If you were dropped at a completely random spot on the planet, what would be your chances of landing on land?.

Based on the equations e=hv and e=hc/^lambda, we can say that energy increases as frequency increases. Therefore, FM radio waves with a frequency of 1.015 x 10^8 Hz (101.5 MHz) have less energy compared to visible green light with a frequency of 5 x 10^14 Hz.

To understand this better, we can look at the frequency and wavelength of both the FM radio waves and visible green light. FM radio waves have a lower frequency of 1.015 x 10^8 Hz (101.5 MHz) and a longer wavelength of approximately 3 meters, while visible green light has a higher frequency of 5 x 10^14 Hz and a shorter wavelength of approximately 500 nanometers.

Since energy is directly proportional to frequency and inversely proportional to wavelength, we can conclude that visible green light has higher energy compared to FM radio waves. This is because visible green light has a higher frequency and a shorter wavelength, which means that it carries more energy per photon.

In summary, visible green light with a frequency of 5 x 10^14 Hz has higher energy compared to FM radio waves with a frequency of 1.015 x 10^8 Hz (101.5 MHz) due to its higher frequency and shorter wavelength.

Learn more about Money here:

https://brainly.com/question/1932868

#SPJ11

Answer:

All of the above

Explanation:

A circuit must have wires, a light bulb, a battery and no gaps if u want to light up a bulb.

Answer:

2-3-1-4

Explanation:

First you will need an energy source so 2 is the first step.

Then the lead and lead oxide are reformed during re-charge so 3 is the second step.

The battery is back in operation when Lead dissolves in acid so 1 is the third step.

Battery produces electrons so 4 is the final step.

Answer:

ohhhhhhhhhhhhhhhhjhhhhhhh

Solve for the linear/tangential speed:

a = v²/r

where a = centripetal acceleration, v = speed, and r = radius.

4.7 m/s² = v²/(0.3 m)

v² = (0.3 m) (4.7 m/s²)

v ≈ 3.96 m/s

For every time the record completes one revolution, a fixed point on the edge of the record travels a distance equal to its circumference, which is 2π (0.3 m) ≈ 1.88 m. So if 1 rev ≈ 1.88 m, then the angular speed of the record is

(3.96 m/s) (1/1.88 rev/m) ≈ 7.46 rev/s

Take the reciprocal of this to get the period:

1 / (7.46 rev/s) ≈ 0.134 s/rev

So it takes the record about 0.134 seconds to complete one revolution.

The focal length of the mirror is 22 cm.

Given that,

An inverted image is magnified by 2 when the object is placed 22 cm in front of a concave mirror.

Formula used:

Focal length of a mirror is given by the relation;

1/f = 1/v + 1/u

Where,

f = focal length of the mirror

v = image distance

u = object distance

We have been asked to determine the focal length of the mirror.

Given, the object is placed 22 cm in front of a concave mirror.The magnification is 2, we have;

Magnification m = - v/u = -2

Since the image is inverted, the value of magnification will be negative.

u = -11 cm

v = 22 cm

Substituting the value of v and u in the equation, we get;

1/f = 1/v + 1/u

Putting the values, we get:

1/f = 1/22 + 1/(-11)

1/f = 1/22 - 1/11 (taking LCM)

1/f = (2 - 4)/44f

= -44/2f = -22

To know more about focal visit :

brainly.com/question/15365254

#SPJ11

Given:

Height = 0.8 m

Initial velocity = 7.6 m/s

Given that the ball goes straight up, let's solve for the following.

(a) What will be the ball's velocity when it gets back to its original height.

Since the ball has an initial velocity of 7.6 m/s, the ball's velocity when it gets back to its original height will be the opposite of the initial velocity.

Here, the final velocity will be the same as the initial velocity but in the downward direction.

Therefore, the ball's velocity when it gets back to its original height will be -7.6 m/s

(b) How long will it take the volleyball to get to the top of its path.

To find how long it will take the volleyball to get to the top of its path, apply the formula:

Where:

vf is the final velocity at its maximum height = 0 m/s

vi is the initial velocity = 7.6 m/s

a is acceleration due to gravity = -9.8 m/s^2

d is the displacement

Let's solve for the displacement.

We have:

Now, to find the time it will take, apply the formula:

Where t is the time.

We have:

ANSWER:

(a) -7.6 m/s

(b) 0.78 s

A) energy of the recoiling electron (in J) is 2.656 × 10-14 J.

B) change in the photon's wavelength that occurs when an electron scatters an X-ray photon at 37∘ is 1.94 × 10-13 m.

Question 1. In Compton scattering the change in the frequency of the scattering photon is 4×10¹⁹ Hz. What is the energy of the recoiling electron (in J)?In Compton scattering, when a photon is scattered from a free electron, its wavelength increases by the Compton shift. Energy conservation, momentum conservation, and the assumptions of a free electron and a weak interaction give the Compton effect's physical basis.

The Compton scattering equation states that the incident photon's energy and the energy of the recoiling electron can be computed using the following formula: 1/λ' - 1/λ = h/mc (1 - cosθ)

Here, λ' - the scattered photon's wavelength

λ - the incident photon's wavelength - Planck's constant

m - the mass of the electron

c - speed of light in vacuum

θ - the angle between the incident photon's direction and the direction in which the scattered photon was detected.

As a result, using the equation given above we can calculate the energy of the recoiling electron as:

∆E = (hc / λ) (1 - cos θ)

     = hc / λ' - hc / λ

     = (6.626 × 10-34 Js) × (3 × 108 m/s) / (λ' - λ).

where, λ = speed of light / frequency= (3 × 108 m/s) / 4 × 1019 s-1

                = 7.5 × 10-12 mλ'

                = λ + ∆λ = (1 + ∆λ/λ) λ

                = (1 + ∆λ/λ) (3 × 108 m/s)

             E = hc / λ' - hc / λ

             E = (6.626 × 10-34 Js) × (3 × 108 m/s) / [(1 + ∆λ/λ) (3 × 108 m/s)] -                         (6.626 × 10-34 Js) × (3 × 108 m/s) / (3 × 108 m/s)

              E  = 2.656 × 10-14 J.

Therefore, the energy of the recoiling electron (in J) is 2.656 × 10-14 J.

Question 2. Determine the change in the photon's wavelength that occurs when an electron scatters an x-ray photon at 37∘ (in m).In Compton scattering, the wavelength of the incident photon increases as a result of its scattering.

This increase in wavelength is referred to as the Compton shift, which can be calculated using the following formula:

λ' - λ = (h/m.c) (1 - cosθ)

Here, λ' - the scattered photon's wavelength

λ - the incident photon's wavelength

h - Planck's constant

m - the mass of the electron

c - speed of light in vacuo

θ - the angle between the incident photon's direction and the direction in which the scattered photon was detected. As a result, using the equation given above we can determine the change in wavelength that occurs when an electron scatters an X-ray photon at 37∘.

λ' - λ = (h/m c) (1 - cosθ)

        = (6.626 × 10-34 Js / (9.11 × 10-31 kg) (3 × 108 m/s)) (1 - cos 37°) = 1.94 × 10-13 m.

Therefore, the change in the photon's wavelength that occurs when an electron scatters an X-ray photon at 37∘ is 1.94 × 10-13 m.

To learn more about Compton scattering equation :

https://brainly.com/question/12765258

#SPJ11

Answer:

B

Explanation:  HELP ME PLEASE, WRITE A ONE PAGE ESSAY TO EXPLAIN THE AUTHOR'S PURPOSE IN WRITING HOM SMART ARE ANIMAL

The statements that are true are:

Explanation:

The given statements are related to the graph representing the height of a rock thrown from a ledge over time. Looking at the options, the first statement correctly states that the rock reaches a maximum height of 43 m, as indicated by the graph.

The second statement is also true, as the graph shows a downward slope for a duration of 2 seconds, indicating that the height of the rock is decreasing during that time period.

The remaining statements in the options do not accurately describe the information given in the question or are not supported by the graph.

