y changes by approximately 0.807 units as t changes from 1 to 6.
To find how much y changes as t changes from 1 to 6, we need to integrate the given derivative with respect to t:
y(t) = ∫ 6e^(-0.08(t-5)^2) dt
We need to evaluate the above integral between t=1 and t=6 to find the change in y over that interval.
y(6) - y(1) = ∫₁⁶ 6e^(-0.08(t-5)^2) dt
Unfortunately, this integral cannot be solved analytically. However, we can approximate the value using numerical methods. One common method is to use a numerical integration technique such as the trapezoidal rule or Simpson's rule. These methods use discrete approximations to the integral to compute an estimate of its value.
Using the trapezoidal rule with 10 subintervals, we get:
y(6) - y(1) ≈ (5/18) [6e^(-0.08(1-5)^2) + 4(6e^(-0.08(1.5-5)^2) + 2(6e^(-0.08(2-5)^2) + ... + 2(6e^(-0.08(5.5-5)^2) + 4(6e^(-0.08(6-5)^2) + 6e^(-0.08(6-5)^2))]
y(6) - y(1) ≈ 0.807
Therefore, y changes by approximately 0.807 units as t changes from 1 to 6.
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Which number line shows the solution of –5x + 10 > –15?
Answer:
b
Step-by-step explanation:
Answer:
Where is the number line?? ;-;
Step-by-step explanation:
Dude I cant answer if you dont show me the number lines
middle school math!
really easy points :D
Answer:
check b, c, and d
Step-by-step explanation:
not all functions are linear so don't click A.
Answer:
I'm not sure if it's c but b and d are true
Step-by-step explanation:
Sorry this is late.... need the points
Find the equation of the set of points P, the sum of whose distances from A(4,0,0) and B(−4,0,0) is equal to 10.
The equation of the set of points P, the sum of whose distances from A(4,0,0) and B(−4,0,0) is equal to 10 is (x - 4)² + (x + 4)² + y² + z² = 25.
In the given problem, we are required to find the equation of the set of points P, the sum of whose distances from A(4,0,0) and B(−4,0,0) is equal to 10. Therefore, the equation of the set of points P can be found using the distance formula. Let P(x, y, z) be a point on the set of points P.
The distance between the point P(x, y, z) and A(4, 0, 0) can be found using the distance formula:
d1(P, A) = √[(x - 4)² + y² + z²]
Similarly, the distance between the point P(x, y, z) and B(-4, 0, 0) can be found using the distance formula:
d2(P, B) = √[(x + 4)² + y² + z²]
Therefore, according to the problem statement, we have:
d1(P, A) + d2(P, B) = 10
Substituting the values of d1(P, A) and d2(P, B) in the above equation, we get:
√[(x - 4)² + y² + z²] + √[(x + 4)² + y² + z²] = 10
Squaring both sides of the above equation, we get:
(√[(x - 4)² + y² + z²] + √[(x + 4)² + y² + z²])² = 100
On simplifying, we get:
2[(x - 4)² + (x + 4)²] + 2y² + 2z² = 100
On simplying it more, the required equation of the set of points P, the sum of whose distances from A(4, 0, 0) and B(-4, 0, 0) is equal to 10 becomes (x - 4)² + (x + 4)² + y² + z² = 25.
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A nurse mixes 50 cc of a 70% saline solution with a 10% saline solution to produce a 15% saline solution. How much of the solution should he use?
We have an algebraic problem about proportions of solutions. We will find that the nurse needs to use 550 cm^3 of the 10% solution.
We know that the nurse mixes 50cm^3 of 70% saline solution with a volume V of a 10% saline solution, such that the end product would be 15% saline solution.
We need to find the value of V.
The total amount of salt in each solution is given by the product between the volume and the percent of salt in it (written as a decimal, for example, 70% would be 0.7)
Then we have:
50cm^3*0.7 + V*0.1 = (50cm^3 + V)*0.15
Above says that the salt of the mix must be equal to the salt in a 15% solution with a volume of (50cm^3 + V)
Now we just need to solve this for V.
