In a freezing point depression experiment, 1.25 grams of an unknown compound is dissolved in 50.0 grams of carbon tetrachloride, CCl4. The resulting freezing temperature of this mixture was -26.52 degrees Celsius. What is the molar mass of this unknown compound? Kf(CCl4) = 29.9 degrees Celsius/m; Freezing point(CCl4) = -22.90 degrees Celsius.

The net ionic equation can be given as Sn²⁺ (aq) + S²⁻ (aq) → SnS (s).

The atoms or molecules on losing or gaining electrons in order to achieve the stable configuration results in the formation of positive or negative charge and are termed as ions.

The ionic equation can be given with the formation of the respective ions of the reactant and the product side.

SnSO₄ (aq) → Sn²⁺ (aq) + SO₄²⁻ (aq)

Na₂S (aq) → 2 Na⁺ (aq)  + S²⁻ (aq)

SnS (s) → did not dissociates as form a solid covalent compound

Na₂SO₄ (aq) → 2 Na⁺ (aq)  + SO₄²⁻ (aq)

The complete ionic equation can be given as:

Sn²⁺ (aq) + SO₄²⁻ (aq) + 2 Na⁺ (aq)  + S²⁻ (aq) → SnS (s)  2 Na⁺ (aq)  + SO₄²⁻ (aq)

Eliminating the common ions on the product and the reactant side:

Sn²⁺ (aq) + S²⁻ (aq) → SnS (s)

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The aromatic ring in phenacetin exhibits an AB pattern because it has two mutually coupled nuclei that are unrelated to other protons or whose shift differences is equal to the coupling constant.

Deshielding occurs for the ring protons of benzene due to their larger chemical shift (7.3 ppm vs. 5.6 ppm for the vinylic protons in cyclohexene) and the fact that the magnetic field induced outside of the ring is the same orientation as that of the external field.

Protons are present in benzene at levels of 6–8 ppm.This value is larger than that of the protons in those other hydrocarbon like alkanes & alkenes because of the aromatic ring's deshielding effect.

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Answer: first you have to calculate the amount ionized. We will say it is x mol / L

then % ionization = (amount ionized / initial concentration) * 100%

x can be calculated using an ice chart

HC3H5O2           -----> H+    + C3H5O2-

Initial HC3H5O2 = 0.250  

change              = -x

equilibrium         = 0.250 - x

initial H+            = 0

change              = +x

equilibrium         = x

C3H5O2- initial   = 0

change              = +x

equilibrium         = x

Ka         = [H=][C3H5O2-] / HC3H5O2]

 1.3 * 10 ^ -5    = [x][x] / (0.250 - x)  

So 1.3 * 10 ^ -5 * (0.250 - x)   = x ^ 2  

     3.25 * 10^ -6 - (1.3 * 10^-5)x = x^2   now this is a quadratic equation and you have to rearrange it and solve for x

x^2 + 1.3 * 10^-5)x - 3.25 * 10^ -6 = 0

use the equation x = {-b (+ or -)[b^2 - 4.a.c] ^ 1/2} / 2a

you should get x = 1.80 * 10 ^ -3 or x = -1.80* 10^-3

but x can not be negative..

so x = 1.80 * 10 ^ -3

so percent ionization = (1.80 * 10 ^ -3 / 0.250) * 100%

                               =0.72 %

the other way which is more easier is  

assuming that x is very small and therefore 0.250 - x is approximately equals to 0.250  

then 1.3 * 10^-5 = x^2 / 0.250

so x^2    = 1.3 * 10^-5 * 0.250

        x   = 1.80 * 10 ^-3

then percent ionization is = (1.80 * 10 ^ -3 / 0.250) * 100%

                               =0.72 %

if the percent ionization is > 5 % you can not do that approximation. in such a case you have to solve the quadratic equation. that is why I showed both methods.

now you can do the parts b and c

b answer : percent ionization = 1.27 %  

c answer : 2.54%

good luck

Answer:

We would need to give approximately 15 tablets to the animal.

Explanation:

To solve this problem, we need to first convert the weight of the animal from pounds to kilograms by dividing by 2.205. Then, we can use the desired dosage and weight in kilograms to calculate the total amount of medication needed. Finally, we can divide the total amount of medication needed by the amount of medication per tablet to determine the number of tablets needed.

So, let's start with converting the weight of the animal from pounds to kilograms:

```

54 pounds ÷ 2.205 = 24.49 kilograms (rounded to two decimal places)

```

Next, we can calculate the total amount of medication needed:

```

24.49 kg × 150 g/kg = 3,673.5 g (rounded to one decimal place)

```

We can convert the amount of medication needed from grams to tablets by dividing by the amount of medication per tablet:

```

3,673.5 g ÷ 250 g/tab = 14.69 tablets (rounded up to the nearest whole tablet)

```

Answer:

The q value for this process is -241.69 kJ.

Explanation:

To calculate the q value, we need to use the equation:

q = m * c * ΔT

where:

q is the heat energy absorbed or released,

m is the mass of the substance,

c is the specific heat capacity of the substance,

ΔT is the change in temperature.

In this case, the mass of the water (m) is given as 0.523 kg, the change in temperature (ΔT) is 23°C, and the specific heat capacity of water (c) is approximately 4.18 kJ/kg°C.

Substituting the values into the equation:

q = 0.523 kg * 4.18 kJ/kg°C * 23°C

q = 5.46 kJ * 23°C

q = -125.58 kJ

The negative sign indicates that heat is being released from the water as it cools. Therefore, the q value for this process is -125.58 kJ or approximately -241.69 kJ (rounded to two decimal places).

Answer: The final pressure is 12.6 atm

Explanation:

The combined gas equation is,

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)

where,

\(P_1\) = initial pressure of gas = 5.6 atm

\(P_2\) = final pressure of gas = ?

\(V_1\) = initial volume of gas = v

\(V_2\) = final volume of gas = \(v-\frac{50}{100}v=0.5v\)

\(T_1\) = initial temperature of gas = \(-19.0^0C=(-19+273)K=254K\)

\(T_2\) = final temperature of gas = \(12.0^0C=(12.0+273)K=285K\)

Now put all the given values in the above equation, we get:

\(\frac{5.6\times v}{254}=\frac{P_2\times 0.5v}{285}\)

\(P_2=12.6atm\)

The final pressure is 12.6 atm

A change in the entropy of a system indicate that the disorder of the system has changed. Option A

A change in entropy indicates is a measure of the disorder, or randomness, in a system.

An increased value of entropy means more disorder, and a decreased value of entropy means less disorder.

These changes in entropy occur spontaneously

Thus, a change in the entropy of a system indicate that the disorder of the system has changed. Option A

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Answer:

\(T=-75.59\°C\)

Explanation:

Hello!

In this case, since we can treat neon as an ideal gas, it is possible for us to use the following equation:

\(PV=nRT\)

Whereas the temperature is out unknown, so we proceed as follows:

\(T=\frac{PV}{nR}\)

However, we need the moles of neon in 0.02 kg as shown below:

\(n=0.02kg*\frac{1000g}{1kg}*\frac{1mol}{20.17g} =0.992mol\)

Thus, we obtain the following temperature in Kelvins:

\(T=\frac{6.43atm*2.5L}{0.992mol*0.08206\frac{atm*L}{mol*K}} \\\\T=197.56K\)

Therefore, in degree Celsius it is:

\(T=197.56-273.15\\\\T=-75.59\°C\)

Best regards!

The compound that has the greatest polarity is CH3-CH2-CH2-CH2-CH2-OH

The polarity of a compound refers to the distribution of electric charge within the molecule. It depends on the electronegativity difference between the atoms in the molecule. Electronegativity is the ability of an atom to attract electrons towards itself.

Polarity is an important concept in chemistry and has implications for the physical and chemical properties of compounds, including solubility, boiling points, and reactivity.

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Answer:

A

Explanation:

Answer: the molarity of 0.650 mol of Na2 in 1.50 L of solution is 0.433 M.

Explanation: the molarity of 0.650 mol of Na2 in 1.50 L of solution is 0.433 M.

The safety feature aimed at keeping nuclear radiation contained is steel-reinforced concrete.

A nuclear power plant is a building with reactors that contain controlled nuclear reactions to produce energy.

Nuclear power plants are able to generate warm water by using atomic properties of matter  (i.e.,m the process of nuclear fission), which is in turn converted into steam to move turbines.

The walls of nuclear power reactors are composed of steel-reinforced concrete in order to avoid radiation release.

In conclusion, the safety standard property that maintains nuclear radiation contained is steel-reinforced concrete.

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Answer:

im gonna say b

Explanation:

Answer:

A. -423.346 °F, 20.18 K

B. -40°F, 233.15K

C. 1947.2 °F, 1337.15 K

Explanation:

A.

(-252.97 °C × 9/5) + 32 = -423.346 °F

-252.97 °C + 273.15 = 20.18 K

B.

(-40 °C × 9/5) +32 = -40 °F

-40 °C + 273.15 = 233.15 K

C.

(1064 °C ×9/5) + 32 = 1947.2 °F

1064 °C + 273.15 = 1337.15 K

The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.

Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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Answer:

solid X contains only ionic bond, and solid Y contains only covalent bonds.

Explanation:

solid X contains only ionic bond, and solid Y contains only covalent bonds. Because ionic compounds they have high melting point compared to covalent compounds, ionic compound they are generally insoluble in non polar solvent such as toluene but soluble in polar solvent such as water, ionic compound they conduct electricity.

Answer:

Yes, a precipitate will form when solutions of potassium sulfate (K2SO4) and barium nitrate (Ba(NO3)2) are combined. When these two solutions are mixed, a double displacement reaction occurs, which results in the formation of solid barium sulfate (BaSO4) and aqueous potassium nitrate (KNO3).

The balanced chemical equation for the reaction is:

Ba(NO3)2 + K2SO4 -> BaSO4 + 2KNO3

In this reaction, the barium cations (Ba2+) and sulfate anions (SO42-) combine to form insoluble barium sulfate (BaSO4), which precipitates out of the solution as a white solid. The potassium cations (K+) and nitrate anions (NO3-) remain in solution as aqueous potassium nitrate.

Explanation:

It is worth noting that barium sulfate is a highly insoluble compound, which makes it an excellent candidate for use in diagnostic imaging tests, such as barium sulfate X-ray tests, because it does not dissolve in water or organic solvents.

The precipitate that forms is solid barium sulfate (BaSO4), which is insoluble in water and appears as a white solid.

Answer:

1,2,1,1

Explanation:

Answer:

Explanation:

For the pH value of a buffer solution , the Henderson formula given is as follows

pH = pKa + log [ A⁻] / [AH ]

Now let us discuss about the phosphoric and succinic acid . The phosphoric acid has a pKa value of 2.3 and for succinic acid , the pKa value is 4.2 . The pKa value of succinic acid is more close to 5 . So to achieve pH value of 5 , succinic acid is a better alternative . The value of  [ A⁻] / [AH ]  is kept almost equal to 1 to increase the buffer capacity .

Answer:

The concentration of Mg3P2 solution = 0.24mol/L

Explanation:

Mass = 81.1g

Volume = 2.5L

Concentration (C) of a solution = \(\frac{Moles (n)}{Volume (V)}\)

but moles = \(\frac{mass}{Molar mass}\)       and      Molar mass of Mg3P2 = 134.88g/mol

Moles = \(\frac{81.1g}{134.88g/mol}\)

          = 0.60mol

hence the concentration can be calculated by;

C =  \(\frac{0.60mol}{2.5L} \\\)

  = 0.24mol/L or 0.24M

Taking into account definition of percent yield, the percent yield for the reaction is 76.25%.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

\(percent yield=\frac{actual yield}{theorical yield}x100\)

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

In this case, you know:

Replacing in the definition of percent yields:

\(percent yield=\frac{1.22 mol}{1.60 mol}x100\)

Solving:

percent yield= 76.25%

Finally, the percent yield for the reaction is 76.25%.

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The student's method for preparing pure crystals of copper sulfate contains errors and does not produce the desired outcome.

Use copper oxide instead of calcium carbonate: The student should add copper oxide (CuO) to the hydrochloric acid instead of calcium carbonate. Copper oxide reacts with hydrochloric acid to form copper chloride, which can then be converted to copper sulfate through a subsequent reaction with sulfuric acid.

Add sulfuric acid to the copper chloride solution: After the copper chloride solution is formed, the student should add sulfuric acid to it. This reaction between copper chloride and sulfuric acid will yield copper sulfate and hydrochloric acid. The student should ensure that the correct stoichiometric ratio is maintained to maximize the yield of copper sulfate crystals.

Crystal formation: The student should allow the solution to cool slowly after the reaction with sulfuric acid. This promotes the formation of larger, well-defined copper sulfate crystals.

Filtration and drying: Once the crystals have formed, the student should filter the solution to separate the solid crystals from the remaining liquid. The filtered crystals should then be thoroughly dried to remove any remaining water, resulting in pure copper sulfate crystals.

By following these improvements, the student can obtain pure crystals of copper sulfate.

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The standard reduction potential of the Cr³+/Cr electrode is -0.46V. None of the option is correct.

To determine the standard reduction potential of the Cr³+/Cr electrode, we can use the Nernst equation, which relates the standard reduction potential to the cell potential under non-standard conditions. The Nernst equation is given by:

E = E° - (0.0592/n) * log(Q)

where E is the cell potential, E° is the standard reduction potential, n is the number of electrons transferred in the half-reaction, and Q is the reaction quotient.

In this case, we have the standard potential of the cell as −0.60V. We know that the standard reduction potential of the Sn/Sn²+ electrode is -0.14V. Therefore, the reduction potential of the Cr³+/Cr electrode can be calculated as:

E = -0.60V - (-0.14V)

E = -0.60V + 0.14V

E = -0.46V

Therefore, the standard reduction potential of the Cr³+/Cr electrode is -0.46V.

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Answer:

1) 61.8%

Explanation:

(4.2/6.8)*100

The rate of a reaction refers to how fast or slow a reaction progresses over time. Option B is correct.

It is a measure of the change in concentration of reactants or products per unit of time. The rate of a reaction can be expressed in different units, such as moles per liter per second or grams per second. Factors that can affect the rate of a reaction include the concentrations of the reactants, the temperature, the presence of a catalyst, and the surface area of the reactants.

The rate law equation, which expresses the dependence of the reaction rate on the concentrations of the reactants, can also be used to determine the rate of a reaction under different conditions. The rate of a reaction is important for many applications, such as designing chemical reactions for industrial processes, optimizing reaction conditions in laboratories, and understanding biological processes that involve chemical reactions. Option B is correct.

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Answer:

I think the answer is 12.0107 u and 6 (6 as the atomic number) and (12.0107 u as the atomic mass).

Explanation:

I Hope this helps.

Answer:b zinc ,d=7.14g/

Explanation: