the given equation, we get:

A(5,730) = 20(1/2)^(5,730/5,730)

Simplifying, we get:

A(5,730) = 20(1/2)^1

A(5,730) = 20(1/2)

A(5,730) = 10

Hence, after 5,730 years, 10 grams of carbon-14 would be present.

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The t value that forms the boundary of the critical region in the right-hand tail for a one-tailed test with α = .01 is 2.821 for sample size a. n=10, 2.861 for sample size b. n=20, and 2.756 for sample size c. n=30.

To find the t value that forms the boundary of the critical region in the right-hand tail for a one-tailed test with α = .01, we need to consult the t-distribution table. Specifically, we need to find the t value that corresponds to the α/2 = .005 level of significance (since this is a one-tailed test in the right-hand tail, we only need to consider the upper tail of the distribution).
For sample size a (n=10), the degrees of freedom (df) = n-1 = 9. From the t-distribution table with 9 degrees of freedom and α/2 = .005, we find a t value of 2.821.
For sample size b (n=20), the degrees of freedom (df) = n-1 = 19. From the t-distribution table with 19 degrees of freedom and α/2 = .005, we find a t value of 2.861.
For sample size c (n=30), the degrees of freedom (df) = n-1 = 29. From the t-distribution table with 29 degrees of freedom and α/2 = .005, we find a t value of 2.756.
So, the t value that forms the boundary of the critical region in the right-hand tail for a one-tailed test with α = .01 is 2.821 for sample size a, 2.861 for sample size b, and 2.756 for sample size c.

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Answer:

\(x^{2}\)-\(\frac{2}{3}x\)+\(\frac{1}{9}\)-\(\frac{1}{3(3x-4)}\)

Step-by-step explanation:

Answer:

Options 2, 4, 6

Step-by-step explanation:

Hi,

9x = 21 - 3

9x = 18

x = 18/9 = 2

This is a two-step equation:

\(9x + 3 = 21\\\\9x = 18\\\\x = 2\)

The probability for those who used debit card will be 37%.

Probability is the occurence of likely events. It is the area of mathematics that deals with numerical estimates of the likelihood that an event will occur or that a statement is true.

From the information, Ava owns a small business selling clothing. She knows that in the last week 34 customers paid cash, 26 customers used a debit card, and 11 customers used a credit card.

The Total number of customers will be:

= 34 + 26 + 11

= 71

Therefore, the probability for those who used debit card will be:

= Number of debit cards users / Total customers × 100

= 26 / 71 × 100

= 37%

The probability is 37%.

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the equation are:

So in this case the slope of the first equatin is 0 and is a horizontal line, and the slope in the second equation is undefine so it is a vertical line.

This means that the lines are perpendicular so the answer is yes

The answer is B. anticipatory socialization. Aman's anticipation and excitement about his new role as a computer scientist indicate his engagement in anticipatory socialization.

Anticipatory socialization refers to the process through which individuals learn and internalize the values, norms, and behaviors associated with a future role or status they aspire to have. In this case, Aman's graduation from college and his upcoming job as a computer scientist represent a transition to a new role.

As he looks forward to this new position, he is likely engaging in activities such as researching the company, learning about the responsibilities of a computer scientist, and acquiring the necessary skills to excel in his job. By doing so, Aman is preparing himself and adjusting his attitudes and behaviors to fit the expectations of his future role, which characterizes anticipatory socialization.

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The complete question is:

Aman is graduating from college and looking forward to his new role in his job as a computer scientist for a large firm. This is an example of

A.the imagination stage

B.anticipatory socialization.

C.the game stage.

D.looking-glass self

Answer:

Well, in this case all the students selected live in the dorms, so it is actually likely that they eat in the cafeteria regularly.

For example, a student that lives in a house (with family, friends, etc) may have access to eat in his own place or may have larger economic freedom, so maybe they go and eat out. In this group, you may find that the probability for a randomly selected student eats in the cafeteria regularly may be smaller than in the group of the students that live in the dorms.

So the sample will be biassed towards eating regularly in the cafeteria.

Using the Riemann sum, we divide the interval [2, 4] into n equal subintervals, where Δx = (4 - 2) / n.

To find the expression for the area under the graph of the function f(x) = x^2 √(1/2x) as a limit, we can use the definition of a Riemann sum and take the limit as n approaches infinity of the sum from i = 1 to n.

The Riemann sum is a method to approximate the area under a curve by dividing it into smaller rectangular regions. In this case, we need to express the area under the graph of f(x) as a limit of a Riemann sum.

