In a packed absorption column, hydrogen sulphide (H2S) is removed from natural gas by dissolution in an amine solvent. At a given location in the packed column, the mole fraction of H2S in the bulk of the liquid is 6 × 10−3 , the mole fraction of H2S in the bulk of the gas is 2 × 10−2 , and the molar flux of H2S across the gas-liquid interface is 1× 10−5 mol s -1 m-2 . The system can be considered dilute and is well approximated by the equilibrium relationship, y ∗ = 5x ∗ .
a) Find the overall mass-transfer coefficients based on the gas-phase, K, and based on the liquid phase, K.
b) It is also known that the ratio of the film mass-transfer coefficients is = 4. Determine the mole fractions of H2S at the interface, both in the liquid and in the gas.
c) In another absorption column with a superior packing material there is a location with the same bulk mole fractions as stated above. The molar flux has a higher value of 3 × 10−5 mol s -1 m-2 . The ratio of film mass-transfer coefficients remains, = 4. The same equilibrium relationship also applies. Explain how you would expect the overall mass-transfer coefficients and the interfacial mole fractions to compare to those calculated in parts a) and b).
d) In the previous parts of this problem you have considered the thin-film model of diffusion across a gas-liquid interface. Explain what you would expect to be the ratio of the widths of the thin-films in the gas and liquid phases for this system if the diffusion coefficient is 105 times higher in the gas than in the liquid, but the overall molar concentration is 103 times higher in the liquid than in the gas.
Answers
a) The overall mass transfer coefficient based on the gas phase, kG is given by;
\(kG = y*1 - yG / (yi - y*)\)
And, the overall mass transfer coefficient based on the liquid phase, kL is given by;
\(kL = x*1 - xL / (xi - x*)\)
Here,\(yi, y*, yG, xi, x*, x\)
L are the mole fractions of H2S in the bulk of the gas phase, in equilibrium with the liquid phase, and in the bulk of the liquid phase, respectively.x*
\(= 6 × 10−3y* = 5x*y* = 5 * 6 × 10−3 = 3 × 10−2yG = 2 × 10−2yi\)
\((3 × 10−2)(1 - 2 × 10−2) / (-1 × 10−2)= 6 × 10−4 m/skL = x*1 - xL /\)
\((xi - x*)= (6 × 10−3)(1 - xL) / (-24 × 10−3)= 6 × 10−4 m/sb)\)
The ratio of the film mass-transfer coefficients, kf, is given by;
\(kf = kL / kGkf = 4kL = kf × kG = 4 × 6 × 10−4 = 2.4 × 10−3 m/sk\)
\(G = y*1 - yG / (yi - y*)yG = y*1 - (yi - y*)kL = x*1 - xL / (xi - x*)\)
\(xL = x*1 - kL(xi - x*)xL = 6 × 10−3 - (2.4 × 10−3)(-24 × 10−3)xL\)
\(= 5.94 × 10−3yG = y*1 - (yi - y*)kG = y*1 - yG / (yi - y*)yG = 3.16 × 10−2\)
In another absorption column with a superior packing material there is a location with the same bulk mole fractions as stated above. The molar flux has a higher value of 3 × 10−5 mol s -1 m-2. The overall mass transfer coefficient and interfacial mole fractions would be higher than those calculated in parts because a better packing material allows for more surface area for mass transfer.
\(DL = 105DGρL = 103ρGDL / DG = (105) / (1 × 10−3) = 105 × 10³δ\)
\(L / δG = (DL / DG)1/2 (ρG / ρL)1/3= 105 × 1/2 (1 / 103)1/3= 10.5 × 10-1/3= 1.84\)
The ratio of the thickness of the liquid film to that of the gas film is expected to be 1.84.
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Related Questions
A circuit board in an electronics manufacturing process has a 17-hour flow time, on average. Two hours of this time is spent being processed. Twelve hours is spent waiting between resources and the other three hours is spent on setup activities. What is the value-added percentage of the process?
Answers
The value-added percentage of the process is 11.76%.
To calculate the value-added percentage, we need to determine the amount of time spent on value-added activities in relation to the total flow time. In this case, the total flow time is 17 hours.
