In the context of green marketing, sustainability provides strong incentives for redesigning products in ways that make it easier to reuse and recycle becasue by focusing on sustainable practices, companies can attract environmentally conscious consumers who prioritize the longevity and eco-friendliness of products.
This can ultimately lead to increased sales and brand loyalty, making it a win-win situation for both the company and the environment. Additionally, government regulations and policies also provide incentives for companies to adopt more sustainable practices, further emphasizing the importance of incorporating green initiatives in marketing strategies.
Green and sustainable marketing can help organizations appeal to a growing base of environmentally and socially conscious consumers, employees and investors. Marketing leaders should understand the differences between green and sustainable marketing so they can create and launch the most effective campaigns for their target audiences.
So, In the context of green marketing, sustainability provides strong incentives for redesigning products in ways that make it easier to reuse and recycle.
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A cop car’s siren has a frequency of 700. H z. If you are standing on the sidewalk as the cop car approaches you at a speed of 15.0 m/ s, what frequency would you hear if the cop was driving away from you at a speed of 25 m/s. The speed of sound is 343 m/ s.
a. 1166 Hz
b. 732 Hz
c. 652 Hz
d. 1263 Hz
URGENT PLS HELP!!!
The frequency you hear if the cop was driving away from you at a speed of 25 m/s is 652 Hz. The correct option is C.
What is frequency?It is the number of oscillations per second of the sinusoidal wave.
A cop car’s siren has a frequency of 700. H z. If you are standing on the sidewalk as the cop car approaches you at a speed of 15.0 m/ s.
The cop was driving away from you at a speed of 25 m/s. The speed of sound is 343 m/ s.
The frequency you hear will be calculated using the following formula
f' = f(Vs - Vo)/(Vs +Vc)
Substitute the values into the above equation, we get
f' = 700 x (343 - 0) / (343 + 25)
f' = 652.45 Hz
or f' = 652 Hz
Thus, the frequency you hear when the cop is driving away is 652 Hz.
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If 1000 droplets of water of surface tension 0. 07N/m,having same radius 1mm each,combine to form a single drop. In the process the released surface energy is
Surface energy released when 1000 droplets of water of surface tension 0.07 N/m, each with a radius of 1 mm, combine to form a single drop is approximately \(8.82 * 10^-7 J.\)
When the 1000 droplets of water combine to form a single drop, the surface area of the resulting drop decreases. As a result, the surface energy of the drop decreases because the surface tension of water is a measure of the energy required to increase the surface area of the water.
The surface area of the combined droplets can be calculated using the formula for the surface area of a sphere:
A = \(4pi*r^2\)
where A is the surface area, and r is the radius of the individual droplets.
Substituting the known value of the radius, we get:
A =\(4pi*(0.001 m)^2\)
A ≈ \(1.26 * 10^-5 m^2\)
The surface energy of the combined droplets can be calculated using the formula:
E = σA
where E is the surface energy, and σ is the surface tension of water.
Substituting the known values, we get:
E = \((0.07 N/m) * (1.26 * 10^-5 m^2)\)
E ≈\(8.82 * 10^-7 J\)
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A Physicist is studying a newly discovered radioactive isotope. She begins her experiment with a 4 x 10-8 kg sample of the isotope, and over the course of several hours, the sample emits several gamma rays. After the experiment, the sample now weighs 3 x 10-8 kg. Which of the following describes what happened? The isotope gamma decayed, turning some of its energy into the energy of the gamma rays. The isotope gamma decayed, turning some of its mass into the energy of the gamma rays. The isotope gamma decayed, turning some of its mass into the mass of the gamma rays. The isotope gamma decayed, turning some of its energy into the mass of the gamma rays.
The isotope gamma decayed, turning some of its mass into the energy of the gamma rays.
During the experiment, the physicist observed that the sample of the newly discovered radioactive isotope lost mass. This loss of mass indicates that the isotope underwent gamma decay, a type of radioactive decay process.
