Answer:
Step-by-step explanation:
1) 2.094 < 2.702
2) 10.09 < 10.9
5) 24.552 = 24.522
6) 21.337 > 21.31
Define Torsion, pure torsion and it's assumptions, torsion
equation and limitation of its formula?
Torsion refers to the twisting of a structural member due to the application of torque. Pure torsion occurs when a structural member is subjected to torsional loading only. It is analyzed using assumptions such as linear elasticity, circular cross-sections, and small deformations. The torsion equation relates the applied torque, the polar moment of inertia, and the twist angle of the member. However, this formula has limitations in cases of non-circular cross-sections, material non-linearity, and large deformations.
Torsion is the deformation that occurs in a structural member when torque is applied, causing it to twist. In pure torsion, the member experiences torsional loading without any other external forces or moments acting on it. This idealized scenario allows for simplified analysis and calculations. The assumptions made in pure torsion analysis include linear elasticity, which assumes the material behaves elastically, circular cross-sections, which simplifies the geometry, and small deformations, where the twist angle remains small enough for linear relationships to hold.
To analyze pure torsion, engineers use the torsion equation, also known as the Saint-Venant's torsion equation. This equation relates the applied torque (T), the polar moment of inertia (J), and the twist angle (θ) of the member. The torsion equation is given as T = G * J * (dθ/dr), where G is the shear modulus of elasticity, J is the polar moment of inertia of the cross-section, and (dθ/dr) represents the rate of twist along the length of the member.
However, the torsion equation has its limitations. It assumes circular cross-sections, which may not accurately represent the geometry of some structural members. Non-circular cross-sections require more complex calculations using numerical methods or specialized formulas. Additionally, the torsion equation assumes linear elasticity, disregarding material non-linearity, such as plastic deformation. It also assumes small deformations, neglecting cases where the twist angle becomes significant, requiring the consideration of non-linear relationships. Therefore, in practical applications involving non-circular cross-sections, material non-linearity, or large deformations, more advanced analysis techniques and formulas must be employed.
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25 POINTS!!!!!! PLEEASEEEE HELP!!!!!!!!!!!!!!NO LINKS OR SPAMS I already solved half of it pls help on part 4 and down.
YOUR ASSIGNMENT: Desert Temperatures
In this assignment, you may work alone, with a partner, or in a small group. Discuss the results of your work and/or any lingering questions with your teacher.
Temperature in the desert can be modeled by the function C(t), where t represents hours after midnight (0 ≤ t ≤ 24), and C is the temperature measured in degrees Celsius. Examine what happens to the graph when you transform the function to degrees Fahrenheit.
Circle the desert you picked:
Sahara Desert
Patagonian Desert
Death Valley California(I choose this one)
Exploring Degrees Celsius
1. Fill out the following chart to find the temperatures for t = 12 (noon) and t = 24 (midnight). (2 points: 1 point for each row)
t
C(t) = –0.30(t – 12)2 + 40
0
12
C(t) = -0.30 (12 - 12)² + 40
C(t) = -0.30 (0)² + 40
C(t) = 40
24
C(t) = -0.30 (24 - 12)² + 40
C(t) = -0.30 (12)² + 40
C(t) = -0.30 × 144 + 40
C(t) = - 43.2 + 40
C(t) = -3.2
2. Plot the three points from the chart onto the graph below. Use the plotted points to sketch the graph of C(t) = –0.30(t – 12)2 + 40. (3 points: 2 points for correct coordinates, 1 point for correct shape)
Convert the Function to Degrees Fahrenheit:
3. Suppose you want to represent the desert temperature in degrees Fahrenheit instead. How would you transform the function C(t) to make the new function, F(t)? (2 points: 1 point for each transformation)
Note: The conversion rule for Celsius to Fahrenheit is .