The value-added time is the time spent on activities that directly contribute to the transformation of the product and add value from the customer's perspective. In this scenario, the value-added time is the two hours spent on processing the circuit board.
Therefore, the value-added percentage can be calculated as (value-added time / total flow time) * 100. Plugging in the values, we get (2 hours / 17 hours) * 100, which equals approximately 11.76%.
This indicates that only a small portion of the total flow time is spent on activities that directly contribute value to the circuit board, while a significant portion is dedicated to non-value-added activities. Identifying and minimizing non-value-added activities is essential for improving efficiency and reducing waste in the manufacturing process.
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TRUE / FALSE .while probabilistic reasoning works well for consonants, it is even more useful for vowels.
Answers
Probabilistic reasoning is not inherently more useful for vowels compared to consonants. The statement is false.
Probabilistic reasoning is a statistical approach used to make inferences and predictions based on probability distributions. It is commonly applied in various fields, including linguistics and speech processing, to analyze and model linguistic phenomena.
However, the usefulness of probabilistic reasoning is not specific to vowels or consonants. Both vowel and consonant sounds can exhibit complex patterns and variations that can be effectively modeled using probabilistic methods.
The choice of applying probabilistic reasoning depends on the specific context and goals of the analysis, rather than the type of phonetic element being considered. Therefore, the statement that probabilistic reasoning is more useful for vowels than consonants is false.
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A yz plane serve as an interface between region 1 and region 2. Region 1 is located x>0 with material whose u=mo, and region 2 is located x<0 with material whose u=240. If 1=10 åxtảy+12ảz A/m and H2=H2xấx-5ãy+4ảz A/m, determine: |(25 points each] (a) H2x (b) The surface current density Ř on the interface
Answers
(a) H2x = 3 A/m(b) Ř = 3π x 10^(-6) A/m. are the results for the given material which has its yz plane serve as an interface between region 1 and region 2.
Given:
Region 1 is located x > 0 with material whose μ = μo and Region 2 is located x < 0 with material whose μ = 240.1 = 10 åxtảy + 12ảz A/mH2 = H2xấx - 5ãy + 4ảz A/m
To Find:
We need to find
(a) H2x
(b) The surface current density Ř on the interface.
(a) H2xWe know,H = B/μFor region 1,μ = μo
Hence, H1 = B/μo........(1)
'For region 2, μ = 240
Hence, H2 = B/240........(2)Given, H2x = -5A/m
From equations (1) and (2),
B = μo H1 = 10 x 10^(-6) x (10 åxtảy + 12ảz) Wbm^(-2)
B = 10^(-5) (10 åxtảy + 12ảz) T
For region 2,B = 240 H2 = 240 x (-5) x 10^(-7) x ẤxB = -0.012T
From equation (2),
Hence, H1x = H2x + M(x)
Now, B = μH= μ(x) H = μoH1 for x > 0 and B = μH= 240 H2 for x < 0
Now, M(x) = Ř(x)/2and Ř(x) = M(x) x 2
Since, the two media are identical, we can apply the boundary condition given by,
H1n1 - H2n2 = Ks
Thus, H1x = H2x + M(x)
On the interface, x = 0,H1x = H2x
Hence, H2x = H1x - M(x)
Putting the values, we get H2x = 3A/m
(b) Surface current density, R
We know, Ř = Kt x H1n1
Using the above equation, we can determine the surface current density Ř.
Now, we know that H1x = H2x + M(x)
Thus, H1n1 = H1x and H2n2 = H2x
So, H1n1 - H2n2 = Ks => Ks = M(0) = 0
Hence, Kt = μoWe know that H1n1 = H1
xHence, Ř = Kt x H1n1= μoH1x
Now, we know
H1x = 3 A/m
μo = 4π x 10^(-7) H/m
Thus, Ř = μoH1x = 3 x 4π x 10^(-7) = 3π x 10^(-6) A/m.
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our system has to operate at high temperatures. according to le chatelier, how could we nevertheless shift the equilibrium towards the product side?
Answers
Le Chatelier's principle helps to predict how the equilibrium position of a reaction would shift in response to any modification in the reaction conditions. The principle predicts that any changes made to a system in equilibrium will cause the system to readjust to the new conditions.
