One earth day equals 24 hours.
Answer:
Correct, is there another part to the question?
Answer:
claro u es iq
Explanation:
a converging meniscus lens with a refractive index of 1.52 has spherical surfaces whose radii are 7.00 cm and 4.00 cm cm. what is the position of the image if an object is placed 26.0 cm to the left of the lens?
The position of the image if an object is placed 26.0 cm to the left of the lens is 57.98 cm to the right of the lens.
1 / f = ( μ - 1 ) ( 1 / r1 - 1 / r2 )
f = Focal length
μ = Refractive index
r1 = Radius of lens 1
r2 = Radius of lens 2
μ = 1.52
r1 = 4 cm
r2 = 7 cm
f = ( 1.52 - 1 ) ( 1 / 4 - 1 / 7 )
f = 0.52 ( 3 / 28 )
f = 17.95 cm
Lens formula,
1 / f = 1 / u + 1 / v
u = Object distance
v = Image distance
u = 26 cm
1 / v = 1 / f - 1 / u
1 / v = 1 / 17.95 - 1 / 26
1 / v = 26 - 17.95 / 466.7
1 / v = 8.05 / 466.7
v = 57.98 cm
Therefore, the position of the image is 57.98 cm to the right of the lens.
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What is a food chain? (site 1)
Answer:
food chain is a process of how food is transported to the plant and then to the animal that eats the animal. there are primary, secondary, and tertiary and then decompose.
Explanation:
plz mark my answer as the brainliest
Answer:
A hierarchical series of organisms each dependent on the next as a source of food.
Explanation:
Hope this helps!! plz mark brainliest-Lily ^_^ ( food chain also known as the Circle Of Life)
Is this right? Please help me ITS SOCIOLOGY
A cyclist acceleration from 0m/s to 8m/s in 3second. what is his acceleration?
Answer:
2.66 m/s² .
Explanation:
Initial velocity , u = 0 m/s
Final Velocity , v = 8 m/s
Time Taken , t = 3 s
So , Acceleration = (v-u)/t = (8 m/s - 0 m/s) /3 sec . = 8/3 m/s² = 2.66 m/s²
Water is considered to be
Answer: the thing that brings you life- h2o- idrk the question but if this helps your welcome ^-^have a good day
Explanation:
Astronomers use the term interstellar matter to refer to
Answer:
Astronomers refer to all the material between stars as interstellar matter; the entire collection of interstellar matter is called the interstellar medium (ISM). Some interstellar material is concentrated into giant clouds, each of which is known as a nebula (plural “nebulae,” Latin for “clouds”).
Explanation:
Astronomers use the term interstellar matter to refer to the material between stars, which is called the interstellar medium (ISM) and includes giant clouds known as nebulae.
Explanation:Astronomers refer to all the material between stars as interstellar matter; the entire collection of interstellar matter is called the interstellar medium (ISM). Some interstellar material is concentrated into giant clouds, each of which is known as a nebula (plural "nebulae," Latin for "clouds"). The best-known nebulae are the ones that we can see glowing or reflecting visible light.
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Which two statements describe part of the frost wedging process
Rock pores and small fissures allow water to soak in. When water freezes, its volume swells, widening fissures in the rock.
What kind of weathering takes place when water seeps into cracks, freezes, and expands?Two types of physical weathering can be distinguished: Water performs a process known as freeze-thaw when it seeps into cracks over time, freezes, and then expands, eventually breaking the rock.
What causes the expansion of rock fissures when water seeps in and freezes?As the temperature dips below freezing, the water seeps into the cracks in the rocks and expands into ice. The tremendous pressure and wedge-like action of the expansion on the nearby rock causes the cracks to widen. Water that freezes and thaws frequently causes the rock to disintegrate.
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Question:
Which two statements describe part of the frost wedging process?
a) Water enters a crack in a rock.
b) The temperature drops below freezing, causing the water to freeze and expand.
c) The rock heats up and expands, widening the crack.
d) Water evaporates from the crack, leaving behind mineral deposits.
e) Repeated cycles of freezing and thawing cause the crack to widen and deepen.
The mass of kerosene needed to boil 5 liters of water at 10°C is (q = 4. 6. 10 J/ kg, % = 4200 J/ kg·grad, heat losses are neglected)
The mass of kerosene needed to boil 5 liters of water at 10°C is approximately 28070 kg.
To determine how much kerosene is needed to boil 5 liters of water at 10°C, we must first determine how much heat is needed to bring the water's temperature up to 100°C and then boil it at that degree.
Heating water from 10°C to 100°C:
4.186 J/g°C (or 4.186 kJ/kg°C) is the specific heat capacity of water. As a result, J is the quantity of heat needed to raise the temperature of 5 liters (or 5000 grams) of water from 10°C to 100°C is:
Q1 = m x c x ΔT
= 5000 g x 4.186 J/g°C x (100°C - 10°C)
= 1952200 J
Water vaporizes at a heat of 2260 kJ/kg (or 2.26 × 106 J/kg) at 100 °C when it is heated to boiling. To boil 5 liters (or 5000 grams) of water at 100°C, the following amount of heat is needed:
Q2 = m x L
= 5000 g x 2.26 x 10^6 J/kg
= 1.13 x 10^10 J
To heat and boil the water, the following amount of heat is needed:
Qtot = Q1 + Q2
= 1952200 J + 1.13 x 10^10 J
= 1.149522 x 10^10 J
Where m is kerosene's mass, c is kerosene's specific heat capacity (4.6 kJ/kg°C), and ΔT is the temperature change of the kerosene.
Assuming that the initial temperature of the kerosene is also 10°C, the temperature change of the kerosene is:
ΔT = 100°C - 10°C
= 90°C
Substituting the values into the equation, we get:
1.149522 x 10^10 J = m x 4.6 kJ/kg°C x 90°C
Solving for m, we get:
m = 28069.6 kg
Hence, 28070 kg of kerosene is required to boil 5 liters of water at 10°C.
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a physical quantity Z is given by z=ad/g .calculte the relatibe error in z
Answer:
e_{r} = Δa /a + Δd /Δ d + Δg / g
Explanation:
The error or uncertainty of a quantity is given by several factors, the most direct error is the absolute one that is given by the appreciation of the instruments, when some quantities obtained by a mathematical formula we must know how each error is programmed in the total error, we can see this with the relative error
the calculated quantity is Z
its relative error is
\(e_{r}\) = ΔZ/Z = 1/Z (dZ /da Δa + dZ /dd Δd + dZ /dg Δg)
e_{r} = 1 / Z (d /g Δa + a /g Δd + ad !1/g²! Δg)
e_{r} = Δa /a + Δd /Δ d + Δg / g
notice that we take the worst case.
The measured quantities have absolute errors Da, Dd, Dg
Does applying force on a body mean that it has to become faster or
slower?? Explain on the basis of circular motion
Answer:
it means it will become faster because more force are applied. This means that if you get pushed, the harder you are pushed, the faster you'll move (accelerate). The bigger you are, the slower you'll move.
hope this helps bby<3
Suppose you are jumping on a trampoline. At your maximum height, your potential energy is
(highest or lowest) and
is (highest or lowest).
your kinetic
energy
Answer:
at max height you potential energy is highest
Explanation
At your maximum height, your potential energy is highest.
And at your exact peak, your kinetic energy is zero, which is the lowest it can ever be.
what happens to most of the energy when energy is transferred to ocean water from the moving air above it? responses it pushes the water forward. it pushes the water forward. it reflects off the surface of the water. it reflects off the surface of the water. it moves through the water. it moves through the water. it causes the water to evaporate.
Most of the energy moves through the water when it is transferred to ocean water from the moving air above it. Option c is correct answer.
When energy is transferred to ocean water from the moving air above it, the most common response is that it moves through the water. The energy transferred from the moving air above the ocean is typically in the form of wind energy, which can generate waves and currents in the water. These waves and currents carry the energy through the water, causing the water to move and creating a variety of ocean phenomena such as tides, upwelling, and ocean currents. While some of the energy may be reflected off the surface of the water or cause some water to evaporate, these are typically minor effects compared to the overall energy transfer that occurs through the water. Hence, Option c is correct answer.
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--The complete question is, What happens to most of the energy when energy is transferred to ocean water from the moving air above it? responses
a. it pushes the water forward.
b. it reflects off the surface of the water.
c. it moves through the water.
d. it causes the water to evaporate.--
Answer: It moves through the water.
Explanation: I took the quiz on k12 and got 100% and here is proof.
The submarine emits a pulse of sound to detect other objects in the sea. The sped of sound in sea water is 1500m/s. An echo is received with a time delay of 0.50s after the original sound is emitted.
Calculate the distance between submarine and the other object
Answer:
d = 375 m
Explanation:
The speed of sound is constant in any medium, therefore we can use the uniform motion relationships
v = x / t
x = v t
In this case it indicates that the time since the sound is emitted and received is t = 0.50 s, in this time the sound traveled a round trip distance
x = 2d
2d = v t
d = v t/2
let's calculate
d = 1500 0.5 / 2
d = 375 m
Consider the position vector ⃗r (t) = 〈3t^2 + 1, 4t^2 + 3〉, t ≥
0. (a) Find the velocity vector. (b) Find the speed of the object.
(c) Find the acceleration vector
The position vector ⃗r (t) = 〈3t^2 + 1, 4t^2 + 3〉, t ≥. The velocity vector is ⃗v(t) = 〈6t, 8t〉.. the acceleration vector is ⃗a(t) = 〈6, 8〉.
(a) To find the velocity vector ⃗v(t), we need to take the derivative of the position vector ⃗r(t) with respect to time t.
⃗v(t) = d⃗r(t)/dt = 〈d(3t^2 + 1)/dt, d(4t^2 + 3)/dt〉 = 〈6t, 8t〉
So, the velocity vector is ⃗v(t) = 〈6t, 8t〉.
(b) The speed of the object represents the magnitude of the velocity vector. In this case, the speed is given by the formula:
speed = |⃗v(t)| = √(v1^2 + v2^2) = √((6t)^2 + (8t)^2) = √(36t^2 + 64t^2) = √(100t^2) = 10t
Therefore, the speed of the object is 10t.
(c) To find the acceleration vector ⃗a(t), we need to take the derivative of the velocity vector ⃗v(t) with respect to time t.
⃗a(t) = d⃗v(t)/dt = 〈d(6t)/dt, d(8t)/dt〉 = 〈6, 8〉
So, the acceleration vector is ⃗a(t) = 〈6, 8〉.
In summary, the velocity vector ⃗v(t) is 〈6t, 8t〉, the speed is 10t, and the acceleration vector ⃗a(t) is 〈6, 8〉. These vectors describe the motion of the object with respect to time.
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Suppose that an object is dropped from a height of hy meters and hits the ground with a velocity of v meters per second. Then v 1962 an object is dropped from a height of 269 meters, with what velocity does it hit the ground? Round your answer to the nearest tenth. meters per second
Answer:
The velocity at which it hit the ground is 72.6 meters.
Explanation:
The v1962 an object is dropped from a height of 269 meters.The Kinematic equation for free fall is v² = u² + 2gh.where v is the final velocity, u is the initial velocity, and g is the acceleration due to gravity.So,
h = 269 meters
u = 0 m/s ( 0 for a dropping object )
g = 9.8 m/s²
By Substitute the kinematic equation
v² = u² + 2gh
v² = 0 x 0 + 2 x 9.8 x 269
v² = 0 + 5272.4 => 5272.4
v = √5272.4
v = 72.6
Therefore the object is dropped from a height of 269 meters, it will hit the ground with a velocity of 72.6 meters per second.
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Which of the following predictions is likely to be correct?
A
If it is August, shadows will soon be longer.
B
If it is March, shadows will soon be longer.
C
If it is September, shadows will soon be shorter.
D
No matter what time of year it is, shadows will remain the same.
