In a multiple regression with four explanatory variables and 100 observations, it is found that SSR = 4.75 and SST = 7.62.
a. Calculate the standard error of the estimate. (Round your answer to 2 decimal places.)
Answers
The standard error of the estimate is 0.36.
The standard error of the estimate (SEE) can be calculated as:
SEE = sqrt(SSR / (n - k))
where SSR is the sum of squared residuals, n is the sample size (number of observations), and k is the number of explanatory variables (excluding the intercept).
In this case, SSR = 4.75, SST = 7.62, n = 100, and k = 4. Therefore, we have:
SEE = sqrt(4.75 / (100 - 4))
SEE = sqrt(4.75 / 96)
SEE ≈ 0.49
Rounding to 2 decimal places, the standard error of the estimate is approximately 0.49.
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Related Questions
The slope field for certain differential equae tion is shown below: Which of the following statements about solution y = f (x) the differential equation must be false?
A). The graph of the particular solution that satisfies f "(0)=0 has = point of inflection at x=0 _
B.) The graph of the particular solution that satisfies f (0) =0 is concave up on the interval -k
C) The graph of the particular solution that satisfies f(-1)=1 concave up on the interval -1
D.) The graph of the particular solution that satisfies f ()=-1is concave down on the interval 0
Answers
The slope field shown in the question is that of a differential equation of the form y'= f(x,y).
The solutions of this equation are the curves in the slope field that emanate from each point and that have the same slope as the line at that point. Thus, for each point (x,y) in the slope field, it is possible to calculate the particular solution that passes through that point.
The first statement is false because it involves the second derivative of the particular solution, which cannot be determined from the slope field. The second statement is false because a concave up graph requires that the derivative of the solution be increasing at x=0, but the slope field does not indicate the sign of the derivative of the particular solution. The third statement is false because a concave up graph requires that the derivative of the solution be decreasing at x=-1, which cannot be determined from the slope field. The fourth statement is false because a concave down graph requires that the derivative of the solution be increasing at x=0, which cannot be determined from the slope field.
In summary, none of the statements can be determined to be true or false from the slope field shown.
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c. using systematic random sampling, every fifth dealer is selected starting with the third dealer in the list. which dealers are included in the sample?
Answers
The dealers included in the sample are dealers 3, 8, 13, 18, 23, 28, 33, 38, 43, 48, 53, 58, 63, 68, 73, 78, 83, 88, 93, and 98.
How to find dealers that included in the sample?To use systematic random sampling, we need to choose a starting point and a sampling interval. In this case, we are starting with the third dealer in the list, so we need to skip the first two dealers.
Let's assume that the dealers are numbered 1 to 100 in the list. Since we are starting with the third dealer, our starting point is dealer 3. We also need to choose a sampling interval of 5, since we want to select every fifth dealer.
To find out which dealers are included in the sample, we can use the following formula:
Sampled Dealers = Starting Point + (Sampling Interval * Number of Samples)
Using the formula, we can calculate the dealers that are included in the sample as follows:
Sampled Dealers = 3 + (5 * n)
where n is the number of samples.
If we want to select a sample of 20 dealers, we can substitute n = 1 to 20 into the formula to get the following list of dealers:
3, 8, 13, 18, 23, 28, 33, 38, 43, 48, 53, 58, 63, 68, 73, 78, 83, 88, 93, 98
Therefore, the dealers included in the sample are dealers 3, 8, 13, 18, 23, 28, 33, 38, 43, 48, 53, 58, 63, 68, 73, 78, 83, 88, 93, and 98.
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ILL MARK BRAINLIEST
15. EYE COLOR If −2 of the girls in class have brown eyes and −1 of the girls 34
have blue eyes, what fraction of the girls in class have neither blue or brown eyes?
16. PIE Ubi made a banana cream pie. His brother ate −1 of the pie and his 23
sister ate −5 of the pie. How much less did his brother eat than his sister?