Gamma decay involves the emission of gamma rays, which are high-energy photons. The fact that the sample emitted gamma rays suggests that the isotope released some of its energy during the decay process.
According to Einstein's mass-energy equivalence principle (E=mc²), energy and mass are interchangeable. In this case, as the isotope underwent gamma decay, some of its mass was converted into the energy of the emitted gamma rays.
This conversion is possible because the energy of gamma rays is directly proportional to their frequency and inversely proportional to their wavelength.
Therefore, the correct explanation for what happened in the experiment is that the isotope gamma decayed, turning some of its mass into the energy of the gamma rays. This process highlights the fundamental relationship between mass and energy in the realm of nuclear physics.
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A coach notices that a weightlifter is lifting the bar suboptimally during a clean because the bar is traveling too far out in front of the athlete. Using your knowledge of force vectors, how can the weightlifter change his technique to improve performance
In order to improve performance, a weightlifter can change his technique in a few ways to avoid the bar traveling too far out in front of the athlete.
The first step the weightlifter could take to change his technique would be to shift his weight towards the back of his heels. This would cause the force vector to push the bar straight up, avoiding the bar traveling too far out in front of the athlete. This technique will help the weightlifter to have more control over the bar.Secondly, he could start pulling the bar closer to his body during the lift. This will help to keep the bar close to his center of gravity, which will help to keep the bar under control.
When pulling the bar closer to his body, the athlete should focus on keeping his elbows high and outside, this will help to control the bar better. By doing so, the athlete can effectively reduce the forward force on the bar, thus helping him in improving his performance.Therefore, these techniques will be helpful to the athlete in improving his performance by ensuring that the bar travels in the correct path, allowing him to have more control over the bar during a clean.
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A state that encourages immigrants to learn and speak one primary
language and adopt the national currency is an example of. *
A state that encourages immigrants to learn and speak one primary language and adopt the national currency is an example of linguistic and cultural assimilation or integration. Linguistic assimilation refers to the process of adopting the dominant language of a society, while cultural assimilation involves adopting the customs, values, and norms of the host country.
By encouraging immigrants to learn and speak the primary language of the country, the state aims to promote effective communication and social integration. This policy facilitates interaction among individuals from diverse backgrounds and fosters a sense of national unity.
Similarly, encouraging immigrants to adopt the national currency promotes economic integration and facilitates participation in the country's financial system. It enables immigrants to conduct transactions, engage in economic activities, and fully participate in the economy of the host country.
Both linguistic and cultural assimilation policies are often implemented with the intention of promoting social cohesion, facilitating economic integration, and fostering a sense of national identity among immigrants and the broader population. However, it is important to note that the implementation and effectiveness of such policies can vary across different countries and contexts.
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A powerful motorcycle can accelerate from rest to 29.2 m/s in only 3.9 s. What is its average acceleration in meters per second squared?
56 meters have been determined as the distance traveled.
s-displacement, u-initial velocity, v-final velocity, a-acceleration, and t-time variables are equal to v=u + at and v2 = u2 + 2ass, respectively.
The motorcycle's values are as follows:
u= 0m/s
v=28m/s
t=4s
a=??
s=??
v=u +at
28= 0 + 4a
4a=28
a= 7m/s2
As a result, the typical acceleration is 7 m/s2.
displacement u2+2as, v2=s
28^2= 0^2+ (2x7s)
784= 14s
s= 784/14
s= 56
Therefore, the journey's distance was 56 meters.
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Solve the following numerical problems. a) A load of 400N is liſted up by an effort of 100N. If load distance is 20cm, what will be the effort distance? (Ans 80cm)
Answer:
Solution
Load(L)=400
Effort(E)=100
Load distance (Ld)=20cm
Effort distance(Ed)=?
