in the spaces provided, write the formula of the conjugate base or conjugate acid. acid hno3 hso4- hc2h3o2 conjugate base nh3 hso4-

Answer: The researchers may not be able to watch the entire area at once.

Explanation:

because!!!

To calculate the number of millimoles of phenyl bromide present, we need to first convert the given quantity of phenyl bromide (1.4555 g) into moles by dividing it by its molar mass.

The molar mass of phenyl bromide is the sum of the molar masses of its constituent atoms, which is 157.01 g/mol.

Therefore, the number of moles of phenyl bromide present is:

1.4555 g / 157.01 g/mol = 0.0092711 mol

To convert this into millimoles, we need to multiply it by 1000:

0.0092711 mol x 1000 = 9.2711 mmol

Therefore, there are 9.2711 millimoles of phenyl bromide present in the Grignard reaction. It is important to accurately measure the amount of reactants involved in a reaction to determine the stoichiometry and yield of the reaction.

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Answer:

Lung function decreses at a faster rate for young people (last answer choice)

Explanation:

Answer: are you in times4learning?

Explanation:

Answer:

Mercury is a chemical element with symbol Hg and atomic number 80. Classified as a transition metal, Mercury is a liquid at room temperature.

...

Explanation:

Answer:

Mercurous nitrate!

The specific rate constant of the second-order irreversible reaction is 122.34 L/mol.s.

A second-order irreversible reaction A-3R was studied in a PFR reactor, where reactant pure A (CAO=0.121 mol/lit) is fed with an inert gas (40%), and flow rate of 1 L/min (space velocity of 0.2 min-1). Product R was measured in the exit gas as 0.05 mol/sec.

To calculate the specific rate constant, we use the following equation:0.05 mol/sec = -rA * V * (1-X). The negative sign is used to represent that reactants decrease with time. This equation represents the principle of conservation of mass.Here, V= volume of the PFR. X= degree of conversion. And -rA= the rate of disappearance of A= k.CA^2.To calculate the specific rate constant, k, we need to use a few equations. We know that -rA = k.CA^2.We can also calculate CA from the volumetric flow rate and inlet concentration, which is CAO. CA = (CAO*Q)/(Q+V)The volumetric flow rate, Q = V * Space velocity (SV) = 1 * 0.2 = 0.2 L/min.

Using this, we get,CA = (0.121*0.2)/(1+0.2) = 0.0202 mol/LNow, we can substitute these values in the equation of rate.0.05 = k * (0.0202)^2 * V * (1 - X)The volume of PFR is not given, so we cannot find the exact value of k. However, we can calculate the specific rate constant, which is independent of volume, and gives the rate of reaction per unit concentration of reactants per unit time.k = (-rA)/(CA^2) = 0.05/(0.0202)^2 = 122.34 L/mol.

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The statement is supported by the data, is that the youngest rocks on the seafloor were at the mid-ocean ridge.

The data collected by scientists regarding rock ages along a mid-ocean ridge seafloor with mid-ocean ridge showing age of rock increasing the further from the ridge.

From the data, they found that the youngest rocks on the seafloor were at the mid-ocean ridge and the rocks get older with distance from the ridge crest.

Thus, the statement is supported by the data, is that the youngest rocks on the seafloor were at the mid-ocean ridge.

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Answer:

Explanation:

Answer:

A geologist visits an environment to make observations. The scientist predicts that the environment will undergo secondary succession. What did the geologist likely observe in the environment to draw this conclusion? Check all that apply a

The geologist saw rocks and gravel.

b

The geologist saw cooled lava flows.

c

The geologist saw remaining soil.

d

The geologist saw a few plant species.

e

The geologist saw a few small insects.

The percent composition of oxygen in tripotassium phosphate is 30.15%.

Percent composition  is defined as a convenient way to record concentration of solution.It is a expression which relates mass of an element  to compound as,mass of element/mass of compound ×100.

In the given compound of tripotassium phosphate the molar mass is 212.27 g/mole, while that of oxygen is 16×4=64 g/mole.Thus, the percent composition of oxygen in tripotassium phosphate is 64/212.27×100=30.15%.

