Answer:
the length of RB is 18 cm.
Step-by-step explanation:
In △QRS, since point A is between points Q and R, and point B is between points R and S, we have that QR > QA > 0 and RS > RB > 0. Additionally, since AB∥QS, we know that the segment AB is parallel to the segment QS.
We can use this information to set up an equation to solve for RB. Since AB∥QS and QA = 23 cm, we have that QR = RB + 23. We can substitute this expression into the equation QR = 41 cm to get:
RB + 23 = 41
Solving this equation for RB, we get:
RB = 41 - 23
Therefore, the length of RB is 18 cm.
A simple linear regression model is given as: y = 70 + 10x + ϵ , with the error standard deviation as σ = 5. The intercept in the regression model is ?
In the given model, the intercept for the regression model is 70.
The intercept in the given simple linear regression model is 70. This means that when the independent variable (x) is zero, the predicted value of the dependent variable (y) is 70. The intercept represents the starting point or the y-value when x is zero in the regression equation.
In a simple linear regression model, the equation takes the form: y = β0 + β1x + ϵ, where β0 represents the intercept, β1 represents the coefficient of the independent variable (x), and ϵ represents the error term.
In the given regression model, the intercept (β0) is stated as 70. This means that when x is zero, the predicted value of y is 70. The intercept captures the inherent value of y that is not explained by the independent variable. It represents the baseline value of y when there is no influence from x.
Therefore, in the given model, the intercept is 70.
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sara chose a date from the calendar. what is the probability that the date she chose is a prime number, given that the date is after the 7th of the month?
The probability that the date sara chose is a prime number is 0.2.
Given that, sara chose a date from the calendar.
We know that, probability of an event = Number of favourable outcomes/Total number of outcomes.
Here, total number of outcomes = 30
Number of favourable outcomes = 6
Now, probability = 6/30
= 1/5
= 0.2
Therefore, the probability that the date sara chose is a prime number is 0.2.
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What is the coefficient of the term of degree 1 in the polynomial?
2x^8 - 5x^2 + 3x+ 4
Answer:
3
Step-by-step explanation:
The term with a degree of 1 is 3x. The coefficient of that term is 3.
Options are PR = 18, 14, 9 and 11 please help me with which it is
Given B=45, C=95, & c=5. Find b. This is Laws of Sines
Answer:
b = 3.55 to the nearest hundredth.
Step-by-step explanation:
b / sin B = c / sin C
b / sin 45 = 5 / sin 95
b = 5 sin 45 / sin 95
= 3.549.
a sequence is a set of
Answer:
set of related events, movements, or things that follow each other in a particular order.
Step-by-step explanation:
a sequence is an enumerated collection of objects in which repetitions are allowed and order matters. Like a set, it contains members (also called elements, or terms). The number of elements (possibly infinite) is called the length of the sequence.
simplify: log64+2log5-2log40
Answer: 0
Step-by-step explanation:
Use rules of logarithms to condense.
find the mass and center of mass of the solid e with the given density function . e is the tetrahedron bounded by the planes x = 0, y = 0, z = 0, x y z = 2; (x, y, z) = 8y.
The answer to the following question is 2ln2 -2 and 4√2 - 4.
To find the mass and centre of mass of the solid e, we need to first find the volume of the tetrahedron, which is given by the integral and then calculating mass and centre of mass respectively:
V = ∫∫∫e dx dy dz
where e is the region enclosed by the planes x = 0, y = 0, z = 0, and xy z = 2. Since the density function is given by ρ(x, y, z) = 8y, the mass of the tetrahedron is given by the integral:
M = ∫∫∫e ρ(x, y, z) dx dy dz
We can compute the integrals using the following order of integration: first integrate over z from 0 to 2/xy, then integrate over y from 0 to 2/x, and finally integrate over x from 0 to √2. This gives:
Mass = ∫∫∫e dx dy dz = ∫0^√2 ∫0^2/x ∫0^2/(xy) dz dy dx
= ∫0^√2 ∫0^2/x [2/(xy)] dy dx
= ∫0^√2 [2 ln(2/x)] dx
= 2 ∫0^√2 ln(2/x) dx
= 4√2 - 4
Centre of Mass = ∫∫∫e ρ(x, y, z) dx dy dz = 8 ∫∫∫e y dy dz dx
= 8 ∫0^√2 ∫0^2/x ∫0^2/(xy) y dz dy dx
= 8 ∫0^√2 ∫0^2/x [1/2(2/(xy))^2] dy dx
= 2 ∫0^√2 [ln(2/x)]^-1 dx
= 2 ln(2) - 2.
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What happens to the ones digit when you add on tens?
Answer:
nothing
Step-by-step explanation:
The ones digit will not change.....only the 'tens' digit will change...
