In Natural selection, individuals whose unique characteristics are well-suited for an environment tend to survive and produce more offspring. true or false? i need this help!right now!

Answer:

For completely converting 6.34 moles of hydrogen to ammonia, 2.11 moles of Nitrogen is required.

The chemical reaction for the formation of ammonia by nitrogen and hydrogen reaction has been as follows:

For the formation of 2 moles of ammonia, 3 moles of hydrogen, and 1 mole of nitrogen s required.

The utilization of 3 moles of hydrogen requires 1 mole of Nitrogen.

So, the utilization of 6.34 moles of hydrogen requires:

3 moles Hydrogen = 1 -mole Nitrogen

6.34 moles hydrogen =  moles of Nitrogen

6.34 moles of hydrogen requires = 2.11 moles of Nitrogen.

For completely converting 6.34 moles of hydrogen to ammonia, 2.11 moles of Nitrogen is required.

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Answer rating5.0

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Answer:

39.99g/mol

Explanation:

Na = 22

O= 16

H = 1

= 40g or 39.99g/mol

Answer: 39.99g/mol

Explanation:

right

Answer:

Option d. 6.95 g

Explanation:

First of all, we state the reaction:

2NaCl + Pb(NO₃)₂ → PbCl₂ +  2NaNO₃

We determine the moles of each reactant, to state the limiting

Firstly we convert volume frm mL to L

0.200 L . 0.250M = 0.05 moles of NaCl

0.200L . 0.250M = 0.05 moles of Pb(NO₃)₂

Acording to stoichiometry we know that relation is 1:2, so the limiting reagent is the NaCl.

For 1 mol of Pb(NO₃)₂ I need 2 moles of NaCl

For 0.05 moles of Pb(NO₃)₂ I would need, the double → 0.1 moles

(We only have, 0.05 moles of NaCl)

Stoichiometry to the formed product is 2:1

From 2 moles of NaCl I produce 1 mol of PbCl₂

From 0.05 moles I would produce, the half → 0.025 moles

Let's convert the moles to mass → 0.025 mol . 278.1 g / 1mol = 6.95 g

6.95 g mass of lead (II) chloride would be produced.

Considering the balanced equation of the reaction:

2 NaCl + Pb(NO3)2 → PbCl2 + 2 NaNO3

Mole of 200 mL, 0.250 M NaCl = 0.200 x 0.25

                                                      = 0.05 mole

Mole of 200 mL, 0.25 M Pb(NO3)2 = 0.2 x 0.25

                                                          = 0.05 mole

Stoichiometric mole ratio of NaCl and Pb(NO3)2 = 2:1

Thus, NaCl is the limiting reactant.

Mole ratio of NaCl to PbCl2 = 2:1

Equivalent mole of PbCl2 = 0.05/2

                                           = 0.025 mole

Mass of 0.025 mole PbCl2 = 0.025 x 278.1

                                             = 6.95 g

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The volume of the water is obtained as 72 mL.

We know that the heat of vaporization is the heat that is required to raise convert the substance from the liquid state to the gaseous state. Now, we know that we can be able to find the energy from the use of the formula;

H = mL

H = heat that is required

m = Number of moles of the object

L = Heat of vaporization

We know from the problem that we have that;

H = 163 kJ

L = 40.66 kJ/mol

Then we would have;

Number of moles = H/L

= 163kJ/40.66 kJ/mol

=  4 moles

Mass of water = 4 moles * 18 g/mol = 72 g

Since the density of water = 1 g/mL

Volume = Density * mass

= 1 g/mL * 72 g

= 72 mL

Thus, the volume of the water that would be vaporized in the process that we have described is about a volume of 72 mL.

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How many mL of a 0.10 M NaOH solution are needed to neutralize 15 mL of 0.20 M H3PO4?

  5.0 (328)

Ph. D. in organic chemistry with 6+ years of teaching experi..

Write down the balanced reaction first

3NaOH + H3PO4   makes    Na3PO4 + 3H2O

Given 0.10M NaOH (0.10mol/lit NaOH)

0.2M H3PO4 ( 0.2 mol/lit H3PO4)

15 ml of H3PO4 or 0.015 lit of H3PO4

Find volume of NaOH needed to neutralize the solution

Relate moles of H3PO4 with the moles of NaOH with the helps of coefficients in front of NaOH and H3PO4 seen in balanced equations.

               moles ↔ Litre use definition of molarity (moles/litrs)

Start with what is given for H3PO4

0.015 lit of H3PO4 x 0.2 moles of H3PO4 / lit of H3PO4 x 3 moles of NaOH/1 mole of H3PO4 x lit of NaOH/0.1 mol of NaOH = 0.09 lit or 90 ml.

