In poor weather you should___ your following distance
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Two kg of a two phase liquid vapor mixture of carbon dioxide(co2) exists at a - 40C in a 0.05 tank
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The question is incomplete. Here is the complete question.
Two kg of a two phase liquid vapor mixture of carbon dioxide (CO₂) exists at -40°C in a 0.05m³ tank. Determine the quality of the mixture, if the values of specific volume for saturated liquid and saturated vapor CO₂ at -40°C are \(v_{f}\) = 0.896 x 10⁻³m³/kg and \(v_{g}=\) 3.824 x 10⁻²m³/kg, respectively.
Answer: x = 1
Explanation: In a phase change of a pure substance, at determined pressure and temperature, the substance exists in two different phases: saturated liquid and saturated vapor.
Quality (x) is the ratio of saturated vapor in the mixture and can be written as:
\(x=\frac{m_{vapor}}{m_{liquid}+m_{vapor}}\)
It has value between 0 and 1: x = 0 for saturated liquid and x = 1 for saturated vapor.
When related with volumes, quality is rearranged as:
\(x=\frac{v-v_{f}}{v_{g}-v_{f}}\)
Solving for x:
\(x=\frac{0.05-0.896.10^{-3}}{3.824.10^{-2}-0.896.10^{-3}}\)
\(x=\frac{0.049104}{0.037344}\)
x = 1.3
Quality of mixture of carbon dioxide is x = 1, which means it's for saturated vapor.
Why are there few effective HCI standards?
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Answer:
There are few effective Human Computer Interaction (HCI) standards because for one, standards are more suitable for hardware than software because they are relatively unstable. ... Some software product standards have been in place long before any formal standard documents were published.
Need help please due today ill give brainliest for non-irrelevant answers
Describe the quality control measures engineers likely will use for a newly introduced line of cars that use solar power to recharge high-capacity batteries. Propose at least three tests or processes that will be important to any quality assessment for such a vehicle system.
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Answer:
make sure its safe make sure it works as inteded
Explanation:
yes
A feature control frame must be connected to
Answers
Answer:
Surface Parallelism When a surface is to be parallel to a datum plane, the feature control frame is connected by a leader to the surface, or to an extension line from the surface.
Explanation:
Which characteristic would atoms of a ferromagnetic material have?A. A lack of electrons B. North and south poles C. A temporary magnetic field D. The ability to attract nonmagnetic materials
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Answer:
Option B
Explanation:
Atoms of ferromagnetic materials have north and south pole but these atoms are oriented in random directions due to which they do no exhibit magnetic properties until unless they are brought into influence of any external temporary or permanent magnetic field.
Under the influence of external magnetic force, the atoms of the ferromagnetic material get oriented in a particular direction.
Hence, option B is correct
Why does the ceramic made from Thorium and Oxygen have the chemical ratio of 2 oxygen atoms to every thorium atom (ThO2)
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You are to dim your headlights at a minimum distance of ____ when following another vehicle. A.) 100 feet.B.) 300 feet. C.) 750 feet. D.) 1,000 feet.
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B) You are to dim your headlights at a minimum distance of 300 feet when following another vehicle.
You can find yourself operating a vehicle in a construction zone, on an unfamiliar road, or on a dark downtown street. Realizing that you can't see the road ahead is unsettling. Slow down if your vision is blurry. Turn on your high lights if there are no other vehicles in the area. The pedestrians and cyclists who may be crossing in front of you or walking along the side of the road will also be safe thanks to your high lights. State law normally mandates that you lower your high lights in metropolitan areas when approaching cars are within 300 to 1000 feet. Also, you must dim them when you are 200 to 300 feet or less from a vehicle you are following, particularly at stop signs and traffic lights.
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A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
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Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
A force of 100 kip is acting at angle of 60 with horizontal axis. What is horizontal component of the force? 100* Cos60 100* Sin60 100* Sin30 100* Cos3
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The horizontal component of a force of 100 kip acting at an angle of 60 degrees with the horizontal axis is 50 kip.
