In a busy airport, aeroplanes from EZPlanes Airways depart every 264 minutes
whilst aeroplanes from Bryanair Airlines depart every 198 minutes. If both airlines
have aeroplanes departing at 06:20 when is the next time they will depart from
the airport together again?
Answers
The next time they will meet again is 08:44 (next day)
How to determine the next time they will meet againFrom the question, we have the following parameters that can be used in our computation:
EZPlanes Airways depart = every 264 minutes
Bryanair Airlines depart = every 198 minutes
Both airlines depart = at 06:20
Using the above as a guide, we have the following departure times
EZPlanes Airways depart = 264, 528, 792, 1056, 1320, 1584, 1848, 2112, 2376 and 2640 minutes,
Bryanair Airlines depart = 198, 396, 594, 792, 990, 1188, 1386, 1584, 1782 and 1980 minutes
The common departure time in the above is
Time = 1584 minute
So, we have
Common departure time = 06:20 + 1584 minutes
Evaluate the sum
Common departure time = 06:20 + 26 hours + 24 minutes
Evaluate the sum
Common departure time = 08:44 (next day)
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Related Questions
Suppose you are trying to estimate the average age of the entire CSU student population. You collect a sample of size n-163, and from your data you calculate x =20.1 s 1.8 round your answers to 3 decimal places) 1. The standard error of the mean for this data set is: 2. The approximate 95% margin of error is (Use the approximation method from the notes, in which the critical value is approximately 2.) 3. The approximate 95% CI for lage is
Answers
a) The standard error of mean for this data set is approximately 0.141.
b) The approximate 95% margin of error is approximately 0.282.
c) The approximate 95% confidence interval for the population mean age is 19.824 to 20.376.
a) The standard error of mean (SEM) is given by the formula: SEM = s / sqrt(n), where s is the sample standard deviation and n is the sample size. Plugging in the values given, we have:
SEM = 1.8 / sqrt(163) ≈ 0.141
So the standard error of the mean is approximately 0.141.
b) The approximate 95% margin of error (MOE) can be calculated using the formula: MOE ≈ 2 * SEM. Plugging in the SEM value from part 1, we get:
MOE ≈ 2 * 0.141 ≈ 0.282
So the approximate 95% margin of error is approximately 0.282.
c) The approximate 95% confidence interval (CI) for the population mean age can be calculated using the formula: CI = x ± (z*SEM), where x is the sample mean, z is the critical value from the standard normal distribution corresponding to the desired level of confidence (95% in this case), and SEM is the standard error of the mean. The critical value for 95% confidence is approximately 1.96. Plugging in the values, we get
CI = 20.1 ± (1.96 * 0.141) ≈ 19.824 to 20.376
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if 6 pomegranates weighed 9 pounds how many pounds would you expect 1 pomegranate to weigh
Answers
Answer:
1.5 pounds
Step-by-step explanation:
6/9 = 1/x (cross multiplication)
= 1.5
What is the value of X in this question?? I need help please!
Answers
Answer:
The value of x would be 23
Step-by-step explanation:
You must first find the angles of triangle CDE. So to find angle C you must know that a straight line is equal to 180 degrees, 180-117=63 So angle C would be 63 degrees. Angle D is congruent to Angle B so Angle D would equal 24 Degrees. Then to find the angle of Angle E simply subtract 87 from 180 (You Get 87 From Adding 24 and 63), 180-87=93. Know that you know that Angle E is 93 Degrees set up the equation, 4x+1 = 93 SOLVE.
4x+1=93
4x = 92
x = 23.
What is 4 & 1/2+1/8? *
Answers
Answer:
4 5/8
Step-by-step explanation:
Rewriting our equation with parts separated
=4+12+18
Solving the fraction parts
12+18=?
Find the LCD of 1/2 and 1/8 and rewrite to solve with the equivalent fractions.
LCD = 8
48+18=58
Combining the whole and fraction parts
4+58=458
Plot −5/4 and its opposite on the number line.
Select the points on the line to plot.
-3 | | | -2 | | | -1 | | | 0 | | | 1 | | | 2 | | | 3
Answers
If P = (8,2), Find: r270 (P)
Answers
Answer:
In geometry we use input/output process when we determine how shapes are altered or moved. ... f) P (x,y) ------ > (x + 3, 2y) (-4,9). A' (-1, 18)_.
