The Kinematics of Spring Motion is 73730 N
Kinematics of Spring Motion:
An elastic spring abides by Hooke's law, which states that the force needed to stretch or compress a spring is inversely proportional to the length of the spring in question. Simple harmonic motion is performed by a mass that is connected to a spring.
According to Hooke's law, compression in spring is related to applied force as following.
F applied = -kx
Where,
k = force constant
x = compression in spring
Step 1)First, we will determine force constant of spring
k = 730/ (0.40*10-3)
k = 1825000 N/m
Step 2)We will determine compression in bathroom scale when man jumps on the scale.
m g (H+x) = 0.5 k x2
730 * (2.0 + x) = 0.5 * 1825000 * x2
0.0008 * (2.0 + x) = x2
x2 - 0.0008 x - 0.0016 = 0
x = 0.04040 m, -0.03(rejected since negative)
Hence,
F = k x = 1825000 * 0.04040 = 73730 N
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A 55 kg skater spins with a speed of 7.2 m/s with her arms outstretched making a
radius of 0.6 m. Calculate the angular momentum of the skater. *
33 kg m^2/s
0 237.6 kg m^2/s
396 kg m^2/s
660 kg m^2/s
e xddd snoAnswer:n
E
xplanation:s no
What action should you take if you are in debt
Answer:
1. save enough money to pay larger debts
Explanation:
A 81 kg man weighs himself at the north pole and at the equator. Which scale reading is higher? By how much?
Answer:
The scale reading at the pole is higher. The difference is 8.019 N.
Explanation:
The centrifugal force of the equator is the same as the centrifugal force of the Earth itself. On the other hand, the centrifugal force on the poles are zero, since they are not spinning in the way the equator is. The centrifugal force on a body at the equator is 0.034 m/s^2 times the mass of the body. The centrifugal force at the poles is zero. Therefore, the total weight of the man at sea level at the equator (gravity minus centrifugal force) is 9.764 m/s^2 times his mass, whereas his weight is 9.863 m/s^2 times his mass at the poles. Using simple multiplication, I figured out his weight at the north pole is 798.903 N, and his weight at the equator is 790.884 N. The difference of these two numbers is 8.019 N.
Hope this helps!
Source: https://www.wtamu.edu/~cbaird/sq/2014/01/07/do-i-weigh-less-on-the-equator-than-at-the-north-pole/
The location where the weight of a person will be more is required.
The scale at the pole has a higher reading.
The difference in weight is 4.212 N.
m = Mass of man = 81 kg
The acceleration due to gravity on the poles is \(g_p=9.832\ \text{m/s}^2\)
The acceleration due to gravity on the equator is \(g_e=9.78\ \text{m/s}^2\)
Gravitational acceleration is given by
\(g=\dfrac{GM}{R^2}\)
where,
M = Mass of Earth
G = Gravitational constant
R = Radius
The Earth in not a perfect sphere it is wider at the equator than at the poles.
As \(R\) increases, the value of \(g\) decreases.
Weight of the person at the north pole
\(w_p=mg_p\\\Rightarrow w_p=81\times 9.832=796.392\ \text{N}\)
Weight of the person at the Equator
\(w_e=mg_e\\\Rightarrow w_e=81\times 9.78=792.18\ \text{N}\)
The difference in the weight is \(796.392-792.18=4.212\ \text{N}\)
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ππππππππππwhy does the author think emojis are good? but u have to use the R.A.C.E
In a hydraulic system, a force of 400 N is exerted on a piston with an area of 0.001 m2. The load-bearing piston in the system has an area of 0.2 m^2.
Required:
a. Calculate in kPa the pressure in the hydraulic fluid induced by the applied pressure.
b. What is the magnitude of the force exerted on the load bearing piston by the hydraulic fluid?
