The coefficient and symbol for iodine be I₂.
What is the coefficient in a chemical equation?Coefficients are the numbers used to balance chemical equations and are placed in front of a chemical symbol or formula. It tells us about how many atoms or molecules of substance or compound are involved in the reaction.As in mathematics, coefficient is the number used in front of a variable similarly in chemistry, coefficient is a number used in chemical equation, just as a prefix of chemical formula to define the number of molecules reacting and producing in a reaction. We add coefficients to balance the chemical equations so as to assure that law of conservation of mass is being followed.bromine + potassium iodide → potassium bromide + iodine
The balanced chemical equations:
Br₂ + 2KI → 2KBr + I₂
2KBr means 2 molecules of potassium iodide.
From the above balanced equation, we know that the coefficient of bromine = 2, iodine = 2, potassium iodide = 2and potassium bromide = 2.
Hence, option D is the correct answer.
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If all candles are the same size, which would burn longer?
O a candle with a 750ml beaker as a cover
O a candle with a 250ml beaker as a cover
They would burn the same amount of time
O a candle with a 150mL beaker as a cover
The candle with a 750 mL beaker as the cover would burn longer than the rest.
The burning of the candle requires oxygen and the volume of oxygen each beaker can hold depends on the volume of the beakers.
Thus, a beaker of 750 mL capacity will hold more oxygen than beakers of 250 mL or 150 mL capacity.
Since the higher volume beaker has the capacity to hold more oxygen than the rest, it means that the candle will be able to burn longer in it than the rest.
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Hola alguien me puede ayuda esto no se como
What other organisms feed on the same material?
Answer:
A heterotroph is an organism that eats other plants or animals for energy and nutrients. The term stems from the Greek words hetero for “other” and trophe for “nourishment.”
CH4 +2O2 ➡️CO2 +2h2OHow many grams of water can be formed from 88 grams of Methane?
Answer:
198 g of water (H2O).
Explanation:
What is given?
Mass of methane (CH4) = 88 g,
Molar mass of CH4 = 16 g/mol,
Molar mass of water (H2O) = 18 g/mol.
Step-by-step solution:
First, let's convert 88 g of CH4 to moles using its molar mass:
\(88\text{ g CH}_4\cdot\frac{1\text{ mol CH}_4}{16\text{ g CH}_4}=5.5\text{ moles CH}_4.\)In the chemical equation you can see that 1 mol of CH4 reacted produces 2 moles of H2O, so let's see how many moles of H2O can be formed by 5.5 moles of CH4, as follows:
\(5.5\text{ moles CH}_4\cdot\frac{2\text{ moles H}_2O}{1\text{ mol CH}_4}=11\text{ moles H}_2O.\)The final step is to convert 11 moles of H2O to grams using the molar mass of H2O, like this:
\(11\text{ moles H}_2O\cdot\frac{18\text{ g H}_2O}{1\text{ mol H}_2O}=198\text{ g H}_2O.\)The answer would be that we can produce 198 g of water (H2O) by 88 g of methane (CH4).
Tapeworm and Roundworn
Answer:
Tapeworms and roundworms both belong to the same phylum however, their families are different from one another.
Tapeworms are flat, segmented intestinal parasites of the cat and dog and humans sometimes. They are present in the intestines of pets and depend on them, therefore, are parasites. These parasites look like tape which gives it its name.
Roundworms can also infect humans and the most common cases are among children. When not treated immediately, they can cause severe damage to a human host and can even cause blindness. Tapeworms are white in color with a long, segmented body.
Whose atomic theory explains how atoms emit (release) and absorb light?
O Bohr's
O Dalton's
O Rutherford's
O Thomson's
Answer:
Bohr's model of hydrogen atom
I hope this answer is correct
Answer:
Bohr's
Explanation:
Which of the following options correctly balances the equation below? __HNO2 + __O2 --> __HNO3
Answer:
2HNO2 + O2 ------> 2HNO3
Explanation:
sodium+ ________acid= sodium cholride + ___________
magnesium _________+ sulfric acid = magnesium sulfate + water + carbon dioxide
The complete forms of the chemical reactions are as follows:
sodium + hydrochloric acid = sodium chloride + hydrogenmagnesium carbonate + sulfric acid = magnesium sulfate + water + carbon dioxideWhat is a chemical equation?A chemical equation is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.
In a chemical reaction, the atoms of substances called reactants are rearranged to form new substances called products.
According to this question, two chemical reactions are given incompletely. The complete forms of these reactions showing the missing reactants and products are as illustrated above.
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the following solutions of NaOH are mixed together 20.ML of 3.0N, 40.mL of 2.0N, 60.mL of 1.0N, 80. mL of 4.0 N, and 100. mL of 5.0 N. what is the volume and normality of the final solution
Answer:
The volume of the final solution is 300 mL, and the normality of the final solution is 3.40 N.
Explanation:
To find the volume and normality of the final solution, we need to calculate the total amount of moles of NaOH in each solution and then combine them.
Step 1: Calculate the amount of moles for each solution.
20 mL of 3.0 N NaOH:Moles = Volume (L) x Normality
= 0.020 L x 3.0 N
= 0.060 moles
40 mL of 2.0 N NaOH:Moles = Volume (L) x Normality
= 0.040 L x 2.0 N
= 0.080 moles
60 mL of 1.0 N NaOH:Moles = Volume (L) x Normality
= 0.060 L x 1.0 N
= 0.060 moles
80 mL of 4.0 N NaOH:
Moles = Volume (L) x Normality
= 0.080 L x 4.0 N
= 0.320 moles
100 mL of 5.0 N NaOH:Moles = Volume (L) x Normality
= 0.100 L x 5.0 N
= 0.500 moles
Step 2: Calculate the total moles of NaOH by summing up the moles from each solution.
Total moles of NaOH = 0.060 + 0.080 + 0.060 + 0.320 + 0.500
= 1.020 moles
Step 3: Calculate the total volume of the final solution.
Total volume of the final solution = 20 mL + 40 mL + 60 mL + 80 mL + 100 mL
= 300 mL or 0.300 L
Step 4: Calculate the normality of the final solution.
Normality = Total moles of NaOH / Total volume of the solution (L)
= 1.020 moles / 0.300 L
= 3.40 N
Therefore, the volume of the final solution is 300 mL, and the normality of the final solution is 3.40 N.
HOW DOES WALTER WHITE SLEEP AT NIGHT
Answer:
Since Walter can alter time and space he doesn't have the kind of place to take a nap or buy a cap for his dog zap
Explanation:
Answer:
Breaking Bad
Explanation:
walt
Convert 6.13 mg per kg determine the correct dose in g for 175lb patient
The correct dose for a 175 lb patient would be approximately 0.48602 grams.
To convert 6.13 mg/kg to grams, we need to consider the weight of the patient and perform a unit conversion. Here's the step-by-step process:
1. Convert the weight of the patient from pounds to kilograms.
175 lb * (1 kg / 2.205 lb) = 79.37 kg (rounded to two decimal places)
2. Calculate the correct dose in grams by multiplying the patient's weight by the given dosage.
79.37 kg * 6.13 mg/kg = 486.02 mg
3. Convert the dose from milligrams (mg) to grams (g) by dividing by 1000.
486.02 mg / 1000 = 0.48602 g (rounded to five decimal places)
Therefore, the correct dose for a 175 lb patient would be approximately 0.48602 grams.
It's important to note that this calculation assumes the dosage is based on body weight and that the given dosage is appropriate for the patient's condition. Always consult a healthcare professional or follow the instructions of a medical prescription for accurate dosing information.
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superficial zone chondrocytes can get compacted under physiological loading: a multiscale finite element analysis.
a. true
b. false
The statement "Superficial zone chondrocytes can get compacted under physiological loading: a multiscale finite element analysis" is true.
Superficial zone chondrocytes are the most exposed to mechanical loading and are therefore at risk of being compacted under physiological loading. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.
This means that chondrocytes in the superficial zone of cartilage are at risk of being compacted under the physiological loading that it experiences in everyday life. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.
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What is the difference in energy levels of the sodium atom if emitted light has a wavelength of 589 nm?
Question 3(Multiple Choice Worth 3 points) (01.03 LC) What is potential energy? The energy of change O The energy of position or composition O The energy of mass or volume O The energy of motion
Potential energy is often referred to as the energy of position or composition. The energy that an object has due to its tension, electric charge, or relative immobility in space is known as potential energy. Potential energy is among the two basic forms of energy.
William Rankine, a Scottish engineer and physicist, coined the phrase "potential energy" in the 19th century. Potential energy comes in a variety of forms, each linked to a particular kind of force. It is the power imparted to an object by its position in relation to other objects. Learn more about potential energy in this article, which includes a definition, several categories, and examples.
The force acting on the two objects affects the formula for potential energy. The following is the formula for gravitational force:
W = m×g×h = mgh
Where,
m is the mass in kilogramsg is the acceleration due to gravityh is the height in metersPotential Energy Unit
In terms of units, kinetic energy and gravitational potential energy are equivalent: kg m2 / s2.
The unit used to measure all energy is the joule, which has the same units as kg m2 / s2 (J).
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Enter your answer in the provided box.
Answer the following questions about the fermentation of glucose (C6H12O6, molar mass 180.2 g/mol) to ethanol (C2H6O) and CO2.
C6H12O6(s) → 2 C2H6O(l) + 2 CO2(g) ΔH = −16 kcal/mol
glucose ethanol
How many kilocalories of energy are released from 40.0 g of glucose?
kcal of energy released
Report answer to TWO significant figures.
Answer:
Explanation:
40/ 180.2 x (-16 / 1 mole glucose)=-3.6 KJ
A student is weighing a standard 5.00-g weight four times on two different balances to check them for accuracy and precision. The following table shows the data:
Which of the balances is more accurate? Which is more precise?
A. Balance B is more accurate.
B. Balance A is more precise.
To determine which balance is more accurate and which one is more precise, let's analyze the data provided:
A. Accuracy:
To assess accuracy, we need to compare the average measurements from each balance to the true value, which is 5.00 g.
For Balance A:
Average weight measured = (4.2 g + 4.1 g + 4.3 g + 4.2 g) / 4 = 16.8 g / 4 = 4.2 g
For Balance B:
Average weight measured = (5.1 g + 4.9 g + 4.7 g + 5.2 g) / 4 = 20.9 g / 4 = 5.225 g
Comparing the averages to the true value:
Accuracy of Balance A = |4.2 g - 5.00 g| = 0.8 g
Accuracy of Balance B = |5.225 g - 5.00 g| = 0.225 g
Since the accuracy is determined by the difference between the measured values and the true value, Balance B is more accurate as it has a smaller difference.
B. Precision:
Precision refers to how close the measured values are to each other. To assess precision, we can calculate the standard deviation of the measurements from each balance.
For Balance A:
Standard deviation = \(\sqrt([ (4.2 g - 4.2 g)^{2} + (4.1 g - 4.2 g)^{2} + (4.3 g - 4.2 g)^{2} + (4.2 g - 4.2 g)^{2}]/4)\)
Standard deviation = \(\sqrt([0 + (-0.1)^{2} + 0.1^{2} + 0]/4)\) = \(\sqrt(0.02 / 4)\)
= \(\sqrt(0.005)\) ≈ 0.071 g
For Balance B:
Standard deviation = \(\sqrt([ (5.1 g - 5.225 g)^{2} + (4.9 g - 5.225 g)^{2} + 4.7 g - 5.225 g)^{2} + (5.2 g - 5.225 g)^{2}] / 4)\)
Standard deviation = \(\sqrt([0.075 ^{2} + (-0.325)^{2}) + (-0.525)^{2} + (-0.025)^{2}] / 4)\)
≈ 0.213 g
Comparing the standard deviations:
Precision of Balance A ≈ 0.071 g
Precision of Balance B ≈ 0.213 g
Since precision is determined by the spread or variability of the measured values, Balance A is more precise as it has a smaller standard deviation, indicating less variation in the measurements.