HELP ASAP PLEASEEEEE C is the center of the circle. Find the length of DGE A. s= 161 over 18 pie B. s= 343 over 35 pie C. s= 343 over 18 pie D. s= 343 over 9 pie
Answers
Answer:
C. \( \frac{343}{18} pie \)
Step-by-step explanation:
Given a circle of:
Radius (r) = 14
Measure of minor arc = 115°
We are required to find the length of DGE = length of major arc.
Length of arc is given as 2πr(θ/360)
Measure of the major arc DGE (θ) = 360 - 115 = 245°
Length of major arc DGE = \( 2*pie*14*\frac{245}{360} \)
\( = 28*pie*\frac{49}{72} \)
\( = \frac{28*49}{72} pie \)
\( = \frac{7*49}{18} pie \)
\( = \frac{343}{18} pie \)
Length of arc DGE =
\( \frac{343}{18} pie \)
What value could you write in the blank that would make the equation 3x + 8 = 3x + true for...Just one value of x?
Answers
we have the expression
3x+8=3x+
the value is 8because3x+8=3x+8the equation is true for any value of xwrite the equation the represents the following table
Answers
Answer:
It increase by 3 each time
Step-by-step explanation:
add 3 to 2 to get 5. then add 6 to 4 to get 10, etc.
Plzz give brainliest. I will make my day, thank you! :)))
please answer this question
Answers
We are given with the function \({\bf{f(x,y,z)=e^{x+y}\cos (z)+(y+1)\sin^{-1}(x)at}}\) and we need to find \({\bf \nabla f}\) , that's nothing but just the gradient of f(x,y,z) . But before starting let's recall ;
For a function F(x, y, z, ....) , the gradient is given by ;
\({\boxed{\bf{\nabla F=\dfrac{\partial F}{\partial x}\hat{i}+\dfrac{\partial F}{\partial y}\hat{j}+\dfrac{\partial F}{\partial z}\hat{k}+\cdots}}}\)So , now let's calculate the partial derivatives of f(x, y, z) first with respect to x , y and z one after other .So consider ;
\({:\implies \quad \sf f(x,y,z)=e^{x+y}\cos (z)+(y+1)\sin^{-1}(x)at}\)
Partial differentiating both sides w.r.t.x will yield ;
\({:\implies \quad \sf \dfrac{\partial f}{\partial x}=e^{x+y}\cos (z)+(y+1)at\dfrac{1}{\sqrt{1-x^{2}}}}\)
Simplifying will yield ;
\({:\implies \quad \sf \dfrac{\partial f}{\partial x}=\dfrac{e^{x+y}\cos (z)\sqrt{1-x^{2}}+(y+1)at}{\sqrt{1-x^{2}}}}\)
Now again consider ;
\({:\implies \quad \sf f(x,y,z)=e^{x+y}\cos (z)+(y+1)\sin^{-1}(x)at}\)
Partial differentiating both sides w.r.t.y will yield ;
\({:\implies \quad \sf \dfrac{\partial f}{\partial y}=e^{x+y}\cos (z)+\sin^{-1}(x)at}\)
Now , again consider ;
\({:\implies \quad \sf f(x,y,z)=e^{x+y}\cos (z)+(y+1)\sin^{-1}(x)at}\)
Partial differentiating both sides w.r.t.z will yield ;
\({:\implies \quad \sf \dfrac{\partial f}{\partial z}=-e^{x+y}\sin (z)}\)
\({:\implies \quad \bf \therefore \quad \underline{\underline{\nabla f=\bigg\{\dfrac{e^{x+y}\cos (z)\sqrt{1-x^{2}}+(y+1)at}{\sqrt{1-x^{2}}}\bigg\}\hat{i}+\bigg\{e^{x+y}\cos (z)+\sin^{-1}(x)at\bigg\}\hat{j}-\bigg\{e^{x+y}\sin (z)\bigg\}\hat{k}}}}\)
This is the required answer
Used Concepts :- \({\boxed{\bf{\dfrac{d}{dx}\{\sin^{-1}(x)\}=\dfrac{1}{\sqrt{1-x^{2}}}}}}\) \({\boxed{\bf{\dfrac{d}{dx}(e^x)=e^{x}}}}\) \({\boxed{\bf{\dfrac{d}{dx}\{\cos (x)\}=-\sin (x)}}}\)(2.8•10^8)(1.9•10^4)
Answers
Answer: 5.32 × 10^12
Step-by-step explanation:
This is a question relating to indices. In indices, we add the power given for question relating to multiplication. Hence, this will be:
= (2.8•10^8)(1.9•10^4)
= (2.8 × 1.9) × 10^8+4
= 5.32 × 10^12
Therefore, the answer to the question will be 5.32 × 10^12.