The expression for the area under the graph of f(x) as a limit is given by:

lim n → ∞ Σ i=1^n [f(xi) Δx]

In this formula, xi represents the ith subinterval, Δx represents the width of each subinterval, and f(xi) represents the value of the function at a point within the ith subinterval.

To calculate the Riemann sum, we divide the interval [2, 4] into n equal subintervals, where Δx = (4 - 2) / n. Then, for each subinterval, we evaluate f(xi) and multiply it by Δx. Finally, we sum up all these values as n approaches infinity.

However, without evaluating the limit or specifying the specific method of partitioning the interval, it is not possible to provide a more precise expression for the area. The given information is insufficient to calculate the exact value.

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The width of the rectangle is 9 meter.

Now, According to the question:

The perimeter of a rectangle is defined as the sum of all the sides of a rectangle. For any polygon, the perimeter formulas are the total distance around its sides. In case of a rectangle, the opposite sides of a rectangle are equal and so, the perimeter will be twice the width of the rectangle plus twice the length of the rectangle and it is denoted by the alphabet “p”.

Now, Solving the problem:

Perimeter of rectangle is 50 meter sq.

Length of the rectangle(L) is 16 meter.

We have to find the width (W) of the rectangle.

We know that,

Perimeter of rectangle is = 2 (L + W)

50 = 2(16 + W)

50 = 32 + 2W

2W = 50 - 32

2W = 18

W = 18/2

W = 9

Hence, The width of the rectangle is 9 meter.

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The number of tickets were sold are; 150 for adult tickets and 250 for child tickets

There are 400 seats in the auditorium which means that there are 400 tickets to be sold and the total ticket sales were 2600 dollars.

Since there were adult tickets for 9 each and child tickets for 5 dollars each.

9x + 5y = 2600

x + y = 400

Solving;

9x + 5(400-x) = 2600

9x + 2000 - 5x = 2600

4x = 600

x = 150

Then y = 250

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Answer:

am not really sure but ig the answer is B

Step-by-step explanation:

Plz help timed test I’ll give extra points

Using the z table, the probability that a standard normal random variable will be between 0.3 and 3.2 is 0.3814.

In the given question,

We have to find that the probability that a standard normal random variable will be between 0.3 and 3.2 .

We firstly learn about a standard normal random variable which is expressed with a mean and standard deviation.

Since we have to find the probability that a standard normal random variable will be between 0.3 and 3.2 .

So The probability should be

P(0.3<z<3.2)=P(z<3.2)−P(z<0.3)

From the standard value of z

P(0.3<z<3.2)=0.9993−0.6179

Simplifying

P(0.3<z<3.2)=0.3814

Hence, the probability that a standard normal random variable will be between 0.3 and 3.2 is 0.3814.

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Answer:

22.4 ft

Step-by-step explanation:

Given

\(Height = 2.5ft\)

\(Shadow = 4ft\)

Required

Determine the shadow of 14 ft Tom

The given parameters represents direct variation.

Let x represents the shadow of Tom.

So, we have:

When

\(2.5ft\ height = 4ft\ Shadow\)

\(14ft\ height = x\)

Cross Multiply:

\(2.5 * x = 14 * 4\)

\(2.5 * x = 56\)

Solve for x

\(x = 56/2.5\)

\(x = 22.4\)

Hence, the height of the shadow is 22.4ft

Answer:

the y-intercept is 8 and the slope is -4/3 .

Step-by-step explanation:

The y - intercept is (0, 8) and the slope is -4/3

"It is the point at which the graph of the function intersects the y-axis"

The slope of the line passing through points \((x_1,y_1),(x_2,y_2)\) is,

\(m=\frac{y_2-y_1}{x_2-x_1}\)

For given example,

We can observe that the line of best fit on this scatter plot passes though points (0, 8) and (6, 0)

Using the slope formula,

⇒ slope = (0 - 8)/(6 - 0)

⇒ slope = (-8)/6

⇒ slope = -4/3

Also, we can observe that the line of best fit on this scatter plot intersects y-axis at point (0, 8)

So, the y - intercept is (0, 8)

Therefore, the y - intercept is (0, 8) and the slope is -4/3

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Equation of line passing through the point and having slope m=1

y=mx+C

In this question, m=tan45°=1

So the equation becomes y=x+C

New line passes through (3,5)

Putting the values in the equation,5=3+c

C=2

New equation of line becomes y=x+2

Another line x+y−6=0

These two lines intersect at Q

y=x+2

y=−x+6

2y=8

y=4

Put the value of y=4 in line equation,

y=x+2

x=2

Q(2,4)

P(3,5)

O(0,0)

Distance between two points

=9×PQ² +14×O ² +10×OQ²

=9×2+14×34+10×20

=18+476+200

=694

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