Imagine that you are hovering next to the space shuttle in an Earth orbit. Your buddy of equal mass, who is moving at 4 km/h with respect to the shuttle, bumps into you. If he holds onto you, how fast do you both move with respect to the ship?
Answers
When your buddy of equal mass bumps into you and holds onto you, both of you will move with a velocity of 4 km/h with respect to the space shuttle.
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When your buddy bumps into you, there is a force exerted on you in one direction, and an equal and opposite force exerted on your buddy in the opposite direction.
Since the forces are equal and opposite, the total momentum of the system remains constant. Momentum is the product of mass and velocity. Since both you and your buddy have equal masses, the change in momentum of one person is balanced by the change in momentum of the other person.
When your buddy holds onto you, the two of you become a combined system with a total mass equal to the sum of your masses. As a result, the change in momentum is distributed between the two of you, maintaining momentum conservation.
Since your buddy is moving at 4 km/h relative to the space shuttle, and he holds onto you, both of you will move with the same velocity. Therefore, you both move at a speed of 4 km/h with respect to the space shuttle.
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Related Questions
Relative density is known as ----------.A. gravity densityB. specific gravityC. weight
Answers
The relative density of the substance is equal to the density of the substance concerning the density of the reference substance.
The relative density of the substance is known as the specific gravity.
Hence, option B is the correct answer.
A wind blowing at a constant speed parallel to straight line isobars with the pressure gradient force (pgf) and the coriolis force in balance is called a:_________
Answers
A wind blowing at a constant speed parallel to straight line isobars with the pressure gradient force (pgf) and the coriolis force in balance is called Geostrophic Wind
The geostrophic winds are present at heights greater than 1000 meters (3300 feet) above sea level. Weather balloons can be used to measure the speed of the geostrophic winds. At heights up to 100 meters, the ground surface has a significant impact on winds.
The pressure gradient force and the Coriolis force interact to create geostrophic winds. Winds are unhindered by intervening obstructions that delay wind speeds and lessen the Coriolis force above the friction layer. The effects of pressure gradient forces accelerate the wind. A long-range artillery projectile is a classic illustration of geostrophic winds.
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Space Curves Arc length: Find the length of the space curve with vector equation Find vector functions for the intersection of two surfaces: F(x)=(2,²-30) Given TNB Find a unit tangent vector to " Find a unit normal vector to " Find a unit binormal vector to " Velocity, acceleration and curvature Find the velocity vector, the acceleration vector and the curvature of " Find the tangential and normal components of the acceleration. r(t) = (4t, 3 cost, 3 sint ) over [ 0,27] 2+2+4= = 1 and y=x² (= ≥0) 12 Note: (² + 2)² =² +4² +4
Answers
The velocity vector is r'(t) = (4, -3 sin t, 3 cos t), the acceleration vector is r''(t) = (0, -3 cos t, -3 sin t), the curvature is κ = 3 / 14^(3/2), and the tangential and normal components of the acceleration are aT = 0 and aN = 3.
Space Curves: Arc lengthArc length formula is given by \(L = ∫a b |r'(t)|dt\)
, where r(t) is the vector function for the given curve.
Let's find the arc length of the given space curve:
r(t) = (2t, t^2 - 2, 5 - t^2) for 0 ≤ t ≤ 4.
The speed of r(t) is |r'(t)|.r'(t) = (2, 2t, -2t) and
||r'(t)|| = √(2^2 + (2t)^2 + (-2t)^2)
= 2√2t.So,
the arc length of the space curve is
L = ∫0 4 2√2t dt
= (4/3)√2 [t^(3/2)] from 0 to 4
= (4/3)√2 (4√2 - 0)= (16/3) * 2
= 32/3.
Therefore, the length of the given space curve with vector equation is 32/3. Vector Functions for the intersection of two surfaces
The equation for the given surface is \(F(x)=(2,x²-30).\)
Let's find the vector functions for the intersection of two surfaces.
To find the intersection, we equate the two given equations:2 = y = x².
We get y = x² = 2. So, x = ±√2.
The vector functions for the intersection of two surfaces are:
r1(t) = (t, 2, t^2 - 30)
for x = √2 and r2(t)
= (-t, 2, t^2 - 30)
for x = -√2.
Given TNB for a space curveLet's find the unit tangent vector to the space curve r(t) = (cos t, sin t, t).
