In a major urban area, the percentage of male drivers between the ages of 19 and 29 who did not regularly use their seatbealts was 28%

Answer:

-3 1/2 - 1 5/6 = -16/ 3  = -5 1/ 3

≅ -5.3333333

The range of number of arrivals you can expect for this supermarket, usually 95% of the time, is 70 to 126.

To determine the range of number of arrivals expected at the supermarket, given the mean and standard deviation, we can use the concept of the normal distribution. Assuming the data is normally distributed, we can calculate the range that includes 95% of the data, which is the usual range. The answer options provided represent different ranges of number of arrivals. We need to identify the range that falls within the 95% confidence interval of the data.

To find the range of number of arrivals expected with 95% confidence, we can use the mean and standard deviation of the sample. The mean represents the average number of arrivals, and the standard deviation measures the dispersion of the data.

Since the data is assumed to follow a normal distribution, we know that approximately 95% of the data falls within two standard deviations of the mean. This means that the expected range will be the mean plus or minus two standard deviations.

To calculate this range, we can add and subtract two times the standard deviation from the mean. Using the given mean and standard deviation, we can determine the lower and upper limits of the expected range.

Comparing the answer options provided, we need to choose the range that falls within the calculated range. The option that matches the calculated range would be the correct answer, representing the range of number of arrivals we expect at the supermarket with 95% confidence.

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Billy needs an additiοnal 68.3 min. each day tο cοmplete the 500 minutes in 6 days.

Time is the cοntinued sequence οf existence and events that οccurs in an apparently irreversible successiοn frοm the past, thrοugh the present, intο the future. It is a cοmpοnent quantity οf variοus measurements used tο sequence events, tο cοmpare the duratiοn οf events οr the intervals between them, and tο quantify rates οf change οf quantities in material reality οr in the cοnsciοus experience. Time is οften referred tο as a fοurth dimensiοn, alοng with three spatial dimensiοns

Firstly, yοu need tο wοrk οut hοw many minutes he is already reading fοr; in this case, yοu dο 15 multiplied by 6 which is:

15 × 6 = 90

Then tο wοrk οut hοw many minutes mοre he needs tο read, yοu dο

500 − 90 = 410

Finally, tο wοrk οut hοw many minutes per day, yοu just divide 410 by the 6 days he's gοing tο read fοr. Sο yοu get the answer οf

\(\frac{205 }{3} = 68.\bar3\)

Hence, Billy needs an additiοnal 68.3 min. day tο cοmplete the 500 minutes in 6 days.

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Doane's rule is used for choosing the number of histogram bins, not for determining the minimum sample size needed for a multiple regression analysis.

However, a commonly cited rule of thumb is that the sample size should be at least 10 times the number of predictors, so for a multiple regression dataset with 3 predictors, a minimum of 30 observations may be recommended.

Doane's rule is a guideline for choosing the number of histogram bins based on the sample size and skewness of the data. It suggests that the number of bins should be approximately equal to 1 + log2(N) + log2(1 + |g1|/SE(g1)), where N is the sample size and g1 is the sample skewness.

It is important to note that Doane's rule is used for determining the number of bins for a histogram, not for determining the minimum sample size needed for a multiple regression analysis.

That being said, in general, the minimum sample size needed for a multiple regression analysis depends on a variety of factors, including the number of predictors, the strength of the relationships between the predictors and the outcome variable, the desired statistical power, and the level of significance. There is no set minimum sample size that applies to all situations. However, a commonly cited rule of thumb is that the sample size should be at least 10 times the number of predictors, so for a multiple regression dataset with 3 predictors, a minimum of 30 observations may be recommended.

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The total surface area of solid $pqrswxyz$ is $1300$ square units

The total surface area of the frustum $pqrswxyz$ can be found by adding the surface areas of the two bases, the lateral surface area of the frustum, and the surface areas of the four triangular faces formed by connecting the midpoints of the edges of the square base.

To find the total surface area of the frustum $pqrswxyz$, we need to calculate the surface areas of its components and add them together.

1. Bases: The frustum has two bases, the larger square base $pqrs$ and the smaller square base $wxyz$. The surface area of a square is given by $s^2$, where $s$ is the length of its side. Therefore, the surface area of the larger base is $20^2 = 400$, and the surface area of the smaller base is $(20/2)^2 = 100$.

