ill mark brainlist plss help

Ill Mark Brainlist Plss Help

Answers

Answer 1

Answer:

multiply 0.15 times 26.40 which is $3.96 which is C $4 since they say ESTIMATE A 15% TIP

Step-by-step explanation:


Related Questions

Joe is selling hot chocolate for $0.25 per cup. It costs $12 for a case of cocoa mix. Each paper coffee cup costs $0.10. How many cups of hot chocolate does he need to break even?

Answers

Answer: He needs 80 cups.

Step-by-step explanation:$12/$.15=80 cups


It rained 4/5 inches on Monday.

On Tuesday, it rained 7/10 inches less than it did on Monday.

How much did it rain on Tuesday?
Answer:
inches.
Write your answer as a decimal.

Answers

it rained 1.5 inches. 4/5=0.8 and 7/10=0.7 add those together and that’s your answers Brainliest would be appreciated :)

a box with a square base and open top must have a volume of . we wish to find the dimensions of the box that minimize the amount of material used. first, find a formula for the surface area of the box in terms of only , the length of one side of the square base. simplify your formula as much as possible. next, find the derivative, .

Answers

The formula for the surface area of the box, in terms of the length of one side of the square base (s), is A = s^2 + 4s^2 = 5s^2.

The derivative of the surface area function with respect to s, denoted as dA/ds, gives us the rate of change of the surface area with respect to the length of one side of the base.

1. The surface area of the box consists of the area of the square base and the four equal sides. The area of the square base is s^2, and each side has a length of s. Therefore, the total surface area is given by A = s^2 + 4s^2 = 5s^2.

2. To find the derivative of the surface area function, we differentiate 5s^2 with respect to s using the power rule of differentiation. The power rule states that if we have a function f(x) = cx^n, then the derivative is f'(x) = cnx^(n-1).

  Applying the power rule, we have dA/ds = d(5s^2)/ds = 10s.

3. The derivative, dA/ds = 10s, represents the rate of change of the surface area with respect to the length of one side of the square base. This means that for every unit increase in s, the surface area increases by 10s units.

  The derivative does not provide information about minimizing the amount of material used. To find the dimensions of the box that minimize the amount of material used, we need to set up an optimization problem and solve for the critical points. This involves setting the derivative equal to zero and finding the values of s that satisfy this equation. However, since the problem statement does not provide a specific volume constraint or objective function, we cannot proceed with the optimization process.

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Help I need help quickly

Help I need help quickly

Answers

Answer:

y=-2x-10

Step-by-step explanation:

You have -4/2

Simplify.

-2x.

plese help fast please....

plese help fast please....

Answers

Answer:

its b

Step-by-step explanation:

its esay for even a non smart person to know not saying your one!! never mind.IT IS BBBBBBBB!!!!!!

a box with open top is to have a volume of 8 m3 . the base is to be square. the material for the base costs twice as much per m2 as the material for the sides. find the dimensions of the box that will minimize the total cost of materials.

Answers

The dimensions that minimizes the total cost are 2√2 meters by 1 meter

How to find the dimensions that minimizes the total cost

From the question, we have the following parameters that can be used in our computation:

Volume = 8

Base = square

Base = x

So, the volume is

V = x²h

This gives

x²h = 8

The surface area is calculated as

A = x² + 4xh

This means that the total cost is

C = 2x² + 4xh

Make h the subject in x²h = 8

h = 8/x²

So, we have

C = 2x² + 4x * 8/x²

C = 2x² + 32/x

Differentiate and set to 0

4x - 32/x = 0

So, we have

4x = 32/x

4x² = 32

x² = 8

Differentiate

x = 2√2

Recall that

h = 8/x²

So, we have

h = 8/8

h = 1

Hence, the dimensions are base length of 2√2 meters and a height is 1 meter

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Find the length of the helix r (3 sin(2t), -3cos (2t), 7t) through 3 periods.

Answers

The length of the helix through three periods is 6π × \(\sqrt{85}\).

The helix is represented by the vector-valued function r(t) = (3 sin(2t), -3cos(2t), 7t), where t is the parameter.

To find the length of the helix through three periods, we need to integrate the magnitude of the derivative of r(t) over the desired interval.

The magnitude of the derivative of r(t) is given by

||r'(t)|| = \(\sqrt{(dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2}\)

where dx/dt, dy/dt, and dz/dt are the derivatives of each component of r(t) with respect to t.

Differentiating each component of r(t) gives us:

dx/dt = 6cos(2t)

dy/dt = 6sin(2t)

dz/dt = 7

Substituting these derivatives into the formula for the magnitude of the derivative, we have:

||r'(t)|| = \(\sqrt{(6cos(2t))^2 + (6sin(2t))^2 + 7^2}\)

\(= \sqrt{(36cos^2(2t) + 36sin^2(2t) + 49)}\\ = \sqrt{(36(cos^2(2t) + sin^2(2t)) + 49)}\\ = \sqrt{(36 + 49)}\)

=  \(\sqrt{85}\)

To find the length of the helix through three periods, we integrate ||r'(t)|| from t = 0 to t = 6π (three periods):

Length = ∫(0 to 6π) ||r'(t)|| dt

= ∫(0 to 6π)  \(\sqrt{85}\)  dt

=  \(\sqrt{85}\)  × ∫(0 to 6π) dt

=  \(\sqrt{85}\)  × [t] (0 to 6π)

=  \(\sqrt{85}\)  × (6π - 0)

= 6π × \(\sqrt{85}\)

Therefore, the length of the helix through three periods is 6π × \(\sqrt{85}\).

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Which unit is the largest?

kiloliter
liter
hectoliter
centiliter

Answers

hectoliter is the biggest

Answer:

kiloliter

Step-by-step explanation:

10 hectoliters fit in one kiloliter

Please helpppppppppp

Please helpppppppppp

Answers

Answer: a is 180 because 10*3*6 = 180

b is 1/180 because a is 180

If $1000 is invested at 16% interest compounded continuously for five years was standing balance

Answers

The standing balance after 5 years of continuously compounded interest at a rate of 16% on an initial investment of $1000 is approximately $4290.20.

The formula for continuously compounded interest is given by the formula A = Pe^(rt), where A is the ending balance, P is the principal, r is the interest rate as a decimal, and t is the time in years.

In this case, P = 1000, r = 0.16, and t = 5. Plugging these values into the formula, we get:

A = 1000e^(0.165) ≈ $4290.20

Therefore, the standing balance after 5 years of continuously compounded interest at a rate of 16% on an initial investment of $1000 is approximately $4290.20.

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If 18√8 - 8√18 = √n, what is n? Can you express 18√8 - 8√18 as multiples of the same square root?

Answers

Step-by-step explanation:

squaring both side

(18√8-8√18)^2=(√n)^2

(18√8)^2+(8√18)^2-(2)(8√18)(18√8)=n

after solving it we will get

3744-3456=n

n=288

Answers:n = 288Yes it is possible to express \(18\sqrt{8}-8\sqrt{18}\) as multiples of the same square root (12 multiples of \(\sqrt{2}\) )

=====================================================

Explanation:

Simplify the first part of the left side

\(18\sqrt{8} = 18\sqrt{4*2}\\\\18\sqrt{8} = 18\sqrt{4}*\sqrt{2}\\\\18\sqrt{8} = 18*2*\sqrt{2}\\\\18\sqrt{8} = 36\sqrt{2}\)

And do the same for the second part of the left side

\(8\sqrt{18} = 8\sqrt{9*2}\\\\8\sqrt{18} = 8\sqrt{9}*\sqrt{2}\\\\8\sqrt{18} = 8*3*\sqrt{2}\\\\8\sqrt{18} = 24\sqrt{2}\)

For each simplification, you are trying to factor the stuff under the square root so that you pull out the largest perfect square factor possible.

-------------------------

The original equation \(18\sqrt{8}-8\sqrt{18} = \sqrt{n}\) turns into \(36\sqrt{2}-24\sqrt{2} = \sqrt{n}\)

We have the common factor of \(\sqrt{2}\) so we can combine like terms on the left side ending up with \(12\sqrt{2}\)

-------------------------

So,

\(18\sqrt{8}-8\sqrt{18} = \sqrt{n}\\\\36\sqrt{2}-24\sqrt{2} = \sqrt{n}\\\\12\sqrt{2} = \sqrt{n}\\\\\sqrt{n} = 12\sqrt{2}\\\\\left(\sqrt{n}\right)^2 = \left(12\sqrt{2}\right)^2\\\\n = 288\)

Yes it is possible to express \(18\sqrt{8}-8\sqrt{18}\) as multiples of the same square root. In this case, we can express the left hand side of the original equation as 12 multiples of \(\sqrt{2}\)

Hi guys could some please help me answer this question???
Please dont answer if you dont know
I really need to pass..

Hi guys could some please help me answer this question???Please dont answer if you dont know I really

Answers

Answer: the bottom one

Step-by-step explanation:

i think its the bottom one i did some math

how do you factorise 2k + 10ak

Answers

Hii!

____________________________________________________________

\(\rightsquigarrow\circ\boldsymbol{Answer}\circ\leftharpoonup\)

2k(1+5a) or 2k(5a+1)

\(\rightsquigarrow\circ\boldsymbol{Explanation.}\circ\leftharpoonup\)

First of all, let's find the common term of this binomial (an expression with two terms; the prefix bi- means "two")

Note that both terms have 2k in them. So, we factor it out.

\(\twoheadrightarrow\sf 2k\div2k+10ak\div2k\)

\(\bullet\) Simplify

\(\twoheadrightarrow\sf 1+5a\)

\(\bullet\) 2k can't just vanish into thin air, so we put it outside the parentheses:

\(\twoheadrightarrow\sf 2k(1+5a)\)

\(\bullet\) Great job! We factored the expression successfully

--

Hope that this helped! Best wishes.

\(\textsl{Reach far. Aim high. Dream big.}\\\boldsymbol{-Greetings!-}\)

--

you have factored out 2k from both terms, leaving you with 2k(1 + 5a). This is the factored form of the expression 2k + 10ak.

To factor the expression 2k + 10ak, you want to find the greatest common factor (GCF) of the terms in the expression. The GCF is the largest expression that can be factored out of all the terms.

In this case, the GCF of 2k and 10ak is 2k because both terms have a factor of 2k:

2k + 10ak = 2k(1 + 5a)

By factoring out the GCF, you are essentially dividing each term by 2k:

1. 2k divided by 2k is 1.

2. 10ak divided by 2k is 5a.

So, you have factored out 2k from both terms, leaving you with 2k(1 + 5a). This is the factored form of the expression 2k + 10ak.

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Use the given scale factor and the side lengths of the scale drawing to determine the side lengths of the real object. 10 in Scale factor. 5:1 10 in 12 in Scale drawing адь C Real object pls assp​

Answers

The side lengths of the real object will be 50 inches and 60 inches.

What is a scale factor?

The scale factor is the ratio of the actual size of the image to the new size of the image. It is used to Map the objects like if you want to increase or decrease the size without changing the original shape of the image it is done by the scale factor.

The given scale factor is 5:1, which means that the dimensions of the scale drawing are 1/5 of the dimensions of the real object.

To find the side lengths of the real object, we can use the ratio of the dimensions in the scale drawing and the real object.

For example, the length of the real object can be found by multiplying the length of the scale drawing by the scale factor:

Real object length = Scale drawing length x Scale factor

Real object length = 10 in x 5

Real object length = 50 in

Similarly, the width of the real object can be found using the same method:

Real object width = Scale drawing width x Scale factor

Real object width = 12 in x 5

Real object width = 60 in

Therefore, the side lengths of the real object are 50 inches and 60 inches.

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If we draw 1,000 samples of size 100 from a population and compute the mean of each sample, the variability of the distribution of sample means will tend to be _________ the variability of the raw scores in any one sample.
A) smaller than
B) equal to
C) greater than
D) cannot be determined from the information givenv

Answers

The correct answer is A) smaller than.

The statement refers to the concept of the Central Limit Theorem (CLT). According to the CLT, when random samples are drawn from a population, the distribution of sample means will tend to follow a normal distribution, regardless of the shape of the population distribution, given that the sample size is sufficiently large. This means that as the number of samples increases, the variability of the distribution of sample means will decrease.

In this case, drawing 1,000 samples of size 100 from a population and computing the mean of each sample implies that we have a large number of sample means. Due to the CLT, the distribution of these sample means will have less variability (smaller standard deviation) compared to the variability of the raw scores in any one sample. Thus, the variability of the distribution of sample means will tend to be smaller than the variability of the raw scores in any one sample.

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solve the system of inequalities by graphing and indicate all of the integers that are in the set: 3-2a<13, 5a<17

Answers

Thus, the shaded region is the set of solutions for this system of inequalities, and the integers in this region are -4, -3, -2, -1, 0, 1, 2, and 3.



To solve the system of inequalities by graphing, we first need to rewrite each inequality in slope-intercept form, y < mx + b, where y is the dependent variable (in this case, we can use y to represent both 3-2a and 5a), m is the slope, x is the independent variable (in this case, a), and b is the y-intercept.

Starting with the first inequality, 3-2a < 13, we can subtract 3 from both sides to get -2a < 10, and then divide both sides by -2 to get a > -5. So the slope is negative 2 and the y-intercept is 3. We can graph this as a dotted line with a shading to the right, since a is greater than -5:

y < -2a + 3

Next, we can rewrite the second inequality, 5a < 17, by dividing both sides by 5 to get a < 3.4. So the slope is 5/1 (or just 5) and the y-intercept is 0. We can graph this as a dotted line with a shading to the left, since a is less than 3.4:

y < 5a

To find the integers that are in the set of solutions for this system of inequalities, we need to look for the values of a that satisfy both inequalities. From the first inequality, we know that a must be greater than -5, but from the second inequality, we know that a must be less than 3.4. So the integers that are in the set of solutions are the integers between -4 and 3 (inclusive):

-4, -3, -2, -1, 0, 1, 2, 3

To see this graphically, we can shade the region that satisfies both inequalities:

y < -2a + 3 and y < 5a

The shaded region is the set of solutions for this system of inequalities, and the integers in this region are -4, -3, -2, -1, 0, 1, 2, and 3.

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vanessa has 24 marbles. she gives 3/8 of the marbles ti her brother cisco. if you divide vanessas marbles into 8 equal groups , how many are in each group ? how many marbles does vanessa give to cisco ? explain.

Answers

There are 3 marbles in each group when Vanessa's marbles are divided into 8 equal groups and Vanessa gives 9 marbles to Cisco.

Vanessa has 24 marbles.

She gives 3/8 of the marbles to her brother Cisco.

To find out how many marbles are in each group when divided into 8 equal groups.

we need to divide the total number of marbles (24) by the number of groups (8).

Number of marbles in each group = Total number of marbles / Number of groups

Number of marbles in each group = 24 marbles / 8 groups

Number of marbles in each group = 3 marbles

To calculate the number of marbles Vanessa gives to Cisco, we need to determine 3/8 of the total number of marbles.

Number of marbles given to Cisco = (3/8) × Total number of marbles

= (3/8) × 24 marbles

= (3×24) / 8

= 72 / 8

= 9 marbles

Therefore, Vanessa gives 9 marbles to Cisco.

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Please help will give Brainly

Please help will give Brainly

Answers

Answer:

410 is the outlier.

What is an outlier?

An outlier is an observation that lies an abnormal distance from other values in a random sample from a population. In a sense, this definition leaves it up to the analyst (or a consensus process) to decide what will be considered abnormal.

In simpler words, it is the number that is significantly bigger or smaller than the rest of the numbers, and 410 is it.

Step-by-step explanation:

Hope it helps! =D

The coordinate grid shows points A through K. What point is a solution to the system of inequalities? y > −2x + 10 y > 1/2x − 2 coordinate grid with plotted ordered pairs, point A at negative 5, 4 point B at 4, 7 point C at negative 2, 7 point D at negative 7, 1 point E at 4, negative 2 point F at 1, negative 6 point G at negative 3, negative 10 point H at negative 4, negative 4 point I at 9, 3 point J at 7, negative 4 and point K at 2, 3
answer:
a) E
b) K
c) B
d) D

Answers

Based on the analysis, point D at (-7, 1) is the only solution to the system of inequalities y > -2x + 10 and y > (1/2)x - 2. Therefore, the correct answer is option d) D.

To determine which point is a solution to the system of inequalities y > -2x + 10 and y > (1/2)x - 2, we can test each point to see if it satisfies both inequalities.

a) Point E at (4, -2):

Substituting the coordinates into the inequalities:

-2 > -2(4) + 10 -> -2 > -8 + 10 -> -2 > 2 (False)

-2 > (1/2)(4) - 2 -> -2 > 2 - 2 -> -2 > 0 (False)

b) Point K at (2, 3):

Substituting the coordinates into the inequalities:

3 > -2(2) + 10 -> 3 > -4 + 10 -> 3 > 6 (False)

3 > (1/2)(2) - 2 -> 3 > 1 - 2 -> 3 > -1 (True)

c) Point B at (4, 7):

Substituting the coordinates into the inequalities:

7 > -2(4) + 10 -> 7 > -8 + 10 -> 7 > 2 (True)

7 > (1/2)(4) - 2 -> 7 > 2 - 2 -> 7 > 0 (True)

d) Point D at (-7, 1):

Substituting the coordinates into the inequalities:

1 > -2(-7) + 10 -> 1 > 14 + 10 -> 1 > 24 (False)

1 > (1/2)(-7) - 2 -> 1 > -3.5 - 2 -> 1 > -5.5 (True)

Based on the analysis, point D at (-7, 1) is the only solution to the system of inequalities y > -2x + 10 and y > (1/2)x - 2. Therefore, the correct answer is option d) D.

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number 68 is increased by 43%

Answers

Answer:

68 increased by 43% is 97.24.

Step-by-step explanation:

Multiply 68 by 1.43.

68×1.43=97.24

The answer is 97.24.

Hope this helps!

Answer:

97.24 Absolute change, And the actual difference is 97.24 - 68 = 29.24.

Step-by-step explanation:

Find the equation of the line that is perpendicular to y = - 1/3 x + 2 and passes though the point (-5,2)

Answers

Answer:

y - 2 = 3(x + 5)

Step-by-step explanation:

The given equation has slope -1/3.  Any line perpendicular to the given line has a slope which is the negative reciprocal of -1/3, which comes out to +3.

Use the point-slope formula y - k = m(x - h):

y - 2 = 3(x + 5)

Solve:
4(x-8) > 3 - (2x + 7)

A. 4 2/3

B. 6 2/3

C. 6

D. 7

Answers

Answer:

A. 4 2/3

Step-by-step explanation:

4(x-8) > 3 - (2x + 7)

4x-32 > 3 -2x -7

4x - 32 > -4 -2x

6x -32 > -4

6x > 28

divide both sides by 6

6 divide by 6 is 1

28 divide by 6 is simplified to 14/3 which can be changed into a mixed number 4 2/3

Consider the logistic differential equation:
dy/dx = y/8(6 - y)
Let f(t) be the particular solution to the differential equationwith f(0) = 8
a. What is the limiting factor?
b. Use Euler's method, starting at t=0 with two steps of equalsize, to appropriate F(1).
c. What is the range of f for t > 0

Answers

The approximate value of f(1) using Euler's method with two steps of equal size is 6.636. The range of f for t > 0 is 0 < f(t) < 6.

a. The limiting factor in this logistic differential equation is the carrying capacity, which is 6 in this case. As y approaches 6, the growth rate of y slows down, until it eventually levels off at the carrying capacity.

b. To use Euler's method, we first need to calculate the slope of the solution at t=0. Using the given differential equation, we can find that the slope at t=0 is y(0)/8(6-y(0)) = 8/8(6-8) = -1/6.

Using Euler's method with two steps of equal size, we can approximate f(1) as follows:

f(0.5) = f(0) + (1/2)dy/dx|t=0

= 8 - (1/2)(1/6)*8

= 7.333...

f(1) = f(0.5) + (1/2)dy/dx|t=0.5

= 7.333... - (1/2)(7.333.../8)*(6-7.333...)

= 6.636...

Therefore, the approximate value of f(1) using Euler's method with two steps of equal size is 6.636.

c. The range of f for t > 0 is 0 < f(t) < 6, since the carrying capacity of the logistic equation is 6. As t approaches infinity, f(t) will approach 6, but never exceed it. Additionally, f(t) will never be negative, since it represents a population size. Therefore, the range of f for t > 0 is 0 < f(t) < 6.

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which expression is equivalent to

which expression is equivalent to

Answers

The provided expression can be simplified in the form 2y4/x4 option ( B) Using the integer exponent characteristics,  = [x\(^\frac{1}{8}\) . y⁸]  is the right answer.

What is defined as an integer exponent?

In mathematics, integer exponents are exponents that fall under the integer category. It's possible for the number to be either positive or undesirable. The positive integer exponents in this example dictate how many times that base number must be multiplied by itself.

It's possible for the number to be either positive or undesirable. The positive integer exponents in this example dictate how many instances the base number must be multiplied by itself.

According to the given information:

= [x\(^\frac{1}{4}\) . y¹⁶]\(^\frac{1}{2}\)

= [x\(^\frac{1}{8}\) . y⁸]

The provided expression can be simplified in the form 2y4/x4 option ( B) Using the integer exponent characteristics,  = [x\(^\frac{1}{8}\) . y⁸]  is the right answer.

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Help please! I can't understand this question!

Help please! I can't understand this question!

Answers

Answer:

Step-by-step explanation:

y = 2x + 8

She know 8 songs. 8 will be the y-intercept and each month she learns 2 songs which will be the slope of the function.

Answer:

y=2x+8

Step-by-step explanation:

It's for how many songs he knows in total

2 songs a month so

songs he knows=2(number of months)+the 8 he already knows

Construct a Deterministic Finite Accepted M such that L(M) = L(G), the language generated by grammar G = ({S, A, B}, {a, b}, S , {S -> abS, S -> A, A -> baB, B -> aA, B -> bb} )

Answers

To construct a Deterministic Finite Accepted M such that L(M) = L(G), the language generated by grammar G = ({S, A, B}, {a, b}, S , {S -> abS, S -> A, A -> baB, B -> aA, B -> bb} ), the following steps should be followed:

Step 1: Eliminate the Null productions from the grammar by removing productions containing S. The grammar, after removing null production, becomes as follows.{S -> abS, S -> A, A -> baB, B -> aA, B -> bb}

Step 2: Eliminate the unit productions. The grammar is as follows. {S -> abS, S -> baB, S -> bb, A -> baB, B -> aA, B -> bb}

Step 3: Now we will convert the given grammar to an equivalent DFA by removing the left recursion. By removing the left recursion, we get the following productions. {S -> abS | baB | bb, A -> baB, B -> aA | bb}

Step 4: Draw the state diagram for the DFA using the following rules: State diagram for L(G) DFA 1. The start state is the initial state of the DFA. 2. The final state is the final state of the DFA. 3. Label the edges with symbols on which transitions are made. 4. A table for the transition function is created. The table for the transition function of L(G) DFA is given below:{Q, a} -> P{Q, b} -> R{P, a} -> R{P, b} -> Q{R, a} -> Q{R, b} -> R

Step 5: Construct the DFA using the state diagram and transition function. The DFA for the given language is shown below. The starting state is shown in green and the final state is shown in blue. DFA for L(G) -> ({Q, P, R}, {a, b}, Q, {Q, P}) Where, Q is the starting state P is the first intermediate state R is the second intermediate state.

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please answer first will be marked brainliest

Circle O has a center at (3,1) and a diameter of 10 units. Which point
lies on circle O?
a.(0,0)
b(7,47
c(1,3)
d(3,5)

Answers

Answer: I think it's (7,47 but I need a coordinate plane

What type of solutions to quadratic equations can be solved by factoring and using the zero product property?

Answers

Answer:

The Zero Product Property states that if ab = 0, then either a = 0 or b = 0, or both a and b are 0. When the product of factors equals zero, one or more of the factors must also equal zero. Once the polynomial is factored, set each factor equal to zero and solve them separately.

Step-by-step explanation:

hope this helps

a shark can swim d miles in t hours how fast can it swim​

Answers

A shark usually swims up to 25 mile per hour in seconds. So it would take approximately one minute for it to get to 60 miles

Use the rational zeros theorem to list all possible rational zeros of the following.

Use the rational zeros theorem to list all possible rational zeros of the following.

Answers

The given function is:

\(g(x)=-25x^3-5x^2-2x-1\)

The theorem states that the factors are p/q where p is the factors of the last term (constant term) and q is the factors of the leading coefficient.

Here the leading coefficient is -25 and the constant term is -1.

The factors are listed below:

\(\begin{gathered} -25\Rightarrow\pm25,\pm5,\pm1\Rightarrow q \\ -1=\pm1\Rightarrow p \end{gathered}\)

So the value of p/q can be the values shown below:

\(\frac{p}{q}\Rightarrow\pm\frac{1}{25},\pm\frac{1}{5},\pm1\)

Hence the possible zeroes of the given function are:

\(\pm\frac{1}{25},\pm\frac{1}{5},\pm1\)

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