A chi-square test for independence has df = 2. what is the total number of categories (cells in the matrix) that were used to classify individuals in the sample?
According to the given statement There are 2 rows and 3 columns in the matrix, resulting in a total of 6 categories (cells).
In a chi-square test for independence, the degrees of freedom (df) is calculated as (r-1)(c-1),
where r is the number of rows and c is the number of columns in the contingency table or matrix.
In this case, the df is given as 2.
To determine the total number of categories (cells) in the matrix, we need to solve the equation (r-1)(c-1) = 2.
Since the df is 2, we can set (r-1)(c-1) = 2 and solve for r and c.
One possible solution is r = 2 and c = 3, which means there are 2 rows and 3 columns in the matrix, resulting in a total of 6 categories (cells).
However, it is important to note that there may be other combinations of rows and columns that satisfy the equation, resulting in different numbers of categories.
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which of the following is (are) time series data? i. weekly receipts at a clothing boutique ii. monthly demand for an automotive part iii. quarterly sales of automobiles
i. weekly receipts at a clothing boutique
ii. monthly demand for an automotive part
Which data sets represent time series data?Time series data refers to information collected and recorded at regular intervals over a specific period. In the case of i. weekly receipts at a clothing boutique and ii. monthly demand for an automotive part, both data sets are examples of time series data.
Time series data consists of observations recorded over regular intervals, allowing for the analysis of patterns and trends over time. In i. weekly receipts at a clothing boutique, the data is collected on a weekly basis, providing insights into the boutique's revenue fluctuations over different weeks. Similarly, ii. monthly demand for an automotive part captures the demand for the part on a monthly basis, enabling analysis of monthly variations and seasonal patterns.
On the other hand, iii. quarterly sales of automobiles do not fall under time series data. While it represents sales data, the intervals between measurements are not consistent enough to qualify as time series. Quarterly intervals are less frequent and may not capture shorter-term trends or variations as effectively as weekly or monthly intervals.
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According to an article on yahoo!news, you should change your sheets every 7 days...at minimum. to investigate the sheet changing habits of adults, a random sample of 20 adults reported how often they change their sheets using an anonymous survey.
The sheet-changing habits of a sample of 20 adults were surveyed and analyzed to estimate the sheet-changing habits of the general population. The mean and standard deviation were calculated, and a 95% confidence interval was constructed.
First, we can calculate the mean of the sample to determine the average sheet-changing frequency among the adults surveyed. To do this, we add up the sheet-changing frequencies for each adult and divide by the total number of adults:
Mean sheet-changing frequency = (frequency for adult 1 + frequency for adult 2 + ... + frequency for adult 20)/20
= (7 + 14 + ... + 28)/20
= X/20
Next, we can calculate the standard deviation of the sample to determine the degree of variation in sheet-changing habits among the adults surveyed.
Sum of squares of differences = ∑(sheet-changing frequency - mean sheet-changing frequency)²
For each adult in the sample, we can calculate the difference between their sheet-changing frequency and the mean frequency:
Adult 1: 7 - X
Adult 2: 14 - X
.
.
.
Adult 20: 28 - X
The sum of squares of differences is then:
Sum of squares of differences \(= (7 - X)^2 + (14 - X)^2 + ... + (28 - X)^2\)
We can then divide the sum of squares by the degrees of freedom (20-1=19) and take the square root to calculate the standard deviation:
Standard deviation = √((sum of squares of differences)/(degrees of freedom))
= √((X)/19)
= Y
To calculate the confidence interval, we can use the following formula:
Confidence interval = mean ± (critical value * standard deviation/√(sample size))
The critical value can be obtained from a t-table based on the desired confidence level and degrees of freedom. For a 95% confidence interval with 19 degrees of freedom, the critical value is 2.093.
Plugging in the values for the mean, standard deviation, and critical value, we can calculate the 95% confidence interval for the population mean sheet-changing frequency:
Confidence interval = X ± (2.093 * Y/√20) = X ± Z
The confidence interval gives us an estimated range for the population mean sheet-changing frequency, with a 95% level of confidence. This can be useful in understanding the sheet-changing habits of the general adult population, based on the sample data collected.
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Ms. Palmer is buying pencils and erasers. The pencils come in packs of 8. The erasers come in packs of 12. Ms. Palmer wants to have one eraser per pencil. What is the fewest number of packs of each item that she needs to buy? How many of each item will she have?
(a) Find an equation for the plane that is perpendicular to v = (1, 1, 1) and passes through (1, 0, 0). x + y + z = 1 (b) Find an equation for the plane that is perpendicular to v = (2,6, 9) and passes through (1, 1, 1). x+y+z=1 x (c) Find an equation for the plane that is perpendicular to the line 1(t) = (9,0, 6) + (2, -1, 1) and passes through (9, -1,0). 3x + 2z=27 (d) Find an equation for the plane that is perpendicular to the line l(t) = (-3, -6, 8) + (0, 8, 1) and passes through (2, 4, -1).
a) The equation of plane is x − y = 1. ; b) The equation of the plane is -3x + y = -2. ; c) The equation of the plane is x + 2y + 3z = 27. ; d) The equation of the plane is -8x + y = -18.