50cm^3*0.7 + V*0.1 = (50cm^3 + V)*0.15
50cm^3*0.7 + V*0.1 = 50cm^3*0.15 + V*0.15
50cm^3*0.7 - 50cm^3*0.15 = V*0.15 - V*0.1
27.5 cm^3 = V*(0.15 - 0.1) = V*0.05
(27.5 cm^3)/0.05 = V = 550 cm^3
The nurse needs to use 550 cm^3
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I need help please on this question
If quiz grades are normally distributed with a mean of 80. and a standard deviation of 7.0, what is the probability that a student will have a quiz grade of 90. or greater?
The probability of a student having a quiz grade of 90 or greater is 7.4%.
The probability of a student having a quiz grade of 90 or greater can be calculated using the standard normal distribution. The formula used to calculate this probability is P(x ≥ 90) = 1 - P(x < 90).
The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. To convert our quiz grade to a z-score, we must subtract the mean (80) from our quiz grade (90) and divide by the standard deviation (7). This gives us a z-score of 1.43.
To calculate the probability of a quiz grade of 90 or greater, we subtract the cumulative probability of a z-score of 1.43 from 1. This can be done using a z-table or a calculator. The result of this calculation is 0.0740 or 7.4%.
In conclusion, the probability of a student having a quiz grade of 90 or greater is 7.4%.
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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. A tank contains 15,000 L of brine with 22 kg of dissolved salt. Pure water enters the tank at a rate of 150 L/min. The solution is kept thoroughly mixed and drains from the tank at the same rate. Exercise (a) How much salt is in the tank after t minutes? Click here to begin! Exercise (b) How much salt is in the tank after 10 minutes? Click here to begin! Need Help? Read It Talk to a Tutor
Answer:
a) 22e^-0.01t kilograms
b) about 19.906 kilograms
Step-by-step explanation:
You want an equation for the amount of salt in a 15 kL brine tank initially containing 22 kg of salt if 150 L/min of the contents is replaced by pure water.
(a) Remaining saltThe quantity of salt s(t) in kilograms can be described by the differential equation ...
s(0) = 22; s'(t) = -150/15000·s(t)
The solution can be found by separation of variables.
\(\displaystyle\dfrac{ds}{dt}=-0.01s\\\\\int{\dfrac{1}{s}}\,ds=-0.01\int{}\,dt\\\\\ln{s}=-0.01t+c_1\\\\s=c_2\cdot e^{-0.01t}\qquad\text{where $c_2$ is $s(0)=22$}\\\\\boxed{s(t)=22e^{-0.01t}}\)
(b) s(10)The amount of salt remaining after 10 minutes is ...
s(10) = 22·e^(-0.01·10) = 22·e^-0.1
s(10) ≈ 19.906 . . . . kilograms
There is about 19.906 kg of salt in the tank after 10 minutes.
__
Additional comment
The initial rate of change of the amount of salt is -22/100 kg/min, so after 10 minutes, we expect an approximate reduction by 2.2 kg to 19.8 kg. Since the rate slows as salt is removed, the value 19.9 kg after 10 minutes is reasonable.
There are a couple of places where the integration constant can be put in the equation for the salt quantity. As a multiplier of the exponential function, its value is found in a straightforward way.
Stephen Curry plays for the Golden States Warriors and touts a 90% free throw shooting record. If he shot 20 free throws in a game, how many did he miss?
I NEED HELPPPPPPPP PLEASE
He missed 2.
90% of 10 is 9. So he makes 9 shots and misses 1 for every 10 free throws.
So just double that number (1 shot missed) and so you get 2 missed shots
Hope this helps, and please consider marking branliest if this did
Consider a cost-benefit-trade-off problem having the following data. Benefit Contribu tion per Unit of Each Activity Accept able Level Benefit 2 60 30 126 Unit cost$60 $50 a. Formulate a linear programming model for this problem on a spreadsheet. b. Use the spreadsheet to check the following solutions: (x1,32)(7,7. (7. 8), (8. 7), (8, 8) (8, 9), (9, 8). Which of these solutions are feasible? Which of these feasible solutions has the best value of the objective function? c. Express the model in algebraic fom. d. Use the graphical method to solve this model.