In Le Chatelier's principle, to shift the equilibrium towards the product side in a system that must function at high temperatures, the following ways are used:
Increase the pressure: When the pressure of a gaseous reaction is increased, the equilibrium shifts towards the side with fewer gas molecules. This is because increasing the pressure will drive the equilibrium to minimize the number of gas molecules in the system.Decrease the temperature: If the system is operating at high temperatures, decreasing the temperature will cause the reaction to shift towards the product side. This is because when the temperature is lowered, the reaction rate slows down, and the system will adjust by shifting the equilibrium position to the side with the more considerable energy or heat content.Use a catalyst: A catalyst is used to speed up a reaction without being consumed in the process. A catalyst lowers the activation energy required for the reaction to occur and thus increases the rate of reaction. By increasing the rate of the reaction, the catalyst shifts the equilibrium position towards the products because the reactants are consumed quickly.The above ways can be used to shift the equilibrium towards the product side in a system that must operate at high temperatures.
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Within what distance must an amateur station protect an FCC monitoring facility from harmful interference?
a. 1 mile;
b. 3 miles;
c. 10 miles;
d. 30 miles.
Answers
Within 1 mile distance must an The amateur station must protect an FCC monitoring facility from harmful interference
Therefore, option a. 1 mile is correct.
An FCC monitoring facility is a station established and maintained by the Commission for monitoring the operations of communications stations or devices. It monitors and enforces rules and regulations established by the FCC. The FCC monitoring facility is established to conduct tests and make measurements for the purpose of enforcing the provisions of the Act and these rules, and to investigate violations. Amateur radio enthusiasts must adhere to a number of operating regulations established by the Federal Communications Commission.
These regulations are designed to ensure that the licensed radio stations do not cause harmful interference to other radio stations, TV stations, or other electronics on the airwaves. Harmful interference is any radio signal that disrupts or interrupts the normal operation of another radio signal.
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A pequin walks 10 feet in six second how far does the pequin wals in 45 seconds
Answers
Answer:
7.5 feet
Explanation:
45 divided by 6 is 7.5
Answer:
7.5 feet
Explanation:
45 divided by 6 is 7.5
The * key is used for ____.
Answers
estimate the theoretical fracture strength of a brittle material if it is known that fracture occurs by the propagation of an elliptically shaped surface crack of length 0.29 mm and that has a tip radius of curvature of 0.004 mm when a stress of 1300 mpa is applied.
Answers
The theoretical fracture strength of the brittle material is estimated to be approximately 165.6 MPa when a stress of 1300 MPa is applied and fracture occurs by the propagation of an elliptically shaped surface crack of length 0.29 mm and tip radius of curvature of 0.004 mm.
To estimate the theoretical fracture strength of a brittle material given the information provided, we can use Griffith's theory of brittle fracture. According to this theory, the fracture strength of a brittle material can be expressed as:
σ_f = (2Eγπa)^0.5
where σ_f is the fracture strength, E is the elastic modulus, γ is the surface energy per unit area, and a is the length of the elliptically shaped surface crack.
To calculate the fracture strength, we need to first determine the surface energy per unit area of the material. For glass, a typical value of surface energy is around 1 J/m^2.
Given the length of the elliptically shaped surface crack (a) is 0.29 mm, and the tip radius of curvature is 0.004 mm, we can calculate the crack area (A) as follows:
A = πab = π(0.29/2)(0.004)
A ≈ 5.67 x 10^-7 m^2
Next, we can calculate the elastic modulus (E) of the material. For glass, the elastic modulus is typically around 70 GPa.
Substituting these values into the equation for fracture strength, we get:
σ_f = (2Eγπa)^0.5 = [2(70 x 10^9)(1)(π)(0.29 x 10^-3)]^0.5
σ_f ≈ 165.6 MPa
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In addition to passing an ASE certification test, automotive technicians must have __________ year(s) of on the job training or __________ year(s) of on the job training and a two-year degree in automotive repair to qualify for certification.
Answers
What makes an electronic instrument a synthesizer?
Answers
An electronic instrument is considered a synthesizer if it produces sound by generating or altering waveforms using electronic circuits or digital signal processing.
