I'm not sure how to do this and im super confused

sorry po di ko ma intindihan

Step-by-step explanation:

sorry po

Answer:

3x²

= 3(10)²

= 3(100)

= 300

Step-by-step explanation:

A20-3a+2=0

22-3a=0

-3a=-22

a=22/3

A= 7,3

Answer:

option a is the correct answer

Answer:

17 meters

Step-by-step explanation:

Area = Length x Width

Width = 7

Area = 119

Solving for: Length

Equation:

119 = 7 * x

Solving for Length (x) :

119 = 7 * x

x = 119/7

x = 17

Units = meters

Answer: 17 meters

If my answer is incorrect, pls correct me!

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-Chetan K

The function f(x,y) can be expressed as \(2y^3 - 4x^{2y}\) + D.

We know that if F(x,y) is a scalar field, then its gradient is given by:

∇F(x,y) = (∂F/∂x)i + (∂F/∂y)j

So, in this case, we are given:

grad F(x,y) = 12xyi + 6(x² + y²)j

Comparing this to the general formula, we see that:

To find F(x,y), we need to integrate each of these partial derivatives with respect to their respective variables. Integrating with respect to x, we get:

F(x,y) = ∫(12xy)dx \(= 6x^{2y} + C(y)\)

Here, C(y) is the constant of integration with respect to x. To find C(y), we differentiate F(x,y) with respect to y and compare it to the second partial derivative of F(x,y) with respect to y:

Differentiating F(x,y) with respect to y, we get:

∂F/∂y = 6x² + C'(y)

Here, C'(y) is the derivative of C(y) with respect to y. Comparing this to the second partial derivative, we get:

Integrating C'(y) with respect to y, we get:

C(y) \(= 2y^3 - 4x^{2y} + D\)

Here, D is the constant of integration with respect to y. Putting everything together, we get:

F(x,y) \(= 6x^{2y} + 2y^3 - 4x^{2y} + D = 2y^3 - 4x^{2y} + D\)

Therefore, f(x,y) \(= 2y^3 - 4x^{2y} + D\).

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Answer:

rad 3

Step-by-step explanation:

it just is

Hello, the answer should be $178.49.

If Devaughn earns $7.25 an hour at his job, we need to find out how much money he will make if he works for 37 hours.

\(37.(7.25)=268.25\)

Next, we need to subtract the deduction amount from the total amount.

Net Equation will be defined as;

\(N=T-D\)

\(N=(268.25)-(89.76)=178.49\)

Good luck! If you have any questions, then feel free to ask in comments!

Answer:

22?

Step-by-step explanation:

just follow PEMDAS. first multiply then divide then add then subtract

The equation of the plane through the line of intersection of the planes and and perpendicular to the plane is x - 2y + 15z - 51 = 0.

The line of intersection of the planes and can be found by setting the two equations equal to each other and solving for x, y, and z. Doing so gives:

3x - y + 2z = 1

2x + y - 3z = -4

Adding the two equations yields:

5x - z = -3

Solving for z, we get:

z = 5x + 3

Now we need to find a normal vector to the plane . The coefficients of x, y, and z in the equation of the plane give us the normal vector:

n = <1, 2, -3>

The dot product of the normal vector n and the vector parallel to the line of intersection gives us the direction of the plane we are looking for:

n . <5, 0, 1> = 1(5) + 2(0) + (-3)(1) = 2

Thus, the equation of the plane we are looking for is:

1(x - x0) + 2(y - y0) - 3(z - z0) = 0

where (x0, y0, z0) is a point on the line of intersection of the planes and . We can use the solution we found earlier to obtain:

z = 5x + 3

Substituting this into the equation of the plane gives:

x - 2y + 15z - 51 = 0

Thus, the equation of the plane through the line of intersection of the planes and and perpendicular to the plane is:

x - 2y + 15z - 51 = 0.

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The method of moments estimate for 0 is 0, and the maximum likelihood estimate is undefined due to the nature of the probability mass function. To estimate the parameter 0 using the method of moments, we equate the sample moment to the population moment.

The first population moment (mean) is given by E(Y) = Σ(y * p(Y = y)), where p(Y = y) is the probability mass function.

Since p(Y = y) = 0 for y ≠ 1, we only consider y = 1.

E(Y) = 1 * p(Y = 1) =\(1 * 0(1 - 0)^(-1)\) = 0

Setting the sample moment (sample mean) equal to the population moment, we have:

0 = (1/n) * ΣYᵢ

Solving for 0, we get the estimate for the parameter using the method of moments.

To estimate the parameter 0 using the method of maximum likelihood estimation (MLE), we maximize the likelihood function L(0) = Π(p(Y = yᵢ)), where p(Y = y) is the probability mass function.

Since p(Y = y) = 0 for y ≠ 1, the likelihood function becomes

L(0) = \(p(Y = 1)^n.\)

To maximize L(0), we take the logarithm of the likelihood function and differentiate with respect to 0:

ln(L(0)) = n * ln(p(Y = 1))

Differentiating with respect to 0 and setting it equal to 0, we solve for the MLE of 0.

However, since p(Y = y) = 0 for y ≠ 1, the likelihood function will be 0 for any non-zero value of 0. Therefore, the maximum likelihood estimate for 0 is undefined.

In summary, the method of moments estimate for 0 is 0, and the maximum likelihood estimate is undefined due to the nature of the probability mass function.

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1. the equation that exemplifies the additive identity property is: C. 33 + 0 = 33.

2. The equation that exemplifies the multiplicative identity property is: A. 9.5 × 1 = 9.5.

The additive identity property states that the sum of adding zero to any number will give you the same number itself.

For example, 4 + 0 = 0.

The multiplicative identity property states that a number multiplied by 1 will always give you a product that is the same number itself.

For example, 4 × 1 = 4.

1. The equation, 33 + 0 = 33, shows the additive identity property, because the sum is the same number itself after 0 is added to it.

2. The equation, 9.5 × 1 = 9.5, also shows the multiplicative identity property.

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Answer:

\(x=\frac{5\±i√203}{6}\)(the lanky a is a square root)

Step-by-step explanation:

I suppose the equation is \(3x^2-5x+19=0\)?

A good old quadratic equation! Back to the good old days when we are memorizing the formula...

\(x=\frac{-b\±√(b^2-4ac)}{2a}\)

(Yes that little lanky a is a square root)

\(x=\frac{-(-5)\±√((-5)^2-4(3)(19))}{2(3)} \\x=\frac{5\±√(25-228)}{6}\\x=\frac{5\±√-203}{6} \\x=\frac{5\±i√203}{6}\)

Since the discriminant is negative, there are no real solutions, but instead, we have complex solutions shown above.

Answer and Step-by-step explanation:

1. We can see that this kite-shape has 4 triangles in it.

The area of a triangle is as follows:

\(A = \frac{bh}{2}\)

Where:

b = Base (length)

h = Height

Top Right Triangle Area:

b = 9

h = 3

A = \(\frac{3 * 9}{2}\)

A = \(\frac{27}{2}\)

Bottom Right Triangle Area:

b = 9

h = 3

A = \(\frac{3 * 9}{2}\)

A = \(\frac{27}{2}\)

Top Left Triangle Area:

b = 4

h = 3

\(A = \frac{4*3}{2}\)

A = \(\frac{12}{2}\)

A = 6

Bottom Left Triangle Area:

b = 4

h = 3

\(A = \frac{4*3}{2}\)

A = \(\frac{12}{2}\)

A = 6

Now, we add all the areas together to get the area of the kite figure.

A = \(\frac{27}{2}\) +

A = 27 + 12

A = 39

The area of the kite figure is 39 \(m^{2}\).

2. We have to find the area of the trapezoid.

(I'm not sure if the 9 is for the entire bottom side length)

A = \(\frac{a + b}{2} h\)

to find the area of the entire trapezoid.

A = \(\frac{2.4 + 9}{9}\) × 8.2

A ≈ 46.74 \(mi^{2}\)

#teamtrees #PAW (Plant And Water)

Answer:

  52°

Step-by-step explanation:

Angle AOB is the a.pex angle of the isosceles triangle AOB.* Then angles at A and B are congruent and each is the complement of half the angle at O:

  ∠OAB = 90° -(1/2)(76°) = 90° -38°

  ∠OAB = 52°

_____

* You know ΔAOB is isosceles because OA and OB are both radii of the circle, hence the same length.

108°

Step-by-step explanation:

since LMP is 85° and since PMN is 23° to find LMN which is the entire angle you would as 85° + 23° to get 108°

Answer:

the set of all the real values which are strictly greater than zero which is all positive real numbers

Step-by-step explanation:

In interval notation: (0, ∞)

Any exponential function with a positive base and positive multiplier will have a horizontal asymptote at y=0 and will extend to +∞. That's what this one does.

Range of a function--

The range of a function is the set of all the values that are attained by a function.

We are asked to find the range of the function f(x)

the set of all the real values which are strictly greater than zero

x > 0

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The statements that are always true regarding the diagram of interior and exterior angles of a triangle include the following:

C. m∠5 + m∠6 =180°.

D. m∠2 + m∠3 = m∠6.

E. m∠2 + m∠3 + m∠5 = 180°.

In Mathematics and Geometry, the exterior angle property can be defined as a theorem which states that the measure of an exterior angle in a triangle is equal in magnitude to the sum of the measures of the two remote or opposite interior angles of that triangle:

m∠2 + m∠3 = m∠6.

According to the Linear Pair Postulate which states that the measure of two (2) angles would add up to 180° provided that they both form a linear pair, we have:

m∠5 + m∠6 =180°.

As a general rule in geometry, the sum of all the angles that are formed by a triangle is equal to 180º and this gives:

m∠2 + m∠3 + m∠5 = 180°.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The projectile will stay in the air for 4 seconds.

The given function is:

\(f(x) =-10x(x-4)\), which is a quadratic function.

A function f(x) in the form of \(ax^{2} +bx+c\) a quadratic function.

As we know the equation of projectile motion is a quadratic equation whose non-zero root provides us the time when motion lasts or we can say it provides the time when an object will hit the ground from the time it was launched in the air.

The roots of the given function are 0 and 4.

So, non-zero root i.e. 4 will be the total time for which projectile stays in the air

Therefore, The projectile will stay in the air for 4 seconds.

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Answer:

D) 4 seconds

Step-by-step explanation:

Got it right on edge! Good Luck <3

the critical value zα/2 that corresponds to an 80% confidence level is approximately 1.2816.

To find the critical value zα/2 that corresponds to an 80% confidence level, we need to determine the value of α/2.

A confidence level of 80% implies that the remaining area under the standard normal distribution curve is (1 - 0.80) = 0.20.

Since the standard normal distribution is symmetric, we divide this remaining area equally between the two tails, resulting in

α/2 = 0.10.

To find the corresponding critical value, we look up the z-score that corresponds to an area of 0.10 in the standard normal distribution table (also known as the z-table) or use a statistical calculator.

The critical value zα/2 for α/2 = 0.10 is approximately 1.2816.

Therefore, the critical value zα/2 that corresponds to an 80% confidence level is approximately 1.2816.

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Answer:

(5x+4)(5x-6)

Step-by-step explanation:

\(25x^{2} -10x-24\)

Separate into two parts, first realizing that the only two factor pairs for 25 are 5 and 5 or 1 and 25. Using 5 and 5 makes the most sense, so

(5x      )(5x     )

The other two numbers need to multiply to -24 and add up to -10.

Pairs that muliply to 24 could be 1 and 24, 2 and 12, 3 and 8, and 4 and 6. The more you factor the easier it will be to quickly discern which numbers to use. In this case, the right pair is 4 and 6. Because it needs to add up to -10, it should be 4 and -6 (because multiplying out, -30 + 20 = -10).

Thus, the final factored equation is (5x+4)(5x-6). You can check this by FOILing and making sure you get the original equation.

The distance between line k and point F(-4,0) is 3.6 units

The correct answer is an option (G) 3.6 units

We know that for a line l: ax + by + c = 0 and a point P(x1, y1), the distance between the line line 'l' and a point P is:

\(d=\frac{|ax_1+by_1+c|}{\sqrt{a^{2} +b^{2} } }\)

In this question we have been given a line k contains points at (4,1) and (-5,-5).

Also, we have been given a point F(-4, 0)

We need to find the distance between line k and point F(-4,0).

First we find the equation of line k.

\(\frac{y-1}{-5-1} =\frac{x-4}{-5-4} \\\\\frac{y-1}{-6} =\frac{x-4}{-9} \\\\-9y+9=-6x+24\\\\6x-9y+9-24=0\\\\6x-9y-15=0\)

So, the equation of line k is 6x - 9y - 15 = 0

Now we find the distance between line k and point F(-4, 0).

Using above formula the distance between line k and point F(-4,0) would be,

\(d=\frac{|6(-4) - 9(0) - 15|}{\sqrt{6^{2} +(-9)^{2} } } \\\\d=\frac{|-24-0-15|}{\sqrt{36+81} }\\\\ d=\frac{|-39|}{\sqrt{117} } \\\\d=\frac{39}{10.82}\\\\ d=3.6\)

Therefore, the distance between line k and point F(-4,0) is 3.6 units

The correct answer is an option (G) 3.6 units

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Answer:

In this section we will discuss the method of graphing an equation in two variables. In other words, we will sketch a picture of an equation in two variables.

Step-by-step explanation:

Answer:A

Step-by-step explanation:

20/25 = 4/5

16/20 = 8/10 = 4/5

Answer:

(2x+3)(x+4)

Step-by-step explanation:

hope the picture helps.

Answer:

a = 29

Step-by-step explanation:

Answer: a= 29

Step-by-step explanation:

1. Flip the Equation

34.8=a +5.8

a+5.8=34.8

2. Subtract 5.8 for both sides

Using four approximating rectangles and right endpoints, the estimated area under the graph of f(x) = 4x from x = 0 to x = 4 is 40 square units.

To estimate the area under the graph of the function f(x) = 4x from x = 0 to x = 4 using four approximating rectangles and right endpoints, we can use the right Riemann sum method.

The width of each rectangle is determined by dividing the interval [0, 4] into four equal subintervals. The width of each subinterval is (4 - 0) / 4 = 1.

Next, we evaluate the function at the right endpoint of each subinterval to determine the height of each rectangle. For the right endpoint approximation, we evaluate f(x) = 4x at the right endpoint of each subinterval.

The right endpoints of the four subintervals are:

x1 = 1

x2 = 2

x3 = 3

x4 = 4

Now, we calculate the area of each rectangle by multiplying the width by the height. The height of each rectangle is given by the function evaluated at the right endpoint.

Rectangle 1: width = 1, height = f(x1) = 4(1) = 4

Rectangle 2: width = 1, height = f(x2) = 4(2) = 8

Rectangle 3: width = 1, height = f(x3) = 4(3) = 12

Rectangle 4: width = 1, height = f(x4) = 4(4) = 16

Finally, we sum up the areas of the four rectangles to estimate the total area under the graph:

Estimated area = Area of Rectangle 1 + Area of Rectangle 2 + Area of Rectangle 3 + Area of Rectangle 4

= (1)(4) + (1)(8) + (1)(12) + (1)(16)

= 4 + 8 + 12 + 16

= 40

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