The velocity vector is r'(t) = (-sin t, cos t, 1).
The speed of the curve is |r'(t)| = √(sin² t + cos² t + 1) = √2.
The unit tangent vector is T = r'(t) / |r'(t)| = (-sin t/√2, cos t/√2, 1/√2).
Now, let's find a unit normal vector to the space curve.The acceleration vector is r''(t) = (-cos t, -sin t, 0).
The magnitude of acceleration is |r''(t)| = 1.
The unit normal vector is N = r''(t) / |r''(t)| = (-cos t, -sin t, 0).The binormal vector is given by B = T × N.
Therefore, the unit tangent vector to the space curve r(t) = (cos t, sin t, t) is T = (-sin t/√2, cos t/√2, 1/√2),
the unit normal vector is N = (-cos t, -sin t, 0),
and the unit binormal vector is
B = (cos t/√2, -sin t/√2, 1/√2) × (-cos t, -sin t, 0)
= (sin t/√2, -cos t/√2, 1/√2).
Velocity, acceleration and curvature
Let's find the velocity vector, the acceleration vector, and the curvature of the space curve r(t) = (4t, 3 cos t, 3 sin t) for 0 ≤ t ≤ 27.
The velocity vector is r'(t) = (4, -3 sin t, 3 cos t).
The speed of the curve is |r'(t)| = √(16 + 9 sin² t + 9 cos² t) = 5.
The unit tangent vector is T = r'(t) / |r'(t)| = (4/5, -3 sin t/5, 3 cos t/5).
The acceleration vector is r''(t) = (0, -3 cos t, -3 sin t).
The magnitude of acceleration is |r''(t)| = 3.
The tangential component of acceleration is aT = T · r''(t) = 0.
The normal component of acceleration is aN = |r''(t)| · |N| = 3.
The unit normal vector is N = (-cos t, -sin t, 0).
The curvature is κ = |r''(t)| / |r'(t)|² = 3 / (25 + 9 sin² t + 9 cos² t)^(3/2) = 3 / (25 + 9)^(3/2) = 3 / 14^(3/2).
Therefore, the velocity vector is r'(t) = (4, -3 sin t, 3 cos t),
the acceleration vector is r''(t) = (0, -3 cos t, -3 sin t),
the curvature is κ = 3 / 14^(3/2), and the tangential and normal components of the acceleration are aT = 0 and aN = 3.
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Ariel dropped a golf ball from her second story window. The ball starts from rest and hits the sidewalk 3.5 s later with a velocity of 14.7 m/s. Find the average acceleration of the golf ball.
Answers
Answer:
By using the acceleration formula,
\(a = \frac{v - u}{t} \)
\(a = \frac{14.7 - 0}{3.5} \)
\(a = 4.2m \: s ^{ - 2} \)
Which statement about the universality of gravity is untrue?
Answers
Answer: The gravitational force between two objects depends only on their masses.
Explanation:
When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.
Therefore, gravity relies on mass and distance, not just mass.
There are three types of friction. ______________ friction occurs when an object is not moving. ______________ friction occurs when an object is moving against another surface. ______________ friction occurs in the case of wheels or other round objects. The amount of friction depends on two things.First, how ______________ the surfaces are; and second, how ______________ the object is. It is ______________ to keep an object moving than to start it moving. This is because static friction is ______________ than sliding friction.
Word Bank:
static
sliding
rolling
bumpy
heavy
easier
greater
Answers
Answer:
1. Static friction = not moving
2. sliding friction = moving
3. rolling friction = wheels
4. bumpy the surfaces are
5. how heavy the object is
6. it is easier to keep an object moving
7. static friction is GREATER than sliding friction
Explanation:
. An object with a mass of 1.0 kg is attached to a spring and is set into
vibration with a period of 3.0 s. What will be the calculated spring
constant?
Answers
The calculated spring constant is approximately (9.0 s^2 / 4π^2) kg.