Answer:
Explanation:
Pressure on the hydraulic system is expressed as;
Pressure = Force/Area
Given
Force on the fluid = 400N
Area = 0.001m²
Pressure in the fluid = 400/0.001
Pressure in the fluid = 400,000N/m²
1N/m² = 0.001kPa
400,000N/m² = x
x = 400,000 × 0.001
x = 400kPa
Hence the pressure in kPa is 400kPa
b) Using the formula;
Pa = Pb
Fa/Aa = Fb/Ab
Pa = Fb/Ab
Fb = PaAb
Fb = 400,000(0.2)
Fb = 80,000N
Hence the magnitude of the force exerted on the load bearing piston by the hydraulic fluid is 80,000N
A crate with a mass of 35.0 kg is pushed with a horizontal force of 150 N. The crate moves at a constant speed across a level, rough surface a distance of 5.85 m
(a) The work done by the 150 N force is 877.5 Joules.
(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.
To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.
(a) The applied force's work may be estimated using the following formula:
Work = Force * Distance * cos(theta)
where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.
As a result, the applied force's work is:
Work = 150 N * 5.85 m * cos(0) = 877.5 J
So, the work done by the 150 N force is 877.5 Joules.
(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.
The frictional work may be estimated using the following formula:
Work = Force of Friction * Distance * cos(theta)
The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.
Thus, the work done by friction is:
Work = 150 N * 5.85 m * cos(180) = -877.5 J
Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.
The coefficient of kinetic friction may be calculated using the following equation:
Friction Force = Kinetic Friction Coefficient * Normal Force
The normal force equals the crate's weight, which may be computed as:
Normal Force = mass * gravity
where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.
Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N
Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:
Force of Friction = coefficient of kinetic friction * Normal Force
150 N = coefficient of kinetic friction * 343 N
coefficient of kinetic friction = 150 N / 343 N ≈ 0.437
As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.
In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.
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What is generally TRUE about diagnosing psychological disorders?
A.
High levels of neurotransmitters have been linked to depression.
B.
Diagnoses are not based on opinion or personal assessment.
C.
Doctors agree about what behaviors make up each disorder.
D.
Psychological disorders can be very difficult to diagnose.
The statement that says "Psychological disorders can be very difficult to diagnose" is true about diagnosing psychological disorders.
What are psychological disorders?Psychological disorders are those mental, behavioral, emotional and thinking conditions that interfere with the normal performance of the individual in society.
Mental disorders are psychiatric conditions that are expressed in a syndrome, verifiable from different diagnostic criteria.The steps to obtain a diagnosis include a medical history, physical examination, and possibly laboratory tests and a psychological evaluation.Therefore, we can conclude that a psychological disorder is an alteration in the mental balance of a person that requires specialized attention adapted to the characteristics of the dysfunction.
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26. Which member of the carbon family is a non-metal?
Please help
Explanation:
Check out the Periodic Table attached here. The Carbon family is the vertical group starting with Carbon, Group 14. Nonmetals are in green, which element there is a nonmetal?
Two 51 g blocks are held 30 cm above a table. As shown in the figure, one of them is just touching a 30-long spring. The blocks are released at the same time. The block on the left hits the table at exactly the same instant as the block on the right first comes to an instantaneous rest. What is the spring constant?
The concept of this question can be well understood by listing out the parameters given.
The mass of the block = 51 g = 51 × 10⁻³ kgThe distance of the block from the table = 30 cmLength of the spring = 30 cmThe purpose is to determine the spring constant.
Let us assume that the two blocks are Block A and Block B.
At point A on block A, the initial velocity on the block is zero
i.e. u = 0
We want to determine the time it requires for Block A to reach the table. The can be achieved by using the second equation of motion which can be expressed by using the formula.
\(\mathsf{S = ut + \dfrac{1}{2}gt^2}\)
From the above formula,
The distance (S) = 30 cm; we need to convert the unit to meter (m).
