Therefore, the wavelength of the incident x-rays is approximately 0.771 nm using integration.
This is an application of Bragg's law in X-ray crystallography. When a beam of X-rays is incident on a crystal, it can be diffracted by the crystal's atoms, producing constructive interference between the waves scattered by different atoms. Bragg's law relates the wavelength of the X-rays, the angle of incidence, and the distance between the crystal planes to the angle at which the X-rays are diffracted:
nλ = 2d sin(θ)
where n is an integer representing the order of the reflection, λ is the wavelength of the X-rays, d is the distance between the crystal planes, θ is the angle of incidence, and 2θ is the angle at which the X-rays are diffracted.
In this case, a first-order reflection maximum is observed, which means that n=1. The distance between the crystal planes is given as 0.114 nm, and the angle of incidence is 31.1 degrees. We can rearrange Bragg's law to solve for the wavelength of the X-rays:
λ = 2d sin(θ)/n
Substituting the given values, we get:
λ = 2(0.114 nm) sin(31.1 degrees)/1 = 0.071 nm
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The area of a rectangle 12x^2 + 32x square units. If the width can be represented by 3x + 8, write an expression to represent the length of the rectangle.
Answer:
Step-by-step explanation:
The area of a rectangle is length time width.
A=LW
In this case,
A=32x^2+12
W=4x
Solve for L
L=A/W
Substitute
L=(32x^2+12)/4x
L=(8x^2+3)/x
8. Find (f+g)(x) if f(x) = 4x² - 5x and g(x) = 3x² + 6x - 4.
\( {\qquad\qquad\huge\underline{{\sf Answer}}} \)
Here we go ~
\(\qquad \sf \dashrightarrow \: (f + g)(x)\)
\(\qquad \sf \dashrightarrow \: f(x) + g(x)\)
\(\qquad \sf \dashrightarrow \: (4 {x}^{2} - 5x) + (3 {x}^{2} + 6x - 4)\)
\(\qquad \sf \dashrightarrow \: 7 {x}^{2} + x - 4\)
at least how many hours of sleep do students ages seven to twelve need per night
A seven
b eight
C nine
d ten
Answer:
10 hours
Step-by-step explanation:
ok
Suppose you invest $3500 at annual interest rate of 2.5 % How much money do you have in the account after five years?
Round two decimal places.
compounded monthly $ ____
compounded weekly $ _____
Answer:
Please check the explanation.
Step-by-step explanation:
To find the amount we use the formula:
\(A=P\cdot \left(1+\frac{r}{n}\right)^{nt}\)
Here:
A = total amount
P = principal or amount of money deposited,
r = annual interest rate
n = number of times compounded per year
t = time in years
Given
P=$3500
r=2.5%
n=12
t = 5 years
Calculating compounded monthly
After plugging in the values
\(A=3500\left(1+\frac{2.5\%\:}{12}\right)^{12\cdot \:5}\)
\(A=3500\left(1+\frac{0.025}{12}\right)^{12\cdot \:5}\)
\(A=3500\cdot \frac{12.025^{60}}{12^{60}}\)
\(A = 3959.93\)
Thus, If you deposit $3500 into an account paying 2.5% annual interest compounded monthly, you will have $3959.93 after five years.
Calculating compounded weekly
n = 52
\(A=3500\left(1+\frac{2.5\%\:}{52}\right)^{52\cdot \:5}\)
\(A=3500\left(1+\frac{0.025}{52}\right)^{52\cdot \:5}\)
A = 3,965.90
Thus, If you deposit $2000 into an account paying 4.5% annual interest compounded weekly, you will have $3,965.90 after five years.
What is nine more than 10 groups of three
Answer:
39
Step-by-step explanation:
10 groups of 3 equals 30 so just add the 9 and that equals 39
true or false? "Because in a randomized controlled trial (RCT), the assignment is random, therefore there is no coverage bias---by definition" g
The statement "Because in a randomized controlled trial (RCT), the assignment is random, therefore there is no coverage bias---by definition" g is false because, it is important to consider both randomization and other factors when assessing the potential for bias in an RCT.