Answer:
D
No matter what time of year it is, shadows will remain the same.
Explanation:
Answer:
A
Explanation:
Late in the year the sun the earth is tilted away from the sun that means the sunlight is not coming in as directly. So, shadows during are longer.
an ice hockey puck is tied by a string to a stake on rough ice and slides around in a circle until it comes to a stop. what is the sign of the work done by the tension in the rope as it slides to a stop?
The rope slides to a stop with no work being done by the tension in the rope.
Which of Newton's equations of motion best describes how a hockey puck would move if there was no external force acting on it as it slid around the ice?first rule of Newton If not affected by a net external force, an item at rest or in motion maintains its state of motion at a constant speed.
A hockey puck striking is governed by what rule of motion?The First Law of Motion by Newton Ice hockey is a sport that can help us understand Newton's laws of motion. Until pushed to change its condition by a net force, an object stays at rest or moves at a constant speed (speed in a constant direction).
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A force of 70 N is applied to a 28 kg rock causing it to slow down from 25 m/s to 15 m/s, a change in velocity of 10 m/s. How long was that force applied?
Answer: 4 s
Explanation:
Given
The applied force is 70 N
mass of the rock is 28 kg
initial velocity \(u=25\ m/s\)
final velocity \(v=15\ m/s\)
Deceleration provided by force is
\(a=-\dfrac{70}{28}=-2.5\ m/s^2\)
using the equation of motion
\(v=u+at\\\Rightarrow 15=25-2.5t\\\Rightarrow 2.5t=10\\\Rightarrow t=4\ s\)
When is mechanical energy NOT conserved? ANSWER ASAP WILL GIVE BRAINLIEST IF CORRECT
A-When you are in outer space
B-When it is cold outside
C-When the electricity is turned off
D-When there is significant friction or air resistance or other force affecting on the object.
Answer:
hope this helps D.
Explanation:
Mechanical energy may not be conserved when nonconservative forces act. For example, when a car is brought to a stop by friction on level ground, it loses kinetic energy, which is dissipated as thermal energy, reducing its mechanical energy.
A when you are in outer space since there is no gravity the mechanical energy just continues to push the direction it was pointed to
Activity log - Chest and Back Record your time and activity below and in your unit fitness log. If a particular category does not apply, leave it blank. Date: Warm-up: Cool-down: Type of Activity: (Cardiovascular, Muscular, or Flexibility) Description of Activity and Time: Intensity Level: (Moderate or Vigorous) Total Time:
Answer:
Muscular and vigorous
Explanation:
Big gains only
Answer:Date: 08/21/21
Warm-up: 5 minutes
Cool-down: 1 minute
Type of Activity: Muscular
Description of Activity and Time: push up, and repetitions 10 minutes
Intensity Level: Moderate
Total Time:16 minutes
Explanation:
What is average velocity?
Answer:
amount of displacement divided by the time the displacement occurs
Explanation:
Best answer of those given
Create the following configurations of three or more charges. Draw the electric field lines for each situation. Avoid intersecting your electric field lines. Note that Diagram F is similar to Diagram E but has five negative charges piled onto the same location
Once the consecutive Charges square measure opposite in Sign like in between two same charges field lines square measure faint, however, once they're opposite in magnitude then field lines are closure and field intensity is greatest.x
How to illustrate the electric field lines4. In F, the negative charge is five times greater than E, therefore, the line is going to be a lot curved compared to E, and field density is going to be higher just in the case of F compare to E.
5. Two same charges repel one another, therefore, field lines additionally repeal one another.
Once the consecutive Charges square measure opposite in Sign like in between two same charges field lines square measure faint, however, once they're opposite in magnitude then field lines are closure and field intensity is greatest.x
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an astronomical telescope, having an objective of focal length 100cm and eyepiece of focal length 10cm, is used in normal adjustment. calculate the separation of the lenses
The separation of the lenses is 110 cm.
The separation of the lenses in an astronomical telescope can be calculated using the lens formula, which states that:
1/f = 1/v - 1/u,
where f is the focal length of the lens, v is the image distance, and u is the object distance.