Answers
Answer:
for 31/34 is the answer for eye color
Step-by-step explanation:
2 + 1 =3
34-3=31
31 out of the 34 students have neither blue or brown eyes.
31/34
Which function does the graph represent? What is the asymptote of the function?
5
5
5
On
4
النا
2
2
m
5
-1
-2
3
4
-5
The function is
B. Its asymptote is
e
Answers
Answer:
your new acc has not verify
plss try again!!
Find the hypotenuse round to the nearest hundredth
Answers
Answer:
7.62
Use the Pythagorean theorem. (a^2)+(b^2)=(c^2)
(3^2)+(7^2)=58
Then the square root of 58 is 7.61577 rounding that to the hundredths gives you 7.62
7.62
To round find the hypotenuse, use the Pythagorean theorem which states that A squared plus B squared = C squared which is the answer to our problem. Then find the square root of the solution and voila.
Where is the blue dot on the number line?
Answers
Answer:
6.2
Step-by-step explanation:
ahmm recommend answer lang
Answer:
6.8
Step-by-step explanation:
hope this helped! :)
write a polynomial of degree 5 with zero x=0,i square root 7, -2i
Answers
Answer:
\(P(x)=x^5+11x^3+28x\)
Step-by-step explanation:
Roots of a polynomial
If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula
\(P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)\)
Where a is an arbitrary constant.
We know three of the roots of the degree-5 polynomial are:
\(x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}\)
We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:
\(x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}\)
Let's build up the polynomial, assuming a=1:
\(P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})\)
Since:
\((a+b\boldsymbol{i})\cdot (a-b\boldsymbol{i})=a^2+b^2\)
\(P(x)=(x)(x^2+7)(x^2+4)\)
Operating the last two factors:
\(P(x)=(x)(x^4+11x^2+28)\)
Operating, we have the required polynomial:
\(\boxed{P(x)=x^5+11x^3+28x}\)
Guys help me question 25,26
Answers
25. B or 25
26. A or 20
Determine whether each of these statements is true or false.a) 0 ∈ ∅ b) ∅∈{0}c) {0}⊂∅ d) ∅⊂{0}e) {0}∈{0} f ) {0}⊂{0}g) {∅} ⊆ {∅}
Answers
a) True, b) False, c) False, d) True, e) False, f) False, g) True
a) The statement is true. The symbol "∅" represents the empty set, which does not contain any elements. Since 0 is not an element of the empty set, the statement "0 ∈ ∅" is false.
b) The statement is false. The symbol "{0}" represents a set containing the element 0. The empty set, represented by "∅", does not contain any elements. Therefore, the empty set is not an element of the set {0}.
c) The statement is false. The symbol "{0}" represents a set containing the element 0. However, the empty set, represented by "∅", does not contain any elements. Therefore, the set {0} is not a subset of the empty set.
d) The statement is true. The empty set, represented by "∅", does not contain any elements. Every set is a subset of the empty set, including the set {0}.
e) The statement is false. The symbol "{0}" represents a set containing the element 0. In this case, {0} is not an element of itself. Therefore, the statement "{0}∈{0}" is false.
f) The statement is false. The symbol "{0}" represents a set containing the element 0. In this case, {0} is not a proper subset of itself. Therefore, the statement "{0}⊂{0}" is false.
g) The statement is true. The symbol "{∅}" represents a set containing the empty set. In this case, {∅} is a subset of itself because it contains the element ∅. Therefore, the statement "{∅} ⊆ {∅}" is true.
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5x+2y<8 graph the inequality
Answers
A statistics module has been running for many years and, in the past, it has been found that each year the number of students passing the exam has distribution Bi(n. 0.75), where n are the number of students taking the module that year. A lecturer is teaching the module for the first time and 105 out of 150 students pass the exam. Perform a hypothesis test at the 0.05-significance level, where the null hypothesis is The probability of a student passing the module is 0.75and the alternative hypoth- esis is The probability of a student passing the module is less than 0.75. What is the conclusion? [Hint: Clearly state any assumptions made and recall the conditions under which a bino- mial distribution can be approximated by a normal distribution.]
