in a(n) ____ joint the edges of the metal meet so that the thickness of the joint is approximately equal to the thickness of the metal.
Answers
In a butt joint, the edges of the metal meet so that the thickness of the joint is approximately equal to the thickness of the metal.
In a butt joint, the edges of the metal pieces are placed together so that they are flush with one another, with little or no overlap. This results in a joint where the thickness of the joint is approximately equal to the thickness of the metal being joined. Butt joints are commonly used in welding and metal fabrication, as they provide a clean, simple joint that can be easily welded or brazed together. However, they may not be as strong as other types of joints, such as lap joints or T-joints, which provide more surface area for welding or brazing.
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In welding, a joint refers to the area where two pieces of metal are joined together. There are several types of joints used in welding, including butt joints.
A butt joint is formed when two pieces of metal are placed together, edge to edge, and welded.
The joint is formed so that the thickness of the joint is approximately equal to the thickness of the metal being joined.
The process of making a butt joint involves
1) first preparing the edges of the metal.
2) This may involve grinding or filing to ensure that the edges are clean and straight.
3) The two pieces of metal are then brought together, with their edges touching, and held in place using clamps or other devices.
4) Once the pieces are in place, a welding machine is used to fuse the metal together.
The welding process may involve the use of heat or pressure, or a combination of both, depending on the type of welding being used.
The resulting joint is strong and durable, and is often used in a variety of applications where a strong, seamless joint is needed.
Butt joints are commonly used in the construction of buildings, bridges, and other structures, as well as in the manufacturing of machinery and equipment.
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Related Questions
Two stars with identical diameters are the same distance away. One has a temperature of 16800 ºK, the other has a temperature of 4200 ºK. How much brighter is the hotter star? (Use Stephan-Boltzmann law) Brightness = F = σ T4
a. 32 times
b. 64 times
c. 26 times
d. 60 times
Answers
The correct answer is (b) 64 times.
The Stefan-Boltzmann law relates the luminosity of a star (F) to its surface temperature (T) and radius (R) by the equation:
F = σT^4A
where σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2 K^4) and A is the surface area of the star.
Assuming that the two stars have the same radius, we can calculate the ratio of their luminosities (and therefore their brightness) as:
F_hot / F_cool = (σ T_hot^4 A) / (σ T_cool^4 A)
= (T_hot / T_cool)^4
= (16800 K / 4200 K)^4
= 16^4
= 65536
Therefore, the hotter star is 65536 / 1 = 65536 times brighter than the cooler star.
The closest answer choice is b. 64 times, which is the result of rounding the actual answer. So, the correct answer is (b) 64 times.
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What is the centripetal acceleration acting on a 19 kg ball if it is being spun around by a tension force of 125 N?
Answers
Answer:
Explanation:
The centripetal acceleration:
aₙ = F /m = 125 /19 ≈ 6.6 m/s²
two converging lenses, each of focal length 14.8 cm, are placed 39.7 cm apart, and an object is placed 30.0 cm in front of the first lens. where is the final image formed? the image is located cm ---location--- what is the magnification of the system?
Answers
The final image is formed by two converging lenses at 15.3 cm in front of the second lens and the magnification of the system is -0.99.
To find the location of the final image, we can use the lens formula:
1/f = 1/do + 1/di
where f is the focal length of the lens, do is the object distance, and di are the image distance.
For the first lens, f = 14.8 cm and do = 30.0 cm. Plugging these values into the lens formula gives:
1/14.8 = 1/30 + 1/di
Solving for di, we get:
di = 20.1 cm
This means that the first lens forms an image 20.1 cm behind it, which serves as the object for the second lens.
Using the lens formula again for the second lens, f = 14.8 cm and do = 39.7 - 20.1 = 19.6 cm. Plugging these values into the lens formula gives:
1/14.8 = 1/19.6 + 1/di
Solving for di, we get:
di = 9.1 cm
Therefore, the final image is formed 9.1 cm behind the second lens.
To find the magnification of the system, we can use the formula:
m = - di/do
where m is the magnification, di is the image distance, and do is the object distance.
