In the situation below, ring is stationary in space and initially sits perpendicular to large magnetic field B1 0.59 T. After mT The area of the ring is A 0,61 m2: (a) What the Initial flux, Di when the ring sits In; (b) What the flnal flux, Bi When the ring slt; (c) What is the change flux between the Initial and fina scenarios

The following is required to have a successful collision: ii. A collision of the appropriate orientation must occur,  iii. Transfer of energy must occur in a collision such that the molecule has energy equal to or greater than the activation energy, v. Formation of products.

Collision is when two objects come in contact with one another and experience a force as a result. This force can be a direct result of the objects hitting each other, or it can be the result of the objects exerting a force on one another in order to move away. In either case, the objects experience a momentary change in their respective velocities.

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If the coefficient of kinetic friction between Josh's sled and the snow is 0.08, he slides 6.97 meter from the base of the hill.

To find how far from the base of the hill Josh's sled ends up, we need to first find the speed of the sled at the bottom of the hill using the conservation of energy principle,

mgh = (1/2)mv², plugging in the values given in the problem, we get,

m(9.81 m/s²)(3.5 m) = (1/2)mv²

Simplifying and solving for v, we get,

v = √(2gh)

v = √(2(9.81 m/s²)(3.5 m))

v = 8.29 m/s

Now we can use the kinematic equation,

d = vt - (1/2)at, to find how far the sled slides on the horizontal patch of snow before coming to a stop, where d is the distance traveled, v is the initial velocity (8.29 m/s), a is the acceleration due to friction (-μg), and t is the time it takes to come to a stop (which we can find by setting v = 0 and solving for t),

0 = 8.29 m/s - μg*t

t = 8.29 m/s / μg

Substituting this value of t back into the kinematic equation, we get,

d = (8.29)(8.29/μg) - (1/2)μg(8.29/μg)²

d = 6.97 m

Therefore, Josh's sled ends up 6.97 meters from the base of the hill.

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Less reflective material is sprayed thickly in one-way glass, unlike a regular mirror, the glass is not entirely opaque. The glass reflects about half of the light that hits it while letting through about half of it.

An actual or hypothetical image is produced by a mirror, which is a reflecting surface that reflects light. A mirror reflects the identical image of a thing when it is held up in front of it. The incident rays originate from the object, and the image is made by the reflected rays. The intersection of the light beams determines whether the images are real or simulated. While virtual images are created when light beams from a point appear to diverge, real pictures are created when light rays actually cross.

We may establish the direction of the light as it moves to a specific location on a photograph of an object by using ray diagrams.

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Based on the provided information, the statements about t1 and t2 which is correct is T2 > T1 because an unbalanced clockwise torque is needed to accelerate the wheel clockwise. (Option B)

Torque refers to a measure of the force that can cause an object to rotate about an axis.  It is the rotational equivalent of linear force. Similar to linear force which causes an object to accelerate in linear kinematics, torque causes an object to acquire angular acceleration. Hence, the angular momentum of the body refers to the moment of momentum about the axis of rotation. In the given figure, when the wheel is released from rest and rotates clockwise from left to right, the torque T2 must be greater than torque T1 as the unbalanced clockwise torque is needed to accelerate the wheel clockwise.

Note: The question is incomplete as it is missing options which are a. T1 = T2 because both blocks have the same acceleration. b. T2 > T1 because an unbalanced clockwise torque is needed to accelerate the wheel clockwise. c. T1 > T2 because m1 is farther from the wheel than m2. d. T1 = T2 because the wheel has mass. e. T1 > T2 because m1 accelerates upward.

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Answer:

marijuana effects on Serotonin and GABA

Explanation:

A psychoactive drug is a chemical that changes our states of consciousness, and particularly our perceptions and moods. These drugs are commonly found in everyday foods and beverages, including chocolate, coffee, and soft drinks, as well as in alcohol and in over-the-counter drugs, such as aspirin, Tylenol, and cold and cough medication. Psychoactive drugs are also frequently prescribed as sleeping pills, tranquilizers, and antianxiety medications

These drugs are thought to raise serotonin levels by inhibiting the reuptake process that brain cells use to remove excess serotonin. But several lines of evidence suggest that marijuana has negative effects on serotonin levels and may block the action of serotonin-boosting

The drug activates CB1 receptors on GABAergic and glutamatergic neurons in the ventral tegmental area (VTA), inhibiting the activity of both. CB1 inhibition of GABA neurons promotes, and inhibition of glutamate dampens, VTA dopaminergic neurons' activity and dopamine release in the NAC.

