im stuck on this question

When you want to produce 2,234 model cars per day, you need to hire 32 people.

In its most basic form, an equation is a mathematical statement that shows that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign. A mathematical statement made up of two expressions joined by an equal sign is known as an equation. 3x - 5 = 16 is an example of an equation. We get the value of the variable x as x = 7 after solving this equation.

Here

No of cars produced in an Hour = 12 Cars

No or cars produced in a day by one employee = 12*6 = 72

No of employees needed = 2234 / 72 = 31.02

=32 Employees

You need to hire 32 employees when you want to produce 2,234 model cars each day.

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Answer:

for band female box: 32, for band male box: 29, for chorus female box: 24, for chorus male box: 25. then you can add up for the total boxes

The exponential function that has a decreasing graph is given by:

\(f(x) = 1.25(0.3)^x + 7\)

An exponential function is modeled by:

\(y = ab^x\)

In which:

The parameter b defines if the graph is increasing or decreasing, as follows:

The function that has |b| < 1, thus decreasing, is given by:

\(f(x) = 1.25(0.3)^x + 7\)

In which b = 0.3, hence |b| = 0.3.

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The number makes the expression equivalent is m = 0.2584.

A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.

Given, An expression 12(- 1.4m + 0.4) = m + 0.2.

- 16.8m + 4.8 = m + 0.2.

- 16.8m - m = 0.2 - 4.8

- 17.8m = - 4.6.

m = (-4.6/-17.8).

m = 0.2584.

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Answer:

322 ft^2

Step-by-step explanation:

Kindly note that no attachment was found

Step one:

Given data

Length= 23 ft

Width = 14 ft

Required

The area of the kennel

Step two:

From

A= length * Width

The area of the kennel is

A= 23*14

A= 322 ft^2

Answer:

You should have it right I checked the math the product is right and the estimate would mate sense so that should be right

Step-by-step explanation:

Answer:

Estimate: 4200

Product: 3828

Step-by-step explanation:

An estimate would be an approximate solution and the product is the actual solution.  To estimate I rounded the 2 numbers (66 and 58) to numbers that are easier to work with, like 70 and 60, and multiplied those in my head, resulting in 4200.  That is my estimate.  For the actual product I just imputed 66 and 58 in my calculator which gave e 3828.  

Answer:

9 , 18, 1080

yes

Hope this helps!

Step-by-step explanation:

use Pythagoras theorem,

\( {a}^{2} + {b}^{2} = {c}^{2} \)

\({6}^{2} + {8}^{2} = {c}^{2} \\ 36 + 64 = {c}^{2} \\ c = \sqrt{100 } \\ c = 10\)

Answer:

The length of missing side of triangle is 10 m.

Step-by-step explanation:

Here, we have given that the two sides of triangle are 6 m and 8 m.

Finding the third side of triangle by pythagorean theorem formula :

\({\longrightarrow{\pmb{\sf{{(c)}^{2} = {(a)}^{2} + {(b)}^{2}}}}}\)

Substituting all the given values in the formula to find the third side of triangle :

\(\begin{gathered} \qquad{\longrightarrow{\sf{{(c)}^{2} = {(a)}^{2} + {(b)}^{2}}}}\\\\\qquad{\longrightarrow{\sf{{(c)}^{2} = {(6)}^{2} + {(8)}^{2}}}}\\\\\qquad{\longrightarrow{\sf{{(c)}^{2} = (6 \times 6)+ (8 \times 8)}}}\\\\\qquad{\longrightarrow{\sf{{(c)}^{2} = (36)+ (64)}}}\\\\\qquad{\longrightarrow{\sf{{(c)}^{2} = 36 + 64}}}\\\\\qquad{\longrightarrow{\sf{{(c)}^{2} =100}}}\\\\\qquad{\longrightarrow{\sf{c = \sqrt{100}}}}\\\\\qquad{\longrightarrow{\sf{c = 10 \: m}}}\\\\\qquad\star{\underline{\boxed{\sf{\red{c = 10 \: m}}}}}\end{gathered}\)

Hence, the length of missing side of triangle is 10 m.

\(\rule{300}{2.5}\)

The triangle similarity can be proven by three methods, and the AA similarity postulate states that two triangles are similar if and only if their corresponding angles are congruent.

If they have the same shape but different sizes. This is what is known as similarity. In mathematics, there are three ways to prove that two triangles are similar: AA, SAS, and SSS.