To determine the horizontal component of a force, we use trigonometric functions. In this case, we can use the cosine function to find the horizontal component. The cosine of an angle is defined as the ratio of the length of the adjacent side to the length of the hypotenuse in a right triangle.
In the given scenario, the force of 100 kip can be represented as the hypotenuse of a right triangle, with the horizontal component being the adjacent side. The angle between the force and the horizontal axis is 60 degrees. By using the cosine function, we can calculate the horizontal component as the product of the force magnitude (100 kip) and the cosine of the angle (cos 60 degrees):
Horizontal component \(= 100 kip \times cos(60 \textdegree) = 100 kip \times 0.5 = 50 kip.\)
Therefore, the horizontal component of the force is 50 kip.
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Kendal is working on a document with a SmartArt object. The SmartArt is obscured by a picture. In order to ensure the SmartArt is visible, she should do which of the following?
1. Bring the SmartArt object to the front.
2. Align the SmartArt object to the top.
3. Change the text wrapping to In Front of Text.
4. Set the vertical alignment to Top.
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The correct answer to the question is option 1. In order to ensure the SmartArt is visible, Kendal should bring the SmartArt object to the front.
What is SmartArt? SmartArt is a new feature in Microsoft Office applications that enables users to create diagrams and charts to represent information graphically. Excel, Outlook, PowerPoint, and Word all support SmartArt graphics. This tool lets you quickly create an amazing graphic that can be customized to your specific needs, making it easier to present complex data with clarity and style. Therefore, to ensure the SmartArt is visible, Kendal should bring the SmartArt object to the front.
To ensure that the SmartArt object is visible and not obstructed by other elements such as pictures in Microsoft Office applications like Excel, Outlook, PowerPoint, or Word, Kendal should bring the SmartArt object to the front. By bringing the SmartArt object to the front, it will be positioned in a higher layering order compared to other objects, allowing it to appear in front of the picture and ensuring its visibility.
This adjustment in layering order can be done within the application's interface, usually through options like "Bring to Front" or "Move Forward" available in the formatting or arrange menus. By selecting these options for the SmartArt object, Kendal can ensure that it is positioned above the picture and easily visible to viewers. This way, SmartArt can effectively present complex information in a visually appealing and comprehensible manner.
It's important to note that SmartArt is a powerful feature that allows users to create dynamic and customizable diagrams and charts, aiding in the effective communication of data. By bringing the SmartArt object to the front, Kendal can maximize its impact and ensure that it is prominently displayed within the document or presentation.
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to avoid falling objects in construction don't stack materials higher than
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Answer:Falling or flying objects on a worksite can expose workers to relatively minor injuries, such as cuts and abrasions, as well as more serious injuries, such as concussions or blindness. Working beneath scaffolds or other areas where overhead work is being performed puts workers at risk from falling objects. Flying objects become a concern when workers are using power tools or performing tasks that involve pushing, pulling or prying.
Explanation:General
Always wear hard hats when work is being performed overhead or when other work conditions call for it.
Stack materials securely to prevent them from sliding, falling or collapsing.
Overhead work
Secure all tools and materials to prevent them from falling on people below.
Use toe boards or guardrails on scaffolds to prevent objects from falling. Alternately, use debris nets or catch platforms to grab falling objects.
Machine use
When working with machines or power tools that can produce flying particles, wear safety glasses, goggles or face shields.
Inspect tools prior to use, and be sure all guards are in place and in good working condition.
Allow only properly trained workers to use power-actuated tools.
Cranes/hoists
Whenever possible, avoid working under moving loads.
Erect barricades and post warning signs at hazardous work zones.
Inspect cranes and hoists prior to use to ensure all components are in good working order, including wire rope, lifting hooks and chains.
Never exceed the lifting capacity of cranes and hoists.