Plugging in the values we found, we get:
m = -9.1/30.0 = -0.303
Therefore, the magnification of the system is -0.303, which indicates that the image is inverted and smaller than the object.
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5)a heat engine is operating on a carnot cycle and has a thermal efficiency of 55 percent. the waste heat from this engine is rejected to a nearby lake at 60 f at a rate of 800 btu/min. determine (1) the power output of the engine and (b) the temperature of the source.
Answers
(1) the determined power output of the heat engine is 1075.66kJ/min.
(b) the temperature of the source 676.891 K.
η = 55%
T = 15 degree = 288K
Q' = 800 btu/ mint
To calculate Q
η = 1 - Q'/Q
0.55 = 1 - (800 x1.05506)/Q
(∵ 1 btu = 1.05506 kJ )
btu = British thermal unit
then
0.55 = 1 - (800 x 1.05506)/Q
Q = 1875.66kJ/min
To calculate output work
W = Q - Q' = 1075.66kJ/min.
b) Temperature of the source is given as:
T ∝ Q
T/T' = Q/Q'
T' = 60F = 288.705556 K
Then
T/288.705556 K = 1875.66 /800
T = (1875.66 x 288.705556) /800
T = 676.891 K
(1) the determined power output of the heat engine is 1075.66kJ/min.
(b) the temperature of the source 676.891 K.
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You drive a car 660 m to the east, then 400 m to the north. What is the magnitude of your displacement? Using a sketch, estimate the direction of your displacement. Verify your estimate with a numerical calculation of the direction.
Answers
Explanation:
You walk 53m to the north, then you turn 60° to your right and walk another 45m. Determine the direction of your displacement vector. Express your answer as an angle relative to east.
How many protons, neutrons, and electrons are there, respectively, in an atom of o-17?.
Answers
In an atom of O-17, proton and electron is 8, and neutrons is 9.
The atomic number, sometimes referred to as nuclear charge number, of a chemical element is the charge number of an atomic nucleus. For conventional nuclei, this is comparable to the proton number, or the number of protons found in the nucleus of each atom of that element.The atomic number of oxygen is 8. Therefore, an atom needs 8 protons in order to be referred to as an oxygen atom. For instance, an atom will no longer be oxygen if it has 9 protons and will now be fluorine. Any atom that lacks 8 protons is not an oxygen atom. For an atom to be neutrally charged, the number of protons and electrons within it must match. Therefore, there should be 8 electrons in all. However, depending on the isotope, the neutron count can change. An oxygen isotope is a distinct variety of oxygen. For instance, oxygen-15, which has 7 neutrons, is a possibility. The neutron count for oxygen-16 would be 8, for oxygen-17 it would be 9, and so on.Learn more about the quantum mechanics with the help of the given link:
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A neutral metal sphere is attracted to a positively-charged amber rod. Why does this occur?.
Answers
Hi there!
A neutral metal sphere is comprised of both ELECTRONS and PROTONS.
Recall that electrons have a NEGATIVE (-) charge, and protons have a POSITIVE (+) charge.
Opposite charges attract, and like charges repel.
In this instance, the positively-charged rod will cause the electrons in the neutral metal sphere to move towards the side facing the rod (opposite charges attract), which causes the two to be attracted to one another.
For this truss geometry:
|/\|/\|/\|/\|
Select one or more:
a. The bottom chords do not usually need the verticals, since the bottom chords are not subjected to bending loads and the bottom chords only go into compression under severe wind suction that overcomes the dead weight of the structure.
b. This is called a Modified Warren Truss.
c. The vertical webs help brace the top chord against buckling upward and downward.
d. The vertical webs help support parts of the top chord, thereby reducing the span, and associated bending stress, of the top chord under the uniform gravity force of the decking resting on the top chord of the truss.
e. The unbraced length for the bottom chords is twice as long as the unbraced length for the top chords.
Answers
The bottom chords do not usually need the verticals, since the bottom chords are not subjected to bending loads and the bottom chords only go into compression under severe wind suction that overcomes the dead weight of the structure.
