An insulated vessel containing a quantity of hot water at temperature T₁ mixed with different amounts of cold water at temperature T₂, After equilibrium is established the vessel contains water at a mixture temperature between T₁ and T₂.
What is thermal equilibrium?Thermal equilibrium is a state reached by two (or more) systems characterized by limited coordinate values of the systems after the systems interact with each other through the diathermic wall.
When hot water and cold water are mixed, heat will flow from hot water (higher temperature) to cold water (lower temperature). In other words, hot water "gives" heat to cold water or cold water "receives" heat from hot water.
The direction of heat transfer is from an object or place with a higher temperature to a place with a lower temperature. Temperature transfer occurs until temperature equality is achieved between the two objects.
Hot water has a higher temperature than cold water, so heat moves from hot water which provides heat, to cold water which absorbs heat.
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The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. What is (a) the speed of the roller coaster at the top of the loop (in m/s) if the radius of curvature there is 13.0 m and the downward acceleration of the car is 1.50 g, and (b) the minimum speed necessary for the coaster to complete the loop without falling off the track?
the answer for the speed of the roller coaster at the top of the loop is v = 14.8 m/s
the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.
Explanation to the Roller Coaster Speed Calculation(a) To find the speed of the roller coaster at the top of the loop, we can use the equation for centripetal acceleration: a = v^2/r. We know that the radius of curvature is 13.0 m and the downward acceleration of the car is 1.50 g (where g is the acceleration due to gravity, approximately 9.8 m/s^2).
So, we can rearrange the equation to solve for v: v = sqrt(ar)
Plugging in the values, we get: v = sqrt(1.5g * 13m)
v = sqrt(22.5 * 9.8)
v = sqrt(219.5)
v = 14.8 m/s
(b) To find the minimum speed necessary for the coaster to complete the loop without falling off the track, we can use the same equation for centripetal acceleration, but this time we will use the minimum value of a that will keep the car on the track, which is equal to the acceleration due to gravity (g).
So, we can rearrange the equation to solve for v: v = sqrt(ar)
Plugging in the values, we get: v = sqrt(g * 13m)
v = sqrt(9.8 * 13m)
v = sqrt(127.4)
v = 11.3 m/s
So the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.
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How much work is done on the object as it moves from 0.0m to 2.0m?
The work done on the object as it moves from a distance of 0.0m to 2.0m is 40 J.
What is work done?Work done is defined as the product of the force applied and the distance moved by the force.
Work done = force * distanceThe unit of work done is Joules.
Based on the graph:
When the object moves from 0.0 m to 2.0 m
The force applied between 0.0 m to 2.0 m is 20 N
Hence, the work done will be:
Work done = 20 * 2.0
Work done = 40 J
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What two areas of your body (related to the skeletal system) would be impacted by prolonged periods of sitting and typing
Answer: Weak Legs and Glutes
Explanation: Cause ur legs go brrrrrr
A man runs 400.0m around the track,
then another 400.0m around the track again.
As the track is 400.Om long, the man is back
where he started!
a) calculate distance travelled
b) calculate mans displacement
Answer:
Distance = 800 m, Displacement = 0
Explanation:
It is given that,
A man runs 400 m around the track, then another 400 m around the track again.
(a) Distance travelled by an object is the sum of total path covered.
In this case, he has covered total path of 400 m + 400 m i.e. 800 m. It means he travelled a distance of 800 m.
(b) Displacement covered by an object is the shortest path covered by it. In this problem, he reaches the point from where he has started. It means that his displacement is equal to 0.
A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through a potential difference of 3V0, what speed would it gain? Group of answer choices
Answer:
\(v_{0,new} = v0\sqrt{}2\)
Explanation:
Initial work done on the proton is given by, \(\DeltaW0 = q V_o\)
we know that, \(\DeltaW = \DeltaK.E\)
\(qV0 = (1/2) m v_0^2\)
\(v_0 = \sqrt{}2 q V_0 / m\) { eq.1 }
If it were accelerated instead through a potential difference of 2V0, then it would gain a speed will be given as :
using the above formula, we have
\(v_{0,new} = \sqrt{}2 q (2V0) / m\)
\(v_{0,new} = \sqrt{}4 q V0 / m\)
\(v_{0,new} = v0\sqrt{}2\)
What happens to the acceleration of a ball if the force increases while the mass remains the same?
Answer:
if the force increases while the mass of the ball remains the same, the acceleration increases.
Explanation:
According to Newton's second law of motion, the acceleration of an object produced by a net force is directly proportional to the magnitude of the net force Fn and inversely proportional to the mass of the object m.
\(\displaystyle a=\frac{Fn}{m}\)
Suppose the net force doubles to 2Fn. The new acceleration will be:
\(\displaystyle a'=\frac{2Fn}{m}=2\frac{Fn}{m}=2a\)
The acceleration doubles too. Thus, if the force increases while the mass of the ball remains the same, the acceleration increases.
Which of Newton’s laws explains why a satellite continually orbits the earth and does not fall into the ground?
1st
2nd
None
3rd
Answer:
Newtons 1st law of inertia
Explanation:
Explanation:
probably the 1st law of motion, it'll continue at in a straight line as long as no external force is added or the net force equals to zero, same for the centrifugal force and the gravitational force
Why is an element considered a pure substance?
Answer:
Pure substance are made of only one kind of particles and fixed constant.
Explanation:
Pure substance are combined in fixed ratio into separate by chemical methods into a physical and chemical methods.
Pure substance are the classified by the compounds and elements, that pure substance fixed into melting and boiling points.Pure substance is used to the chemical reaction product, and there are homogeneous nature only one type.Pure substance include that the copper, oxygen and gold, and water or crystals as that used in pure substance.Pure substance are made the single element,and mainly used in uniform composition throughout.Pure substance element are contain the only one atom to perform the substance the physical and chemical.Pure substance elements into similar substance by heat and electricity reactions with other substance.Pure substance compound contain the two or more elements combined in a fixed proportion.Pure substance compound perform the separate by the physical methods, by that the electric chemical methods.Pure substance compound has fixed composition, and it has two elements hydrogen and oxygen in a ratio to combined.Answer:
A compound is a pure substance composed of two or more different atoms chemically bonded to one another. A compound can be destroyed by chemical means. It might be broken down into simpler compounds, into its elements or a combination of the two
Explanation:
separating paper from a mixture by burning it is it a physical change true or false
Answer:
false
Explanation:
burning something is a chemical change
if a 0.08kg cell phone falls of a table at 15 m/s then what is its kinetic energy right before it hits the ground?
The Kinetic energy of the cell phone of mass 0.08 kg is 9 J.
What is kinetic energy?Kinetic energy is the energy of a body in motion.
To calculate the kinetic energy of the cell phone, we use the formula below.
Formula:
K.E = mv²/2............. Equation 1Where:
K.E = Kinetic energy of the cell phonem = Mass of the cell phonev = Velocity of the cell phoneFrom the question,
Given:
m = 0.08 kgv = 15 m/sSubstitute these values into equation 1
K.E = 0.08×15²/2K.E = 9 JHence, the Kinetic energy of the cell phone is 9 J.
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A 1.35 kg block is pulled across a flat, frictionless floor with a 3.07 n force at 32.0 above horizontal. What is the acceleration of the block
Describe how spatial awareness during physical activity impacts student performance
I uploaded the answer to a file hosting. Here's link:
tinyurl.com/wpazsebu
Spatial awareness may impact student performance (even physical performance) because spatial understanding is fundamental for visual processing.
Spatial awareness refers to the understanding of a person (in this case a student) and of the relationships between different objects within a specific space.It has been shown that spatial awareness can affect performance in mathematics, punctuation spelling, etc. An example of spatial awareness includes the visualization of different objects from different perspectives.In conclusion, spatial awareness may impact student performance (even physical performance) because spatial understanding is fundamental for visual processing.
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What comes to mind when you think of the
word energy?
Think of all of the ways that you have heard
people use that word.
Good energy, Bad energy, Energy used to run, Energy drinks,
A charged particle moves from point A to point B in an external electric field, and in the process its kinetic energy decreases fro, 87.6 J at A to 57.3 J at B. The electric potential at A is -48.0 V, and the electric potential at B is 18.0 V. What is the charge of the particle, including sign
Answer:
-0.46 C
Explanation:
The relationship between total kinetic energy, KE, and total electric potential, V is:
ΔKE = ΔV * q
where ΔKE = change in kinetic
ΔV = change in voltage
q = charge
The kinetic energy changes from 87.6 J to 57.3 J while the electric potential changes from -48.0 V to 18.0 V.
Therefore:
57.3 - 87.6 = (18.0 - (-48.0)) * q
-30.3 = 66q
=> q = -30.3 / 66
q = -0.46 C
The charge of the particle is -0.46 C.
How far did the object travel from time = 0 to time =15 s 120 m. 180 m 90 m 45 m
Answer:Position is an object’s location in relation to a reference point.