Answers
The probability of a student passing the module is less than 0.75. Therefore, the lecturer should reconsider his method of teaching.
Question analysis A statistics module has been running for many years, and the module is given to n students each year. It has been discovered that in each year, the number of students passing the exam is distributed Bi(n, 0.75). In the current year, 150 students took the module for the first time, and 105 students passed the exam.
Using the 0.05 level of significance, we will conduct a hypothesis test to decide if the module's pass rate this year is less than 0.75.AssumptionsIf the number of trials is huge, the distribution of successes will be nearly normal. The number of trials n is greater than 30 in this situation. The probability of success in each trial is the same, namely p = 0.75. This condition is also satisfied. Therefore, we may use a normal distribution to approximate the binomial distribution.
What is the conclusion?
Null hypothesis: H₀: P = 0.75
Alternative hypothesis: H₁: P < 0.75The level of significance is 0.05, which implies that the rejection area will be in the left tail because the alternative hypothesis is one-tailed. Since the distribution of successes is approximately normal with a mean of np and a variance of np(1−p), we may find the p-value using this formula:
[The probability that X ≤ 105]
= [Z = (X − µ)/σ]
= [Z = (105 − (150 × 0.75))/sqrt(150 × 0.75 × (1 − 0.75))]
= [Z = (105 − 112.5)/3.2958]
= -2.2782
The p-value is [P(Z < -2.2782)] = 0.011. Because the p-value is less than 0.05, we reject the null hypothesis and accept the alternative hypothesis.
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Given : A statistics module has been running for many years and, in the past, it has been found that each year the number of students passing the exam has distribution Bi(n. 0.75), where n are the number of students taking the module that year. A lecturer is teaching the module for the first time and 105 out of 150 students pass the exam. The conclusion is that we fail to reject the null hypothesis.
The null and alternative hypotheses are given as follows:
Null hypothesis: The probability of a student passing the module is 0.75.
Alternative hypothesis: The probability of a student passing the module is less than 0.75.
We need to perform a hypothesis test at the 0.05-significance level.
The given probability distribution Bi(n,0.75) can be approximated to the normal distribution N(np,npq) under the following conditions:
The sample size n is large enough.
np≥5 and nq≥5, where q=1-p.
Here, n=150 and
p = 0.75
q = 1−p
= 1−0.75
= 0.25
Since np and nq are both greater than 5, the distribution Bi(150,0.75) can be approximated by the normal distribution N(150×0.75,150×0.75×0.25) = N(112.5,28.125).
Let X be the number of students that passed the module.
Under the null hypothesis, X follows the binomial distribution Bi(150,0.75).
Let μ be the mean of X under the null hypothesis.
μ = np
= 150×0.75
= 112.5
Since the alternative hypothesis is the probability of passing the module is less than 0.75, we need to perform a one-tailed test in the left tail at the 0.05-significance level.
The test statistic is given by,
Z=(X−μ)/σ
Z=(105−112.5)/√28.125/150
Z ≈ −1.5
This is a left-tailed test, so the critical value for a 0.05-significance level is z=−1.645.
Since the test statistic z=-1.5 > critical value z=-1.645, we fail to reject the null hypothesis.
Hence, there is not enough statistical evidence to conclude that the probability of a student passing the module is less than 0.75.
Therefore, the conclusion is that we fail to reject the null hypothesis.
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How are the solutions to the inequality -3x≥ 18 different from the solutions to
-3x>18
Answers
Answer:
si, por qué ecuación da diferente resultado
Find the distance between the two points in simplest radical form.
Answers
The distance bewteen the points (-3,5) and (3,1) in a simple radical form is 2√13.