Why the bottom chords not usually need verticles?
Truss is a building structure that is usually composed of several triangular units made of straight bars. The triangle shape helps distribute the weight evenly across the structure, making it much stronger than a traditional beam or other type of structure. The Warren truss is a common type of truss used in construction and engineering projects that is used for its strength and durability.
Modified Warren Truss: It is a variation of the Warren truss that includes vertical web members that are added to the structure to help support the top chord and reduce the span of the structure. This reduces the amount of bending stress that is put on the top chord and helps to keep the structure stable and secure.
Vertical webs: The vertical webs are the diagonal members that are added to the Modified Warren Truss. These help to brace the top chord against buckling upward and downward and support parts of the top chord, thereby reducing the span and associated bending stress of the top chord under the uniform gravity force of the decking resting on the top chord of the truss.
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rank the automobiles based on the magnitude of the force needed to stop them, from largest to smallest. rank from largest to smallest. to rank items as equivalent, overlap them. if the ranking cannot be determined, check the box below.
Answers
The ranking of the cars from the largest to smallest based on the linear momentum, size of impulse and force needed to stop them is,
Light blue car = Purple car > Red car = Yellow car = Blue car > Green car
The linear momentum of each car can be calculated by;P = mu
where;
m is the mass of the automobile
u is linear speed of the automobile
The linear momentum of the Red car is given as;
P = 1000 x 10 = 10, 000 kg.m/s
The linear momentum of the Yellow car is given as;
P = 2,000 x 5 = 10,000 kg.m/s
The linear momentum of the Blue car is given as;
P = 500 x 20 = 10,000 kg.m/s
The linear momentum of the Light blue car is given as;
P = 1,000 x 20 = 20,000 kgm/s
The linear momentum of the Green car is given as;
P = 500 x 10 = 5,000 kg.m/s
The linear momentum of the Purple car is given as;
P = 4,000 x 5 = 20,000 kg.m/s
we can defined Impulse as the change in linear momentum;
J = ΔP
J = m(u - v)
J = mu = P
The force needed to stop each car is directly proportional to the impulse needed to stop the car.
Force x t = J
where;
t is the time of motion
Thus, we can conclude that the linear momentum of each car is directly proportional to the impulse and force needed to stop it.
P ∝ J ∝ Force
Ranking the cars from the largest to smallest based on the linear momentum, size of impulse and force needed to stop them;
Light blue car = Purple car > Red car = Yellow car = Blue car > Green car
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Complete question:
Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The drivers step on the brakes and all automobiles are brought to rest. Red Car: 1000kg, 10m/s Yellow Car: 2,000kg, 5m/s Blue Car: 500kg, 20m/s Light Blue Car: 1,000kg, 20m/s Green Car: 500kg, 10m/s Purple Car: 4,000kg, 5m/s Part A Rank these automobiles based on the magnitude of their momentum before the brakes are applied, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. Part B Rank these automobiles based on the magnitude of the impulse needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. Part C Rank the automobiles based on the magnitude of the force needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. if the ranking cannot be determined, check the box below.
PLZZ HELP
If you have two objects moving at the same velocity, would the object with bigger mass have higher or lower kinetic energy?
Answers
Answer:
The kinetic energy of a moving object is directly proportional to its mass and directly proportional to the square of its velocity. This means that an object with twice the mass and equal speed will have twice the kinetic energy while an object with equal mass and twice the speed will have quadruple the kinetic energy.
5. The Hall coefficient and conductivity of Cu at 400 K have been measured to be 0.45x10-10 m³/As and 6.5 /ohm-meter respectively. Calculate the drift mobility of the electrons in Cu.
Answers
The drift mobility of electrons in Cu is the ratio of the electric field to the charge carried by an electron and the time it takes for an electron to reach from one end of a conductor to the other under an applied electric field.
The Hall coefficient is defined as \(RH = (1/ne) * (dVH/dB)\) where n is the charge density, e is the charge of an electron, VH is the Hall voltage, and B is the magnetic field. To calculate the drift mobility of the electrons in Cu, we will first determine the charge density n using the Hall coefficient.
We can then use the conductivity and charge density to calculate the drift mobility. Given, Hall coefficient \(RH = 0.45 × 10^-10 m^3/A s\) and Conductivity \(σ = 6.5 /ohm\) meter at a temperature of 400K. (Magnetic field)
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[16 POINTS: 3 Physics Q’s]
9. What is the difference between contact forces and field forces?
11. As an object falls through Earth’s atmosphere, which statement correctly describes the energy change (assume no friction or drag)
A. The potential energy of an object decreases while the thermal energy increases.
B. The kinetic energy of the object increases while the elastic energy increases.
C. The potential energy of the object decreases while the kinetic energy increases.
D. The thermal energy of the object decreases while the kinetic energy increases.
12. Which of the following is true about the charge of an electron?
A. It is 1.602 x 10^-19 C, and the smallest unit of charge
B. It is -1.602 x 10^-19 and the smallest unit of charge.
C. It is -1.602 x 10^-9 , and it a multiple of the smallest unit of charge.
D. It is 1.602 x 10^-19, and it is a multiple of the smallest unit of charge.
*Thanks in advance* ❤️
Answers
Answer:
c
Explanation:
gfdschhgfdxcvhgfd
A hockey puck slides to a stop on ice. The coefficient of friction between the puck and
the ice is 0.026. What is the puck’s acceleration?
Answers
Answer:
Explanation:
The puck slides on the ice . Coefficient of sliding friction μ = .026
Limiting frictional force = μ R
R is reaction force of the surface .
R = mg
Friction force = μ mg
deceleration = μ mg / m
= μ g
= .026 x 9.8 = .2548
= 0.26 m /s².
what will happen to the charge on the second ball (i.e., the ball further away from the rod) if it is momentarily grounded while the rod is still there? g
Answers
If the second ball is momentarily grounded while the rod is still there, the charge on the second ball will be neutralized.
What is meant by grounding?Grounding is the process of removing excess charge on object by means of transfer of electrons between it and another object of substantial size. When charged object is grounded, then the excess charge is balanced by the transfer of electrons between the charged object and ground.
When the second ball is grounded, it establishes an electrical connection with the Earth, allowing excess electrons to flow from the ball to the Earth, thus neutralizing its charge.
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3500 - kg truck traveling 20. 0 m/s [E] strikes a 2000-kg parked minivan. After the collision, the parked minivan is propelled forward with a velocity of 14. 0 m/s [E]. Determine the final velocity of the truck
Answers
The final velocity of the truck after the collision is 12 m/s in the same direction (east) as before the collision.
To determine the final velocity of the truck after the collision, we can use the principle of conservation of momentum.
The initial momentum of the system (truck + minivan) before the collision is given by:
Initial momentum = (mass of truck) × (velocity of truck) + (mass of minivan) × (velocity of minivan)
= (3500 kg) × (20.0 m/s) + (2000 kg) × (0 m/s) [since the minivan is parked]
Since the minivan is stationary before the collision, its initial velocity is 0 m/s.
The final momentum of the system after the collision is given by:
Final momentum = (mass of truck) × (final velocity of truck) + (mass of minivan) × (final velocity of minivan)
= (3500 kg) × (final velocity of truck) + (2000 kg) × (14.0 m/s) [given]
According to the conservation of momentum, the initial momentum of the system should be equal to the final momentum:
Initial momentum = Final momentum
(3500 kg) × (20.0 m/s) + (2000 kg) × (0 m/s) = (3500 kg) × (final velocity of truck) + (2000 kg) × (14.0 m/s)
Now, we can solve the equation to find the final velocity of the truck:
(3500 kg) × (20.0 m/s) = (3500 kg) × (final velocity of truck) + (2000 kg) × (14.0 m/s)
70000 kg·m/s = (3500 kg) × (final velocity of truck) + 28000 kg·m/s
42000 kg·m/s = (3500 kg) × (final velocity of truck)
final velocity of truck = 42000 kg·m/s / 3500 kg
final velocity of truck = 12 m/s
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2.3. A local municipality wants to reduce the speed limit in school areas to 50 km.h¹. Do you think this is an acceptable idea? Support your answer with scientific facts.