Thus, the percent composition of oxygen in tripotassium phosphate is 30.15%.

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Answer:

Thermal energy typically flows from a warmer material to a cooler material.

Explanation:

the producers' surplus at a price of $14 and MC = $6 would be $8.

The first step is to find the quantity supplied at the given price of $14. Substituting p = 14 in the supply equation, we get:
14 = 10 + 2q
4 = 2q
q = 2
Therefore, at a price of $14, the quantity supplied is 2 units. To calculate the producers' surplus, we need to find the area between the supply curve and the price line, up to the quantity supplied. This is a right triangle with base 2 (the quantity) and height (p - MC), where MC is the marginal cost of producing one unit. The marginal cost is not given, so we cannot calculate the exact value of producers' surplus. However, we can say that it will be positive as long as the price is above the marginal cost. If we assume a marginal cost of $6, for example, then the height of the triangle would be 14 - 6 = 8. The area would be (1/2) x 2 x 8 = $8. Therefore, the producers' surplus at a price of $14 and MC = $6 would be $8.

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Answer:

c

Explanation:

Tetraphosphorus trisulfide is the correct name for \(P_4S_3\). Hence, option C is correct.

IUPAC nomenclature is based on naming a molecule's longest chain of carbons connected by single bonds, whether in a continuous chain or in a ring.

Tetraphosphorus trisulfide is the correct name for \(P_4S_3\).

Hence, option C is correct.

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Respiration deals with the gaseous exchange that occur between the individuals and the environment.

The term respiration deals with the gaseous exchange that occur between the individuals and the environment. The individuals take in a gas from the environment and pass out a gas to the environment. This is the way in which the balance of the universe is maintained.

Now, plants take in carbon dioxide and give out oxygen whereas animals take in oxygen and give out carbon dioxide. By so doing, the delicate carbon - oxygen balance in nature is maintained unless it is upturned by anthropogenic activities.

The following fill in the blanks as requested in the question;

a) Inhalation and exhalation'

b) trachea

c) carbon dioxide

d) leaves and stomata

e) xylem and phloem

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Answer:

a) inhalation and exhalation

b) trachea

c) carbon dioxide

d) leaves and stomata

e) xylem and phloem

A LOAEL is defined as the lowest dose that demonstrates a significant increase in an observable adverse effect. The term LOAEL stands for "Lowest Observed Adverse Effect Level."

When testing chemicals and other substances for toxicity, the goal is to determine the concentration or dose at which adverse effects begin to appear. The LOAEL is the lowest dose at which an adverse effect is observed. This value can be used to establish a safe level of exposure to a substance.
To determine the LOAEL, a series of tests are conducted in which different doses of the substance being tested are administered to test animals. The animals are observed for any adverse effects, such as changes in behavior, weight loss, or organ damage. The lowest dose at which an adverse effect is observed is the LOAEL.
It is important to note that the LOAEL is a relative measure of toxicity. It only provides information on the dose at which an adverse effect is first observed and not on the severity of the effect. In addition, the LOAEL may vary depending on the species tested and other factors.
In summary, the LOAEL is the lowest dose at which an observable adverse effect is detected. This value is used to establish a safe level of exposure to a substance.

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Answer:

The TV signal.

Explanation: Hope this is right! :)

Answer: The specimens appears larger with a higher magnifications because a smaller area of the object is spread out to cover the filed view of your eye.

Explanation:

Answer:

In the 2nd millennium, the eastern coastlines of the Mediterranean are dominated by the Hittite and Egyptian empires, competing for control over the city states in the Levant (Canaan)

Explanation:

because it is

Therefore, the equilibrium constant for the reaction HCN(g) + 2 H2(g) → CH3NH2(g) at 655 K is 1.48 x 10^7.

To determine the equilibrium constant for this reaction, we need to use the following equation:
ΔG° = -RTln(K)
where ΔG° is the standard free energy change, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.
First, we need to calculate the standard free energy change ΔG° using the following equation:
ΔG° = ΔH° - TΔS°
where ΔH° is the standard enthalpy change and ΔS° is the standard entropy change.
Given that ΔH° = -158 kJ and ΔS° = -219.9 J/K, we can convert ΔS° to kJ/K by dividing by 1000:
ΔS° = -0.2199 kJ/K
Substituting these values into the equation, we get:
ΔG° = -158 kJ - 655 K(-0.2199 kJ/K)
ΔG° = -3.79 kJ/mol
Next, we can use the equation ΔG° = -RTln(K) to solve for K:
K = e^(-ΔG°/RT)
Substituting the values we have:
K = e^(-(-3.79 kJ/mol)/(8.314 J/K/mol x 655 K))
K = 1.48 x 10^7
Therefore, the equilibrium constant for the reaction HCN(g) + 2 H2(g) → CH3NH2(g) at 655 K is 1.48 x 10^7.

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Answer:

17190 years          

Explanation:

The exponential decay equation is:

\( N_{t} = N_{0}e^{-\lambda t} \)          

\( \frac{N_{t}}{N_{0}} = e^{-\lambda t} \)

Where:

N(t) is the quantity at time t

N₀ is the initial amount

λ is the decay constant = ln(2)/t(1/2)

t(1/2) is the half-life    

Since the ratio of carbon-14 to carbon-12 is 12.5%, we have that:

\( \frac{N_{t}}{N_{0}} = e^{-\lambda t} \)

\( \frac{0.125N_{0}}{N_{0}} = e^{-\lambda t} \)

\( ln(0.125) = -\lambda t \)

By solving the above equation for t:

\( t = \frac{ln(0.125)}{-\lambda} = \frac{ln(0.125)}{-ln(2)/t_{1/2}} = \frac{5730 y* ln(0.125)}{-ln(2)} = 17190 y \)

Therefore, the site is 17190 years old.  

I hope it helps you!

Answer:

Erythrocytes

Erythrocytes do not contain a nucleus. This would make answer choice "A" correct. Erythrocytes are red blood cells and these cells differ from the other cells of the body because of the absence of the nucleus. All the other cells noted have nuclei.

Explanation:

Have A Wonderful Day !!

Answer:a. Prokaryotes

Explanation:

The electronic configuration for an atom of oxygen is:

1s2 2s2 2p2

The correct options is:

C. This specific electron configuration has one unpaired electron.

Electron configuration can be defined as the specific arrangement of negatively charged electrons in different energy levels around atomic nuclei.

The correct statements about this electron configuration are:

A. The atom of oxygen represented by this configuration will have a charge: This statement is incorrect. The electron configuration provided is for a neutral oxygen atom, which means it has no charge.

B. This specific electron configuration has three unpaired electrons: This statement is incorrect. The 2p subshell contains a total of 4 electrons, which are arranged in 2 orbitals with opposite spins. This means that there are 2 paired electrons and 2 unpaired electrons, not 3.

C. This specific electron configuration has one unpaired electron: This statement is correct. The 2p subshell contains 2 orbitals, each of which can hold a maximum of 2 electrons. Since the 2p subshell contains 4 electrons, there are 2 paired electrons and 2 unpaired electrons, with one unpaired electron in each of the two 2p orbitals.

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The shielding effect is not influenced by electronic configuration because the shielding effect indicates a blockage in the attraction. Conversely, electronic configuration refers to the arrangement of electrons.

The shielding effect can be defined as 'blocking valence shell electron (e-) attraction', which is due to the shells located between the nucleus and the valence shells.

Conversely, electronic configuration refers to the differential arrangement of the e- in different energy levels around a given nucleus.

Electronic configurations are used to represent one or more e- moving independently in a given orbital, thereby evidencing how many e- an atom contains and how they are positioned in their corresponding shells.

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options (a) and (c) are true, and option (b) is false. To solve this problem, we need to rewrite the given equation of the circle in standard form by completing the square.

x² + y² – 2x – 8 = 0

x² – 2x + y² = 8

(x – 1)² + y² = 9

Now, we can see that the center of the circle is (1, 0) and the radius is 3. Therefore, the following statements are true:

The radius of the circle is 3 units.

The center of the circle does not lie on the y-axis.

The standard form of the equation is (x – 1)² + y² = 9.

So, options (a) and (c) are true, and option (b) is false.