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Answer:

20 kg*m/s

Explanation:

we're looking for the change in the cars momentum . the formula to identify the cars momentum is Δp=m*vf-m*vi . In this case m= mass , vf= velocity final, and vi= velocity initial . The mass is how much the car weighs , which is 4 kg . Velocity final would be 8 m/s since that's how fast it last was . Velocity initial would be 3 m/s since it had first started at that speed . Now we can jus plug it into the formula .

m= 4 kg

vf= 8 m/s

vi= 3 m/s

Δp= (4)*(8) - (4)*(3)

Δp= 32-12

Δp= 20 kg*m/s

hope this helps .

Answer:

e

Explanation:

D No, Crystal is incorrect. The other two light bulbs would remain lit because the current flowing through them would increase.

Parallel circuit

The sort of circuit you will likely see most frequently is the parallel circuit. In one manner or another, loads in power distribution networks are often linked in parallel with one another.

The terminals of each separate load device are connected to create a parallel circuit, which ensures that each component receives the same voltage.

In each branch, the voltage is the same.

Current can go via three different routes (branches), each of which travels from the negative terminal to the positive terminal.

In contrast to a series circuit, if any branch or component in a parallel circuit is opened, current still flows to the other devices in the circuit.

Voltage, current, and resistance have three essential interactions in parallel circuits.

Voltage

Each load resistor functions as a separate branch circuit in a parallel circuit, allowing each branch to "see" the whole supply voltage.

The voltage across each branch and the overall voltage of a parallel circuit are equal.

This connection may be stated as follows:

ET = E1 = E2 = E3…

Current

In a parallel circuit, current can travel through many paths. The quantity of load resistors linked in parallel determines the number of current routes.

Resistance

When more resistances are linked in series, the overall circuit resistance decreases as a result.

Any individual resistance value in a parallel circuit has a lower value than the net resistance.

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We will have the following:

First, we recall that momentum is given by:

So:

Then:

[Let's assume that when astronaut 2 moved 12 meters = t]

Then:

Finally, the total distance will be:

The concrete walls' strength, stability, and resistance to water and fire damage can help to reduce the effects of natural phenomena on buildings.

Concrete home construction gives a wall structure that is more durable than steel and wood. Concrete walls do not deteriorate when exposed to moisture from wind-driven rain, diffusion, or airflow. Contrary to steel, concrete does not rust when exposed to moisture. Termites are resistant to concrete barriers.

Powerful building materials like steel and concrete support the home's façade, and ceilings made of western red cedar temper the industrial style inside. These constructions are resistant to natural calamities since they are constructed of sandbags, barbed wire, and soil.

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Answer:

true

Explanation:

these are not the only parts of the atmosphere, i dont know the full list but i know these arent the only parts

Answer:

The truck will undergo the largest change in momentum if it has a greater mass than the small car.

Explanation:

The change in momentum of an object can be calculated using the equation:

Δp = m * Δv

where Δp represents the change in momentum, m represents the mass of the object, and Δv represents the change in velocity.

Since we are comparing the change in momentum of the car and the truck, we need to consider the masses of both vehicles.

Let's assume the mass of the car is represented by m_car, and the mass of the truck is represented by m_truck.

Since both vehicles collide head-on, the change in velocity (Δv) will be the difference between their initial velocities, considering that they are moving in opposite directions:

Δv = v_truck - v_car

Now, let's compare the change in momentum for the car and the truck:

For the car:

Δp_car = m_car * Δv

For the truck:

Δp_truck = m_truck * Δv

Comparing the magnitudes of the change in momentum, we can neglect the negative sign:

|Δp_car| = |m_car * Δv|

|Δp_truck| = |m_truck * Δv|

Since both Δv and Δp are positive values, we can conclude that the vehicle with the greater mass will undergo the largest change in its momentum.

Therefore, if the mass of the truck (m_truck) is greater than the mass of the car (m_car), then the truck will undergo the largest change in its momentum. Conversely, if the mass of the car is greater, then the car will undergo the largest change in its momentum.

