in the figure, a conducting metal bar of mass 0.5 kg sliding along conducting rails is connected to a battery of emf 18 v and resistor r

The component of the net force on the cart is 36.1 N at 74⁰.

The component of the net force on the cart is calculated by resolving the tension in the ropes into x and y components.

The x component of force on each rope is calculated using the formula below;

Fx = F cosθ

where;

The y component of force on each rope is calculated using the formula below;

Fy = F sinθ

where;

note:

For the force of 30 N west; (θ = 0, since the rope parallel to the cart)

Fx = -30  x cos(0)

Fx = -30 N

Fy = 30 x sin(0)

Fy = 0

For the force of 40 N west; (θ = 90 - 30⁰ = 60⁰ above the horizontal)

Fx = 40 x cos(60)

Fx = 20 N

Fy = 40 x sin(30)

Fy = 34.64 N

Sum of x and y component of the forces;

∑Fx = -30 N + 20 N = -10 N

∑Fy = 0 + 34.64 N = 34.64 N

The net force on the cart is calculated as the resultant force;

F = √(∑Fx² + ∑Fy²)

F = √(-10² + 34.64²)

F = 36.1 N

Direction of the force is calculated as follows;

tan θ = ΣFy/ΣFx

tan θ = 34.64 / 10

tan θ = 3.464

θ = arc tan (3.464)

θ = 74⁰

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Answer:

(a) The value of the ratio m₁/m₂ is 0.581

(b)  the acceleration of the combined masses is 1.139 m/s²

Explanation:

Given;

The acceleration of force applied to M₁, a₁ = 3.10 m/s²

The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²

Let this force = F

According Newton's second law of motion;

F = ma

(a) the value of the ratio m₁/m₂

since the applied force is same in both cases,  M₁a₁ = M₂a₂

\(\frac{m_1}{m_2} = \frac{a_2}{a_1} \\\\\frac{m_1}{m_2} = \frac{1.8}{3.1} \\\\\frac{m_1}{m_2} = 0.581\)

(b) the acceleration of m₁ and m₂ combined as one object under the action force F

F = ma

\(a = \frac{F}{M} \\\\a = \frac{F}{m_1 + m_2} \\\\a = \frac{F}{0.581m_2 + m_2}\\\\a = \frac{F}{1.581m_2}\)

\(But, m_2 = \frac{F}{a_2} \\\\a = \frac{F}{1.581m_2} = \frac{F*a_2}{1.581F} \\\\a = \frac{a_2}{1.581} \\\\a = \frac{1.8}{1.581} = 1.139 \ m/s^2\)

Therefore, the acceleration of the combined masses is 1.139 m/s²

a. The value of the ratio is 0.581.

b. The acceleration should be \(1.139 m/s^2\)

Since

The acceleration of force applied to \(M_1,a_1 = 3.10 m/s^2\)

The same force applied to\(M_2\) has acceleration, \(a_2 = 1.80 m/s^2\)

Here we assume force be F

Now we know that

F = ma

a. The ratio should be

\(m_1\div m_2 = a_2\div a_1\\\\m_1\div m_2 = 1.8\div 3.1\)

= 0.581

b.  The acceleration should be

f = ma

a = F/m

\(a = f/m_1+m_2\\\\= F/0.581 + m_2\\\\=F/1.581m_2\)

However \(m_2 = F/a_2\)

So,

\(a = F\div 1.581m_2\\\\= f\times a_2/1.581F\\\\= a_2/1.581\\\\= 1.8/1.581\\\\= 1.139 m/s^2\)

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As the rope becomes shorter, the length of the rope is  decreased and the centripetal force decreases according causing the ball to move in smaller circles.

The centripetal force is defined as the force that keeps an object moving in a circular path. Also, the centripetal force is equal to the tension in the rope and the tension in the rope depends on the length of the rope.

As the rope shortens, the tension in the rope decreases and the centripetal force on the ball decreases hence the ball moves in smaller and smaller circles, the ball goes around with a shorter and shorter period.

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a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.

The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.

The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.

b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.

The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.

In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.

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Answer: 13.2678 kg

Explanation: Well, 13.2678 kg is 29.25 in mass and kg.

Answer:

27.91ohms

Explanation:

From the question we are given the following

Voltage across the inductor VL = 120V

Current in the inductor I = 4.3A

Required

Inductive reactance XL

Using two formula

VL =IXL

XL = VL/I

XL = 120/4.3

XL = 27.91ohms

Hence the inductive reactance is 27.91ohms

Answer:

A venturi meter is used to measure the flow speed of a fluid in a pipe. The meter is connected between two sections of the pipe (the figure); the cross-sectional area A of the entrance and exit of the meter matches the pipe's cross-sectional area. Between the entrance and exit, the fluid flows from the pipe with speed V and then through a narrow ''throat'' of cross-sectional area a with speed v. A manometer connects the wider portion of the meter to the narrower portion. The change in the fluid's speed is accompanied by a change Δp in the fluid's pressure, which causes a height difference h of the liquid in the two arms of the manometer. (Here Δp means pressure in the throat minus pressure in the pipe.) Let A equal 5·a. Suppose the pressure p1 at A is 2.1 atm.

