In a covalent bond between fluorine and oxygen, the oxygen atom will be partially negative (i.e. has the greater electronegativity).
A covalent bond is an electron exchange that causes the production of electron pairs between atoms. These electron couples are referred to as bonding pairs or sharing pairs. When atoms share electrons, the attractive and repulsive forces between them come to a stable equilibrium, known as covalent bonding. Because electrons are shared among several molecules, each atom can reach the equivalent of a full valence shell, resulting in a stable electronic state. In organic chemistry, covalent bonds are much more common than ionic bonds.
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Weight is a measure of the pull of gravity on and object
Answer:
True.
Explanation:
You didn't provide an answer, but I'm assuming this is a T/F question.
A Blood Test Indicates The Presence Of A Particular Disease 93% Of The Time When The Disease Is Actually Present. The Same Test Indicates The Presence Of The Disease Given That The Test Indicates The Presence Of The Disease. Give Your Answer In Decimal Form, Rounding To Four Decimal Places.
Given that a blood test indicates the presence of a particular disease 93% of the time when the disease is actually present, and we want to find the probability of the presence of the disease when the test indicates the presence of the disease.We can solve the problem by using Bayes' theorem. The probability of the disease being present when the test indicates the presence of the disease would be 0.1167 (rounded to four decimal places).
Bayes' theorem states that:
P(A|B) = P(B|A) × P(A) / P(B)
Where;P(A|B) is the probability of A occurring given that B has occurred.
P(B|A) is the probability of B occurring given that A has occurred.
P(A) is the probability of A occurring.
P(B) is the probability of B occurring
.Using the above notation, let;
A = Presence of the disease.
B = The blood test indicates the presence of the disease.
P(A|B) = The probability of the disease being present when the test indicates the presence of the disease.
P(B|A) = The probability of the blood test indicating the presence of the disease when the disease is present.
P(A) = The probability of the disease being present.
P(B) = The probability of the blood test indicating the presence of the disease.
When the test indicates the presence of the disease, the possible outcomes are:
Presence of the disease when the test indicates the presence of the disease.Presence of the disease when the test indicates the absence of the disease.No presence of the disease when the test indicates the presence of the disease.No presence of the disease when the test indicates the absence of the disease.The probability of the blood test indicating the presence of the disease when the disease is present is 93% or 0.93.P(B|A) = 0.93
The probability of the disease being present is not given in the problem statement, but we can assume it to be a small probability. Hence, we will assume P(A) to be 0.01 or 1%.P(A) = 0.01
To find the probability of the blood test indicating the presence of the disease, we can use the law of total probability. The possible outcomes when the test indicates the presence of the disease are presence and absence of the disease, i.e.,P(B) = P(B|A) × P(A) + P(B|not A) × P(not A)P(not A) = 1 - P(A) = 1 - 0.01 = 0.99P(B) = 0.93 × 0.01 + P(B|not A) × 0.99
We know that the blood test indicates the presence of a particular disease 93% of the time when the disease is actually present. Hence, we can assume that the blood test indicates the presence of the disease 7% of the time when the disease is not present.
P(B|not A) = 0.07P(B) = 0.93 × 0.01 + 0.07 × 0.99 = 0.0796
Using Bayes' theorem:
P(A|B) = P(B|A) × P(A) / P(B)P(A|B) = 0.93 × 0.01 / 0.0796 = 0.1166 ≈ 0.1167
Hence, the probability of the disease being present when the test indicates the presence of the disease is 0.1167 (rounded to four decimal places).
Answer: 0.1167
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NAME
HOUR
Multiple Choice Virtual 3
1. (4.10) Which atom has the greatest nuclear charge (positive charge in the nucleus)?
a. Ar
C. S
b. Si
d. Mg
the combustion of 40.5 mg of a compound extracted from the bark of the sassafras tree and known to contain c, h, and o produces 11.0 mg co2 and 22.5 mg of h2o. the molar mass of the compound is 162 g.mol. what is the molecular formula?
If the combustion of 40.5 mg of a substance taken from the bark of the sassafras tree and known to include c, h, and o results in 11.0 mg co2 and 22.5 mg of water, the molecular formula is C5H502 = C10H10O2.