Answers
If you are driving your car you must pay attention to speed limit signals and respect them if you don't want to be fined by the police. Depending on the art of the city or the municipality, speed limits change. For instance, if you cross a school zone, the standard speed limit is 50mph.
What is average speed?
The entire distance traveled by the object in a specific amount of time is its average speed. A scalar value represents the average speed. The magnitude serves as its representation, and it lacks direction.
Average speed of answer (ASA) is the length of time it takes to answer a call from the time a consumer is added to a waiting list to the time an agent picks up the phone.
Why is average speed used as a term?
The definition of speed is the rate of movement at which anything is moving. The term "average speed" refers to the pace that a vehicle travels at on average during a trip. Typically, average speed is used to describe moving objects like cars, trains, and airplanes.
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What distance is required for a train
to stop if its intial Velocity is 23 m/s
and its deceleration is 0.25m/s (Assume the train decelerates at a constant rate.)
Answers
Explanation:
what is time in this question
This a solving question
Please please help
Answers
Answer:
Part A
The sound intensity at the location 150 from the firework = 4.3\(\overline 5\) W/m²
Part B
The power the firework is emitting is approximately 1,231.5 kW
Explanation:
Part A
The data of the firework sound heard by the two friends are;
Let 'A' represent the location of the friend at a point 150 m from the fireworks and let 'B' represent the location of the friend watching from a distance of 700 m from the firework
The distance of 'A' from the sound, r₁ = 150 m
The distance of 'B' from the sound, r₂ = 700 m
The intensity at which 'B' hears the sound, I₂ = 0.2 W/m²
The relationship between sound intensity and distance is given as follows;
\(\dfrac{I_2}{I_1} = \left (\dfrac{r_1}{r_2} \right )^2\)
\(\therefore {I_1} = \dfrac{I_2}{ \left (\dfrac{r_1}{r_2} \right )^2} = I_2 \times \left (\dfrac{r_2}{r_1} \right )^2\)
Plugging in the values gives;
\(\therefore {I_1} = 0.2 \times \left (\dfrac{700}{150} \right )^2 = \dfrac{196}{45} = 4.3\overline 5\)
The sound intensity at location 'A', I₁ = 4.3\(\overline 5\) W/m²
Part B
The relationship between power, 'P', and intensity, 'I', is presented as follows;
\(I = \dfrac{P}{4 \cdot \pi \cdot r^2}\)
P = I·4·π·r² = 4·I·π·r²
Therefore, at point 'A', where the distance, r₁ = 150 m, and the intensity, I₁ = 4.3\(\overline 5\) W/m², we have;
P = 4 × 4.3\(\overline 5\) W/m² × π × (150 m)² = 1231504.32021 W
The power the firework is emitting, P ≈ 1,231.5 kW.
Neutron stars have about the same mass as our sun but a much smaller diameter. The radius of a
neutron star is 10 x 10 m and its mass is 1.99 x 1030 kg. If you weigh 675 N on the earth, what
would you weigh on the surface of a neutron star?
A) 8.36 x 10^13 B) 7.42 x 10^13 C) 6.87 x 10^13 D) 9.16 x 10^13
Answers
Answer:
\(9.15\times 10^{13}\ \text{N}\)
Explanation:
\(m=\text{Mass of person}=\dfrac{675}{g}=\dfrac{675}{9.8}\ \text{kg}\)
\(g=\text{Acceleration due to gravity on Earth}=9.8\ \text{m/s}^2\)
\(r=\text{Radius the neutron star}=10\ \text{km}\)
\(M=\text{Mass of neutron star}=1.99\times 10^{30}\ \text{kg}\)
\(G=\text{Gravitational constant}=6.674\times10^{-11}\ \text{Nm}^2/\text{kg}^2\)
Weight on neutron star would be
\(W_n=\dfrac{GmM}{r^2}\\\Rightarrow W_n=\dfrac{6.674\times 10^{-11}\times \dfrac{675}{9.8}\times 1.99\times 10^{30}}{10000^2}\\\Rightarrow W_n=9.15\times 10^{13}\ \text{N}\)
Weight of the person on the neutron star would be \(9.15\times 10^{13}\ \text{N}\)
A 5 kg object oscillates with simple harmonic motion. Its position as a function of time varies according to the following equation x(t) = 2 sin(( π/2)t + ( π/6))
At what time (in seconds) after t = 0 seconds is the kinetic energy first at a maximum?