Since 1 cm = 0.01 mThen, 30cm = 0.3 mThe acceleration (g) due to gravity = 9.8 m/s²
∴
inputting the values into the equation above, we have;
\(\mathsf{0.3 = (0)t + \dfrac{1}{2}*(9.80)*(t^2)}\)
\(\mathsf{0.3 = \dfrac{1}{2}*(9.80)*(t^2)}\)
\(\mathsf{0.3 =4.9*(t^2)}\)
By dividing both sides by 4.9, we have:
\(\mathsf{t^2 = \dfrac{0.3}{4.9}}\)
\(\mathsf{t^2 = 0.0612}\)
\(\mathsf{t = \sqrt{0.0612}}\)
\(\mathbf{t =0.247 \ seconds}\)
However, block B comes to an instantaneous rest on point C. This is achieved by the dropping of the block on the spring. During this process, the spring is compressed and it bounces back to oscillate in that manner. The required time needed to get to this point C is half the period, this will eventually lead to the bouncing back of the block with another half of the period, thereby completing a movement of one period.
By applying the equation of the time period of a simple harmonic motion.
\(\mathbf{T = 2 \pi \sqrt{\dfrac{m}{k}}}\)
where the relation between time (t) and period (T) is:
\(\mathsf{t = \dfrac{T}{2}}\)
T = 2t
T = 2(0.247)
T = 0.494 seconds
\(\mathbf{T = 2 \pi \sqrt{\dfrac{m}{k}}}\)
By making the spring constant (k) the subject of the formula:
\(\mathbf{\dfrac{T}{2 \pi } = \sqrt{ \dfrac{m}{k}}}\)
\(\Big(\dfrac{T}{2 \pi }\Big)^2 = { \dfrac{m}{k}\)
\(\dfrac{T^2}{(2 \pi)^2 }= { \dfrac{m}{k}\)
\(\mathsf{ T^2 *k = 2 \pi^2*m} \\ \\ \mathsf{ k = \dfrac{2 \pi^2*m}{T^2}}\)
\(\mathsf{ k =\Big( \dfrac{(2 \pi)^2*(51 \times 10^{-3})}{(0.494)^2} \Big) N/m}\)
\(\mathbf{ k =8.25 \ N/m}\)
Therefore, we can conclude that the spring constant between the two 51 g blocks held at a distance 30 cm above a table as a result of instantaneous rest caused by the compression of the spring is 8.25 N/m.
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12. A coconut falls out of a tree 12.0 m above the ground and hits a bystander 3.00 m tall on the top of the head. It bounces
back up 1.50 m before falling to the ground. If the mass of the coconut is 2.00 kg, calculate the potential energy of the
coconut relative to the ground at each of the following sites:
(a) while it is still in the tree,
(b) when it hits the bystandlar on the head,
(c) when it bounces up to its maximum height,
(d) when it lands on the ground,
(e) when it rolls into a groundhog hole, and falls 2.50 m to the bottom of the hole,
Explanation:
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This week we discuss injuries to the head, neck and spine. There are so many long term affects of so many different head injuries. One of the biggest changes to head injuries that we have seen in the last decade is the implementation of concussion protocol. No matter the age or activity, the medical world has a recommended protocol for possible concussions and any head injury.
This weeks assignment. Research concussion protocol and submit the following in a written paper format.
-What is a concussion?
-Why do we need to have a concussion protocol?
-Who needs a concussion protocol? This is in regards to caring for injuries, not the injured person itself,
-Is there a standard concussion protocol should you follow? What is it?
-At a minimum, concussion protocol steps should include the what people in the process?
-Have you or anyone you know had to follow concussion protocol for a head injury? Tell me about it.
This is due Sunday I want to get started on it please someone help me ?
Answer:
Concussion is the most common type of mild traumatic brain injury and can have serious consequences
Explanation:
Which of the following is most likely the caption for the illustration that was scratched out of the textbook?
A. An electrically-charged object can attract an uncharged object with magnetic properties.
B. An electrically-charged object is stronger than a magnet.
C. A dry cell battery has magnetic properties.
D. An electric circuit can only have one dry cell battery.
IMAGE DOWN BELOW OR UP
The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.