The value of the objective function at this point is Z = 840. The solution (7, 7) is feasible.
a. Formulation of linear programming model:To solve this problem, the following linear programming model can be used:x1 = Activity 1 (in units)x2 = Activity 2 (in units)Maximize Z = 60x1 + 50x2 subject to30x1 + 126x2 ≤ 4,752 (Acceptable limit)60x1 + 126x2 ≤ 8,436 (Benefit 1)Step-by-step explanation is given below:Function: Linear Programming modelSolution:
a. Formulation of linear programming model:To solve this problem, the following linear programming model can be used:x1 = Activity 1 (in units)x2 = Activity 2 (in units)Maximize Z = 60x1 + 50x2 subject to30x1 + 126x2 ≤ 4,752 (Acceptable limit)60x1 + 126x2 ≤ 8,436 (Benefit 1)
b. Checking for feasible solutionsWe need to check the following solutions:(x1, 32) (7, 7) (7, 8) (8, 7) (8, 8) (8, 9) (9, 8)Let us substitute the values in the linear programming model for each solution:Solution: (x1, 32)30x1 + 126(32) = 4,752 + 4,032 = 8,784 > 4,752 (Infeasible)Solution: (7, 7)30(7) + 126(7) = 966 < 4,752 (Feasible)60(7) + 126(7) = 1,092 < 8,436 (Feasible)Solution: (7, 8)30(7) + 126(8) = 5,070 > 4,752 (Infeasible)Solution: (8, 7)30(8) + 126(7) = 5,016 > 4,752 (Infeasible)Solution: (8, 8)30(8) + 126(8) = 5,196 > 4,752 (Infeasible)Solution: (8, 9)30(8) + 126(9) = 5,322 > 4,752 (Infeasible)Solution: (9, 8)30(9) + 126(8) = 5,358 > 4,752 (Infeasible)Therefore, only the solution (7, 7) is feasible.
c. Expressing the model in algebraic form:We have,x1 = Activity 1 (in units)x2 = Activity 2 (in units)Maximize Z = 60x1 + 50x2 subject to30x1 + 126x2 ≤ 4,752 (Acceptable limit)60x1 + 126x2 ≤ 8,436 (Benefit 1)The solution x = (7, 7) is feasible and optimal, with Z = 60(7) + 50(7) = 840.d. Using the graphical method:Below is the graph plotted for the above linear programming model:graph{(y-4752)/126<=-(3/2)x+316}The feasible region is given by the shaded region in the graph. The optimal solution is (7, 7), which is at the point of intersection of the two lines. The value of the objective function at this point is Z = 840.
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Find m∠ABC and m∠CBD if m∠ABD =120°
The measures of angles m∠ABC = 36° and m∠CBD = 84°.
What is geometryGeometry is a branch of mathematics that deals with shapes, sizes, angles, and dimensions of objects.
The angle m∠ABD = 120° is the result for the sum of the two angles m∠ABC and m∠CBD so;
m∠ABC + m∠CBD = m∠ABD
2x + 5x - 6 = 120°
7x - 6 = 120° {add 6 to both sides}
7x = 120° + 6°
7x = 126° {divide through by 7}
x = 126°/7
x = 18
2x = 2(18) = 36°
5x - 6 = 5(18) - 6 = 84°
Therefore, the geometry question have the measure of angles m∠ABC = 36° and m∠CBD = 84°.
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Possible Question:
Find m∠ABC and m∠CBD if m∠ABD =120°, m∠ABC = 2x, m∠CBD = (5x - 6)°, and the angle m∠ABD is the sum of m∠ABC and m∠CBD.
the quotient of n and 3 is less than 5
Jamari says the slope of the line shown is 2/3.
Mia says the slope is 4/6.
Part 1) Explain how both answers represent the slope of the line.
Part 2) What is Mia's next step?
Answer:
Kindly check explanation
Step-by-step explanation:
Given that:
Jamari's slope value = 2/3
Mia's slope value = 4/6
Even though the points used to calculate the slope aren't given, the problem is still solvable.
Slope = Rise / Run.
The value of slope calculated by Jamari and Mia is the same from the result given, with the only notable difference being that;
Jamari reduced his solution to it's simplest form while, Mia did not
The next step Mia should take is :
Reduce 4/6, tomits lowest term
Find a number which can divide both until. Both aren't designed visible by the same number.
4/6 = 2/3 [Dividing both by 2]
“Won’t you please please help me”
Answer: Angle BGA
Step-by-step explanation:
When added together they make 180 degrees.
What are the steps to find this answer?
Find the slope from the 2 pairs of points.