A marketing consulting group wants to see whether placing a seasonal cookie product on an end cap (the shelf at the end of an aisle at a store) will make a difference in sales. The average sales of the seasonal cookie for this region was 650 units. A sample of 36 stores that placed the cookie on an end cap showed a sample mean of 671 units sold with a standard deviation of 81. The resulting p-value is 0.1288; thus, the null hypothesis is not rejected. The marketing consulting group concludes that placing the cookies on an end cap does not affect sales. What type of error is possible in this situation
Answers
Answer:
Type II error.
Step-by-step explanation:
We have a hypothesis test for the claim that placing a seasonal cookie product on an end cap (the shelf at the end of an aisle at a store) will make a difference in sales.
The null hypothesis will state that there is no difference, while the alternative hypothesis will state that there is significant positive difference.
The result is a P-value of 0.1288 and the null hypothesis failing to be rejected.
As the null hypothesis failed to be rejected, if an error has been made in the conclusion, is that we erroneusly accept a false null hypothesis.
This is a Type II error, where the null hypothesis is accepted although the alternative hypothesis is true.
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Select the graph of the solution. Click until the correct graph appears. |x| + 1 < 3
Answers
The solution to the given inequality is x<2. Therefore, option C is the correct answer.
What are inequalities?Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.
The given inequality is |x|+1<3.
Here, subtract 1 on both the sides of an inequality, we get
x<2
Therefore, option C is the correct answer.
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x = -9 and y = 2 plz help me plz
Answers
Answer: 9 and -2
Step-by-step explanation: because of the way it's writen.
if three medians of a triangle are equal than triangle is called
Answers
Answer:
Equilateral
Step-by-step explanation:
if three medians of a triangle are equal than triangle is called Equilateral
Questions
1. There are 30 students in a class: 16 boys and 14 girls. What is the probability that a boy will be chosen at random?
2. A bag contains 3 green marbles, 6 blue marbles and 6 red marbles. One marble is taken out of the bag at random.
What is the probability of choosing:
(1) a red marble?
a
(11)
a green marble?
3.
(a) What is the probability of choosing the letter B at random from the word ALPHABET?
+
Answers
Answer:
1. 8/15
2. Green marble: 3/15
Red Marble: 6/15
Blue marbles: 6/15
3. a 1/8
Answer:
1: 8/15
2: a: 2/5
b: 1/5
3: 1/8
Step-by-step explanation:
1:
16/30 chance
simplify
8/15
2:
3 + 6 + 6 = 15
red: 6/15 --> 2/5
green: 3/15 --> 1/5
3:
1/8
Express the following sum in sigma notation. Use 1 as the lower limit of summation and k for the index of summation. 1+16+81+256+625+1296
Answers
The answer to the sum is: ∑ k⁴ (k ranges from 1 to 6)
Express the sum in sigma notation :
According to the question,
1 = lower limit of summation
k = the index of summation
1 + 16 + 81 + 256 + 625 + 1296 = 1² + 4² + 9² + 16² + 25² + 36²
= 1⁴ + 2⁴ + 3⁴ + 4⁴ + 5⁴ + 6⁴ ( i.e 16 = 4²=(2²)²)
= ∑ k⁴ (k ranges from 1 to 6)
So, The answer to the sum is - ∑ k⁴ (k ranges from 1 to 6).
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Graph y = -1/3 x + 5
Answers
Answer:
hope this hellp for for you
Step-by-step explanation:
Looking at the table above ,
A. What would you consider as the independent variable in this situation ? Introduce the symbol/ name (x,t,...) you will use to represent this variable . Remember to include the units.
B. What is the dependent variable ? Introduce the symbol /name for this variable . Remember the units .
Answers
The independent Variable in the situation presented in the table is the temperature (T), which is measured in degrees Celsius (°C), and the dependent variable is the volume (V), which is measured in milliliters (mL).
The table above illustrates the relationship between the temperature of a substance and its volume. The independent variable is the temperature of the substance and the dependent variable is the volume of the substance.
