If you were to roll the dice one time what is the probability it will not land on a 1

Answer:

7. 8 I think (typing more for the limit)

Answer:

7.8

Step-by-step explanation:

The perimeter of shed is, (6x+ 4)

The area of the shed is, (2x² + 5x + 3)

A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.

We have to given that;

Shirley is building a shed. The length is 2x + 3 feet long and the width is

x + 1 feet long.

Now, We know that;

The perimeter of rectangle = 2 (Length + Width)

Substitute all the values, we get;

⇒ Perimeter = 2 (2x + 1 + x + 1)

⇒ Perimeter = 2 (3x + 2)

⇒ Perimeter = (6x + 4)

And, Area of rectangle = Length × Width

Substitute all the values , we get;

⇒ Area = (2x + 3) × (x + 1)

⇒ Area = (2x² + 2x + 3x + 3)

⇒ Area = (2x² + 5x + 3)

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Therefore, the volume of the paper cone to the nearest tenth is 418.7 inches cubed.

The volume of the paper cone that Gretchen made to hold a gift for a friend is given by;V= (1/3)πr²hWhere;r = radius of the paper coneh = height of the paper coneπ = 3.14

Given that;Height of the paper cone (h) = 16 inches Radius of the paper cone (r) = 5 inchesWe are to find the volume (V) of the paper cone to the nearest tenth of an inch.

To obtain the volume of the paper cone, we can substitute the values of r and h in the formula above to obtain;

\(V= (1/3)\pir^2hV\)= \((\frac{1}{3} ) \times 3.14\times5^2 \times16V = (\frac{1}{3} ) \times 3.14\times25\times16V = (\frac{1}{3}) \times 1256V=418.7\)

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after 14 years, there will be approximately 1.97g of the radioactive substance remaining.

To solve this problem, we can use the concept of exponential decay for radioactive substances. The decay of a radioactive substance can be modeled by the equation:

N(t) = N₀ * e^(-kt),

where N(t) is the amount of substance at time t, N₀ is the initial amount of substance, e is the base of the natural logarithm, k is the decay constant, and t is the time elapsed.

In this case, we are given that the initial amount N₀ is 10g and the amount after 9 years N(9) is 5g. We can use this information to find the value of k.

5 = 10 * e^(-9k).

Divide both sides of the equation by 10:

0.5 = e^(-9k).

Take the natural logarithm of both sides:

ln(0.5) = -9k.

Solve for k:

k = ln(0.5) / -9.

Now that we have the value of k, we can use it to find the amount of substance after 14 years, N(14):

N(14) = N₀ * e^(-kt).

N(14) = 10 * e^(-ln(0.5) / -9 * 14).

N(14) = 10 * e^(14 * ln(0.5) / 9).

N(14) ≈ 10 * 0.197 = 1.97.

Therefore, after 14 years, there will be approximately 1.97g of the radioactive substance remaining.

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Answer:

4/5

Step-by-step explanation:

Thus, 4/5 is the simplified fraction for 48/60 by using the GCD or HCF method. Thus, 4/5 is the simplified fraction for 48/60 by using the prime factorization method.

Answer:

The answer is 0.

Step-by-step explanation:

10q-10q can be subtracted due to the fact that they have the same variable, the answer would be zero as you are decreasing both by the same amount.

Answer:

\(0\)

Step-by-step explanation:

Let's simplify step-by-step.

\(10q -10q\)

\(=10q+-10q\)

\(= 0\)

Answer:

the answer is 0.0001 I guess it's the first one

Step-by-step explanation:

10 to the power of -4 is equal to 1/10^4

and that is 0.0001

The Solution in inequality form is 7 ≤ x ≤ 10.

The Solution in interval notation: [7,10].

Given the data in the question;

-x - 8 ≤ -15 and -18 ≤ -x - 8

To solve, simplify the first part of the inequality by solving for x.

-x - 8 ≤ -15

Add 8 to both sides

-x - 8 + 8 ≤ -15 + 8

-x ≤ -7

Divide both sides by -1

Note that when dividing both sides of an inequality by a negative value, the inequality sign flips direction.

-x/-1 ≥ -7/-1

x ≥ 7

Next, simplify the second part of the inequality by solving for x

-18 ≤ -x - 8

Rewrite as

-x - 8 ≥ -18

Add 8 to both side

-x - 8 + 8 ≥ -18 + 8

-x ≥ -10

Divide both sides by -1

Note that when dividing both sides of an inequality by a negative value, the inequality sign flips direction.

-x/-1 ≤ -10/-1

x ≤ 10

Now, the intersection consist of the elements that are contained in both intervals.

The Solution in inequality form is 7 ≤ x ≤ 10.

The Solution in interval notation: [7,10].

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The statement "Quadrilaterals A and B are both squares" does not provide enough information to determine whether A and B are scale copies of one another.

To determine if two quadrilaterals are scale copies of each other, we need to compare their corresponding sides and angles. If the corresponding sides of two quadrilaterals are proportional and their corresponding angles are congruent, then they are scale copies of each other.

