in a closed system, an object with a mass of 10 kg moves at a velocity of 5.4 m/s. it collides with a second object that has a mass of 12 kg and that is moving in the opposite direction with a velocity of 3.5 m/s. what is the total momentum of the system after the collision?(1 point) responses 42 kg-m/s

Answer:

1467 atoms

Explanation:

5730 yrs = carbon 14 half life

10 740 / 5730 = 1.87 half lives

400 = C (1/2)^1.87

C = original = ~1467 atoms

At a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa. Specific details to consider are Chalk Strength, Chalk Permeability, Chalk Heterogeneity.

Before proceeding with the excavation of the cavern beneath the sea, the main geological information that would be important to have includes the properties and characteristics of the chalk formation. Some specific details to consider are:

a) Chalk Strength: It is essential to determine the strength and stability of the chalk formation to ensure that it can support the excavation without collapsing or experiencing excessive deformation. This would involve assessing parameters such as the cohesion, friction angle, and compressive strength of the chalk.

b) Chalk Permeability: Understanding the permeability of the chalk is crucial, especially since the cavern will be beneath the sea. The permeability will impact the water flow within the chalk and may affect stability, seepage, and potential groundwater inflow into the excavation.

c) Chalk Heterogeneity: Chalk formations can exhibit variations in their composition, including the presence of layers or discontinuities such as faults or joints. Understanding the geological structure and heterogeneity of the chalk will help in assessing the potential for rock mass instability, water ingress, or the presence of other geological hazards.

To estimate the vertical and horizontal in-situ stresses at a depth of 500 meters in the mine, we can use the principles of rock mechanics and consider the given parameters.

Vertical Stress:

The vertical stress is the stress component acting vertically downward due to the weight of the overlying rock. It can be calculated using the average unit weight of the rock and the depth.

Vertical Stress = Unit Weight of Rock × Depth

Vertical Stress = 27 kN/m³ × 500 m

Vertical Stress = 13,500 kN/m² or 13.5 MPa

Horizontal Stress:

The horizontal stress can be estimated using the in-situ stress ratio, which is influenced by Poisson's ratio. The relationship between the horizontal and vertical stresses can be expressed as:

Horizontal Stress = Vertical Stress × (2 × Poisson's Ratio) / (1 - Poisson's Ratio)

Horizontal Stress = 13.5 MPa × (2 × 0.3) / (1 - 0.3)

Horizontal Stress = 13.5 MPa × 0.6 / 0.7

Horizontal Stress = 11.57 MPa

Therefore, at a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa.

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Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass in kg

v is the velocity in m/s

From the question

m = 20 kg

v = 2.5 m/s

From the question we have

\(k = \frac{1}{2} \times 20 \times {2.5}^{2} \\ = 10 \times 6.25 \\ = 62.5\: \: \: \: \: \: \: \: \: \: \)

We have the final answer as

Hope this helps you

The two compositions are: f( g(x) ) =  x  and g( f(x) ) = x

The inverse function is defined as a function obtained by reversing the given function.

We have given functions :

f(x) = 4/5x + 1

g(x) = (5x - 5)/4

Let's check if the functions are inverses.

f( g(x) ) =  4/5g(x) + 1 = 4/5{(5x - 5)/4} + 1 = (x - 1) + 1 = x

g( f(x) ) = (f(x) - 1)5/4 = (4/5x + 1 - 1)5/4 = x

So, f(x) and g(x) are inverses.

Hence, the two compositions are: f( g(x) ) =  x and g( f(x) ) = x

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A grain of sand with a mass of 170 mg, 670. um wide, moving at 4.00 mm/s - Classical.

Mass is the measure of an object’s inertia, or its resistance to changes in motion. It is a fundamental property of matter and is typically measured in kilograms. It is different from weight, which is a measure of the force of gravity acting on an object.

An eyelash mite with a mass of 13.5 µg, 270 um wide, moving at 31. um/s. - Quantum
An airplane with a mass of 1.88 x 10 kg, 14.0 m long, moving at 1500. km/h - Classical
A turtle with a mass of 480. g, 28. cm long, moving at 1.6 cm/s. - Classical
All of the objects in question are macroscopic, meaning that their behavior can be accurately described with classical mechanics. However, because the Planck constant is larger than its value in our universe, the eyelash mite is at the limit of being small enough to require quantum mechanics to describe its behavior. Therefore, it would be the only object that would require quantum mechanics in this alternate universe.