The question was incomplete. find the full content below:
A student is weighing a standard 5.00-g weight four times on two different balances to check them for accuracy and precision. The following table shows the data:
Trial - 1,2,3,4
Balance A - 4.2 g, 4.1 g, 4.3 g, 4.2 g
Balance B - 5.1 g, 4.9 g, 4.7 g, 5.2 g
A. Which of the balances is more accurate?
B. Which is more precise?
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Calculate the solubility of BaCO3 (a) in pure water and (b) in a solution in which [CO32-] = 0.289 M. Solubility in pure water = M Solubility in 0.289 M CO32- = M
Answer:
(a). The solubility of \(BaCO_{3}\) in pure water is \(4.4\times10^{-5}\ M\)
(b). The solubility of \(BaCO_{3}\) in solution is \(6.92\times10^{-9}\ M\)
Explanation:
Given that,
(a). The solubility of \(BaCO_{3}\) in pure water
(b). The solubility of \(BaCO_{3}\) in a solution
Solubility of \(CO_{3}^{-2}\) is 0.289 M
We know that,
The solubility product constant of \(BaCO_{3}\) is \(2\times10^{-9}\)
Let the solubility of \(BaCO_{3}\) is s.
We need to calculate the solubility of \(BaCO_{3}\) in pure water
Using formula of solubility
\(ksp=s\times s\)
\(ksp=s^2\)
\(s=\sqrt{ksp}\)
Put the value into the formula
\(s=\sqrt{2\times10^{-9}}\)
\(s=4.4\times10^{-5}\ M\)
(b). We need to calculate the solubility of \(BaCO_{3}\) in solution
Using formula of solubility
\(ksp=s\times s\)
Put the value into the formula
\(2\times10^{-9}=s\times 0.289\)
\(s=\dfrac{2\times10^{-9}}{0.289}\)
\(s=6.92\times10^{-9}\ M\)
Hence, (a). The solubility of \(BaCO_{3}\) in pure water is \(4.4\times10^{-5}\ M\)
(b). The solubility of \(BaCO_{3}\) in solution is \(6.92\times10^{-9}\ M\)
Refer to picture for question, all must be answered to be considered for Brainliest!!!
Li₃PO₄ + 3 Zn(NO₃)₂ → 3 LiNO₃ + Zn₃(PO₄)₂. In this balanced equation, one of the products is Zn₃(PO₄)₂. To ensure that the equation is balanced, we need 3 moles of Zn(NO₃)₂ for every 1 mole of Li₃PO₄.
What is product in any given reaction?In a chemical reaction, a product is a substance that is formed as a result of the chemical reaction. It is the end result of a chemical reaction, and it is produced by the rearrangement of atoms and/or ions of the reactants.
In the given equation, we end up with 1 mole of Zn₃(PO₄)₂ for every 3 moles of Zn₃(PO₄)₂. This means that the molar ratio of Zn₃(PO₄)₂ to Zn₃(PO₄)₂ is 1:3, indicating that we need three times as much Zn₃(PO₄)₂ as Zn₃(PO₄)₂ to balance the equation. Therefore, one of the products, Zn₃(PO₄)₂, must be produced in a smaller quantity than the other product, LiNO₃.
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Identify the following for an atom with 8 protons, 8 electrons, and 7 neutrons.
a. Atomic number:
b. Mass number:
c. Nuclear Notation:
d. Hyphen Notation:
please help
Answer:
i thinks its a. but iam not sure
Dale is speaking to a group of students about the importance of extracurricular activities. He provides specific scenarios to show the audience how the information presented will affected them directly. Dale is fulfilling which goal of informational speaking?
to enhance understanding
to be heard
to maintain interest
to be remembered
A sample of the compound has 9 grams of cobalt. How many grams of fluorine does the sample have?
The mass (in grams) of fluorine the sample have is 2.91 g
How do I determine the mass of fluorine?First, we shall determine the mole of 9 grams of cobalt. Details below:
Mass of cobalt = 9 grams Molar mass of cobalt = 58.93 g/mol Mole of cobalt =?Mole = mass / molar mass
Mole of cobalt = 9 / 58.93
Mole of cobalt = 0.153 mole
Finally, we shall determine the mass of fluorine the present in the compound. Details below:
Molar mass of fluorine = 19 g/mol Mole of cobalt = 0.153 moleMole of fluorine = Mole of cobalt = 0.153 moleMass of fluorine = ?Mole = mass / molar mass
0.153 = Mass of fluorine / 19
Cross multiply
Mass of fluorine = 0.153 × 19
Mass of fluorine = 2.91 g
Thus, the mass of fluorine is 2.91 g
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Hey can someone help me fill out these blanks
Answer:
Constructive interference is when two waves interact causing larger waves because the crest will meet a crest or a trough will meet a trough which adds the waves together changing the size of the amplitude.