Compute the values of (a) the speed V at A and (b) the speed v at a that make the pressure p2 at a equal to zero.

(c) Compute the corresponding volume flow rate if the diameter at A is 4.0 cm.The phenomenon that occurs at a when p2 falls to nearly zero is known as cavitation. Please assume that the fluid is water. The water vaporizes into small bubbles.

Time = t = 6.62 s

Explanation:

Given data:

Height = h = 215 m

Initial velocity =  = 0 m/s

gravitational acceleration = g = 9.8 m/s²

Time = t = ?

According to the second equation of motion

As the initial velocity is zero, the first term of right-hand side of the above equation is equal to zero.

                                       t² = 2h/g

                                        t = square root 2h/g

                                        t = square root 2x215/9.8

                                        t = 6.62 s

Answer:

The conditions stop air from getting to the nail is the oil

Explanation:

The time that would be taken is 1.6 s.

We know that the speed would be the ratio of the distance to the time that have been taken and that is how we would be able to solve the problem that we have in the case that is ahead of us in this question

We have that the speed is; Distance/Time

= 91 m/29s

= 3.1 m/s

At the same speed;

Time = Distance/Speed

= 5 m / 3.1 m/s

= 1.6 s

Hence we k now that the spaghetti would be able to take a time that is about 1.6 s

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Answer:

I cant really see the imagine

Explanation:

The change in momentum of your knees during the fall is the same with or without the kneepads.

option B is the correct answer.

The law of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.

The sum of the initial momentum of the system is equal to sum of the final momentum of the system.

Pi = Pf

where;

Thus, according the law of conservation of linear momentum, the change in the momentum of the skater is constant. That is the change in momentum is the same with or without the kneepads.

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Answer:

Isaac Newton came up with the 3 Laws of Motion

Answer:

Isaac Newton came up with three laws of motion

Answer:

-2.83 m/s²

Explanation:

❖ Acceleration is defined as the rate of change in velocity with time.

→ a = (v - u)/t

→ a = (17 - 34)/6 m/s²

→ a = -17/6 m/s²

(Minus sign implies that the velocity is decreasing.)

We have to make the conversations

mass rod=100g=.1 kg

mass =50g=0.05 kg

in order to obtain the weight, we need to multiply the mass by the gravity in this case 9.8 m/s^2

w_rod= .1*9.8=0.98 N

w_mass=.05*9.8=0.049N

Then wee need to draw a diagram

We have RA and RB the reactions of the support

First we need to find the sum of forces

Then we analyze the moments of force

then we can calculate RB

then we can calculate RA

the reactions will be

RA=0.79625N=0.80N

RB=0.67375N=0.67N

Answer:

Explanation:

Wt = ρVg

Wt = ρ(πD²/4)hg

Wt = 7800(π0.0275²/4)0.94(9.81)

Wt = 42.72152359...

Wt = 42.7 N

The speed of the ball just after striking the floor a second time, is 30.0 m/s.

Initial height (h) = 45 m

Acceleration due to gravity (g) = 10 m/s²

Energy loss per collision (k) = 19% = 0.19

At each collision with the floor, the ball loses 19% of its kinetic energy, which means the remaining kinetic energy is 81% (100% - 19%).

When the ball reaches the floor for the first time, it has converted all its potential energy into kinetic energy. So, the initial kinetic energy (K₁) is equal to the potential energy (PE) at the initial height:

K₁ = PE = mgh

Now, let's consider the ball's motion from the initial height to the first collision point. The ball undergoes free fall, so we can use the equations of motion:

h = (1/2)gt²

t = sqrt(2h/g)

Using this time, we can calculate the initial kinetic energy (K₁):

K₁ = mgh = m * 10 m/s² * 45 m

Since the ball loses 19% of its kinetic energy at each collision, the remaining kinetic energy is 81%:

K₂ = K₁ * 0.81

The ball then rebounds elastically from the floor, conserving both kinetic energy and speed. Therefore, the speed just after striking the floor for the second time (v₂) is equal to the speed just before the first collision (v₁):

v₂ = v₁

To find the speed just before the first collision (v₁), we can use the equation of motion:

v = gt

Substituting the time (t) we found earlier, we have:

v₁ = g * sqrt(2h/g)

Now, we can substitute the known values and calculate the speed just after striking the floor for the second time:

v₁ = 10 m/s² * sqrt(2 * 45 m / 10 m/s²)

v₂ = v₁

By evaluating the expression, we find:

v₁ ≈ 30.0 m/s

v₂ ≈ 30.0 m/s

Therefore, the speed of the ball just after striking the floor for the second time is 30.0 m/s.

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Answer:

A B C

Explanation:just took the test

Answer:

Komal could have mixed up the labels on the vials.

Someone might have jiggled the table and made the water surface tension bubble spill over.

The water could actually have been saltwater instead of pure water.

Explanation:

...........................

Explanation:

To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:

Efficiency = (Output Work / Input Work) * 100

Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.

Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.

Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."

Using the velocity ratio, we have the following relationship:

dE / dL = 5

Now, we can calculate the input work (Wi) and the output work (Wo):

Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)

Output Work (Wo) = Load (L) * Distance moved by the load (dL)

Given that the efficiency is 80%, we can rewrite the formula for efficiency as:

0.80 = (Wo / Wi) * 100

Now, let's solve for the effort (E) using the given values:

Load (L) = 200N

Efficiency = 0.80

Velocity Ratio = 5

First, calculate the output work (Wo):

Wo = Load (L) * Distance moved by the load (dL)

Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):

dL = (1/5) * dE

Wo = L * (1/5) * dE

Wo = 200N * (1/5) * dE

Wo = 40N * dE

Next, calculate the input work (Wi):

Wi = Effort (E) * Distance moved by the effort (dE)

Wi = E * dE

Now, substitute the values into the efficiency formula:

0.80 = (Wo / Wi) * 100

0.80 = (40N * dE) / (E * dE) * 100

0.80 = 40 / E * 100

0.80 * E = 40

E = 40 / 0.80

E = 50N

Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.

A net force can act in the same direction as that of the current velocity of the object, in which case it will not change the direction in which the object moves.

The terminal velocity of the sphere is approximately 22.68 mph.

The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:

Fd = (1/2) * rho * Cd * A * v²

where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.

The gravitational force pulling the sphere down is given by:

Fg = m * g

where m is the mass of the sphere and g is the acceleration due to gravity.

At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:

Fd = Fg

Substituting the expressions for Fd and Fg and solving for v, we get:

v = √((2 * m * g) / (rho * Cd * A))

where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.

Plugging in the given values, we get:

v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s

To convert this to mph, we multiply by 2.23694:

v ≈ 22.68 mph

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An insulating vessel contains 80 g of a block of ice at -12 °C. If 450 g of water at 60 °C is added to the ice in the vessel, Energy required for complete melting = \(80 g X (3.33 X 10^3 J/kg)\).

To determine whether the ice will soften absolutely and calculate the final temperature of the system, we need to do not forget the strength transferred among the ice and water at some stage in the procedure.

(i) To decide if the ice will melt completely, we need to examine the energy won by using the ice to the electricity required for complete melting.

Energy received by way of the ice = mass of ice × particular heat capacity of ice × alternate in temperature

Energy won by using the ice = eighty g × 2100 J/(kg·°C) × (final temperature - (-12°C))

Energy required for complete melting = mass of ice × latent warmth of fusion of ice

Energy required for whole melting = 80 g × (3.33 × 10^3 J/kg)

If the strength received via the ice is extra than or same to the electricity required for entire melting, the ice will soften completely.

(ii) To calculate the very last temperature of the gadget, we want to keep in mind the power transferred between the ice and water.

Energy won by the water = mass of water × unique heat ability of water × trade in temperature

Energy received by using the water = 450 g × 4200 J/(kg·°C) × (final temperature - 60°C)

Since electricity is conserved inside the machine, the power gained by means of the ice and water need to be identical:

Energy gained through the ice = Energy won by the water

Using the equations above, we will installation the following equation:

80 g × 2100 J/(kg·°C) × (very last temperature - (-12°C)) = 450 g × 4200 J/(kg·°C) × (very last temperature - 60°C)

Thus, this the final temperature of the system.

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Answer: 4

Explanation: because my pet monkey said it was

Answer:

C: 5

Explanation:

MA = radius of wheel/ radius of axle

MA =2.5/0.5

MA = 5.0

Answer:

\(d_{i}=465 cm=4.65 m\)  

Explanation:

Using the thin lens equation, we have:

\(\frac{1}{f}=\frac{1}{d_{o}}+\frac{1}{d_{i}}\)

Where:

f is the focal length

d(o) is the distance of the object

d(i) is the distance of the image

\(\frac{1}{15}=\frac{1}{15.5}+\frac{1}{d_{i}}\)

\(\frac{1}{15}-\frac{1}{15.5}=\frac{1}{d_{i}}\)    

\(d_{i}=465 cm=4.65 m\)          

Therefore, the screen is at 465 cm.

I hope it helps you!

Answer:

A.

Explanation:

this would make sense but it seems to be more like they both sound different

Answer:

that was sooo terible i cant understand like that im so sorry i cant help you im soo realy sorry

Answer:

Names of the Equations of Motion

1 The First Equation of Motion is, v=u+at is known as velocity – time relation. 2 The Second Equation of Motion is, s=ut+12at2 is known as position – time relation.

Answer:

The more the mass, the more the gravity. The more the distance the less the gravity.

Explanation:

I just learned about it on E_d_g_e_n_u_i_t_y