In a physics lab, you attach a 0.200-kg air-track glider tothe end of an ideal spring of negligible mass and start itoscillating. The elapsed time from when the glider first movesthrough the equilibrium point to the second time it moves throughthat point is 2.60 s.
Find the spring's force constant.
Thanks so much in advance.

Answer:

thats a force

Explanation:

Answer:

force

Explanation:

the definition of a push or pull is force

Answer: The answer is True

Space has tremendous distances. The everyday measurement units we use are far too tiny to measure in distance without adding a lot of zeros. 150,000 kilometres approximately.

Distance is an object's overall movement, independent of direction. Regardless of an object's beginning or finishing position, distance may be defined as the amount of ground it has travelled.

A point designating the end of a phase or step of a process, particularly: the point in a calibration at which a clear impact (such a change in color) is noticed.expanse of space is enormous. Our everyday units of measurement are considerably too tiny to accurately distance objects in space without using a lot of zeros. It's almost 150,000 kilometers away.

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Answer:

The name of the highly Electropositive element goes first.

e.g

\(Cl_{2}O \: = > \: dichloride \: oxide\)

Chlorine is more Electropositive than Oxygen.

e.g

\(NO_{2} \: = > \: nitrogen \: dioxide\)

Nitrogen is more Electropositive than Oxygen

Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density of n = 910 wires/m and current per wire of IL = 0.14 A in the +zdirection.

The right-hand sheet, which intersects the x-axis at x = a = 12 cm, is identical to the left-hand sheet, except that it has a current per wire of IR = 0.14 A in the -z-direction.

(a) Calculate the y-components of the net magnetic field in the following places:

x1 = -15 cm, x2 =6 cm, and x3 = 24 cm. (The x- and z-components of the B-field are zero.)

B(x1)y = T

B(x2)y = T

B(x3)y = T

Please check the attached file for a detailed answer.

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Since Intensity depends on power and area, star b will have the same brightness as star a but look smaller

Luminous Intensity is the magnitude or quantity of the brightness of light emitted by a luminous object.

If two stars have the same luminosity, but star b is three times farther away from us than star a. If we are to compare star a with star b, star b will look bright but small.

The reason is due to the fact that Intensity is directly proportional to power and inversely proportional to area and not to the distance or length.

Therefore, star b will look bright but small.

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Explanation:

improved saftey for children

Answer:

D. Improved safety for children

Explanation:

Answer:

https://earthobservatory.nasa.gov/features/EnergyBalance#:~:text=The%20atmosphere%20absorbs%2023%20percent,surface%20radiates%20only%2012%20percent.

Explanation:

A heat engine does 20 J of work while exhausting 30 J of waste heat. We have to find the engine's efficiency.

To calculate the engine's efficiency, we should consider the work done by the engine, the waste heat, and the total heat input. The heat engine does 20 J of work and exhausts 30 J of waste heat.Hence the total heat input is (20 J + 30 J = 50 J). Now, efficiency is the ratio of work done to the total heat input. So, efficiency = (work done / total heat input) × 100%.

Plugging in the values:

Efficiency = (20 J / 50 J) × 100% = 0.4 × 100% = 40%

The engine's efficiency is 40%.

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Answer:

Wrong answer

Explanation:

Answer:

1. motion, motion, rest, rest

2. law of motion

3 f=m×a

4. for every action there is an equal and opposite reaction.

The weight of the combined system is 58,800 N.

To determine the weight of the combined system, we need to consider the weight of the plastic tank and the weight of the water it contains.

Step 1: Weight of the Plastic Tank

The weight of an object is given by the equation W = m ×  g, where W is the weight, m is the mass, and g is the acceleration due to gravity. Since the mass of the plastic tank is 6 kg, and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the weight of the tank as follows:

W_tank = 6 kg ×  9.8 m/s² = 58.8 N

Step 2: Weight of the Water

The weight of the water is determined by its mass and the acceleration due to gravity. The density of water is given as 1000 kg/m³, and the volume of the tank is 0.18 m³. We can calculate the mass of the water using the equation m = density * volume:

m_water = 1000 kg/m³ × 0.18 m³ = 180 kg

Now, we can calculate the weight of the water:

W_water = 180 kg × 9.8 m/s² = 1764 N

Step 3: Weight of the Combined System

To find the weight of the combined system, we sum the weights of the tank and the water:

W_combined = W_tank + W_water = 58.8 N + 1764 N = 1822.8 N

Therefore, the weight of the combined system, consisting of the 6-kg plastic tank filled with water, is 1822.8 N.

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Answer:

no change

Explanation:

The Newton's Second Law of motion states that when an unbalanced force is applied to an object, it causes an accelerated motion in the object, in the direction of the unbalanced force. So, if there is no unbalanced force, then there is no motion. In this case both the forces have same magnitude and opposite direction. Therefore, the unbalanced force will be zero:

Unbalanced Force = Upthrust - Weight

Unbalanced Force = 2448 N - 2448 N

Unbalanced Force = 0 N

hence, there will be no motion in the vertical direction. Therefore, the correct option is:

no change

Answer:

9 km/h

Explanation:

Speed can be found using the following formula.

s=d/t

where d is distance and t is time.

The car traveled 45 kilometers in 5 hours.

d=45 km

t=5 h

Substitute these values into the formula

s=45 km/5 h

Divide 45 by 5

s=9 km/h

The average speed of the car is 9 kilometers per hour.

Answer:

4.978 m

Explanation:

\(\mathsf v_x\) , the x-component of a vector is given by \(\boldsymbol v\cos\theta\) where \(\theta\) is the angle formed by the vector with the x-axis. The sign of the x-component depends on which quadrant the vector is

Here \(\theta = 77.1\)°

\(\cost\theta = \cos(77.1) = 0.22325\)

The vector has magnitude of 22.3 m

So the x-component = 22.3 x 0.22325 = 4.978 m

The total kinetic energy of the wheel is 18 Joules.

The total kinetic energy of the wheel can be calculated using the formula:

K = (1/2)mv^2

where m is the mass of the wheel and v is its velocity.

In this case, the mass of the wheel is given as 1.0 kg and the velocity is 6.0 m/s.

Plugging these values into the formula, we get:

K = (1/2)(1.0 kg)(6.0 m/s)^2 = 18 J

Therefore, the total kinetic energy of the wheel is 18 Joules.

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The final velocity of the girl after the collision is determined as -4.8 m/s.

The final velocity of the girl is determined from the principle of conservation of linear momentum.

m1u1 + m2u2 = m1v1 + m2v2

50(0) + 80(0) = 50(v1) + 80(3)

0 = 50v1 + 240

50v1 = -240

v1 = -240/50

v1 = -4.8 m/s

Thus, the final velocity of the girl after the collision is determined as -4.8 m/s.

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Answer:

W = 76 N

Explanation:

In this exercise you are asked to find the weight of the body.

Mass is a quantity that is invariant, it measures the same everywhere, the weight depends on where it is measured, a simple way to find the weight of a body is

          W = g m

where g is the constant of the place, in this case we have the weight of the body on Mars and its mass which is constant on Earth and on Mars

            W = 3.8 20

            W = 76 N

Answer:

Option A. 500

Explanation:

From the question given, we obtained the following:

Numbers of home with pet dogs = 250

Percentage with pet dogs = 50%

Total number of homes =.?

Thus, we can obtain the total number of homes represented by the chart as follow:

Let T be the total number of Homes.

Number of homes with dog = percentage of homes with dog × total number

Numbers of home with pet dogs = 250

Percentage with pet dogs = 50%

Total number of homes = T

250 = 50% × T

Divide both side by 50%

T = 250 ÷ 50%

T = 250 ÷ 50/100

T = 250 × 100/50

T = 250 × 2

T = 500

Therefore, the total number of homes represented by the chart is 500.

Answer:

516m/s^2

Explanation:

Given the following :

Height of aircraft = 10000m

Acceleration due to gravity (g) = 10m/s^2

Angle of projection (θ) = 60°

Height of aircraft = maximum height

Maximum height of a projectile:

H = (u^2sin^2θ) / 2g

Where H = height

u = initial velocity

10000 = [(usinθ)^2] / 2g

10000 = [(u * sin60°) ^2] / 2*10

10000 = (0.866 * u)^2 / 20

20 * 10000 = 0.749956 * u^2

200000 = 0.749956u^2

u^2 = (200000/0.749956)

u^2 = 266,682.31

u = √266,682.31

u = 516.41292

Initial velocity (u) = 516m/s^2

Considering the table the acceleration is 2.72 Km/hr

Acceleration is defined as the rate of change of velocity with respect to time.

This means that if an object's velocity changes by a certain amount over a certain period of time, then the object is said to have experienced acceleration during that time.

The formula is

= Final velocity - initial velocity / time taken

plugging in the values

= (65 - 60) / (11:55 - 10:05)

= 5 / 1:50

converting 50 minutes to hour = 50 / 60

= 5 / 1 50/60

= 2 6/11

= 2.72 Km/hr

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(a) The required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) The required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) The average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant acceleration, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) The total length of the track is approximately 5.28 kilometers.

(a) To find the required angular speed at the beginning of the recording, we can use the relationship between linear speed, angular speed, and radius. The linear speed is given as 1.30 m/s, and the radius is 2.30 cm (or 0.023 m). The formula to relate these quantities is:

Linear Speed = Angular Speed * Radius

Solving for angular speed:

Angular Speed = Linear Speed / Radius

Plugging in the given values:

Angular Speed = 1.30 m/s / 0.023 m

Angular Speed ≈ 56.52 radians/second

Therefore, the required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) Similarly, to find the required angular speed at the end of the recording, we use the same formula and plug in the linear speed of 1.30 m/s and the radius of 5.80 cm (or 0.058 m):

Angular Speed = 1.30 m/s / 0.058 m

Angular Speed ≈ 22.41 radians/second

Therefore, the required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) To find the average angular acceleration, we can use the formula:

Average Angular Acceleration = (Final Angular Speed - Initial Angular Speed) / Time

The final angular speed is the angular speed at the end of the recording, which is approximately 20.95 radians per second. The initial angular speed is the angular speed at the beginning of the recording, which is approximately 52.38 radians per second. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Average Angular Acceleration = (20.95 radians/second - 52.38 radians/second) / 4473 seconds

Average Angular Acceleration ≈ -0.000286 radians/second squared

Therefore, the average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant angular acceleration, we can use the formula to find the angular displacement:

Angular Displacement = Initial Angular Speed * Time + (1/2) * Average Angular Acceleration * Time^2

The initial angular speed is approximately 52.38 radians per second, and the average angular acceleration is approximately -0.000286 radians per second squared. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Angular Displacement = 52.38 radians/second * 4473 seconds + (1/2) * -0.000286 radians/second squared * (4473 seconds)^2

Angular Displacement ≈ -0.343 radians

Therefore, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) To find the total length of the track, we need to calculate the arc length of each bit and sum them up. Each bit occupies 0.6 mm of the track, which is equivalent to 0.0006 m.

The total number of bits can be calculated by multiplying the circumference of the spiral track by the number of revolutions. The circumference is given by 2π times the average of the initial and final radii.

Circumference = 2π * (2.30 cm + 5.80 cm) / 2

Circumference ≈ 27.77 cm

Converting the circumference to meters:

Circumference = 27.77 cm * 0.01 m/cm

Circumference ≈ 0.2777 m

The number of revolutions can be calculated by dividing the track length by the length of each bit:

Number of Revolutions = Track Length / Length of Each Bit

Number of Revolutions = 0.2777 m / 0.0006 m

Number of Revolutions ≈ 462.83 revolutions

Finally, we can calculate the total length of the track:

Total Length of the Track = Number of Revolutions * Circumference

Total Length of the Track ≈ 462.83 revolutions * 0.2777 m/revolution

Total Length of the Track ≈ 128.53 m

Therefore, the total length of the track is approximately 5.28 kilometers (or 5280 meters).

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the answer for 0.429m to mm is 429

Answer:

0.429m=429 mm

Explanation:

Since there are 1,000 millimeters per meter, you need to multiply by 1,000 to convert from meters to millimeters.

It will take about 11.8 days for the water to boil.

The first step is to find the decay constant (λ) of the radium isotope using the half-life equation:

t1/2 = 0.693/λ

where t1/2 is the half-life.

So, rearranging the equation, we get:

λ = 0.693/t1/2

  = 0.693/11.43 days

  = 0.0605 day⁻¹

Next, we need to calculate the number of radium atoms in the 1.0 g cube using Avogadro's number and the molar mass of 223Ra:

Number of atoms \(= (1.0 g)/(223 g/mol) * (6.022 * 10^{23} atoms/mol)\)

                             = 2.7 x 10²⁰ atoms

Since each radium atom emits an alpha particle during decay, we can calculate the activity of the radium sample:

Activity = (2.7 x 10²⁰ atoms) x (1 decay/atom) x (1 alpha particle/decay)

             = 2.7 x 10²⁰ alpha particles per second

Now, we need to calculate the energy released per alpha particle. The energy (E) released per alpha particle can be calculated using the equation:

E = (Q/m) x Na

where

Q is the energy released per decay,

m is the mass of the radionuclide per decay, and

Na is Avogadro's number.

For 223Ra,

Q = 5.69 MeV,

m = 223/2 = 111.5 g/mol, and

Na = 6.022 x 10^23 atoms/mol.

Therefore,

E = (5.69 MeV/decay)/(111.5 g/mol) x (6.022 x 10²³ atoms/mol)

   = 3.84 x 10⁻¹³ J/alpha particle

Finally, we can calculate the rate of energy transfer to the water by multiplying the activity of the radium sample by the energy released per alpha particle:

Rate of energy transfer = (2.7 x 10²⁰ alpha particles/s) x (3.84 x 10⁻¹³ J/alpha particle)

                                      = 1.04 W

To boil the water, we need to transfer enough energy to raise its temperature from 16°C to 100°C and to vaporize it.

The specific heat capacity of water is 4.18 J/g°C, and the heat of vaporization of water is 40.7 kJ/mol, or 2257 J/g. The mass of the water is 460 g, so the total energy required is:

Energy required = (460 g) x (4.18 J/g°C) x (100°C - 16°C) + (460 g) x (2257 J/g)  

                            = 1.06 x 10⁶ J

Finally, we can calculate the time required to transfer this amount of energy to the water using the formula:

Energy transferred = Rate of energy transfer x time

Solving for time, we get:

time = Energy required/Rate of energy transfer

       = (1.06 x 10⁶ J)/(1.04 W)

       = 1.02 x 10⁶ s

       = 11.8 days

Therefore, it will take about 11.8 days for the water to boil.

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Answer:

NO

Explanation:

if it has no acceleration then it's not moving

Answer:

Yes when the velocity is constant then the acceleration is said to be zero. Thus an object with 0 acceleration can be in motion.

Let me give you an example to make you more clear

Example:

When  a car is  traveling at a constant 90 km/h in a straight line has nonzero velocity and zero acceleration.

As the temperature increases, the solar cell's ability to supply power to the batteries may decrease due to a phenomenon known as the temperature coefficient. This coefficient represents the change in the solar cell's voltage and current output with temperature fluctuations. In general, the temperature coefficient of solar cells is negative, meaning that as temperature rises, the output voltage and current decrease. This is due to the increase in electron-hole recombination rates and internal resistance of the solar cell at higher temperatures, leading to a decrease in efficiency. However, some solar cells have a positive temperature coefficient, meaning their output voltage and current increase with rising temperature. These cells are typically made of different materials and have unique properties that make them better suited for high-temperature environments.

As temperature increases, the solar cells' ability to supply power to the batteries is affected due to changes in the cells' efficiency and performance. Higher temperatures can cause the solar cells to experience a decrease in their efficiency, known as the temperature coefficient.

This is because, as temperature rises, the semiconductor materials in the solar cells become more conductive, leading to an increase in internal resistance and a drop in voltage output. Consequently, the power output from the solar cells to the batteries is reduced, resulting in less energy being stored in the batteries.

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The way that Q and W are related during the isobaric part of the overall path is that W provides energy output, while Q provides energy input; Q is larger. Option A.

A thermodynamic process called an isobaric process keeps the pressure constant. This is typically accomplished by allowing the volume to alter in size in order to balance off any pressure changes brought on by heat transfer.

Vb > Vd

W tends towards the positive. This is the energy output of the system. The pressure is constant so Q is energy input. Hence the first option is the correct one

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Question

how are q and w related during the isobaric part of the overall path from state d to state b?

1. W provides energy output, while Q provides energy input; Q is larger

2. Both W and Q provide energy input

Answer:

When a branch of a tree is shaken, some of the fruits may fall down. Why? Solution : The fruits fall down due to inertia of rest.

Answer:

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