In the Roman soldier model for refraction, a muddy stream crosses the road they are on walking on at 45°. Will the soldiers in the front row all hit the water at the same time?
A. Sometimes
B. Yes
C. No
D. Not enough info

Examples of following forces mentioned -

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The average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

The acceleration of the box is calculated as follows;

vf² = vi² + 2as

a = (vf² - vi²)/2s

a = (11.5² - 13²) / (2 x 8.5)

a = -2.16 m/s²

The time taken for the box to travel is calculated as follows;

a = (vf - vi)/t

t = (vf - vi) / a

t = (11.5 - 13) / (-2.16)

t = 0.69 s

P = Fv

P = (ma)(vf - vi)

P = (1 x -2.16) x (11.5 - 13)

P = 3.24 W

Thus, the average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

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Answer:

-15 as it inverse to gravity

the direction of big force

When doing work, a reduction in effort is generally accompanied by a decrease in the distance covered by the effort which is therefore denoted as option B.

This is referred to as a type of an applied force which brings the desired change to the position of the load or object.

In a situation whereby an individual who is doing work reduces the effort involved in moving the object then there will most likely be a decrease in the distance covered by the effort which is therefore the reason why option B was chosen as the correct choice.

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The distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.

Velocity is a vector quantity. It has both a direction and a magnitude. Speed is used to calculate the magnitude of velocity. The meter per second is the S.I. unit for this. The units km/h and km/s are additional units. [LT-1] is the dimensional equation for it.

The distance traveled by the object is calculated as the product of the velocity with which it was moving and the time interval for which the distance covered is calculated.

Distance traveled =  Velocity × Time

Given in the question

Velocity of the plane = 1200 Km/h

Time Traveled = 2.5 h

Put in the value, we get

Distance traveled =  1200 × 2.5

Distance traveled = 3000 Km

Hence, the distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.

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Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

Reflected wave E: -30 cos(wt - Bz)ax - 40 sin(wt - Bz)ay V/m

Reflected wave H: (1/377) x (-30 cos(wt - Bz)ax - 40 sin(wt - Bz)ay)

Transmitted wave E: 0 V/m

Transmitted wave H: 0

To find H₁, we can use the relation between electric field (E) and magnetic field (H) in a uniform plane wave in free space. The relation is given by:

H = (1/η) x E

where η is the intrinsic impedance of air, which is approximately 377 ohms. Given the electric field Ei = 30 cos(wt - Bz)ax + 40 sin(wt - Bz)ay V/m, we can calculate H₁ as follows:

H₁ = (1/377) x Ei

Substituting the values, we have:

H₁ = (1/377) x (30 cos(wt - Bz)ax + 40 sin(wt - Bz)ay)

When the uniform plane wave encounters a perfectly conducting plate normal to the z-axis at z = 0, it gets reflected. The electric field and magnetic field of the reflected wave can be found using the boundary conditions for a perfect conductor. The reflected wave has the same magnitude as the incident wave, but the direction of the electric field is reversed.Therefore, the reflected electric field Er = -30 cos(wt - Bz)ax - 40 sin(wt - Bz)ay V/m.

Using the same relation as before, we can find the reflected magnetic field Hr:

Hr = (1/377) x Er

Substituting the values, we have:

Hr = (1/377) x (-30 cos(wt - Bz)ax - 40 sin(wt - Bz)ay)

The transmitted wave occurs when the incident wave passes through the conducting plate. Since the plate is a perfect conductor, the transmitted wave is completely absorbed, and there is no transmission through the plate. Therefore, the transmitted wave has zero electric field and magnetic field.

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Answer:

To investigate into how the height of a ramp affects the speed of a toy car rolled down a hill or slope because the higher the ramp the more Gravitational potential Energy (GPE), the more kinetic energy converted and the car will go faster. So the ramp increases, the velocity will also increase.

Explanation:

The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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The substances that are altered and the chemicals on the right side of a chemical equation are the results of a chemical reaction. B and D are the appropriate choices.

Reactants are the substance(s) in a chemical equation to the left of the arrow. A component that is present at the outset of a chemical reaction is known as a reactant. Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product. The creation of products from the reaction of two reactants is known as a chemical reaction. The compounds that result from a reaction are called products. The substances that are original materials are the reactants.

On the left side of the reaction are the reactants, and on the right are the products. B and D are the proper choices as a result.

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Answer:

Mathematical

Explanation:

The answer mathematical because you comparing the length and width of an average human face. I hope this helps you out.

Answer:

40 N

Explanation:

Both forces to the right are friction forces.  The 40 N force has to be the kinetic friction force because kinetic friction is always less than static friction.  So, the 80 N force has to be the static friction force, which is always greater than the kinetic friction.