The period of vibration of an object attached to a spring is related to the mass of the object and the spring constant. The formula to calculate the period (T) of an oscillating mass-spring system is:
T = 2π√(m/k)
Where:
T = period of vibration
m = mass of the object
k = spring constant
In this case, the period (T) is given as 3.0 seconds, and the mass (m) is 1.0 kg. We can rearrange the formula to solve for the spring constant (k):
T = 2π√(m/k)
(3.0 s) = 2π√(1.0 kg/k)
Now, we can isolate k:
(3.0 s) / (2π) = √(1.0 kg/k)
(3.0 s) / (2π) = √(k/1.0 kg)
Square both sides:
(3.0 s / 2π)^2 = k / 1.0 kg
Simplifying:
(9.0 s^2 / 4π^2) = k / 1.0 kg
Multiplying both sides by 1.0 kg:
k = (9.0 s^2 / 4π^2) kg
Therefore, the calculated spring constant is approximately (9.0 s^2 / 4π^2) kg.
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Which two substances in the table would float in water?explain how you can tell. water=1.0 copper=8.9 paraffin wax=0.90 steel=7.8 ice=0.92 lead=11.4
Answers
The two substances that would float in water are paraffin wax (0.90) and ice (0.92). This can be determined by comparing their densities with the density of water (1.0 g/cm³).
Substances with densities less than that of water will float, while those with densities greater than that of water will sink.
In this case, both paraffin wax and ice have densities lower than that of water, indicating that they will float.
Paraffin wax, with a density of 0.90 g/cm³, is less dense than water and will float on its surface. Ice, with a density of 0.92 g/cm³, is also less dense than water and will float in liquid water.
Density is a property that relates the mass of a substance to its volume. When comparing the densities of different substances, we can determine whether they will sink or float in a given medium.
In this case, the lower densities of paraffin wax and ice compared to water allow us to conclude that they will float in water.
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CLASSWORK
1. Mr. Njie has a mass of 52.0 kg .Calculate Mr. Njie's weight.
[g = 10ms -2]
Answers
Answer:
Answer: Weight = 520 N
Explanation:
Weight = mass × acceleration
\({ \rm{weight = 52 \times 10}} \\ \\ { \rm{w = 520 \: newtons}}\)
Answer:
520 N
Explanation:
weight is 520 N.....
Blocks with masses of 2. 0 kg, 3. 0 kg, and 4. 0 kg are lined up in a row on a frictionless table. All three are pushed forward by a 14 n force applied to the 2. 0 kg block.
Answers
Force exerted on 4kg block = 6.2 N
Force exerted on 2kg block = 4.51 N
What is force?Forces are influences that can change the movement of an object. A force may change the velocity of an object of mass (m), i.e. accelerate it. Forces can also be referred by pushing or pulling. A force has both magnitude and direction and thus it is a vector quantity.
For the acceleration of all the boxes:
Fₙ = ma
a = Fₙ/m
a = 14/(2+3+4)
a = 1.55 m/s²
For 2 kg block:
Fₙ - F₁ = m₁ × a
14 - F₁ = 2 × 1.55
F₁ = 4.51 N
For 4 kg block:
F₂ = m₃ × a
F₂ = 4 × 1.55
F₂ = 6.2 N
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Complete question is as follows:
Blocks with masses of 2. 0 kg, 3. 0 kg, and 4. 0 kg are lined up in a row on a frictionless table. All three are pushed forward by a 14 n force applied to the 2. 0 kg block.
How much force does the 3kg block exerted on 4 kg block?
How much force does the 3 kg block exerted on 2 kg block?
A neutron star is the collapsed core of a dead star. It has 3.29 x 10^30 kg of mass in a radius of only 10800 m. What is the acceleration of gravity on its surface?
Answers
Answer:
1.88 x 10^12
Explanation:
I'm in Acellus and just got the question right
angular velocity of a rotating wheel increases 2 rev/s every minute. The angular acceleration of this wheel is:
Answers
The angular acceleration of the rotating wheel at the given rate of change of angular velocity is 0.21 rad/s².
Angular acceleration of the wheel
The angular acceleration of an object is the rate of change of anguar velocity of the object with time.
\(\alpha = \frac{\Delta \omega }{\Delta t}\)
where;
Δω is the change in the angular velocityΔt is the change in timeChange in angular velocity of the wheel is calculated as follows;
\(\Delta \omega = 2 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = 4\pi \ rad/s = 12.57 \ rad/s\)
Change in time, Δt = 1 min = 60 s
The angular acceleration of the rotating wheel is calculated as follows;
α = (12.57) / (60)
α = 0.21 rad/s²
Thus, the angular acceleration of the rotating wheel at the given rate of change of angular velocity is 0.21 rad/s².
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what is the acceleration due to gravity on the surface of the asteroid?
Answers
Explanation:
The acceleration due to gravity on the surface of the asteroid is directly proportional to the mass of the asteroid and inversely proportional to the square of the distance from the center of the asteroid.
Therefore, it varies depending on the asteroid's size, shape, and composition.
What is acceleration?Acceleration is the rate of change of velocity over time. A change in velocity, which can be either a change in magnitude or direction or both, results in acceleration.
It is measured in units of meters per second squared (m/s²) or centimeters per second squared (cm/s²).
What is gravity?Gravity is a fundamental force in physics that exists between any two objects in the universe.
The force of gravity pulls all objects with mass toward each other.
Gravity's strength depends on the mass of the two objects and the distance between them.
What is an asteroid?An asteroid is a small rocky or metallic object in space that orbits the sun. They are usually composed of rock, metal, or a combination of the two.
They vary in size from a few meters to hundreds of kilometers in diameter.
Most asteroids are found in the asteroid belt between Mars and Jupiter, although some are also found in other regions of the solar system.
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You see a plane directly overhead at 1622 m.3.51 seconds later, you hear the sonic boom. The speed of sound is 344
s
m
How fast is the plane traveling? Round your answer to 2 decimal places.
s
m
What is the Mach Number for the plane? Round your answer to 2 decimal places.
Answers
The Mach number for the plane is approximately 3.51.
To find the speed of the plane, we can use the equation:
Speed of sound = Speed of the plane / Time taken
Given: Speed of sound (v) = 344 m/s
Time taken (t) = 3.51 seconds
Let's calculate the speed of the plane:
Speed of plane = Speed of sound × Time taken
Speed of plane =\(344 m/s * 3.51 s\)
Speed of plane ≈ 1206.44 m/s
Rounded to 2 decimal places, the speed of the plane is approximately 1206.44 m/s.
To find the Mach number of the plane, we need to divide the speed of the plane by the speed of sound:
Mach number = Speed of plane / Speed of sound
Mach number ≈ \(1206.44 m/s / 344 m/s\)
Mach number ≈ 3.51
Rounded to 2 decimal places, the Mach number for the plane is approximately 3.51.
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if titanium has a density of 4510 kg/m3, what would a 0.001500 m3 block of titanium weigh in pounds? 1 pound is equal to 0.453592 kilograms (kg).
Answers
0.001500 m³ block of titanium would weigh approximately 14.915 pounds.
What is meant by density?Density is physical property of matter that explains how much mass is contained in any given volume of a substance and in other words, it is the amount of "stuff" (mass) per unit of space (volume).
We calculate the mass of the titanium block using its density and volume: mass = density × volume
mass = 4510 kg/m³ × 0.001500 m³
mass = 6.765 kg
6.765 kg × (1 pound / 0.453592 kg) ≈ 14.915 pounds
Therefore, a 0.001500 m³ block of titanium would weigh approximately 14.915 pounds.
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A car starts from rest and speeds up to 30 m/s in a total of 6 s.
What is the acceleration?
1. 5m/s2
2. 30 m/s
3. 24 m/s2
4. 5 m/s
Answers
Calculate the pressure on the bottom of a swimming pool 3. 5 m deep. How does the pressure compare with atmospheric pressure, 105 Pa? (density of water=1000kg/m3 ).
Answers
Answer:
1.343 atm
Explanation:
The mass of water above 1 square meter of swimming pool bottom is ...
M = (3.5 m)·(1000 kg/m^3) = 3500 kg/m^2
Then the force exerted by the water on the pool bottom is ...
F = Mg = (3500 kg/m^2)(9.8 m/s^2) = 34300 N/m^2 = 34300 Pa
Compared with atmospheric pressure, this is ...
34,300/10^5 = 0.343 . . . . atmospheres
Added to the atmospheric pressure on the water's surface, the total pressure on the pool bottom is 1.343 atmospheres.
What is your average speed in mph if you travel 15 miles in 2 hours and 30
minutes?
hey
Answers
Answer:
6 mph
Explanation:
mph = miles per hour
So 15 miles over 2.5hrs
So 15/2.5 = 6 mph
Assuming a current is flowing, what increases the strength of the magnetic field of a coiled electrical wire?
O straightening the wire
O changing the direction of the current flow
O adding more coils to the wire
O stopping the current
I give brainliest
Answers
Answer:
B
Explanation:
Answer:
It is C.
Explanation:
I apologize that im 7 days late. Have a wonderful day!
What is a material in which electrons are able to move easily
Answers
A material in which electrons do not move easily is called an insulator, while a material in which electrons move easily is called a conductor, so the correct answer is option B.
The Elements of the periodic table that are metals and, in some chemical or physical respects, nonmetals, are called metalloids. Some examples of metalloids are boron, silicon, germanium, arsenic, antimony, tellurium, etc.
As stated in the question, we need to find the term for a material in which electrons cannot move easily,
The term "insulator" means a substance in which electrons cannot move freely, while the term "conductive" means a substance in which electrons can flow freely. Therefore, option B is the correct answer.
A perfect insulator does not exist because even insulators contain small amounts of mobile charges (charge carriers) that can carry current. In addition, all insulators become electrically conductive when a voltage large enough is applied for the electric field to pull electrons away from the atoms. This is known as the insulator breakdown voltage. Certain materials such as glass, paper and PTFE, which have high resistance, are very good electrical insulators. A much larger class of materials, although they may have a lower bulk resistance, are still good enough to prevent the flow of significant current at normally used voltages and are therefore used as insulation for power lines and cables. Examples include rubber-like polymers and most plastics, which may be thermoset or thermoplastic in nature.
Complete Question:
A material in which electrons are not able to move easily
a. conductor
b. insulator
c. circuit
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heyy! i’ll give brainliest please help
Answers
as an interstellar cloud of hydrogen gas shrinks in size, its temperature increases
Answers
As an interstellar cloud of hydrogen gas shrinks in size, its temperature increases due to the principle of conservation of energy.
When the cloud contracts, gravitational potential energy is converted into thermal energy. The gravitational force pulling the gas inward does work on the gas particles, increasing their kinetic energy and causing them to move faster. As the particles move faster, collisions between them become more frequent and more energetic, resulting in an overall increase in temperature. This process is governed by the ideal gas law, which states that the pressure of a gas is directly proportional to its temperature when the volume is held constant. As the interstellar cloud contracts, its volume decreases, leading to an increase in pressure. According to the ideal gas law, this increase in pressure is accompanied by an increase in temperature.
Therefore, as the interstellar cloud of hydrogen gas shrinks in size, its temperature increases as gravitational potential energy is converted into thermal energy through the increase in kinetic energy of the gas particles.
FULL QUESTION: As an interstellar cloud of hydrogen gas shrinks in size, its temperature increases,
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what is fc if all the quantities are the same as in part a but the force applied to the box is horizontal? express your answer with the appropriate units.
Answers
Therefore, the magnitude of the applied force is 155 N. Therefore, the magnitude of the applied force is 126 N.
What is force?Force is a physical quantity that describes the interaction between two objects, causing a change in the motion of the objects. More specifically, force is defined as the push or pull on an object that can cause its velocity to change. The unit of force is Newton (N) in the International System of Units (SI). For example, when you push a table, you apply a force to it, and the table moves in the direction of the force. Similarly, when you throw a ball, you apply a force to the ball, and it moves in the direction of the force. Force has both magnitude and direction and is represented by vectors. The direction of the force is the direction in which the force is applied, and the magnitude of the force is the strength of the force. According to Newton's laws of motion, the acceleration of an object is directly proportional to the force applied to it, and inversely proportional to its mass.
Here,
A. To find F, we can use the equation:
FF - μkmg = ma
where FF is the applied force, μk is the coefficient of kinetic friction, m is the mass of the box, g is the acceleration due to gravity, and a is the acceleration of the box. We can rearrange this equation to solve for FF:
FF = μkmg + ma
Since the box starts from rest, its initial velocity is zero, so we can use the equation:
v² = u² + 2as
where v is the final velocity, u is the initial velocity (which is zero), a is the acceleration, and s is the distance traveled. Rearranging this equation to solve for a, we get:
a = v² / (2s)
Substituting this expression for a into the first equation, we get:
FF - μkmg = mv² / (2s)
Substituting the given values, we get:
FF - 0.300 * 18.0 kg * 9.81 m/s² = 18.0 kg * (6.00 m/s)²/ (2 * 0.00800 m)
Solving for FF, we get:
FF = 155 N
B. If the surface is frictionless, then the frictional force is zero, and the equation of motion becomes:
FF = ma
Using the same values as before, we get:
FF = 18.0 kg * (6.00 m/s)² / (2 * 0.00800 m)
Solving for FF, we get:
FF = 4050 N
Therefore, the magnitude of the applied force is 4050 N.
C. If the force applied to the box is horizontal, then the angle between the force and the horizontal is zero, so the equation of motion becomes:
FF - μkmg = ma
Substituting the given values, we get:
FF - 0.300 * 18.0 kg * 9.81 m/s² = 18.0 kg * a
Since the force is horizontal, the acceleration is also horizontal, so we can use the equation:
a = F / m
Substituting this expression for a into the first equation, we get:
FF - 0.300 * 18.0 kg * 9.81 m/s²= FF / 18.0 kg
Solving for FF, we get:
FF = 126 N
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Complete question:
A box of mass 18.0 kg sits at rest on a horizontal surface. The coefficient of kinetic friction between the surface and the box is 0.300. The box is initially at rest, and then a constant force of magnitude FF and direction 39.0 ∘∘ below the horizontal is applied to the box; the box slides along the surface. A. What is F if the box has a speed of 6.00 m/s after traveling a distance of 8.00 mm? Express your answer with the appropriate units. B. What is FB if the surface is frictionless and all the other quantities are the same? Express your answer with the appropriate units. C. What is FC if all the quantities are the same as in part A but the force applied to the box is horizontal? Express your answer with the appropriate units.
A non relativistic proton is confined to a length of 2.0 pm on the x-axis. What is the kinetic energy of the proton if its speed is equal to the minimum uncertainty possible in its speed? (1 eV = 1.60 Ã 10-19 J, h= 1.055 Ã 10-34 J ? s, m proton = 1.67 Ã 10-27 kg) a. 0.13 eV b. 1.3 eV c. 13 eV d. 130 eV e. 1300 eV
Answers
According to the question the kinetic energy of the proton is 0.13 eV.
What is proton?Proton is a subatomic particle that is found in the nucleus of every atom. It has a positive electric charge and a mass that is roughly equal to 1/1800 of the mass of a hydrogen atom. Protons are the primary building blocks of atoms and are responsible for the stability of atoms. They are also the source of the chemical properties of atoms, enabling them to interact with other atoms and form molecules. Protons are composed of three quarks, two up quarks and one down quark, which are held together by the strong nuclear force.
The kinetic energy of the proton can be calculated using the equation \(E_k = (h/(2*π))*v\), where h is Planck's constant, v is the speed of the proton, and π is the mathematical constant pi.
The minimum uncertainty in the speed of the proton is given by the equation v = (h/(2*L)), where h is Planck's constant, and L is the length of the proton's confinement. Substituting the given values, we get v = \((1.055*10-34 J ? s) / (2*2.0*10-12 m) = 2.625*1023 m/s.\)
Substituting this value into the equation for kinetic energy, we get\(E_k = (h/(2*π))*v = (1.055*10-34 J ? s) / (2*3.14) * (2.625*1023 m/s) = 0.13 eV.\)
Therefore, the answer is A. 0.13 eV.
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Given F1=800 N, F2=600N (a) Determine the support reaction forces at the smooth collar A. Ax= [ Select] . Ay= (Select) [Select] (b) Determine the support reaction moments at the smooth collar A. M(A) [Select] "Nim, M(A)y= (Select] Nim M(A)z= [Select] Nim. (c) Determine the normal reaction at the roller support B.B- [Select] N 0 m
Answers
a. The support reaction forces at the smooth collar A are Ax = 800 N and Ay = 600 N,
b. The support reaction moments at the smooth collar A are M(A)x = -1600Nm, M(A)y = 0Nm, and M(A)z = 400Nm
C. the normal reaction at the roller support B is B- = 600N.
The value of Ax = 800 N and Ay = 600 N , M(A)x = -1600Nm, M(A)y = 0Nm, and M(A)z = 400Nm B- = 600N.
The support reaction forces at the smooth collar A can be determined using equations of equilibrium:
F1 + F2 = Ax + Ay and F1x = Ax.
Therefore, Ax = 800 N and Ay = 600 N.
The support reaction moments at the smooth collar A can be determined using the moments equation of equilibrium: M(A)x + M(A)y + M(A)z = 0.
Substituting in the values for Ax and Ay, we can solve for the support reaction moments: M(A)x = -1600Nm, M(A)y = 0Nm, and M(A)z = 400Nm.
The normal reaction at the roller support B can be determined using equations of equilibrium:
F1 + F2 + B- = 0 and Ay = B-.
Therefore, B- = 600N.
In summary, the support reaction forces at the smooth collar A are Ax = 800 N and Ay = 600 N, the support reaction moments at the smooth collar A are M(A)x = -1600Nm, M(A)y = 0Nm, and M(A)z = 400Nm, and the normal reaction at the roller support B is B- = 600N.
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buoyancy: a steel ball sinks in water but floats in a pool of mercury, which is much denser than water. where is the buoyant force on the ball greater?
Answers
The buoyant force on the ball in the pool of mercury is greater.
What do you mean by buoyant force?An object is subject to the buoyant force of the liquid ( fully or partially submerged in a liquid ). An object won't sink in a liquid if its buoyant force (pointing upward) exceeds its weight (pointing downward) on the object. A fluid's buoyancy, also known as its upthrust, is the upward force it exerts in opposition to the weight of an object that is partially or completely submerged. The weight of the fluid on top causes pressure in a fluid column to rise with depth. As a result, the pressure at the bottom of a fluid column is higher than at the top.
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An amusement park ride goes a circle at 10m/s. If its centripetal acceleration is 5m/s^2, then how big is the radius of the circle?
Answers
The radius of the circle is equal to 20m if the centripetal acceleration is 5m/s².
What is centripetal acceleration?The centripetal force is perpendicular to the velocity in a circular motion. If the particles change their speeds in a circular motion then acceleration is produced and the acceleration from directing toward the center.
The mathematical Formula for the centripetal acceleration used:
a = v²/r
Where 'r' is the radius of the circle and a is the centripetal acceleration.
Given, the velocity of the ride, v = 10 m/s
The centripetal acceleration, a = 5 m/s²
The radius of the circle in which the ride is going on is :
r = v²/a
r = (10)²/5
r = 20 m
Therefore, the radius of the circle is equal to 20m.
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A 24 resistor, an inductor with a reactance of 12 , and a capacitor with a reactance of 10 are in series across a 60 V 50 Hz source. Calculate the voltage across the inductor.
Answers
Answer:
A⋅24=24A
12=24A
10=24A
a⋅(60V)⋅(50Hz)=3000aVHz
Explanation:
Kayaks have been used for thousands of years to hunt and fish in Arctic regions. The total volume of a particular kayak is 285 litres (which is 0.285 m3). It has a mass of 75 kg. The man using it has a volume of 0.066 m3. When sitting in the kayak, half of man’s volume is inside the kayak. The density of the human body is about 1000 kg/m3.Calculate the density of the empty kayak.
Answers
Given,
The volucme of Kayak, V₁=0.285 m³
The mass of the Kayak when the man is sitting in it, m₁=75 kg
The volume of the man, V₂=0.066 m³
The density of the man, d=1000 kg/m³
The mass of the man inside the Kayak is given by,
\(m_2=V_2\times d\)On substituting the known values,
\(\begin{gathered} m_2=0.066\times1000 \\ =66\text{ kg} \end{gathered}\)The mass of the empty Kayak is,
\(\begin{gathered} M=m_1-m_2 \\ =75-66 \\ =9\text{ kg} \end{gathered}\)Given that only half of the volume of the man is inside the Kayak when he is sitting in it. Half of the man's volume which is outside the Kayak will be considered in the total volume of the Kayak when he is sitting in it. Thus we have to subtract half of his volume, which is outside the Kayak, while we calculate the density of the Kayak.
Thus the density of the empty Kayak is
\(\rho=\frac{M}{V_1-\frac{V_2}{2}}\)On substituting the known values,
\(\begin{gathered} \rho=\frac{9}{0.285-\frac{0.066}{2}} \\ =35.71kg/m^3 \end{gathered}\)Thus the density of the Kayak is 35.71 kg/m³
What is the direction of the magnetic force on the electrin
Answers
Answer:
we can see the direction of magnetic force on the proton is towards right and on electron is towards left. Hence, the magnitude of force on electron and proton under the same conditions is equal but the direction of magnetic force is opposite due to opposite signs of these charges.
Answer:
Explanation:
The Lorentz force is directed according to the "left hand" rule