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Answer:

Maximum gravitational potential energy could occur at either the top of the first hill, or at the ball’s highest point on the second hill, depending on circumstances.

Answer:

The answer is C. Series.

The example provided, where Isaac Newton showed that the same laws govern motion in both realms of Earth and space, best fits the theory of explanation known as Causal Unifications'.

Causal Unifications theory aims to explain phenomena by identifying common causes or underlying principles that apply to seemingly distinct phenomena. In this case, Newton's discovery of the laws of motion demonstrated that the same fundamental principles govern both celestial and earthly motion.

To summarize, the example of Isaac Newton demonstrating that the same laws govern motion on Earth and in space aligns with the Causal Unificationist theory of explanation, which seeks to identify common causes or underlying principles that apply to seemingly distinct phenomena. By discovering the laws of motion, Newton provided a unified explanation for motion in both realms, challenging the previous belief in separate laws for celestial and earthly motion.

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The temperature of the inner surface of the window will be lower than the room temperature, 21°C.

The steady rate of heat transfer through a double-pane window is determined by the heat conduction through the glass layers, convection to the outdoor air, and convection to the room air. The temperature of the inner surface of the window will depend on the temperature difference between the outdoors and the room.

The heat transfer rate, Q, through the double-pane window can be calculated using the overall heat transfer coefficient U:

Q = U × (Area of window) × (Temperature difference)

The overall heat transfer coefficient can be calculated using the equation below:

U = 1/[(1/h1) + (L/k) + (1/h2)]

Where h1 and h2 are the convection heat transfer coefficients on the inner and outer surfaces of the window, respectively; L is the thickness of the air space between the two glass layers; and k is the thermal conductivity of the air space.

Given the parameters in the question, the overall heat transfer coefficient is calculated to be U = 1.30 W/m2K. Thus, the heat transfer rate through the double-pane window is

Q = 1.30 × (2.4 m × 1.5 m) × (26 K) = 72 W.

The temperature of the inner surface of the window can be calculated by considering the heat transfer balance between the room air and the outdoor air. The rate of heat transfer from the outdoors is

Qout = h2 × (2.4 m × 1.5 m) × (26 K) = 90 W.

The rate of heat transfer to the room air is

Qin = h1 × (2.4 m × 1.5 m) × (26 K) = 36 W.

Thus, the rate of heat transfer to the room air is 72 W - 90 W = -18 W.

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The two main methods employed to control the rotor speed of an induction machine are the Voltage control method and the Frequency control method.

Voltage control method: In this method, the voltage applied to the stator windings of the induction machine is controlled to regulate the rotor speed. By adjusting the magnitude and frequency of the applied voltage, the magnetic field produced by the stator can be controlled, which in turn influences the rotor speed. By increasing or decreasing the voltage, the speed of the rotor can be adjusted accordingly. This method is commonly used in applications where precise control of the rotor speed is not required.

Frequency control method: In this method, the frequency of the power supplied to the stator windings is controlled to regulate the rotor speed. By adjusting the frequency of the applied power, the synchronous speed of the rotating magnetic field can be varied, which affects the rotor speed. By increasing or decreasing the frequency, the rotor speed can be adjusted accordingly. This method is commonly used in applications where precise control of the rotor speed is required, such as variable speed drives and motor control systems.

Both voltage control and frequency control methods provide effective means of controlling the rotor speed of an induction machine, allowing for versatile operation and adaptation to various application requirements.

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Answer:

A wedge can split an object apart

A  lever is the seesaw

inclined plane is a ramp

a pulley can reduce the amount of friction

wheel and axle is the rope one

Explanation:

Following are the matches:

Simple machines are basic mechanical devices that can help make work easier by reducing the amount of force or effort needed to do a task. They are usually the most basic forms of machines, often made up of only one or two parts, and are used to change the direction or magnitude of a force.

There are six types of simple machines:

Simple machines are the building blocks for more complex machines, and they are used in many everyday devices and equipment to make work easier and more efficient.

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For the given mode values with n > 1, we will calculate the average frequency and uncertainty for each resonance based on the spread in the measured maximum and minimum sustainable frequencies are 33.3 Hz and 47.7 Hz.

For n = 2, the maximum sustainable frequency is 33.6 Hz, and the minimum sustainable frequency is 33.3 Hz. To calculate the average frequency, we take the average of these two values: (33.6 Hz + 33.3 Hz) / 2 = 33.45 Hz. The uncertainty is obtained by taking half of the difference between the maximum and minimum frequencies: (33.6 Hz - 33.3 Hz) / 2 = 0.15 Hz. Therefore, the average frequency for n = 2 mode is 33.45 Hz with an uncertainty of ±0.15 Hz. The fundamental frequency for this mode would be the minimum sustainable frequency, which is 33.3 Hz.

For n = 3, the maximum sustainable frequency is 48.9 Hz, and the minimum sustainable frequency is 47.7 Hz. Following the same procedure, the average frequency is (48.9 Hz + 47.7 Hz) / 2 = 48.3 Hz, and the uncertainty is (48.9 Hz - 47.7 Hz) / 2 = 0.6 Hz. Therefore, the average frequency for n = 3 mode is 48.3 Hz with an uncertainty of ±0.6 Hz. The fundamental frequency for this mode is 47.7 Hz.

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Algol is a binary star system consisting of two stars orbiting around their common center of mass.

The more massive star, Algol A, is still on the main sequence, while the less massive star, Algol B, has evolved into a red giant.

This difference in evolutionary stage can be explained by their initial masses and the difference in their ages.

The more massive a star is, the faster it consumes its nuclear fuel and progresses through its evolutionary stages. In the case of Algol, Algol A is more massive than Algol B, which means that it burns its nuclear fuel at a higher rate.

Algol B, being less massive, has a lower rate of energy production and a longer lifespan. As it exhausts the hydrogen fuel in its core, it expands and enters the red giant phase.

This expansion occurs as the core contracts and the outer layers of the star expand, causing it to become larger and cooler, leading to its classification as a red giant.

On the other hand, Algol A, being more massive, continues to burn hydrogen in its core at a faster rate, maintaining its high core temperature and pressure. As a result, it remains on the main sequence, where stars primarily burn hydrogen into helium through nuclear fusion.

The difference in evolutionary stage between the two stars in Algol is primarily determined by their masses and their different rates of energy production and consumption.

The more massive star progresses faster through its life cycle, while the less massive star evolves more slowly, leading to the difference in their evolutionary stages observed in the Algol binary system.

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Answer:

A) F_g = 8.9278 × 10^(-30)

B) F_e = 1.6 × 10^(-17) N upwards

C) F_m = 6.8 × 10^(-17) N downwards

Explanation:

A) Formula for gravitational force is;

F_g = m_e × g

m_e is mass of electron = 9.11 x 10^(-31) kg

F_g = 9.11 x 10^(-31) × 9.8

F_g = 8.9278 × 10^(-30) N downwards

B) Formula for Electric force is;

F_e = qe

q is charge on electron = 1.6 × 10^(-19) C

E is electric field = 100 N/C

F_e = 1.6 × 10^(-19) × 100

F_e = 1.6 × 10^(-17) N upwards

C) Magnetic force is given by the formula;

F_m = qVB

q is charge on electron = 1.6 × 10^(-19) C

V is velocity given as 8.50 × 10^(6) m/s

B is magnetic field = 50.0 μT = 50 × 10^(-6) T

F_m = 1.6 × 10^(-19) × 8.50 × 10^(6) × 50 × 10^(-6)

F_m = 6.8 × 10^(-17) N downwards

The heating curve is a representation of temperature change for a body with time as shown on cartesian axes.

The heating curve is a representation of temperature change for a body with time as shown on cartesian axes.

The point A represents the steady increase in the temperature of the solid. The point B shows the point of fusion, at this point, the solid is transformed into liquid. The point C shows the temperature rise with time as the liquid is heated. The point D shows the process of vaporization which converts the liquid to gas. The point E shows when the substance now exists in the gas phase.

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The particle is an electron. The field slows down the electron without deflecting it. The direction of the electric field is right.

In physics, the motion of electrically charged particles gives rise to a field called an electric field. It is measured in force per unit charge.

This field applies force on other charged particles.

Particles bearing opposite charges attract each other while particles having similar charges repel each other in the field.

If a positive charge is placed in the field then the field line moves in an outward direction and for a negative charge, the direction of the lines is inward.

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Answer:

1 Solid ball, no subatomic particles.

4 Solid ball of positive materials with electrons scattered throughout. (Plum Pudding Model)

3 # The atom is mostly empty space. A dense nucleus with protons and neutrons is in the center and electrons travel around it randomly.

2 A dense nucleus with protons and neutrons is in the center of the atom. The electrons travel around the nucleus in distinct energy levels.

Сл A dense nucleus with protons and neutrons in the center of the atom. The electrons are found in "electron clouds" which surround the nucleus. Electron cloud show where electrons are likely to be, but not exactly where they are.

