In the synthesis of ammonia, if ¢ H2 /¢t 4.5 104 mol/ L min, what is ¢ NH3 /¢t ? N2(g) 3 H2(g) 2 NH3(g)
Answers
The balanced chemical equation for the synthesis of ammonia is: `N2(g) + 3H2(g) → 2NH3(g)`
The reaction ratio between N2 and H2 is 1:3. This means that for every one mole of N2 that reacts, three moles of H2 react. Therefore, if the rate of consumption of H2 is given as `Δ[H2]/Δt = -4.5 x 10^4 mol/L min`, the rate of production of NH3 can be calculated as follows:First, determine the stoichiometric ratio between H2 and NH3. The ratio is 3:2. This means that for every three moles of H2 that react, two moles of NH3 are produced.
The rate of production of NH3 can be calculated using the formula: `Δ[NH3]/Δt = (2/3) x Δ[H2]/Δt`
Substituting the given value for the rate of consumption of H2, we get:`Δ[NH3]/Δt = (2/3) x (-4.5 x 10^4) mol/L min``Δ[NH3]/Δt = -3 x 10^4 mol/L min`
Therefore, the rate of production of NH3 is `-3 x 10^4 mol/L min`.
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Related Questions
consider the williamson ether synthesis between 2‑naphthol and 1‑bromobutane in strong base. quizlet
Answers
The Williamson ether synthesis is a method used to synthesize ethers by reacting an alkoxide ion with an alkyl halide. In this case, we have 2-naphthol and 1-bromobutane as the reactants.
To perform the Williamson ether synthesis between 2-naphthol and 1-bromobutane, we need a strong base. The strong base will deprotonate the 2-naphthol to form the alkoxide ion, which will then react with 1-bromobutane.
Here are the steps for the synthesis:
1. Dissolve 2-naphthol and 1-bromobutane in a solvent, such as an alcohol like ethanol.
2. Add a strong base, such as sodium hydroxide (NaOH), to the reaction mixture. The strong base will deprotonate the 2-naphthol, forming the alkoxide ion.
3. The alkoxide ion will then attack the electrophilic carbon atom in the 1-bromobutane molecule, leading to the formation of a new carbon-oxygen bond.
4. The bromide ion is displaced as a leaving group.
5. After the reaction, the product will be a naphthyl ether, which is formed by the combination of 2-naphthol and 1-bromobutane.
It's important to note that the reaction conditions, such as temperature and reaction time, can affect the yield and selectivity of the reaction. Additionally, the choice of solvent and base can also influence the outcome of the synthesis.
In summary, the Williamson ether synthesis between 2-naphthol and 1-bromobutane in strong base involves the deprotonation of 2-naphthol, followed by the nucleophilic attack of the alkoxide ion on 1-bromobutane, resulting in the formation of a naphthyl ether.
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The Williamson ether synthesis is a common method used to prepare ethers by reacting an alkoxide ion with an alkyl halide. In the case of the reaction between 2-naphthol and 1-bromobutane
in strong base, the general procedure would be as follows:
Set up a reaction flask equipped with a reflux condenser and a magnetic stir bar.
Add 2-naphthol (the nucleophile) and an appropriate base, such as sodium hydroxide (NaOH), to the reaction flask.
Dissolve 1-bromobutane (the electrophile) in an appropriate solvent, such as anhydrous ether or dimethyl sulfoxide (DMSO).
Gradually add the dissolved 1-bromobutane to the reaction flask while stirring.
Heat the reaction mixture under reflux for a specific duration to facilitate the reaction.
After the reaction is complete, cool the mixture and transfer it to a separatory funnel.
Wash the organic layer with water to remove any impurities and extract the desired ether product.
Dry the organic layer using an appropriate drying agent, such as anhydrous sodium sulfate (Na2SO4).
Filter the dried organic layer to remove the drying agent and transfer it to a distillation apparatus.
Distill the ether product to obtain a pure sample.
The Williamson ether synthesis allows for the formation of a new ether bond between the oxygen of the 2-naphthol and the carbon of the 1-bromobutane, resulting in the synthesis of a naphthyl alkyl ether compound. The strong base, such as NaOH, helps in generating the alkoxide ion from the 2-naphthol, which then reacts with the electrophilic carbon of the 1-bromobutane to form the desired ether product.