Answers
The kinetic energy is first at a maximum after approximately 3.67 seconds after t=0.
To determine the time when the kinetic energy is first at a maximum, we need to find the time at which the velocity of the object is at a maximum. The kinetic energy of an object undergoing simple harmonic motion is maximum when the velocity is maximum.
The equation for velocity as a function of time in simple harmonic motion is given by:
v(t) = Aω cos(ωt + φ)
where A is the amplitude, ω is the angular frequency, t is time, and φ is the phase constant.
In this case, the equation for position is x(t) = 2 sin((π/2)t + (π/6)), which is in the form x(t) = A sin(ωt + φ).
Comparing the two equations, we can see that ω = π/2.
The velocity equation becomes:
v(t) = (π/2)A cos((π/2)t + φ)
To find the time at which the velocity is maximum, we need to find when the cosine term is at its maximum value of 1. This occurs when (π/2)t + φ = 0 or (π/2)t + φ = 2π.
Solving for t, we get:
(π/2)t = -φ or (π/2)t = 2π - φ
t = (-2φ/π) or t = (4π - 2φ)/π
Since the phase constant φ in the given equation is π/6, we substitute this value into the equations:
t = (-2(π/6)/π) or t = (4π - 2(π/6))/π
t = -1/3 or t = 11/3
Therefore, the kinetic energy is first at a maximum at t = 11/3 seconds.
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a spaceship of proper length 300 m takes 0.75 μs to pass an earth observer. determine the speed of this spaceship as measured by the earth observer.
Answers
The speed of the spaceship as measured by the earth observer is 0.4c.
To determine the speed of the spaceship, we can use the time dilation formula:
Δt' = Δt/√(1-v²/c²)
where Δt is the time interval measured by the earth observer, Δt' is the time interval measured by an observer on the spaceship, v is the velocity of the spaceship, and c is the speed of light.
In this case, Δt' = 0.75 μs and the proper length of the spaceship, L, is 300 m.
Using the equation for proper length contraction, we can find L' = L/√(1-v²/c²)
Solving for v in both equations and equating them, we get:
v = (L/L') * c * √(1-((Δt/Δt')²))
Plugging in the values, we get v = 0.4c, where c is the speed of light. Therefore, the speed of the spaceship as measured by the earth observer is 0.4 times the speed of light.
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What natural disaster presents the greatest threat to Western Central Europe?
volcanoes
flooding
Tsunamis
earthquakes
Answers
Answer:
flooding
Explanation:
The moon is lit by light bouncing off of it. That light reaches Earth as ____. The different shapes that the moon appears to have are called ____. The moon goes through ____ phases as it revolves around the ____ every ____ days. The phase that we see depends on how much of the ____ part of the moon we can see. This depends on the positions of the ____, ____, and ____.
Answers
Answer:
Moonlight; phases; eight; 29 days; sunlit; earth; sun; moon.
Explanation:
A moon generally do not have or possess light but rather it reflects the light from the sun.
The moon is lit by light bouncing off of it. That light reaches Earth as moonlight. The different shapes that the moon appears to have are called phases. The moon goes through eight (8) phases as it revolves around the earth every 29 days. The phase that we see depends on how much of the sunlit part of the moon we can see. This depends on the positions of the earth, sun, and moon.
The eight (8) phases of the moon include the following;
1. Last quarter half moon.
2. Waning crescent moon.
3. New moon.
4. Waxing crescent moon.
5. First quarter half moon.
6. Waxing Gibbous moon.
7. Full moon.
8. Waning Gibbous moon.
a uniform solid sphere of mass m1 and radius r is inside and concentric a sphere shell of mass2 and radius r2. find the gravitational force exerted by the sphere
Answers
Find the gravitational force exerted by the sphere is r = a
How to find the gravitational force ?
Total gravitational Field at r=a
Total gravitational Field at r = a =Field due to solid sphere+ field due to spherical shell
we know gravitational field inside spherical shell is zero.
and gravitational field due to solid sphere inside = GMr/ R²
so here
Total gravitational Field= Field due to solid sphere+ field due to spherical shell
G = (Gm1a / R²1) + 0
Force exerted on particle F = mG
F = Gm1 ma / R²1
Gravitational force :
Gravity is a fundamental interaction in physics that causes mutual attraction between all things that have mass or energy. By far the weakest of the four fundamental interactions, gravity is approximately \(10^{38}\) times weaker than the strong interaction, \(10^{36}\) times weaker than the electromagnetic force, and \(10^{29}\) times weaker than the weak interaction.
As a result, it has no effect at the level of subatomic particles. Gravity, on the other hand, is the most significant interaction between objects on the macroscopic scale, determining the motion of planets, stars, galaxies, and even light.
Gravity gives physical objects weight on Earth, and the Moon's gravity is responsible for sublunar tides in the oceans. Gravity also serves many important biological functions, such as guiding plant growth via gravitropism and influencing fluid circulation in multicellular organisms.
Gravity is responsible for many of the large-scale structures in the Universe because the gravitational attraction between the original gaseous matter in the Universe allowed it to coalesce and form stars, which eventually condensed into galaxies. Gravity has an infinite range, but its effects weaken as objects move further away.
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Jasmine, a san francisco hot dog vender, has fallen asleep on the job. when an earthquake strikes, her 327 kg hot dog cart rolls down nob hill and reaches point a at a speed of 2.9 m/s. how fast is the hot dog cart going at point b when jasmine finally wakes up?
Answers
The speed of the hot dog cart going at point B wen jasmine finally wakes up is 21.36 m/s.
Mass of the cart = m = 327 Kg
Speed of the cart while rolling downhill = v = 2.9 m/s
Height of the hill = h = 50 m
Height at point B = h' = 30 m
Speed of the cart when jasmine wakes up = v' =
Using the conservation of energy theorem,
= sum of kinetic and potential energy initially = sum of kinetic energy finally at point B
= mgh + (1/2)mv² = (1/2)mv'²
= gh + (1/2)v² = (1/2)v'²
= 9.81 X (50-30) + (1/2) X 2.9² = (1/2)v'²
= v'² = 21.36 m/s
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A farmer is walking through a field at a
velocity of +0.5 meters per second (m/s)
relative to the ground. At the same time, he
is throwing seeds in front of him at a
velocity of +2.1 m/s relative to himself.
What is the velocity of the seeds relative to
the ground as they travel through the air?
Answers
Answer:
The velocity of the seeds relative to the ground as they travel through the air is V = +2.6 m/s
Explanation:
Let V be the velocity of the seeds relative to the ground, v be the velocity of the seeds relative to the farmer and v' be the velocity of the farmer relative to the ground.
By vector addition, V = v + v'
Since v = the velocity of the seeds relative to the farmer = +2.1 m/s and
v' = the velocity of the farmer relative to the ground = +0.5 m/s
Then,
V = v + v'
V = +2.1 m/s + (+0.5 m/s)
V = +2.6 m/s
So, the velocity of the seeds relative to the ground as they travel through the air is V = +2.6 m/s
What is benford's law.
Answers
Answer:
Known variously as the Newcomb–Benford law, the law of anomalous numbers, or the first-digit law, Benford's Law is the observation that the first digit in many real-world collections of numerical data will be tiny, as shown by the example of the first-digit law.
Explanation:
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Measures wave heights. a. e. buoys b.c. dropsonde c. b. ASOS d. d. satellite e. a. radar
Answers
The correct answer is a. buoys.
Buoys are floating devices that are used to measure the height of waves.
They are typically anchored to the seabed, and they have a sensor that measures the height of the waves as they pass by. This information is then transmitted to a central location, where it can be used to track the movement of waves and to predict their behavior. Buoys are an important tool for monitoring the ocean and for predicting the weather. They are also used to warn ships of dangerous conditions at sea. Buoys are floating devices that are used to measure the height of waves. They are typically anchored to the seabed, and they have a sensor that measures the height of the waves as they pass by. This information is then transmitted to a central location, where it can be used to track the movement of waves and to predict their behavior. Buoys are an important part of the global network of ocean observing systems. They provide valuable data that is used to track the movement of waves, to predict the weather, and to warn ships of dangerous conditions at sea.
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When designing the client's solution What is the order of importance related to Confidentiality Integrity and Availability CIA )?
Answers
Due to the nature of the sector and applicable laws, confidentiality is followed by integrity, then availability.
When it comes to sensitive information, confidentiality refers to the idea and practice of keeping it secret until the owner or data custodian explicitly consents to sharing it with another party. Another definition of confidentiality is the request to uphold the rule and custom.
Owners and custodians of sensitive data create policies defining the categories of information that require protection in order to preserve confidentiality. On the basis of it, they specify a number of procedures for the environments, tools, and people engaged in data handling and storage. These include educating and training staff members and the clients they serve, investing in and maintaining the buildings, equipment, and software where data resides and travels, tracking the movements of sensitive data, and planning and implementing data loss prevention (DLP).
One of the most well-known laws governing the confidentiality of patient data, namely how healthcare providers and insurers handle and transmit such data, is the Health Insurance Portability and Accountability Act of 1996 (HIPAA).
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A hydraulic lift is used to raise an automobile of mass 1520 kg. The radius of the shaft of the lift is 8.00 cm and that of the piston is 1.00 cm. How much force must be applied to the piston to raise the automobile?
Answers
To raise the automobile with a hydraulic lift, a force of approximately 19,000 N must be applied to the piston.
In a hydraulic lift, the principle of Pascal's law is applied, which states that pressure applied to an enclosed fluid is transmitted undiminished to all portions of the fluid and the walls of its container. By utilizing this principle, a smaller force applied to a smaller piston can generate a larger force on a larger piston.
In this scenario, the force needed to lift the automobile can be calculated using the formula:
\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)
where \(F_{1}\) is the force applied to the piston, \(A_{1}\) is the area of the piston, \(F_{2}\) is the force generated on the larger piston (required to lift the automobile), and \(A_{2}\) is the area of the larger piston.
Given the radius of the shaft (small piston) as 0.08 m and the radius of the piston as 0.01 m, we can calculate the forces applied and generated as follows:
\(A_{1} = \pi (0.08)^2\\A_{2}= \pi (0.01)^2\)
\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)
Simplifying the equation and substituting the values, we can solve for \(F_{2}\):
\(F_{2}=\frac{F_{1}A_{2}}{A_{1}}\)
Plugging in the values, we find:
\(F_{2}=\frac{F_{1} \pi (0.01)^2 }{ \pi (0.08)^2} \\F_{2}= \frac{F_{1}\times 0.0001}{0.0064} \\F_{2}= 0.015625 \times F_{1}\)
Given that the mass of the automobile is 1520 kg and the acceleration due to gravity is \(9.8 \hspace m/s^{2}\), we can equate \(F_{2}\) to the weight of the automobile:
\(F_{2}= mg\\0.015625\times F_{1}= 1520\times 9.8\)
Solving for \(F_{1}\), we find:
\(F_{1}\approx \frac{1520\times 9.8}{0.015624} \\F_{1} \approx 19072 \hspace N\)
Therefore, a force of approximately 19,000 N must be applied to the piston in order to raise the automobile using the hydraulic lift.
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