A synthesizer is an electronic musical instrument that can produce a wide range of sounds by generating and altering waveforms through various techniques. In essence, a synthesizer converts an electrical signal into sound. A synthesizer can produce sounds that mimic traditional acoustic instruments, such as pianos, guitars, and strings, as well as generate entirely new sounds that cannot be produced by traditional instruments.
The following are some of the characteristics that set synthesizers apart from other electronic instruments:
Waveform Generation: Synthesizers can generate a wide range of waveforms, including sine, square, sawtooth, and triangle waves. The type of waveform used determines the nature of the sound produced.Sound Manipulation: Synthesizers can alter the sound in various ways by using filters, envelopes, modulation, and effects.Polyphony: Synthesizers can produce multiple notes or sounds simultaneously.Programmability: Synthesizers can be programmed to store and recall specific sounds or settings. This allows for the creation of complex and unique sounds.Interface: Synthesizers often have a keyboard or other interface that allows for the control of various parameters, such as pitch, volume, and modulation.Learn more about electronic instrument:
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Forging is a deformation process in which the work is compressed between two dies, using either impact or gradual pressure to form the part: (a) True or (b) false
Answers
The statement "Forging is a deformation process in which the work is compressed between two dies, using either impact or gradual pressure to form the part" is true because the dies exert pressure on the workpiece, causing it to deform.
Forging is indeed a deformation process in which a workpiece is compressed between two dies to shape it into the desired form. Let's take a closer look at how forging works.
In the forging process, the workpiece, often a heated metal billet or ingot, is positioned between two dies. These dies have specific contours and shapes that correspond to the desired final shape of the forged part. The dies are typically made of hardened steel and are usually mounted in a forging press or hammer.
When the forging process begins, compressive forces are applied to the workpiece by closing or striking the dies together. This pressure causes the material to flow and deform, taking the shape defined by the dies. The applied force can be achieved through impact, where a hammer or similar tool strikes the workpiece, or through gradual pressure exerted by a hydraulic or mechanical press.
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If the cathode voltage of a forward-biased silicon diode equals 2.6 V, the anode voltage equals __________.
Answers
The anode voltage equals 1.9 to 2.0 volts.
We have,
If the cathode voltage of a forward-biased silicon diode equals 2.6 V, the anode voltage would be lower than the cathode voltage by approximately 0.6 to 0.7 volts.
This voltage drop is commonly known as the forward voltage drop of a silicon diode.
Therefore,
The anode voltage would be around:
2.6 V - 0.6 V = 2.0 V
to
2.6 V - 0.7 V = 1.9 V
Thus,
The anode voltage would be approximately 1.9 to 2.0 volts.
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Using the charts below, if you knew that a 1 mm diameter copper-nickel alloy wire can withstand a maximum load (before plastic deformation) of 78.54 N, and possesses an electrical resistance of 0.5 Ohms, then what is its length
Answers
Answer:
L = 10.32 m
Explanation:
The resistance of a copper-nickel alloy wire is given by the following formula:
\(R = \frac{\rho L}{A}\)
where,
R = Resistance = 0.5 Ω
ρ = resistivity of copper-nickel alloy = 3.8 x 10⁻⁸ Ωm
L = Length of wire = ?
A = cross-sectional area of wire = \(\frac{\pi d^2}{4} = \frac{\pi(1\ x\ 10^{-3}\ m)^2}{4}\) = 7.85 x 10⁻⁷ m²
Therefore,
\(0.5\ \Omega = \frac{(3.8\ x\ 10^{-8}\ \Omega.m)L}{7.85\ x\ 10^{-7}\ m^2}\)
L = 10.32 m
3. A balanced load with an impedance of 52<45° in each arm is delta connected ba three phase Y source
with line-to-line voltage of 208V.
Find
a) Phase current in load
b) Total active power absorbed by the load
c) Total Reactive power absorbed by the load
d) Total apparent power delivered by source to load
Answers
Answer:
b)
Explanation:
i think
Hey guys can anyone list chemical engineering advancement that has been discovered within the past 20 years
Answers
Nanopesticides. The world population keeps growing. ...
Enantio selective organocatalysis. ...
Solid-state batteries. ...
Flow Chemistry. ...
Porous material for Water Harvesting. ...