Hence, Williamson synthesis reaction is explained above.
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1a)Which of the following amines is classified as a secondary amine? 1)N-methyl-2-butanamine 2)1-butanamine 3)2-butanamine 4)3-methyl-2-butanamine 1b) A polymer has the structure: -(CH2C(CH3)2CH2C(CH3)2CH2C(CH3)2)n-What is the monomer of this polymer? 1) (CH3)2C=CH2 2) CH3CH2CH3 3) CH3CH2CH=CHCH2CH3 4) CH2=CHCH3
Answers
Answer:
1) N-methyl-2-butanamine.
Explanation:
Secondary amines have 2 hydrogen atoms replaced by organic groups, so in this case, the secondary amine is N-methyl-2-butanamine:
. An atom of nitrogen has an atomic
number of 7 and a mass number of 14.
bive the number of electrons, protons
and neutrons in the atom.
Answers
Here's the Answer !
Atomic number = no. of electrons = no. of protons, therefore :
no. of electrons = 7no. of protons = 7and mass number = no. of protons + no. of neutrons
so,
7 + no. of neutrons = 14no. of neutrons = 7Which of the following terms describes the area where the Himalaya Mountains formed?
A.)Convergent Boundary
B.)Transform Boundary
C.)Divergent Boundary
B.)Subduction Zone
Answers
Answer:
Convergent Boundary describes the area where himalayan mountains formed.
Predict the polarity of 6 real molecules (O2, HF, H2O, NH3, CF4, CH3F). First, draw the
molecules and any bond dipoles. Then draw any molecular dipoles. Explain your
reasoning before you check your predictions with the simulation.
Answers
The polarity of 6 real molecules are given below,
O2- Neutral
HF- Acidic
H2O- Neutral
NH3- Basic
CF4-Nonpolar
CH3F- Polar
How to determine polarity of molecules?Predicting the polarity of molecules can be done using a variety of methods. One method is to use the molecular dipole moment, which is a measure of the separation of positive and negative charge in a molecule. Molecular dipole moments can be calculated using quantum chemistry methods such as Density Functional Theory, or other methods. Another method is to consider the electronegativity of the atoms in the molecule and the type of bond between them. Non-polar molecules have atoms with similar electronegativities and strong covalent bonds, while polar molecules have atoms with different electronegativities and polar covalent or ionic bonds. Finally, the polarity of a molecule can also be predicted by looking at its shape and symmetry. Non-polar molecules often have symmetrical shapes, while polar molecules tend to be asymmetrical.To learn more about polarity of molecules refer :
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A ballon contains 5.30kL of gas when the temperature is 12c what will the temperature of the container be when the volume increases to 6.00kL if the pressure remains constant
Answers
A balloon contains 5.30mL of gas when the temperature is 12°C.13.58°C will the temperature of the container be when the volume increases to 6.00ml if the pressure remains constant.
What is gas law ?Gas laws, which link a gas's volume, pressure, and temperature. According to Boyle's law, which bears Robert Boyle's name, a gas's pressure P changes inversely with its volume V at constant temperature, or PV = k, where k is a constant.
Given:
V₁ = 5.30ml
V₂ = 6.00ml
T₁ = 12⁰C
T₂ = ?
Pressure is constant then formula become as follows:
V₁/T₁ = V₂/T₂
V₁ × T₂ = V₂ × T₁
By substituting given values in above equation and we get,
5.30 × T₂ = 6.00 × 12
T₂ = 6.00 × 12 / 5.30
T₂ = 13.58°C
Thus, 13.58°C will the temperature of the container be when the volume increases to 6.00ml.
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What is the mass of oxygen in 240.0 grams of water?
Answers
Answer:
jvjckv
Explanation:
vjch jhoccixtzrzizfzirz
Which of the following uses electrical energy?
A washing machine
The sun
A plant
A cat
Answers
Answer:
★ B. A washing machine.
Explanation:
What's Electrical energy?
Electrical energy is energy derived from electric potential energy or kinetic energy. When used loosely, electrical energy refers to energy that has been converted from electric potential energy.