Compressed air
Reduce compressed air for cleaning to 30 psi, and always use proper personal protective equipment and guarding.
Never clean clothing with compressed air.
Quotient rule of sin3x.se X/3
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Answer:
\(y' = \frac{sec(x)}{3}[sin(3x) tan(x) + 3cos(3x)]\)
Explanation:
Given
\(\frac{sin3x\ secx}{3}\)
Required
The quotient rule
Quotient rule states that:
\(y' = \frac{V\frac{du}{dx} - U\frac{dv}{dx}}{v^2}\)
Where
\(v = 3\) and \(\frac{dv}{dx} = 0\)
\(u = sin3x\ secx\)
\(\frac{du}{dx}\) using product rule is:
\(\frac{du}{dx} = sin3x * \frac{d[secx]}{dx} + secx * \frac{d[sin3x]}{dx}\)
Differentiate all:
\(\frac{du}{dx} = sin(3x) sec(x) tan(x) + 3sec(x)cos(3x)\)
Factorize:
\(\frac{du}{dx} = sec(x)[sin(3x) tan(x) + 3cos(3x)]\)
So, the rule:
\(y' = \frac{V\frac{du}{dx} - U\frac{dv}{dx}}{v^2}\) becomes
\(y' = \frac{3[sec(x)[sin(3x) tan(x) + 3cos(3x)]] - [sin3x\ secx] * 0}{3^2}\)
Solving further:
\(y' = \frac{3[sec(x)[sin(3x) tan(x) + 3cos(3x)]]}{9}\)
\(y' = \frac{sec(x)[sin(3x) tan(x) + 3cos(3x)]}{3}\)
\(y' = \frac{sec(x)}{3}[sin(3x) tan(x) + 3cos(3x)]\)
Find Ic(t),
If Vs(t)=8sin(4t+180°) V
3
د3
lic
62.5met
O 2.5cos(4t+53.1) A
O scos(4x+53.1°) A
O 2.5cos(4t+143°) A
Oscos(4t+143) A
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Answer:
the answer is equal to 2.5cos(4t +53.1)
In which of the following classes of games would a Nash equilibrium in mixed strategies exist?
___ Prisoner’s Dilemma ___ Games with 2 pure Nash eq. ___ Chicken Games
___ Leadership Games ___ 2x2 game with dominated strategies
___ Battle of the 2 Cultures ___ 3x3 game with a dominant strategy by only 1 player
Answers
Nash equilibrium in mixed strategies would exist in Prisoner's Dilemma, Chicken Games, and Leadership Games, but not in games with 2 pure Nash equilibria or 2x2 games with dominated strategies.
To determine in which classes of games a Nash equilibrium in mixed strategies would exist, we need to analyze each class of game and consider the conditions for a Nash equilibrium. Here's a step-by-step explanation:
1. Prisoner's Dilemma: In the Prisoner's Dilemma, where two players must decide to cooperate or betray each other, a Nash equilibrium in mixed strategies can exist. Each player can randomize their actions to create uncertainty for the opponent and achieve an equilibrium.
2. Games with 2 pure Nash equilibria: In games with 2 pure Nash equilibria, where both players have two possible strategies resulting in Nash equilibria, there is no need for mixed strategies. Each player can simply choose one of the pure Nash equilibria.
3. Chicken Games: In Chicken Games, where two players must decide whether to swerve or continue straight, a Nash equilibrium in mixed strategies can exist. By randomizing their choices, players can create uncertainty and ensure no player has an incentive to deviate.
4. Leadership Games: Leadership Games involve a leader and a follower, where the leader chooses an action first, and the follower observes it before making their decision. In such games, a Nash equilibrium in mixed strategies can exist if the leader randomizes their actions and the follower's best response is a mixed strategy.
5. 2x2 game with dominated strategies: In a 2x2 game with dominated strategies, where one strategy is strictly dominated by another for both players, there is no Nash equilibrium in mixed strategies. The players would have dominant strategies, and the equilibrium would be in the form of a pure strategy.