F(t)=9/5{–0.30 (t – 12)² + 40}+32
F(t) = -0.54 (t – 12)² + 72 + 32
F(t) = -0.54 (t – 12)² + 104
4. Take your values from the previous chart (in question 2) and convert them from Celsius to Fahrenheit. Follow the example below, and use the conversion rule to fill out the chart for degrees Fahrenheit when t = 12 and t = 24. (2 points: 1 point for each row)
t
0
12
24
5. Use the conversion formula to write the equation for the new function, F(t).
(4 points: 2 points for setting up the equation, 2 points for the answer)
Hint: Substitute the equation for C(t) into .
6. Plot the points from the Fahrenheit chart in question 4 onto the graph below. Use the plotted points to sketch out the graph of F(t). (3 points: 2 points for correct coordinates, 1 point for correct shape)
7. Compare the graph in question 6 (F(t)) with the graph in question 2 (C(t)). What changes were made to the graph of C(t) to transform it to F(t)? (1 point)
Answer:
Death Valley California
C(t) = -0.30 (0)² + 40
C(t) = 40
C(t) = -0.30 (12)² + 40t – 12)2 + 40
65f
Answer:
4.
12: (12, 40)
c(12) = 40
F(12) = 9/5(40) + 32
F(12) = 72 + 32
F(12) = 104 °F
24: (24, -3.2)
c(24) = -3.2
F(24) = 9/5(-3.2) + 32
F(24) = -5.76 + 32
F(24) = -26.24 °F
5. not answered
6. attached below
7. not answered
The set of numbers 1, 7, 11 and 36 contains values for m. What value of m makes the equation below true?
4m + 8 = 36
* ASAP *
Answer:
7
Step-by-step explanation:
If m was 1, then it would be
4 +8 = 36, which is not true.
If m was 7, then it would be
28 + 8 = 36, which is true.
If m was 11, then it would be
44 + 8 = 36, which is not true.
If m was 36, then it would be
144 + 8 = 36, which is not true.
Hope that helps!
2. A 5-foot-tall fencepost casts a 7.25-foot shadow at the same time that a nearby
gazebo casts a 36.25-foot shadow. How tall is the gazebo?
Answer:
I think the answer is 25 feet
Step-by-step explanation:
5 / 7.25 = .6896551724
.6896551724 x 36.25 = 25
10 points Help Me Please I will give brainiest
y = 1/2x + 0
but you can also type y = 1/2x or y = 0.5x
Answer:
y=1/2x+0
Step-by-step explanation:
Michelle has French class every third Saturday and karate class every other Saturday. This Saturday she went to both classes. When is the next Saturday she will have both classes on the same day?
Therefore, the next Saturday that Michelle will have both French and karate classes on the same day is the 15th Saturday of the year.
What is pattern?A pattern is a repeating sequence or design that occurs in a particular way. In mathematics, patterns can refer to sequences of numbers or geometric shapes that follow a specific rule or formula. Patterns can be observed in many areas of math, including algebra, geometry, number theory, and calculus. Identifying and analyzing patterns is an important skill in math and helps us to understand the underlying structure and relationships between numbers, shapes, and functions. Patterns can also help us to make predictions and solve problems more efficiently. In addition to math, patterns can be found in many other fields such as art, music, language, and nature. Recognizing and creating patterns can enhance creativity, critical thinking, and problem-solving skills.
Here,
We can solve this problem by finding the next time that both of Michelle's class schedules coincide.
Let's start by determining the pattern of Michelle's French and karate classes.
French class is every third Saturday, so Michelle attends French class on Saturdays that are evenly divisible by 3: 3, 6, 9, 12, 15, 18, 21, and so on.
Karate class is every other Saturday, so Michelle attends karate class on Saturdays that are every second Saturday, starting with the first Saturday: 1, 3, 5, 7, 9, 11, 13, 15, and so on.
To find the next Saturday that Michelle will have both classes on the same day, we need to find the next Saturday that satisfies both of these patterns.
Starting with the first Saturday, we can list the dates that satisfy each pattern:
French class: 3, 6, 9, 12, 15, 18, 21, ...
Karate class: 1, 3, 5, 7, 9, 11, 13, 15, ...
The first date that appears in both lists is 15. This means that Michelle will have both classes on the same day on the 15th Saturday of the year.
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Will Give Brainliest if Correct
Answer:
35
Step-by-step explanation:
Law of cosines
c^2=a^2+b^2-2ab(cos(A))
14^2=11^2+8^2-2(11)(8)Cos(A)
A=93.5833
Law of Sines
Sin(A)/a=Sin(B)/a
Sin(93.5833)/11=Sin(B)/8
B=34.7719
I need 30 please thank you
Answer:
ok good morning
have a nice day
Step-by-step explanation:
#toxicsquad
Answer:
i think its 7, but you should probably check that...
The rectangle is 18.5 in.the base of the rectangle is 9.25 inches what is the height of the rectangle in inches?
Answer: 4
Based on the given conditions, formulate
Multiply both the numerator and denominator with the same integer
Convert decimal to fraction
Simplify fraction(s)
how many children own a rabbit but not a fish
Answer: 17
Step-by-step explanation:
Own just a fish: 4
Middle/overlap: 2
Own just a rabbit: 17
Own neither: 1
6-2=4
20-1-2=17
22 The five-number summary for scores on a statistics exam is: 35, 68, 77, 83 and 97. In all, 196 students took this exam About how many students had scores between 68 and 83? a. 98 b. 39 c. 6
d. 148 e.49
The approximate number of students with Scores between 68 and 83 is 98.Answer: a. 98
The five-number summary for scores on a statistics exam is: 35, 68, 77, 83 and 97. In all, 196 students took this exam About how many students had scores between 68 and 83?
The five-number summary consists of the minimum value, the first quartile, the median, the third quartile, and the maximum value.
The interquartile range is the difference between the third and first quartiles. Interquartile range (IQR) = Q3 – Q1, where Q3 is the third quartile and Q1 is the first quartile. The 5-number summary for scores on a statistics exam is given below:
Minimum value = 35
First quartile Q1 = 68
Median = 77
Third quartile Q3 = 83
Maximum value = 97
The interval 68–83 is the range between Q1 and Q3.
Thus, it is the interquartile range.
The interquartile range is calculated as follows:IQR = Q3 – Q1 = 83 – 68 = 15
The interquartile range of the scores between 68 and 83 is 15. Therefore, the number of students with scores between 68 and 83 is roughly half of the total number of students. 196/2 = 98.
Thus, the approximate number of students with scores between 68 and 83 is 98.Answer: a. 98
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48 identical looking bags of lettuce were delivered to Circle J grocers. Unfortunately, 12 of these bags of lettuce are contaminated with listeria. Joe, from Joes Cafe randomly selects 4 bags of the lettuce for his cafe. Let X equal the number of the selected packets which are contaminated with listeria. a. How many possible ways are there to select the 4 out of 48 packets (order does not matter) without replacement? b. What is the probability thatX=0
c. What is the probability thatX=4? d. What is the probability thatx>2? e. What is the expected value ofX? f. What is the standard deviation ofX? g. What is the probability that X is smaller than its expected value?
h. What is the probability thatX=5?
Probability that X = 5:Since, Joe selects only 4 bags of lettuce. X can't be 5.P(X=5) = 0Hence, the probability that X = 0 is 0.3164 and the probability that X = 5 is 0.
The given problem can be solved using the concept of binomial distribution.
In the given question, there are 48 bags of lettuce out of which 12 bags are contaminated with listeria.
Joe selects 4 bags of lettuce. X is the random variable which represents the number of contaminated bags of lettuce selected by Joe. X can take values from 0 to 4. (as Joe selects only 4 bags).
Part A)Number of ways to select 4 bags of lettuce out of 48:This can be solved using the concept of combinations. The formula to calculate the number of combinations is\(:nCr = n! / r!(n-r)!\)Here, n = 48 and r = 4.
Number of ways = 48C4 = 194,580
Part B)Probability that X = 0:This can be calculated using the formula for the binomial distribution :
\(P(X = r) = nCr * p^r * q^(n-r)\)
Here, p = probability of selecting contaminated bag = 12/48 = 0.25q = probability of selecting non-contaminated bag = 1-0.25 = 0.75Also, n = 4 and r = \(0P(X=0) = 4C0 * 0.25^0 * 0.75^4= 0.3164\)
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Evaluate the following expression. (8¹)0 1 8 0
The evaluated expression is 8.
evaluate the given expression. First, let's break down the expression:
(8¹)⁰ 1 8 ₀
In this expression, we have four parts:
1. (8¹)⁰: This represents 8 raised to the power of 1, which is 8. Then, we have 8 raised to the power of 0. Any nonzero number raised to the power of 0 equals 1.
2. 1: This number is already simplified.
3. 8: This number is also already simplified.
4. ₀: This subscript 0 is typically used to denote the initial value in a sequence or series. However, in this context, it seems irrelevant to the expression and can be ignored.
Combining the simplified parts, we have:
1 * 1 * 8 = 8
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answer and solution in 2xy-5yz-4x+10z
Answer:
2xy+10z-5yz-4x
Step-by-step explanation:
Just put the positives and negatives together. You can't add or subtract any of them because they aren't like terms.
what is 400 centimetres to millimetres
How do you write the slope-intercept form of the equation of the line through the given point and parallel to the given line?.
The slope-intercept form of the equation of the line through the given point and parallel to the given line is y=x−14.
In the given question we have to write the slope-intercept form of the equation of the line through the given point and parallel to the given line.
The given points are (–2, –16).
The given equation of line is y = x – 5.
Standard equation of line is y=mx+c.
After comparing to the standard equation.
Slope m(1) = 1
The line passes through (−2,−16), so the point will satisfy the equation y=mx+c. So
−16=−2*1+c
Simlifying
−16=−2+c
Add 2 on both side, we get
c = −16+2
c = −14
As we know that if line is parallel then
m(1)=m(2)
So the value of solpe m = 1
Now the equation of line
y=1*x+(−14)
y=x−14
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The right answer is:
How do you write the slope-intercept form of the equation of the line through the given point and parallel to the given line?
Point (−2,−16), y = x – 5
"Derive the demand function
Endowment (1,0)
U(x,y) = -e⁻ˣ — e⁻ʸ
To derive the demand function from the given utility function and endowment, we need to determine the optimal allocation of goods that maximizes utility. The utility function is U(x, y) = -e^(-x) - e^(-y), and the initial endowment is (1, 0).
To derive the demand function, we need to find the optimal allocation of goods x and y that maximizes the given utility function while satisfying the endowment constraint. We can start by setting up the consumer's problem as a utility maximization subject to the budget constraint. In this case, since there is no price information provided, we assume the goods are not priced and the consumer can freely allocate them.
The consumer's problem can be stated as follows:
Maximize U(x, y) = -e^(-x) - e^(-y) subject to x + y = 1.
To solve this problem, we can use the Lagrangian method. We construct the Lagrangian function L(x, y, λ) = -e^(-x) - e^(-y) + λ(1 - x - y), where λ is the Lagrange multiplier.
Taking partial derivatives of L with respect to x, y, and λ, and setting them equal to zero, we can find the values of x, y, and λ that satisfy the optimality conditions. Solving the equations, we find that x = 1/2, y = 1/2, and λ = 1. These values represent the optimal allocation of goods that maximizes utility given the endowment.
Therefore, the demand function derived from the utility function and endowment is x = 1/2 and y = 1/2. This indicates that the consumer will allocate half of the endowment to each good, resulting in an equal distribution.
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Select the correct answer.
When Isabella pushes a box of mass 5.25 kilograms with a force of 15.7 newtons, it accelerates by a rate of 2.50 meters/second. What is the force due to friction in this scenario?
OA. -2.60 newtons
OB. 5.50 newtons
-7.75 newtons
D. 13.5 newtons
C.
-2.60 Newtons. Is the correct answer. Are u in k12? And If I'm correct please give me brainliest.
Is the solution positive or negative?
2 ⋅ = 6
− 2 ⋅ = 6.1
2.9 ⋅ = −6.04
− 2.473 ⋅ = −6.859
please help :
Answer:
FOR QUESTION - 2.473 . = -6.859
Positive
(I think)
Step-by-step explanation:
When you multiple negatives you will get a positive.
Ava is a high school basketball player. In a particular game, she made some three
point shots and some two point shots. Ava made a total of 12 shots altogether and
scored a total of 28 points. Determine the number of three point shots Ava made and
the number of two point shots she made.
Answer:
2(x+31)+3x+1=83
2x+62+3x+1=83
5x=83-62-1
5x=20
x=20/5
x=4 3-points made.
4+31=35 3-points made.
Proof:
2*35+3*4+1=83
70+12=1=83
83=83 hope this helps
Answer:
Ava made 4 three point shots and 8 two point shots.
let c = 550 0.8y and i = 75. assume no government or foreign sector. if investment increase by 100, the equilibrium output increases by a total of
Using the equation for equilibrium output, Y = C + I, we can solve for the initial output level when I = 75:
Y = C + I
Y = 550(0.8Y) + 75
Y = 440Y + 75
Y = 75/(1-440)
Y = 132.35
So the initial equilibrium output is 132.35.
Now, if investment increases by 100, the new level of investment would be I = 75 + 100 = 175. Plugging this into the equation for equilibrium output, we get:
Y = C + I
Y = 550(0.8Y) + 175
Y = 440Y + 175
Y = 175/(1-440)
Y = 313.72
So the new equilibrium output is 313.72. The increase in equilibrium output is the difference between the new and initial equilibrium output levels:
ΔY = 313.72 - 132.35 = 181.37
Therefore, if investment increases by 100, the equilibrium output increases by a total of 181.37.
Based on the information provided, we have a simple economy with no government or foreign sector. The consumption function is given as C = 550 + 0.8Y, and the initial investment (I) is 75. If the investment increases by 100, we need to find the increase in equilibrium output.
In this economy, the equilibrium output (Y) is determined by the equation Y = C + I. After the investment increase, the new investment (I') is 175 (75 + 100). Now, we can find the new equilibrium output (Y') using the updated equation Y' = C + I':
Y' = 550 + 0.8Y' + 175
To solve for Y', we can rearrange the equation:
0.2Y' = 725
Y' = 3625
Now, to find the increase in equilibrium output, we subtract the initial output (Y) from the new output (Y'):
Increase in output = Y' - Y = 3625 - 3250 = 375
So, the equilibrium output increases by a total of 375 when the investment increases by 100.
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Derek decides that he needs $184,036.00 per year in retirement to cover his living expenses. Therefore, he wants to withdraw $184036.0 on each birthday from his 66th to his 90.00th. How much will he need in his retirement account on his 65th birthday? Assume a interest rate of 5.00%.
Derek plans to retire on his 65th birthday. However, he plans to work part-time until he turns 71.00. During these years of part-time work, he will neither make deposits to nor take withdrawals from his retirement account. Exactly one year after the day he turns 71.0 when he fully retires, he will wants to have $2,742,310.00 in his retirement account. He he will make contributions to his retirement account from his 26th birthday to his 65th birthday. To reach his goal, what must the contributions be? Assume a 5.00% interest rate.
Derek needs to make contributions of approximately $21,038.34 per year from his 26th birthday to his 65th birthday in order to accumulate $2,742,310.00 in his retirement account by the time he fully retires.
To determine the amount Derek needs in his retirement account on his 65th birthday, we can use the concept of present value. Since he plans to withdraw $184,036.00 per year, starting from his 66th birthday until his 90th, the cash flows can be treated as an annuity. The interest rate is 5.00%, and the time period is 25 years (from 66 to 90). Using the formula for the present value of an annuity, we can calculate the required amount. The formula is:
PV = PMT * (1 - \((1 + r)^(-n)\)) / r
where PV is the present value, PMT is the annual withdrawal amount, r is the interest rate per period, and n is the number of periods.
Plugging in the values, we get:
PV = $184,036.00 * (1 - \((1 + 0.05)^(-25)\)) / 0.05 ≈ $2,744,607.73
Therefore, Derek needs approximately $2,744,607.73 in his retirement account on his 65th birthday to cover his desired annual withdrawals.
Moving on to the second part, Derek plans to make contributions to his retirement account from his 26th birthday to his 65th birthday. To reach his goal of having $2,742,310.00 in his retirement account after fully retiring, we can calculate the necessary contributions using the formula for the future value of an ordinary annuity:
FV = PMT * \(((1 + r)^n\) - 1) / r
Rearranging the formula, we can solve for the required contributions (PMT):
PMT = FV * (r / (\(((1 + r)^n\) - 1))
Plugging in the values, we get:
PMT = $2,742,310.00 * (\(\frac{0.05} {((1+0.05)^{39}-1 )}\))≈ $21,038.34
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A lake has a surface area of 15.4 square miles. What is its surface area in square meters?
Determine the (shortest) distance between the straight line l: x = 5-9t, y=2+4t, z=3+t, te R, and the plane P: 2x + 3y +62 = 33. (b) When a skydiver (of mass m = 60 kg) drops from a plane, she is immediately subjected to two forces: a constant downward force mg = 600 N due to gravity, and an air resistance force proportional to the square of her speed. By Newton's law, the skydiver's speed v satisfies the differential equation dv 60- = 600-kv² dt where t is time and k is a constant. (i) After a long time (roughly 12 seconds, in real life), the skydiver will reach a terminal (constant) velocity of 70 metres per second. Without solving the given differential equation, determine k. (ii) Solve the given differential equation (using the value of k found in (i)). You should assume that the skydiver is initially at rest, i.e. that v(0) = 0. (iii) Sketch your solution for t≥ 0.
The shortest distance between the given line and plane is 11 units. For the skydiver's differential equation, the constant k is found to be 0.025. The solution to the differential equation, with the initial condition v(0) = 0, is v(t) = 20√(3 - \(e^{-0.025t}\)) m/s. The graph of the solution shows the skydiver's speed increasing and eventually approaching the terminal velocity of 70 m/s.
(a) To find the distance between the line l and the plane P, we can use the formula for the shortest distance between a point and a plane. Let's take a point Q on the line l and find its coordinates in terms of t: Q(t) = (5 - 9t, 2 + 4t, 3 + t). The distance between Q(t) and the plane P is given by the formula:
d = |2(5 - 9t) + 3(2 + 4t) + 6(3 + t) - 33| / √(2² + 3² + 6²)
Simplifying this expression, we get d = 11 units as the shortest distance between the line and the plane.
(b)(i) The given differential equation is dv/dt = (600 - kv²) / 60. Since the skydiver reaches a terminal velocity of 70 m/s, we have dv/dt = 0 when v = 70. Plugging these values into the differential equation, we get 0 = 600 - k(70)². Solving for k, we find k = 0.025.
(ii) To solve the differential equation dv/dt = (600 - 0.025v²) / 60, we can separate variables and integrate both sides. Rearranging the equation, we have:
60 dv / (600 - 0.025v²) = dt
Integrating both sides gives us:
∫60 dv / (600 - 0.025v²) = ∫dt
Using a trigonometric substitution or partial fractions, the integral on the left side can be evaluated, resulting in:
-2arctan(0.05v/√3) = t + C
Simplifying further and applying the initial condition v(0) = 0, we find:
v(t) = 20√(3 - \(e^{-0.025t}\)) m/s.
(iii) The graph of the solution shows that initially, the skydiver's speed increases rapidly, but as time goes on, the rate of increase slows down. Eventually, the speed approaches the terminal velocity of 70 m/s, indicated by the horizontal asymptote in the graph. This behavior is expected as the air resistance force becomes equal in magnitude to the gravitational force, resulting in a constant net force and a terminal velocity.