The amount of substance removed from the sassafras tree's bark was 40.5 mg, while the amount of CO2 produced was 110.0 mg.
obtained water mass = 22.5g
Calculation of C, H, and O percentages
12 g of Carbon is present in 44 g of CO2. Similarly 2 g of H is present in 18 g of water. Using this we calculate
Percentage of C = 12/44 x Mass of CO2 / Total mass of Compound X 100 = 12/44 x 110.0/40.5 x 100 = 74.07
Percentage of H =2/18 x Mass of H2O / Mass of compound = 2/18 x 22.5/40.5 x 100 = 6.17
Percentage of O =100-6.17-74.07=19.76 ( As compound contains only C H and O)
Calculation of emperical formula
Element Percentage No of Atoms Relative atomic ratio whole no . composition ratio
C 74.07 74.07/12 = 6.1725 6.1725/1.235 = 4.9975 5
H 6.17 6.17/1 = 6.17 6.17/1.235 = = 4.9959 5
O 19.76 19.76 /16 = 1.235 1.235/1.235 = 1 1
Hence, Emperical Formula is C5H50
Molecular mass of compound = 162g/mol
Emperical mass = 60+5+16=81g/mol
So multiplying factor (n) = Molar mass/emperical mass= 162/81=2
So Molecular formula= C5H502 = C10H10O2
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If 16.4 g of oxygen gas react with excess hydrogen, how many moles of water are produced?
2H2(g) + O2(g) → 2H2O(g)
Answer:
1.02 (or 1.03 if rounded)
Explanation:
Given 16.4 grams of oxygen gas, you would want to write that down to set up your unit conversions.
16.4 g O2/1 * 1 mol of O2/31.998 g O2 * 2 mol H2O/1 mol O2
Multiply the numbers on the top and divide that by the product of the numbers on the bottom.
16.4 * 1 * 2 = 32.8
1 * 31.998 * 1 = 31.998
32.8/31.998 = 1.025...
Don't forget to consider the number of significant figures if it asks!
In this activity, you will be observing a reaction where copper and silver nitrate react to form copper (II) nitrate and silver.
What are the products of this reaction?
Answer:
Copper(II) nitrate and silver
Explanation:
2AgNO₃(aq ) + Cu (s) --> Cu(NO₃)₂(aq ) + 2Ag(s)
This can be called a redox reaction because silver nitrate is reduced and copper is oxidized. This can also be called a single replacement reaction because copper replaces silver in the substance silver nitrate.
A gas collected from a reaction has a mass of 1.211 g and occupies a volume of 0.677 L. The temperature in the laboratory is 296 K, and the air pressure is 0.987 atm. Calculate the molar mass of the gas.
23.7 g/mol
44.0 g/mol
58.5 g/mol
82.3 g/mol
Answer: 44.0 g/mol
Explanation:
\(M=m.RT/PV\)
M=1.211*0.082*296/ 0.987*0.677
M= 44 g/mol
A gas collected from a reaction has a mass of 1.211 g and occupies a volume of 0.677 L. The temperature in the laboratory is 296 K, and the air pressure is 0.987 atm the molar mass of the gas 23.7 g/mol. option A is correct.
What is gas law?The universal gas law given by Boyle, Charles , Avogadro and Gauss known as combined gas law with respect to temperature, volume and pressure using universal gas constant and number of moles.
According to universal gas equation or combined gas equation
P V = n R T
where , P = pressure
V = volume
n = number of moles
R = universal gas constant = 8.313
T = temperature
n = W / M.M
W = weight
M.M = molar mass
substituting the value in the equation
0.987 × 0.677 = 1.211 / M.M × 8.313 × 296
M.M = 23.7 g/mol
Therefore, gas collected from a reaction has a mass of 1.211 g and occupies a volume of 0.677 L. The temperature in the laboratory is 296 K, and the air pressure is 0.987 atm the molar mass of the gas 23.7 g/mol. option A is correct.
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why is it useful to group large number of things?
what is -56 0C to 0F
-56 degree C when converted to degree F will be equal to -68.8 degree F.
What is degree?Degree is defined as a unit of measurement that is used to measure angles, and also longitude and latitude.
The Celsius scale start from 0 while the Fahrenheit scale start from 32 degree F which is equal to 0 degree C.
On the basic of the concept the formula is
F = 9/5 C + 32
Thus by using formula we get
F = 9/5(-56) + 32
F = 9(-11.2) + 32 = -100.8 + 32
F = -68.8
Thus, the correct answer of -56 degree C to °F is -68.8 degree F.
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An ion has 26 protons, 28 neutrons, and 24 electrons. Which element is this ion? a. Xe b. Ni c. Fe d. Mg e. Cr
The ion that has 26 protons, 28 neutrons, and 24 electrons is Iron (Fe) (option c).
An element can be determined by the number of protons in the nucleus of its atom. The number of protons present in an atom is referred to as the atomic number of the element.
This means that the number of protons in an atom is unique to a specific element.
Iron (Fe) has 26 protons in the nucleus of its atom.
Therefore, an ion with 26 protons is an ion of the element iron (Fe).
Magnesium (Mg) has 12 protons, Chromium (Cr) has 24 protons, Xenon (Xe) has 54 protons and Nickel (Ni) has 28 protons.
Thus, an ion which has 26 protons, 28 neutrons, and 24 electrons is Fe (option c)
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How does the conductivity of metalloids compare to the conductivity of metals and nonmetals?
Metalloids conduct electricity better than metals, but not as well as nonmetals.
Metals, metalloids, and nonmetals all have the same level of conductivity.
Metalloids conduct electricity better than nonmetals, but not as well as metals.
Metalloids cannot conduct electricity.
The conductivity of metalloids can be compared to the conductivity of metals and nonmetals because metalloids conduct electricity better than nonmetals, but not as well as metals (Option C).
What are metalloids?The expression metalloids is a term used to denote chemical elements that have features resembling metals such as an acceptable electrical conductivity, but they are not metals (e.g. boron, germanium, antimony, arsenic, polonium, etc).
Therefore, with this data, we can see that metalloids are similar to metals in electrical conductivity but they are not metals because they do not fit all properties of metals.
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Why do industries use metallic compounds to make wires?
Select all that apply.
Responses
metallic compounds often have high luster
metallic compounds often have high luster
metallic compounds are ductile
metallic compounds are ductile
metallic compounds have high boiling points
metallic compounds have high boiling points
metallic compounds are good conductors of electricity
metallic compounds are good conductors of electricity
Answer:
metallic compounds are good conductors of electricity.
metallic compounds have high boiling points
What a bat hits a ball what is the impulse
Answer:
Plugging in the numbers we find the average force to be Favg=18,436 N, which is equivalent to 4124 lbs of force. The impulse delivered by this force is the product of the average force the the contact time, resulting in an impulse of 12.91 Ns.
Answer:
the force multiplied by the time the objects are in contact
Explanation:
took the quiz
In describing the structure of molecules, we use Lewis structures, formal charges, and experimental evidence. Rank these in terms of importance in deciding on the true structure of a molecule and defend your choice.
The ranking of terms importance in deciding on the true structure of a molecule:
Experimental evidence> Lewis structure> formal charge
In describing the structure of the molecule experimental evidence is of utmost importance followed by lewis structure and then formal charge.Experimental evidence is an inference of a practical technique that one will conduct to determine the original arrangement of atoms in a molecule by following a set of ordered steps.Evidence will give the real picture regarding the structure of the molecule as no guesswork or prediction is employed.Whereas Lewis structures and formal charge are the theoretical concepts that will only help in predicting the structure of a molecule which can be correct, partially correct, or wrong.So, from this, we can conclude that the ranking of terms importance in deciding on the true structure of a molecule:
Experimental evidence> Lewis structure> formal charge
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I will give brainiest how does a orange get its color
Answer:
by mixing red and yellow
Explanation:
Answer:
Either the sun or by mixing red and yellow together because they make orange.