In this case, the objective lens has a focal length of 100 cm, and the eyepiece lens has a focal length of 10 cm.
For the objective lens, u1 is the distance between the object being observed and the lens, and v1 is the distance between the lens and the image formed by the objective lens.
For the eyepiece lens, u2 is the distance between the image formed by the objective lens and the eyepiece lens, and v2 is the distance between the eyepiece lens and the final image formed.
Since the telescope is in normal adjustment, the final image is formed at infinity, so v2 is equal to infinity.
Using the lens formula for the objective lens, we can write:
1/f1 = 1/v1 - 1/u1.
Using the lens formula for the eyepiece lens, we can write:
1/f2 = 1/v2 - 1/u2.
Substituting v2 = infinity, the equation becomes:
1/f2 = 0 - 1/u2.
1/f2 = -1/u2.
Since the telescope is in normal adjustment, the final image formed is at infinity. Therefore, u2 is equal to the distance between the eyepiece lens and the image formed by the objective lens, which is equal to v1.
So, u2 = v1.
1/f2 = -1/v1.
1/10 = -1/v1.
v1 = -10 cm.
Since the distance between the object and the objective lens is equal to the distance between the objective lens and the image formed (u1 = v1), the separation between the lenses is the sum of the focal lengths of the two lenses:
separation = focal length of objective lens + focal length of eyepiece lens.
Substituting the values:
separation = 100 cm + 10 cm = 110 cm.
Therefore, the separation of the lenses in the astronomical telescope is 110 cm.
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In order to increase the rate of acceleration of a car, you should apply more
force to it. true or false
Answer:
True
Explanation:
Because with more force the car will move faster than it did before!!!
A block on a horizontal surface is attached to a horizontal spring of negligible mass and spring constant 30 N / m . The other end of the spring is attached to a wall , and there is negligible friction between the block and the horizontal surface The block - spring system experiences simple harmonic motion , as shown in the graph ?
A 10cm long, 2cm wide wooden wedge is pushed into a soft wood block calculate the load on the soft wood if the effort applied id 30 N
Helppp idk how to do these so explain to me please? thank you
0.03 L/hr is how many mL/min?
Answer:
0.5 mL/min
Explanation:
There are 1000 mL in a L, and 60 minutes in an hour.
0.03 L/hr × (1000 mL/L) × (1 hr / 60 min) = 0.5 mL/min
how many valence electrons does the oxygen atom (o) share with each hydrogen atom (h)?
Answer:
The oxygen atom shares one pair of valence electrons with each hydrogen atom.
Explanation:
A ball is dropped from the top of a cliff. By the time it reaches the ground, all the energy in its gravitational potential energy store has been transferred into its kinetic energy store. If the ball is travelling at 20 m/s when it hits the ground, what height was it dropped from? (Assume that the gravitational field strength is 10 N/kg.)
The answer is 20 meters, how do I get that?
U = mgh, Ek = 1/2*m*v^2
U = Ek (conservation of mechanical energy)
⇒ mgh = 1/2*m*v^2
∵g = 10, v = 20
⇒ 10h = 1/2*400
⇒ h = 20 (m)
A ball is dropped from the cliff and the ball is travelling at the speed of 20 m/s, then the height at which the ball is dropped will be equal to 20 meters.
What is Gravitational Potential Energy?The work per unit mass required to transport an object from a fixed reference position to a given location is the gravitational potential at a certain location. With mass taking the function of charge, it is comparable to the electric potential. As per convention, any mass is infinitely far from the reference line, where the potential is 0, causing a negative potential at any particular distance.
The gravitational potential, also referred to as the Newtonian potential in mathematics, is essential for the understanding of potential theory.
From the equation of energy conservation,
Total mechanical energy = PE + KE
U = mgh and,
KE = 1/2 mv²
mgh = 1/2mv²
Speed, v = 20 m/s and,
acceleration due to gravity. g = 9.8 m/s²
10h = 1/2 × 400
h = 20 meters.
Therefore, the height from where the ball is dropped is 20 meters.
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