In a weighted grading system, students are graded on quizzes, tests, and a project, each with a different weight. Matrix W represents the weights for each kind of work, and matrix G represents the grades for two students, Felipe and Helena.

Q T P

W = [0.40 0.50 0.10] Felipe Helena

G= Q {80 70}
T {60 80}
p { 90 60}

Final grades are represented in a matrix F. If F = WG, what is F?

A. [7174]

B. [7174]

C. [7471]

D. [7471]

By using the Cauchy-Riemann equations on a real-valued function, it can be proven that the function f(z) is constant in the domain D. This is important for understanding analytic functions in complex analysis.

To prove that if f(z) is real-valued for all z in D, then f(z) must be constant throughout D, let a function f be analytic everywhere in a domain D. We know that a real-valued function is said to be a function whose values lie on the real line. In the case of the complex plane, a function whose values lie on the real line is real-valued.

The Cauchy-Riemann equations, which define the necessary conditions for a function f(z) to be analytic in a domain, say that the imaginary component of f(z) is determined by its real component.

To be more precise, if f(z) is real-valued for all z in D, then we can say that:u(x, y) = f(z),v(x, y) = 0

By definition, the Cauchy-Riemann equations can be stated as:

∂u/∂x = ∂v/∂y∂u/∂y = -∂v/∂x

Taking the first equation, we get:

∂u/∂x = ∂v/∂y => ∂v/∂y = 0

Since v is equal to 0 for all values of x and y, the above equation reduces to ∂u/∂x = 0, which implies u is constant with respect to x.

Similarly, taking the second equation, we get:

∂u/∂y = -∂v/∂x => ∂u/∂y = 0

Since u is equal to a constant for all values of x and y, the above equation reduces to ∂v/∂y = 0, which implies v is constant with respect to y. Since u and v are both constant with respect to their respective variables, u + iv = f(z) is a constant with respect to z throughout the domain D. Thus, we have proved that if f(z) is real-valued for all z in D, then f(z) must be constant throughout D.

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y = 40x + 150

The slope intercept form is y = mx + c.

A line with m as its slope, m as its y-intercept, and c as its coefficient makes up the graph of the linear equation y = mx + c. The values of m and c in this version of the linear equation—known as the slope-intercept form—are real numbers.

The steepness of a line is indicated by the slope, m. Sometimes, the term "gradient" is used to refer to the line's slope. The point on a line's graph where it meets the y-axis is designated by the y-coordinate, or b, as the line's y-intercept. The supplied line L's distance c is known as its y-intercept.

Therefore, the coordinate of the point where the line L intersects the y-axis will be (0, c).

As a result, line L has a slope of and passes through the fixed point (0, c).

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Answer:

(A.)

Step-by-step explanation:

Hope it helps :)

Have a good day/night

Brainliest pls?

Answer:

tan A = -15/8.

Step-by-step explanation:

sin^2a = 1 - cos^2A

= 1 - (-8/17)^2

= 225/289

So sin A= 15/17

tan A = sin A / cos A

=  15/17 / -8/17

= 15/-8

= -15/8.

There are 715 ways to select 9 players for the starting lineup.

Permutation is used whenever there is arrangement or where order is important . denoted by \(P(n,r)=\frac{n!}{(n-r)!}\)

n= no of item  , r = no of items to be arranged.

Combination is used when there is selection . denoted by\(C(n,r)=\frac{n!}{r!(n-r)!}\)

n=no of item  , r= no of item to be selected.

Part (a)

In the given question

we have to select 9 players out of 13 player , combination will be used

\(C(13,9)=\frac{13!}{9!*(13-9)!}=\frac{13*12*11*10*9!}{9!*4!} =\frac{13*12*11*10}{4*3*2}\)=715 ways.

Part(b)

In this part we have to find how many ways are there to select 9 players for the starting lineup and a batting order for the 9 starters.

Since the batting order is important , permutation will be used.

\(P(13,9)=\frac{13!}{4!} =\frac{13*12*11*10*9*8*7*6*5*4!}{4!} =13*12*11*10*9*8*7*6*5\)

=259459200 ways.

Part(c)

In this part we have to do selection of  3 left-handed outfielders and have all other 6 positions occupied by right-handed players.

Since order is not important Combination  will be used.

To select 3 left handers from total 6 left handers = C(6,3)

& to select 6 positions of left handers from remaining 7 right handers=C(7,6)

No of ways of selection = C(6,3)*C(7,6)

\(=\frac{6!}{3!*(6-3)!} *\frac{7!}{6!*(7-6)!} \\ \\= \frac{6!}{3!*3!} *\frac{7!}{6!*1!} \\ \\\)

On solving further we get

\(= \frac{7!}{3!*3!} =\frac{7*6*5*4*3!}{3!*3*2*1} =7*5*4=140ways\)

Therefore ,(a)There are 715 ways to select 9 players for the starting lineup.

(b) there are 259459200 ways to to select 9 players for the starting lineup and a batting order for the 9 starters and 140 ways .