The sharpless reagent uses one of two different chiral reagents along with a titanium catalyst and tert-butyl hydroperoxide. what is the identity of the chiral reagents?
Answers
The chiral reagent is used to determine the optical activites of Sharpless reagent using one of two different chiral reagents along with a titanium catalyst and tetra-butyl hydroperoxide.
What are chiral reagents?The reagent is mostly used in analytical chemistry to distinguish between the optical activities of the chiral carbons in analytical chemistry.
The tetra-butyl hydroperoxide is an optically active compound and chiral reagents use to know about the symmetry of carbons.
Therefore, the chiral reagent is used to determine the optical activities of the Sharpless reagent using one of two different chiral reagents along with a titanium catalyst and tetra-butyl hydroperoxide.
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Describe a few abiotic factors found within the taiga that limit its biodiversity.
Answers
Answer:
Some abiotic factors of the taiga are temperature, precipitation, soil, and sunlight.
Explanation:
emperature affects the taiga because the winter temperature range is -65*F to 30*F (-54*C to -1*C), while the temperature range in the summer is 20*F to 70*F (-7*C to 21*C)
Precipitation affects the taiga because there's some precipitation that falls [30-85 cm. (12-33 in.)].
Soil affects the taiga because there's some acidic and low-in-nutrients soil, and some fertile soil.
Sunlight affects the taiga because there are small amounts of it that reach the ground.
The taiga biome's abiotic components include temperature, sunshine, soil, air, water, etc. Cold arctic air predominates in the taiga environment. The taiga receives more light in the summer, which causes the days to be hotter.
What are abiotic components ?Abiotic elements, also known as abiotic factors, are non-living chemical and physical elements of the environment that have an impact on the health of living things and the operation of ecosystems. Biology as a whole is supported by abiotic causes and the phenomena that go along with them.
Biotic and abiotic components, such as rainfall, in that order. The taiga is the biggest biome on Earth's surface and features a diversity of migratory and resident creatures. It also has long, cold, and dry winters and short, warm, and moist summers.
The Taiga biome is restricted by four primary criteria. Fire, temperature, the quantity of nutrients in the soil, and sunshine are the four limiting elements. Because certain plants, like the Jack Pine, recover after fire, it is a limiting element in the Taiga biome.
Thus, The taiga biome's abiotic components include temperature, sunshine, soil, air, water, etc.
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What volume will 1000 grams of nitrogen dioxide occupy at 380 mmHg at 0°C
Answers
0.69(78)Explanation:
What is the percent composition by mass of oxygen in magnesium oxide.
Answers
Answer
Explanation:
Magnesium Oxide has a formula of MgO.
Magnesium has a molar mass of 24.30g/mol and Oxygen has a molar mass of 15.99g/mol.
From this, we can say we are assuming a 1 mole sample of magnesium oxide, as the stoichiometric coefficients will always be the same, as will the ratio of oxygen to magnesium.
From this,
\(15.99g/mol *1 mol MgO = 15.99 gOxygen\\24.30g/mol *1molMgO=24.30gMagnesium\\Oxygen mass percent = 15.99/(15.99+24.30) = .396\)
The Magnesium equation will be the same but a different numerator. Notice, if there were different coefficients on the elements, you would have to multiply by the stoich coefficient.
There is 100 mCi of Cs-137 and 300 mCi of Co-60. Calculate the time it will take for both isotopes to decay
until their activities are equal.
Rationale:
Use the decay function for both isotopes and set
them equal to each other. (Cs-137 decay = Co-60
decay) Solve for t.
Answers
It will take approximately 35.4 years for both Cs-137 and Co-60 isotopes to decay until their activities are equal.
To determine the time it takes for both Cs-137 and Co-60 isotopes to decay until their activities are equal, we can use the decay function for each isotope and set them equal to each other.
The decay function for a radioactive isotope is given by:
A(t) = A₀ * exp(-λt)
Where:
A(t) is the activity at time t,
A₀ is the initial activity,
λ is the decay constant,
t is the time.
The decay constant (λ) can be calculated using the half-life (T₁/₂) of the isotope:
λ = ln(2) / T₁/₂
For Cs-137, the half-life is approximately 30.17 years, and for Co-60, the half-life is approximately 5.27 years.
