In each pair, select the body with more internal energy.

Answer:

Yeast can use oxygen to release the energy from sugar (like you can) in the process called "respiration". ... So, the more sugar there is, the more active the yeast will be and the faster its growth (up to a certain point - even yeast cannot grow in very strong sugar - such as honey).

Answer:

Wnet = 0

Explanation:

        \(W_{net} = \frac{1}{2} k* \Delta x^{2} - m*g*h_{max} (1)\)

        \(\frac{1}{2} k* \Delta x^{2} = m*g*h_{max} (2)\)

The position of the center of mass of the system is 13.0 cm from the left edge of square A.

The center of mass can be calculated by multiplying the masses you're trying to find the center of mass between by their positions. Then you add them all up and divide the total by the sum of the individual masses.

We use the formula for the center of mass of a system of particles,

\(x_c_m = (m_Ax_A + m_Bx_B + m_C*x_C) / (m_A + m_B + m_C)\)

\(m_A\) = mass of square A

\(m_B\) = mass of square B

\(m_C\) = mass of square C

\(x_A\) = distance of the center of mass of square A

\(x_B\) = distance of the center of mass of square B

\(x_C\) = distance of the center of mass of square C

Substitute values,

\(x_c_m = (100.0 cm^2 * 5.0 cm + 400.0 cm^2 * 10.0 cm + 900.0 cm^2 * 15.0 cm) / (100.0 cm^2 + 400.0 cm^2 + 900.0 cm^2)\)

\(x_c_m = 13.0 cm\)

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If the potential difference across a capacitor is doubled, the energy stored in it is quadrupled.

The ability difference between any points inside the electric-powered field is defined as the quantity of labor done in transferring a unit of fantastic charge without acceleration from one point to another alongside any route among the 2 factors. The distinction in price between higher capability and lower capacity is known as a voltage or capacity distinction.

The voltage between points can be a result of the build-up of electric rate (e.g., a capacitor), and from an electromotive pressure (e.g., electromagnetic induction in generators, inductors, and transformers).On a macroscopic scale, a potential distinction can be due to electrochemical methods (e.g., cells and batteries), the stress-induced piezoelectric effect, and the thermoelectric effect.

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Explanation:

Given:

Diameter = 200 m

Radius, r = 200/2 = 100 m

Time taken, t = 30 seconds

Formula to be used:

Distance traveled, = circumference of circle = 2πr

Answer:

Putting all the values, we get

Distance traveled = 2πr

So, the distance traveled by Raju is 628.57 m.

Now, magnitude of the displacement,

At the end of 30 seconds, Raju will come to starting position or initial position, so displacement is zero.

-- If A and B are pointing in exactly opposite directions, then their sum A+B is the minimum possible value.  A+B = 2 N in the same direction as B.

-- If A and B are pointing in exactly the same direction, then their sum A+B is the maximum possible value.  A+B = 6 N in that same direction.  

Answer:

Explanation:

According to Newton's Law of Gravitation, the gravitational force between two objects is always mutual, meaning that the force that one object exerts on the other is equal in magnitude but opposite in direction.

This means that if planet A exerts a gravitational force on planet B, then planet B will also exert a gravitational force on planet A. The magnitude of this force will be equal to the magnitude of the force that planet A exerts on planet B, but the direction will be opposite.

For example, if planet A exerts a gravitational force on planet B that is pulling planet B towards planet A, then planet B will also exert a gravitational force on planet A that is pulling planet A towards planet B. The magnitude of these two forces will be equal, but the directions will be opposite.

hat he sais

Answer:w

Explanation:

Answer:

Choice 2: 6/17

Explanation:

4+7=11. 6+11= 17. so it's 6/17

The value of  the missing resistance, R₃ = 10.35 ohms.

The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.

The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.

The values of the missing component of the circuit is calculated by applying the following formula.