A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.
The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.
So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.
Therefore, The correct answer is option C.
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What is the average speed of a car that travels 100 m over 10 s?
Answer: 10m per second.
Explanation: 100/10 is 10/1, so it would be 10m per second.
A ball is thrown horizontally at 30 m/s from a height of 45m. How long is it in the air?
(i) How fast is it moving horizontally when it hits the ground?
Answer:
1.25s
1) 90.9m
Explanation:
From the question, we are given the following;
Speed v = 30m/s
Maximum height H = 45m
Required;
Time
Using the equation of motion S = ut + 1/2gt²
Substitute;
45= 30t + 1/2(9.8)t²
45 = 30t + 4.9t²
4.9t² + 30t - 45 = 0
Factorize;
t = -30 ±√30²-4(-45)(4.9)/2(4.9)
t = -30 ±√900+882/9.8
t = -30 ±42.21/9.8
t = -30 + 42.21/9.8
t = 12.21/9.8
t = 1.25secs
Hence the ball spent 1.25secs in air.
i) To get the horizontal distance, we will use the formula;
R = U√2H/g
R = 30√2(45)/9.8
R = 30√90/9.8
R = 30√9.18
R = 30(3.03)
R = 90.9m
Hence the horizontal distance is 90.9m
a true statement of
kinetic theory
Answer:
real kinetic theory means that kinetic energy
. In a classic clip on America’s Funniest Home Videos, a sleeping cat rolls gently off the top of a warm TV set. Ignoring
air resistance, calculate (a) the position and (b) the velocity of the cat after 0.100 s, 0.200 s, and 0.300 s.
After 0.100 s, the cat would be 0.049 m below its initial position, with a velocity of 0.98 m/s. After 0.200 s, the cat would be 0.196 m below its initial position, with a velocity of 1.96 m/s. Finally, after 0.300 s, the cat would be 0.441 m below its initial position, with a velocity of approximately 2.94 m/s.
To calculate the position and velocity of the sleeping cat after certain time intervals, we need to make some assumptions and use basic principles of physics.
Assuming the cat falls vertically downward due to gravity and ignoring air resistance, we can apply kinematic equations to solve the problem.
(a) Position:
Using the equation for the position of an object in free fall, h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is time, we can determine the position of the cat.
After 0.100 s: h = (1/2)(9.8 m/s^2)(0.100 s)^2 = 0.049 m (approximately)
After 0.200 s: h = (1/2)(9.8 m/s^2)(0.200 s)^2 = 0.196 m (approximately)
After 0.300 s: h = (1/2)(9.8 m/s^2)(0.300 s)^2 = 0.441 m (approximately)
(b) Velocity:
The velocity of the cat can be calculated using the equation v = gt, where v is the velocity and t is time.
After 0.100 s: v = (9.8 m/s^2)(0.100 s) = 0.98 m/s (approximately)
After 0.200 s: v = (9.8 m/s^2)(0.200 s) = 1.96 m/s (approximately)
After 0.300 s: v = (9.8 m/s^2)(0.300 s) = 2.94 m/s (approximately)
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When there is no torque acting
on a
body, its angular momentum is constant.
True or false
Answer:
the correct answer is true.
Explanation:
hope the above photo is self explanatory.please not forget to rate and mark brainliest!!!Answer: True
Explanation:
The following graph shows the kinetic energy of a roller coaster car as it passes through a loop.
Roller Coaster Car's Kinetic Energy
O B.
Kinetic Energy (kilojoules)
OC.
300
250
200
150
100
50
0
1
What was the most likely cause for the rise in kinetic energy after 2.5 seconds?
A. The roller coaster was pulled with decreasing gravitational force.
The roller coaster began slowing down.
The roller coaster started gaining elevation.
O D. The roller coaster began speeding up.