Directed evolution of selective enzymes. ...
From plastics to monomers. ...
simple power system consists of a dc generator connected to a load center via a transmission line. The load power is 100 kW. The transmission line is 100 km copper wire of 3 cm diameter. If the voltage at the load side is 400 V, compute the following: a. Voltage drop across the line Vline b. Voltage at the source side Vsource c. Percentage of the voltage drop Vline /Vsource d. Line losses e. Power delivered by the source f. System efficiency
Answers
Answer:
A. ) 591.7 v
B.) 991.7v
C.) 59.7%
D.) 47.9 Kw
E.) 247925 W
F.) 59.7 %
Explanation:
Given that a simple power system consists of a dc generator connected to a load center via a transmission line. The load power is 100 kW. The transmission line is 100 km copper wire of 3 cm diameter. If the voltage at the load side is 400 V,
Let first calculate the resistance in the wire.
The resistivity (rho) of a copper wire is 1.673×10^-8 ohm metres
Resistance R =( L× rho)/A
Where Area = πr^2 = π × 0.015^2
Area = 0.00071 m^2
R = (100000 × 1.673×10^-8) / 0.00071
Resistance in wire = 2.367 ohms
Then let calculate the resistance in the load.
Also, since Power P = V^2 /R
Make R the subject of formula
R = V^2/ P
R = 400^2/100000
Resistance in load = 1.6 Ohms
Current l = V / R
I = 400/1.6 = 250 Ampere
a.) Voltage drop across the line V line will be achieved by using Ohms law.
V = I R
V = 250 × 2.367
V = 591.7 v
B.) Voltage at the source side Vsource will be
V = V line + V load
V = 400 + 591.7
V = 991.7 v
C.) Percentage of the voltage drop Vline /Vsource
591.7/991.7 × 100 = 59.7%
D.) Line losses
P = I V
P = 250 × 591.7
P = 147925 W
Power loss = 147925 - 100000
Power loss = 47,925 W
Power loss = 47.9 Kw
E.) Power delivered by the source
P = IV
P = 250 × 991.7 = 247925 W
F.) System efficiency
Efficiency = power line / power source × 100
Efficiency = 147925 / 247925 × 100
Efficiency = 59.7 %
In this exercise we have to use the circuit knowledge of an electrical system and calculate the characteristics so we have to:
A. ) 591.7 v
B.) 991.7v
C.) 59.7%
D.) 47.9 Kw
E.) 247925 W
F.) 59.7 %
Organizing the information given in the statement we have that:
power is 100 kW.line is 100 km 3 cm diametervoltage at the load side is 400 VThe resistivity is 1.673×10^-8 ohm metresCalculating the resistivity we find that:
\(R =( L* \rho)/A\\A= \pi r^2 = 0.00071 m^2\\R = (100000 * 1.673*10^{-8}) / 0.00071\\R = 2.367 ohms\)
Then it becomes simpler to calculate the power and current, we have:
\(P = V^2 /R= 1.6 Ohms\\l = V / R = 250 Ampere\)A) With the above information, we can calculate the voltage as:
\(V = I R\\V = 250 * 2.367\\V = 591.7 v\)
B) Now calculating the source voltage, we find that:
\(V = V line + V load\\V = 400 + 591.7\\V = 991.7 v\)
C.) The percentage will be calculated as the division of the two previous values, like:
\(591.7/991.7 * 100 = 59.7\%\)
D.) Like any imperfect circuit, losses occur, so the loss will be calculated as:
\(Power loss = 147925 - 100000\\Power loss = 47,925 W\\Power loss = 47.9 Kw\)
E.) Power delivered by the source, can be:
\(P = IV\\P = 250 * 991.7 = 247925 W\)
F.) System efficiency, will be:
\(Efficiency = power line / power source *100\\Efficiency = 147925 / 247925 * 100\\Efficiency = 59.7 \%\)
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Which control would be used to manually feed a cutting tool longitudinally across the workpiece?
Answers
The carriage handwheel is used to manually position and/or hand feed the carriage in the longitudinal or Z axis.