Explanation:

Given : L=2 m A=0.0225mm

2

=0.0225×10

−6

m

3

F=100 N

Stress =

A

F

=

0.0225×10

−6

100

=4.4×10

9

N/m

2

Energy stored U=

2

1

×

Y

(stress)

2

×AL

Or U=

2

1

×

20×10

10

(4.4×10

9

)

2

×(0.0225×10

−6

)(2)=2.222 J

The minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

Deceleration is defined as  the decrease in speed as the body moves away from the starting point.

The minimum deceleration required can be calculated using the equation of motion:

d = v^2 / (2 * a)

where d is the distance, v is the initial velocity, and a is the acceleration.

Rearranging the equation to solve for a:

a = v^2 / (2 * d) = (3500 m/s)^2 / (2 * 35 m) = 40000 m/s^2

In conclusion, , the minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

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Answer:

If a compound if IONIC then it will dissolve quickyl/easily in water and have a higher boiling point.

If a compound if COVALENT then it will dissolve slowly in water and have a lower boiling point.

We can measure the flow rate of various liquid by pouring the liquid down an incline and time how long it takes each one to reach the bottom.

option C.

The flow rate of a liquid is how much fluid passes through an area in a particular time.

Flow rate can be articulated in either in terms of velocity and cross-sectional area, or time and volume. As liquids are incompressible, the rate of flow into an area must be equivalent to the rate of flow out of an area.

Generally, the best equipment to measure the flow rate of a liquid is flow meters. In the absence of flow meters, we can other methods such as the one given in the options.

We can pour the various liquid down an incline and time how long it takes each one to reach the bottom.

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A photon is a tiny energy packet of electromagnetic radiation, also referred to as a light quantum.

1) Ultraviolet radiation is commonly used in sanitizing hospitals because, viruses, methicillin-resistant Staphylococcus aureus, and vancomycin-resistant enterococci are all susceptible to the germicidal effects of UV-C.

2) According to the photon theory, electrons that have been stimulated return to the ground state to create atomic emission spectra. Light or the photon is the energy that is released when electrons drop to a lower energy level.

3) To characterise the atomic characteristics of light, Albert Einstein used Planck's quantum theory.

Planck's hypothesis is supported by Einstein's demonstration that electromagnetic radiation, such as light, has both wave-like and particle-like properties.

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The height of the 4 kilograms book with a gravitational potential energy of 98 Joules is approximately 2.5 meters.

Gravitational potential energy is simply the potential energy an object possessse in relation to another object due to gravity.

It is expressed as;

U = m × g × h

Given that:

Gravitational potential energy of the book U = 98 Joules

Mass of the book m = 4 kilograms

Acceleration due to gravity g = 9.8 m/s²

Height h = ?

Plug these values into the above formula and solve for height.

U = m × g × h

h = U / ( m × g )

h = 98  / ( 4 × 9.8 )

h = 98/39.2

h = 2.5 meters

Therefore, its height is 2.5 meters.

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The system of lenses' created picture is 80 cm to the left of the diverging lens.

The reciprocal of a lens's focal length is said to be its power. A parallel beam of light can be strongly converged or diverged by a lens with a short focal length. If the lens's focal length is 1 m, its power is 1 diopter. If the lens's focal length is 1 m, its power is 1 diopter.

We can use the thin lens equation to determine the image position:

1/f = 1/o + 1/i

For the converging lens with focal length f1 = 40 cm, we have:

1/40 cm = 1/60 cm + 1/i1

Solving for i1, we get:

i1 = 120 cm

For the diverging lens with focal length f2 = -40 cm, we have:

1/-40 cm = 1/120 cm + 1/i2

Solving for i2, we get:

i2 = -80 cm

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tbm queria saber essa pergunta!!

Answer: 0.5J

Explanation:

We can use the formula for the potential energy stored in a spring:

U = (1/2) k x^2

where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.

Since we want to compress the spring, x will be negative, and we need to find the potential energy change between the uncompressed length and a compression of 10 cm:

U = (1/2) k (0.1 m)^2 - (1/2) k (0 m)^2

U = (1/2) (100 N/m) (0.1 m)^2 - (1/2) (100 N/m) (0 m)^2

U = 0.5 J

So the work required to compress the spring from its uncompressed length to x = 10 cm is 0.5 J.

The amount of work required by the spring to compress it from its uncompressed length (x = 0) to x = 10 cm is 0.5 J.