Explanation:

1 Solid ball, no subatomic particles. This model was proposed by some Greek Philosophers and John Dalton in 1803. That matter was made up of small indivisible substances called atoms.

4 Solid ball of positive materials with electrons scattered throughout. (Plum Pudding Model). This model was proposed by JJ Thomson in 1904. That the atom contained a large positively charged ball with negative charges scattered about.

3 # The atom is mostly empty space. A dense nucleus with protons and neutrons is in the center and electrons travel around it randomly. This model was proposed by Ernest Rutherford in 1911. The center of the atom was dense and positively charged with protons and neutrons surrounded by electrons orbiting it and most of the space between the nucleus and the electron orbit empty.

2 A dense nucleus with protons and neutrons is in the center of the atom. The electrons travel around the nucleus in distinct energy levels. This model was proposed by Niels Bohr in 1913. This was due to the fact that atoms only emit light at certain wavelengths which would imply that they have discrete energy levels which the electrons are contained in.

Сл A dense nucleus with protons and neutrons in the center of the atom. The electrons are found in "electron clouds" which surround the nucleus. Electron cloud show where electrons are likely to be, but not exactly where they are. This model was proposed by Erwin Schrodinger in 1926 through the solution of the Schrodinger wave equation. The position of the electron is assumed to to be a probability in an electron cloud.

If the child's center of gravity is 3.57 m below the pivot, it would take approximately 3.791 seconds for the child to complete one swing.

The time it takes for a child on a swing to complete one swing depends on several factors, including the length of the swing's arm, the angle at which the swing is released, and the force exerted by the child to keep swinging. However, if we assume a simple idealized case, we can use a formula to estimate the time period of a pendulum.

The formula for the time period of a simple pendulum (which can be approximated to a swing) is:

T = 2π√(L/g)

Where:

T = Time period (in seconds)

π ≈ 3.14159 (pi)

L = Length of the pendulum arm (from pivot to center of gravity)

g = Acceleration due to gravity (approximately 9.8 m/s²)

In this case, you mentioned that the child's center of gravity is 3.57 m below the pivot. Assuming this refers to the length of the pendulum arm (L), we can use this value in the formula. Therefore:

L = 3.57 m

g = 9.8 m/s²

Plugging in these values, we can calculate the time period:

T = 2π√(3.57/9.8)

T = 2π√(0.364)

T = 2π * 0.603

T = 3.791 seconds

Therefore, if the child's center of gravity is 3.57 m below the pivot, it would take approximately 3.791 seconds for the child to complete one swing.

The question is '' How long does it take a child on a swing to complete one swing if her center of gravity is 3.57 m below the pivot''.

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The given statement "properly conducting electricity so that its signal can travel unimpeded from one node on a network to another" is False.

The statement refers to the concept of transmitting data on a computer network, rather than conducting electricity.

The proper term for the process described is "network transmission," which involves ensuring that signals can travel unimpeded from one node to another on a network.

Conducting electricity refers to the movement of electric charges through a material, such as a wire, to create an electrical current. While network transmission may involve the use of electrical signals, it is distinct from the process of conducting electricity.

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This is an example of Newton's third law of motion

There is an equal and opposite reaction to every action, according to Newton's third law of motion. These forces of action and reaction work on two different bodies. As an illustration, when we walk, we push the ground backward. In turn, the ground pushes us forward (reaction), which facilitates our movement on the surface.

A player's leg responds to this force by exerting an equal and opposite force that can stop the ball from moving. We refer to this as the reaction. Any force that is greater than the action-reaction pair will cause the ball to move further. As a result, the soccer game makes use of Newton's third law of motion.

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Answer:

8550 Joules of energy.

Explanation:

                                                                                             = -8550 J

Answer: the velocity is not changing bc the speed is constant

Explanation:

A student rides the Ferris wheel when visiting an amusement park. She moves at a constant speed of 3 m/s which means that the velocity is not changing because the speed is constant.

The overall distance the object covers in a given amount of time is its average speed. The scalar quantity represents the average speed. It does not have direction; it is represented by magnitude.

Average Speed = \(total\ distance/total\ time\)

Average velocity is a vector quantity. The change in position or displacement divided by the periods during which the displacement happens is known as average velocity. Depending on how the displacement is displaced, the average velocity may be positive or negative. Meters per second (m/s), the SI unit of average velocity, is used.

According to the question, she is moving at a constant speed of 3 m/s means that the velocity is constant, and its acceleration will also be equal to zero because there is no change in velocity then acceleration is zero.