Destructive interference is when two waves interact causing smaller waves because the crest will meet a trough or a trough will meet a crest which subtracts the waves together changing the size of the amplitude.
Molybdenum can form a wide series of halide compounds, including four different fluoride compounds. The percent by mass of molybdenum in the four compounds is 63.0%,
56.0%,
50.0%,
and 46.0%.
Determine the formula and name for each of the four different molybdenum fluorides.
The formula and names of the compounds are:
1. Formula of compound => MoF₃
Name of compound => Molybdenum trifluoride
2. Formula of compound => MoF₄
Name of compound => Molybdenum tetrafluoride
3. Formula of compound => MoF₅
Name of compound => Molybdenum pentafluoride
4. Formula of compound => MoF₆
Name of compound => Molybdenum hexafluoride
1. Determination of the name and formula of the molybdenum fluoride having 63.0% of molybdenum.
Molybdenum (Mo) = 63.0%
Fluorine (F) = 100 – 63 = 37%
Formula =?Mo = 63.0%
F = 37%
Divide by their molar mass
Mo = 63.0 / 96 = 0.656
F = 37 / 19 = 1.947
Divide by the smallest
Mo = 0.656 / 0.656 = 1
F = 1.947 / 0.656 = 3
Therefore,
Formula of compound => MoF₃
Name of compound => Molybdenum trifluoride
2. Determination of the name and formula of the molybdenum fluoride having 56.0% of molybdenum.
Molybdenum (Mo) = 56.0%,
Fluorine (F) = 100 – 56 = 44%
Formula =?Mo = 56%
F = 44%
Divide by their molar mass
Mo = 56 / 96 = 0.583
F = 44 / 19 = 2.316
Divide by the smallest
Mo = 0.583 / 0.583 = 1
F = 2.316 / 0.583 = 4
Therefore,
Formula of compound => MoF₄
Name of compound => Molybdenum tetrafluoride
3. Determination of the name and formula of the molybdenum fluoride having 50.0% of molybdenum.
Molybdenum (Mo) = 50.0%,
Fluorine (F) = 100 – 50 = 50%
Formula =?Mo = 50%
F = 50%
Divide by their molar mass
Mo = 50 / 96 = 0.520
F = 50 / 19 = 2.632
Divide by the smallest
Mo = 0.520 / 0.520 = 1
F = 2.632 / 0.520 = 5
Therefore,
Formula of compound => MoF₅
Name of compound => Molybdenum pentafluoride
4. Determination of the name and formula of the molybdenum fluoride having 46.0% of molybdenum.
Molybdenum (Mo) = 46.0%,
Fluorine (F) = 100 – 46 = 54%
Formula =?Mo = 46%
F = 54%
Divide by their molar mass
Mo = 46 / 96 = 0.479
F = 54 / 19 = 2.842
Divide by the smallest
Mo = 0.479 / 0.479 = 1
F = 2.842 / 0.479 = 6
Therefore,
Formula of compound => MoF₆
Name of compound => Molybdenum hexafluoride
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3. Suppose you had titrated your vinegar sample with barium hydroxide instead of sodium hydroxide:
Ba(OH)2(aq)+2CH3COOH(aq)⟶Ba(CH3COO)2(aq)+2H2O(l)
Consider a 0.586 M aqueous solution of barium hydroxide,
What volume (in mL) of 0.586 M Ba(OH)2 solution are required to neutralize 10 ml of vinegar containing 2.78 g of acetic acid?
Answer:
39.6 mL
Explanation:
Step 1: Write the balanced neutralization reaction
Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)
Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH
The molar mass of CH₃COOH is 60.05 g/mol.
2.78 g × 1 mol/60.05 g = 0.0463 mol
Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH
The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.
Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂
0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL
1:How many moles of ammonia will be produced if 12 moles of nitrogen are used?
2:How many moles of nitrogen are required to react with 6 moles of hydrogen?
3:Honors: If there are 40 moles of nitrogen and 30 moles of hydrogen, what is the limiting reactant? Explain your answer.
4:Honors: What is the mass of hydrogen required to produce 80 g of ammonia?
Please, I really need help, so I can graduate
Answer:
See Explanation
Explanation:
The reaction equation is
3H2(g) + N2(g) -----> 2NH3(g)
1)If 1 mole of N2 yields 2 moles of NH3
12 moles of N2 will yield 12 * 2/1 = 24 moles of NH3
2) 3 moles of nitrogen reacts with 1 mole of nitrogen
6 moles of hydrogen will react with 6 * 1/3 = 2 moles of nitrogen
3) The limiting reactant yields the least amount of product
If 1 mole of nitrogen yields 2 moles of NH3
40 moles of nitrogen yields 40 * 2/1 = 80 moles of NH3
If 3 moles of hydrogen yields 2 moles of NH3
30 moles of hydrogen yields 30 * 2/3 = 20 moles of NH3
Hence hydrogen is the limiting reactant
4) Number of moles in 80g of NH3 = 80g/17g/mol = 4.71 moles
3 moles of hydrogen produces 2 moles of ammonia
x moles of hydrogen produces 4.71 moles of ammonia
x = 3 * 4.71/2 = 7.065 moles of hydrogen
Mass = 7.065 moles of hydrogen * 2 g/mol
Mass = 14.13 g of hydrogen
The element Aluminium (AI) Is
Answer:
a metal which is found in 13 group and 3 period of periodic table
Hello How do you do?
What is logic bomb and time bomb?
Answer:
A logic bomb and a time bomb are both types of malicious software or code that are designed to cause harm to a computer system or network. Here's a brief explanation of each:
Logic Bomb:
A logic bomb is a piece of code or software that is intentionally inserted into a system to execute a malicious action when specific conditions are met. It remains dormant until triggered by a predefined event or circumstance, such as a specific date, time, or user action. Once triggered, the logic bomb may perform various harmful actions, such as deleting files, corrupting data, or disrupting system functionality. The purpose of a logic bomb is often to cause damage or to gain unauthorized access to a system.
Time Bomb:
A time bomb is similar to a logic bomb, but it is specifically designed to activate or execute its malicious payload at a certain date or time. It is usually programmed to remain undetected until the predetermined time arrives. The time bomb can be set to trigger after a specific time period or on a particular date, at which point it may carry out destructive actions. Time bombs can be used by attackers to target specific events or to coordinate an attack to occur simultaneously across multiple systems.
Both logic bombs and time bombs are considered forms of malicious code or malware and are used with malicious intent to disrupt, damage, or compromise computer systems or networks. They can be extremely harmful, and it is important to have strong security measures, such as antivirus software and regular system updates, to protect against such threats.
Explanation:
Lab 2: paper chromatography of organic dyes
Picture of questions below.
Answer:
The three primary colors used when mixing dyes or paints are red, yellow, and blue. Other colors are often a mixture of these three colors. Try running a chromatography test again with non-primary-color markers, like purple, brown, and orange.
Explanation:
Mixtures that are suitable for separation by chromatography include inks, dyes and colouring agents in food. ... As the solvent soaks up the paper, it carries the mixtures with it. Different components of the mixture will move at different rates. This separates the mixture out.
Correctly predict the ionic compound that would form between the atoms rubidium (Rb) and oxygen (O).
Answer:
Rb2O
Explanation:
Rb is a 1+ element and Oxygen is a 2- element. To have a neutral overall charge you must change the molar ratio to have 2 (1+ elements) and 1 (2- element). Together add to 2+(-2)=0. So the overall product is neutral.
The equation for the reaction between aqueous lead(II) nitrate and aqueous potassium iodide is shown
Pb(NO₃)₂(aq) + 2Kl(aq) → Pbl₂(s) + 2KNO₃(aq)
colourless colourless yellow colourless
Which method could be used to separate the products?
A chromatography
B crystallization
C distillation
D filtration
The method that can be used to separate the products of the reaction between aqueous lead(II) nitrate and aqueous potassium iodide is filtration (option D).
What is filtration?
Filtration is the mechanical separation of a liquid from the undissolved particles floating in it.
According to this question, a reaction occurs between aqueous lead (II) nitrate and aqueous potassium iodide as shown:
Pb(NO₃)₂(aq) + 2Kl(aq) → Pbl₂(s) + 2KNO₃(aq)
Based on the equation above, lead iodide is a solid product while pottasium nitrate is an aqueous solution.
Filtration is used to separate insoluble solid particles from liquid like the aqueous product, hence, it is a suitable separation technique.
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