(a) Find an equation for the plane that is perpendicular to v = (1, 1, 1) and passes through (1, 0, 0).The equation of a plane can be represented in the form of Ax + By + Cz = D.
We have the following information:Vector v = (1, 1, 1)Point P = (1, 0, 0)To find the normal to the plane, we need to calculate the cross product of vector v and a vector that connects the given point and any other point on the plane: 0 = (y − 0) + (z − 0) implies y + z = 0.The normal vector is (1, -1, 0).
So the equation of the plane is:1(x) − 1(y) + 0(z) = D1(1) − 1(0) = D1 = D
(b) Find an equation for the plane that is perpendicular to v = (2,6, 9) and passes through (1, 1, 1).The equation of a plane can be represented in the form of Ax + By + Cz = D. We have the following information:
Vector v = (2, 6, 9)
Point P = (1, 1, 1)
To find the normal to the plane, we need to calculate the cross product of vector v and a vector that connects the given point and any other point on the plane.So, the normal vector is (-3, 1, 0).
(c) Find an equation for the plane that is perpendicular to the line 1(t) = (9,0, 6) + (2, -1, 1) and passes through (9, -1,0).The equation of a plane can be represented in the form of Ax + By + Cz = D.
We have the following information:Point P = (9, -1, 0)Vector v = (2, -1, 1)
To find the normal to the plane, we need to calculate the cross product of vector v and a vector that connects the given point and any other point on the plane.
So, the normal vector is (1, 2, 3).
(d) Find an equation for the plane that is perpendicular to the line l(t) = (-3, -6, 8) + (0, 8, 1) and passes through (2, 4, -1).The equation of a plane can be represented in the form of Ax + By + Cz = D.
We have the following information:Point P = (2, 4, -1)Vector v = (0, 8, 1)
To find the normal to the plane, we need to calculate the cross product of vector v and a vector that connects the given point and any other point on the plane.So, the normal vector is (-8, 1, 0).
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Dee spends $0.25, $0.30, $0.10 and $0.04.
How much $ does she spend in all?
By adding all the money she spend we get $0.69
What is the unitary method?The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.
Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.
We are given that Dee spends $0.25, $0.30, $0.10 and $0.04.
We need to find the money she spend in all.
Therefore, we have to add all the expenditure
0.25 + 0.30 + 0.10 + 0.04 = 0.69
The total money she spend could be 0.69.
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-3(2t - 1) = t + t + t + 3
Answer:
-3(2t - 1) = t + t + t + 3
-6t + 3 = 3t + 3
-6t -3t = 3t - 3t +3
-9t + 3 - 3 = 0
9t = 0
t = 0
Step-by-step explanation:
A hardware dealer has 168kg of nails, if one nail weighs 0.25kg, how many nails he have?
Answer:
He has 672 nails
Step-by-step explanation:
168/.25
Answer:
He has 672 nails.
Step-by-step explanation:
Weight of all nails=168
Weight of a nail=0 .25
Then,
Number of nails=168/0.25
=672
How much tax would you pay on items that cost $13.25 if the tax rate is 7%?
the graph represents a function with the form f(x)=asin(bx+c) which values of a,b, and c are possible
Answer:B
Step-by-step explanation: edge 2020
A device contains two components. The device fails if either component fails. The joint density function of the lifetimes of the components, measured in hours is f (s, t), where 0
The probability that the device fails during its first hour of operation is; 0.625
How to Calculate Joint Density Function?
The joint density function of the lifetimes of the two components, both measured in hours, is:
f(x, y) = (x + y)/8; 0 < x < 2, 0 < y < 2
Compute the probability that the device fails during its first hour of operation as follows:
P[(X < 1) ∪ (Y < 1)] = 1 - \(\int\limits^2_1 {} \int\limits^2_1 {\frac{x + y}{8} } \, dx \, dy\)
Integrating the above with respect to the boundary conditions as above gives;
P[(X < 1) ∪ (Y < 1)] = 1 - 0.375
P[(X < 1) ∪ (Y < 1)] = 0.625
The complete question is;
A device runs until either of two comonents fails, at which point the device stops running. The joint density function of the lifetimes of the two components, both measured in hours, is f(x,y) = x + y/8 for 0 < x < 2 and 0 < y < 2Calculate the probability that the device fails during its first hour of operation.
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please help me out, I'll give anyone a brainliest in they can help me :)
Euler's formula, V − E + F = 2 relates the number of vertices V, the number of edges E, and the number of faces F of a polyhedron. Solve Euler's formula for V.
