In​ basketball, some baskets are worth two points. Others are worth three points. In one​ game, the ratio of​ three-point baskets to​ three-point tries for one team was . If the team scored 27 points from​ three-point baskets, how many​ three-point tries did the team​ have?

The cosine of angle J is given as follows:

\(\cos{J} = \frac{14\sqrt{2}}{49}\)

The three trigonometric ratios are the sine, the cosine and the tangent of an angle, and they are obtained according to the rules presented as follows:

For the angle J in this problem, we have that:

Hence the cosine of angle J is given as follows:

\(\cos{J} = \frac{4}{\sqrt{98}} \times \frac{\sqrt{98}}{\sqrt{98}}\)

\(\cos{J} = \frac{4\sqrt{98}}{98}\)

\(\cos{J} = \frac{2\sqrt{98}}{49}\)

As 98 = 2 x 49, we have that \(\sqrt{98} = \sqrt{49 \times 2} = 7\sqrt{2}\), hence:

\(\cos{J} = \frac{14\sqrt{2}}{49}\)

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Answer:

2.58

Step-by-step explanation:

129/50 = 2.58

Number equivalent to 129 /50 is 2.58 .

Given,

129 divided 50

Using division property,

The rules for division are:

(1) positive × or ÷ positive = positive

(2) positive × or ÷ negative = negative

(3) negative × or ÷ negative = positive

Rule for long division method,

Divide the tens column dividend by the divisor.

Multiply the divisor by the quotient in the tens place column.

Subtract the product from the divisor.

Bring down the dividend in the ones column and repeat.

Therefore,

divide, multiply, subtract, bring down and repeat or find the remainder.

Here the required value is of :

129/50

= 2.58

Hence the answer is2.58

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Answer:

Step-by-step explanation:

It's B

7 + 3 = 10

The chance that a randomly selected individual found to have a positive result actually has the disease is called the Positive Predictive Value (PPV). What is the chance that a randomly selected individual found to have a positive result actually has the disease?

The probability that a randomly chosen individual with a positive test result really has the disease is referred to as the Positive Predictive Value (PPV). It reflects how well the test can detect disease in those who have it. In statistics, the PPV is calculated as follows:

PPV = True Positives / (True Positives + False Positives) x 100

In addition, the PPV is influenced by a variety of factors, including the disease's prevalence, the sensitivity and specificity of the test, and the prevalence of the disease in the population.

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The derivative of a function at a point can be shown as the slope of the tangent line to the graph of the function at that point [a,f(a)]. This slope is found by taking the limit of the difference quotient [f(a+h) - f(a)]/h as h approaches 0.

The derivative of a function f at a number a, denoted by f'(a), can be represented graphically as the slope of the tangent line to the graph of f at the point [a,f(a)].

To illustrate this, we can sketch the graph of f(x) and draw a secant line passing through the points [a,f(a)] and [a+h, f(a+h)], where h is a small positive number. As h approaches 0, the secant line becomes closer and closer to the tangent line at the point [a,f(a)].

The slope of the secant line is given by the difference quotient [f(a+h) - f(a)]/h, and the slope of the tangent line is given by the limit of this difference quotient as h approaches 0. This limit is f'(a), the derivative of f at a.

In summary, the definition of the derivative of a function at a point a can be represented graphically as the slope of the tangent line to the graph of the function at the point [a,f(a)]. This slope is found by taking the limit of the difference quotient  [f(a+h) - f(a)]/h as h approaches 0.

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Answer:

16

Step-by-step explanation:

i think

Answer:

7.348469228

Step-by-step explanation:

34+24+50=108

108/2=54

then you take 54 and minus each side like 54-34,54-24 and 54-50 then square root the final solution.

hope this help:)

0.50 sample proportion will require the largest number of work sampling observations for a given confidence level and allowable error as the variability is largest at 0.50.

A part, share, or quantity is a percentage when it is compared to the total. It can be any number between 0 and 1, 0, or 1. A number or percentage can be used to represent it. The percentage of Canadians who reside in a certain province is one illustration from official statistics. A special class of ratio called a proportion has the numerator and denominator combined. An illustration is the ratio of deaths to men, which is calculated by dividing deaths to men by deaths to men and women.