6. Battle of the 2 Cultures: There is not enough information provided to determine whether a Nash equilibrium in mixed strategies would exist in the Battle of the 2 Cultures game. Without knowledge of the specific game structure and payoff matrix, it is not possible to make a definitive determination.
7. 3x3 game with a dominant strategy by only 1 player: In a 3x3 game where only one player has a dominant strategy, there can still be a Nash equilibrium in mixed strategies. The player with the dominant strategy can randomize their choices, while the other player chooses their actions accordingly.
In summary, a Nash equilibrium in mixed strategies would exist in the Prisoner's Dilemma, Chicken Games, and Leadership Games. It would not exist in games with 2 pure Nash equilibria or 2x2 games with dominated strategies. The determination for the Battle of the 2 Cultures game cannot be made without further information.
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Draw the circuit diagram for 3 cells connected in series, two resistors in series and a switch.
If V = I x R, calculate l if one cell = 2V and the resistor = 4Ω.
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Answer:
See the image for solution
A motor car reaches a velocity of 17 m/s from rest. Draw a velocity-time graph and determine the acceleration.
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The automobile initially accelerates for 5 seconds. As a result, the velocity-time graph initially slopes and then maintains a constant speed.
What is velocity of time ?Your understanding of velocity and its scientific definition are probably similar. You are aware that a big displacement over a short period of time corresponds to a large velocity, and that velocity is measured in terms of the speed of objects in terms of miles an hour or kilometres per hour. The shift in position multiplied by the distance travelled is how average velocity is calculated. Velocity and speed describe how quickly or slowly a moving object moves. We frequently encounter circumstances when we must determine which of two or more moving objects is going faster. If the two are travelling on the same route in the same direction, it is simple to determine which is quicker.
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what are the types of knives
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Some types of knives are listed as follows:
Chef's knife - used for chopping, slicing, and dicing ingredientsSantoku knife - a Japanese-style knife with a shorter blade, used for a variety of tasksParing knife - used for peeling and trimming fruits and vegetablesSerrated knife - used for slicing bread and other soft foodsBread knife - used for slicing through hard crusts without crushing the soft interiorCleaver - a heavy knife used for chopping through bones and other tough materialsWho invented Knives?The exact origin of knives is unc
The oldest known knife dates back to 2.5 million years ago and was discovered in Ethiopia. Knives have evolved over time and have been made from various materials including stone, bone, and metal. The exact inventor of knives is not known, but they have played an essential role in human survival and development throughout history.
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Which control would be used to manually feed a cutting tool longitudinally across the workpiece?
Answers
The carriage handwheel is used to manually position and/or hand feed the carriage in the longitudinal or Z axis.
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A single fixed pulley is used to lift a load of 400N by the application of an effort of 480N in 10s through a vertical height of 5m. Determine the V.R, M.A and efficiency of the machine.
Answers
Answer:
(a) the velocity ratio of the machine (V.R) = 1
(b) The mechanical advantage of the machine (M.A) = 0.833
(c) The efficiency of the machine (E) = 83.3 %
Explanation:
Given;
load lifted by the pulley, L = 400 N
effort applied in lifting the, E = 480 N
distance moved by the effort, d = 5 m
(a) the velocity ratio of the machine (V.R);
since the effort applied moved downwards through a distance of d, the load will also move upwards through an equal distance 'd'.
V.R = distance moved by effort / distance moved by the load
V.R = 5/5 = 1
(b) The mechanical advantage of the machine (M.A);
M.A = L/E
M.A = 400 / 480
M.A = 0.833
(c) The efficiency of the machine (E);
\(E = \frac{M.A}{V.R} \times 100\%\\\\E = 0.833 \ \times \ 100\%\\\\ E = 83.3 \ \%\)
if each nail can support a shear force of 200 lblb , determine the maximum spacing of the nail ss .
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The maximum spacing of the nails can be calculated by dividing the length of the member by the number of nails minus one, assuming each nail can support a shear force of 200 lb.
What is the method to determine the maximum spacing of nails?To determine the maximum spacing of the nails, we need to consider the shear force capacity of each nail and the total shear force that needs to be supported.
If each nail can support a shear force of 200 lb, and we assume the load is evenly distributed among the nails, we can calculate the maximum spacing.
Let's say the total shear force that needs to be supported is S lb. If we divide S by 200 lb, we get the minimum number of nails required.
To find the maximum spacing, we divide the length of the member by the number of nails minus 1 (since there will be one less gap than the number of nails).
Therefore, the maximum spacing of the nails would be (length of member) / (number of nails - 1).
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The A-36 steel drill shaft of an oil well extends 12 000 ft into the ground. Assuming that the pipe used to drill the well is suspended freely from the derrick at A, determine the maximum average normal stress in each pipe string and the elongation of its end D with respect to the fixed end at A. The shaft consists of three different sizes of pipe, AB, BC, and CD, each having the length, weight per unit length, and cross-sectional area indicated.
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check photo solvecheck photo solve
A soil sample, taken from a borrow pit has a specific gravity of soil solids of 2.66. The sample was taken to a materials laboratory and tested. The results of a standard Proctor test are tabulated below.
Weight of Soil (lb) Moisture Content (%)
3.20 12.8
3.78 13.9
4.40 15.0
4.10 15.7
3.70 16.6
3.30 18.1
The maximum dry density in lb/ft3 is most nearly:_______
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Answer:
115 Ib/ft^3
Explanation:
To determine the maximum dry density in Ib/ft3 we have to calculate :
Bulk unit weight ( yb ) ; W / v
Dry unit weight ( yd. ) : yb / ( 1 + w )
For every set of data given
assuming v = 1/30 ft^3
calculating for the 3 data set ( maximum dry density )
weight of soil (W) = 4.40
moisture content (%) (w) = 15.0 = 0.15
Bulk unit weight (yb) = 4.40 / (1/30) = 132 Ib/ft^3
Dry unit weight ( yd. ) = 132 / ( 1 + 0.15 ) = 114.702 Ib/ft^3
therefore after calculations the maximum dry density in Ib/ft^3 ≈ 115 Ib/ft^3
To convert a measurement in centimeters to
meters, you simply move the decimal point
a. two places to the left
b. three places to the right
c. three places to the left
do four places to the right
Answers
Answer:
a
Explanation:
To convert a measurement in centimeters to meters, simply move the decimal point two places to the left. Thus, the correct option is A). two places to the left.
What is the way to convert centimeters to meters and decimals?There are 100 centimeters in every meter, which means that dividing the measurement in centimeters by 100 will convert it to meters. This conversion is very quick and easy by simply moving the decimal point in the measurement 2 spaces to the left.
The centimeter to meter conversion (cm to m) is basically, the conversion from centimeters to meters. One centimeter is approximately equal to 0.01 meter or we can say that one meter equals to 100 centimeters.
Simply, in order to convert cm to m, multiply the given centimeter value by 0.01 m. For example:- 5 cm = 5 x 0.01 m
5 cm = 0.05 m
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A cylindrical specimen of some metal alloy 10 mm in diameter and 150 mm long has a modulus of elasticity of 100 GPa. Does it seem reasonable to expect a tensile stress of 200 MPa to produce a reduction in specimen diameter of 0.08 mm
Answers
Answer:
N0
Explanation:
It does not seem reasonable to expect a tensile stress of 200 MPa to produce a reduction in specimen diameter of 0.08 mm
Given data :
Diameter ( d ) = 10 mm
length ( l ) = 150 mm
elasticity ( ∈ ) = 100 GPa
longitudinal strain ( б ) 200 MPa
Poisson ratio ( μ ) ( assumed ) =0.3
Assumption : deformation totally elastic
attached below is the detailed solution to why it is not reasonable .