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Answer:

1. Initial vertical velocity its 0m/s

2. 2.47 seconds

3. 10.12 m/s

4.10.12 m/s

Explanation:

Remember that we have here two parts of a problem, first we know that the ball made a free fall of 30 meters, since the ball was hit horizontally and doesn't state otherwise the vertical velocity is 0. To calculate the time we just use 30 m as our Height and use the formula for vertical distance on free fall:

\(H=\frac{g*t^{2} }{2} \\\)

Now we just solve for time:

\(t=\sqrt{\frac{2H}{g} }\)

With this we just insert the values we know:

\(t=\sqrt{\frac{2H}{g} }\\t=\sqrt{\frac{2*30}{9.81} }\\t=2.47\)

Now we know that the ball was 2.47 seconds in the air, so the ball hti the ground at the second 2.47.

To calculate the velocity of the ball we just need to divide the horizontal distance covered by the time it spent on air:

\(v=\frac{d}{t} \\v=\frac{25}{2.47} \\v=10.12\)

The final and initial horizontal velocity of the ball would be the same since nothing states otherwise, of course the hitting of the ground would decrease its velocity but since nothing is said in the problem it is not considered.

1. The initial-vertical velocity of the golf ball is equal to zero because the ball would start its motion from a stationary position (at rest).

2. The time it took the golf ball to hit the ground is 2.47 seconds.

3. The initial-horizontal velocity of the golf ball is 10.12 m/s.

4. The final-horizontal velocity of the golf ball is 10.12 m/s.

Given the following data:

1. The initial-vertical velocity of the golf ball is equal to zero because the ball would start its motion from a stationary position (at rest).

2. To determine the time it took the golf ball to hit the ground:

At maximum height, time is given by the formula:

\(Time = \sqrt{\frac{2H}{g} }\)

Where:

Substituting the given parameters into the formula, we have;

\(Time = \sqrt{\frac{2\times 30}{9.8} }\\\\Time = \sqrt{\frac{60}{9.8} }\\\\Time =\sqrt{6.12}\)

Time = 2.47 seconds.

3. To determine the initial-horizontal velocity of the golf ball:

\(Horizontal\;velocity = \frac{Horizontal\;distance}{Time} \\\\Horizontal\;velocity = \frac{25}{2.47}\)

Initial horizontal velocity = 10.12 m/s.

4. To determine the final-horizontal velocity of the golf ball:

The initial-horizontal velocity and final-horizontal velocity of the golf ball would be the same.

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A. The magnitude of C can be determined.
D. The magnitude of C is between 1m and 10m.

When two vectors are added, the magnitude of the resulting vector can be found using the law of cosines. For the vectors A and B, the magnitude of their sum C is given by:
|C|² = |A|² + |B|² + 2|A||B|cosθ,

where θ is the angle between the vectors A and B. Since the directions of A and B are unknown, θ could take any value between 0 and 180 degrees. However, the minimum value of cosθ is -1, which occurs when θ = 180 degrees. Therefore, the minimum magnitude of C is:

|C|min = |A| - |B| = 1 m - 10 m = 9 m.

The maximum value of cosθ is 1, which occurs when θ = 0 degrees. Therefore, the maximum magnitude of C is:

|C|max = |A| + |B| = 1 m + 10 m = 11 m.

Therefore, the magnitude of C is between 1m and 10m, and it can be determined.

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correct question

Which of the following statements are true about the magnitude of the vector C, which is defined as the sum of two given vectors A and B with magnitudes 1m and 10m respectively, but unknown directions? (Choose all that apply.)

A. The magnitude of C can be determined.
B. The magnitude of C is less than 10m.
C. The magnitude of C is less than 1m.
D. The magnitude of C is between 1m and 10m.
E. The magnitude of C is greater than 11m.

Answer:

A & D your welcome

Propanol surface is more flattered and has less boiling point than that of water.

To determine the correct statements among all the statements, we need to know about the surface tension.

Since, propanol has less surface tension than that of water, so its surface is more flattered and has less boiling point than that of water.

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Answer:

To find the net charge on the sphere using electric flux, we can use the formula:  

Φ = Q/ε0

Where Φ is the electric flux, Q is the charge, and ε0 is the permittivity of free space.  

Given that the electric field 20 cm from the center of the sphere is N/C and points radially inwards, we can use the formula for electric field due to a charged sphere to find the charge on the sphere:

E = kQ/r^2  

Where E is the electric field, k is Coulomb's constant, Q is the charge, and r is the distance from the center of the sphere.  

Substituting the given values, we get:  

20 = (1/4πε0)(Q)/(0.2)^2  

Solving for Q, we get:  

Q = (20)(0.2)^2(4πε0)  

Q = 0.64πε0 C  

Now, substituting this value of Q in the formula for electric flux, we get:  Φ = Q/ε0 = (0.64πε0)/(ε0) = 0.64π C  

Therefore, the net charge on the sphere is 0.64π C.

Answer:

A) X-rays

Explanation:

Airport security screenings use X-rays because they can penetrate through bags to see objects that are located within that are obscured through normal view.