The total resistance of the circuit;

For R₂, R₃, 1/R = 1/R₂ + 1/R₃

1/R = 1/12 +  1/R₃

1/R = (R₃ + 1)/(12R₃)

R = 12R₃ / (R₃ + 1)

For, R₁, R₂ and R₃, total resistance;

R = 12R₃ / (R₃ + 1) + R₁

R = [12R₃ / (R₃ + 1)] + 2

R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)

R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)

R = (14R₃ + 2 ) / (R₃ + 1)

The total current in circuit is calculated as;

I = V/R

I = 30 / R

I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)

I = (30R₃ + 30) / (14R₃ + 2) ------- (1)

The voltage in parallel circuit is the same

V₂ = V₃ = 24 V

V₃ = IR₃

24 = IR₃

I = 24/R₃  --------- (2)

Solve (1) and (2) together as follows;

24/R₃ = (30R₃ + 30) / (14R₃ + 2)

30R₃² - 306R - 48 = 0

Solve the quadratic equation, using formula method.

R₃ = 10.35 ohms

I₃ = V₃/R₃

I₃ = 24 V / 10.35

I₃ = 2.32 A

If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V

The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A

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Answer:

To Avoid accidents and injuries

Explanation:

Safety measures are vital dancing as this may prevent bad things like accidents and injuries from happening.

When dancing,the safety of dancers is a must to be observed and considered.

Dancers are also most likely to exert their full potential if they know that they are safe no matter what happen....

HAVE A GOOD DAY....

5.66 seconds after it is thrown, the position of the rock is approximately 157.266 meters below the initial position at the edge of the cliff.

To calculate the position of the rock 5.66 seconds after it is thrown, we can use the equations of motion.

First, let's break down the problem into two parts: the upward motion and the downward motion of the rock.

1. Upward motion:

During the upward motion, the acceleration due to gravity acts in the opposite direction of the initial velocity. We can use the equation of motion for displacement:

s₁ = u₁t + (1/2)at²

where s₁ is the displacement, u₁ is the initial velocity, t is the time, and a is the acceleration.

Since the rock is thrown straight up, the initial velocity u₁ is 24.8 m/s, the acceleration a is -9.8 m/s² (taking it as negative due to the opposite direction), and the time t is 5.66 seconds.

Plugging in the values:

s₁ = (24.8 m/s)(5.66 s) + (1/2)(-9.8 m/s²)(5.66 s)²

s₁ = 140.448 m + (-78.633 m)

s₁ = 61.815 m

2. Downward motion:

During the downward motion, the rock is in free fall, so we can use the equation for displacement again:

s₂ = u₂t + (1/2)at²

where s₂ is the displacement, u₂ is the final velocity (which is the negative of the initial velocity due to the change in direction), a is the acceleration due to gravity (taking it as -9.8 m/s²), and t is the time.

Since the rock starts from rest at its highest point during the upward motion, the final velocity u₂ is -24.8 m/s.

Plugging in the values:

s₂ = (-24.8 m/s)(5.66 s) + (1/2)(-9.8 m/s²)(5.66 s)²

s₂ = -140.448 m + (-78.633 m)

s₂ = -219.081 m

To find the total displacement, we sum the upward and downward displacements:

s_total = s₁ + s₂

s_total = 61.815 m + (-219.081 m)

s_total = -157.266 m

Therefore, 5.66 seconds after it is thrown, the position of the rock is approximately 157.266 meters below the initial position at the edge of the cliff.

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The distance between the two objects is reduced in half, that will be the changed force of attraction between them is option (E) 2.5 newtons.

According to Newton's law of universal gravitation, the force of attraction between two objects is inversely proportional to the square of the distance between them.

If the distance between Object A and Object B is reduced to half, the force of attraction will increase by a factor of 2² = 4. This means that the new force of attraction will be one-fourth of the original force.

Given that the original force of attraction is 5 newtons, the changed force of attraction between Object A and Object B, when the distance is reduced in half, will be 5 newtons / 4 = 1.25 newtons, which can be rounded to 2.5 newtons.The correct answer is option e.

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The time that have been taken by the liquid is  4.4 * 10^5 min.

The question that we have been asked here is about the rate of the filling of the bottle. We can see that we have been given the volume of the bottle clearly.

We know that the volume of the solution that we have is   195 U. S. fluid gallons or 0.74 m^3. Then we have that;

Density = mass/volume

mass = Density * volume

= 0.74 m^3 * 1000 Kg/m^3

= 740 Kg or 740000 g

Rate = mass/time

Time = mass/rate

Time = 740000 g/1.7 g/min.