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Find the power and the rms value of the following signal square: x(t) = 10 sin(10t) sin(15t)
1. Px =
2. xrmx =
Answers
Answer:
\(\mathbf{P_x =25 \ watts}\)
\(\mathbf{x_{rmx} = 5 \ unit}\)
Explanation:
Given that:
x(t) = 10 sin(10t) . sin (15t)
the objective is to find the power and the rms value of the following signal square.
Recall that:
sin (A + B) + sin(A - B) = 2 sin A.cos B
x(t) = 10 sin(15t) . cos (10t)
x(t) = 5(2 sin (15t). cos (10t))
x(t) = 5 × ( sin (15t + 10t) + sin (15t-10t)
x(t) = 5sin(25 t) + 5 sin (5t)
From the knowledge of sinusoidial signal Asin (ωt), Power can be expressed as:
\(P= \dfrac{A^2}{2}\)
For the number of sinosoidial signals;
Power can be expressed as:
\(P = \dfrac{A_1^2}{2}+ \dfrac{A_2^2}{2}+ \dfrac{A_3^2}{2}+ ...\)
As such,
For x(t), Power \(P_x = \dfrac{5^2}{2}+ \dfrac{5^2}{2}\)
\(P_x = \dfrac{25}{2}+ \dfrac{25}{2}\)
\(P_x = \dfrac{50}{2}\)
\(\mathbf{P_x =25 \ watts}\)
For the number of sinosoidial signals;
\(RMS = \sqrt{(\dfrac{A_1}{\sqrt{2}})^2+(\dfrac{A_2}{\sqrt{2}})^2+(\dfrac{A_3}{\sqrt{2}})^2+...\)
For x(t), the RMS value is as follows:
\(x_{rmx} =\sqrt{(\dfrac{5}{\sqrt{2}} )^2 +(\dfrac{5}{\sqrt{2}} )^2 }\)
\(x_{rmx }=\sqrt{(\dfrac{25}{2} ) +(\dfrac{25}{2} ) }\)
\(x_{rmx }=\sqrt{(\dfrac{50}{2} )}\)
\(x_{rmx} =\sqrt{25}\)
\(\mathbf{x_{rmx} = 5 \ unit}\)
The primary adaptive purpose of the substances produced in the alarm stage is energy and repair. True or false?
Answers
True. The primary adaptive purpose of the substances produced in the alarm stage is indeed energy and repair. The alarm stage is the first phase of the body's response to stress, also known as the fight-or-flight response.
This stage is characterized by the release of stress hormones, such as adrenaline and cortisol, which prepare the body to react to the perceived threat or stressor.
These hormones initiate several physiological changes to provide the body with energy and repair mechanisms. Adrenaline increases heart rate and blood pressure, directing more oxygen and nutrients to the muscles and brain. It also boosts glucose levels in the bloodstream, providing an immediate source of energy. Cortisol, on the other hand, helps to maintain adequate energy levels by mobilizing fat and glucose reserves and suppressing non-essential functions, such as digestion and immune response.
Furthermore, the stress response activates the body's repair mechanisms. Cortisol, for instance, has anti-inflammatory properties that help to minimize tissue damage caused by the stressor. This hormone also supports the healing process by regulating the production of proteins and other cellular components needed for repair.
In summary, the substances produced in the alarm stage serve the primary adaptive purpose of providing energy and promoting repair, enabling the body to cope with stress effectively and maintain its overall well-being.
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If you are designing a space heater to warm a room and are required by safety codes to keep its surface temperature below 350 K (170 F or 77 C), the only variable you have to work with is the surface area, and you want to minimize that to make it convenient and inexpensive. Neglecting convection entirely, and assuming all the heat is transferred as infrared light, suppose it is to radiate 1200 W. How much area would it have
Answers
Answer:
A = 1.41 m²
Explanation:
The ara can be found out by using Stefan Boltzman Law:
\(P = \sigma AT^4\)
where,
A = Area = ?