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Expand the following :
A) 2(x+3)
B) 5(2x-4)
C) 4(2x+1)
D) 6(x-4y)
Answer:
A. 2x+6 . B. 10x-20 C. 8x+4 D. 6x-24y
Step-by-step explanation:
how many simple paths of nonzero length are there in a tree with vertices, where ? (regard two simple paths as the same if they have the same edges.)
there are n(n-1)(n-2)/2 simple paths of nonzero length in a tree with n vertices, where two simple paths are regarded as the same if they have the same edges.
In a tree with n vertices, there are (n-1) edges, since a tree is a connected acyclic graph.
To count the number of simple paths of nonzero length in the tree, we can consider each vertex as a starting point for a path and count the number of possible paths from that vertex.
Starting from any vertex, there are at most (n-1) paths that can be formed by moving to any of the neighboring vertices. From each of these neighboring vertices, there are at most (n-2) paths that can be formed by moving to a new neighboring vertex (excluding the vertex that was just visited).
This process can be continued until there are no more vertices to visit. However, to avoid counting the same path twice, we should only consider paths that do not backtrack on themselves.
Therefore, the total number of simple paths of nonzero length in the tree is the sum of all simple paths that start from each vertex:
(number of paths starting from vertex 1) + (number of paths starting from vertex 2) + ... + (number of paths starting from vertex n)
Using the reasoning above, we can see that the number of paths starting from each vertex is at most (n-1) * (n-2), since each path can visit at most (n-2) additional vertices after the starting vertex, and there are at most (n-1) vertices to choose from as the next vertex on the path.
Therefore, the total number of simple paths of nonzero length in the tree is at most n(n-1)(n-2).
However, we have counted each simple path twice (once in each direction), so the actual number of distinct simple paths of nonzero length is half of this maximum value, which is:
n(n-1)(n-2)/2
So, there are n(n-1)(n-2)/2 simple paths of nonzero length in a tree with n vertices, where two simple paths are regarded as the same if they have the same edges.
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One reason a sample may fail to represent the population of interest is _____.
a. statistical inference
b. measurement error
c. sampling error
d. population proportion
One reason a sample may fail to represent the population of interest is sampling error.
The correct answer is an option (c)
We know that the sampling error is a statistical error that occurs when an analyst does not select a sample which represents the entire population of data.
So, the results found in the sample and the results obtained from the entire population would be different.
This error occurs when the sample used in the study is not representative of the entire population.
A sampling error is nothing but a deviation in the sampled value vs. the true population value.
Even randomized samples might have some degree of sampling error because in randomized samples, sample is only an approximation of the population from which it is drawn.
There are different categories of sampling errors.
- Population-Specific Error
- Selection Error
- Sample Frame Error
- Non-response Error
- Eliminating Sampling Errors
Therefore, One reason a sample may fail to represent the population of interest is sampling error.
The correct answer is an option (c)
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two cars start moving from the same point. one travels south at 48 mi/h and the other travels west at 20 mi/h. at what rate is the distance between the cars increasing two hours later? (no response) seenkey 52 mi/h
The rate at which the distance between the two cars is increasing two hours later is 52 mi/h.
To determine the rate of change of the distance between the cars, we can use the concept of relative velocity. Since one car is moving south and the other is moving west, their velocities are perpendicular to each other. Thus, we can use the Pythagorean theorem to find the distance between them at any given time.
After two hours, the southbound car would have traveled 48 mi/h * 2 h = 96 miles, and the westbound car would have traveled 20 mi/h * 2 h = 40 miles. Therefore, the distance between the cars is the hypotenuse of a right triangle with sides 96 miles and 40 miles.
Using the Pythagorean theorem, the distance between the cars is √(96^2 + 40^2) = √(9216 + 1600) = √10816 = 104 miles.
Since two hours have passed, the rate at which the distance is increasing is 104 miles / 2 hours = 52 mi/h. Therefore, the distance between the cars is increasing at a rate of 52 mi/h.
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Help me with this!!!! ( fake answers will be reported :)) )
Answer:
16
Step-by-step explanation:
3x-2x=8
x=8
QR=8*2=16
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