(5,-7), (4,-10)
Answer:
3
Step-by-step explanation:
Slope=rise/run
-10 - -7=-10+7=-3
4-5=-1
-3/-1=3
(Final equation y=3x-22)
In august how do i twice the numbers of pets were sold than in april?
To double the wide variety of pets sold in August as compared to April, you need to decide the number of pets sold in April after which multiply that wide variety through 2.
The variable "A" represents the number of pets sold in April. By multiplying "A" by 2, you purchased the favored quantity of pets offered in August, that is 2A.
This manner that the number of pets offered in August is twice the variety sold in April.
Thus, by enforcing strategies including promotional gives, marketing campaigns, or unique activities, you may potentially entice greater clients and increase the range of puppy sales in August, accordingly reaching the aim of doubling the income in comparison to April.
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What did you multiply together to find the sales tax?
Answer:
Step-by-step explanation:
To find the sales tax on a purchased or sold item, first convert the sales tax percentage into the equivalent decimal fraction. If the sales tax rate is 5.5%, then the desired decimal fraction is 0.055. Next, multiply the selling price of the purchased or sold item by this decimal fraction. If, for example, the selling price is $100, the sales tax is 0.055($100) = $5.50
square root of (x-15)(x-15)
Answer: x - 15
Step-by-step explanation:
The answer is x - 15
Answer:
x-15
Step-by-step explanation:
The Abubakar family household uses 850 kWh of electricity per month (kWh stands for Kilowatt hour, a measure of electricity usage). They want to decrease their electricity usage, so they begin to decrease their usage by 25 kWh per month. The equation y = –25x + 850 can be used to model this scenario.
How many kWh of electricity will they be using 12 months after they've started doing this?
Answer:
550 kWh
Step-by-step explanation:
To find the number of kilowatt hours of electricity the Abubakar family will be using 12 months after they've started decreasing their usage, we can substitute 12 for x in the equation y = –25x + 850. This gives us y = –25 * 12 + 850 = –300 + 850 = 550.
Therefore, the Abubakar family will be using 550 kilowatt hours of electricity 12 months after they've started decreasing their usage.
Graph the line that represents a proportional relationship between ddd and ttt with the property that an increase of 555 units in ttt corresponds to an increase of 222 units in ddd. What is the unit rate of change of ddd with respect to ttt
a) The unit rate of change of d with respect to t is equal to 1.6
b) the graph of the line in the attached figure.
Given: A proportionate relationship between d and t with the characteristic that a rise in t of 5 units causes a rise in d of 8 units.
To locate: A rise of 5 units in t causes a rise of 8 units in d, according to the line's unit rate of change with respect to t.
=> Slope = Δd/Δt = 8/5 = 1.6
the proportional relationship between d and t
=> d ∝ t
=> d = 1.6t
t d=1.6t
0 0
1 1.6
2 3.2
3 4.8
Plot the points and draw a line passing through points.
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help plshelp plshelp plshelp plshelp pls
Answer:
90 grams of paint
Step-by-step explanation:
Easy, if you check this is a 3 x 3 x 2 cube which totals 18
So if each small cube is 5 grams
18 * 5 = 90
The interior angles in a regular polygon sum to 1620°.
How many sides does the polygon have?
Answer:
the answer to your question is 11
Step-by-step explanation:
1620÷180= 9
9+2=11
Find the measurement of V.
Answer: 60 degrees
Step-by-step explanation: Because all sides are equilateral, and in an equilateral triangle all angles are 60 degrees, hope that helps.
please help it says to choose one or more!
Answer:
it's A And CStep-by-step explanation:
Always remember:beluga always love answer your question by following these steps:Follow belugaask meBrainliest me first oktake note please: everyone i answer question I got happy:)please don't delete Your question beacause Brainliest Marks & pointswill be loseAnswer: it’s A and C (45 ft and 37 ft) I think
how many days could a 60kg deer survive without food at -20 degrees - has 5kg of fat
18 days
The survival time of a 60kg deer without food at -20 degrees Celsius depends on various factors, including its age, sex, and physical condition. However, assuming the deer is healthy and has 5kg of fat, it could potentially survive for around 30 to 50 days without food.
The exact survival time can vary depending on several factors, such as the deer's level of physical activity, environmental conditions, and how much energy it is expending to stay warm in the cold temperature. Additionally, if the deer is able to find sources of water, this can also increase its chances of survival.