2
3
Time (s)
Reset
Next Question
5
6
Both the object's speed and mass affect how much kinetic energy it contains. Motional energy is produced while the roller coaster descends. The roller coaster's bottom of the track position is where the most kinetic energy is produced. Kinetic energy changes to potential energy when it starts to rise.
Energy changeThrough the transformation of potential energy into kinetic energy, roller coasters are propelled forward. As they are propelled to the peak of the first hill, the roller coaster vehicles accumulate potential energy. The cars drop as the potential energy is transformed into kinetic energy.Kinetic energy is produced by converting potential energy. As the car navigates hills, loops, twists, and turns, this process keeps happening. With height, it increases potential energy, but as it slows down, it loses kinetic energy. Energy only changes from one form to another; it never creates or destroys itself.For more information on kinetic energy of roller coaster kindly visit to
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Hot water is added to three times its water at 10 degree Celsius and the resulting temperature at 20 degree Celsius. what is the initial temperature
What is the electric potential energy of the group of charges in the figure? (Figure 1)
that the relative placements of the charges as well as their multiples affect a set of ions' potential energy. When the specific charge have the same sign or have equal signs, the energy is positive. Or else, it is negative.
How is potential energy calculated?The force acting just on two objects affects the potential energy formula. The formula for gravitational force is P.E. (= mgh, where g seems to be the acceleration caused by gravity (9.8 m/s2 at the earth's surface) while h represents the elevation in metres.
What is a system with two charges' potential energy?As a result, the system's potential energy equals the sum of a work that was done to set up the entire system of two counts. The potential energy that exists in the combination of two charges in such an external field can be stated as follows: q1V(r1) = q2V(r2) + (q1q2/4or12).
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Jason takes off from rest across level water on his jet-powered skis. The combined mass of Jason and his skis is 75 kg (the mass of the fuel is negligible). The skis have a thrust of 200 N and a coefficient of kinetic friction on water of 0.10. Unfortunately, the skis run out of fuel after only 48 s. What is Jason's top speed
Answer:
81.1 m/s
Explanation:
The net force of Jason is T - f = ma where T = thrust = 200 N f = frictional force = μN = μmg where μ = coefficient of kinetic friction of water = 0.10, m = mass of Jason plus skis = 75 kg, g = acceleration due to gravity = 9.8 m/s² and a = Jason's acceleration
So, T - f = ma
T - μmg = ma
a = T/m - μg
susbstμituting the values of the varμiables into the equation, we have
a = 200 N/75 kg - 0.1 × 9.8 m/s²
a = 200 N/75 kg - 0.1 × 9.8 m/s²
a = 2.67 m/s² - 0.98 m/s²
a = 1.69 m/s²
Using v = u + at, we find Jason's velocity v where u = initial velocity = 0 m/s (since he starts from rest), a = 1.69 m/s² and t = time = 48 s
So, v = u + at
v = 0 m/s + 1.69 m/s² × 48 s
v = 0 m/s + 81.12 m/s
v = 81.12 m/s
v ≅ 81.1 m/s
So, Jason's top speed is 81.1 m/s
Some students are trying to determine whether the radius of a metal sphere affects the amount of charge that it can hold. The students have metal spheres of different radii and known masses that can be attached to a stand by a string, as shown above. The stand is midway between a set of large plates that are connected to a battery to create a nearly uniform electric field in the region between them and near their centers. The students rub a rod with cloth and touch it to each sphere to charge the sphere, and they observe the deflection of the sphere as it is attracted to one plate. They keep adding charge to each sphere until they cannot observe any change in deflection. Which of the following data will give them information that is useful for quantitatively comparing the amount of charge on each sphere?
The number of times they rub the cloth back and forth on the rod
The number of times they touch the rod to the sphere
The string's angle of deflection
The string's angle of deflection is useful for quantitatively comparing the amount of charge on each sphere.