Random assignment in an RCT can help to reduce selection bias, but it does not guarantee the absence of coverage bias.
Coverage bias can occur if the participants who are enrolled in the trial do not represent the population to which the results will be generalized.
For example, if the trial only includes participants who are healthier or more compliant than the typical patient, the results may not be applicable to the broader population.
Therefore, it is important to consider both randomization and other factors when assessing the potential for bias in an RCT.
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What a deal! Just deShirts is having a 20% off sale. Trixie rushes to the store and buys 14 shirts. When the clerk rings up her purchases, Trixie sees that the clerk has added the 5% sales tax first, before taking the discount. Trixie wonders whether adding the sales tax before the discount makes her final cost more than adding the sales tax after the discount. Without making any calculations, make a conjecture. Is Trixie getting charged more when the clerk adds sales tax first? The next few problems will help you figure it out for sure.
Does it matter if sales tax is added before the discount or after her final total? (Yes or no AND why or why not?)
Answer:
no because she would get the same total if she added it before or after
Step-by-step explanation:
A line segment whose endpoint are on the circle is called a __________ of a circle .
Chord
Radius
Tangent
Diameter
A line segment whose endpoint are on the circle is called a __________ of a circle.
Chord
Radius
Tangent
Diameter
Answer: Chord
Rewrite in simplest terms: (10x-5)-(8x-6)
Answer:
2x-1
Step-by-step explanation:
(10x-5)-(8x+6)
10x-8x-5+6
2x-1
Find the slope between the points (3,8) and (5,-1).
Answer:
i gotchuuu
Step-by-step explanation:
slope is 9/-2. this is because i used the slope formula y2-y1 over x2-x1. hope this helped :)
work out the value of (3.5 x 10^6) ÷ (5 x 10^-3) give your answer in standard form.
The standard form of (3.5 x 10^6) ÷ (5 x 10^-3) is 7*10^8
What is standard form?Any number that we can write as a decimal number, between 1.0 and 10.0, multiplied by a power of 10, is said to be in standard form.
Given:
(3.5 x 10^6) ÷ (5 x 10^-3)
On further solving
3.5 * 10^(6 -(-3)) / 5
3.5* 10^9 /5
0.7 * 10^9
7*10^8
Hence, the standard form is 7*10^8.
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Which statements are true about the functions y sin (c), y D sin (c) and y sin(2), y sin (z), y = sin (c), y = sin (2) and y = The graphs of y The domains of y = The amplitudes of y The periodela v Both y sin (2) and y on that interval. decreasing cos (x), and y tan (z)? cos (z) do not have midlines. cos (2), and y = tan (2) are all real numbers. cos(x), and y tan (z) are 1. cos (2) are 27, and the period of y – tan (I) is T. cos (x) is tan (x) are increasing on the interval (0,), and y
The true statements regarding the trigonometric functions are given as follows:
The periods of y = sin(x) and y = cos(x) are of 2π, while the period of y = tan(x) is of π.Both y = sin(x) and y = tan(x) are increasing on the interval (0, π/2), while y = cos(x) is decreasing on the same interval.What are the correct statements?The three trigonometric functions are defined as follows:
y = sin(x).y = cos(x).y = tan(x).The statements are described as follows:
Statement 1 is false, as tan(x) = sin(x)/cos(x), hence the tangent function is not defined when cos(x) = 0 at x = kπ/2, k = ± 1, ±3, ..., and it's domain is not all real values.Statement 2 is false, as the tangent function does not have an amplitude, as close to the vertical asymptotes it assumes values close to infinity.Statement 3 is false, as the sine function and the cosine function have a midline.The remaining statements are true.
Missing InformationThe statements are given by the image shown at the end of the answer.
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Help me please (NO WRONG ANSWERS!) Pictures below
Rick is taking a 1-mile ride on his bicycle. For each rotation of his tire, he travels 72 inches. How many rotations will his tire make during the 1-mile trip?