(c)there are 140 ways to select 3 left-handed outfielders and have all other 6 positions occupied by right-handed players.

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Answer:A. Ink/In5

Step-by-step explanation:

Answer:

Step-by-step explanation:

c is correct

Answer:

ehdjdiewiejfndnekeocodkrnenrkckfoeke

For the answer of factors of expression (12 + 54), in the form of a(b + c), where a is the GCF of 12 and 54 is equals to 6( 2 + 9).

In math, to factor a number means to express it as a product of (other) whole numbers, called its factors. For example, if 7x5 = 35, 7 and 5 are both factors. The divisors that give the remainder to be 0 are the factors of the number. We have an expression of numbers, 12 + 54. We have to write this expression in form of a( b + c), where a is GCF of 12 and 54. Now, we can write the factors of 12 and 54 are 12 = 2×2×3

54 = 2×3 ×3×3

The greatest common factor, GCF of 12 and 54 is 2×3 = 6. So, 12 + 54 = 6× 2 + 6×9

Taking out the common factor 6 from above expression, 6( 2 + 9) which is required form a( b + c). Hence, required expression is 6( 2 + 9).

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Based on your question, it sounds like you are asking about random variables that have a joint probability density function (PDF) of 1/50 over a certain range of values.

In probability theory, a random variable is a variable whose value is determined by chance. It can take on a range of possible values, and the probabilities of each possible value occurring can be described using a probability distribution.

A joint probability density function is a function that describes the probabilities of two or more random variables taking on specific values simultaneously. In your case, you have two random variables that have a joint PDF of 1/50.

Without knowing the specific range of values over which the PDF is defined, it's hard to provide a more detailed answer. However, here are a few general observations about random variables and joint PDFs:

- Random variables can be either discrete or continuous. Discrete random variables take on specific, countable values (e.g. the number of heads in a series of coin tosses), while continuous random variables can take on any value within a certain range (e.g. the height of a randomly selected person).
- A joint PDF is typically used to describe the behavior of two or more continuous random variables. It gives the probability density at each point in the two-dimensional space defined by the values of the two variables.
- The total probability over the entire range of values for a joint PDF must sum to 1. This ensures that the probability of all possible outcomes occurring is equal to 1.

I hope this helps! If you have any further questions or clarifications, please let me know.
It seems that you are asking about random variables with a joint probability density function (pdf) of 1/50. Random variables are quantities that can take on different values according to some probability distribution. When two or more random variables are considered together, their relationship can be described using a joint pdf. In this case, the joint pdf is 1/50, indicating that the probability of a specific combination of these random variables is 1/50.

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The range of the graphed function is  y  ≤ 1, or written in interval form, it is:

(-∞, 1]

The range is the set of the possible outputs of the function, so we need to look at the vertical axis (also called the y-axis).

Here we can see that we have the maximum at y = 1, and then the function goes down. (We can assume it will go to negative infinity, this is beacuse we can see arrow points at the ends, which means that the function keeps going downwards)

Then the range is:

y  ≤ 1

Or (-∞, 1] in interval form.

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Answer:

IM BOUT TO SOLVE

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

Applying the definition of the diagonals of an isosceles trapezoid, the value of x is: C. 13.

An isosceles trapezoid has two congruent legs and two diagonals that are congruent.

Given:

Thus:

SD = LG

Substitute

8x - 5 = 6x + 21

Combine like terms and find x

8x - 6x = 5 + 21

2x = 26

x = 26/2

x = 13

Thus, applying the definition of the diagonals of an isosceles trapezoid, the value of x is: C. 13.

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Answer: Negative linear

Step-by-step explanation: Points are going downwards and you can use a line of best fit.

The quadratic function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).

In this question we have a graph of a quadratic equation translated to another place of a Cartesian plane, whose form coincides with the vertex form of the equation of the parabola, whose form is:

g(x) = C · (x - h)² - k     (1)

Where:

By direct comparison we notice that (h, k) = (5, 1) and C = 1. Now we proceed to check if the points (x, y) = (2, 10) and (x, y) = (8, 10) belong to the parabola.

x = 2

g(2) = (2 - 5)² + 1

g(2) = 10

x = 8

g(8) = (8 - 5)² + 1

g(8) = 10

The quadratic function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).

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Answer: B

Step-by-step explanation:

looked at the points from the dude above, or below, anyway i hope this helps

Answer:

on writing in expanded form we get

9167.364 = 9000 + 100 + 60 + 7 + 0.3 + 0.06 + 0.004

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Step-by-step explanation:

Use COS method (Cos Angle = adjacent/hypotenuse)

given adjacent = 14 ft

hypotenuse = 67 ft

\( \cos(x) = \frac{adjacent}{hypotenuse} \\ \cos(x) = \frac{14}{67} \\ x = {cos}^{ - 1} ( \frac{14}{67} ) \\ = 78 \: deg(nearest \: degree)\)

The common difference is 11. The number of terms in the AP is 9, and the common difference between the terms is 11.

The number of terms in the arithmetic progression (AP) can be found by using the formula:

Number of terms (n) = (Last term - First term) / Common difference + 1.

Given that the first term (a₁) is 1 and the last term (aₙ) is 121, we can substitute these values into the formula:

n = (121 - 1) / Common difference + 1.

To find the common difference, we need additional information. Let's proceed by using the sum of the AP's terms.

The sum of the terms in an AP can be calculated using the formula:

Sum (S) = (n/2) * (First term + Last term).

Given that the sum of the terms is 549, we can substitute the values into the formula:

549 = (n/2) * (1 + 121).

Simplifying the equation:

549 = (n/2) * 122.

Dividing both sides by 122:

4.5 = n/2.

Multiplying both sides by 2:

9 = n.

Therefore, the number of terms in the AP is 9.

To find the common difference, we can use the second sum given, which is 671.

671 = (9/2) * (1 + 121).

Simplifying the equation:

671 = (9/2) * 122.

Dividing both sides by 122:

5.5 = (9/2).

Multiplying both sides by 2:

11 = 9.

Therefore, the common difference is 11.

In summary, the number of terms in the AP is 9, and the common difference between the terms is 11.

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We are given two rational expressions: one with (y² - 13y + 36) in the numerator and (y² + 2y – 3) in the denominator, and the other with (y² - y – 12) in the numerator and (y² - 2y + 1) in the denominator. We need to simplify these rational expressions.

Simplifying the first rational expression:
The numerator of the first expression, y² - 13y + 36, can be factored as (y – 4)(y – 9).
The denominator, y² + 2y – 3, can be factored as (y + 3)(y – 1).
Therefore, the first rational expression simplifies to (y – 4)(y – 9) / (y + 3)(y – 1).

Simplifying the second rational expression:
The numerator of the second expression, y² - y – 12, can be factored as (y – 4)(y + 3).
The denominator, y² - 2y + 1, can be factored as (y – 1)(y – 1) or (y – 1)².
Therefore, the second rational expression simplifies to (y – 4)(y + 3) / (y – 1)².

By factoring the numerator and denominator of each rational expression, we obtain the simplified forms:

First rational expression: (y – 4)(y – 9) / (y + 3)(y – 1)
Second rational expression: (y – 4)(y + 3) / (y – 1)²

These simplified expressions are in their simplest form, with no common factors in the numerator and denominator that can be further canceled.


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Answer:

1) n=±2\(\sqrt{5}\)

2) a=±3\(\sqrt{10}\)

Step-by-step explanation:

1) \(n^{2}\) =20

✰Take the square root of both sides n=±\(\sqrt{20\\}\)

✰ Simplify \(\sqrt{20\\}\) to 2\(\sqrt{5}\)

→ n=±2\(\sqrt{5}\)  

⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆

2) \(a^{2}\) =90

✰ (Same as above) Take the square root of both sides ​a=±\(\sqrt{90\\}\)

✰ Simplify \(\sqrt{90}\) to 3\(\sqrt{10}\)

→ a=±3\(\sqrt{10}\)

Using translation concepts, the correct values are given as follows:

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

Researching this problem on the internet, we have that:

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There are 5 full square and 6 triangles that are half squares.

      5 + (6)(1/2) = 5 + 3 = 8

You could also break this into smaller shapes (like a big triangle on the top and a smaller triangle and rectangle on the bottom and use area formulas to calculate the area.  But counting works well in this example.

Answer: 8

Step-by-step explanation:

First you split up this shape into two different shapes, a triangle and trapezoid

Put a line through the coordinates (-2,2) to  (-1,2); the top is a triangle and the other is a trapezoid

Area of the trapezoid is A = .5x (base1 + base2) x height

base1 of the trapezoid goes from -4 to -1 which is 3

base2 goes from -2 to -1 which is 1

height is 0 to 2 whcich is 2

A = .5 x (3+1) x 2 = 4

Now area of a triangle is A = .5 x base x height

the base goes from -2 to 2 which is 4

the height goes from 2 to 4 which is 2

A = .5 x (4) x (2) = 4

Area of the Trapezoid + Area of the Triangle = Total Area

4 + 4 = 8

Answer:

62

Step-by-step explanation:

2+20+30+10=62

A

cause u get

h is less than or equal to 12 so 12, 14 and 16

this means that h is only equal to 12 but can be of a value that is higher too

sorry delete this please i did it and im  wrong and

Answer:

g(x)=\(-2x^{2}\)+1

Step-by-step explanation:

Answer:

g(x) = (x +2)² + 1

Step-by-step explanation:

original function is moved 2 units to the left and 1 unit up so

g(x) = (x-(-2))²+1

g(x) = (x +2)² + 1

Solution

Hence the answer is option D

Answer:

A solution means any variable that makes the equation true

use sin

sin(50) = x/6

sin(50) x 6 = x

x = ~4.5963