What is the distance between the given points?The distance formula used in finding the distance between two points is expressed as;
d = √( ( x₂ - x₁ )² + ( y₂ - y₁ )² )
From the graph;
Point A: (-3,5)
x₁ = -3
y₁ = 5
Point B: (3,1)
x₂ = 3
y₂ = 1
Plug the given values into the distance formula and simplify.
\(d = \sqrt{( x_2 - x_1)^2 + (y_2 -y_1 )^2} \\\\d = \sqrt{( 3-(-3))^2 + (1 -5)^2} \\\\d = \sqrt{( 3+ 3)^2 + (1 -5)^2} \\\\d = \sqrt{( 6)^2 + (-4)^2} \\\\d = \sqrt{36 + 16} \\\\d = \sqrt{52}\\\\d = 2\sqrt{13}\)
Therefore, the distance between the points is 2√13.
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160 cars and vans, in the ratio of 3:7.
25% of cars are electric
1/8 of cars are diesel.
The remainder of the cars run on petrol. How many cars run on petrol?
Answers
If the number of cars will be 48. Then the number of cars that run on petrol will be 30.
What are ratio and proportion?A ratio is an ordered set of integers a and b expressed as a/b, with b never equaling 0. A percentage is a mathematical expression in which two things are equal.
160 cars and vans, in the ratio of 3:7.
Let x be the number of cars and y be the number of vans. Then we have
x + y = 160
and
x/y = 3/7
(x + y)/y = 10/7
160/y = 10/7
y = 112
Then the value of x will be
x + 112 = 160
x = 48
Then 25% of cars are electric and 1/8 of cars are diesel. Then the number of the cars that run on petrol will be
Let z be the number of petrol cars.
z + 0.25 (48) + 48/8 = 48
z + 12 + 6 = 48
z = 30
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A trapezium named pqrs with right angles at q&r. PQ equals to 9 cm, PR equals to 4 cm and RS equals to 6 cm. calculate the perimeter of a trapezium
Answers
Answer:
Step-by-step explanation:
Draw a picture. Seriously, this time you need to, so you can see that PS is the hypotenuse of a right triangle with legs of length 3 and 4 .
PS = √(3² + 4²) = 5
Perimeter = PQ + QR + RS + PS = 9 + 4 + 6 + 5 = 24 cm
What is the center of the circle for this equation:
(x + 3)² + (y - 2)² = 25
Answers
The formula for the equation of a circle is (x - h)² + (y - k)² = r²
where (h, k) is the center of the circle and r is the radius.
So we need to find the values of (h, k) in order to find the center of the circle.
If we simply line up the equation of our given circle with our formula,
we can see that -h = 3 or h = -3 and -k = -2 so k = 2.
So now we have our answer.
center ⇒ (-3, 2)
In the following questions, the bold letters X, Y, Z are variables. They can stand for any sentence of TFL. (3 points each) 4.1 Suppose that X is contingent and Y is a tautology. What kind of sentence must ¬XV y be? Explain your answer. 4.2 Suppose that X and Y are logically equivalent, and suppose that X and Z are inconsistent. Does it follow that Y must entail ¬Z? Explain your answer. 4.3 Suppose that X and X → > Z are both tautologies. Does it follow that Z is also a tautology? Explain your answer.
Answers
4.1 If X is contingent (neither a tautology nor a contradiction) and Y is a tautology (always true), ¬X V Y is a tautology.
4.2 No, it does not necessarily follow that Y must entail ¬Z. Y does not necessarily entail ¬Z.
4.3 The tautologies of X and X → Z do not provide sufficient information to conclude that Z itself is a tautology.
4.1 If X is contingent (neither a tautology nor a contradiction) and Y is a tautology (always true), the sentence ¬X V Y must be a tautology. This is because the disjunction (∨) operator evaluates to true if at least one of its operands is true. In this case, since Y is a tautology and always true, the entire sentence ¬X V Y will also be true regardless of the truth value of X. Therefore, ¬X V Y is a tautology.