The symbol or name used to represent the independent variable is "T" for temperature and its units are given as degrees Celsius or °C.The symbol or name used to represent the dependent variable is "V" for volume, and its units are given as milliliters or mL.
The temperature is the independent variable as it is being manipulated in the experiment while the volume is dependent on the temperature as it is changing based on the temperature.
An independent variable is a variable in an experiment that is being manipulated by the experimenter, while the dependent variable is the variable that is being measured in response to changes in the independent variable.
In summary, the independent variable in the situation presented in the table is the temperature (T), which is measured in degrees Celsius (°C), and the dependent variable is the volume (V), which is measured in milliliters (mL).
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Is 2x - 3 = -7 x + 2 > y a true or false statement?
Answers
3 6 9 12 15 18 21 24 27 30 is odd or even numbers?
Answers
Answer: Half of them are even and half of them are odd.
Step-by-step explanation:
The even numbers are 6, 12, 18, 24, and 30. An even number is defined as a number that is divisible by 2, meaning it has no remainder when divided by 2. For example, 6 divided by 2 equals 3 with no remainder, so 6 is even.
The odd numbers are 3, 9, 15, 21, and 27. An odd number is defined as a number that is not divisible by 2, meaning it has a remainder of 1 when divided by 2. For example, 9 divided by 2 equals 4 with a remainder of 1, so 9 is odd.
Therefore, out of the given numbers, half of them are even and half of them are odd.
________________________________________________________
Find the area of the figure below.
Enter the answer as square inches.
Answers
Answer:
42
Step-by-step explanation:
Rectangle: A = 6 x 5 = 30
Triangle: A = 1/2(6 x 4) = 12
Area of figure: 30 + 12 = 42
find the sum of 0.47 and 0.2
Answers
The sum of 0.47 and 0.2 is 0.67
Addition of DecimalsFrom the question, we are to determine the sum of the given decimal numbers.
The numbers are 0.47 and 0.2
In the first model, we have 4 tenths and 7 hundredths
and
In the second model, we have 2 tenths and 0 hundredths
Adding the tenths
4 tenths + 2 tenths = 6 tenths
Adding the hundredths
7 hundredths + 0 hundredths = 7 hundredth
Putting the results together, we get
6 tenths and 7 hundredths
That is,
0.67
Hence, the sum of 0.47 and 0.2 is 0.67
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question what is −8y2 + 8y2
Answers
Answer:
0..................
Answer:
0
Step-by-step explanation:
What is the answer to 34/6?
Answers
Answer:
I don't Know if this is division or fraction
Step-by-step explanation:
But I divided
and my answer was 5r4
Solve for x:
8x - 3 = 5(2x + 1)
A. X=-4
B. x= -2
OC. x=1
D. x = 9
Help quick!!
Answers
Answer:
A. X= -4
Step-by-step explanation:
8x-3=5(2x+1)
8x-3=10×+5
-3=2×+5
-8=2x
x=-4
Answer:
A: x=-4
Step-by-step explanation:
8x - 3 = 5(2x + 1)
8x - 3 = 10x + 5
-3 = 2x + 5
-8 = 2x
x = -4
NASA’s research center has seven crates of hard-shell space suits. Each crate has two suits. If three suits crack during pressure testing, how many suits are left that are NOT cracked?
Answers
what is the realashionship between ceels and tissues
Answers
That’s the similarity
Thank :)
A trail map has a scale of 3 inches to 2 miles. On the map, a trail is 5 1/4 inches long.
5 1/4 inches long.
How long is the actual trail?
A. 1 and 3/4 miles
B. 2 and 5/8 miles
C. 3 and 1/2 miles
D. 7 and 7/8 miles
Answers
Answer: the answer is C
Step-by-step explanation:
On the map, a trail is 5 1/4 inches long, its actual length is 3 and 1/2 miles. Option C is correct.
As given that, A trail map has a scale of 3 inches to 2 miles. To determine the actual length of the measure 5 1 / 4 inches in miles.
In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,
Here,
3 inches = 2 miles
1 inches = 2 / 3 miles
multiply both side by 5 1/4 = 21 / 4
21 / 4 inches = 21 / 4 * 2 / 3 miles
21 / 4 inches = 3 1/2 miles
Thus, on the map, a trail is 5 1/4 inches long, and its actual length is 3 and 1/2 miles. Option C is correct.
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