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Answer:

aunt clares cup of tea was darker because the extra milk in megs made it lighter than aunt clares

Step-by-step explanation:

The minimum value of the product xy is -2. The correct option is d.

To find the minimum value of the product xy, we need to find the minimum value of y and then multiply it by the corresponding x value. In this case, the given equation is y = 4x² - 3.

To determine the minimum value of y, we observe that the coefficient of the x² term is positive (4), indicating a U-shaped parabola that opens upward. Since the parabola opens upward, the vertex of the parabola represents the minimum point.

The x-coordinate of the vertex can be found using the formula: x = -b / (2a), where a and b are the coefficients of the x² and x terms, respectively. In this equation, a = 4 and b = 0. Plugging these values into the formula, we get x = -0 / (2 * 4) = 0.

To find the corresponding y-coordinate, we substitute the value of x = 0 into the equation: y = 4(0)² - 3 = -3.

Therefore, the minimum value of y is -3. Multiplying this minimum y value by the corresponding x value, we get xy = 0 * (-3) = 0.

Therefore the correct option is d.

However, none of the answer options provided includes 0 as a choice. Instead, the closest option is -2 (option d). Although -2 is not the minimum value, it is the closest available option in the given choices.

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Answer:

18

Step-by-step explanation:

9+(-15)+4+20

9-15+4+20

18 ans

Answer:

its d

Explanation:

bc it ask for the lowest Price for the yacht

The functions 1/x, 1-x², and 1-3x are linearly independent on any interval that does not contain x=0, but they are dependent at x=0.

To determine whether the functions 1/x, 1-x², and 1-3x are linearly independent, we can use the Wronskian method. The Wronskian of a set of functions f1(x), f2(x), ..., fn(x) is defined as:

W(f1, f2, ..., fn) = det | f1 f2 ... fn |

| f1' f2' ... fn' |

where f1', f2', ..., fn' are the derivatives of the functions with respect to x.

If the Wronskian is nonzero for all values of x in a given interval, then the functions are linearly independent on that interval. If the Wronskian is zero for at least one value of x in the interval, then the functions are linearly dependent on that interval.

For the functions 1/x, 1-x², and 1-3x, we have:

W(1/x, 1-x², 1-3x) = det | 1/x 1-x² 1-3x |

| -1/x² -2x -3 |

| 0 -2x 0 |

Expanding the determinant, we get:

W(1/x, 1-x², 1-3x) = -6/\(x^3\)

Since the Wronskian is nonzero for all values of x except x = 0, the functions 1/x, 1-x², and 1-3x are linearly independent on any interval that does not contain x = 0.

Therefore, the functions are linearly independent except at x = 0.

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Answer: The answer is B) y < 0

Answer: B

Step-by-step explanation:

The nearest whole number to which the new height of the image is enlarged is 9cm.

What is meant by height?

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12) The new height is 9cm it was originally 4cm wide and 3cm tall, scale factor is 3.

14) The new width is 12cm it was originally 2cm tall  and 4cm wide, scale factor is 3.

In mathematics, a scale factor is the proportion between corresponding measurements of an object and a representation of that object. The copy will be bigger if the scale factor is a whole number. A fraction scale factor means that the copy will be smaller.

To increase an object by a scale factor, measure each side of the object and multiply the result by the scale factor. A 2x2 cm square is presented to you.

Increase the square by a scale factor of 2.

To do this, multiply each side by 2.

The result is a 4x4cm square.

12) scale factor = 12/4

scale factor = 3

14) scale factor = 6/2

scale factor = 3

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Answer:

I think The answer is A

Step-by-step explanation:

Answer:

OPTION A is correct

39 ounces

Step-by-step explanation:

Given:

The amount of water in the pitcher= 32 ounces

The amount of lemon juice in the pitcher = 7.15 ounces

We were to calculate the most reasonable estimate for the amount of liquid in the pitcher

To do this we need to sum up the Amount of water and Amount of lemon juice in the pitcher because the water is a liquid as well as the lemon juice which is

32 ounces + 7.15 ounces

=39.15 ounces

Therefore, the Estimated amount of liquid in the pitcher is approximately 39 ounces

Pedro can sell enough by combining the sales of 40 plates of garlic shrimp and 80 dishes of spicy shrimp to reach his objective.

Near the shore, Pedro runs a shrimp delivery business.

He offers spicy shrimp for $6 a plate and garlic shrimp for $8 per plate.

Pedro wants to make at least $800 per day but only stocks enough shrimp to sell a maximum of 120 plates.

We need to ascertain,

Which dish combining hot shrimp and garlicky shrimp can Pedro sell to reach his objective?

In response to the query,

Let's sell the x dishes of garlic shrimp.

And plates of hot shrimp were sold.

Pedro has 120 dishes' worth of shrimp in stock each day.

Then,

Shrimp sold daily total is equal to the sum of plates of garlic shrimp and spicy shrimp.

                           X + Y = 120

Furthermore, He offers $6spicy and $8garlic shrimp, per plate.

To make at least $800 is what he wants to do.

Then,

the sum of the price of the spicy shrimp per plate and the price of the garlic shrimp per plate,

                             8X + 6Y = 800

When the two equations are solved,

                              X + Y = 120

                           8X + 6Y = 800

From equation 1,

                             Y = 120 - X

In equation 2, replace x with its value.

8X + 6Y = 800

8(120 - Y) + 6Y = 800

960 - 8Y + 6Y = 800

- 2Y = - 160

Y = 160/2

Y = 80

In equation 1, replace y with its value.

X + Y = 120

X + 80 = 120

X = 120 - 80

X = 40

In order to achieve his objective, Pedro sold a combination of 40 plates of garlic shrimp and 80 dishes of spicy shrimp.

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Answer:

Step-by-step explanation:

Make equations

8x+6y≥800

x+y≤120

Graph the system of equations and see which answer falls in the shaded area

Answer: 90 Garlic, 25 Spicy

Answer:

D. y= 2x2

Step-by-step explanation:

y = ax^2

If the absolute value of a is <1 the graph is wider than when a = 1

If the absolute value of a is >1 the graph is narrow than when a = 1

The only function that fits that description is  

y = 2x^2

B <<< answer.

Given: We are given equation of parabola ans to choose narrowest graph.

Parabola form narrowest and widest.

Larger value of a most narrowest graph.

Smaller value of a most widest graph.

Now, we will see the coefficient of x²

Now, we arrange the value of a in descending order.

2 is largest value of these.

Hence, The narrowest graph is  

there are 2 more pictures i have to upload but it won't let me

Answer:

A. Right a multiple of 2 and up a multiple of 1.

B. (2, 1)

C. the same

Step-by-step explanation:

A. The original point was (2, 1), so if Larissa moves right a multiple of 2 and up a multiple of 1, she'll stay within the ratio.

B. We already know this is proportional, since it goes through the origin; the line just has to pass through the right point: (2,1)

C. The line will be proportional, so as long x is twice as much as y, Larissa will have the same shade of green paint every time.

The dependent variable in a study, also known as the response variable, is affected by the independent variables.

What is a variable?
A variable is a sign and placeholder for any mathematical object (from the Latin variabilis, "changeable") in mathematics. A variable can, for example, represent a number, a vector, a matrix, a function, the argument of a function, a set, or a set's component.

Numerous issues are resolved in a single computation by using variables in algebraic calculations as if they were explicit integers. For instance, by exchanging the variables that represent them in the quadratic formula with the numerical values of the coefficients in any given quadratic equation, the quadratic formula may solve any quadratic equation. A variable in mathematical logic is either a symbol for an undefined term in the theory or an undefined phrase itself (a meta-variable).

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The solution to this problem is the p-value must be higher than 0.05.

A confidence interval in frequentist statistics is a range of estimates for an unobserved parameter. The most common confidence level for computing confidence intervals is 95%, however other levels, including 90% or 99%, are sporadically employed.

Here ,

In this given problem we can see confidence interval has 0 in it.

So,

Since the confidence interval comprises 0, the null hypothesis should be rejected.

When the p-value exceeds the level of significance, the null hypothesis is only rejected.

Since alpha=0.05 in this case, the p-value must be higher than 0.05.

Thus, the p-value must be higher than 0.05.

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Answer:

Step-by-step explanation:

ach correct answer scores 3 points.

Each incorrect answer loses 2 points.

A question not answered scores 0

It is possible to finish the quiz with a negative score.

1) If 75 is the maximum score you can get, what is the minimum score on the quiz?

2) A student answers 21 questions. 6 are correct. How many points does she score?

Answer:



Step-by-step explanation:

ach correct answer scores 3 points.

Each incorrect answer loses 2 points.

A question not answered scores 0

It is possible to finish the quiz with a negative score.

1) If 75 is the maximum score you can get, what is the minimum score on the quiz?

2) A student answers 21 questions. 6 are correct. How many points does she score?

Answer:



Step-by-step explanation:



vach correct answer scores 3 points.

Each incorrect answer loses 2 points.

A question not answered scores 0

It is possible to finish the quiz with a negative score.

1) If 75 is the maximum score you can get, what is the minimum score on the quiz?

2) A student answers 21 questions. 6 are correct. How many points does she score?

Answer:



Step-by-step explanation:



ach correct answer scores 3 points.

Each incorrect answer loses 2 points.

A question not answered scores 0

It is possible to finish the quiz with a negative score.

1) If 75 is the maximum score you can get, what is the minimum score on the quiz?

2) A student answers 21 questions. 6 are correct. How many points does she score?

Answer:



Step-by-step explanation:



ach correct answer scores 3 points.

Each incorrect answer loses 2 points.

A question not answered scores 0

It is possible to finish the quiz with a negative score.

1) If 75 is the maximum score you can get, what is the minimum score on the quiz?

2) A student answers 21 questions. 6 are correct. How many points does she score?

Answer:



Step-by-step explanation:



vach correct answer scores 3 points.

Each incorrect answer loses 2 points.

A question not answered scores 0

It is possible to finish the quiz with a negative score.

1) If 75 is the maximum score you can get, what is the minimum score on the quiz?

2) A student answers 21 questions. 6 are correct. How many points does she score?

Answer:



Step-by-step explanation:



ach correct answer scores 3 points.

Each incorrect answer loses 2 points.

A question not answered scores 0

It is possible to finish the quiz with a negative score.

1) If 75 is the maximum score you can get, what is the minimum score on the quiz?

2) A student answers 21 questions. 6 are correct. How many points does she score?

Answer:



Step-by-step explanation:



ach correct answer scores 3 points.

Each incorrect answer loses 2 points.

A question not answered scores 0

It is possible to finish the quiz with a negative score.

1) If 75 is the maximum score you can get, what is the minimum score on the quiz?

2) A student answers 21 questions. 6 are correct. How many points does she score?

Answer:



Step-by-step explanation:



ach correct answer scores 3 points.

Each incorrect answer loses 2 points.

A question not answered scores 0

It is possible to finish the quiz with a negative score.

1) If 75 is the maximum score you can get, what is the minimum score on the quiz?

2) A student answers 21 questions. 6 are correct. How many points does she score?

Answer:

2h



Step-by-step explanation:



Question

.

There are 25 questions in a quiz.

Each correct answer scores 3 points.

Each incorrect answer loses 2 points.

A question not answered scores 0

It is possible to finish the quiz with a negative score.

1) If 75 is the maximum score you can get, what is the minimum score on the quiz?

2) A student answers 21 questions. 6 are correct. How many points does she score?



The next two centroids after one iteration using k-means with k = 2 and euclidean distance are (14.5, 12.75) and (15.5, 15.5).


1. Assign each point to its closest centroid:
- For (12.0, 12.5):
 - Calculate the distance to (12.0, 12.5) and (15.0, 15.5).
 - Assume the distance to (12.0, 12.5) is closer, so assign the point to that centroid.
- For (15.0, 16.0):
 - Calculate the distance to (12.0, 12.5) and (15.0, 15.5).
 - Assume the distance to (15.0, 15.5) is closer, so assign the point to that centroid.
- For (16.0, 15.0):
 - Calculate the distance to (12.0, 12.5) and (15.0, 15.5).
 - Assume the distance to (15.0, 15.5) is closer, so assign the point to that centroid.
- For (17.0, 13.0):
 - Calculate the distance to (12.0, 12.5) and (15.0, 15.5).
 - Assume the distance to (12.0, 12.5) is closer, so assign the point to that centroid.

This gives us two clusters of points assigned to each centroid:
- Cluster 1: (12.0, 12.5), (17.0, 13.0)
- Cluster 2: (15.0, 16.0), (16.0, 15.0)

2. Calculate the mean of the points assigned to each centroid to get the new centroid location:

- For Cluster 1:
 - Mean of (12.0, 12.5) and (17.0, 13.0) = \((\frac{12.0+17.0}{2},\frac{12.5+13.0}{2})\) = (14.5, 12.75)
- For Cluster 2:
 - Mean of (15.0, 16.0) and (16.0, 15.0) = \((\frac{15.0+16.0}{2},\frac{16.0+15.0}{2})\) = (15.5, 15.5)

Therefore, the next two centroids after one iteration using k-means with k = 2 and euclidean distance are (14.5, 12.75) and (15.5, 15.5).

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Answer:

the answer is 20 and 5

Step-by-step explanation:

Number of hats is 5 and the number of sweatshirts is 20

The total number of items bought is 25

The total amount is $172.50

Let a represent the number of sweatshirts

Number of hats is 25-a

Cost of sweatshirt= 8x

Cost of hat= 2.50×(25-x)

= 62.50-2.5x

8x + 62.50 - 2.5x-172.50

8x-2.5x+62.50-172.50

5.5x -110

5.5x= 110

x= 110/5.5

= 20

Number of hats= 25-20, = 5

Number of sweatshirts= 20

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Answer:

  27.57 in

Step-by-step explanation:

You want the length of the longer diagonal of a rhombus with side lengths 14 inches and obtuse angle 160°.

The law of cosines can be used to find the diagonal length. The length of the third side (c) is given by ...

  c² = a² +b² -2ab·cos(C)

where a and b are the other two sides, enclosing angle C.

  c² = 14² +14² -2·14·14·cos(160°)

  c² = 392 -392·cos(160°) ≈ 760.35951

  c ≈ 27.5746

The longer diagonal is about 27.57 inches long.

Answer:

Step-by-step explanation:

fars

Answer:

He can buy 5 pounds of peaches.

Step-by-step explanation:

2 pomegranates cost $3.18 so, subtract that from $10.00 and you get $6.82. Multiply the different number of pounds with the cost per pound until you go over $6.82. Then go back a pound and multiply. 5 pounds times $1.19 equals $5.95.

Answer:

hope it will help you

Step-by-step explanation:

f(x)=x²+7

X(-2)=?

therefore X(-2)=(-2)²+7

=4+7

=11

Answer:

5

Step-by-step explanation:

For this case, we have the following equation:

4/5x = 8

We must find a number that when multiplied on both sides of the equation, as a result:

x = 10x

So, if we multiply 8 * 5 = 40

Now, the left side must also be multiplied by 5 to not alter the equation:

(4/5)x*5=4x

x∗5=4x

Finally we have 4x=40

Clearing "x":

\begin{gathered}x = 40/4

x=10

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(a) Find the dual of the LP.Primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\) subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n \leq\) \(b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n \leq b_m$ and $x_1, x_2,\)..., x_n\(\geq 0$\)

Let us find the dual of the above primal problem.

Dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq\)\(C_1$...$a_{1n}y_1+a_{2n}y_2+...+a_{mn}y_m \leq C_n$\)

and\($y_1, y_2, ..., y_m \geq 0$\)

(b) Find the standard form of the LP and dual.Standard form of the primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\)subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n +s_1 = b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n +s_m = b_m$\) and\($x_1, x_2, ..., x_n, s_1, s_2, ..., s_m \geq 0$\)

Standard form of the dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq 0$...$a_{1n}y\)

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