Regarding the last option (e), the equation x² + y² = 9 represents a circle with a center at the origin (0,0) and a radius of 3. Since the radius of the given circle is also 3, we can say that the two circles have the same radius, but the centers are different.

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This means that the exit concentration of salt after 30 minutes is 0.15 or 150 ppm.

To solve this problem, we need to use the mass balance equation. The mass balance equation states that the amount of salt entering the mixer equals the amount of salt leaving the mixer.
Let C be the concentration of salt in the exit solution after 30 minutes. The amount of salt entering the mixer per minute is (10 kg/min) x (15% salt) = 1.5 kg/min. The amount of salt leaving the mixer per minute is (10 kg/min) x C.
Therefore, we can write the following equation:
1.5 kg/min = 10 kg/min x C
Simplifying the equation, we get:
C = 0.15
It is important to note that the density of alcohol is assumed to be constant due to the low salt concentration. If the salt concentration was higher, the density of the solution would change and the calculations would be more complex.
In summary, the exit concentration of salt after 30 minutes is 150 ppm.

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The molality of the following solution can be calculated by using the formula given below:

molality (m) = moles of solute / mass of solvent (kg)

Therefore, we can calculate the molality of 3.7 M NaCl as follows:

The molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Number of moles of NaCl = (3.7 mol / L) × 1 L = 3.7 mol

Mass of NaCl = 3.7 mol × 58.5 g/mol = 216.45 g

Density of the solution = 1.00 g/mL

Volume of the solution = mass of solution / density of solution

= 216.45 g / 1.00 g/mL

= 216.45 mL

= 0.21645 L

Mass of solvent = mass of solution - mass of solute

= 216.45 g - 216.45 g

= 0 g (As NaCl is solute)

Therefore,

molality = 3.7 mol / 0.000 kg (because mass of solvent is 0.000 kg) = undefined.

Note: Molality cannot be defined for a solution with a mass of solvent that is zero or very close to zero. Therefore, the main answer is undefined.

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The percentage (w/v) of dextrose in the solution is approximately 1.9817%. To determine the percentage (w/v) of dextrose in a solution with a given osmolarity, we need to calculate the amount of dextrose present in 100 mL of the solution.

First, we convert the osmolarity from mosmol/L to mosmol/100 mL:

100 mosmol/L = 100 mosmol/100 mL

Next, we calculate the number of moles of dextrose present in 100 mL of the solution:

Number of moles = Osmolarity (in mosmol/100 mL) / 1000

Number of moles of dextrose = 100 mosmol/100 mL / 1000 = 1 mosmol/100 mL

Now, we can calculate the mass of dextrose present in 100 mL of the solution:

Mass of dextrose = Number of moles of dextrose * Molecular weight of dextrose

Mass of dextrose = 1 mosmol/100 mL * 198.17 g/mol = 1.9817 g/100 mL

Finally, we can calculate the percentage (w/v) of dextrose:

Percentage (w/v) = (Mass of dextrose / Volume of solution) * 100

Percentage (w/v) = (1.9817 g/100 mL / 100 mL) * 100 = 1.9817%

Therefore, the percentage (w/v) of dextrose in the solution is approximately 1.9817%.

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Answer:

When a sample of a gas is heated at constant pressure, the average kinetic energy of its molecules increases and the volume o the gas increases According to the kinetic theory of gases, which assumption is correct

Explanation:

my fingers hurt

Answer: A.En Hedu'Anna

Answer:

En Hedu’Anna!

Explanation:

Magnesium bromide (MgBr2) is a binary ionic compound that breaks up into two ions when dissolved in water. The compound dissociates into magnesium (Mg^2+) ions and bromide (Br^-) ions.

The balanced chemical equation for the dissociation of MgBr2 in water can be written as:

MgBr2 (s) -> Mg^2+ (aq) + 2 Br^- (aq)

So, in solution, MgBr2 breaks up into one magnesium ion and two bromide ions. This ionic dissociation is a common characteristic of many ionic compounds, and it is what gives them their characteristic properties, such as high melting and boiling points, and the ability to conduct electricity when dissolved in water.

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