Yes. As in the movie theater example, an object can be one unit positive from the reference point and a different object can be one unit negative from the reference point. Both objects are one unit away (the same distance), but they occupy different locations in space because they are in different directions.
Distance is the total amount an object has traveled, while displacement is the shortest distance between the object’s starting and finishing point.
Distance does not have direction. Objects can be one unit away from a point in every direction. However, displacement does have a direction. Displacement is defined as a specific distance in a specific direction.
Explanation: hope it helped
A scientist studies what makes leaves fall off trees. Which of the following is
a testable question about this topic?
A. Do leaves still look beautiful once they reach the ground?
B. Should people be allowed to burn leaves?
C. Are trees an interesting topic to study?
D. Do stronger winds make more leaves fall?
SUBMIT
Answer:
A.
Explanation:
During the fall the day gets shorter hence less sunlight this results to leaves stopping their food making process. The chlorophyll breaks down, the green color disappears and the yellow to orange color becomes visible
I need 6 things to save energy or increase energy efficiency in any part of a house
Here are six things that can help save energy or increase energy efficiency in any part of a house:
Install energy-efficient light bulbs: Replace traditional incandescent light bulbs with energy-efficient LED light bulbs. LED bulbs consume less electricity and last much longer.
Use a programmable thermostat: Installing a programmable thermostat can help you control the temperature of your home more efficiently. You can set it to automatically lower the temperature when you're away from home or sleeping.
Air leaks should be sealed with weatherstripping or caulk around windows and doors. By doing so, you can keep your house more pleasant and prevent draughts.
Install ceiling fans: Ceiling fans can help circulate air and keep your home cool in the summer and warm in the winter. They use less energy than air conditioners or heaters.
Upgrade to energy-efficient appliances: When it's time to replace appliances, choose ones with an Energy Star label. These appliances are designed to use less energy and can help you save money on your energy bills.
Use power strips: Plug electronics and appliances into power strips, which can be turned off when not in use. This can prevent phantom energy use, which occurs when electronics and appliances continue to draw power even when turned off.
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1. Two charges are separated by a distance of 1 cm. One charge has a value of 7 micro Coulombs. The other charge has a value of 10 micro Coulombs. What is the force between them, in pounds. Make sure to include the sign of the force which will be positive if the charges repel each other and negative if they attract each other.
2. 12 gauge copper wire is normally used in house wiring. When aluminum wire is used one needs to use a smaller gauge size to obtain the same resistance, 40 ft of 12 gauge copper wire was calculated. What would the resistance be if 10 gauge aluminum wire were used?
3. A 12 V automobile battery can supply 51 amps for one hour and cost $194. What is the cost of this electricity in cents per kWh?
4. Most of the body's resistance is in its skin. When wet, salts go into ion form, and the resistance is lowered. Thus, the resistance of the skin can go from 100,000 ohms when dry to 300 ohms when wet. What is the current that would be carried through the body, in milliAmperes, if you touched a 240 V power line while dry? Currents over 10 mA are almost always deadly.
1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.
2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.
3. The cost of electricity from the automobile battery is 38.6 cents per kWh.
4. The current that would be carried through the body is 0.8 mA if dry.
1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.
Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.
2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.
Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.
3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.
Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.
4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.
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Short, difficult activities that push your body are called
A.
aerobic activity
B.
anaerobic activity
C.
muscle strength
D.
exercise
Answer:
B. is your answer
Explanation:
Have a good day
Sincerly, lipor
Short, difficult activities that push your body are called anaerobic activities. Option b is correct
They are high-intensity exercises that do not require oxygen and primarily use stored energy sources within the muscles. Examples include weightlifting or sprinting.
Short, difficult activities that push your body are called anaerobic activity. Anaerobic activities are high-intensity exercises that do not require oxygen and primarily use stored energy sources within the muscles, such as weightlifting or sprinting. These activities help build muscle strength and improve power and speed.
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Propose two reliable ways of separating the nails from the
sawdust
Answer:
-Use of magnet
-Mixing in water
Explanation:
Two ways are;
1) Use of magnet: Nails are made of steel and thus can be attracted by magnets. So when a magnet is put inside the mixture, it attracts the magnet out.
2) Mixing it in water: When it is put in water, the nails will go to the bottom while the saw dust will float on the water.
26.If a substance with a high specific heat is heated, its temperature will...Select one:a. change quickly.b. change slowly.c. remain the same.d. change quickly, then change slowly.
b. change slowly.
A higher specific heat means it requires more energy to change one degree of one gram o mass.