X- rays are used to  test  body in airports. Low energy waves are used to screen baggages and human body. Thus option A is correct.

Electromagnetic spectrum is the arrangement of radiations in the order of decreasing wavelength or increasing energy and frequency. The order is radio waves, microwaves, infrared, visible, ultraviolet, x-rays and gamma rays.

x -rays are highly energetic short waves which can be easily penetrate through a body. X-ray is used in different diagnostic techniques. X-rays easily penetrate through  tissues and provide the scanned images of internal parts.

In airport security screening x-rays are used to screen baggages and human bodies. High energetic waves are causing serious health risks. Hence, lower energy x-rays are used in testing.

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The resultant velocity of the man relative to water which moves at 10 m / s is 12.5 m / s at 53° N of E

Velocity of man = 7.5 m / s E

Velocity of ship = 10 m / s N

Since these velocities are at right angles, the resultant velocity forms a right angled triangle. Using Pythagoras' theorem,

Resultant velocity = √ ( Velocity of man )² + ( Velocity of ship )²

Resultant velocity = √ ( 7.5 )² + ( 10 )²

Resultant velocity = √ 56.25 + 100

Resultant velocity = √ 156.25

Resultant velocity = 12.5 m / s

tan θ = Velocity of ship / Velocity of man

θ = \(tan^{-1}\) ( 10 / 7.5 )

θ = \(tan^{-1}\) ( 1.33 )

θ = 53° N of E

Therefore, the resultant velocity of the man relative to water is 12.5 m / s at 53° N of E

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The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer:

d 75 miles per hour

Explanation:

60 ÷ 20

3 × 25 = 75

hoped that helped!!

An example of a time a Christmas movie modeled acceleration on incline with friction (physics) is:

It is not uncommon for movies, including Christmas movies, to depict characters moving up or down inclines or hills. In such cases, the motion of the characters can be analyzed using the principles of physics, including acceleration and friction.

In continuation of the story above:

Therefore, By applying the laws of motion to these forces, we could calculate Buddy's acceleration as he runs up the hill.

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Answer:

below

Explanation:

If it went for 360° it would swing through the ENTIRE circumference = 2 pi r

     = 2 pi ( .8 ) =5.026 m

 but it only swings through 45   of the 360

      45 / 360    *  5.026 = .63 m

Answer:

headache

Explanation:

Depending on the type of material used, the length, and other factors, the conductor provides some ohmic resistance to the flow of electrons.

Because electrons in a conducting wire reject one another, a conducting wire provides resistance to the flow of electrons. The electrolyte resistance, the current collector resistance, the active mass, and the transition resistance between the current collector and active mass are added to create the ohmic resistance, or RB.

Theoretically, in accordance with Ohm's rule, the voltage at the ohmic resistance instantly follows the battery current. A substance or material that permits the flow of electricity is known as an electrical conductor. Electrical charge carriers, often electrons or ions, flow freely in a conductor.

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Contingent upon the sort of material utilized, the length, and different variables, the guide gives ohmic protection from the progression of electrons.

Since electrons in a directing wire reject each other, a leading wire gives protection from the progression of electrons. The electrolyte obstruction, the ongoing authority opposition, the dynamic mass, and the progress obstruction between the ongoing gatherer and dynamic mass are added to make the ohmic obstruction or RB.

Hypothetically, as per Ohm's standard, the voltage at the ohmic obstruction in a split second follows the battery current. A substance or material that allows the progression of power is known as an electrical transmitter. Electrical charge transporters, frequently electrons or particles, stream uninhibitedly in a transmitter.

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\( \qquad \pmb{\sf\longrightarrow 10 = \dfrac{(28)^2 \times sin^2 \theta}{2 \times 9.8}}\)

\( \qquad \pmb {\sf \longrightarrow 10 = \dfrac{784 \times sin^2 \theta}{19.6}}\)

\( \qquad \pmb{\sf \longrightarrow 196 = 784 \times sin^2 \theta}\)

\(\qquad \pmb{\sf \longrightarrow sin^2 \theta = \dfrac{196}{784}}\)

\(\qquad \pmb{\sf \longrightarrow sin^2 \theta = 0.25 }\)

\(\qquad \pmb{\sf\longrightarrow sin \theta = \sqrt{0.25}}\)

\(\qquad \pmb{\sf\longrightarrow sin \theta = 0.5}\)

\(\qquad \pmb{\sf\longrightarrow sin \theta = \dfrac{1}{2}}\)

\(\qquad \longrightarrow {\pink{\underline{\underline{\pmb{\sf{ \theta = 30^{\circ} }}}}}}\)

Therefore–

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Answer:

\(s = ut + \frac{1}{2} g {t}^{2} \\ t(u + \frac{1}{2} gt) = H \\ u + \frac{1}{2} gt = H \\ t = 2(H - u) \div g \\ t = \frac{(H - u)}{5} \\ u \: is \: speed \: or \: velocity\)