In order to compress a spring, the following formula must be used:

Work is equal to (1/2)*k*(xf² - xi²)

where:

xi = starting position = 0 m

xf = final position = 10 cm = 0.1 m k = spring constant = 100 N/m

By entering these values, we obtain:

W = (1/2) * 100 N/m * (0.1 m)² = 0.5 J

Hence, it takes 0.5 J of work to compress the spring from its uncompressed length to x = 10 cm (joules).

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The speed of the roller coaster at the bottom of the hill is 33.9 m/s.

The conservation of mechanical energy is used to determine the speed of the roller coaster at the bottom of the hill, as there is no friction. According to the law of conservation of energy, mechanical energy is constant at all points in a frictionless environment.Let's look at the equation below:PEg + KE = PEg + KEwhere PEg is gravitational potential energy and KE is kinetic energyThe kinetic energy is maximum and the gravitational potential energy is zero when the roller coaster is at the bottom of the hill. The gravitational potential energy is highest when the roller coaster is at the top of the hill, with its potential energy equal to its kinetic energy when it reaches the bottom of the hill.Initially, the roller coaster is at rest at the top of the hill. The gravitational potential energy of the roller coaster is transformed into kinetic energy as it descends the hill. We can calculate the speed of the roller coaster using the law of conservation of energy.Solution:Given,Height of the hill, h = 59.3 mGravitational acceleration, g = 9.8 m/s²Mass of roller coaster, m = 2000 kgWe need to find the speed of the roller coaster at the bottom of the hill, v.To begin, calculate the potential energy at the top of the hill.Potential energy at the top of the hill = mgh Where m is the mass of the roller coaster, g is the acceleration due to gravity, and h is the height of the hill.

The potential energy at the top of the hill is given by:PEg = mgh= 2000 kg × 9.8 m/s² × 59.3 m= 1.15 × 10⁶ JNow, let's figure out the velocity at the bottom of the hill.Using the conservation of energy, we can write,PEg = KE + KEwhere PEg is gravitational potential energy and KE is kinetic energyThe gravitational potential energy is equal to the kinetic energy.KE = PEg= 1.15 × 10⁶ JKE = 1/2 × mv²Where m is the mass of the roller coaster and v is the velocity of the roller coaster.Substituting the given values in the above equation, we get;1.15 × 10⁶ = 1/2 × 2000 × v²v² = (2 × 1.15 × 10⁶) / 2000v² = 1150v = √1150v = 33.9 m/s.

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The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.

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The angle to the horizontal the ball was launched at can be determined using trigonometry. Once you have the initial horizontal and vertical velocities, you can use the tangent function to calculate the launch angle.

Velocity is a physical quantity that describes the rate at which an object changes its position. It is a vector quantity, which means it has both magnitude and direction. The magnitude of velocity is the speed of the object, while its direction is the direction of motion.

Time is a concept that refers to the sequence of events that occur in a continuous progression, from the past, through the present, and into the future. It is a way to measure the duration or the length of events or periods, and it is a fundamental aspect of our experience and understanding of the world.

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(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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Answer:

A.

Explanation:

During the fall the day gets shorter hence less sunlight this results to leaves stopping their food making process. The chlorophyll breaks down, the green color disappears and the yellow to orange color becomes visible

Answer:

Explanation:

college are ;)

For any freely falling item, the acceleration in the kinematic equations is -9.8 m/s/s, whether or not this is explicitly stated.

The supplied problem informs us that a ball was dropped and is supposed to be falling freely. Since the problem does not specify whether any other forces were present to influence the ball's motion, we must assume that the initial speed is v0=0 m/s.

Free-falling accelerates at a rate of 9.8 m/s2, which is referred to as the acceleration owing to gravity because it is being drawn towards the center of the earth. This indicates that a=9.8m/s2 is the value of the initial and final accelerations.

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Explanation:

Given:

Diameter = 200 m

Radius, r = 200/2 = 100 m

Time taken, t = 30 seconds

Formula to be used:

Distance traveled, = circumference of circle = 2πr

Answer:

Putting all the values, we get

Distance traveled = 2πr

So, the distance traveled by Raju is 628.57 m.

Now, magnitude of the displacement,

At the end of 30 seconds, Raju will come to starting position or initial position, so displacement is zero.