If x to the power of 2= 60, what is the value of x

Answer:

2p - 5 ≤ 124.

Step-by-step explanation:

If Chis's pay is p then it is:

2p - 5 ≤ 124.

Answer:

No

Step-by-step explanation:

They are not equivalent fractions

Answer:

No, they are not equivalent

Step-by-step explanation:

we will find the length of rectangle when area is divided by the breadth of rectangle.

Some properties are rectangle are stated below:

1. rectangle has four right angles

2. rectangles has four sides and equal opposite sides which are parallel to each other.

3.rectangle has two diagonals which are similar in length.

The bigger side lengths are called length and the smaller sides are called breadth of rectangle.

if area of rectangle is given, we can find length when area is divided by its breadth.

 length = area/breadth

hence, length of rectangle is determined from the value of area and breadth.

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Answer:

Step-by-step explanation:

you add 8,14, and 11 to get 33 then you divide it by 3, because there are 3 numbers meaning the average is 11.

If that makes, all you have to do is add up all the numbers then divide by the amount of numbers you see to find the average of the numbers.

\(\huge\text{\bf Hey there!}\)

\(\large\text{The word \underline{average} is basically the \boxed{\bf mean} of a data set. When you }\\\large\text{hear or see the word \underline{average} in math think of its asking you to \boxed{\bf find \ your \ total}}\\\large\text{in your data set.}\)

\(\large\text{Here is the formula to make it easier to solve}\downarrow\)

\(\mathbf{mean = \dfrac{sum\ of\ all\ terms}{number\ of\ terms}}}\)

\(\large\text{YOUR EQUATION:}\)

\(\mathbf{average = \dfrac{8 + 14 + 11}{3}}\)

\(\mathbf{\dfrac{8 + 14 + 11}{3}}\)

\(\mathbf{= \dfrac{22 + 11}{3}}\)

\(\mathbf{= \dfrac{33}{3}}\)

\(\mathbf{= \dfrac{33\div3}{3\div3}}\)

\(\mathbf{= \dfrac{11}{1}}\) \(\mathbf{\rightarrow 11\div1}\)

\(\mathbf{= 11}\)

\(\huge\boxed{\text{Therefore, your answer should be: \textsf{11}}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

3990 is the lowest common multiple (LCM) of 105 and 190.

To work out the lowest common multiple (LCM) of 105 and 190, we need to first draw the prime factor tree for 190. According to the prime factor tree for 190 is:

Next, we can find the prime factors of 105 using a similar method. According to, the prime factorization of 105 is 3 x 5 x 7.

To find the LCM of two numbers, we need to multiply together the highest powers of all the prime factors that appear in either number. In this case, the prime factors that appear in either number are 2, 3, 5, 7, and 19.

\(2^1 \times 3^1 \times5^1 \times 7^1 \times 19^1 = 3990\)

So, the lowest common multiple (LCM) of 105 and 190 is 3990.

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Answer: your answer is negative $88.31

Step-by-step explanation:

$15,440 minus $42,50 minus $51,50 minus $9,75= negative $88.31

Answer:

x < 11

Step-by-step explanation:

8 - 3x > -25

-8            -8    (subtract 8 from both sides)

-3x > -33

/-3      /-3        (divide each side by -3: because we divided we must flip the symbol)

x < 11

Answer:

A

12+7x=a

x=days

a=amount of money

B 12+7x=a

Step-by-step explanation:

7(18)=126

12+126=a

138=a

Step-by-step explanation:

part A:12+7x

first day 12+7=$19

second day 19+7=$26

third day 26+7=$33

....

so

number of moneys on x day will be

12+7*x where x represent the number of days

so

for three days

12+7*3=12+21=33

part B:138

12+7x where x=18

12+7*18=12+126=$138

He will have $138 on the 18th day.

Using the inverse function, it is found that the value is of k = 1.

Suppose we have a function y = f(x).

To find the inverse, we exchange the instances of x and y, and then we isolate y.

In this problem, the function is:

\(y = k(4 + 2x)\)

Exchanging x and y, and isolating y:

\(x = k(4 + 2y)\)

\(4k + 2ky = x\)

\(2ky = x - 4k\)

\(y = \frac{x - 4k}{2k}\)

\(f^{-1}(x) = \frac{x - 4k}{2k}\)

f^-1(6)=1, hence:

\(f^{-1}(x) = \frac{x - 4k}{2k}\)

\(1 = \frac{6 - 4k}{2k}\)

\(6 - 4k = 2k\)

\(6k = 6\)

\(k = \frac{6}{6}\)

\(k = 1\)

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Answer:

20/29

Step-by-step explanation:

Sin is Opposite/Hypotenuse. The opposite leg is 20, and the hypotenuse is 29.

The ball is approximately 50 meters from the ground after about 5.477 seconds.

To find the approximate time it takes for the ball to reach a height of 50 meters, we need to solve the quadratic equation \(f(x) = -5x^2 + 200 = 50\).

Let's set f(x) equal to 50 and solve for x:

\(-5x^2 + 200 = 50\)

Rearranging the equation, we have:

\(-5x^2 = 50 - 200\\-5x^2 = -150\)

Dividing both sides by -5:

\(x^2 = 30\)

Taking the square root of both sides:

x = ±√30

Since we are looking for the time in seconds, we only consider the positive value of x:

x ≈ √30

Using a calculator, we find that the square root of 30 is approximately 5.477.

Please note that this is an approximate value since the quadratic model provides an approximation of the ball's height and does not account for factors such as air resistance.

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Explanation:

This is a constant vertical line on x = -1

Answer:

The graph is:

Only Line a and Line b are parallel to each other and Line c is not perpendicular.

What is a Slope of a Starlight Line?

A slope of a line is defined in mathematics as the change in y coordinate with regard to the change in x coordinate.  The net change in y-coordinate is denoted by y, whereas the net change in x-coordinate is denoted by Δx. As a result, the change in y-coordinate in relation to the change in x-coordinate is given by,

m = difference in y/difference in x = Δy/Δx

Where "m" represents the slope of a line.

Solution:

We know that if Slope of Line 1 = Slope of Line 2, then they are parallel

and,

if Slope of Line 1 * Slope of Line 2 = -1, then they are perpendicular

Step 1:

Calculating Slope of all three lines

Slope of a = 0-1/2+1 = -1/3

Slope of b = 4-5/3-0 = -1/3

Slope of c = 0-5/0-2 = 5/2

Step 2:

Since it can be observed that if possible only a and b can be parallel to each other, so checking the condition on line a and line b

Slope of Line a = Slope of Line b = -1/3

Since, both are equal therefore Line a and Line b are parallel

Checking if Line c is perpendicular to Line a or not,

Slope of Line c * Slope of Line a = -5/6

Since, it is not equal to -1 therefore, Line c is not perpendicular line to Line a and Line b.

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Answer:

5

Step-by-step explanation:

Dont ask why i think its 5 mph

Answer: $1000

Step-by-step explanation:

If the ratio is 5:3 and the smaller is 600, then 600/3*5 = x is how you would solve.

Therefore, your answer is 1000

The T - Test is the appropriate test for a comparison a group of 10 dogs and group of 10 cats.

According to the statement

we have to explain and tell bout the those test which is appropriate for the comparison of the group of 10 dogs and group of 10 cats.

So, For this purpose, we know that the

The test used on this are the those test for the applicable on th etwo groups.

So, We know that the

A t-test is a statistical test that compares the means of two samples. It is used in hypothesis testing, with a null hypothesis that the difference in group means is zero and an alternate hypothesis that the difference in group means is different from zero.

here the t test is used for the two samples.

So, The T - Test is the appropriate test for a comparison a group of 10 dogs and group of 10 cats.

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Answer:

72 pi + 48 pi= 120pi (not sure if I am right tho)

Step-by-step explanation:

Answer:

volume = 452.16 units^3

Step-by-step explanation:

volume = (Pi)(r^2)(h)

volume = (3.14)(6^2)(4) = 452.16

The price of the computer if the discount is applied before the rebate is $1225. The composite function is (g.f)(x) = g(f(x))

(g.f)(x) = g(f(x))

f(1500) = 0.95(1500)

= 1425

g(1425) = 1425-20

= 1225

= $1225

Therefore, The price of the computer if the discount is applied before the rebate is $1225. The composite function is (g.f)(x) = g(f(x))

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Answer:

11.3

Step-by-step explanation:

Volume: L * W * H

L = 20

W = 8

H = 35 mm = 35/10 = 3.5 cm

V = 20 * 8 * 3.5

V = 560 cm^3

Density = m/v

Density = 6328 / 560

Density = 11.3

Answer:

C=Radiud ÷2

=

Step-by-step explanation:

B=Radius ÷2

2×3.142

C=2

Answer:

34

Step-by-step explanation:

a + 90 + 56 = 180

a + 146 = 180

a = 180 - 146

a = 34

The population proportion who participated in voting (63%) is higher than the sample proportion from this survey (58.91%).