(a) The roof of a large arena, with a weight of 290 kN, is lifted by 30 cm so that it can be centered. How much work is done on the roof by the forces making the lift? (b) In 1960 a Tampa, Florida, mother reportedly raised one end of a car that had fallen onto her son when a jack failed. If her panic lift effectively raised 4000 N (about 1/4 of the car's weight) by 5 cm, how much work did her force do on the car?
Answer:
87000 J ;
200 J
Explanation:
Workdone = mgh
Weight = mg = 290kN = 290 * 1000=290000 N
h = distance = 30 cm = 0.3 m
Workdone = 290000 * 0.3
Workdone = 87000 J
B.)
Workdone = Force * distance
Force = 4000 N
Distance, d = 5 cm = 0.05 m
Workdone by the woman, W = 4000N * 0.05m
W = 200Nm = 200 J
3. A 1.23 kg object slides down a 1.25 m incline of 35º. Use the data table to construct a graph for force due to gravity vs. distance. Trial 1 Trial 2 Trial 3 Averages Distance (m) 1.25 1.32 1.28
4. Based on the graph in #3, calculate the work done by gravity. Assume work is constant for this data.
5. Using the data from #3, construct a free body diagram and calculate work done by gravity. Explain how this value compare to the value determined graphically in #4.
Remember that this object is on an angle. You'll need to multiply the value for work by cos0
Keep in mind that you'll need to use the angle that forms between the force of gravity and distance.
Answer:
Explanation:
To construct a graph of force due to gravity vs. distance, we need to collect data for force due to gravity (Fg) and distance (d) and plot the data points on a graph. From the information given, we have the mass of the object (1.23 kg) and the angle of the incline (35º), but we do not have any data for force due to gravity or distance. Without this data, it is not possible to construct a graph for force due to gravity vs. distance.
Since we don't have the data for force due to gravity or distance, it's not possible to calculate the work done by gravity using the data table.
Without the data for force due to gravity, distance, or time it's not possible to construct a free-body diagram or calculate work done by gravity. Also, we don't have the angle of the incline, so we cannot calculate the work done by gravity by multiplying it by the cosine of the angle.
It's important to note that work done by gravity (W) = force due to gravity (Fg) x distance (d) x cos(theta), where theta is the angle between the force of gravity and the distance.
It's also important to remember that work is a scalar quantity and not a vector, and it's the angle between the force and the displacement that is important to calculate the work done by gravity, not the angle of the incline.
Friction _____
the motion of an
object.
A. opposes
B. does typt affect
C. increases
D. speeds up
You drive your car 2 km to the gas station, 4 km to the shopping mall to let your mother off, and 4.5 km back home. The trip takes 20
min.
What is your VELOCITY in m/s?
0m/s
-9 m/s
-3 m/s
+4 m/s
Answer:
+4m/s
Explanation:
You drive your car 2 km to the gas station, 4 km to the shopping mall to let your mother off, and 4.5 km back home. The trip takes 20 min, then velocity is 4 m/s.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.
Given in the question you drive your car 2 km to the gas station, 4 km to the shopping mall to let your mother off, and 4.5 km back home. The trip takes 20 min.
The velocity in m/sec is given as 4 m/s.
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A long straight wire carrying a current of 3A flowing in a direction parallel to the unit vector 1 (i+j+ k) is placed in a √√3 --↑ this is the a magnetic field of (0.75i + 0.4k)T. What is the magnetic force per unit length of the wire? A. (0.69i-0.61j - 1.3k )N/m.. B. (0.39i-0.4j-2.3 k )N/m C.(0.49i-0.51j - 1.37k )N/m D. (0.59-0.71j-0.13k )N/m
The magnetic force per unit length of the wire is (C) (0.49i - 0.51j - 1.37k) N/m.
To calculate the magnetic force per unit length of the wire, we can use the formula:
F = I * (L x B),
where F is the force, I is the current, L is the length vector of the wire, and B is the magnetic field.
Given:
Current, I = 3A
Length vector, L = √√3 * (i + j + k)
Magnetic field, B = 0.75i + 0.4k
Let's calculate the cross product of L and B:
L x B = | i j k |
|√√3 √√3 √√3|
|0.75 0 0.4|
To evaluate this cross product, we calculate the determinants:
(i) component: (√√3 * 0 - √√3 * 0.4) = -0.4√√3
(j) component: (-√√3 * 0.75 - √√3 * 0) = -0.75√√3
(k) component: (√√3 * 0.75 - √√3 * 0) = 0.75√√3
Now, multiply the cross product by the current:
F = 3A * (-0.4√√3i - 0.75√√3j + 0.75√√3k)
Simplifying this expression gives:
F = (-1.2√√3i - 2.25√√3j + 2.25√√3k) N
Therefore, the magnetic force per unit length of the wire is approximately (-1.2√√3i - 2.25√√3j + 2.25√√3k) N/m.
Comparing the given answer options, the closest match is C. (0.49i - 0.51j - 1.37k) N/m.
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You are designing a hydraulic lift for a machine shop. The average mass of a car it needs to lift is about 1500 kg. You wish to exert a force on a smaller piston of not more than 550N .a) What should be the specifications on the dimensions of the pistons?Asmall piston/Alarge piston = ???b) How far down will you need to push the piston in order to lift the car 50cm ?h = ???
Answer:
(a) Area(small piston)/Area(large piston) = 0.037
(b) h = 1336.36 cm = 13.36 m
Explanation:
(a)
The stress on the smaller piston is equally transmitted to the larger piston, in a hydraulic lift. Therefore,
Stress (small piston) = Stress (large piston)
Force (small piston)/Area (small piston) = Force (Large Piston)/Area (Large Piston)
Area(small piston)/Area(large piston) = Force (small piston)/Force(Large piston)
Area(small piston)/Area(large piston) = 550 N/(1500 kg)(9.8 m/s²)
Area(small piston)/Area(large piston) = 0.037
(b)
The work is also transmitted equally to the large piston. So,
Work(small piston) = Work(Large Piston)
Force(small piston).Displacement(small piston) = Force(large piston).Displacement(small piston)
(550 N)(h) = (1500 kg)(9.8 m/s²)(50 cm)
h = 735000 N.cm/550 N
h = 1336.36 cm = 13.36 m
(a) The ratio of area smaller piston to area of larger piston is 0.037.
(b) The distance the smaller piston will be pushed down to lift the car at the given height is 13.36 m.
The given parameters;
mass of the car, m = 1500 kgforce on the smaller piston, F₁ = 550 Nlet the area of the small piston = A₁
let the area of the large piston = A₂
Apply constant pressure principle as shown below;
\(P = \frac{F_1}{A_1} = \frac{F_2}{A_2} \\\\\frac{A_1}{A_2} = \frac{A_{small}}{A_{large}} = \frac{F_1}{F_2} = \frac{550}{mg} \\\\ \frac{A_{small}}{A_{large}} = \frac{550}{1500 \times 9.8} \\\\ \frac{A_{small}}{A_{large}} = 0.037\)
The height the car was raised = 50 cm = 0.5 mThe distance the effort will be applied is calculated as follows;
\(550 d = mgh\\\\550d = (1500 \times 9.8 \times 0.5)\\\\550 d = 7350\\\\d = \frac{7350}{550} \\\\d = 13.36 \ m\)
Thus, the distance the smaller piston will be pushed down to lift the car at the given height is 13.36 m.
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static electricity is caused by moving electrical charges? true or false
The given statement "static electricity is caused by moving electrical charges" is false.
Static electricity is not caused by moving electrical charges but by stationary charges. When an object builds up a static electric charge, it has an excess of electrons or a deficiency of electrons.
The charge is stationary and does not move through the object like in a current.The imbalance of charge occurs when there is friction between two surfaces, which can be two objects or an object and the ground. Electrons move from one object to the other, creating a static electric charge on each object.
The amount of charge depends on the types of materials involved, the humidity, temperature, and other factors.Static electricity can be dangerous and cause damage to electrical equipment.
To prevent static electricity, grounding is used. Grounding provides a safe and efficient path for the charge to move through and prevents the buildup of charge on the object.
Static electricity can also be used for useful purposes. Photocopiers and printers use static electricity to transfer ink to paper, and air filters use static electricity to attract and trap pollutants. In industry, static electricity is used to attract and hold materials during the manufacturing process.
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Two divers, G and H, are at depths 20 m and 40 m respectively
below the water surface in lake. The pressure on G is P, while
the pressure on H is P2 if the atmospheric pressure is equivalent
to 10 m of water, then the value of P2/P1 is.
A. 1.67.
B. 2.00.
C. 0.50.
D. 0.60.
Answer:
B
Explanation:
P1/P1 = 40/20
=2
What is revolution?
A. The motion of an object along a curved path
B. The spinning of an object on its axis
C. The orbit of a satellite around a central body
D. The motion of two objects around each other
Answer:
A. the motion of an object along a curved path