Let's denote the time it takes for both activities to be equal as t_eq.
For Cs-137:
A(Cs-137) = 100 * exp(-0.693 / 30.17 * t_eq)
For Co-60:
A(Co-60) = 300 * exp(-0.693 / 5.27 * t_eq)
Setting the two equations equal to each other and solving for t_eq:
100 * exp(-0.693 / 30.17 * t_eq) = 300 * exp(-0.693 / 5.27 * t_eq)
Simplifying the equation:
1/3.0 * exp(-0.693 / 30.17 * t_eq) = exp(-0.693 / 5.27 * t_eq)
Taking the natural logarithm (ln) of both sides:
-0.693 / 30.17 * t_eq = -0.693 / 5.27 * t_eq
Solving for t_eq:
t_eq ≈ 35.4 years
It will take approximately 35.4 years for both Cs-137 and Co-60 isotopes to decay until their activities are equal. This calculation assumes that there is no other source of radiation or decay affecting the activities of the isotopes.
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if you have 0.23 moles of compound AB2 (312g/mol), how many grams do you have?
Answers
Answer: 71.76
Explanation:
Answer:
71.76
Explanation:
You plug them in the equation said there
Molar Mass and Van't Hoff Factor Determination by Freezing Point Depression 1. Answer the following questions given the scenario described below. Show your work. A student determines the molar mass of an unknown solid by the method described by this experiment. She found that the temperature of a mixture of ice and water, after sufficient mixing to assume equilibration had been achieved, was 0.7 °C on her thermometer. When she added 12.1 g of the unknown solid to the ice/water mixture (so that the unknown solid is the solute in a solution with water as the solvent), the temperature, after rapid and thorough stirring, fell to -3.5 °C on the same) thermometer. She then poured the solution through a Styrofoam cup with holes pokes in the bottom of it into a tared Styrofoam cup to filter out the ice). The mass of the (filtered) solution (no ice] was 93.6 g. a) By how many degrees does the freezing point lower? (What is the fp "depression"?) AT = °C b) What was the molality of the unknown solid in the solution? (Hint: Use the answer in (a), along with the fact that the solvent is water and the freezing point depression constant for water is 1.86 °C/m). Molality = mol/kg I c) What mass of the unknown solid (solute) was in the decanted (filtered) solution? Mass of solid = 8 d) What mass of water was in the decanted (filtered) solution? d) What mass of water was in the decanted (filtered) solution? Mass of water . В e) Using the calculated molality (see above), along with the mass of water in the solution (see above), how many moles of the unknown solid were in the solution? Assume the solid is a nonelectrolyte. Mol solid mol 1) What was the molar mass of her unknown solid, given the data from her experiment (show setup)? Molar mass of solid = g/mol
Answers
The molar mass can be determined by calculating the freezing point depression, finding the molality of the unknown solid in the solution, and using the mass of water and molality to calculate the moles of the solid, which then allows for the calculation of the molar mass.
How can the molar mass of an unknown solid?In the given scenario, the student conducted an experiment to determine the molar mass of an unknown solid using freezing point depression. Here are the answers to the questions:
a) The freezing point depression, ΔT, is calculated by subtracting the final temperature (-3.5 °C) from the initial temperature (0.7 °C): ΔT = -3.5 °C - 0.7 °C = -4.2 °C.
b) The molality (m) of the unknown solid in the solution can be calculated using the formula: ΔT = Kf * m. Rearranging the formula, we have m = ΔT / Kf. Substituting the values, m = -4.2 °C / 1.86 °C/m = -2.26 m.
c) The mass of the unknown solid (solute) in the decanted solution is given as 8 g.
d) The mass of water in the decanted solution can be calculated by subtracting the mass of the unknown solid from the mass of the solution: Mass of water = Mass of solution - Mass of solid = 93.6 g - 8 g = 85.6 g.
e) Using the molality (m) and mass of water (85.6 g), we can calculate the moles of the unknown solid using the formula: moles of solid = molality * mass of water / molar mass of water. Since the solid is a nonelectrolyte, the moles of solid are equal to the moles of the unknown solid.
f) The molar mass of the unknown solid can be calculated by rearranging the formula: molar mass of solid = mass of solid / moles of solid = 8 g / moles of solid. The moles of solid were calculated in the previous step.