1. V = 2 − E − F
2. V = 2 + E − F
3. V = −2 + E − F
4. V = −2 − E − F
The Euler's formula solved for the variable V gives . V = 2 + E − F. Option 2
What is subject of formula?The subject of a formula is the variable or variables that represent the quantity being calculated or solved for.
In mathematical formulas, the subject is typically denoted by a letter or symbol, and the formula shows the relationship between the subject and other variables or constants in the equation.
From the information given, we have that;
V − E + F = 2
To make the variable, V, the subject, take the steps
collect the variable E
V + F = 2 + E
Now, collect the F variable
V = 2 + E - F
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1. Find the length of each leg.
R
Q
30⁰
4
60%
P
Answer:
QP = 2
QR = 2√3
Step-by-step explanation:
This is a special right triangle with angle measures as follows:
30° - 60° - 90°
And side lengths represented with:
x - x√3 - 2x respectively to angle measures.
The side length that sees angle measure 90, hypotenuse, is given as 4 so the legs would be:
2 and 2√3
Consider the telephone tariff (charge) schedule by the telephone company: a. First examine the cost of an average phone call with the following charge schedule: each call is charged r for the initial period of length / (or fraction thereof). For call length exceeding !, you are charged incrementally for each subsequent period of length S(or fraction thereof), at a unit cost of p. What is the average cost of a call? (Note that it is a standard practice in the industry to assume that call duration is exponentially distributed.) b. If the cost of a call is $1 per minute, and your call is always pro-rated (as fraction of a minute) and the average call length is one minute, then the average cost of a call is just $1. If your call is rounded up to the next minute (I = S = 1), use the formula derived above to find the average cost. (Are you surprised?) c. If I = S = 0.1 (i.e., rounded up to the next 6 seconds), compute the average cost again.
The average cost of a call depends on the initial period, subsequent period, and unit cost for each subsequent period. By using the formula derived above, we can calculate the average cost of a call for different values of I, S, and p.
The average cost of a call can be calculated using the formula: Average Cost = r + p(S-1)/(S-1+1/e^S), where r is the cost for the initial period, p is the unit cost for each subsequent period, and S is the length of each subsequent period.
If the cost of a call is $1 per minute and the average call length is one minute, then the average cost of a call is just $1. However, if the call is rounded up to the next minute (I = S = 1), then the average cost can be calculated using the formula derived above: Average Cost = r + p(S-1)/(S-1+1/e^S) = $1 + $1(1-1)/(1-1+1/e^1) = $1 + $1(0)/(0+1/e) = $1.
If I = S = 0.1 (i.e., rounded up to the next 6 seconds), then the average cost can be calculated using the formula derived above: Average Cost = r + p(S-1)/(S-1+1/e^S) = $1 + $1(0.1-1)/(0.1-1+1/e^0.1) = $1 + $1(-0.9)/(-0.9+1/e^0.1) = $1.07.
Therefore, the average cost of a call depends on the initial period, subsequent period, and unit cost for each subsequent period. By using the formula derived above, we can calculate the average cost of a call for different values of I, S, and p.
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Someone please help me asap! I will mark as brainliest, thank you!!
Answer:
Perimeter of ABCD = 2(24 + 26 + 28 + 25) = 206 mm.
Step-by-step explanation:
Perimeter of ABCD = 2(24 + 26 + 28 + 25) = 206 mm.
Compare the process of solving
|x - 1 + 1 < 15 to that of solving
1x – 1| + 1 > 15.
Answer:
x-1+1<15; this gonna be x<15 and 1x-1+1>15 this is gonna be the same
Step-by-step explanation:
cos(6x-12) = sin(8x-10)
Subtract sin (8x − 10) from both sides of the equation.
cos (6x − 12) − sin (8x − 10) = 0
Answer:
It doesn't exist
Step-by-step explanation:
since :
cos (90° – x) = sin x
cos(x) = sin(pi/2 - x)
then
cos(6x-12) =! sin(8x-10)
since (8x-10) =! (pi/2- 6+12)
then this identity of cos(6x-12) = sin(8x-10) doesn't exist
happy new year. eeeeeeeee e
Answer:
yeah happy new year but your answer is D
Step-by-step explanation:
I'm good at math
Answer:
What is the slope of a line parallel to the line whose equation is 2x-y=7. Fully simplify your answer.
Answer:
Step-by-step explanation:
Q
(
2
,
1
)
and
R
(
8
,
13
)
is partitioned from
Q
to
R
into a
1
:
2
ratio at point
Z
. What are the coordinates of
Z
?
HELP PLEASE 2x+2<-4x+22<6x+10
Answer:
6//5,10/3
Step-by-step explanation:
maybe hope this is help