The angles of trajectory that all of your strings take across and behind the nut and saddles of your instrument are, in a nutshell, what is meant by this term. The string's angle, which are located above the headstock, are the downward angles your strings make when they travel through the nut slot, emerge over the fingerboard, and exit the rear edge of the nut to the string wraps on the machine head posts. It is the angle that the string makes at the bridge between your saddle and the spot where the ball end of your string is located.
The string's ability to transfer downward stresses into the guitar is governed by break angles.
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Mass, volume and density are all properties of
Answer:
Properties of matter
Explanation:
All properties of matter are either extensive or intensive and either physical or chemical. Extensive properties, such as mass and volume, depend on the amount of matter that is being measured. Intensive properties, such as density and color, do not depend on the amount of matter.
Answer:
The pythagoream theorem
Explanation:
Find a unit vector in the direction of the resultant of vectors A = 21-3) + k, B = i +} + 2k and C = 3î - 2ĵ + 4k
The unit vector in the direction of the resultant of vectors A, B, and C is: (6i - j + 3k) / √46
To find a unit vector in the direction of the resultant of vectors A, B, and C, we need to calculate the sum of these vectors and then normalize the resulting vector.
Given:
Vector A = (2i + 1j - 3k)
Vector B = (i + j + 2k)
Vector C = (3i - 2j + 4k)
To find the resultant vector R, we add these vectors together:
R = A + B + C
= (2i + 1j - 3k) + (i + j + 2k) + (3i - 2j + 4k)
= (2i + i + 3i) + (1j + j - 2j) + (-3k + 2k + 4k)
= 6i - j + 3k
Now, to obtain a unit vector in the direction of R, we divide R by its magnitude:
Magnitude of R = √(6² + (-1)² + 3²)
= √(36 + 1 + 9)
= √46
Unit vector in the direction of R = R / Magnitude of R
= (6i - j + 3k) / √46
Therefore, the unit vector in the direction of the resultant of vectors A, B, and C is:
(6i - j + 3k) / √46
It's important to note that the unit vector represents the direction of the resultant vector, while its magnitude is always 1. By normalizing the resultant vector, we obtain a unit vector that points in the same direction but has a magnitude of 1, providing information solely about the direction of the resultant.
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What is the velocity of a car that travels from mile marker 32 on I-10 to mile marker 312 on I-10 in a time of 2 hours and 45 minutes? SYW!
Answer:
101.81818 MPH
Explanation:
Which of the following statements regarding work and retirement is true?
The statement regarding work and retirement that is true is that most older Americans say they would prefer to enter retirement gradually.
What is retirement?Retirement is defined as the time in an individuals life that such leaves the Labour market or the workforce.
In some countries such as the United States of America, most elderly citizen prefer taking retirement process slowly.
Therefore, the statement regarding work and retirement is that retirement is a gradual process which one starts to process while actively in service
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asap hurry
Part 1
1. Using a graduated cylinder, measure 70 mLof water. Pour this water into a small, empty glass
jar. Dry the graduated cylinder.
2. Remember the old saying: “Do like you ‘oughter’—add the acid to the water.” This means to
add acid to water—never the other way around. Do not add water toacid.
3. Make sure you are working in a well-ventilated area, such as next to an open window. Using
extreme caution, and wearing safety goggles or protective eyeware, protective gloves, and
long sleeves and long pants, measure out 30 mL of the muriatic acid into the graduated
cylinder. Slowly pour this acid into the jar of water. (Add the acid carefully, because heat will be
produced when the two substances mix.)
4. Screw the lid onto the jar and gently swirl the jar to mix the contents fully.
5. Remove the lid and place the galvanized nail into the jar.
6. Loosely cover the jar with the lid (do not screw it on).
7. Allow the reaction in the jar to continue for 20 seconds, recording observations during this
time.
8. Light the wooden splint (toothpick) with the candle and prepare to test for the gas.
Testing and Producing Gases
9. Very carefully, remove the lid from the jar and bring the burning splint to the mouth of the jar.
10. Be prepared for a reaction. Record your observations.
11. Place the lid back on the jar and allow more gas to accumulate.
12. Complete Steps 7, 8, and 9 again to repeat this trial. After your second trial, rinse and dry the
graduated cylinder to prepare for Part 2.