To determine whether the population proportion who participated in voting or the sample proportion from the survey is higher, we need to compare the percentages.

The population proportion who participated in voting is given as 63% of all registered voters.

This means that out of every 100 registered voters, 63 participated in voting.

In the survey of retired voters, 162 out of 275 participants voted. To calculate the sample proportion, we divide the number of retired voters who participated (162) by the total number of retired voters in the sample (275) and multiply by 100 to get a percentage.

Sample proportion = (162 / 275) \(\times\) 100 ≈ 58.91%, .

Comparing the population proportion (63%) with the sample proportion (58.91%), we can see that the population proportion who participated in voting (63%) is higher than the sample proportion from this survey (58.91%).

Therefore, based on the given data, the population proportion who participated in voting is higher than the sample proportion from this survey.

It's important to note that the sample proportion is an estimate based on the surveyed retired voters and may not perfectly represent the entire population of registered voters.

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The equation of g(x) when the parent function f(x) = 3^x is transformed is g(x) = 3^{x - 4} + 5.

The equation of g(x) when the parent function f(x) = 2^x is transformed is g(x) = 4(2)^{x - 3}.

The equation of g(x) when the parent function f(x) = 4^x is transformed is g(x) = -2(4)^{x + 1} + 3.

By critically observing the graph of the exponential function f(x) = 3^x, we can reasonably and logically deduce that f(x) is vertically translated (k) by 5 units up and horizontally translated (h) by 4 units to the right. Therefore, the equation of g(x) is given by:

g(x) = 3^{x - h} + k

g(x) = 3^{x - 4} + 5.

Based on the graph of the exponential function f(x) = 2^x, we can reasonably and logically deduce that f(x) is compressed by a scale factor (a) of 4 units and horizontally translated (h) by 3 units to the right. Therefore, the equation of g(x) is given by:

g(x) = a(b)^x - h}

g(x) = 4(2)^{x - 3}

Based on the graph of the exponential function f(x) = 4^x, we can reasonably and logically deduce that f(x) is reflected across the x-axis and expanded by a scale factor (a) of 2 units, followed by a translation of 1 units left and 3 units up:

where; a = -2, h = -1, and k = 3.

g(x) = a(b)^x - h} + k

g(x) = -2(4)^{x - (-1)} + 3

g(x) = -2(4)^{x + 1} + 3

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Answer:

0.0275

Step-by-step explanation:

It is important to consider the scale of measurement and the specific characteristics of the variables when selecting an appropriate statistical test.The tests can be classified as follows:

1. A researcher measures the proportion of schizophrenic patients born in each season.

This test is nonparametric. The scale of measurement is categorical, as the seasons (spring, summer, fall, winter) represent distinct categories rather than continuous numerical values. Therefore, parametric assumptions, such as normality and equal variances, do not apply to this measurement.

2. A researcher measures the average age that schizophrenia is diagnosed among male and female patients.

This test is parametric. The scale of measurement is continuous and numerical (age in years). Parametric tests, such as t-tests or ANOVA, can be applied when working with continuous data, assuming the data meet the required assumptions (e.g., normality, independence, and equal variances).

3. A researcher tests whether frequency of Internet use and social interaction are independent.

This test can be both parametric or nonparametric, depending on the measurement scale and the specific statistical test used. If the variables are measured on a nominal or ordinal scale, nonparametric tests, such as the chi-square test, would be appropriate. If the variables are measured on a continuous scale, parametric tests, such as logistic regression, could be employed.

4. A researcher measures the amount of time (in seconds) that a group of teenagers uses the Internet for school-related and non-school-related purposes.

This test is parametric. The scale of measurement is continuous (time in seconds), and parametric tests, such as t-tests or ANOVA, can be utilized to compare means or variances, assuming the required assumptions are met.

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the perimeter and area is the hypotenuse multiplied