= 4.4 * 10^5 min

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Answer:

η = 0.2 = 20%

Explanation:

The relationship between the thermal efficiency of a heat engine and the Coefficient of Performance (COP) of the corresponding Heat Pump is given as follows:

\(\eta = \frac{1}{COP_{HP}}\)

where,

η = thermal efficiency = ?

\(COP_{HP}\) = Coefficient of Performance of Heat Pump = 5

Therefore,

\(\eta = \frac{1}{5} \\\\\)

η = 0.2 = 20%

Given:

A ray diagram

To find:

Identify the incident ray.

Explanation:

An incident ray is a ray that falls on the surface that separates two media.

In the given ray diagram, it can be seen that light ray 1 is falling on the surface which separates the two media. Thus, a light ray 1 is an incident ray.

Ray 3 is called a refracted ray and a line represented by number 2 is called a normal which is perpendicular to the surface.

Conclusion:

Ray represented by number 1 is the incident light ray. Thus, the correct option is option a.

Answer:

\(\Rightarrow L=70 .03472 cm\)

Explanation:

For convenience, let's represent the thermal expansion coefficient by \(\alpha\), i.e. \(????=\alpha\).

Given that, for steel \(\alpha =1.24\times 10^{-5}\) °\(C^{-1}\),

initial length, \(L_0=70 cm\), initial temperature, \(T_0=70\) °\(C\), and the final temperature, \(T=110\) °\(C\).

Let the length of the rod at \(T=110\) °\(C\) be \(L\).

Now, change in length, \(\Delta L=\alpha L_0 \Delta T\)

\(\Rightarrow \Delta L=\alpha L_0 (T-T_0)\)

\(\Rightarrow L-L_0=1.24\times 10^{-5}\times 70 (110-70)\)

\(\Rightarrow L-70=1.24\times 10^{-5}\times 70 \times 40\)

\(\Rightarrow L=70 + 0.03472 cm\)

\(\Rightarrow L=70 .03472 cm\)

Hence, the length of the rod at \(T=110\) °\(C\) be \(70.03472 cm\).

Answer:

I believe the answer is A volleyball player sliding across the court while diving for the ball.

Explanation:

Kinetic friction is a body moving on the surface experiences a force in the opposite direction of its movement.

Hope this helps! （づ￣3￣）づ╭❤～

Answer:

The thermal conductivity of the insulated metal rod is \(202.92\,\frac{W}{m\cdot K}\).

Explanation:

This is a situation of one-dimensional thermal conduction of a metal rod in a temperature gradient. The heat transfer rate through the metal rod is calculated by this expression:

\(\dot Q = \frac{k_{rod}\cdot A_{c, rod}}{L_{rod}}\cdot \Delta T\)

Where:

\(\dot Q\) - Heat transfer due to conduction, measured in watts.

\(L_{rod}\) - Length of the metal rod, measured in meters.

\(A_{c,rod}\) - Cross section area of the metal rod, measured in meters.

\(k_{rod}\) - Thermal conductivity, measured in \(\frac{W}{m\cdot K}\).

Let assume that heat conducted to melt some ice was transfered at constant rate, so that definition of power can be translated as:

\(\dot Q = \frac{Q}{\Delta t}\)

Where Q is the latent heat required to melt the ice, whose formula is:

\(Q = m_{ice}\cdot L_{f}\)

Where:

\(m_{ice}\) - Mass of ice, measured in kilograms.

\(L_{f}\) - Latent heat of fussion, measured in joules per gram.

The latent heat of fussion of water is equal to \(330000\,\frac{J}{g}\). Hence, the total heat received by the ice is:

\(Q = (6.15\,g)\cdot \left(330\,\frac{J}{g} \right)\)

\(Q = 2029.5\,J\)

Now, the heat transfer rate is:

\(\dot Q = \frac{2029.5\,J}{(10\,min)\cdot \left(60\,\frac{s}{min} \right)}\)

\(\dot Q = 3.382\,W\)

Turning to the thermal conduction equation, thermal conductivity is cleared and computed after replacing remaining variables: (\(L_{rod} = 0.75\,m\), \(A_{c,rod} = 1.25\times 10^{-4}\,m^{2}\), \(\Delta T = 100\,K\), \(\dot Q = 3.382\,W\))

\(\dot Q = \frac{k_{rod}\cdot A_{c, rod}}{L_{rod}}\cdot \Delta T\)

\(k_{rod} = \frac{\dot Q \cdot L_{rod}}{A_{c,rod}\cdot \Delta T}\)

\(k_{rod} = \frac{(3.382\,W)\cdot (0.75\,m)}{(1.25\times 10^{-4}\,m^{2})\cdot (100\,K)}\)

\(k_{rod} = 202.92\,\frac{W}{m\cdot K}\)

The thermal conductivity of the insulated metal rod is \(202.92\,\frac{W}{m\cdot K}\).

Any mass greater than 150g attached to 100g will make the block move towards point A. Thus, there can be any number of blocks attached to it, but the total mass of the attached blocks must add up to 150g.

The newton, abbreviated N, is the SI unit of force. These are base units that are pertinent to force.

The symbol for the length unit of a meter is m. the kilogram (kg), a unit of mass. s stands for the second, a unit of time.

Seesaws are regulated by a straightforward equation that states that for balance to occur, the force applied to one end of the seesaw multiplied by the distance from the pivot should equal the force applied to the other side of the seesaw multiplied by the distance from the pivot.

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Answer:

Below

Explanation:

s = Distance

v = Velocity ( speed)

t = time

\(s = vt\)

Divide both sides of the equation by t

\( \frac{s}{t} = \frac{vt}{t} \\ \frac{s}{t} = v\)

Answer:

it is double the temperature change of iron

Answer: no other source

Explanation:

The Earth gets energy from the sun which includes both heat and light and these are necessary for chemical reaction.

When the energy from the Sun gets to the Earth, they come as solar radiation and included in such solar radiation are infrared, invisible light, X-rays, ultraviolet light, radio waves, and gamma rays.

We should note that no other source is required for the Earth to get energy. The sun supplies it its energy.

Torque is a measure of the force that can cause an object to rotate about an axis. (answer taken from Khan Academy).

Answer:

2 amperes

Explanation:

V = IR

V/R = I

120 v / 60 ohms = 2 amps

Answer:

it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters

Explanation:

hope it helped

:)

We can use a vernier calliper

Answer:

The instrument is micrometer screw gauge .

Units : millimetres

Explanation:

\(.\)

Answer: 1.14 kg*m/s

Explanation:

The first person explained everything right, they just forgot to convert the angular acceleration to rads/sec^2 from revs/sec^2. Once that is converted, your answer should come out right.

Another small thing, the answer there has an extra unnecessary step. It tells you to find the square root of w^2 to find w but that is unnecessary since the final equation asked for w^2. Hope this helps! :)

The moment of inertia I of the flywheel about its rotation axis is

Given

Angular displacement,

\(\theta = 30rev \\\\\theta = (30) * 2\pi rad \\\\\theta = 188.495rad\)

Therefore, Final angular velocity (w) will be:

\(w^2 = 2\alpha\theta\\\\w^2 = 2 * (0.200 * 2\pi) * (188.49)\\\\w^2 = 473.73\\\\w = 21.76 rad/s\)

Therefore,

moment of inertia

\(I = 2 * K / w^2\)

\(I = 2 * 330 / 473.73\)

\(I = 1.39kgm^2\)

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The work-energy theorem says that the total work done on the block is equal to the difference of its kinetic energies at points B and A. Then the total work done on the block is

\(W_{\rm total} = K_B - K_A = 4.0\,\mathrm J - 5.0\,\mathrm J = -1.0\,\mathrm J\)

Friction acts on the block to oppose its motion, so it does negative work on the block, -4.5 J.

The only other force acting on the block as it moves is the force P. Let \(W_P\) be the work done by the force P. Then the total work done on the block is

\(W_{\rm total} = W_P + W_{\rm friction} \iff -1.0\,\mathrm J = W_P - 4.5 \,\mathrm J \implies W_P = \boxed{3.5\,\mathrm J}\)

Answer:

The formulas are down below

Explanation:

\(w = \frac{o}{t} \)

From V=rw

\(w = \frac{v}{r} \)