Part 2
13. Measure 50 mL of hydrogen peroxide using the graduated cylinder. Pour thehydrogen
peroxide into the second jar.
14. Add approximately 1 teaspoon of yeast to the hydrogen peroxide. Loosely cover the jar with
the lid (do not screw it on). Record your observations.
15. Light the wooden splint (toothpick) with the candle and allow the toothpick to burn for a few
seconds.
16. Extinguish the flame by blowing on it so that the wood is just glowing.
17. Remove the lid on the jar and hold the glowing splint to the mouth of the jar. Record your
observations.
18. Place the lid back on the jar and allow more gas to accumulate.
19. Repeat Steps 14 and 15 to complete a second trial
2 of 5
Science | Testing and Producing Gases
Name Date
• Dispose of nail by taking it out of the acid solution (with gloves on), wrapping it in a paper
towel, and putting it into the trash.
• Dispose of liquid substances by pouring them down a drain. Run plenty of cold water while you
pour these substances down the drain and for several minutes afterward.
• Do not breathe in fumes. Make sure the area you are working in is wellventilated.
• Be sure toothpicks are completely extinguished in water before disposing of them.
Data and Observations
Observations for Part 1
Trial 1:
Trial 2:
Observations for Part 2
Trial 1:
Trial 2:
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Science | Testing and Producing Gases
1. Do you think a chemical reaction took place in Part 1 when you added the galvanized nail to
the acid and water, and in Part 2 when the yeast was added to the hydrogen peroxide? Explain
your answer. (3 points)
2. Did the same result occur in both parts when you held up a lighted splint to the jar’s mouth?
What can you conclude from this about the identity of the gas(es) in Parts 1 and 2? (3
points)
3. In both parts of the activity, you conducted a second trial without having to remix the
chemicals. How was this possible? (3 points)
4. In 1937, a large passenger airship called the Hindenburg mysteriously caught fire. Because
the airship was filled with hydrogen gas, it immediately exploded once the fire reached the gas.
Given this information, do you think one of the reactions above may have produced hydrogen?
Use your data to explain your answer. (3 points)
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Science | Testing and Producing Gases
Answer:
Yes, a chemical reaction took place in Part 1 when the galvanized nail was added to the acid and water, and in Part 2 when the yeast was added to the hydrogen peroxide. This is evidenced by the observations recorded in the trials, such as the production of bubbles and the release of gas.Yes, the same result occurred in both parts when a lighted splint was held up to the jar's mouth. This indicates that the gas produced in both parts was flammable and therefore likely to be hydrogen.In both parts of the activity, a second trial was conducted without having to remix the chemicals because the reactions continued to produce gas even after the first trial, allowing for further testing.Yes, one of the reactions above may have produced hydrogen. Part 2 specifically involved the addition of yeast to hydrogen peroxide, which likely produced oxygen gas and water as byproducts. This means that the gas produced in Part 2 was likely hydrogen gas, as hydrogen peroxide is composed of hydrogen and oxygen. The flammability of the gas produced in both parts also supports the possibility that it was hydrogen.Explanation:
Sorry if I made some mistakes, I completed it as fast as I could.
A car accelerates from rest to a speed of 20 m/s in 6 seconds, what is the acceleration?
Answer:
3 seconds
Explanation:
A woman is taking a walk, moving at a rate of 80 m/min. What additional information would you need to determine her velocity?
Direction of the woman is additional information would you need to determine her velocity.
What is velocity?
When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.
Direction of the woman is additional information would you need to determine her velocity.
To learn more about velocity refer to the link;
brainly.com/question/18084516
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Iu Metallic bonding is similar to iconic bonding because
Answer:
In an ionic bond the valence electrons are transferred from the metal
Explanation: