Answers
An unpolarized light is sent into a stack of three polarizing sheets, whose polarizing directions make angles of 44 degrees and the fraction of the incident intensity is transmitted by the system will be 0.02586.
Accounting for the “automatic” reduction (by a factor of one-half) whenever unpolarized light passes through any polarizing sheet, then our result is.
After passing through 2nd sheet , fraction transmitted = 1/2 * cos² θ)
After passing through 3rd sheet , fraction transmitted = 1/2 (cos² θ)²
here , θ = 44 °
Intensity = 1/2 (cos² θ)²
= 1/2 (cos² 44)²
= 1/2 *(5173)
= 0.2586
Therefore, the intensity of the three unpolarized light will be 0.2586.
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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: an unpolarized beam of light is sent into a system of three polarizing sheets, whose polarizing directions make angles of 44 degrees. what fraction of the incident intensity is transmitted by the system.]
Related Questions
A small car with mass 0.610 kg
travels at constant speed on the inside of a track that is a vertical circle with radius 5.00 m
If the normal force exerted by the track on the car when it is at the top of the track (point B
) is 6.00 N
, what is the normal force on the car when it is at the bottom of the track (point A
)?
Express your answer with the appropriate units.
Answers
The normal force on the car when it is at the bottom of the track is 8.84 N.
At the top of the track (point B), the normal force (N) acting on the car is equal to the weight of the car (mg) plus the centrifugal force (mv²/r) acting outwards:
N = mg + mv²/r
where m is the mass of the car, g is the acceleration due to gravity, v is the speed of the car, and r is the radius of the track.
Since the car is traveling at constant speed, its acceleration is zero, so the centrifugal force is balanced by the force of gravity, and we have:
N = mg
Substituting the given values, we get:
6.00 N = (0.610 kg)(9.81 m/s²)
Solving for g, we get:
g = 9.68 m/s²
At the bottom of the track (point A), the normal force acting on the car is equal to the weight of the car minus the centrifugal force acting downwards:
N = mg - mv²/r
Substituting the known values, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)(v²/5.00 m)
Since the car is traveling at constant speed, we can use the fact that its kinetic energy is equal to its gravitational potential energy to solve for v:
mg(2r) = (1/2)mv²
where 2r is the total distance traveled by the car (i.e., the circumference of the circle), so 2r = 2πr = 31.4 m. Solving for v, we get:
v = sqrt(2gr)
Substituting the known values, we get:
v = sqrt(2(9.68 m/s²)(5.00 m)) = 6.19 m/s
Substituting this value of v into the equation for N, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)((6.19 m/s)²/5.00 m) = 8.84 N
Therefore, the normal force on the car when it is at the bottom of the track is 8.84 N.
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What is scintillator
Answers
Answer:
Scintillators are materials that are able to convert high energy radiation such as X or gamma-rays to a near visible or visible light. They are widely used as detectors in medical diagnostics, high energy physics and geophysical exploration (ref. Knoll).
https://web.stanford.edu › scintillators
What are scintillator materials? - Stanford: Advanced Optical Ceramics Laboratory
In an amusement park water slide, people slide down an essentially frictionless tube. The top of the slide is 3.1 m above the bottom where they exit the slide, moving horizontally, 1.4 m above a swimming pool.
What horizontal distance do they travel from the exit point before hitting the water?
Answers
They travel a horizontal distance of 4.17 m from the exit point before hitting the water.
What is the law of conservation of energy?Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another.
height of the slid: h = 3.1 m
horizontal movement above swimming pool: s = 1.4 m
Let the horizonal speed of the people at the end of the water slide= v
Using energy conservation
mgh = 1/2 mv²
v = √(2gh)
Again time taken for falling s = 1.4 m under gravitation:
t = √(2s/g)
Hence, the horizontal distance travelled = speed × time
= √(2gh)×√(2s/g)
= √(4hs)
= √(4 × 3.1 × 1.4)
= 4.17 m.
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What force in Newton is required to accelerate a car starting from rest to 20 m/s in 15 seconds if the mass of the car is 2500 kilograms?
Answers
Answer:
Explanation:
f =ma
F 2500 kg (20m/s-0m/s/15s)
F=2500kg(1.33m/s²)
F =3,325 N
f =ma, F 2500 kg (20m/s-0m/s/15s) and F=2500kg(1.33m/s²), F =3,325 N.
What is Force?A push or pull that an object experiences as a result of interacting with another item is known as a force. Every time two items interact, a force is exerted on each of the objects.
The force is no longer felt by the two objects when the interaction ends. Only when there is interaction do forces actually exist.
Action-at-a-distance forces are those that happen even when the two interacting objects are not physically touching each other but are nevertheless able to push or pull against each other despite their physical separation. Gravitational forces are an example of action-at-a-distance forces.
Therefore, f =ma, F 2500 kg (20m/s-0m/s/15s) and F=2500kg(1.33m/s²), F =3,325 N.
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What is the net force on an apple that weighs 1 n when you hold it at rest above your head? What is the net force on the apple when you release it?
Answers
Answer:408849499400504053-2
Explanation:kfnkdtozskf
Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
Answers
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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A perfect spring whose spring constant is 180 newtons per meteris attached to a 3.2-kilogram cart that slides on a frictionlesshorizontal surface, as shown. The cart is moved 40 centimetersfrom its equilibrium position and released. Find the speed of thecar when it passes its equilibrium position.
Answers
Given data:
The value of the spring constant is,
\(k=180Nm^{-1}\)The value of the mass of the cart is,
\(m=3.2\text{ kg}\)The distance moved by the cart from the equilibrium is,
\(\begin{gathered} d=40\text{ cm} \\ d=0.4\text{ m} \end{gathered}\)The acceleration acquired by the cart is,
\(\begin{gathered} kd=ma \\ 180\times0.4=3.2\times a \\ 72=3.2\times a \\ a=22.5ms^{-1} \end{gathered}\)The initial velocity of the cart is,
\(u=0ms^{-1}\)The velocity of the cart when it passes the equilibrium is,
\(\begin{gathered} v=u+2ad \\ v=0+2\times22.5\times0.4 \\ v=18ms^{-1} \end{gathered}\)Thus, the velocity of the cart is 18 meter per second.
How much current is running through a circuit powered by a 1.5 volt battery wit 18
ohms of resistance? How much power would this circuit generate?
Answers
One end of an insulated metal rod is maintained at 100c and the other end is maintained at 0.00 c by an ice–water mixture. The rod has a length of 75.0cm and a cross-sectional area of 1.25cm . The heat conducted by the rod melts a mass of 6.15g of ice in a time of 10.0 min .find the thermal conductivity k of the metal?k=............ W/(m.K)
Answers
Answer:
The thermal conductivity of the insulated metal rod is \(202.92\,\frac{W}{m\cdot K}\).
Explanation:
This is a situation of one-dimensional thermal conduction of a metal rod in a temperature gradient. The heat transfer rate through the metal rod is calculated by this expression:
\(\dot Q = \frac{k_{rod}\cdot A_{c, rod}}{L_{rod}}\cdot \Delta T\)
Where:
\(\dot Q\) - Heat transfer due to conduction, measured in watts.
\(L_{rod}\) - Length of the metal rod, measured in meters.
\(A_{c,rod}\) - Cross section area of the metal rod, measured in meters.
\(k_{rod}\) - Thermal conductivity, measured in \(\frac{W}{m\cdot K}\).
Let assume that heat conducted to melt some ice was transfered at constant rate, so that definition of power can be translated as:
\(\dot Q = \frac{Q}{\Delta t}\)
Where Q is the latent heat required to melt the ice, whose formula is:
\(Q = m_{ice}\cdot L_{f}\)
Where:
\(m_{ice}\) - Mass of ice, measured in kilograms.
\(L_{f}\) - Latent heat of fussion, measured in joules per gram.
The latent heat of fussion of water is equal to \(330000\,\frac{J}{g}\). Hence, the total heat received by the ice is:
\(Q = (6.15\,g)\cdot \left(330\,\frac{J}{g} \right)\)
\(Q = 2029.5\,J\)
Now, the heat transfer rate is:
\(\dot Q = \frac{2029.5\,J}{(10\,min)\cdot \left(60\,\frac{s}{min} \right)}\)
\(\dot Q = 3.382\,W\)
Turning to the thermal conduction equation, thermal conductivity is cleared and computed after replacing remaining variables: (\(L_{rod} = 0.75\,m\), \(A_{c,rod} = 1.25\times 10^{-4}\,m^{2}\), \(\Delta T = 100\,K\), \(\dot Q = 3.382\,W\))
\(\dot Q = \frac{k_{rod}\cdot A_{c, rod}}{L_{rod}}\cdot \Delta T\)
\(k_{rod} = \frac{\dot Q \cdot L_{rod}}{A_{c,rod}\cdot \Delta T}\)
\(k_{rod} = \frac{(3.382\,W)\cdot (0.75\,m)}{(1.25\times 10^{-4}\,m^{2})\cdot (100\,K)}\)
\(k_{rod} = 202.92\,\frac{W}{m\cdot K}\)
The thermal conductivity of the insulated metal rod is \(202.92\,\frac{W}{m\cdot K}\).
Microwaves travel at the speed of light 3.00x108 m/s. When the frequency of microwaves is 9.00x109Hz, what is their wavelength?
Answers
The wavelength of microwaves with a frequency of 9.00x10^9 Hz is approximately 0.0333 meters or 33.3 millimeters.
What is the speed of microwaves and what is their frequency?Microwaves are a type of electromagnetic radiation with a frequency range of around 300 MHz to 300 GHz. They are used for various applications, including communication, cooking, and medical imaging.
The speed of microwaves is the same as the speed of light, which is approximately 3.00x10^8 m/s. This means that microwaves travel at a very high speed and can cover long distances in a short amount of time.
How does the wavelength of microwaves change with their frequency?The wavelength of microwaves is inversely proportional to their frequency. This means that as the frequency of microwaves increases, their wavelength decreases.
In other words, higher frequency microwaves have shorter wavelengths, and vice versa. For example, the wavelength of microwaves with a frequency of 9.00x10^9 Hz is approximately 0.0333 meters or 33.3 millimeters.
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Classify the following situations into contact and non-contact forces.
(a) Applying brakes in a vehicle
(b) a coconut falling from a coconut tree
(c ) the planets revolving around the sun
(d) a ball is rolling on ground.
Answers
Answer: Contact force
a. Applying break in a vehicle.
d. The speed of ball rolling on ground is reduced
Non contact force
b. A coconut falling from a coconut tree.
c. The planets revolving around the sun.
Explanation:
The contact force is the force which exerts when one object or entity comes in contact with other object or entity. For example, on application of break the vehicle stops, the force is applied on the breaks to stop the vehicle. The ball rolling on the ground the speed reduces so the application of force on the ground also reduces.
The non contact force is the force one object exerts on the other without coming in direct contact with the other object. The force exerted by one object on other due to gravity is a non contact force. The coconut falling on the ground and planets revolving around the sun are examples of non contact force due to gravity.
______________________________
A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. Determine The Depth of The Water Well.
N.B. The Correct Answer Will Receive 30 Points & The Brainliest Title.
______________________________
Answers
A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. then The Depth of The Water Well is 56.6 m.
In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the receipt of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between about 20 Hz and 20 kHz, or the audio frequency range, may cause a human to have an auditory sensation. These correspond to sound waves in air with an atmospheric pressure of 17 metres (56 ft) to 1.7 centimetres (0.67 in) in wavelength. Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges. Acceleration of the stone is 9.8 m/s²
according to kinematics,
s = ut + 1/2 at²
s = 1/2 ×9.8×3.4²
s = 56.6 m
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The D.A.R.E. program (“Drug Abuse Resistance Education”) began in 1983. In this program, police officers taught special 45-minute lessons in classrooms about the dangers of drugs. However, the program was shown to have very little effect; there was only a small, short-term reduction in tobacco use, but no reduction in alcohol or marijuana use. Long-term rates of teen substance abuse did not change significantly.
In 1998, behavioral scientists began looking for different ways to teach this program. The new D.A.R.E. curriculum is called “keepin’ it REAL,” and students spend most of their time practicing refusal strategies with friends rather than being lectured on the possible effects of drugs. The “REAL” acronym stands for the four main strategies the students practice: Refuse, Explain, Avoid, and Leave. There is also much more emphasis on teaching students how to make safe and responsible decisions in all areas of life.
This approach has been shown to be much more effective. Studies of thousands of students show that those who have been through the program use drugs and alcohol less than students who have not been through the program. Additionally, those who were already abusing substances before beginning the program were more likely to stop using the substances. The effects on students’ antidrug attitudes also lasted much longer.
Based on the excerpt, which statement is true?
Antidrug campaigns have little effect on how much students use drugs.
Lots of students use tobacco, but very few use alcohol or marijuana.
Antidrug campaigns can help prevent substance abuse, but cannot reduce it.
Practicing refusal strategies can help students stay sober.
Answers
Answer:
the correct answer is practicing refusal strategies can help students stay sober
Explanation:
Practicing refusal strategies can help students stay sober is the correct statement according to the excerpt.
What is Drug abuse?This is referred to as an inappropriate use of a drug for a non medical purpose such as for pleasure.
Refusal strategies will make individuals sober due to the body trying to adjust to the lack of drugs or chemicals in the system.
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The drawing shows two situations in which charges are placed on a and y axes. They are located at the same distance if 6.80cm from the origin O. For each of the situations in the drawing, determine the magnitude of the net electric field at the origin
Answers
The electric field strength from the origin is 1.95 x 10¹² q ( N/C ).
What is electric field?
The electric field of a charged particle is the region of space where the influence of electric force is felt.
Mathematically, the formula for electric field strength is given as;
E = kq / r²
where;
k is the Coulomb's constantq is the magnitude of the charger is the position of the chargeThe electric field strength from the origin is calculated as follows;
E = ( 9 x 10⁹ x q ) / ( 0.068 m )²
E = 1.95 x 10¹² q ( N/C )
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Hint: sin2θ + cos2θ = 1 .
Consider the 692 N weight held by two
cables shown below. The left-hand cable had
tension 570 N and makes an angle of θ2 with
the ceiling. The right-hand cable had tension
530 N and makes an angle of θ1 with the
ceiling. a) What is the angle θ1 which the righthand cable makes with respect to the ceiling?
Answer in units of ◦.
b) What is the angle θ2 which the left-hand
cable makes with respect to the ceiling?
Answer in units of ◦.
Answers
a) The angle θ1 which the righthand cable makes with respect to the ceiling is sin^(-1)(692 N / 530 N).
b) The angle θ2 which the left-hand cable makes with respect to the ceiling is sin^(-1)(692 N / 570 N).
We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).
We may apply the ideas of trigonometry and vector addition to address this issue.
a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.
T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).
T1sin(θ1) = 692 N
We may rearrange the equation to find 1:
θ1 = sin^(-1)(692 N / T1)
We can find 1 by substituting the given tension value, T1 = 530 N:
θ1 = sin^(-1)(692 N / 530 N)
b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.
The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).
T2sin(θ2) = 692 N
To find θ2, we can rearrange the equation:
θ2 = sin^(-1)(692 N / T2)
Substituting the given tension value T2 = 570 N, we can solve for θ2:
θ2 = sin^(-1)(692 N / 570 N)
Calculating these angles using the given tension values will provide the answers in degrees.
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what do you mean by kinetic energy and potential energy ?
state the formulas used to calculate them !
\( \\ \)
ty! :)
Answers
Where,
. m is the mass in kilograms
. g is the acceleration due to gravity
. h is the height in meters
Hope it helpz~ uh..
Activity
Spend time observing or thinking about events that involve matter and energy. Which events can you explain? Which
events can't you explain?
Answers
Answer:
According to Albert Einstein's equation, E = m·c², matter and energy are fundamentally related
Events that involve matter and energy that can be explained includes;
The boiling of water in a kettle
The rebound of objects including water after falling
The sound made by airplane and helicopters
Events involving matter and energy that are difficult to explain includes
The cause of the universe that manifest into about matter
The size of the universe
The fundamental object controlling gravity
Decipherable
1) The boiling of water in a kettle; Water boils by the addition of energy that raises the temperature of the particles which result in the forming of vapor as the bonds of the liquid state are broken by the fast moving molecules
2) The rebound of objects including water after falling from a height is proportional to the height from which the object is dropped, due to conservation of energy principle
3) The sound made by airplane and helicopters; This is due the interactions with the air to develop propulsion in the air
Difficult to decipher
1) The cause of the universe that manifest into about matter; The reason behind the formation of the universe is difficult to explain
2) The size of the universe; Will it be possible to know measure a universe
If the universe is measurable, how many universes do we have;
3) The fundamental object controlling gravity; What particle is responsible for gravity and the way if functions
Explanation:
What is a trench? Where would trenches typically be located?
Answers
Answer:
The deepest part of earth or oceans. They are most commonly found in oceans however
Explanation:
Trenches are located in subduction zones at or near a convergent boundary, continental crust, and/ or volcanic islands. The Mariana Trench is the deepest known trench globally, located more than 35,000 feet below sea level.
What is the rabbit's displacement from t = 0s to 3 s?
Answer with two significant digits.
Answers
Answer: i think the answer is 20.0s
Explanation:
Answer:
The rabbit displaces 2.5m to the right.
Explanation:
Khan Academy hints
dimensional formula of stress is same as
Answers
Dimensional formula of stress is same as pressure.
An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
Answers
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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What amount of force is required to accelerate a 20 gram toy car at 5 m/s²?
O 150 N
O 100 N
O 50 N
Ο ΟΝ
Answers
Answer:
100
Explanation:
F = m * a
Given that the mass (m) of the toy car is 20 grams (or 0.02 kilograms, since 1 kilogram = 1000 grams) and the acceleration (a) is 5 m/s^2, we can plug these values into the formula to calculate the force (F):
F = 0.02 kg * 5 m/s^2 = 0.1 N
So, the amount of force required to accelerate the 20 gram toy car at 5 m/s^2 is 0.1 N, which is equivalent to 100 N when rounded to the nearest whole number. Therefore, the correct answer is 100 N.
A 2200-kg railway freight car coasts at 4.1 m/s underneath a grain terminal, which dumps grain directly down into the freight car. If the speed of the loaded freight car must not go below 3.4 m/s, what is the maximum mass of grain that it can accept?
Answers
Answer:
The answer is "\(2.41 \times 10^3\)"
Explanation:
Given:
\(m_i = 2000 \ kg \\\\v_i= 4.1 \ \frac{m}{s} \\\\v_f = 3.4 \ \frac{m}{s} \\\)
Using formula:
\(\to m_iv_i = m_fv_f \\\\\to m_f= \frac{m_iv_i}{v_f}\)
\(p_i, p_f\) = system initial and final linear momentum.
\(V_i, v_f\) = system original and final linear pace.
\(m_i\) = original weight of the car freight.
\(m_f\)= car's maximum weight
\(= \frac{ 2000 \times 4.1}{3.4}\\\\= \frac{ 8.2\times 10^3}{3.4}\\\\= 2.41 \times 10^3\)
\(\boxed{m_f = 2.41 \times 10^3}\)
in the figure if coefficient of friction between block and surface is 0.2 then find acceleration produced by the resultant force acting on the block (take g= 10 m/s²)
Answers
☃ First of all we have to calculate frictional force by using below equation :
→ F = μR
→ F = 0.2 × 5 × 10
→ F = 10 N
Hence,the frictional force (F) is 10 N.☃ But we know that frictional force is acting on opposite direction of the motion :
⇏Net force = 15 - 10
⇏Net force = 5 N
Hence,the net force is 5 N.☃ By using Newton's second law we get :
Let the required acceleration produced by the block be 'a'.➝ Force = mass × acceleration
➝ 5 = 5 × a
➝ a = 5 ÷ 5
➝ a = 1 m/s²
Hence,the acceleration produced by the resultant force acting on the block is 1 m/s².A 45.7 kg woman starts from rest at the bottom of a flight of stairs that has
a total height of 2.54 meters. She reaches the top of the stairs
in 5.00 seconds. How much power does she generate if she is moving at
2.63 m/s at the top of the stairs? Use g = 9.8 m/s2, and only include 3
numbers in your answer.
Answers
Answer:
The power generated by the woman is 259 W
Explanation:
Given;
mass of the woman, m = 45.7 kg
initial velocity of the woman, u = 0
total height ascended by the woman, h = 2.54 m
time of the woman's motion, t = 5.0 s
final velocity of the woman, v = 2.63 m/s
acceleration due to gravity, g = 9.8 m/s²
The potential energy of the woman due to the height she ascended;
P.E = mgh
P.E = 45.7 x 9.8 x 2.54
P.E = 1137.564 J
The kinetic energy of the woman due to her final velocity;
K.E = ¹/₂mv²
K.E = ¹/₂ x 45.7 x (2.63)²
K.E = 158.051 J
The total mechanical energy of the woman at the top of the stairs;
M.E = P.E + K.E
M.E = 1137.564 J + 158.051 J
M.E = 1295.615 J
The power generated by the woman;
Power = Energy/time
Power = 1295.615 J / 5 s
Power = 259.123 W
Power = 259 W
measurement conversions [metric to metric] 568 cm = m
Answers
Answer:
5.68 meters
Explanation:
hope this helps!
Answer:
5.68
Explanation:
to convert cm to m you move the decimal point 2x to the left
Which of the following statements about random assignment is true?
•It works best with a larger number of participants because there is more opportunity for extraneous variables to be equally distributed to each group.
• It works best with a smaller number of participants because fewer participants means there will be fewer opportunities for extraneous variables to confound the results of a study.
• It is the only control technique that explicitly controls for extraneous variables.
• It is the only control technique that produces a sample that is representative of the population.
Answers
The following statements about random assignment is true:
It works best with a larger number of participants because there is more opportunity for extraneous variables to be equally distributed to each group.
Random assignment is a technique used in research studies to assign participants to different groups or conditions. Its purpose is to create equivalent groups, ensuring that any differences in the outcomes can be attributed to the treatment or intervention being studied rather than other factors. The statement that is true about random assignment is that it works best with a larger number of participants because there is more opportunity for extraneous variables to be equally distributed to each group.When the number of participants is larger, the random assignment process becomes more effective in creating groups that are balanced and representative of the population. This is because with a larger sample size, there is a greater chance that random assignment will distribute extraneous variables evenly across the groups. As a result, the groups are more likely to be comparable in terms of their characteristics and any potential confounding variablesOn the other hand, when the number of participants is smaller, there is a higher risk that random assignment may not effectively distribute the extraneous variables equally across the groups. This increases the potential for confounding variables to influence the outcomes of the study, limiting the validity and reliability of the results.While random assignment is an important control technique in research, it is not the only technique available. There are other control techniques such as matching, blocking, and stratification that can also be used to control for extraneous variables. Additionally, random assignment does not guarantee a sample that is representative of the population as it is focused on creating equivalent groups rather than representing the entire population.For more such questions on Random assignment, click on:
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A 2.3kg bicycle wheel has a diameter of 50cm. What torque must you apply to take the wheel from 0rpm to 120rpm in 5.5s?
Answers
Answer:
τ = 0.26 N.m
Explanation:
First we find the moment of inertia of the wheel, by using the following formula:
I= mr²
where,
I = Moment of Inertia = ?
m = mass of wheel = 2.3 kg
r = radius of wheel = 50 cm/2 = 25 cm = 0.25 m
Therefore,
I = (2.3 kg)(0.25 m)²
I = 0.115 kg.m²
Now, we find the angular acceleration of the wheel:
α = (ωf - ωi)/t
where,
α = angular acceleration = ?
ωf = final angular velocity = (120 rpm)(2π rad/1 rev)(1 m/60 s) = 12.56 rad/s
ωi = Initial Angular Velocity = 0 rad/s
t = time = 5.5 s
Therefore,
α = (12.56 rad/s - 0 rad/s)/(5.5 s)
α = 2.28 rad/s²
Now, the torque is given as:
Torque = τ = Iα
τ = (0.115 kg.m²)(2.28 rad/s²)
τ = 0.26 N.m
A remote-controlled plane has a mass of 0.386 kg and flies in a circle with a radius of 75 m. The centripetal force on the plane is 4.0 N.
What is the tangential speed of the plane?
Answers
Answer:
28 m/s
Explanation:
correct
Answer:
b
Explanation:
Convert 20 C to F
-40 C to F
40C to F
Answers
2. -40 degrees fahrenheit
3. 104 degrees fahrenheit
Answer:
20 C to F
Ans: 68F
-40 C to F
Ans:-40F
40C to F
Ans:104F