In the case of AA similarity postulate, two triangles are similar if and only if two corresponding angles are congruent, meaning they have the same degree measure.

Similarly, if triangle ABC is similar to triangle JKL by AA similarity postulate, it means that the corresponding angles of both triangles are congruent.

Therefore, it is possible that triangle ABC is similar to one or more of the triangles given, but it is not possible to say without further information such as the angles and lengths of the sides.

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Complete Question:

Define triangle is ​△ABC​ similar to Similarity property and why?

Which triangle is ​△abc​ similar to and why? responses △abc is similar to △ghi by ​aa similarity postulate. triangle a b c, is similar to , triangle g h i, by , ​, a a similarity postulate, ., △abc is similar to △jkl by ​aa similarity postulate​. triangle a b c, is similar to , triangle j k l, by , ​, a a similarity postulate, ​, . △abc is similar to △def by ​aa similarity postulate​. triangle a b c, is similar to , triangle d e f, by , ​, a a similarity postulate, ​, . ​△abc​ is not similar to any of the triangles given.

Answer:

The answer is b

Step-by-step explanation:

Answer:

3:5 or 3 to 5 or \(\frac{3}{5}\)

Step-by-step explanation:

\(\frac{6}{10}\) ÷\(\frac{2}{2}\) = \(\frac{3}{5}\)

Helping in the name of Jesus.

Answer:

8 words per min

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

15d10mo

Step-by-step explanation:

Simplify:

(9+6)(mod10)

=15d10mo

Reasonably simple series with a tail that is thicker than the tail of the given Σ 1n × >> Σ (1/2), Σ (1/3)^n has a thicker tail than Σ (1/2)^n.

One possible series with a thicker tail than Σ (1/2)^n is the series Σ (1/3)^n, which can be written as:

1 + 1/3 + 1/9 + 1/27 + 1/81 + ...

To see that this series has a thicker tail than Σ (1/2)^n, we can compare the nth terms of the two series:

(1/2)^n = 1/2 × 1/2 × ... × 1/2 (n factors)

(1/3)^n = 1/3 × 1/3 × ... × 1/3 (n factors)

Since 1/2 > 1/3, the nth term of Σ (1/2)^n is greater than the nth term of Σ (1/3)^n for all n. However, the sum of the first k terms of Σ (1/3)^n is:

1 + 1/3 + 1/9 + ... + (1/3)^k

= (1 - (1/3)^k) / (1 - 1/3)

= (3/2) (1 - (1/3)^k)

which approaches 3/2 as k approaches infinity. In contrast, the sum of the first k terms of Σ (1/2)^n is:

1 + 1/2 + 1/4 + ... + (1/2)^k

= (1 - (1/2)^(k+1)) / (1 - 1/2)

= 2 (1 - (1/2)^(k+1))

which approaches 2 as k approaches infinity. Therefore, the series Σ (1/3)^n has a thicker tail than Σ (1/2)^n.

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Answer:

Step-by-step explanation:Correct answer

Answer:

Area of square= side*side

So we will have,

14*14

= 196cm²

Answer: 4 BTUs/ft^3

Step-by-step explanation:

i just did a test and this was the right answer

The probability of an adult having hypertension is  0.344 and an adult having hypertension and being classified as a low level of obesity is 0.102, having hypertension given he/she is classified as a high level of obesity is 0.540. If an adult has hypertension, the probability that he/she also has a high level of obesity is  0.444.

Probability is a branch of mathematics that deals with the likelihood of an event occurring. It is the measure of the likelihood of an event occurring divided by the number of possible outcomes. Probability is used to determine the chances of a particular outcome occurring and can range from 0 to 1.

a)The probability of an adult having hypertension is (34 + 30 + 51) / (34 + 30 + 51 + 119 + 99 + 82) = 115 / 334 = 0.344.

b) The probability of an adult having hypertension and being classified as a low level of obesity is 34 / (34 + 30 + 51 + 119 + 99 + 82) = 34 / 334 = 0.102.

c) The probability of an adult having hypertension given he/she is classified as a high level of obesity is 51 / (30 + 51 + 82) = 51 / 163 = 0.312.

d) The probability of an adult being classified as a high or average level of obesity is (30 + 51 + 99) / (34 + 30 + 51 + 119 + 99 + 82) = 180 / 334 = 0.540.

e) If an adult has hypertension, the probability that he/she also has a high level of obesity is 51 / (34 + 30 + 51) = 51 / 115 = 0.444.

f) No, an adult's hypertension status and obesity categorization are not independent. This is because the probability of an adult having hypertension given he/she is classified as a high level of obesity (0.312) is not the same as the probability of an adult having hypertension (0.344).

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Answer:

Y(0,13)

X(13,0)

The end-points of the line segment will be negative 1.25 and 0.25.

A number line refers to a straight line in mathematics that has numbers arranged at regular intervals or portions along its width. A number line is often shown horizontally and can be postponed in any direction.

The length of the line segment is 1.50 units and the midpoint of the line segment is negative 0.50. Then the end-points of the line segment are given as,

⇒ - 0.50 ± (1.50) / 2

Simplify the expression, then we have

⇒ - 0.50 ± (1.50) / 2

⇒ - 0.50 - (1.50) / 2, - 0.50 + (1.50) / 2

⇒ - 0.50 - 0.75, - 0.50 + 0.75

⇒ - 1.25, 0.25

The end-points of the line fragment will be negative 1.25 and 0.25.

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The relative frequency of the pitcher throwing exactly 4 pitches in an at-bat is given as follows:

3/20.

A relative frequency is calculated as the division of the number of desired outcomes by the number of total outcomes.

The total number of at bats in this problem is given as follows:

80.

In 12 of them, the pitcher threw exactly four pitches, hence the relative frequency of the pitcher throwing exactly 4 pitches in an at-bat is given as follows:

12/80 = 3/20.

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Answer:

$0.97

Step-by-step explanation:

Let the cost of a single apple is x and that of single mango is y.

ATQ,

3x+6y=9.15 ....(1)

8x+4y=11.92 ...(2)

Multiply equation (1) by 8 and equation (2) by 3

24x+48y=73.2 ...(3)

24x+12y=35.76  ...(4)

Subtract equation (2) from (1) :

24x+12y-(24x+48y) = 35.76  - 73.2

12y-48y = -37.44

-36y = -37.44

y = $1.04

Put the value of y in equation (1)

3x+6y=9.15

3x+6(1.04) = 9.15

3x = 9.15-6(1.04)

3x = 2.91

x = $0.97

Hence, the cost of single apple is $0.97.

The area of the square with a side length of 3.1 meters is 9.61 square meters.

To find the area of a square, we need to multiply the length of one side by itself. In this case, the square has a side length of 3.1 m.

Area of a square = side length × side length

Substituting the given side length into the formula:

Area = 3.1 m × 3.1 m

To perform the calculation:

Area = 9.61 m²

It's worth noting that when calculating the area, we are working with squared units. In this case, the side length is in meters, so the area is expressed in square meters (m²). The area represents the amount of space enclosed within the square.

Remember, to find the area of any square, you simply need to multiply the length of one side by itself.

The area of the square with a side length of 3.1 meters is 9.61 square meters.

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Answer:

 A) the curves are ellipses

 B) 161 yards

 C) 366 yards

Step-by-step explanation:

A) The general shape of the side marked c has the appearance of two quarter-ellipses. The major axis is approximately 125 yards, and the minor axis is approximately 80 yards. Paul could assume that the curves are quarter-ellipses.

B) For an ellipse with this eccentricity, its perimeter is within 2% of that of a circle with a diameter equal to the average of these dimensions.*

So, the approximate length of side c is ...

c ≈ π(80 +125)/4 ≈ 161 . . . . yards; length of side c  

C) The perimeter of the pond is the sum of the side lengths, so will be ...  

80 yds + 125 yds + 161 yds = 366 yds . . . pond perimeter  

Indian mathematician Ramanujan developed an approximate formula for the circumference of an ellipse, which would otherwise need to be computed using an elliptic integral. it is ...

C = π(a+b)(1 + 3λ²/(10 +√(4 -3λ²))    where λ = (a -b)/(a +b) and a, b are the semi-axis lengths.

For this ellipse, λ = 9/41, so the last factor is about 1.01208313. Using this factor, the circumference is expected to be good to about 7 significant digits. Continuing the calculation, we find  C ≈ 325.904 . . . . circumference of an ellipse 125 yd long by 80 yd wide

This is twice the length we imagine for c, so c ≈ 163 yards. As we said, the approximation used above is within 2% of this value.

The attachment shows the shape if the curve is actually an ellipse.