Learn more about height here:

https://brainly.com/question/29131380?referrer=searchResults

#SPJ11

Therefore, this reaction's internal energy change is -2850 J. This indicates a loss of 2850 J in the system's internal energy.

The definition defined energy as that of the "power to accomplish work" refers to the capacity to apply a force that moves an object. Kinetic energy and potential energy are the two categories of energy. The quantitative characteristic that is transferred to the a body or into a physical process in physics is energy, which is visible in the performance of labor as well as in form of heat and light. Energy is a resource that is conserved; it can only be changed through one form to another and it cannot be produced or destroyed, according to the law of conservation of energy.

According to the formula E = mc2, a body's mass (m) will vary by an amount equal to E/c2 if its energy increases by an amount E (in any form). This equation was developed by Albert Einstein.

Thomas Young coined the term "energy" for the first time in the realm of physics in 1800, but it didn't catch on. Later, Young utilized interference tests to demonstrate that light is indeed a wave.

The equation: can be used to determine the internal energy change for a reaction.

ΔU = Q - W

where U represents the change in internal energy, Q represents heat added to or released from the system, and W represents work performed by or on the system.

Since it is being released into the environment, the heat contributed to the system in this instance is -2290 J, and the work performed by the system is 560 J. Consequently, the internal energy change can be determined as follows:

ΔU = Q - W

ΔU = -2290 J - 560 J

ΔU = -2850 J

To know more about Energy visit:

https://brainly.com/question/2409175

#SPJ4

The notch sensitivity and fatigue stress concentration factors for the bar are calculated to determine the mean and alternating stresses and find the fatigue strength for different cycles.

To calculate the notch sensitivity and fatigue stress concentration factors, we need to consider the presence of the 10 mm hole in the center of the 30 mm side of the bar. The notch sensitivity factor quantifies the effect of the hole on the stress concentration, while the fatigue stress concentration factor determines the increase in stress due to cyclic loading.

The mean stress (σm) is the average of the minimum (F_min) and maximum (F_max) axial loads applied to the bar. The alternating stress (σa) is half the difference between F_max and F_min.

The fatigue strength for a certain number of cycles is determined by applying the appropriate factors to the ultimate tensile strength (S_Ut) or yield strength (S_y) of the material. The fatigue strength is typically given for a specified number of cycles, such as 100, 10,000, 100,000, or 1,000,000 cycles. The fatigue strength for infinite life refers to the stress level below which the material can withstand an unlimited number of cycles without failure.

To provide accurate values for the notch sensitivity, fatigue stress concentration factors, mean and alternating stresses, and fatigue strength for the specified number of cycles, further calculations and data specific to the material properties and geometry of the bar are required.

Learn more about fatigue analysis

brainly.com/question/32503112

#SPJ11

Answer:

the answers are "mass" and "distance"

Explanation:

hope this helps, plz mark brainiest :)

Answer:

The value moment of inertia the disk:

I = 6.4 kg·m²

Explanation:

Given:

Tk = 70 J

L = 30 kg·m² / s

_____________

I - ?

Rotational kinetic energy:

Tk = I·ω²/2

Angular velocity:

ω = √ (2·T / I)

Angular moment of a rotating body

L = I·ω = I·√ (2·T / I) = √ (2·T·I² / I ) = √ (2·T·I )

Raising to the second degree:

L² = 2·T·I

The value moment of inertia the disk:

I = L² / (2·T)

I = 30² / (2·70) ≈ 6.4 kg·m²

А) 6.4 кг·м²

Answer:

a

 \(v_f = 0.916 v_{ex}\)

b

 \(v_f = 1.05 v_{ex}\)

Explanation:

Considering question a

From the question we are told that

   The mass of the rocket is  \(m_o\)  

    The mass of the fuel which is in the rocket is  m = 0.6 M  

Generally given that the rocket burns all it fuel in a single stage , the final velocity of the rocket is mathematically represented as

          \(v_f = v_{ex} ln [\frac{m_o}{m_k} ]\)