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An example of a wave that can be transmitted through a vacuum (no medium/matter) is the electromagnetic wave.

Electromagnetic waves are composed of oscillating electric and magnetic fields that are perpendicular to each other and propagate through space. Examples of electromagnetic waves include radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.

These waves can travel through a vacuum because they do not require a medium to propagate, unlike mechanical waves such as sound waves or water waves, which require a material medium to travel through. The speed of electromagnetic waves through a vacuum is constant and is known as the speed of light.

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The magnitude of the emf e induced in the loop after exactly time 9.00 s has passed since the circumference of the loop started to decrease is 0.0124V

Magnitude is simply "distance or amount" in the context of physics. In terms of motion, it shows the absolute and relative size, direction, or movement of an item. It is used to describe something's size or scope. Magnitude in physics often refers to a size or amount.

Magnetic Flux(t) = BA(t) = (B)(pi)[r(t)]^2

C(t) = \(C_0\)-at = 2π[r(t)]

So (B)(π)[r(t)]^2 = (B)(π)[C(t)/(2pi)]^2

= (B)[C(t)]^2/(4π)

By the chain rule of calculus dx^2/dt = 2x(dx/dt)

emf = (1.0)(0.11/(2π))(1.7-((9)(.11))) = 0.0124V

emf = (π)(B)(2r)abs(dr/dt)

emf = BC(t)abs(dr/dt)

emf at (t=9) = B(C_0+(dC/dt)t)abs(dr/dt)

emf = (1.0)(0.11/(2pi))(1.7-((9)(.11))) = 0.0124V

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Answer:

165 kPa

Explanation:

Absolute pressure is:

P = Patm + ρgh

where Patm is the atmospheric pressure,

ρ is the density,

g is acceleration due to gravity,

and h is the depth.

P = 101,300 Pa + (1000 kg/m³) (9.8 m/s²) (6.50 m)

P = 165,000 Pa

P = 165 kPa

Answer:

Explanation:

As the king came near the hermit's hut, he saw the hermit digging the ground in front of his hut. He greeted the king and continued digging. ... (ii) The hermit saw simple people only, so the king put on simple clothes to visit him. (iii) The hermit was digging the ground in front of his hut when the king visited him.

Answer: B. I hope you get this right.

An aluminium wire's cross-sectional area is\(A = 3.1 * 10^{-5} m^{2}\), and its length is L = 0.17 m.

The resistance of an aluminum wire is given by the formula:

\(R = \frac{\rho L}{A}\)

Where R = resistance, ρ = resistivity of aluminum, L = length of wire, and A = cross-sectional area of wire.

So that we can solve for A, we can rearrange the equations as follows

\(A =\frac{ \rho L}{R}\)

Plugging in the given values, we have:

\(A =\frac{ (1.7 * 10^{-8} Ohm*m)(L)}{(0.1 Ohm)}\)

Solving for L,

\(L = \frac{(0.1 Ohm)(A)}{(1.7 * 10^{-8} Ohm*m)}\)

We also know that the mass of the aluminum wire is 54 g. The following formula determines a wire's mass:

\(m = \rho AL\)

In order to find A, we can rearrange the equation as follows:

\(A = \frac{m}{(\rho L)}\)

Plugging in the given values, we have:

\(A =\frac{ (54 g)}{((1.7 *10^{-8} Ohm*m)(L))}\\A = 3.1 * 10^{-5} m^{2}\)

Combining the two equations, we obtain:

\(L =\frac{ (54g)(0.1 Ohm)}{((1.7 * 10^{-8} Ohm*m)(A))}\)

L = 0.17 m

Therefore, the cross-sectional area  is \(A = 3.1 * 10^{-5} m^{2}\) and L = 0.17 m is the length of an aluminium wire.

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The correct answer is 2.8s

A good conductor of electricity is also a good conductor of heat because conduction occurs via electrons, which are responsible for carrying charges and heat energy.

A good conductor of electricity is also a good conductor of heat for the main answer. For both electricity and heat, conduction is via electrons, which in a metal are loosely bound, easy flowing, and easy to start moving.

The electrons are responsible for carrying charges and heat energy.

The energy that carries electricity is carried by the electrons, which means that if there is a current through a conductor, there should also be heat produced by resistance.

As the current moves through the conductor, it meets resistance and loses energy in the form of heat.

In conclusion, a good conductor of electricity is also a good conductor of heat because conduction occurs via electrons, which are responsible for carrying charges and heat energy.

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