in a hockey game, player A passes the puck to player B, who is standing on the blue line, as shown in the diagram. The puck travels distance d1=24.1m on its way to player B, making an angle = 52.5 degrees with the x axis. Player B then passes the puck so that it moves d2=7.9m on the blue line in the negative x direction. A) What is the magnitude of the total displacement in meters? B) What angle, in degrees, does the total displacement make with the x axis?

Answer:

The focal length of the mirror is 10.4 cm.

Explanation:

So substitute the values of object distance and image distance in the mirror equation,

1/f = 1/(-18cm) + 1/(-25.0cm)

1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)

1/f = ( -25cm - 18cm)/(18cm x 25cm)

1/f = -43.0/450.0

f = -10.4651 cm.

The focal length of the mirror is approximately -10.4 cm.

To know more about Focal Length,

brainly.com/question/31755962

brainly.com/question/2194024

Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

Answer:

The original analog sound waves are perfect but the copy is not because most analog waves have wavelengths that are too long to reproduce in copies

The original digital waves and the copy are perfect because with digital waves no information gets lost in the transfer of data, and there is no additional noise added to the copy.

Analog refers to audio recorded using methods that replicate the original sound waves. Digital audio is recorded by taking samples of the original sound wave at a specified rate.

Explanation:

i dont need $5

i wrote this using information from go ogle and some from brai nly. I hope it helps.

Even before the advent of the telescope, ancient astronomers were able to observe the following:

1. Celestial Bodies: Ancient astronomers could observe celestial bodies such as the Sun, Moon, stars, and planets. They could track their movements across the sky and study their patterns and behaviors.

2. Solar and Lunar Eclipses: By carefully observing the positions of the Sun, Moon, and Earth, ancient astronomers could predict and witness solar and lunar eclipses. They noticed that during a solar eclipse, the Moon blocks the Sun's light, creating a temporary darkness on Earth, while during a lunar eclipse, the Earth casts a shadow on the Moon, causing it to appear reddish or darkened.

3. Stellar Positions: Ancient astronomers mapped and observed the positions of stars in the night sky. They recognized patterns and constellations, which helped them navigate and keep track of time.

4. Seasons and Celestial Movements: By observing the changing positions of the Sun and its daily and yearly motions, ancient astronomers could understand the changing seasons. They could determine solstices, equinoxes, and the length of days and nights.

5. Comet Appearances: Ancient astronomers were able to observe and document the appearance of comets in the night sky. They recognized these celestial objects as distinct from stars and noted their unusual and transient nature.

These observations formed the basis of ancient astronomy and laid the groundwork for the development of more advanced astronomical techniques and instruments, including the telescope.

For more such questions on telescope, click on:

https://brainly.com/question/30051913

#SPJ8

Answer:

To find the resultant force and its direction, we can use vector addition.

First, let's break down force B and force C into their horizontal and vertical components:

Horizontal component of force B:

Bx = 20N * cos(140°)

Vertical component of force B:

By = 20N * sin(140°)

Horizontal component of force C:

Cx = 16N * cos(290°)

Vertical component of force C:

Cy = 16N * sin(290°)

Now, let's add up the horizontal and vertical components of all the forces:

Horizontal component of resultant force:

Rx = Ax + Bx + Cx

Vertical component of resultant force:

Ry = Ay + By + Cy

To find the magnitude of the resultant force (R), we use the Pythagorean theorem:

R = sqrt(Rx^2 + Ry^2)

To find the direction (θ) of the resultant force, we can use the inverse tangent function:

θ = atan(Ry / Rx)

Plugging in the given values:

Ax = 12N (horizontal component of force A)

Ay = 0N (vertical component of force A)

Bx = 20N * cos(140°)

By = 20N * sin(140°)

Cx = 16N * cos(290°)

Cy = 16N * sin(290°)

Now let's calculate the values:

Bx = 20N * cos(140°) ≈ -11.55 N

By = 20N * sin(140°) ≈ 9.56 N

Cx = 16N * cos(290°) ≈ 13.82 N

Cy = 16N * sin(290°) ≈ -5.45 N

Rx = 12N + (-11.55N) + 13.82N ≈ 14.27 N

Ry = 0N + 9.56N + (-5.45N) ≈ 4.11 N

R = sqrt(14.27^2 + 4.11^2) ≈ 14.98 N

θ = atan(4.11 / 14.27) ≈ -15.58°

The magnitude of the resultant force is approximately 14.98 N, and the direction is approximately -15.58° (or approximately -45° to force A).

Note: The negative sign indicates that the resultant force is in the opposite direction to force A.

The mass of the picture is approximately 5.19 kilograms.

The deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).

The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:

τ = G * γ

To find the weight of the picture, we need to calculate the shear stress first:

The cross-sectional area A of the nail is given by the formula for the area of a circle:

A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².

The shear strain γ is given by:

γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.

The shear stress τ can now be calculated by rearranging the formula:

τ = G * γ

=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²

The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:

τ = F / A

=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.

Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:

m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.

So, the mass of the picture is approximately 5.19 kilograms.

Read m oe on shear deformation here:https://brainly.com/question/30407832

#SPJ1

Answer:

1620000J

Explanation:

Given parameters:

Resistance  = 24ohm

Current  = 5A

Time  = 45min

Unknown:

Work done = ?

Solution:

Electrical work done is given as the product of power with time;

  Electrical work done  = power x time

     Power  = I²R

 Electrical work done  = I²R x time

Convert the given time to seconds;

          1min  = 60s

          45 min  = 45 x 60  = 2700s

Now,

  Work done  = 5² x 24 x 2700 = 1620000J

Assuming that the arrow is launched vertically upward with an initial velocity v and air resistance is negligible, the time the arrow is in the air until it returns to launch height can be expressed as:

t = 2v/g

To know more about air resistance , check out :

https://brainly.com/question/14877316

#SPJ1

Answer:

Explanation:

Units...Nothing is accurate without UNITS. 8.0±0.3 lbs,? Newtons? 3.5±0.2 m²? ft²? cm²? km²? furlong²? fathoms²?

your answer will be  8.0±0.3 / 3.5±0.2  units / units²

Taking the positive direction to be to the right,  the total momentum of this system is - 14kg-m/s

Option B is correct.

momentum is described as the product of the mass and velocity of an object and a vector quantity possessing a magnitude and a direction.

momentum = mass x velocity

momentum 1  = 5 x 8kg = 40 kg-m/s

momentum 2 = 4 x 15 kg = 60 kg-m/s

momentum 3 = 2 x 3kg = 6 kg-m/s

Taking the positive direction to be to the right,  the total momentum of this system is momentum 1  - momentum 2 + momentum 3

total momentum =  40 kg-m/s - 60 kg-m/s + 6 kg-m/s

total momentum  = -20kg-m/ + 6 kg-m/s

total momentum =  - 14 kg-m/s

Learn more about momentum at: https://brainly.com/question/1042017

#SPJ1

When acceleration is equal to zero average velocity and the instantaneous velocity vectors are identical.

Types of velocity

Velocity is defined as the rate of displacement of an object with respect to time. It is measured in meter/ seconds and is a vector quantity.

Acceleration is defined as the rate at which velocity changes with time.

There are two types of velocity which includes:

Average velocity: This is the average rate of change of position of particles with respect to time over an interval.

Instantaneous velocity: This is defined as the specific rate of change of position with respect to time at a particular point.

The situation that will make the average velocity and the instantaneous velocity vectors to be equal or identical is when acceleration is equal to zero.

Four point masses 2kg, 4kg, 6kg and 8kg are placed at the corners of Square ABCD of 2cm long respectively. the Position of center of mass of the system from the corner A. is (1 , 1.4 ) cm.

Considering A as it origin

center of mass along X axis

\(X = \frac{M_{a}r_{a} + M_{b}r_{b} + M_{c}r_{c} + M_{d}r_{d} }{M_{a} + M_{b} + M_{c}+ M_{d}}\)

X = 2×0+4×2+6×2+8×0 ÷ (2+4+6+8)

X = 20 ÷ 20 = 1 cm

\(Y = \frac{M_{a}r_{a} + M_{b}r_{b} + M_{c}r_{c} + M_{d}r_{d} }{M_{a} + M_{b} + M_{c}+ M_{d}}\)

Y = 2×0+4×0+6×2+8×2 ÷ (2+4+6+8)

Y = 28 ÷ 20 = 1.4 =cm

The position of the center of the mass from the corner A which is the origin is (1 , 1.4 ) cm.

To know more about Mass :

https://brainly.com/question/19694949

#SPJ1.

Answer:

5 V

Explanation:

V = IR

V = .25A * 20 Ohms = 5 V

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

For more such information on: mean

https://brainly.com/question/1136789

#SPJ8

Answer:

towards the center of the circle

(which appears to be the last option in your list of possible answers)

Explanation:

The centripetal force points always towards the center of the circle described by the object moving.

The direction of centripetal force acting on an object is always towards the center of the circle in which the object is moving.

The given problem is based on the concept and fundamentals of centripetal force. When an object is known to move around a circular path, then there is a force comes to play acting towards the centre of circular path, known as centripetal force.

Thus, we can conclude that the direction of centripetal force acting on an object is always toward the center of the circle in which the object is moving.

Learn more about the centripetal force here:

https://brainly.com/question/14249440

Answer:

5778.1931

Explanation:

Given that:

Mass (M) = 5.98 x 10^24 kg

Radius (r) = 6.96 x 10^6 m

Gravitational constant (G) = 6.67 * 10^-11

Using the relation:

T² / R³ = 4π² / GM

Where T = period of orbit

T = 2π√(R³ /GM)

T = 2π√((6.96 x 10^6)³) /(6.67 * 10^-11) * (5.98 x 10^24)

T = 2π√((3.37153 * 10^20) / (39.866 * 10^13))

T = 2π √845715.64

T = 2π * 919.62799

T = 5778.1931

The maximum torque that the crane can withstand is 512.1 N.

To calculate the maximum torque that the crane can withstand, we need to find the force produced by the load and the distance from the axis of rotation to the line of action of this force.

And also the distance from the axis of rotation to the line of action of the force = horizontal component of the arm length

The horizontal component of the arm length is given by:

r =  Lcos(θ)

Finally, the maximum torque that the crane can withstand is given by:

τ = F r

τ = 520 N x cos ( 10 )

τ = 512.1 N

Learn more about maximum torque here: https://brainly.com/question/15236339

#SPJ1

Answer: A

Explanation: We know that f=p*n

f=50*300=15000 Hz = 15kHz.

Have a great day! <3

If the number of revolutions is 300 and the paired poles are 50 , then the frequency would be 15 kHz, therefore the correct answer is option A.

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

The frequency of a pendulum is the reciprocal of the time period can be given by the following relation,

F = 1 / T

As given in the problem, we have to calculate frequency if the number of revolutions is 300 and the paired poles are 50.

F = 300 × 50

  = 1500 kHz

Thus, If the number of revolutions is 300 and the paired poles are 50, then the frequency would be 15 kHz, therefore the correct answer is option A.

Learn more about frequency here, refer to the link given below ;

brainly.com/question/14316711

#SPJ2

Answer:

a gas that contributes to the greenhouse effect by absorbing infrared radiation, e.g., carbon dioxide and chlorofluorocarbons.

hope it helps

(a) The magnitude of A is 14  and magnitude of B is 14.2.

(b) The magnitude of A - B is 19.95.

(c) The sum of A and B is 7i + 18j + 5k

(d) The magnitude of A + B is 19.95.

The magnitude of A and B is calculated as follows;

| A | = √ ( 4² + 6² + 12² )

| A | = 14

| B | = √ ( 3² + 12² + 7² )

| B | = 14.2

The magnitude of A - B is calculated as follows;

A - B = ( 4i + 6j + 12k ) - (3i + 12j - 7k)

A - B = ( i  - 6j + 19 k )

|A-B| = √ (1² + 6² + 19²) = 19.95

The sum of A and B is calculated as follows;

A + B = ( 4i + 6j + 12k ) + (3i + 12j - 7k)

A + B = ( 7i  18j + 5k )

The magnitude of A + B is calculated as follows;

|A+B| = √ (7² + 18² + 5²) = 19.95

Learn more about magnitude of vectors here: https://brainly.com/question/3184914

#SPJ1

torque divided by moment of inertia = angular acceleration inertia = radius squared times mass = 7.533

16.2 ÷ 7.533 = 2.15

The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

For more question gas

https://brainly.com/question/31549188

#SPJ8

Answer:

Explanation:

To find the current flowing in the circuit, we can use Ohm's Law and Kirchhoff's circuit laws.

Ohm's Law states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):

I = V / R

In this case, the voltage (V) is the electromotive force (EMF) of the current source, which is 14 V. The total resistance (R) in the circuit is the sum of the internal resistance (r) and the resistances of the two resistors (R1 and R2):

R = r + R1 + R2

Given that the internal resistance (r) is 1Ω and each resistor (R1 and R2) has a resistance of 3Ω, we can substitute these values into the equation:

R = 1Ω + 3Ω + 3Ω = 7Ω

Now we can calculate the current (I):

I = V / R = 14 V / 7Ω = 2 A

Therefore, the current flowing in the circuit is 2 Amperes.

Answer:

i think i am late but b is 3

Explanation:

Answer:

Yes it is matter

Explanation:

In physics, usually the word "electricity" isn't really used. "Electric current" is more common, and is defined as the flow of charges, where the charges are held by particles (electrons). Electrons have mass, so they are definitely matter.

In 7.5 s, 4200 waves will pass a given point. Then, the frequency of the waves is 560 Hz.

Frequency is the number of cycles or oscillations of a wave that occur in one second, measured in Hertz (Hz). It is the rate at which a wave completes a full cycle, which is usually measured as the number of wavelengths that pass a fixed point in a unit of time.

The formula for frequency is;

frequency = waves/time

Where "waves" is the number of waves that pass a given point and "time" is the time it takes for those waves to pass.

In this case, we know that 4200 waves pass a given point in 7.5 seconds, so we can plug those values into the formula;

frequency = 4200/7.5

Simplifying;

frequency = 560

Therefore, the frequency of the waves is 560 Hz.

To know more about frequency here

https://brainly.com/question/14316711

#SPJ1

Answer:

This question heavily relies on the weight of the table and the weight of the person sitting on it, if a 90 pound person sits on the side of a 40 pound table, it will topple over.

Explanation: Tables are generally have a 50/50 weight distribution ratio so that they are even on the ground and can stay upright, but if a table is too light and the person or object sitting on it is heavier than the side they/it is placed on, it will fall.

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.