Now,from the principle of equilibrium
L×Ld=E×Ed
or,Ed=L×Ld/E
or,Ed=400×20/100
:.Ed=80cm and
Therefore,the effort distance will be 80cm
Answer:
80cm
Explanation:
load l = 400
Effort e = 100
load distance Ld = 20
Effort distance Ed = ?
L×ld= E×Ed
Ed=L×Ld \ E
Ed=400×20/100
Ed=80cm Ans
The angle θ always has a value in the range of...?
The angle theta (θ) is a geometric angle that can have a value in the range of 0 to 360 degrees or 0 to 2π radians, depending on the unit of measurement used.
The angle theta (θ) is a geometric angle that can have a value in the range of 0 to 360 degrees or 0 to 2π radians, depending on the unit of measurement used. This is because a full circle contains 360 degrees or 2π radians, and any angle can be expressed as a multiple of this full circle.
When measuring angles in degrees, the range of theta is typically given as 0 ≤ θ ≤ 360 degrees. This means that theta can take on any value between 0 degrees and 360 degrees, inclusive.
When measuring angles in radians, the range of theta is typically given as 0 ≤ θ ≤ 2π radians. This means that theta can take on any value between 0 radians and 2π radians, inclusive.
It's worth noting that angles can also have negative values or values greater than 360 degrees or 2π radians, but these are typically considered to be outside the standard range of theta.
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PLZ NEED ANS ASAP research on the principle behind how these huge ships are able to float on water. Does salt or fresh water make a difference? I WILL GIVE BRAINLIEST
Answer:
Since the density of salt water is higher than that of fresh water.
Explanation:
Less salt water will be displaces and the ship will float higher.
a stalled vehicle is being pushed up a hill at constant velocity by three people. the net force on the car is
The net force on the car is zero, since the car is moving at a constant velocity which means the forces acting on it are balanced.
If a vehicle is moving at a constant velocity, is there a net force acting on it? Why or why not?If a vehicle is moving at a constant velocity, then there is no net force acting on it. This is because the net force is the sum of all the forces acting on an object, and if the vehicle is moving at a constant velocity, then the forces acting on it must be balanced.
If a vehicle is accelerating, is there a net force acting on it? Why or why not?If a vehicle is accelerating, then there is a net force acting on it. This is because acceleration is a change in velocity over time, and to change velocity, a net force must be applied to the object.
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What is an example of a wave that is not mechanical and how is it different?
Answer:
light is an example of a wave that is not mechanical .
it is different as it does not need material medium for its propagation
The distance and displacement of a object in motion can be the same (true or false)
Aswer:
False, the values of the distance traveled and the displacement only coincide when the trayectorie is a straight line. Otherwise, the distance will always be greater than the offset.
Although these terms are used synonymously in other cases, they are totally different. Since the distance that a mobile travels is the equivalent of the length of its trajectory. Whereas, the displacement will be a vector magnitude.
xXCherryCakeXx.
Rank the following compounds in order of increasing viscosity at a given temperature. CH3OH, CH3CH3, H2C=O
A) H2C=O < CH3CH3 < CH3OH
B) CH3CH3 < H2C=O < CH3OH
C) CH3OH < CH3CH3 < H2C=O
D) H2C=O < CH3OH < CH3CH3
C) CH3OH < CH3CH3 < H2C=O CH3CH3 will have a higher viscosity than H2C=O. Therefore, the correct ranking order of increasing viscosity is CH3OH < CH3CH3 < H2C=O.
Viscosity is the measure of a fluid's resistance to flow. In general, compounds with stronger intermolecular forces have higher viscosities. Out of the three given compounds, CH3OH has the strongest intermolecular forces due to hydrogen bonding. Therefore, it will have the highest viscosity. CH3CH3 has weaker intermolecular forces compared to CH3OH, but still stronger than H2C=O.
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FILL THE BLANK. rising air temperature causes the saturation mixing ratio to ______
Rising air temperature leads to an increase in the saturation mixing ratio, allowing the air to hold more water vapor before reaching saturation.