The same colors in above equations cancel our leaving lit of NaOH as final answer.

Answer:Ion-dipole

Explanation:

Explanation:

Answer:

C3H7O + O2 → CO2 + H2O

Explanation:

a) The full symbol equation for the oxidation reaction of an isomer of C3H7O can be represented as:

C3H7O + O2 → CO2 + H2O

b) The proper reagent for this oxidation reaction is O2 (oxygen gas). The catalyst required for this reaction depends on the specific conditions. Common catalysts used for oxidation reactions include transition metals such as platinum (Pt), palladium (Pd), or copper (Cu).

c) There is no need to remove the product (CO2 and H2O) from the reaction vessel because they are typically in the gas or liquid phase and do not significantly interfere with the reaction. The product gases can be easily vented out of the vessel, while the liquid water can be left in the reaction mixture. Additionally, the product CO2 is a stable and inert gas, which does not pose any hazards in most cases. Therefore, it is often not necessary to remove the products after the reaction is complete.

The balanced chemical equation for the reaction between strontium and oxygen can be written as follows: 2 Sr (s) + \(O_2\)(g) → 2 SrO (s).

In this equation, solid strontium (Sr) reacts with gaseous oxygen (\(O_2\)) to produce solid strontium oxide (SrO).

To determine the mass of product expected to form in this reaction, we need to consider the molar ratio between strontium and strontium oxide. From the balanced equation, we can see that 2 moles of strontium react to produce 2 moles of strontium oxide.

The molar mass of strontium (Sr) is 87.62 g/mol, and the molar mass of strontium oxide (SrO) is 119.62 g/mol. Since the molar ratio is 1:1 between strontium and strontium oxide, the mass of strontium oxide formed will be equal to the mass of strontium used.

In this case, the student added 4.93 g of strontium to the crucible. Therefore, the expected mass of strontium oxide formed will also be 4.93 g.

It's important to note that this calculation assumes that the reaction proceeds to completion, meaning that all of the strontium reacts with oxygen. In actual laboratory conditions, the yield of the reaction may be less than 100% due to factors such as incomplete reaction, side reactions, or product loss.

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Explanation:

The main function of the mitochondria in a plant cell is to generate energy for the cell through the process of cellular respiration. The mitochondria convert the energy stored in food into a form that the cell can use through the oxidation of glucose and other organic molecules, which produces ATP (adenosine triphosphate) - the energy currency of the cell. Additionally, the mitochondria play a role in regulating the cell's metabolic processes and also in controlling cell death (apoptosis).

Answer:

29/43

Explanation:because of the numbers

They appear as the trait over a recessive allele. Statement C) is true about the dominant alleles.

Dominant alleles are genetic variants that, when present in an individual's genotype, are expressed phenotypically, meaning they determine the visible or observable traits. Dominant alleles are represented by capital letters, while recessive alleles are represented by lowercase letters in genetics.

In terms of inheritance, if an individual has at least one copy of the dominant allele, it will be expressed in the phenotype, regardless of the presence of a recessive allele. This is because dominant alleles exert their influence over recessive alleles, thus "dominating" their expression.

To illustrate this, let's consider a specific example using a trait controlled by a single gene with two possible alleles: dominant (A) and recessive (a). If an individual is homozygous dominant (AA), meaning they possess two copies of the dominant allele, the dominant trait will be expressed.

However, if an individual is homozygous recessive (aa), with two copies of the recessive allele, the recessive trait will be expressed since there are no dominant alleles to override it.

Therefore, dominant alleles appear as the trait over recessive alleles, regardless of the presence or absence of a recessive allele. The presence of even a single copy of the dominant allele is sufficient for its expression in the phenotype. Option C

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Answer:

cannot be measure

Hope this helps :) !!!

Explanation:

Copper is more reactive than silver.

When copper reacts with AgNO3, Cu displaces Ag from AgNO3, forming Cu(NO3)2.

Chemical reaction -

\(Cu + 2AgNO_3 = 2Ag + Cu(NO3)_2\)

It's a displacement reaction as well as redox reaction.

Reasons are :

The Oxidation number of Cu changes from 0 to 2 so it's oxidized.

Oxidation number of Ag changes from 1 to 0 so it's reduced.

So, it's also a redox reaction.

The given chemical equation represents both single replacement as well as oxidation-reduction reaction as copper is getting oxidized and silver is getting reduced.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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The description of an ideal gas is as follows:

An ideal gas is a theoretical gas composed of many randomly moving particles that do not engage in any inter-particle interactions.

An ideal gas obeys all the gas laws and possess the following characteristics:

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Answer:

-They have no mass.

-They have no volume.

-They have no intermolecular forces.

Explanation:

The names of the given compounds are as follows:

a. NaBr = Sodium bromide

b. Rb\(_2\)O = Rubidium oxide

c. CaS = Calcium sulfide

d. AlI\(_3\) = Aluminium iodide

The formulas for the given compounds are as follows:

e. Strontium fluoride = SrF\(_2\)

f. Aluminum selenide = Al\(_2\)Se\(_3\)

g. Potassium nitride = K\(_3\)N

h. Magnesium phosphide = Mg\(_3\)P\(_2\)

This is the binary nomenclature of ionic compounds which involves both metals as well as non-metals. Metal is always named at the start without any prefix or suffix, while the name of the non-metals is placed after the metal in abbreviated form with the suffix "-ide".

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4 significant figures.

As the number is expressed in standard form, you only need to look at the coefficient.

This is because \(1.006 * 10^7 = 10060000\), so multiplying by 10 to the power of anything just results in zeros at the end of the number. A zero at the end is not a significant figure, so is ignored.

This means that you look at 1.006 for the significant figures.

The first non-zero digit is 1, so this is the first significant figure. There is then a zero, another zero, and finally a six. This is a total of 4 significant figures.

The number 1.006 x 10^7 has 4 significant figures. These include the '1', and the three digits following the decimal point - '0', '0', '6', which all contribute to its precision.

The number 1.006 x 10^7 includes significant figures which are digits carrying meaningful contributions to its measurement precision. This number has 4 significant figures: the '1', and the three numbers after the decimal point, '0', '0', and '6'. Every non-zero number is always significant; zeroes between two significant digits are significant. Here, the zeroes aren't placeholders but significant digits, thus contributing to the precision of the measurement.

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3.59 mol

1.836 x 10 ²⁵ molecules

Given

230 g SO2

30.5 moles LiNO3

Required

moles and molecules

Solution

mol = mass : molar mass

1 mol = 6.02 x 10²³ particles(molecules, atoms, ions)

1. 230 g x 1 mol/64,066 g  =3.59 mol

2. 30.5 moles x 6.02 x 10 ²³ molecules / 1 mol = 1.836 x 10 ²⁵ molecules

Answer:

Explanation:

Water molecules did not have a slight negative charge on one end and a slight positive charge on another, the loss of polarity would have profound effects on various biological, chemical, and physical processes. The unique properties of water that are vital for life as we know it would be significantly altered, potentially rendering many biological systems nonfunctional and disrupting the stability of ecosystems.

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Answer:

red it has to be red cuz it is the largest one out of it

Answer:

Apparently its Green

Explanation:

just took the test on A P E X

The partial pressure of H₂, given that the vapor pressure of water is 17.5 torr and total pressure of the gases is 750 torr, is 732.5 torr

The partial pressure of dry gas is given by the following formula:

Total pressure = Partial pressure of dry gas + pressure of wet gas

From the question given above, the following data were obtained as follow:

The partial pressure of H₂ gas can be obtained as follow:

Total pressure = Partial pressure of dry gas + pressure of wet gas

750 = Partial pressure of H₂ + 17.5

Collect like terms

Partial pressure of H₂ = 750 - 17.5

Partial pressure of H₂ = 732.5 torr

Thus, we can conclude that the partial pressure of H₂ is 732.5 torr

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Answer:

The correct solution is "\(0.480 \ J/g^{\circ}C\)".

Explanation:

Given:

q = 103 J

Mass,

m = 12.6 grams

Temperature,

\(T_1=22.4\)

\(T_2=39.4\)

\(\Delta T=T_2-T_1\)

      \(=39.4-22.4\)

      \(=17^{\circ}C\)

Now,

⇒  \(C=\frac{q}{m\times \Delta T}\)

⇒      \(=\frac{103}{12.6\times 17}\)

⇒      \(=\frac{103}{214.2}\)

⇒      \(=0.480 \ J/g^{\circ}C\)

The type of reaction for each chemical equation is as follows:

1. Displacement reaction

2. Combustion reaction

3. Double displacement reaction

4. Decomposition reaction

5. Synthesis reaction.

The different types of chemical reactions include:

Thus, the chemical equations and their respective reactions are as follows:

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Answer:

see below

Explanation:

A. The given reaction releases energy, indicating that it is an exothermic reaction.

B. The △H value for the reaction can be written as △H = -571.7 kJ, with a negative sign indicating the energy is released.

C. The balanced equation for the reaction between hydrogen and oxygen to form water is:

2H2(g) + O2(g) → 2H2O(l)

D. To calculate the amount of energy released when 10.0g of hydrogen is reacted with an excess of oxygen, we need to first determine the amount of hydrogen involved in the reaction.

The molar mass of hydrogen is 1.008 g/mol, so 10.0 g of hydrogen is equivalent to 10.0 g / 1.008 g/mol = 9.92 mol of hydrogen.

From the balanced equation, we can see that 2 mol of hydrogen is required for every 1 mol of oxygen, so the amount of oxygen involved in the reaction is twice the amount of hydrogen.

Therefore, the amount of oxygen needed for 9.92 mol of hydrogen is 2 × 9.92 mol = 19.84 mol.

Assuming that there is an excess of oxygen, all of the hydrogen will react, so the limiting reactant is oxygen.

Using the △H value of -571.7 kJ, we can calculate the amount of energy released as follows:

-571.7 kJ / 2 mol H2 = -285.9 kJ/mol H2

So the energy released when 10.0 g of hydrogen reacts with an excess of oxygen is:

-285.9 kJ/mol H2 × 9.92 mol H2 = -2836.53 kJ

Therefore, the reaction releases 2836.53 kJ of energy when 10.0 g of hydrogen reacts with an excess of oxygen.

The boiling point of water is 100.0 °C, the boiling point of the solution will be : 101.49 °C.The correct answer is option (a) 100.00049 °C.

Ideal Solution : An ideal solution is a homogeneous mixture of two or more components that obeys Raoult's law, which states that each component's vapor pressure is proportional to its mole fraction.The boiling point of a solution depends on the solvent's properties and the solute's concentration. It's dependent on the mole fraction of the solvent and solute, as well as the total concentration of the solution. The change in boiling point of a solution is given byΔTb = Kb × m × i, whereKb = ebullioscopic constant, m molarity of the solution, and i = van't Hoff factor.Assuming that the solution's behavior is ideal, we may use the molality of the solution to compute the boiling point elevation of the solution.The molality of the solution is given by the following formula:m = (n₂ / m₂) ÷ (n₁ / m₁), where n is the number of moles, m is the mass, and the subscripts 1 and 2 refer to water and non-volatile solute sucrose, respectively.The molar mass of sucrose (C₁₂H₂₂O₁₁) is342.3 g/mol; therefore, the number of moles of sucrose is115.0 g ÷ 342.3 g/mol = 0.335 mol.m₁ = mass of water = 350.0 g, and m₂ = mass of sucrose = 115.0 g, as given in the problem.Therefore, the molality of the solution is given by:m = (0.335 mol / 0.115 kg) ÷ (1 mol / 1 kg) = 2.91 mol/kg.Substituting these values in the formula for ΔTb, we get:ΔTb = Kb × m = 0.512 °C m⁻¹ × 2.91 mol/kg = 1.49 °C.100.0 °C + 1.49 °C = 101.49 °C.

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Answer: Oxygen

Explanation: Its found on the periodic table as an element.

4.41 × 10⁻⁴⁵m is the wavelength of the photon and the energy correspond to red color.

The term wavelength is defined as the distance between two identical points that are adjacent crests and troughs.

The SI unit of wavelength is metre mostly represented as m.

The wavelength is mostly represented by λ is the Greek letter lambda.

Given:

E =  4.50x10⁻¹⁹ J/photon

h = Planck constant = 6.626 × 10⁻³⁴

ν = ?

E = hν

ν = E/h

By substituting the values in above question and we get,

= 4.50x10^-19 /  6.626 × 10⁻³⁴

=  0.679 × 10⁻¹⁵

c = 3 × 10⁸

E = hc/λ

λ = hc/E

By substituting the values in above question and we get,

λ = 6.626 × 10⁻³⁴ ×  3 × 10⁸ / 4.50x10⁻¹⁹

λ = 4.41 × 10⁻⁴⁵m

Thus, the wavelength of the photon is 4.41 × 10⁻⁴⁵m and color does this energy correspond to red.

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