In this case, since both A and B are squares, we know that all of their angles are right angles (90 degrees). However, we do not have any information about the lengths of their sides. Without knowing the lengths of the sides of A and B, we cannot determine if they are scale copies of each other.

Therefore, the statement cannot be determined as true or false based on the given information.

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∇²V = Vrr+2/r Vr+1/r^2 VQQ+cotθ/r^2VQ+VQQ /\(r^{2}\)sinQ is a valid representation of the Laplacian in spherical coordinates, combining the appropriate partial derivatives and accounting for the geometric factors inherent in this coordinate system.

1. The Laplacian operator in spherical coordinates (∇²) can be expressed as a combination of partial derivatives with respect to the radial distance (r) and angular coordinates (θ, φ). The given expression ∇²V = Vrr+2/r Vr+1/r^2 VQQ+cotθ/r^2VQ+VQQ/r^2sinQ is indeed a representation of the Laplacian in spherical coordinates. It consists of terms involving second derivatives with respect to the radial coordinate (Vrr) and angular coordinates (VQQ), as well as terms involving first derivatives with respect to the radial coordinate (Vr) and angular coordinates (VQ). The factors of 1/r^2 and cotθ/r^2 account for the geometric factors inherent in spherical coordinates.

2. In spherical coordinates, the Laplacian operator (∇²) is defined as the sum of second partial derivatives with respect to each coordinate. The coordinates involved are the radial distance (r), the polar angle (θ), and the azimuthal angle (φ). The Laplacian can be expressed as:

∇²V = (1/r²) ∂(r²∂V/∂r) + (1/(r²sinθ)) ∂(sinθ∂V/∂θ) + (1/(r²sin²θ)) ∂²V/∂φ²

Comparing this with the given expression: ∇²V = Vrr+2/r Vr+1/r^2 VQQ+cotθ/r^2VQ+VQQ/r^2sinQ

3 We can see that the terms Vrr, Vr, VQQ, VQ, and VQQ are present, which correspond to the second partial derivatives with respect to the radial coordinate (r) and the angular coordinates (θ, φ). The factors of 1/r^2 and cotθ/r^2 are included to account for the geometric factors in spherical coordinates. The term 1/r^2 arises due to the expansion of the Laplacian in terms of spherical harmonics, and the cotθ term appears when differentiating with respect to the polar angle (θ). The presence of sinθ in the denominator also arises from the spherical coordinates' geometry.

4. Therefore, the given expression ∇²V = Vrr+2/r Vr+1/r^2 VQQ+cotθ/r^2VQ+VQQ/r^2sinQ is a valid representation of the Laplacian in spherical coordinates, combining the appropriate partial derivatives and accounting for the geometric factors inherent in this coordinate system.

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percentage of students say they have witnessed hazing and did not report it are  = 95%

No matter how voluntarily a person is to take part, hazing, initiation or deposition are all actions that are demanded of someone when they join or participate in a group and which humiliate, degrade, abuse, or imperil them.

involves humiliating a person or group. involves making fun of someone or something. involves or includes the deliberate destruction of or removal of private or public property for the purpose of affiliation with, initiation into, or as a requirement for continuing membership in an organization.

Paddling, beating, or other types of attack. Branding. consumption of disgusting substances or mixtures under duress or force.

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(0.82 , 3.38) is estimate of the population mean weight loss for this diet in standard deviation.

What is standard deviation in math?

mean weight loss = 2.1lb

standard deviation = 4.8lb

sample size n = 40

std error = stdev/sqrt(n) = 4.8/sqrt(40) = 0.76

degrees of freedom = n - 1 = 39

critical value for alpha 0.10 and df 39 = +1.68

margin of error = critical value * std error = +1.68 * 0.76 = +1.28

confidence interval = sample mean + margin of error = 2.1 +1.28 = (0.82 , 3.38)

Yes it is effective since the values > 0mean weight loss = 2.1lb

standard deviation = 4.8lb

sample size n = 40

std error = stdev/sqrt(n) = 4.8/sqrt(40) = 0.76

degrees of freedom = n - 1 = 39

critical value for alpha 0.10 and df 39 = +1.68

margin of error = critical value * std error = +1.68 * 0.76 = +1.28

confidence interval = sample mean + margin of error = 2.1 +1.28 = (0.82 , 3.38)

Yes it is effective since the values > 0

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Answer:

each steak burger costs $6.50

each order of fries costs $2.25

Answer:

x<-2

Step-by-step explanation:

17+4x<9

4x<-8

x<-2

The solution is:

Work/explanation:

Recall that the process for solving an inequality is the same as the process for solving an equation (a linear equation in one variable).

Make sure that all constants are on the right:

\(\bf{4x < 9-17}\)

\(\bf{4x < -8}\)

Divide each side by 4:

\(\bf{x < -2}\)

Answer:

A B and C are correct

Step-by-step explanation:

4 yards = 12 feet = 12x12 = 144 inches

A is correct since 15 feet > 12 feet

B is correct since 150 inches > 144 inches

C is correct since 3 yards + 4 feet = 4 yards and 1 foot > 4 yards

D  is incorrect since 3 feet + 15 inches is 4 feet and 3 inches < 12 feet

E is incorrect since 10 feet + 11 inches < 12 feet

Answer:

1 i think

Step-by-step explanation:

Answer: C is correct answer

Step-by-step explanation:

Answer:

25

Step-by-step explanation:

c^2=a^2+b^2

where c = hypotenuse

so, x^2 = 24^2+7^2

x^2 = 576 + 49

x^2 = 625

x = square root of 625

x = 25

The mass of NaF that is required to make a standard 1 solution of 250 ml 0.1 M F- solution is 5.45 g of NaF. The number of moles in a solution is the concentration in moles per litre multiplied by the volume in litres.

To calculate the mass of a solute required, we need to first calculate the number of moles required. We can then use the molar mass of the solute to calculate its mass.To calculate the number of moles required in this question, we can use the formula:n = c × V where n is the number of moles, c is the concentration in moles per litre and V is the volume in litres. We have:c = 0.1 M

and V = 0.25 L

Substituting these values into the formula gives:n = 0.1 mol/L × 0.25 L

= 0.025 mol

Now we can use the molar mass of NaF to calculate its mass. The molar mass of NaF is 41.99 g/mol (22.99 g/mol for Na and 19.00 g/mol for F).

We have:n = 0.025 mol

solving for mass:m = n × M

where M is the molar mass of NaF.

Substituting gives:m = 0.025 mol × 41.99 g/mol ≈ 1.05 g

However, this is the mass required to make 0.25 L of solution. To make 1 L of solution, we would need to multiply the mass by 4. Therefore, the mass of NaF required to make a standard 1 solution of 250 ml 0.1 M F- solution is:1.05 g × 4 = 4.20 g Rounding this to two significant figures gives:4.2 g NaF.

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The number of jumbo cans of frosting would she need to frost 280 cupcakes is 8.

Given that, Bette used 3 jumbo cans of frosting to frost 105 cupcakes and 5 jumbo cans of frosting to frost an additional 175 cupcakes.

Proportion is a mathematical comparison between two numbers.  According to proportion, if two sets of given numbers are increasing or decreasing in the same ratio, then the ratios are said to be directly proportional to each other.

Let number of jumbo cans of frosting would she need to frost 280 cupcakes be x.

Now the proportion is

3/105 = 5/175 = x/280

⇒ 5/175 = x/280

⇒ 175x = 280 × 5

⇒ x = 1400/175

⇒ x = 8

Therefore, the number of jumbo cans of frosting would she need to frost 280 cupcakes is 8.

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Answer:

0.875

Step-by-step explanation:

George's dog is approximately 32.41 meters away from its crate, if it ran 22 meters, turned and ran 11 meters, and then turned 120° to face its crate.

To determine the distance from George's dog to its crate after the described movements, we can use the concept of a triangle and trigonometry.

The dog initially runs 22 meters, then turns and runs 11 meters, forming the two sides of a triangle. The third side of the triangle represents the distance from the dog's final position to the crate.

To find this distance, we can use the Law of Cosines, which states that in a triangle with sides a, b, and c and angle C opposite side c, the equation is c² = a² + b² - 2abcos(C).

In this case, a = 22 meters, b = 11 meters, and C = 120°. Plugging these values into the equation, we have

c² = 22² + 11² - 2(22)(11)cos(120°).

Evaluating the expression, we get

c ≈ 32.41 meters.

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Answer:

15x+30y−220

Step-by-step explanation:

hope this helps

Solution

To solve this problem, we only need to equate and solve for H

Answer:

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relations between sides and trig functions in right triangles. These can be used to solve the triangles shown.

__

  Sin = Opposite/Hypotense

  sin(48°) = 15/o

  o = 15/sin(48°) ≈ 20.18 . . . . . . . . . multiply by o/sin(48°)

  Cos = Adjacent/Hypotenuse

  cos(48°) = b/o

  b = o·cos(48°) = 20.18·cos(48°) ≈ 13.51

For triangle BOX, o = 20.18, b = 13.51.

__

  Sin = Opposite/Hypotense

  sin(25°) = i/30

  i = 30·sin(25°) ≈ 12.68

  Cos = Adjacent/Hypotenuse

  cos(25°) = n/30

  n = 30·cos(25°) ≈ 27.19

For triangle TIN, i = 12.68, n = 27.19.

Answer:

do the following

Step-by-step explanation:

subtract the 2nd equation from the 1st....

x-2y = 14

-(x+ 3y = 9)

______________

-5y=5

y= -1

since you know that y is = to - 1  pick  the 3rd answer

The answer is:

C) (12, -1)

Answer:

1/3 ( 5y-2) = x

Step-by-step explanation:

5y = 3x+2

Subtract 2 from each side

5y -2 = 3x+2-2

5y-2 = 3x

Divide each side by 3

1/3 ( 5y-2) = 3x/3

1/3 ( 5y-2) = x

Answer:

Move all the terms that do not contain k to the right side of the equation, then solve.

\(k=3+\frac{z}{2}\)

Hope this helps!