The saturation mixing ratio refers to the maximum amount of water vapor that air can hold at a particular temperature before it becomes saturated. As the temperature of the air rises, the saturation mixing ratio also increases.
As the air temperature rises, it has the ability to hold more water vapor before reaching saturation. The saturation mixing ratio refers to the maximum amount of water vapor that can exist in the air at a given temperature. When the air temperature increases, the saturation mixing ratio increases because warmer air can hold more moisture.
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Calculate the energy required to:
convert 85 kg of ice to water
The energy required to convert 85 kg of ice to water is 2.856 MJ.
What is heat?The increment in temperature adds up the thermal energy into the object. This energy is Heat energy.
Given is the mass of ice = 85 kg
For a phase change, latent heat of fusion, L = 33600 J/K is required to convert ice into water.
Q =mL
Q = 85 x 33600 J/K
Q = 2856000 Joules.
Q = 2.856 MJ
Thus, the energy required to convert 85 kg of ice to water is 2.856 MJ.
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the nucleus of our Galaxy (which may be elongated and not spherical) generates
The elongated nucleus of our galaxy is responsible for generating a wide range of phenomena, including the influence of a supermassive black hole, star formation activity, and the production of synchrotron radiation. These processes are vital to understanding the overall structure, dynamics, and evolution of the Milky Way.
The nucleus of our galaxy, also known as the galactic center, is a region that plays a crucial role in generating various phenomena. Located approximately 26,000 light-years from Earth, it is thought to have an elongated shape rather than being perfectly spherical.
At the heart of the galactic nucleus lies a supermassive black hole called Sagittarius A* (Sgr A*). This black hole is responsible for generating intense gravitational forces, which influence the motion and behavior of surrounding stars, gas, and dust. Additionally, Sgr A* is a major source of X-ray and radio emissions, contributing to the overall energy output of the galaxy's core.
The galactic center also exhibits a high degree of star formation activity. Massive, young stars in this region emit intense ultraviolet radiation, which in turn ionizes the surrounding gas clouds. This process leads to the creation of H II regions, which are areas of glowing ionized gas. These regions not only serve as stellar nurseries but also contribute to the overall appearance and structure of the galactic nucleus.
Furthermore, the interaction of energetic particles, magnetic fields, and turbulent gas flows in the galactic nucleus generates synchrotron radiation, which is emitted at various wavelengths, including radio, infrared, and X-ray. This radiation is an important tool for astronomers to study the complex processes occurring within the core of our galaxy.
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A 50 gram sample of copper is placed in to cold water and transfers 481.25 Joule
cold water. The sample of copper experiences a 250C decrease in temperature.
specific heat of copper?
The specific heat of copper is 0.965 J/g°C. q = m*c*ΔT where q is the heat transferred, m is the mass of the substance, c is the specific heat of the substance, and ΔT is the change in temperature.
the specific heat of a substance is the amount of heat required to raise the temperature of one gram of the substance by one degree Celsius. In this case, we calculated the specific heat of copper using the amount of heat transferred when a 50 gram sample of copper was placed in cold water and experienced a temperature decrease of 25°C. By using the formula q = m*c*ΔT, we were able to calculate that the specific heat of copper is 0.965 J/g°C. This value is important in understanding how much heat energy is needed to raise the temperature of a certain amount of copper, which can have practical applications in fields such as engineering and thermodynamics.
Plugging these values into the formula, we get:
481.25 J = 50 g * c * 25°C
Solving for c, we get:
c = 0.965 J/g°C.
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The following graphs display the exact function solution y = ex and the three numerical solutions Euler, Improved Euler (Heun) and Runge-Kutta at different intervals (iterations). Analyze each set of graphs (there are a total of four) noticing the Relative Deviation on the right. Write at least 3 - 5 sentence paragraph describing your observation.