4.2 No, it does not necessarily follow that Y must entail ¬Z. Logical equivalence between X and Y means that they have the same truth values for all possible interpretations. Inconsistency between X and Z means that they cannot both be true at the same time. However, logical equivalence and inconsistency do not imply entailment.
Y being logically equivalent to X means that they have the same truth values, but it does not determine the truth value of ¬Z. There could be cases where Y is true, but Z is also true, making the negation of Z (¬Z) false. Therefore, Y does not necessarily entail ¬Z.
4.3 No, it does not necessarily follow that Z is also a tautology. The fact that X and X → Z are both tautologies means that they are always true regardless of the interpretation. However, this does not guarantee that Z itself is always true.
Consider a case where X is true and X → Z is true, which means Z is also true. In this case, Z is a tautology. However, it is also possible for X to be true and X → Z to be true while Z is false for some other interpretations. In such cases, Z would not be a tautology.
Therefore, the tautologies of X and X → Z do not provide sufficient information to conclude that Z itself is a tautology.
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This question: 4 point(s) possible Submit test In the probability distribution to the right, the random variable X represents the number of hits a baseball player obtained in a game over the course of a season. P(x) = 0 0.1666 1 0.3343 2 0.2864 3 0.1499 4 0.0373 4 0.0255 PARIS What is the probability that in a randomly selected game, the player got 2 hits? (Type an integer or a decimal. Do not round.) What is the probability that in a randomly selected game, the player got more than 1 hit? a (Type an integer or a decimal. Do not round.)
Answers
In the given probability distribution, the probability that the baseball player obtained 2 hits in a randomly selected game is 0.2864. This value corresponds to the probability associated with the random variable X being equal to 2.
To calculate the probability that the player got more than 1 hit, we need to sum the probabilities for X greater than 1. In this case, we add the probabilities for X = 2, X = 3, and X = 4. Doing the calculation, we find:
P(X > 1) = P(X = 2) + P(X = 3) + P(X = 4) = 0.2864 + 0.1499 + 0.0373 = 0.4736.
Therefore, the probability that in a randomly selected game the player got more than 1 hit is 0.4736.
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Can you solve for X inside the correct code for question four?
Answers
Answer
CIAD
Step-by-step explanation
The Pythagorean theorem states:
\(c^2=a^2+b^2\)where a and b are the legs and c is the hypotenuse of a right triangle.
Applying this theorem to triangle 1:
\(\begin{gathered} x^2=77^2+36^2 \\ x^2=5929+1296 \\ x^2=7225 \\ x=\sqrt{7225} \\ x=85 \end{gathered}\)Then, the first letter is C.
Applying the theorem to triangle 2:
\(\begin{gathered} x^2=39^2+80^2 \\ x^2=1521+6400 \\ x^2=7921 \\ x=\sqrt{7921} \\ x=89 \end{gathered}\)Then, the second letter is I.
Applying the theorem to triangle 3:
\(\begin{gathered} x^2=25^2+100^2 \\ x^2=625+10000 \\ x^2=10625 \\ x=\sqrt{10625} \\ x=103.08 \end{gathered}\)Then, the third letter is A.
Applying the theorem to triangle 4:
\(\begin{gathered} x^2=17^2+52^2 \\ x^2=289+2704 \\ x^2=2993 \\ x=\sqrt{2993} \\ x=54.71 \end{gathered}\)Then, the fourth letter is D.
Please, help! 20 points
Mrs. Garcia’s class sold burgers for $1.36 each and Mr. Runner’s class sold salads for $1.65 each. Together, the classes sold 79 items and earned $118.17 for their school.
(a) Write a system of equations that model the problem.
x + s = 79 1.36(x) + 1.65(s) = 118.17
(b) Solve the systems of equations from part a.
(c) Whose class sold more items?
(d) Which class earned more money?
Answers
The 42 burgers are sold by Mrs. Garcia's class at $57.12 and 37 salad is sold by Mr. Runner’s class at $61.05.