The Sd value = 0.08 > the calculated Sd value ( 6*10^-3 ) hence it is not reasonable to expect a tensile stress of 200 MPa to produce a reduction in specimen
You have a Linux system that has a 1000GB SSD, which has a 90GB partition containing an ext4 filesystem mounted to the / directory and a 4GB swap partition. Currently, this Linux system is only used by a few users for storing small files; however, the department manager wants to upgrade this system and use it to run a database application that will be used by 100 users. The database application and the associated data will take up over 200GB of hard disk space. In addition, these 100 users will store their personal files on the hard disk of the system. Each user must have a maximum of 5GB of storage space. The department manager has made it very clear that this system must not exhibit any downtime as a result of hard disk errors. How much hard disk space will you require, and what partitions would you need to ensure that the system will perform as needed? Where would these partitions be mounted? What quotas would you implement? What commands would you need to run and what entries to /etc/fstab would you need to create? Justify your answers.
Answers
Given the requirements and constraints, you will need to ensure that the system has sufficient hard disk space to accommodate the database application and the user data, while also ensuring that the system remains stable and free of hard disk errors. To do this, you will need to take the following steps:
Add Hard Disk Space: You will need to add enough hard disk space to accommodate the database application and user data. Given that the database application requires over 200GB of disk space, and each user requires 5GB of disk space, you will need a minimum of 200 + (100 x 5) = 700GB of hard disk space. If you have a spare 1000GB SSD available, you can use that.Create Partitions: You will need to create two partitions on the hard disk: one for the database application and another for the user data. Given that the database application requires over 200GB of disk space, you should create a partition with at least 200GB of disk space for the database application. Given that each user requires 5GB of disk space, you should create a partition with at least 100 x 5 = 500GB of disk space for the user data.Mount Partitions: You should mount the partition containing the database application to the /var/lib/mysql directory, and the partition containing the user data to the /home directory. This will ensure that the database application and user data are stored in separate partitions and do not interfere with each other.Implement Disk Quotas: To limit each user's disk usage to 5GB, you will need to implement disk quotas for the /home partition. You can do this by using the quota command, which allows you to set disk usage limits for individual users or groups of users.Update /etc/fstab: You will need to update the /etc/fstab file to specify the partitions that you have created and the mount points for those partitions. This will ensure that the partitions are mounted automatically when the system is started.Here is an example of what the entries in /etc/fstab might look like:
/dev/sda1 /var/lib/mysql ext4 defaults 0 0
/dev/sda2 /home ext4 defaults,usrquota 0 0
To implement the disk quotas, you will need to run the following commands:
# touch /aquota.user
# chmod 600 /aquota.user
# mount -o remount /home
# quotacheck -avugm /home
# quotaon -avug
These steps should ensure that your Linux system meets the requirements and constraints set by the department manager, while also providing a stable and efficient system for the 100 users who will be using the database application.
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A housing area needs a channel to flow a 9.8 m³/s of rainfall. A trapezoidal channel is proposed with 3 m wide and located on the side slope of 3 (horizontal):4 (vertical). If the channel is concrete lined (n = 0.013) and bottom slope, So is 1: 2000, determine the normal depth by trial and error and graph method. [CH2-ND]
Answers
Using a trial-and-error or diagram pattern, solve the Manning's equating for the normal wisdom (y) by:
Calculating A, P, and R for various y principles.Computing Q for each y advantage.
How to solveTo decide the normal insight of a trapezoidal channel, apply Manning's equating: Q = (1/n) * A * R^(2/3) * S^(1/2)
For a trapezoidal channel: A = (b + zy) * yP = b + 2 * y * sqrt(1 + z^2)R = A / P
Using a trial-and-error or diagram pattern, solve the Manning's equating for the normal wisdom (y) by:
Calculating A, P, and R for various y principles.Computing Q for each y advantage.