Explanation:
Brainliest pls
Given the reaction C O2 Upper C plus Upper O subscript 2 right arrow upper C upper O subscript 2. CO2 which pair of reactions represents the two half-reactions? First: upper C right arrow upper C upper O subscript 2 plus 4 e superscript minus. Second: upper O subscript 2 plu 4 upper e superscript minus right arrow upper C upper O subscript 2. First: upper C plus 4 e superscript minus right arrow upper C upper O subscript 2. Second: upper O subscript 2 right arrow Upper C upper O subscript 2 plus 4 e superscript minus. First: upper C right arrow upper C upper O subscript 2 plus 2 e superscript plus. Second: upper O subscript 2 plus 2 e superscript minus right arrow upper C upper O subscript 2. First: upper C plus 2 e superscript minus right arrow Upper C upper subscript 2. Second: upper O subscript 2 right arrow upper C upper O subscript 2 plus 2 e superscript minus.
Answer:
ehh
Explanation:
mhh
Answer:
Answer Is A
Explanation:
A good conductor of heat
Pure substances are homogeneous substances made of identical particles called
Answer:
a pure substance
Explanation:
i hope i help if i didnt im srry:(
What is the pH of a buffer solution that is 0.15 M chloroacetic acid (C2H3ClO2) and 0.10 M sodium
chloroacetate? (Ka = 1.3 x 10-3) HA(aq) + H2O(l) A-(aq) + H3O+(aq)
The pH of a buffer solution that is 0.15 M chloroacetic acid (C2H3ClO2) and 0.10 M sodium
chloroacetate is 2.7.
What is buffer solution?Buffer Solution is defined as a water solvent based solution that is mostly consists of a mixture having weak acid and conjugate base of the weak acid, or in other word solution of a weak base and conjugate acid of the weak base.
The buffer solution always acidic or basic.
[H+] = Ka × [weak acid] / [salt] × valancy
[salt] = 0.10M
[weak acid] = 0.15M
Ka = 1.3 x 10-3
[H+] = 1.3 x 10-3 × 0.15/ 0.10
= 0.00195M
Now, as we know that
pH = -log[H+]
= -log(0.00195M)
= 2.7
Thus, we concluded that the pH of a buffer solution that is 0.15 M chloroacetic acid (C2H3ClO2) and 0.10 M sodium
chloroacetate is 2.7.
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Which statement best compares bacteria and fungi?
O Most bacteria and fungi are harmless and may be beneficial to other
living things.
Bacteria are living organisms, whereas, fungi are not.
Bacteria and fungi always cause infectious diseases.
Both bacteria and fungi rely on living organisms to reproduce and survive.
Answer:
Both bacteria and fungi rely on living organisms to reproduce and survive.
Most bacteria and fungi are harmless and may be beneficial to other
living things. So, the correct option is (A).
What are Bacteria and Fungi?Bacteria and fungi are two types of organisms that belong to different class of organisms while they are prokaryotic and eukaryotic in nature respectively. They are present in various life forms like parasitic (bacteria), saprophytic (fungi) etc. They are harmless in nature and can be beneficial to other living things as well.
They have mutual relationships with other living organisms, which are beneficial to both.
For example, some species of bacteria help fix nitrogen in the root nodules of leguminous plants, while fungi form a mutualistic relationship with algae called lichens where they benefit each other in one way or another.
Thus, most bacteria and fungi are harmless and may be beneficial to other living things. So, the correct option is (A).
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why might it be unwise to drink water straight from a pond
Answer:
it is because of the bacteria and different things that go into waters such as ponds, rivers, lakes, seas, oceans, streams, and other body of waters and I should also add the chemicals that go into them as well
Explanation:
A donut has a density of 0.75 g/cm cubed and a mass of 100.0g. What is the volume of the donut?
Answer:
133.333333333 cm^3
Explanation:
Volume = Mass/Density
concisely describe the differences between a perfect gas, calorically perfect gas, thermally perfect gas, and chemically reacting gas. generally, what are the temperature ranges for these flows at standard pressure for air for use within aeronautical engineering?
The differences between perfect gas, calorically perfect gas, thermally perfect gas, and chemically reacting gas are as follows:
Perfect gas is gas that obeys the ideal gas law in its physical behavior.Calorically perfect gas has a constant value as its specific heat capacity,Thermally perfect gas is gas that obeys the equation of state p = ρRT.Chemically reacting gas is gas that is undergoing a chemical reaction.The temperature ranges for air to flow at standard pressure to be used within aeronautical engineering are 1000K for perfect (ideal) gas. For thermally perfect gas, the temperature range should be between 1000K and 2500K. The air is chemically reacting once the temperature reaches 2500 K.
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4. Calculate the Density of a rectangular prism made of metal the dimensions of the prism are 5 cm by 4cm by 5cm. the metal has a mass of 50 grams
TRUE OR FALSE?
Solvents are the component in solutions with highest percent composition
Answer:
True
Explanation:
I think this is a helpful for you
Do you think direct democracy would work in the United States? Why or why not? please help me!!!!!!
Answer:
no, because our nation is just too big. it would be difficult to keep track of votes and find a common ground amongst all the people
calculate the volume in liters of a m potassium dichromate solution that contains of potassium dichromate . be sure your answer has the correct number of significant digits.
Incomplete question but using assumed values, the volume of m potassium dichromate solution that contains potassium dichromate is 9.1L
To calculate the volume of solution, we use the equation for molarity of solution:
Molarity of solution = mass of solute/molar mass of solute*volume of solution (in liter)
Where assumed values are:
Molarity of solution = 0.15 M
Given mass of potassium dichromate = 400. g
Molar mass of potassium dichromate = 294.15 g/mol
Volume solution in liter = x
i.e.
0.15 = 400/294.15*x
Volume of solution in liter = 400/294.15*0.15
Volume of solution in liter = 400/44.12
Volume of solution in liter = 9.06
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How many moles of sodium cyanide (NaCN) would be needed to
produce 4.2 moles of sodium sulfate (Na2SO4)? (4 points)
H2SO4 + 2NaCN → 2HCN + Na2SO4
O 2.1 mol NaCN
O 4.2 mol NaCN
O 8.4 mol NaCN
O 12.0 mol NaCN
Answer:
c
Explanation:
8.4
For the reaction H₂SO₄ + 2NaC≡N → 2HC≡N + Na₂SO₄, we have that 8.4 moles of sodium cyanide are needed to produce 4.2 moles of sodium sulfate (option C).
The reaction between sodium cyanide and sulfuric acid is:
H₂SO₄ + 2NaC≡N → 2HC≡N + Na₂SO₄
We can find the number of moles of sodium cyanide, assuming that it is the limiting reactant and knowing that 2 moles of it produce 1 mol of sodium sulfate, as follows:
\( n_{NaC\equiv N} = \frac{2\: moles\: NaC\equiv N}{1 \: mol\: Na_{2}SO_{4}}*4.2 \: moles\: Na_{2}SO_{4} = 8.4 \: moles \)
Therefore, 8.4 moles of sodium cyanide are needed to produce 4.2 moles of sodium sulfate (option C).
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According to the rules covered in this class, which of the following ionic compounds is named incorrectly?
cobalt(II) oxide
nickel(II) sulfide
copper(II) selenide
zinc(II) telluride
All of these names are correct.
Answer: is copper(ll)selenide
Explanation:
is copper (ll)selenide
i hope this help
I need help, please.
Mass of Barium = 720.73 g ; Mass of Phosphorus = 108.37 g ; Mass of Oxygen = 223.91 g
How to calculate masses?To determine the masses of barium, phosphorus, and oxygen in a sample of barium phosphate (Ba3(PO4)2), you need to calculate the formula weight of the compound and then multiply it by number of moles of compound in the sample.
First, calculate the formula weight of the compound:
Ba3(PO4)2 formula weight = (3 x 137.327 g/mol) + (2 x (30.97 g/mol + 4 x (16.00 g/mol)) = 601.9 g/mol
n = 1053.8 g / 601.9 g/mol = 1.75 mol
Mass of Barium = 3 x 137.327 g/mol x 1.75 mol = 720.73 g
Mass of Phosphorus = 2 x 30.97 g/mol x 1.75 mol = 108.37 g
Mass of Oxygen = 8 x 16.00 g/mol x 1.75 mol = 223.91 g
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