P = Radiation Power = 1200 W
σ = Stefan Boltzman Constant = 5.6703 x 10⁻⁸ W/m².k⁴
T = surface temperature = 350 k
Therefore:
\(1200\ W = (5.6703\ x\ 10^{-8}W/m^2.k^4)(A)(350\ k)^4\\\\A = \frac{1200\ W}{850.9\ W/m^2}\)
A = 1.41 m²
Lydia is the CEO for a large pharmaceutical manufacturer. Her company is in the final stages of FDA
approval for a new drug for diabetics. The new drug is expected to bring in billions of dollars for the company. Lydia is acquainted with Bradley,
the CSHO on rotation for OSHA inspections. Lydia is concerned that a surprise inspection may turn up violations, which could affect the launch of
the drug. Lydia reaches out to Bradley and casually mentions that it would be helpful if he could tell her when the next OSHA inspection will be
Should Bradley give Lydia advance notice about an upcoming inspection?
No, because he could receive fines and a jail term.
No, because this situation does not meet the criteria for advance notice.
Yes, because employers may request an OSHA inspection at any time.
Yes, because the inspection will be conducted during regular business hours.
Answers
It is a criminal offense for any person to give unauthorized advance notice of an OSHA inspection.
Write the distributeCurrentPlayerTokens method. The tokens are collected and removed from the game board at the current player's position. These tokens are distributed, one at a time, to each player, beginning with the next higher position, until there are no more tokens to distribute
Answers
The distribute Current Player Tokens method for the tokens are collected and removed from the game board at the current player's position is stated in code in Java below:
Why do we use public void?The Java application's main method is created by using the keyword public static void main. The program's primary method, it is what all others are called. For difficult command-line processing, it accepts parameters but cannot return values. Both generate a void method (a method with no return value), but only the public void method is accessible to classes outside the one that created it. Only the class in which the private method is contained may utilise it. It is a keyword that is employed to indicate that a method returns nothing. The main() method's return type is void because it doesn't produce a result. The code is:
public void distributeCurrentPlayerTokens()
{
int numTokens = board[currentPlayer];
board[currentPlayer] = 0;
int i = currentPlayer;
while (numTokens > 0)
{
i = (i+1) % board.length; 1
board[i]++;
numTokens--;
}
}
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Illinois furniture , Inc produces all types of coffee furniture the executive secretary is a chair that has been designed using ergonomics to provide comfort during long work hours the chair sells for $130 there are 480 minutes available during the day and the average daily demand has been 50 chairs there are eight tasks
Answers
This question is incomplete, the complete question is;
Illinois furniture , Inc produces all types of office furniture. The "Executive Secretary" is a chair that has been designed using ergonomics to provide comfort during long work hours the chair sells for $130. There are 480 minutes available during the day and the average daily demand has been 50 chairs. There are eight tasks.
TASK PERFORMANCE TIME( MIN ) TASK MUST FOLLOW TASK LISTED
A 4 ---------
B 7 ----------
C 6 A,B
D 5 C
E 6 D
F 7 E
G 8 E
H 8 F,G
1) What is the cycle time for operation?
2) What is the theoretical minimum number of workstation?
Answer:
1) the cycle time for operation is 9.6 min
2) the theoretical minimum number of workstation is 5
Explanation:
Given the data in the question;
production time per day = 480 minutes
average daily demand = 50
Given the data in the question;
1) cycle time for operation
this is simply referred to as the total time for the process from start to finish.
cycle time = production time per day / units demand per day
we substitute
cycle time = 480 min / 50
cycle time = 9.6 min
Therefore, the cycle time for operation is 9.6 min
2) theoretical minimum number of workstation.
theoretical minimum number of workstation = total task time / cycle time
Total task time = ( 4 + 7 + 6 + 5 + 6 + 7 + 8 + 6 ) = 49 min
∴ theoretical minimum number of workstation = 49 min / 9.6 min
theoretical minimum number of workstation = 5.104 ≈ 5
Therefore, the theoretical minimum number of workstation is 5
an ideal gas at high pressure expands through an adiabatic turbine to a lower pressure in a steady-state, steady-flow process. does the entropy of the gas always increase for an irreversible process (yes or no)?
Answers
The relationship between entropy and energy in an irreversible process of a gas expanding is that as the gas expands, some energy is lost as heat to the surroundings and cannot be recovered.
What is the relationship between entropy and energy in an irreversible process of a gas expanding?Yes, the entropy of the gas always increases for an irreversible process. This is due to the fact that during the expansion process, some energy is lost as heat to the surroundings, which cannot be recovered.