Plotting the relationship 'tween y and Q.Finding the y advantage corresponding to the likely flow rate of 9.8 m³/s.
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a toddler who can recognize herself in a mirror is more likely to be ________in her daycare class.
Answers
A toddler who can recognize herself in a mirror is more likely to be confident in her daycare class. Explanation: A toddler who can recognize herself in a mirror is more likely to be confident in her daycare class.
It shows that she is developing a sense of self-awareness and is more aware of her place in the world. This can lead to increased confidence and self-esteem, which can translate to better social skills and interactions with others in her daycare class.
In addition, the ability to recognize oneself in a mirror is an important developmental milestone that typically occurs around 18-24 months of age. This is an important sign of healthy cognitive and social-emotional development, and can have a positive impact on the child's overall well-being.
Overall, the ability to recognize oneself in a mirror is an important aspect of a toddler's development, and can have positive implications for their social, emotional, and cognitive growth.
It is a sign of increasing self-awareness and confidence, and can help children develop healthy relationships with others in their daycare class.
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A soil had a liquid limit of 44, a plastic limit of 21, and a shrinkage limit of 14. In the summer, the in situ water content was 18%. (a) Compute the plasticity index of the soil. (b) Calculate the liquidity index of the in situ soil. (c) In which consistency state was the in situ soil
Answers
Answer:
(a) 23
(b)-0.13
(c) In which consistency state was the in situ soil? Plastic limit = 1.1
Explanation:
(a) Compute the plasticity index of the soil.
The formula for plasticity index is given as
Plasticity Index = Liquid limit - Plastic limit
Liquid limit = 44
Plastic limit = 21
Plastics Index = 44 - 21
= 23
(b) Calculate the liquidity index of the in situ soil.
Liquidity Index = Water content - Plastic limit/Liquid limit - Plastic Limit
Water content = 18%
Plastic limit = 21
Liquid limit = 44
Liquidity Index =18 -21/44 - 21
- 3/23
= -0.1304347826
≈ -0.13
(c) In which consistency state was the in situ soil
The consistency state of a soil tells us how firm the soil is.
Consistency state/index = Liquid limit - Water content/ Plastic Index
= Liquid limit - Water content /Liquid limit - Plastic Limit
Water content of the in situ soil = 18%
=44 - 18/44 - 23
= 26/23
= 1.1304347826
= 1.1
Since the consistency index of this situ soil is above 1, it means the soil is at plastic limit.
what is the expected value of the difference between the strength of a cable and the weight of a light fixture
Answers
The expected value of the difference between the strength of a cable and the weight of a light fixture cannot be determined without specific information about their probability distributions.
The expected value is a measure of central tendency that represents the average value we would expect to obtain from a random variable. To calculate the expected value of the difference between the strength of a cable and the weight of a light fixture, we would need to consider the probability distribution associated with each variable.
If we have the probability distributions for the strength of the cable and the weight of the light fixture, we can calculate the expected value by taking the difference between the two variables and multiplying it by the corresponding probabilities. We would sum up these products for all possible values of the variables.
However, without specific information about the probability distributions or any assumptions made, we cannot calculate the expected value. The expected value would vary depending on factors such as the variability and correlation between the strength of the cable and the weight of the light fixture.
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The difference between a thermocouple and a thermistor is the A. technology inside. B. thermocouple measures temperatures at the tip and the thermistor at the dimple. C. thermistor is designed specifically for thinner foods. D. thermocouple is the only one able to use different probes.
Answers
Answer: B. thermocouple measures temperatures at the tip and the thermistor at the dimple.
Explanation:
A thermistor is a temperature-sensitive resistor, whilst a thermocouple generates a voltage proportional to the temperature. Thermocouples can work at much higher temperatures than thermistors. They are commonly used for temperature control in heating systems.