The graphs display the function solution y = ex and three numerical solutions -Euler, Improved Euler, and Runge-Kutta- at different intervals. The Relative Deviation on the right measures the difference between the numerical solutions and the exact function solution.
The analysis of each set of graphs involves comparing the numerical solutions (Euler, Improved Euler, and Runge-Kutta) with the exact function solution y = ex. The Relative Deviation provides an indication of how closely the numerical solutions approximate the exact solution.
To analyze each set of graphs, follow these steps:
Examine the shape of the graphs: Compare the curves of the numerical solutions -Euler, Improved Euler, and Runge-Kutta-with the exact function solution. Look for similarities and differences in terms of how well they capture the shape and behavior of the function.Evaluate the Relative Deviation: Focus on the Relative Deviation values displayed on the right side of the graphs. The Relative Deviation measures the percentage difference between the numerical solutions and the exact function solution. Higher values indicate larger deviations and less accuracy in approximating the true solution.Compare the performance of the numerical methods: Assess the performance of each numerical method -Euler, Improved Euler, and Runge-Kutta-based on their respective graphs and Relative Deviation values. Look for trends and patterns in how the deviation changes with each iteration or interval.Determine the most accurate numerical method: Based on the analysis of the graphs and Relative Deviation values, identify the numerical method that provides the closest approximation to the exact function solution. A lower Relative Deviation indicates better accuracy and a closer match to the true solution.By examining the graphs and assessing the Relative Deviation, one can analyze the accuracy and performance of the numerical solutions -Euler, Improved Euler, and Runge-Kutta- in approximating the exact function solution y = ex at different intervals or iterations.
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Two ropes apply a force to a boat. The first is 100 N in the positive x direction and 100 N in the positive y direction. What is the magnitude and direction of the resulting net force?
The magnitude and direction of the resulting net force is 141.42 N.
What is the magnitude and direction of the resulting net force?The magnitude and direction of the resulting net force is calculated by applying the following formula as follows;
Mathematically, the formula for magnitude of force is given as;
F = √ ( Fy² + Fx²)
where;
Fy is the vertical component of the forceFx is the horizontal component of the forceThe magnitude and direction of the resulting net force is calculated as;
F = √ ( Fy² + Fx²)
F = √ (100² + 100²)
F = 141.42 N
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The temperature of an ideal monatomic gas rises by 8.0 k. what is the change in the internal energy of 1 mol of the gas at constant volume?
The change in the internal energy of 1 mol of the gas at constant volume is 100J
What is internal energy?The energy contained within a thermodynamic system is referred to as its internal energy. Internal energy is constant in an isolated system. It is the energy required to build or prepare the system in the internal state that it is in at the time.
The kinetic energy of individual particles within the system is included, but not the kinetic energy of motion of the system as a whole. It records the system's energy gains and losses that result from modifications to its internal state. It is impossible to directly quantify internal energy. It is determined by comparing the difference to a conventional state-defined reference zero.
We know that, change in internal energy at constant volume is given by
\(dE_{int}\) = n × Cv × dT
Here, n = no. of moles
Cv = molar heat capacity
dT = temperature difference
Applying the equation on the question, we get
\(dE_{int}\) = 1 mol × 12.47 J/mol k × 8k
= 99.76 J ≈ 100J
Hence, the change in internal energy during the process is 100 J
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The hot water needs of a household are to be met by heating water at 55oF to 200oF by a parabolic solar collector at a rate of 5. 4 lbm/s. Water flows through a 1. 25-in-diameter thin aluminum tube whose outer surface is blackanodized in order to maximize its solar absorption ability. The centerline of the tube coincides with the focal line of the collector, and a glass sleeve is placed outside the tube to minimize the heat losses. If solar energy is transferred to water at a net rate of 350 Btu/h per ft length of the tube, determine the required length of the parabolic collector to meet the hot water requirements of this house. Also, determine the surface temperature of the tube at the exit. The properties of water at the average temperature of (55 200)/2
the required length of the parabolic collector to meet the hot water requirements of the house is approximately 0.073 ft, and the surface temperature of the tube at the exit is 200°F.