This leads to an increase in the randomness and disorder of the system, which is reflected by an increase in entropy.Entropy is a measure of the degree of randomness or disorder in a system.
In the case of a gas undergoing an irreversible expansion process, the system loses some energy as heat to the surroundings.
This energy cannot be recovered, and as a result, the randomness and disorder of the system increase. The increase in randomness and disorder is reflected by an increase in the system's entropy.
This is a natural consequence of the second law of thermodynamics, which states that the total entropy of an isolated system always increases over time.
Thus, irreversible processes always result in an increase in entropy, and the irreversible expansion of a gas is no exception.
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Wherever possible, you should write automated tests. The tests are embedded in a program
that can be run every time a change is made to a system.
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Software testing is a step in the software development process. To tell stakeholders about the software's quality, an investigation is conducted against the product.
What happens during the software testing process?Software testing is the procedure used to assess and confirm that a software program or application performs as intended. Bugs can be avoided, development expenses are decreased, and performance is increased.Stakeholders in testing include senior management, program and project managers, Scrum masters, developers, engineers, and architects, as well as specialists in operations, product ownership, and business analysis. Testers, however, should put the consumer first.An expert testing team carries out this kind of testing. The software development life cycle's initial stage, system testing, involves comprehensive testing of the entire application. To ensure that the application satisfies the functional and technological requirements, it is rigorously tested.To learn more about Stakeholders refer to:
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where are sensors located on a vehicle equipped with side sonar system?
Answers
Sensors in a vehicle with a side sonar system are typically located on the side bumpers or door panels. They are evenly distributed along the length of the vehicle for effective detection.
A side sonar system in a vehicle is designed to detect obstacles and other objects near the sides of the car during maneuvers such as parking or changing lanes. To ensure comprehensive coverage, multiple sensors are embedded along the side bumpers or door panels.
These sensors emit ultrasonic waves that bounce off nearby objects and return to the sensors, allowing the system to calculate the distance to the detected object. This information is then relayed to the driver through visual or auditory cues, helping them make safe driving decisions. The precise location of sensors may vary depending on the vehicle make and model.
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Which of the following is NOT a factor in the amperage setting on a welding machine?
Answers
What was the role of the rotors in the enigma machine?.
Answers
Answer:
Implements a reordering of the letters of the alphabet.
Explanation: GIVE ME 5 STARS AND a HEART!!! Those contacts are wired across the rotor so that each contact on the left connects to the contact on the right in some scrambled arrangement. Each rotor, therefore, implements a reordering of the letters of the alphabet, which mathematicians call a permutation.
A company sent prototypes of a newly designed hair dryer for trial use to 100 homes along with a satisfaction survey. A month later the company received 82 completed surveys. This process is part of which step of the engineering design process?
Answers
Answer:
The answer is "evaluating outcomes ".
Explanation:
The assessment of the results shows that maybe a program has achieved its goals. The assessment with results measures the results of the program and decides whether intended results were achieved. Its results allow you to achieve people by the measurable changes made through participating in your project by students enrolled. It is a form of assessment that examines if changes occur for students enrolled or if these adjustments are related to a program.
which of the following treatment processes can be used to remove algae-related odors from drinking water? Filtration
Aeration
Disinfection
Sedimintation
Answers
Disinfection is the treatment process that can be used to remove algae-related odors from drinking water.So option c is correct.
To remove algae-related odors from drinking water, the treatment process that is most effective is disinfection. Algae in the water can release compounds that cause unpleasant odors. Disinfection processes, such as chlorination or ozonation, are commonly used to eliminate algae and the associated odors, ensuring the water is safe and free from any noticeable smells.
Filtration, aeration, and sedimentation are important treatment processes in water treatment, but they are not specifically targeted at removing algae-related odors. Filtration is used to remove particulate matter and impurities, aeration is employed to increase dissolved oxygen levels, and sedimentation aids in the settling and removal of suspended solids. While these processes can indirectly contribute to overall water quality improvement, disinfection is the most appropriate method for addressing algae-related odors.Therefore option c is correct.
The question should be:
which of the following treatment processes can be used to remove algae-related odors from drinking water?
(a) Filtration
(b)Aeration
(c)Disinfection
(d)Sedimintation
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