The actual calculations were not provided, so the specific numerical values cannot be determined without the actual calculations.
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How many atoms are there in 8.97 grams of lead (Pb)
A. 1.12 x 10^27
B. 0.0433
C. 5.40 x 10^24
D. 2.61 x 10^22
Answers
Answer:D. 2.61 x 10^22
Explanation:
Given that mass of Lead(Pb) = 8.97g
Molar mass of lead =207.2g/mol
No of moles = Mass / molar mass
=8.97g/207.2g/mol
= 0.04329moles
Converting to atoms using Avogadro's number
we know that
1 mole = 6.022 x 1023 atom
Therefore 0.04329 moles of Pb = 0.04329moles x 6.022 x 10^23 atoms
=2.6069 x 10^22
=2.61 x10^22atoms
a conbustion reaction occurs between 8.0 mol o2 and 189 g c2h4 . upon completion of the reaction, is there any c2h4 remaining?
Answers
The chemical reaction between 8.0 mol of O2 and 189 g of C2H4 (ethylene) can be represented as shown below:C2H4 + 3O2 → 2CO2 + 2H2OThe balanced equation for the combustion of C2H4 (ethylene) in oxygen is:C2H4 + 3O2 → 2CO2 + 2H2O.
According to the chemical equation above, 1 mol of C2H4 reacts with 3 mol of O2 to produce 2 mol of CO2 and 2 mol of H2O. Hence, the amount of O2 required for the complete combustion of 8.0 mol of C2H4 will be:3 moles of O2 for 1 mole of C2H48.0 moles of C2H4 require:8.0 mol C2H4 x 3 mol O2/mol C2H4 = 24 mol O2Therefore, 8.0 mol of O2 is sufficient for the combustion reaction.
Therefore, the limiting reagent is C2H4 and the excess reactant is O2. Now, we will calculate the amount of C2H4 used. The molar mass of C2H4 is 28.05 g/mol. So, 189 g of C2H4 is:189 g / 28.05 g/mol = 6.74 mol of C2H4Since the 8.0 mol of C2H4 given in the problem is greater than 6.74 mol of C2H4 calculated above, C2H4 is in excess. Thus, all the C2H4 will not be used up in the reaction, and there will be some C2H4 remaining after the combustion reaction has completed. Hence, some C2H4 will remain after the completion of the reaction.
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Study the timeline.
A timeline. 4.5 billion years ago, Earth is formed. 4.3 billion years ago, Earliest water. 4.1 billion years ago, Single celled life. 3.5 billion years ago, Earliest oxygen and photosynthesis. 2.5 billion years ago, Complex single celled life. 1.5 billion years ago, Multi cellular life. 500 million years ago, Land life. 300 million years ago, Dinosaurs. 200 million years ago, Mammals. 130 million years ago, Flowers. 5 million years ago, Humans.
Based on the timeline, about how many years ago could the oldest mammalian organism have lived?
5 million years
200 million years
1.5 billion years
4.5 billion years
Answers
Answer:
The answer would be 200 million years.
Explanation:
Hope you get this right, Stay safe!
Answer: 200 million years ago
Explanation: 200 million years ago, because when you study the timeline, the first mammals that existed was 200 million years ago.
Which molecule contains the most easily broken carbon-carbon bond? H_2C=CH_2 OF_2C=CF_2 H_3C-CH_3 Triple bond in N2
Answers
H₂C=CH₂ contains the most easily broken carbon-carbon bond.
Which molecule among H₂C=CH₂, OF₂C=CF₂, H₃C-CH₃, and N₂ has the weakest carbon-carbon bond?Among the given options, the molecule with the most easily broken carbon-carbon bond is H₂C=CH₂.
In this molecule, the carbon-carbon bond is a double bond, consisting of one sigma bond and one pi bond. Pi bonds are generally weaker than sigma bonds due to their overlapping electron density being spread out above and below the bond axis. As a result, pi bonds are more susceptible to breakage compared to sigma bonds.
On the other hand, in OF₂C=CF₂, the carbon-carbon bond is also a double bond, but the presence of fluorine atoms enhances the bond strength due to their high electronegativity.
In H₃C-CH₃, the carbon-carbon bond is a single bond, which is stronger than a double bond and less prone to breaking.
The triple bond in N₂ is the strongest among the given options, requiring a significant amount of energy to break.
Therefore, H₂C=CH₂ contains the most easily broken carbon-carbon bond.
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In two or more complete sentences, compare the four different types of organic molecules in living organisms. Write
your answer in the essay box below.
(SCIENCE)
Answers
Answer:
The four different types of organic molecules in living organisms are carbohydrates, lipids, proteins, and nucleic acids. Carbohydrates are composed of carbon, hydrogen, and oxygen atoms and are a source of energy for the body. Lipids are composed of carbon, hydrogen, and oxygen atoms and are important for energy storage, insulation, and cell membrane structure. Proteins are composed of amino acids and are involved in various biological functions, such as enzyme catalysis, muscle contraction, and immune response. Nucleic acids are composed of nucleotides and store genetic information. All four types of organic molecules are essential for life and work together to maintain biological processes.
What do Ivan Pavlov and Erik Erikson have in common?
Answers
Answer:
I don't know the exact answer you are looking for
1.) What is a scientific method
2.) What must you always do if you want your statement taken seriously
3.) The scientific method starts with a.
Answers
Which of these statements about reaction rates is accurate?
All chemical reactions occur at a fast rate.
All chemical reactions occur at different rates.
All chemical reactions occur at a slow rate.
All chemical reactions occur at the same rate.
Answers
Answer:
All chemical reactions occur at different rates
What is the sum of the coefficients of these reaction, after balancing?
a) Pb(NO3)2 + Na3PO4 -----> Pb3(PO4)2 + NaNO3 (OR Pb(N O3)2 + N a3P O4 right arrow Pb3(P O4)2 + N a N O3)
b) NH4I + Cl2 -----> NH4Cl + I2 (OR NH4I + Cl2 right arrow NH4Cl + I2)
c) Al(OH)3 + H2SO4 -----> Al2(SO4)3 + H2O (OR A l(O H)3 + H2S O4 right arrow A l2(S O4)3 + H2O)
Answers
In the reaction a), the number of molecules of each reactant and product are as follows:
Reactants:
Pb(NO3)2: 1Na3PO4: 3
Products:Pb3(PO4)2: 1NaNO3: 1
Thus the sum of the coefficients is equal to: 1+3+1+1=6. Therefore, the answer is 6.
For b) the coefficients are:
NH4I: 1Cl2: 1NH4Cl: 1I2: 1
The sum of the coefficients in b) is: 1+1+1+1=4. Hence, the answer is 4.
For c), the coefficients are:
Al(OH)3: 1H2SO4: 1Al2(SO4)3: 1H2O: 3
Therefore, the sum of the coefficients in c) is: 1+1+1+3=6. Thus, the answer is 6.
a) Pb(NO3)2 + Na3PO4 ---> Pb3(PO4)2 + NaNO3
The coefficients of the reactants and products are as follows;
Pb(NO3)2 + Na3PO4 → Pb3(PO4)2 + NaNO31 3 1 1
For the reactants, the sum of the coefficients is 1 + 3 = 4
For the products, the sum of the coefficients is 1 + 3 = 4
Therefore, the sum of the coefficients of the given reaction is 4 + 4 = 8.
The sum of the coefficients of the balanced reaction is equal to the total number of reactant molecules and product molecules present in the balanced reaction.
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A student rode in a car for 3 hours and traveled 135 miles. What was the driver's
average speed?
50 mph
45 mph
405 mph
0.02 mph
Answers
Answer:
45
Explanation:
135 divided by 3 is 45
I hope it's right! Don't get discouraged if you can't find an answer!
Vhat determines a substance's state of matter?
Answers
H2
Define the Omnipotent view of management ( 5 pts)
Define the Symbolic view of management ( 5 pts)
What works best, in your opinion for the current state that ABC CO is in ? ( explain and
justify)–5pts
The importance of setting the right organization culture is clearly an urgent need for
ABC -Describe what kind of culture should be created – what will be its characteristics ?
(5 pts)
How about the organizational environment ? (customers , suppliers , competitors ,
economic , legal , socio cultural) - what needs to be done ? ( 5 pts)
Answers
The Omnipotent view of management refers to the belief that managers are directly responsible for an organization's success or failure. According to this view, managers have the power and control to make decisions that will significantly impact the organization's performance.
In terms of the organizational environment, ABC CO needs to focus on several aspects. Firstly, it should prioritize building strong relationships with customers by understanding their needs and delivering value through its products or services. Secondly, maintaining good relationships with suppliers is crucial to ensure a reliable supply chain and access to necessary resources. Thirdly, keeping a close eye on competitors is essential to stay competitive and identify opportunities for differentiation. Lastly, monitoring and adapting to economic, legal, and socio-cultural factors is vital to ensure compliance with regulations and aligning the organization with societal trends and expectations.
In conclusion, the Omnipotent view of management emphasizes the influence of managers in shaping organizational outcomes, while the Symbolic view recognizes the significance of external factors. For the current state of ABC CO, a balanced approach that considers both internal and external factors would be beneficial. The culture should promote collaboration, innovation, and adaptability, while the organization should focus on building strong relationships with customers, suppliers, and competitors while adapting to the economic, legal, and socio-cultural environment.
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Grey-coloured iron powder was heated in reddish-brown bromine vapour. A yellowish-green powder was formed. State if the yellowish-green powder is an element, a compound or a mixture. Explain your answer.
Answers
The yellowish-green powder is a compound because two elements (iron and bromine) chemically combined to form it.
What is a compound?A compound in chemistry is a substance formed by chemical bonding of two or more elements in definite proportions by weight.
This means that a compound is formed by the chemical bonding of two or more elements.
According to this question, a grey-coloured iron powder was heated in reddish-brown bromine vapour to form a yellowish-green powder.
The grey-coloured iron is an element that combined with the reddish-brown bromine gas. This suggests that two elements combined. It can be said to be a chemical reaction because a colour change was observed.
Therefore, the yellowish-green powder is a compound because two elements (iron and bromine) chemically combined to form it.
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An excerpt from a fantasy periodic table, including molar masses, is shown below. Using this information, what is the molecular formula for a substance with a molar mass of 1644.28 g/mol and an empirical formula of Bg2DGr3?
Bg8D4Gr12
Bg10D5Gr15
Bg4D2Gr6
Bg6D3Gr9
Answers
The molecular formula for the substance with a molar mass of 1644.28 g/mol and an empirical formula of Bg₂DGr₃ is Bg₁₀D₅Gr₁₅.
To determine the molecular formula, we need to calculate the molecular weight of the empirical formula, which can be done by adding up the molar masses of the atoms in the empirical formula.
The molar mass of Bg₂DGr₃ is:
(2 x 10.81 g/mol) + (3 x 2.01 g/mol) + (3 x 72.63 g/mol) = 328.50 g/mol
Next, we can divide the given molar mass by the empirical formula mass to get the ratio between the empirical formula and the molecular formula:
1644.28 g/mol ÷ 328.50 g/mol = 5
This tells us that the molecular formula contains 5 times as many atoms as the empirical formula. To find the molecular formula, we simply multiply the subscripts in the empirical formula by 5:
Bg₁₀D₅Gr₁₅
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explain the difference in behavior between water and the buffer with addition of acid or base. are your results as expected? why or why?
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The adding of an acid or base to a buffer seems to have no effect on the pH of the buffer. In contrast, going to add acid or base to unbuffered water drastically changes the pH.
Any hydrogen-containing substance skilled of making a donation a proton (hydrogen ion) to that other substance is defined as an acid. A base is a compound or ion that really can accept an acid's hydrogen ion. The sour flavours of weak acids is generally described by the contaminant that emits hydrogen ions in water and formation salts by incorporating with these metals. Acids have a bitter aftertaste and cause certain dyes to turn red. buffer is an aqueous solution that withstands adjustments in pH upon on the addition of either an acid or a base". Furthermore, adding water to a buffer or going to allow it to evaporate from of the buffer has no significant effect just on pH of the buffer.
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