Answer:
880 rotations
Step-by-step explanation:
Answer:
880 rotations
Step-by-step explanation:
A rock is 7 feet below the surface of a river. If its position can be recorded as -7, what would the position of 0 represent?
A. On the surface of the river
B. At the bottom of the river
C. 7 feet above the surface of the river
D. 7 feet below the surface of the river
Solve by elimination.
5x - 6y = 27
7x + 6y = 9
Show work pls
Answer:
x = 3y = - 2Step-by-step explanation:
5x - 6y = 27 .......... Equation 1
7x + 6y = 9 ………… Equation 2
To solve using elimination add the second equation to the first one to eliminate y
That's
5x - 6y + 7x + 6y = 27 + 9
12x + 6y - 6y = 36
12x = 36
Divide both sides by 12
x = 3
Substitute it into any of the equations
Using equation 2
That's
7(3) + 6y = 9
21 + 6y = 9
6y = - 12
Divide both sides by 6
y = - 2
The solutions are
x = 3
y = - 2
Hope this helps you
A circle has a diameter of 25.3 inches. What is the circumference of the circle? Round to the nearest hundredth.
Show work.
Answer:
73in to the nearest inch
Step-by-step explanation:
r=d/2
r=25.3/2
r=11.6cm
C=2πr
C=πd
C=22/7×25.3
C=72.51
C=73 to the nearest inch
Given f(x)=x^3+kx-4, and x-1 is a factor of f(x), then what is the value of k?
Answer:
3
Step-by-step explanation:
If x-1 is a factor, then x=1 is a solution. So:
0=1³+1k-4
1k=3
k=3 .........
For the given trinomial that has the factor (x -1), k = 1,
What is Polynomial?A polynomial is a mathematical equation that solely uses the operations addition, subtraction, multiplication, and non-negative integer exponentiation of variables. Variables are sometimes known as indeterminate in mathematics. Majorly used polynomials are binomial and trinomial.
Given a trinomial equation:
f(x)=x^3+kx-4
And also given it has a factor (x - 1)
Thus, at x = 1 the value of the f(x) will be 0
So,
f(x) = x^3 + kx - 4
f(1) = 1^3 + k*1 - 4
0 = 1 + k -4
k = 3
therefore, The value of k = 1 for the given Trinomial that has the factor (x -1)
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A company currently pays a dividend of $2.2 per share (D
0
=$2.2). It is estimated that the company's dividend will grow at a rate of 24% per year for the next 2 years, and then at a constant rate of 5% thereafter. The company's stock has a beta of 1.3, the risk-free rate is 9%, and the market risk premium is 4.5\%. What is your estimate of the stock's current price? Do not round intermediate calculations. Round your answer to the nearest cent.
The estimated current price of the stock is $57.83.
To calculate the stock's current price, we can use the dividend discount model (DDM). The DDM states that the price of a stock is equal to the present value of its future dividends.
In this case, the dividend is expected to grow at a rate of 24% per year for the next 2 years and then at a constant rate of 5% thereafter. We can calculate the dividends for the next two years as follows:
D1 = D0 * (1 + growth rate) = $2.2 * (1 + 0.24) = $2.728
D2 = D1 * (1 + growth rate) = $2.728 * (1 + 0.24) = $3.386
To find the price of the stock at the end of year 2 (P2), we can use the Gordon growth model:
P2 = D2 / (r - g) = $3.386 / (0.09 - 0.05) = $84.65
Next, we need to discount the future price of the stock at the end of year 2 to its present value using the required rate of return. The required rate of return is the risk-free rate plus the product of the stock's beta and the market risk premium:
r = risk-free rate + (beta * market risk premium) = 0.09 + (1.3 * 0.045) = 0.1565
Now, we can calculate the present value of the future price:
P0 = P2 / (1 + r)^2 = $84.65 / (1 + 0.1565)^2 = $57.83
Therefore, based on the given information and calculations, the estimated current price of the stock is $57.83.