What is a system of equation?A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.
Mrs. Garcia’s class sold burgers for $1.36 each and Mr. Runner’s class sold salads for $1.65 each. Together, the classes sold 79 items and earned $118.17 for their school.
(a) Write a system of equations that model the problem.Let x burgers are sold by Mrs. Garcia's class and s salad is sold by Mr. Runner’s class. Together, the classes sold 79 items for their school. Thus,
\(x + s = 79\) .....1
Mrs. Garcia’s class sold burgers for $1.36 each and Mr. Runner’s class sold salads for $1.65 each. Together, the classes earned $118.17 for their school. Thus,
\(1.36(x) + 1.65(s) = 118.17\\1.36x + 1.65s = 118.17\) ....2
(b) Solve the systems of equations from part a.Rewrite the first equation,
\(x + s = 79 \\ x = 79-s\) .....3
Put this value of x in equation 2,
\(1.36(79-s) + 1.65s = 118.17\\107.44-1.36s + 1.65s = 118.17\\0.29s=118.17-107.44\\s=\dfrac{10.73}{0.29}\\s=37\)
Put this value in equation 3,
\(x=79-37\\x=42\)
(c) Whose class sold more items?42 burgers are sold by Mrs. Garcia's class and 37 salad is sold by Mr. Runner’s class. Thus, Mrs. Garcia's class sold more items.
(d) Which class earned more money?Money earned by Mrs. Garcia's class by selling 42 burger at $1.36 each is,
\(M_x=1.36\times42\\M_x=57.12\)
Money earned by Mr. Runner’s class by selling 37 salad at $1.65 each is,
\(M_s=1.65\times37\\M_s=61.05\)
Thus, Mr. Runner’s class earned more money.
Hence, the 42 burgers are sold by Mrs. Garcia's class at $57.12 and 37 salad is sold by Mr. Runner’s class at $61.05.
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129°
(16x + 17)*
Solve for x.
Answers
Therefore , the solution of the given problem of angles comes out to be
x = 7 is the answer to the equation (16x + 17) = 129° for the variable x.
An angle's meaning is what?A skew greatest and smallest walls are located where the roads leading to its ends meet. A crossroads could be where two paths converge. Angle is another outcome of two things interacting. They mimic dihedral shapes more than anything. A two-dimensional curve can be created by arranging two line beams in various ways between their endpoints.
Here,
The steps below can be used to find x in the equation (16x + 17) = 129°:
To find the term with x on one side of the equation, first subtract 17 from both sides of the equation:
=> 16x + 17 - 17 = 129 - 17
=> 16x = 112
Step 2: To find x, multiply both sides of the equation by 16:
=> 16x / 16 = 112 / 16 x = 7
Thus, x = 7 is the answer to the equation (16x + 17) = 129° for the variable x.
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it is known that the population variance equals 522. what is the sample size that needs to be taken if the desired margin of error is 4 or less with 0.95 probability?
Answers
If the intended margin of error equals 4 less than with a 0.95 probability, the sample size is 126.
The \(\alpha\) level is calculated by subtracting 1 from the confidence interval and dividing by 2.
\(\alpha\) = (1 - 0.95) ÷ 2
\(\alpha\) = 0.025
Find z inside the Z-table because it has a p-value of 1 - \(\alpha\).
So, z = 1.96 with a p-value = 1 - 0.025 = 0.975.
Now, consider that margin of error M.
M = z × (σ ÷ √n)
The standard deviation is determined as the square root of variance.
σ = √522 = 22.84
With a 0.95 probability, the sample size that requires to be accepted if the expected margin of error is 4 or less is,
The sample size of at least n, in which n is encountered when M = 4. So,
M = z × (σ ÷ √n)
4 = 1.96 × (22.84 ÷ √n)
4√n = 1.96 × 22.84
√n = (1.96 × 22.84) ÷ 4
√n = 11.1916
n = (11.1916)²
n = 125.25 ≈ 126
A sample size of at minimum 126 people is required.
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Select the correct choice. To apply the CLT, the typical rule of thumb for setting sample size is greater than or equal to what?
Answers
Answer:
Step-by-step explanation:
30
If f(x) = 2x³ = x² + 3x + 10 and g(x) = x³ + 3x² + 2x + 4, determine when f(x) > g(x).
Answers
Hope this helps, if not sorry.
AJ needs $800. So far, he has saved $290. If his job pays him $12 per hour, write and solve an inequality that can be used to determine the minimum number of hours that he needs to work in order to have enough money for the computer.
Answers
Answer:
The minimum number of hours is 43.
Step-by-step explanation:
Total money required = $ 800
Saved money = $ 290
Per hour income = $ 12
Let the number of hours be n.
According to the question
\(290 + 12n \geqslant 800\\\\12 n \geqslant 510\\\\n\geqslant 42.5\)
So, the minimum number of hours is 43.
Answer:
800 - 290 = 510. 510 = 12h
Step-by-step explanation:
$800 is the amount he is trying to save.
$290 is the amount he has so far.
$800 - $290 = $510.
$510 is the amount more he needs to earn.
12h.
12 represents the amount he is paid every 1 hour
H represents the hours he works.
Multiply
7x(x^2-x+2)
Answers
Answer:
7x^3-7x^2+14x
Step-by-step explanation: hope I helped
Pls help question on the photo
Answers
Answer:first answer choice (subtract 11 from both side)
Step-by-step explanation:
The bookstore has 4 women's magazines and 76 other magazines. What percentage of the magazines at the bookstore are women's magazines?
Answers
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Women’s magazines = 4
Total magazines = 76
Divide no. of women’s magazines by no. of total magazines and multiply by 100
4/76 x 100 = 5.26%
This question is dealing with fractions and percentages.
Fractions and percentages are just means of expressing a part of a whole portion.
percentage of magazines that belong to women is = 5%
Number of women magazines = 4
Number of other magazines = 76
Total number of magazines = 4 + 76 = 80
Therefore,
percentage of magazines that belong to women is; \(\frac{4}{80}\) × 100
percentage of magazines that belong to women is = 5%
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Answers
Answer:
wait that? there is no question
Step-by-step explanation:
N
Drag each division expression to the correct location on the table.
Solve each division problem, and classify it based on its quotient.
5
11
Reset
Next
Answers
Answer:
Step-by-step explanation:
1). \(8\frac{1}{4}\) ÷ \(\frac{3}{4}\)
= \(\frac{33}{4}\) ÷ \(\frac{3}{4}\)
= \(\frac{33}{4}\times \frac{4}{3}\)
= 11
2). \(3\frac{1}{3}\) ÷ \(\frac{10}{3}\)
= \(\frac{10}{3}\) ÷ \(\frac{10}{3}\)
= \(\frac{10}{3}\times \frac{3}{10}\)
= 1
3). \(\frac{5}{4}\) ÷ \(\frac{1}{4}\)
= \(\frac{5}{4}\times \frac{4}{1}\)
= 5
4). \(\frac{25}{4}\) ÷ \(6\frac{1}{4}\)
= \(\frac{25}{4}\) ÷ \(\frac{25}{4}\)
= \(\frac{25}{4}\times \frac{4}{25}\)
= 1
5). \(11\frac{1}{4}\) ÷ \(\frac{9}{4}\)
= \(\frac{45}{4}\) ÷ \(\frac{9}{4}\)
= \(\frac{45}{4}\times \frac{4}{9}\)
= 5
6). \(3\frac{1}{7}\) ÷ \(\frac{2}{7}\)
= \(\frac{22}{7}\) ÷ \(\frac{2}{7}\)
= \(\frac{22}{7}\times \frac{7}{2}\)
= 11
Now we can classify the expressions by their quotients as 1, 5 and 11.