It's important to note that this is just an estimate and that the actual survival time may vary. If the deer is injured or sick, its chances of survival may be reduced, and it may not be able to survive as long without food.
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Complete Question
How many days could a 60kg deer survive without food at -20 degrees Celsius if it has 5kg of fat?
I need help with this please
The segment AB is a radius and the notation is ↔ AB
Writing the notation with the term that best describes the segment ABFrom the question, we have the following parameters that can be used in our computation:
The circle
On the circle, we can see that
The segment AB goes from the center of the circle to a point on the circle
A line that goes from the center of the circle to a point on the circle is the radius of the circle
This means that the segment AB is a radius and the notation is ↔ AB
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2. Two painting companies were hired to paint two different buildings. The amount of area
left to paint on both buildings is related to the amount of time that the painters spend
on painting each of them. This relationship is shown in the two graphs below:
a. what are the linear functions modelling the two relationships in the graphs above?
b. which painting company is painting their building at a faster rate? how much faster?
c. which painting company had less area to paint when they began painting their building?
d. how many hours will it take each painting company to completely finish painting their building?
pls help its due today and its 100 points
#a
#1
(0,2100)(7,2000)Slope:-
m=2000-2100/7=-100/7Equation in point slope form
y-2100=-100/7(x)y=-100/7x+2100Slope=-100/7
#2
(0,1800)(8,1700)Slope
m=1700-1800/8=-100/8Y intercept=1800
Equation
y=-100/8+1800Slope=-100/8
#b
First company is painting faster
-100/7 ÷-100/88/7 times faster#c
Comapny B
as their y intercept is 1800 which is less than 2100#d
for #1
-100/7x+2100=0100/7x=2100x=21(7)=147hours#2
100/8x=1800x=18(8)x=144hoursGive the coordinates of D (-2, -4) after a 270 degrees counterclockwise rotation about the origin followed by a reflection across the x-axis
Transformation involves changing the position of a point.
The image of D after the transformation is (-4,-2)
The point is given as:
\(\mathbf{D = (-2,-4)}\)
The rule of 270 degrees counterclockwise rotation is:
\(\mathbf{(x,y) \to (y,-x)}\)
So, we have:
\(\mathbf{D' = (-4,2)}\)
The rule of reflection across the x-axis is:
\(\mathbf{(x,y) \to (x,-y)}\)
So, we have:
\(\mathbf{D" = (-4,-2)}\)
Hence, the image of D after the transformation is (-4,-2)
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Help me with number 14 plss
Answer:
-3 1/5
Step-by-step explanation:
to find the slope of the line you use the equation (y2 - 1) / (x2 - x1)
when plugged in you get
(5 + 3) / (-2 1/4 - 1/4)
then you do what is inside the parenthesis
8 / -2 1/2
8 / -2.5
lastly you divide
you get -3 1/5
that is your answer
Multiply and simplify if possible - radical functions. Thank you!
We want to simplify the following expression
\(\sqrt{7x}(\sqrt{x}+7\sqrt{7})\)First, we can apply the distributive rule to rewrite this product
\(\sqrt{7x}(\sqrt{x}+7\sqrt{7})=(\sqrt{7x})(\sqrt{x})+(\sqrt{7x})(7\sqrt{7})\)Then, using the following property
\(\sqrt{x}\cdot\sqrt{y}=\sqrt{x\cdot y}\)we can rewrite our expression as
\((\sqrt{7x})(\sqrt{x})+(\sqrt{7x})(7\sqrt{7})=\sqrt{7x\cdot x}+7\sqrt{7x\cdot7}\)We can remove the squared terms out of the root
\(\sqrt{7x\cdot x}+7\sqrt{7x\cdot7}=x\sqrt{7}+7\cdot7\sqrt{x}=x\sqrt{7}+49\sqrt{x}\)and this is our answer.
\(\sqrt{7x}(\sqrt{x}+7\sqrt{7})=x\sqrt{7}+49\sqrt{x}\)If DF and G
are parallel lines and mZFEC = 134º, what is mZGHE?
Answer:
46
Step-by-step explanation:
Angle CED and GHE are equal as the lines are parallels. Also, the line rom D to F will be a total of 180.
Therefor, substract the angle FEC from 180 and you get the angle CED which is equal to GHE