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Lisa works two jobs to pay for college. She tutors for $21 per hour and also works as a delivery person for $16 per hour. Due to her class and study schedule, Lisa is only able to work up to 20 hours per week but must earn at least $195 per week. If T represents the number of hours Lisa tutors and D represents the number of hours she works as a delivery person, which system of inequalities represents this scenario?
The inequality that represents the hours which Lisa can work is t+b≥20, 21t+16b≥195
Given that,
Lisa has two jobs to help pay for her education. She earns $21 per hour as an instructor and $16 per hour as a delivery person. Lisa can only work up to 20 hours per week due to her class and study schedule, but she has to make at least $195 each week.
We have to find which inequality system best describes this situation if T is the amount of tutoring hours Lisa works and D is the number of delivery hours she works.
The inequality we get ,
t+b≥20
21t+16b≥195
Therefore, the inequality are t+b≥20, 21t+16b≥195
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Standard Appliances obtains refrigerators for $1,620 less 26% and 6%. Standard's overhead is 17% of the selling price of $1,690. A scratched demonstrator unit from their floor display was cleared out for $1,345. a. What is the regular rate of markup on cost? % Round to two decimal places b. What is the rate of markdown on the demonstrator unit? % Round to two decimal places c. What is the operating profit or loss on the demostrator unit? Round to the nearest cent d. What is the rate of markup on cost that was actually realized? % Round to two decimal places
a. The regular rate of markup on cost is approximately 26%.
b. The rate of markdown on the demonstrator unit is approximately 20%.
c. The operating profit on the demonstrator unit is approximately $3.73.
d. The rate of markup on cost that was actually realized is approximately 0.28%.
a. To calculate the regular rate of markup on cost, we need to find the difference between the selling price and the cost, and then calculate the percentage markup based on the cost.
Let's denote the cost as C.
Selling price = Cost + Markup
$1,690 = C + (26% of C)
To find the cost:
$1,690 = C + 0.26C
$1,690 = 1.26C
C = $1,690 / 1.26
C ≈ $1,341.27
Markup on cost = Selling price - Cost
Markup on cost = $1,690 - $1,341.27
Markup on cost ≈ $348.73
Rate of markup on cost = (Markup on cost / Cost) * 100
Rate of markup on cost = ($348.73 / $1,341.27) * 100
Rate of markup on cost ≈ 26%
The regular rate of markup on cost is approximately 26%.
b. The rate of markdown on the demonstrator unit can be calculated by finding the difference between the original selling price and the clearance price, and then calculating the percentage markdown based on the original selling price.
Original selling price = $1,690
Clearance price = $1,345
Markdown = Original selling price - Clearance price
Markdown = $1,690 - $1,345
Markdown = $345
Rate of markdown on the demonstrator unit = (Markdown / Original selling price) * 100
Rate of markdown on the demonstrator unit = ($345 / $1,690) * 100
Rate of markdown on the demonstrator unit ≈ 20%
The rate of markdown on the demonstrator unit is approximately 20%.
c. Operating profit or loss on the demonstrator unit can be calculated by finding the difference between the clearance price and the cost.
Cost = $1,341.27
Clearance price = $1,345
Operating profit or loss = Clearance price - Cost
Operating profit or loss = $1,345 - $1,341.27
Operating profit or loss ≈ $3.73
The operating profit on the demonstrator unit is approximately $3.73.
d. The rate of markup on cost that was actually realized can be calculated by finding the difference between the actual selling price (clearance price) and the cost, and then calculating the percentage markup based on the cost.
Actual selling price (clearance price) = $1,345
Cost = $1,341.27
Markup on cost that was actually realized = Actual selling price - Cost
Markup on cost that was actually realized = $1,345 - $1,341.27
Markup on cost that was actually realized ≈ $3.73
Rate of markup on cost that was actually realized = (Markup on cost that was actually realized / Cost) * 100
Rate of markup on cost that was actually realized = ($3.73 / $1,341.27) * 100
Rate of markup on cost that was actually realized ≈ 0.2781% ≈ 0.28%
The rate of markup on cost that was actually realized is approximately 0.28%.
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a statistics teacher started class one day by drawing the names of 10 students out of a hat and asked them to do as many pushups as they could. the 10 randomly selected students averaged 15 pushups per person with a standard deviation of 9 pushups. suppose the distribution of the population of number of pushups that can be done is approximately normal. if we would like to capture the population mean with 95% confidence the margin of error would be .
The true mean number of pushups that can be performed, as determined by the t-distribution, is within a 95% confidence interval of (9, 21).
Since we know the sample standard deviation for this issue, the t-distribution is applied.
Given,
The sample mean, x = 15 .
The sample standard deviation, s = 9 .
The sample size, n = 10 .
As a result, df = 9. Next, we determine the number of degrees of freedom, which is one less than the sample size.
The crucial value for a 95% confidence interval is then determined by looking at the t-table or using a calculator, yielding t = 2.2622.
The margin of error;
M = t × s/n
Then,
M = 2.2622 × 9/√10 = 6
The confidence interval is:
x ± M
Then
x - M = 15 - 6 = 9
x + M = 15 + 6 = 21
Therefore,
The confidence interval is (9, 21).
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Twenty pounds of strawberries are being shared equally by a group of friends. The equation 20\div4=520÷4=5 represents the division of strawberries.
If the 5 represents the pounds of strawberries per person, what does the 4 represent?
Answer: 4 represents the number of people.
Step-by-step explanation:
20 divided by 5 lbs each = 4 : number of people.
find the coefficient of x7 when the following expression is expanded by the binomial theorem. x7 in (3x +4)10 the term
The coefficient of x7 in the expansion of (3x + 4)10 is 53,248,000.
To find the coefficient of x^7 in the expansion of (3x + 4)^10 using the binomial theorem, we need to identify the term that has x^7.
The binomial theorem states that (a + b)^n = Σ (nCk) * a^(n-k) * b^k, where k goes from 0 to n and nCk denotes the binomial coefficient, which is the combination of choosing k items from n.
In our case, a = 3x, b = 4, and n = 10. We need to find the term with x^7, so the power of a (3x) should be 3 (since 3x raised to the power of 3 is x^7). This means the term will have the form:
10C3 * (3x)^3 * 4^(10-3)
Now we calculate the coefficients:
10C3 = 10! / (3! * (10 - 3)!) = 120
(3x)^3 = 27x^{7}
4^7 = 16384
Now, we multiply the coefficients together:
120 * 27 * 16384 = 53,248,000
Therefore, the coefficient of x^7 in the expansion of (3x + 4)^10 is 53,248,000.
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What are the coordThe general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 = 0.
The equation of this circle in standard form is
. The center of the circle is at the point
, and its radius is
units.inates for the center of the circle and the length of the radius?
The equation of this circle in standard form is (x-2)² + (y+3)² = 18
The center of the circle is at the point (2,-3), and its radius is 4.2426 units
What is circle?Circle is the 2D geometry which is round in shape with radius R.
Given is the general form of the equation of a circle is
7x² + 7y² − 28x + 42y − 35 = 0.
Dividing by 7, we get
x² -4x + y² + 6x = 5
Completing the squares, we have
x² -4x + 4 + y² +6x + 9 = 5 +4 + 9
(x-2)² + (y+3)² = 18 = (3 √2)²
Circle's center is (2,-3) and radius = 3 √2 = 4.2426 units
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Answer:
(x-2)^2 + (y+3)^2 = 18,
2,-3
3(2^(1/2)) units
Step-by-step explanation:
Below
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Quadrilateral ABCD is graphed below. Part A. What are the coordinates of each vertex of quadrilateral ABCD if the y-axis is the line of reflection Part B: What are the coordinates of each vertex of quadrilateral ABCD if the x-axis is the line of reflection.
Answer:
see explanation
Step-by-step explanation:
part A
under a reflection in the y- axis
a point (x, y ) → (- x, y ) , then
A (- 6, 11 ) → (6, 11 )
B (- 5, 6 ) → (5, 6 )
C (- 7, 1 ) → (7, 1 )
D (0, 8 ) → (0, 8 ) ← no change
part B
under a reflection in the x- axis
a point (x, y ) → (x, - y ) , then
A (- 6, 11 ) → - 6, - 11 )
B (- 5, 6 ) → (- 5, - 6 )
C (- 7, 1 ) → (- 7, - 1 )
D (0, 8 ) → (0, - 8 )
some tests are developed using criterion groups. others are developed using factor analysis and/or theory. list one test which used each developmental strategy
One test that used criterion groups as a developmental strategy is the Graduate Record Examinations (GRE). The GRE is a standardized test commonly used for admission into graduate programs in various fields. During the development of the GRE, a criterion group strategy was employed.
The criterion group strategy involves selecting a group of individuals who are already deemed successful or proficient in the field being assessed. In the case of the GRE, the criterion group consisted of graduate students who were performing well academically. The test developers administered the test to this group of high-achieving individuals and analyzed their performance to establish a benchmark or criterion for success.
By examining the performance of the criterion group, the test developers were able to identify the types of questions and content areas that distinguished successful students from those who were less successful. This information was then used to design the test items and determine the scoring criteria for the GRE. The test was tailored to assess the knowledge and skills that were identified as important indicators of success in graduate-level study.
Now let's consider an example of a test that used factor analysis and/or theory as a developmental strategy. The Minnesota Multiphasic Personality Inventory (MMPI) is a psychological assessment tool that used factor analysis and theory during its development.
The MMPI is a widely used personality test that assesses various aspects of an individual's personality, psychopathology, and clinical disorders. It was developed by Starke R. Hathaway and J.C. McKinley in the late 1930s. In the development process, they employed a combination of factor analysis and theoretical considerations.
Factor analysis is a statistical technique used to identify underlying dimensions or factors that explain the relationships among a set of observed variables. In the case of the MMPI, factor analysis was utilized to identify the main dimensions or factors of personality and psychopathology that the test should measure. Through extensive data analysis and item selection, the test developers identified several key factors, such as depression, hypochondriasis, hysteria, and social introversion.
Additionally, the developers of the MMPI incorporated theoretical considerations in the selection and construction of the test items. They drew upon existing theories and knowledge in the field of personality and psychopathology to guide their item selection process. The test items were designed to capture the manifestations of specific personality traits and clinical symptoms that were theoretically relevant.
The combination of factor analysis and theoretical considerations allowed the developers of the MMPI to create a comprehensive and reliable instrument for assessing personality and psychopathology. The test has undergone several revisions and updates over the years, but its foundation in factor analysis and theory has remained integral to its development and continued use in psychological assessment.
In summary, the GRE utilized the criterion group strategy during its development, where the performance of successful graduate students served as a benchmark for test design. On the other hand, the MMPI employed factor analysis and theoretical considerations to identify key dimensions of personality and psychopathology, resulting in a comprehensive assessment tool. Both tests demonstrate the application of different developmental strategies to ensure the validity and reliability of the assessments.
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What type of decimal is this fraction: LaTeX: \frac{11}{20}
terminating
neither
both
repeating
11/20
Divide 11 by 20 to find the decimal value.
11/20 = 0.55
The decimal only contains two numbers, so it is a terminating fraction.
Find the value of each variable.
Simplify your answers as much as possible.
If necessary, you may learn what the markings on a figure indicate.
Answer:
Step-by-step explanation:
In circle O, and are diameters. The measure of arc AB is 55° and the measure of arc CD is 25°.
Circle O is shown. Line segments A D and B E are diameters. Line segments O F and O C are radii.
What is the measure of Arc E A C?
Your Answer Is in this attachment.
Answer:
D-212 Degrees
Step-by-step explanation
i got it right on edge