To determine the required length of the parabolic collector and the surface temperature of the tube at the exit, we need to consider the energy balance equation.
The energy balance equation can be written as:
Q_in = m_dot * Cp * (T_out - T_in) - Q_loss
Where:
Q_in is the solar energy transferred to the water
m_dot is the mass flow rate of water
Cp is the specific heat capacity of water
T_out is the desired outlet temperature of water (200°F)
T_in is the initial temperature of water (55°F)
Q_loss is the heat loss from the system
First, let's calculate the solar energy transferred to the water:
Q_in = (m_dot * Cp) * (T_out - T_in)
Given:
m_dot = 5.4 lbm/s
Cp = specific heat capacity of water = 1 Btu/lbm°F
T_out = 200°F
T_in = 55°F
Q_in = (5.4 lbm/s * 1 Btu/lbm°F) * (200°F - 55°F)
Q_in = 924 Btu/s
Next, we need to calculate the heat loss:
Q_loss = (U * A) * (T_avg - T_amb)
Where:
U is the overall heat transfer coefficient
A is the surface area of the tube
T_avg is the average temperature of the water (T_avg = (T_in + T_out) / 2)
T_amb is the ambient temperature
Since the glass sleeve is placed outside the tube to minimize heat losses, let's assume the overall heat transfer coefficient is zero (U = 0). This implies that there are no heat losses from the system.
Therefore, Q_loss = 0 Btu/s
Now, we can rewrite the energy balance equation:
Q_in = m_dot * Cp * (T_out - T_in) - Q_loss
924 Btu/s = (5.4 lbm/s * 1 Btu/lbm°F) * (200°F - 55°F) - 0 Btu/s
Simplifying the equation, we can solve for the required length of the parabolic collector:
Length = Q_in / (Net rate of energy transfer per unit length)
Length = 924 Btu/s / 350 Btu/h per ft length
Length = 924 Btu/s / (350 Btu/h * 3600 s/h)
Length ≈ 0.073 ft
Finally, we can determine the surface temperature of the tube at the exit:
T_surface_exit = T_out - (Q_loss / (m_dot * Cp))
T_surface_exit = 200°F - (0 Btu/s / (5.4 lbm/s * 1 Btu/lbm°F))
T_surface_exit = 200°F
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Express the answer in scientific notation:
5.0 x 10^-7mg + 4 x 10^-8mg
Answer:
4 * 10^-8 mg = .4 * 10^-7 mg divide and multiply by 10
5.0 x 10^-7mg + .4 x 10^-7 mg = 5.4 x 10^-7 mg
Also 5.4 x 10^-7 mg = 5.4E-7 mg
At temperatures near absolute zero, Bc approaches 0.142 T for vanadium, a type-l superconductor. The normal phase of vanadium has a magnetic susceptibility close to zero Consider a long, thin vanadium cylinder with its axis parallel to an external magnetic field Bo in the +x-direction. At points far from the ends of the cylinder, by symmetry, all the magnetic vectors are parallel to the x-axis. Part A. At temperatures near absolute zero, what is the magnitude of the resultant magnetic field B inside the cylinder for Bo = (0.130T) B= ___ T . Part B What is the direction of the resultant magnetic field B inside the cylinder for this case? O in the +x direction Oin the -x direction O perpendicular to the x-axis the O field is zero. Part C What is the magnitude of the resultant magnetic field B outside the cylinder (far from the ends) for this case?
Part A: At temperatures near absolute zero, what is the magnitude of the resultant magnetic field B inside the cylinder for Bo = (0.130T) B= 0 T.
Part B: The direction of the resultant magnetic field B inside the cylinder is 0. The correct option is field is zero.
Part C: The magnitude of the resultant magnetic field B outside the cylinder is 0.130 T.
Part A: To find the magnitude of the resultant magnetic field B inside the cylinder at temperatures near absolute zero, we need to compare the external magnetic field Bo (0.130 T) to the critical field Bc (0.142 T). Since Bo < Bc, the vanadium acts as a perfect diamagnet and expels the external magnetic field. Thus, the magnetic field B inside the cylinder is 0 T.
Part B: Since the magnetic field B inside the cylinder is 0 T, there is no resultant magnetic field direction inside the cylinder in this case. The correct option is field is zero.
Part C: The magnitude of the resultant magnetic field B outside the cylinder (far from the ends) for this case is equal to the external magnetic field Bo. So, the magnetic field B outside the cylinder is 0.130 T.
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suppose that you have a piece of string 7 cm long. if one end is held fixed and you draw with a pen at the other end, keeping the string tight, then you will draw a circle. what is the circumference of this circle?
The circumference of the circle that can be drawn with a string that is 7 cm long is 7π or approximately 21.99 cm.
To find the circumference of the circle that can be drawn with a string that is 7 cm long, we need to use the formula for circumference. The formula for circumference is C = 2πr, where r is the radius of the circle.
Since we have a piece of string that is 7 cm long, this means that the radius of the circle is half of the length of the string, which is 7/2 = 3.5 cm.
Now, we can use the formula for circumference to calculate the value:
C = 2πr
C = 2π(3.5)
C = 7π
Therefore, the circumference of the circle that can be drawn with a string that is 7 cm long is 7π, which is approximately 21.99 cm (since π is approximately 3.14).
In conclusion, the circumference of the circle that can be drawn with a string that is 7 cm long is 7π or approximately 21.99 cm.
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You push a lawn mower across a level yard at constant velocity. You exert a
force of 75 N along the handle that makes a 43° angle with the horizontal.
What is the force of friction between the mower and the ground?
Answer:
Explanation:
11.535 newtons
which is the best definition of pitch
Answer:
a black or dark viscous substance obtained as a residue in the distillation of organic materials and especially tars
Explanation:
A racecar was going 60 m/s when it quickly came to a full stop at a pitstop in 8.0 sec. What was the acceleration of the dragster? Answer to the nearest hundredth
In a salt solution, salt is a solute. why
Answer: Because it can dissolve in water
Explanation: Logic
blocks x and y are attached to each other by a light rope and can slide along a horizontal surface. Mass of block x is 10 kg and that of block y is 5 kg. the magnitude of force of friction on blocks x and y is 8.0 N and 4.0N respectively. Find the action-reaction forces that the blocks exert on each other if an applied force of 40 N(right) acts on block per illustration below.
Blocks x and y exerts action-reaction forces on each other with 146.1 N and 53.1 N respectively.
The given parameters:
mass of block x = 10 kg
mass of block y = 5 kg
magnitude of the frictional force of block x = 8 N
magnitude of the frictional force of block y = 4 N
the applied force to the right = 40 N
To find:
the action-reaction forces that the blocks exert on each otherThe block y pulls block x to the left with the following reaction forces;
Force of block y = force due to its own weight + frictional force
Reaction Force of block y = mg + 4 Nwhere;
g is the acceleration due to gravity = 9.81 m/s²
Reaction Force of block y = (5 x 9.81) + 4Reaction Force of block y = 49.1 + 4Reaction Force of block y = 53.1 NThus, block y reacts on block x with a force of 53.1 N
The block x acts on block y towards the right direction with following forces;
Force of block x on y = force due to its own weight + frictional force + applied force to the right
Force of block x on y = (mg) + (8 N) + (40 N)Force of block x on y = (10 x 9.81) + (48)Force of block x on y = 98.1 + 48Force of block x on y = 146.1 NThus, block x acts on block y with a force of 146.1 N
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How are potential energy and kinetic energy related?
Answer:
Energy stored in an object due to its position is Potential Energy. Energy that is "stored" in a moving object has due to its motion is Kinetic Energy.