Here \(m_k\) is the mass  of the rocket without fuel which is mathematically evaluated as

        \(m_k = m_o- m\)

=>      \(m_k = m_o -0.6m_o\)

=>    \(m_k = [1- 0.6] m_o\)

=>      \(v_f = v_{ex} ln [\frac{m_o}{[1 - 0.6]m_o} ]\)    

=>      \(v_f = 0.916 v_{ex}\)

Considering question b

From the question we are told that

   The mass of the fuel it burn at the first stage is  \(m = 0.3 m_o\)

     The mass of the first stage fuel tank \(m_1 = 0.1 m_o\)

    The mass of the fuel at the second stage is  \(m_f = 0.3m_o\)

Generally the  velocity of the rocket at the first stage  is mathematically represented as

           \(v_i = v_{ex} * ln [ \frac{m_o }{[1- m]m_o } ]\)

=>         \(v_i = v_{ex} * ln [ \frac{m_o }{[1- 0.3]m_o } ]\)

=>         \(v_i = v_{ex} * ln [ \frac{1 }{0.7 } ]\)  

=>         \(v_i =0.357 v_{ex}\)

Generally the mass of the rocket after first stage is  

    \(m_r = m_o - 0.3m_o -0.1m_o\)

=>   \(m_r = 0.6m_o\)

Generally the final  velocity of the rocket at the second stage is  

     \(v_f = v_i + v_{ex} * ln [\frac{m_r}{ m_f } ]\)

=>   \(v_f = v_i + v_{ex} * ln [\frac{0.6 m_o }{0.3mo } ]\)

=>   \(v_f = 0.357 v_{ex} + 0.693 v_{ex}\)

=>   \(v_f = 1.05 v_{ex}\)

The power output the 52 kg student output by climbing a 3 m high staircase in 5.9 seconds is found as  260 W.

The energy that an object has or can acquire owing to a change within the position when it is in a gravitational field is known as gravitational potential energy.

Mass of the student m =  52 kg .

Height climbed h = 3 m

Time taken t = 5.9 seconds.

Power = GPE / time

Power = m*g*h / t

Power = 52 * 9.81 * 3 / 5.9

Power = 259.38

Power = 260 W

Thus, the power output the 52 kg student output by climbing a 3 m high staircase in 5.9 seconds is found as  260 W.

To know more about the gravitational potential energy, here

https://brainly.com/question/3120930

#SPJ1

Answer:

234 oz = 0.0066339 t.

Explanation:

Boom Logic...

If the proper voltage is supplied ,the possible causes could be a defective heater or an open limit switch. The correct options are C) the heater is defective or D) the limit switch is open.

When an electric heating element does not get hot despite the proper voltage being supplied, there are a few potential reasons for this issue. Firstly, the heater itself may be defective.

There could be a problem with the heating element, such as a broken or burnt-out filament, a faulty connection, or internal damage. If the heater is defective, it will not generate heat even when the correct voltage is applied.

Alternatively, the limit switch may be open. A limit switch is a safety device designed to shut off power to the heating element if certain conditions, such as excessive temperature or pressure, are detected. If the limit switch is open, it disrupts the circuit and prevents the heating element from receiving power, resulting in no heat production.

It is important to note that the circuit breaker being reset or the fusible link melting would not directly cause the heating element to not get hot. The circuit breaker is a protective device that trips to interrupt the flow of electricity when there is an overload or a short circuit.

Resetting the circuit breaker may be necessary if it has tripped, but it is not the primary cause of the heating element not heating. Similarly, a fusible link melting is typically associated with protecting the circuit from excessive current flow, but it does not directly impact the heating element's functionality.

In summary, if the proper voltage is supplied to an electric heating element and it does not get hot, the likely causes are a defective heater or an open limit switch.

The heater may have internal issues preventing it from generating heat, while the limit switch being open interrupts the power supply to the heating element. Therefore, the correct options are C) the heater is defective or D) the limit switch is open.

Learn more about voltage here; brainly.com/question/1176850

#SPJ11

"Yes, the electronic crime scene is handled completely differently from a traditional crime scene. The electronic crime scene refers to a crime that has taken place in the digital world.

In contrast, a traditional crime scene refers to a crime that has taken place in the physical world, and it is evident that the two scenarios are handled differently.

An electronic crime scene refers to the area or place where electronic evidence is gathered for use in investigations or legal proceedings. Electronic evidence refers to information or data stored, created, or transmitted in electronic devices, including computers, smartphones, flash drives, and other digital devices. The collection of electronic evidence differs significantly from the collection of traditional evidence. The first step is the preservation of electronic evidence. In a traditional crime scene, it is possible to cordon off the area using yellow tapes, close windows, and take photographs of the scene. However, this is not the case with an electronic crime scene since electronic evidence is intangible. This is why digital forensic investigators begin the evidence preservation process by creating a forensic image of the electronic device under investigation. This is done to prevent data loss or alteration before investigations commence.

To learn more about electronic crime

https://brainly.com/question/10224131

#SPJ11

A radio wave travels at the speed of light, which is equal to approximately 300,000 km/s.

So, to travel a distance of 998.25 km, the time needed is:

Therefore the time required is approximately 3327.5 microseconds.

The force of friction of the cart of mass 16.4 kg is 159.18 N.

Friction is the force that opposes the motion of two bodies in contact.

To calculate the force of friction acting on the cart, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the force of friction is 159.18 N.

Learn more about friction here: https://brainly.com/question/23161460

#SPJ1

Answer:

3.85 V

Explanation:

The potential difference between two points can be calculated using the following equation

Where E is the energy and Q is the charge. So, replacing E = 250 J and Q = 65 C, we get:

Therefore, the potential difference is 3.85 V

(a) If only 1% of the light is absorbed, what is the optical depth through the column? The optical depth is 10.

The optical depth is a measure of how much light is absorbed by a material. It is calculated by dividing the number of photons absorbed by the number of photons that enter the material. In this case, only 1% of the photons are absorbed, so the optical depth is 10.

The optical depth is calculated using the following formula:

optical depth = -ln(transmission)

where transmission is the fraction of light that is transmitted through the material. In this case, the transmission is 0.99, so the optical depth is:

optical depth = -ln(0.99) = 10

(b) If 50% of the light is absorbed, what is the optical depth through the column? The optical depth is 1.

The optical depth is a measure of how much light is absorbed by a material. It is calculated by dividing the number of photons absorbed by the number of photons that enter the material. In this case, 50% of the photons are absorbed, so the optical depth is 1.

The optical depth is calculated using the following formula:

optical depth = -ln(transmission)

where transmission is the fraction of light that is transmitted through the material. In this case, the transmission is 0.5, so the optical depth is:

optical depth = -ln(0.5) = 1

(c) If 99% of the light is absorbed, what is the optical depth through the column? The optical depth is 100.

The optical depth is a measure of how much light is absorbed by a material. It is calculated by dividing the number of photons absorbed by the number of photons that enter the material. In this case, 99% of the photons are absorbed, so the optical depth is 100.

The optical depth is calculated using the following formula:

optical depth = -ln(transmission)

where transmission is the fraction of light that is transmitted through the material. In this case, the transmission is 0.01, so the optical depth is:

optical depth = -ln(0.01) = 100

To learn more about optical depth click here: brainly.com/question/31833779

#SPJ11

The change in enthalpy is  0 J/kg if the incompressible substance with a density of 1000 kg/m3 is isothermally compressed from 100 to 1000 kpa. Thus, option b is correct.

The given data is as follows:

The density of substance = 1000 kg/m3

In-compression pressure = 100 to 1000 kph

The given substance is incompressible. So its specific volume stays constant during the process. The work done is Zero.

Assuming that the process is Isothermal, the temperature remains steady.

The change in enthalpy is calculated by using the formula:

ΔH = m × C × ΔT

The density of mass is calculated by using the formula,

m = V × ρ = 1 m3 × 1000 kg/m3

m = 1000 kg

Change in enthalpy is calculated as:

ΔH = m × C × ΔT

ΔH = 1000 kg × 0 J/(kg·K) × 0 K

ΔH = 0 J/kg

Therefore we can conclude that the change in enthalpy is  0 J/kg.

To learn more about enthalpy

https://brainly.com/question/24170335

#SPJ4

The complete question is-

an incompressible substance with a density of 1000 kg/m3 is isothermally compressed from 100 to 1000 kph. determine the change in enthalpy. multiple choice questions.

a.900 kj/kg

b. 0 kj/kg

c.10 kj/kg

d.0.9 kj/kg

To determine the exact height of the man's image on the CCD detector, you would need to know the specific details of the imaging system and the distances involved.

Height is the measurement of vertical distance or elevation relative to a reference level, such as sea level. A person's height is measure from the bottom of their feet to the top of their head. Height is an important indicator of health and overall physical development in individuals. Height is also an important factor in determining physical attractiveness and social standing.

We need to take into account the optical characteristics of the imaging equipment and the positioning of the guy in relation to the detector to estimate how high the well-focused image of the man is on the CCD detector.

The focal length of the lens being used, the separation between the subject and the lens, and the size of the CCD detector are just a few of the variables that will affect how tall the subject appears on the CCD detector.

Generally speaking, the magnification formula can be used to determine the height of the image:

(Image Distance / Object Distance) * (Object Height) = Image Height

Where:

The man's actual height is indicated by the term "object height."

The distance between the lens and the CCD detector is known as the image distance.

The distance between the subject and the lens is known as object distance.

However, a numerical solution cannot be given in the absence of precise values for these variables. You would need to be aware of the precise specifications of the imaging system and the distances involved to calculate the precise height of the man's picture on the CCD detector.

To determine the exact height of the man's image on the CCD detector, you would need to know the specific details of the imaging system and the distances involved.

complete question:

How high is the man's well-focused image on the CCD detector?

To learn more about height

https://brainly.com/question/30620889

#SPJ4

Complete Question:
In (Figure 1) the camera lens has a 54 mm focal length.
How high is the man's well-focused image on the CCD detector?
Express your answer to two significant figures and include the appropriate units.

The height of each bob rebound is 0.66m.

Height is the measurement of someone or something.

The velocity with which the 75g bob collides with the 95g bob is u = sqrt(2gl) = 4.12m/s Now th given collsion is headon and elastic therefore the  energy and linear momentum of both will be conserves and from the law of conservationists of linear momentum and laws of conservationists of energy we get for lighter (75g) bob

v1 = (m_1 -m_2 \over m_1 +m_2 )u_1 +( 2m_2 \over m_1 +m_2 )u_2

= 0.075-0.095

\over 0.075+ 0.095 ×4.12 + 0

= -0.485 m/s ( -ve sign shows that the bob will move in opp. dir. to its initial dir.)

and v2 = (m_2 -m_1 \over m_1 +m_2 )u_2 +( 2m_1 \over m_1 +m_2 )u_1 = 0 + 2×0.075 \over 0.075+ 0.095 × 4.12 = 3.63 m/s

as at max hieght both the bob will come to rest for a moment then applying v2 - u2 = 2as we get for bob of 95g 0 - 13.21 = -2×10h or h = 13.21/20 = 0.66m for bob height.

To know more about height click-

https://brainly.com/question/25700589

#SPJ4

All the light in an agn outburst is emitted: a. at the same frequency.

An active galactic nucleus (AGN) is a compact area at the core of a galaxy with much higher-than-normal brightness throughout at least some section of the electromagnetic spectrum and features indicating that the luminosity is not created by stars. The non-stellar radiation emitted by an AGN is thought to be the product of matter accretion by a supermassive black hole at the heart of its host galaxy.

Active galactic nuclei are the most brilliant and enduring sources of electromagnetic radiation in the cosmos, and as such, they may be utilised to find faraway objects.

learn more about   agn outburst refer

https://brainly.com/question/14521181

#SPJ4