2. Lateral Surface Area: The lateral surface area of the frustum is the sum of the areas of the four trapezoidal faces. Each trapezoid can be divided into two triangles and a rectangle. The area of a trapezoid is given by the formula $\frac{1}{2}(a + b)h$, where $a$ and $b$ are the lengths of the parallel sides and $h$ is the height. In this case, the height of the frustum is the same as the height of the pyramid, which is the distance from the apex to the base. Since the pyramid's total surface area is given as $1200$, the lateral surface area of the frustum is $1200 - 400 - 2(100) = 600$.

3. Triangular Faces: The frustum has four triangular faces formed by connecting the midpoints of the edges of the square base. Each triangular face is an isosceles right triangle with legs of length $10$ (half the side length of the base). The area of an isosceles right triangle is $\frac{1}{2}(a^2)$, where $a$ is the length of the legs. Therefore, the total surface area of the four triangular faces is $4 \cdot \frac{1}{2}(10^2) = 200$.

Finally, we add up the surface areas of the bases, the lateral surface area, and the triangular faces to find the total surface area of the frustum:

Total Surface Area = Base 1 + Base 2 + Lateral Surface Area + Triangular Faces

                 = 400 + 100 + 600 + 200

                 = 1300

Hence, the total surface area of solid $pqrswxyz$ is $1300$ square units.

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Answer:

It's C

Step-by-step explanation:

Because I'm BIG-BRAINED

The average velocity for the time period beginning when t = 2 and lasting is:  -19.016 ft/sec. The instantaneous velocity of the ball when t = 2 is: 19 ft/sec.

Velocity = 45-32t

When t=2

v(2) = 45-32(2)

v(2) =45-64

v(2) = -19 ft per second ( downward direction)

Velocity=45-32t

When t=2.1

v(2.1) = 45-32(2.1)

v(2.1) = 45-67.2

v(2.1) = -22.2 ft per second

Average velocity from t=2 to t=2.1

Average velocity= (-19-22.2)/2

Average velocity= -41.2/2

Average velocity=-20.5 ft/sec

Velocity=45-32t

When t=2.001

v(2.001) = 45-32(2.001)

v(2.001) = 45-64.032

v(2.001)  = -19.032.

Average velocity from t=2 to 2.001

Average velocity = (-19-19.032)/2

Average velocity  = -19.016 ft/sec

Velocity=45-32t

When t=2.0001

v(2.0001) = 45-32(2.0001)

v(2.0001) =45-64.0032

v(2.0001)  = -19.0032

Average velocity from t=2 to 2.0001

Average velocity= (-19-19.0032)/2

Average velocity = -19.0016 ft/sec

b. Instantaneous v at t=2

Instantaneous = -19 ft/sec

Therefore The average velocity for the time period beginning when t = 2 and lasting is:  -19.016 ft/sec. The instantaneous velocity of the ball when t = 2 is: 19 ft/sec.

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Answer:

-2 times (y + 7)

Step-by-step explanation:

first, -2 times the sum of y and 7.

(y + 7)

altogether = -2 times (y + 7)

The pattern for the 6th term of the sequence is A₆ = 36

Given data ,

The first term has one dot (1² = 1)

The second term has four dots (2² = 4)

The third term has nine dots (3² = 9)

The fourth term has sixteen dots (4² = 16)

So , the fifth term A₅ = 25

And , from the pattern , the 6th term A₆ = 36

Hence , the 6th term is A₆ = 36

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Answer:

(5×0.16)+ (1× 0.56) +(1 ×0.45)

Answer:

Step-by-step explanation:

Given that:

First Option (Leasing)

250x - y + 4000 = 0

Expressing the equation in the Slope-Intercept Form y=mx+b, we have:

y=250x+4000

Second Option (Financing)

$400 for 0 months of ownership, (0,400), and $4400 for 10 months of ownership, (10, 4400).

First, we determine the slope of the line joining (0,400) and (10,4400)

\(Slope, m= \dfrac{4400-400}{10-0}= \dfrac{4000}{10}=400\)

We have:

y=400x+b

When y=400, x=0

400=400(0)+b

b=400

Therefore, the Slope-Intercept Form of the second option is:

y=400x+400

Significance

Part B

We notice from the graph that after 24 months, the cost for leasing and financing becomes the same ($10,000). Therefore, a consumer will be better off financing since the downpayment for leasing is higher.

i.e

9514 1404 393

Answer:

  6.01 m

Step-by-step explanation:

Apparently, the washing line is the hypotenuse of a right triangle with sides (2.1-1.7) = 0.4 m and 6 m. The Pythagorean theorem can be used to find its length.

  ab = √(0.4² +6²) = √36.16 ≈ 6.0133

The distance ab is about 6.01 m.

The absolute maximum of the function on the given interval is at x = 7, and the value is f(7) = 4^(3/4).

To determine the location and value of the absolute extreme values of the function f(x) = (x-3)^3/4 on the interval [-7, 7], follow these steps:

1. Find the critical points by taking the derivative of the function and setting it to zero.
2. Evaluate the function at the critical points and the endpoints of the interval.
3. Compare the function values to determine the absolute maximum and minimum.

Step 1: Find the critical points.
f(x) = (x-3)^(3/4)
f'(x) = (3/4)(x-3)^(-1/4)

Set f'(x) = 0
(3/4)(x-3)^(-1/4) = 0

There is no solution for x, so there are no critical points.

Step 2: Evaluate the function at the endpoints of the interval.
f(-7) = (-7-3)^(3/4) = (-10)^(3/4) = 10^(3/4) * (-1)^(3/4)
f(7) = (7-3)^(3/4) = 4^(3/4)

Step 3: Compare the function values.
f(-7) = 10^(3/4) * (-1)^(3/4)
f(7) = 4^(3/4)

Since (-1)^(3/4) is a complex number and f(7) is a real number, the absolute maximum occurs at x = 7.

The absolute maximum of the function on the given interval is at x = 7, and the value is f(7) = 4^(3/4).

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For a two-tailed hypothesis test about μ, we can use any of the following approaches except comparing the level of significance; to the confidence coefficient

To determine if the sample mean is substantially more than or significantly less than the population mean, a two-tailed hypothesis test is used. The area under both tails or sides of a normal distribution is what gives the two-tailed test its name.

Any of the following methods, with the exception of comparing the level of significance to the confidence coefficient, can be used for a two-tailed hypothesis test regarding. To create a confidence interval estimate for the population mean, approach (d) compares the level of significance which is a to the confidence coefficient which is 1- a. This method is employed to estimate the population parameter rather than test a hypothesis.

Complete Question:

For a two-tailed hypothesis test about μ, we can use any of the following approaches EXCEPT compare the _____ to the _____.

a.confidence interval estimate of μ; hypothesized value of μ

b.p-value; value of α

c.value of the test statistic; critical value

d.level of significance; confidence coefficient

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The interval where f is positive is \(0 \le x < 1.5\)

The missing function is added as an attachment

From the attached graph, the function f(x) is positive from x = 0 to x = 1.5

As an interval notation, this can be represented as:

\(0 \le x < 1.5\)

Hence, the interval where f is positive is \(0 \le x < 1.5\)

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\( \bf \underline{Given :}\)

\( \sf{• \: Principal \: (P) = \$ \: 2000}

\)

\( \sf{• \: Simple \: Interest \: (I) = \$ \: 1000}

\)

\( \sf{• \: Time \: (T) = 10 \: years}\)

\( \sf{• \: Interest \: Rate \: (R) = \: ?}\)

\( \bf \underline{Solution:-}\)

\( \sf {We \: know \: that, }\)

\(\bf \red{\bigstar{ \: I = PRT}}\)

\( \sf{⟹1000 = 2000 \times \frac{R}{100} \times 10 }\)

\( \sf{⟹1000 = \frac{R}{100} \times 20000}\)

\( \sf{⟹ \frac{R}{100} = \frac{1000}{20000} }\)

\( \sf{⟹R = \frac{1}{20} \times 100 }\)

\( \sf⟹ R = 5\)

\( \pink{\bf{Hence, \: the \: interest \: rate \: is \: 5 \: \%. }}\)

Answer:

x-12

Step-by-step explanation:

Let the variable be x

12 less than

x-12

Answer:

There are 2 solutions to square root x = 9

They are 3, and -3

Step-by-step explanation:

The square root of x=9 has 2 solutions,

The square root means, for a given number, (in our case 9) what number times itself equals the given number,

Or, squaring (i.e multiplying with itself) what number would give the given number,

so, we have to find the solutions to \(\sqrt{9}\)

since we know that,

\((3)(3) = 9\\and,\\(-3)(-3) = 9\)

hence if we square either 3 or -3, we get 9

Hence the solutions are 3, and -3

The book is opened to pages 11 and 12.

How to get the product of the page

x * (x + 1) = 132

Expanding the equation, we get:

x² + x = 132

To solve for x, we need to rewrite the equation as a quadratic equation:

x²+ x - 132 = 0

Now, we can factor the quadratic equation:

(x - 11)(x + 12) = 0

This equation has two solutions for x:

x = 11

x = -12

Since page numbers cannot be negative, we discard the second solution. Thus, the left-hand page number is 11, and the right-hand page number is 11 + 1 = 12.

So, the book is opened to pages 11 and 12.

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Answer:

x=0

Step-by-step explanation:

x+x-x=x-x

Answer:

x=0...........................................

The probability that chad gets at least 2 heads on 3 flips is 1/2 which was found using the sample space.

Given: To decide who will pay for lunch, Jeff and Chad decide to flip a coin three times. Chad chooses heads, and in order to win and have Jeff pay for his lunch, he must get heads at least twice out of three times.

Let,

H = Heads

T = Tails

Sample space =  {HHH, HTH,THH,TTH, HHT, HTT,THT,TTT​}

Total number of possible outcomes = 8

Probability that chad gets at least 2 heads is given as:

P(A)=P(getting two heads)+P(getting 3 heads)

= 3/8 + 1/8

= 4/8

= 1/2

Therefore,  the probability chad gets at least 2 heads on 3 flips is 1/2 which was found using the sample space.

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Answer:

the answer is parallelogram and rectangle

Step-by-step explanation:

because a Parallelograms are quadrilaterals with two sets of parallel sides. Since squares must be quadrilaterals with two sets of parallel sides, then all squares are parallelograms.A parallelogram is a rectangle.hope this helps if not let me know have a good day.

Answer:

Its the first one. Hope it helps

Step-by-step explanation:

Answer:

Intensity = 2500/x^2

6.25 lumem

5 Feets

Step-by-step explanation:

Given the following :

Area (A) = 0.1x^2

Intensity, Energy and Area are related by the formular :

Intensity = power / Area

A) If 250 lumens of light energy is produced :

Intensity (I) = 250 / 0.1x^2

Intensity = 2500/x^2

x = distance

B) USING THE EQUATION :

1) What is the intensity of light on an object that is 20 feet from the spotlight source?

x = 20

Intensity = 2500/x^2

Intensity = 2500/20^2

Intensity = 2500/400

Intensity = 6.25 lumen

11) How far from the spotlight is an object that recieves 100 lumens of light per square foot?

Intensity = 100

100 = 2500 / x^2

100x^2 = 2500

x^2 = 2500/ 100

x^2 = 25

x = 5 Feets

The computed value of the test statistic is 2.94.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

We have a sample size of n = 12, engine size (x) and emissions (y) are the two variables being correlated, and the sample correlation coefficient is r = 0.47.

The null hypothesis is that the population correlation is zero (H0: ρ = 0) and the alternative hypothesis is that the population correlation is positive (Ha: ρ > 0).

To compute the test statistic, we need to first calculate the degrees of freedom (df), which is (n-2) = 10 in this case.

We can then use the formula for the test statistic, which is:

t = (r√(df)) / √1 - r²

Substituting the values we have, we get:

t = (0.47 √10) / √(1 - 0.47²)

t = 2.94

Therefore, the computed value of the test statistic is 2.94.

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The coordinate of point P is (1, 5).

Here we have to find the coordinate of the point P, which is on the line between x(-1,2) and y(7,14) which are partitions in the ratio 1:3.

The formula of the coordinate when two points are separated in the ratio m:n

Let a and b be the coordinate of P.

a = 7m + (-1)n/ m+n

b = 14m + 2n / m+n

Now put the value m: n as 1:3

a = 7×1 +(-1)×3/ 1+3

 = 7 - 3/ 4

 = 4/4

 = 1

b = 14×1 + 2×3/ 1 +3

  = 14 + 6/ 4

  = 20/4

  = 5

Therefore the coordinate of P is (1,5).

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As the sample size (n) increases, the power of the statistical test also increases.

The power of a statistical test measures the ability of the test to detect a true effect or reject a false null hypothesis. In this case, the investigator states that the power of his test at a significance level of 1% is 0.87. If the sample size (n) increases, the power of the test increases.

Increasing the sample size generally leads to an increase in the power of a statistical test. This is because a larger sample size provides more information and reduces the variability in the data. With a larger sample size, the test has a greater chance of detecting a true effect and rejecting the null hypothesis when it is false. Consequently, the power of the test increases.

In summary, as the sample size (n) increases, the power of the statistical test also increases. This is because a larger sample size enhances the test's ability to detect true effects and reject false null hypotheses, resulting in higher statistical power. Therefore, in this scenario, increasing the sample size would lead to an increase in the power of the test.

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The total dollar change in labor expense from this 15% increase in productivity is [calculated value]. The percent change in labor expense is [calculated value].

Part I: Effective cost per hour per employee

To calculate the effective cost per hour per employee, we need to consider various factors such as base wage, fringe benefits, paid time off, and the number of working hours per year.

Base hourly wage: $12.30 per hour

Number of working hours per day: 8 (1 shift)

Number of holidays: 5

Number of vacation days: 7

First, let's calculate the total fringe benefits per hour:

Fringe benefits = 37% of base wage = 0.37 * $12.30 = $4.551

Next, let's calculate the paid time off per hour:

Paid time off = (Number of holidays + Number of vacation days) * 8 hours = (5 + 7) * 8 = 96 hours

Now, let's calculate the effective cost per hour per employee:

Effective cost per hour = Base hourly wage + Fringe benefits + (Paid time off * Base hourly wage)

Effective cost per hour = $12.30 + $4.551 + (96 * $12.30)

Part II: Reduction in labor cost

To calculate the reduction in labor cost due to a 15% increase in productivity, we need to consider the total number of working hours needed and the change in productivity.

Number of working hours needed every year: 306,050

Productivity increase from 70% to 85%: 85% - 70% = 15%

First, let's calculate the initial number of workers needed:

Initial number of workers = Number of working hours needed / (Productivity rate / 100)

Initial number of workers = 306,050 / (70 / 100)

Next, let's calculate the new number of workers needed after the productivity increase:

New number of workers = Number of working hours needed / (New productivity rate / 100)

New number of workers = 306,050 / (85 / 100)

Finally, let's calculate the total dollar change in labor expense:

Total dollar change in labor expense = (Initial number of workers - New number of workers) * Effective cost per hour * Number of working hours per year

To calculate the percent change in labor expense, we can use the following formula:

Percent change in labor expense = (Total dollar change in labor expense / Initial labor expense) * 100

Please provide the values for Effective cost per hour and Initial labor expense to calculate the final answers in Part I and Part II.

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Answer: Priya practiced for 189 minutes

Tyler practiced for 123 minutes

-------------------------------------------------------------------------------------------------------------

The Explanation:  Now, Han spent 75 minutes practicing the piano over the weekend

Then, Priya practiced the violin for 152% as much time as Han practiced the piano.

Priya = 152% of 75 minutes + 75 minutes

= 152/100 × 75 + 75

= 1.52 × 75 + 75

= 114 + 75

= 189 minutes

Finally, Priya practiced for 189 minutes

-------------------------------------------------------------------------------------------------------------

Tyler practiced the clarinet for 64% as much time as Han practiced the piano.

Tyler = 64% of 75 minutes + 75 minutes

= 64/100 × 75 minutes + 75 minutes

= 64 / 100 × 75 + 75

= 0.64 × 75 + 75

= 48 + 75

= 123 minutes

Lastly, Tyler practiced for 123 minutes

 The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b). The y-coordinate is the value of b in the slope-intercept form. The Slope is - ⅖.

Y-intercept = (0, 4), where b = 4

Given the linear equation in standard form, 2x + 5y = 20, where A = 2, B = 5, and C = 20:

Start by transforming the standard equation into its slope-intercept form, y = mx + b, where m = slope, and b = y-intercept.

Subtract 2x from both sides:

2x -2x + 5y = - 2x + 20

5y = -2x + 20

Divide both sides by 5 to isolate y:

y = - ⅖x + 4 ⇒ This is the slope-intercept form where the slope, m = -⅖, and the y-intercept, b = 4.  The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b). The y-coordinate is the value of b in the slope-intercept form. Therefore, the y-intercept is (0, 4).

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