If we see everything moving away from us, does that mean we are at the center of the Universe?
No, it does not mean we are at the center of the Universe. The observed phenomenon of galaxies moving away from us is due to the expansion of the Universe. This expansion is explained by Hubble's Law and the Big Bang Theory. According to these principles, the Universe has been expanding since its beginning, and the galaxies are moving away from each other as a result. This creates the illusion that we are at the center of the Universe, but in reality, there is no defined center, as the expansion is happening uniformly in all directions.
Instead, we are likely located on the outer edge of the universe, where galaxies are moving away from us due to the expansion of space. This discovery was made through observations of redshift, which occurs when light waves from distant galaxies stretch out and move towards the red end of the spectrum as they travel through expanding space. This phenomenon is known as the Doppler effect and it allows us to measure the speed and direction of galaxies relative to our own.
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a car travels west at 40 km/h
a man on a bike travels at 10 km/h
what is the speed of the car relative to the speed of the bicycle ?
Answer:
The car is going 0 km/h more than the bike
Explanation:
A physical quantity X is connected from X = ab2/C. Calculate percentage error in X, when percentage error in a,b,c are 4,2 and 3 respectively.
Answer: 11%
Explanation:
Given that
X = ab^2/C. Calculate percentage error in X, when percentage error in a,b,c are 4,2 and 3 respectively.
Percentage error of b = 2%
Percentage error of b^2 = 2 × 2 = 4
When you are calculating for percentage error that involves multiplication and division, you will always add up the percentage error values.
Percentage error of X will be;
Percentage error of a + percentage error of b^2 + percentage error of c
Substitute for all these values
4 + 4 + 3 = 11%
Therefore, percentage error of X is 11%
a magnetic field of magnitude 0.300 t is oriented perpendicular to the plane of a ciruclar loop
A magnetic field of magnitude 0.300 T is oriented perpendicular to the plane of a circular loop. According to the Faraday's law of electromagnetic induction, the emf induced in a coil is directly proportional to the rate of change of magnetic flux .
which is given as;emf = -NdΦ/dtwhere, N = number of turns in the coil,dΦ/dt = rate of change of magnetic fluxThus, the main ans to this question is the emf induced in the circular loop. The explanation for the emf induced in a circular loop can be given as follows; The magnetic flux through a circular loop of area A is given by;Φ = B*AWhere,B = magnetic field strength A = area of the circular loop Hence, the rate of change of magnetic flux can be given as;dΦ/dt = dB/dt *
A Therefore, the emf induced in the circular loop can be given as;emf = -NdΦ/dtemf = -N*dΦ/dtTherefore,emf = -N * d(B*A)/dtemf = -N * A * dB/dt Given, B = 0.300 T Therefore, dB/dt = 0The magnitude of magnetic field and the area of the circular loop are given .Hence, the emf induced in the circular loop can be found by using the following formula; emf = -N * A * dB/dtemf = -N * A * 0Therefore,emf = 0
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Can you take your phone in a tanning bed?
No, you cannot take your phone in a tanning bed. Tanning beds use ultraviolet (UV) light to help people achieve a dark, even tan. However, this light can damage electronic devices, such as cell phones.
The heat generated by the bulbs and the strong UV radiation can damage the phone’s internal components and cause the phone to overheat. This can lead to short circuits and permanent damage to the phone.
In addition to the damage caused by UV light, the high temperatures of the tanning bed may cause the phone to overheat, leading to further damage, such as battery failure. Overheating may also cause the phone to shut down or restart unexpectedly, resulting in data loss and further damage.
Finally, taking your phone into a tanning bed may be a distraction. Tanning beds require the user to remain still and relaxed in order to achieve optimal results. Having your phone in the bed may disrupt this process and lead to a less effective tanning session.
For all of these reasons, it is not recommended to take your phone into a tanning bed. Doing so may cause irreparable damage to the device and may disrupt the tanning process.
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1. A car travels 180 m southeast in 30 s. What is the average velocity? (Lesson 2.01)
Show your work and include units.
Step 1: write formula
Step 2: list “givens”
Step 3: plug in numbers
Step 4: calculate & write answer
Step 5: add units
i
Answer:
6m/s
Explanation:
Velocity (m/s) = Displacement (m) / Time (s)
Given:
Displacement = 180m
Time = 30s
Velocity = 180/30 = 6m/s
Gravity on Jupiter is 25 m/s/s, what is the weight of a 12 kg object on Jupiter?
Answer:
300 Newtons
Explanation:
Weight is the force of attraction between two bodies, one usually larger (like a planet), and one smaller (like a person). Force can be calculated using the formula: Force = mass × acceleration.
The mass here is 12kg, the acceleration, which in this case, is the acceleration due to gravity is 25m/s/s, by plugging in our values, we have
Force = 12 × 25 = 300 Newtons or 300 N for short.
Which laboratory activity involves a chemical change?
Answer:
The green growing on the penny of copper and the rust forming on the nail of iron are chemical changes. Boiling away salt water, scraping iron filings from a mixture of sand with a magnet, and breaking a rock with a hammer, are physical changes.
a train with a monochromatic headlight is approaching you at a speed of 1 18 c. if a student on the train measures the wavelength of the light to be 590 nm, what do you measure the wavelength (in nm) to be? nm
The wavelength of the light you measure is 197.53 nm.
Wavelength is a concept that describes the length of one wave. It's typically measured in meters or nanometers in the context of electromagnetic waves, such as light waves.
The student on the train measured the wavelength of light to be 590 nm, and the speed of the train was 1.18c.
λ2 = λ1 / (1 - (v/c)), where λ1 is the wavelength of the light measured on the train, λ2 is the wavelength of the light measured by you, v is the velocity of the train, and c is the speed of light.
λ1 = 590 nm, v = 1.18c, and c = 3.00 x 108 m/s are the values we'll input.λ2 = λ1 / (1 - (v/c)) is the calculation we'll make.
λ2 = 590 nm / (1 - (1.18c / 3.00 x 108 m/s))We'll begin by simplifying the denominator:λ2 = 590 nm / (1 - 3.93 x 10-3)λ2 = 590 nm / 0.99607λ2 = 591.79 nm
We can round our answer to three significant figures, as the original wavelength measurement had three.λ2 = 592 nm.The wavelength of the light you measure is 197.53 nm.
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Match the phrase with word please help!
Phrases:
1.) The amount of work done when jerry carries a box from his house to the moving truck . He exerts a force of 35 N while carrying the box 4 meters
2.) The power resulting from 420 Nm of work being completed in 3 seconds
3.) The amount of work done when Fido carries his toy from the backyard to his crate. He exerts a force of 1.2 N over a distance of 15 m
4.) The power resulting from 120 Nm of work being completed in 20 seconds
A.) 140 joules
B.) 140 Newton-meters
C.) 6 joules
D.) 6 Newton-meters
Answer:
1-B, 2-A, 3-D, 4-C
Explanation:
1. The force exerted is, F = 35 N
Distance the box is moved, d = 4 m
So the amount of work done is, W = F x d
= 35 x 4
= 140 Newton-meters
2. Work done, W = 420 Nm
Time, T = 3 seconds
Therefore, the power required is,
\($P=\frac{W}{T}$\)
\($P=\frac{420}{3}$\)
= 140 joules
3. The force exerted is, F = 1.2 N
Distance the box is moved, d = 5 m
So the amount of work done is, W = F x d
= 1.2 x 5
= 6 Newton-meters
4. Work done, W = 120 Nm
Time, T = 20 seconds
Therefore, the power required is,
\($P=\frac{W}{T}$\)
\($P=\frac{120}{20}$\)
= 6 joules
How much power does it take to do 1000 J of work in 8 seconds?
ball is thrown upward from a window that is 12 m above the ground. The ball reaches a maximum height of 4 m above the window before falling all the way down to the ground. What distance did the ball travel?
Answer:
20 m
Explanation:
The ball travels 4 m up, then 16 m down. It travels a total distance of 20 m.
Among the objects found in the excavated temple were small terra-cotta effigies left by supplicants who were either asking the goddess Bona Dea's aid in healing physical and mental ills or thanking her for such help.
(A) in healing physical and mental ills or thanking her for such help
(B) in healing physical and mental ills and to thank her for helping
(C) in healing physical and mental ills, and thanking her for helping
(D) to heal physical and mental ills or to thank her for such help
(E) to heal physical and mental ills or thanking her for such help
(A) in healing physical and mental ills or thanking her for such help.
This option accurately captures the meaning of the sentence. The supplicants left the terra-cotta effigies either as a request for the goddess Bona Dea's aid in healing physical and mental ills or as an expression of gratitude for the help received. The phrase "in healing physical and mental ills" and "thanking her for such help" effectively conveys both the supplicants' requests and expressions of gratitude.
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explain how the metric units for length, volume and mass are related
In the metric system, length, volume, and mass are related by a set of units that are based on fundamental physical constants.
The base unit for length is the meter, which is defined as the distance traveled by light in a vacuum in 1/299,792,458 of a second. This unit is used to define all other length units in the metric system. The base unit for volume is the liter, which is defined as the amount of a liquid that occupies a space of 1 liter at a temperature of 0°C and a pressure of 1 atm.
The base unit for mass is the kilogram (kg), which is defined as the amount of matter that has a mass of 1 kilogram. This unit is used to define all other mass units in the metric system. In the metric system, other units are defined in multiples or fractions of these base units. For example, the meter is divided into 100 centimeters, and the liter is divided into 10 deciliters. Similarly, the kilogram is divided into 100 grams, and the meter is divided into 100 centimeters.
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Part B
Based on the information in the article, how could plants be used in the future to help counteract some human
emissions?
Answer:
Having more plants performing photosynthesis could help reduce the amount of carbon dioxide in the atmosphere.
Explanation:
sample answer
The plants can be used in the future to help counteract some human
emissions they absorb carbon dioxide from the air and release oxygen.
What is photosynthesis?It is a process carried out by photosynthetic autotrophic organisms, such as plants, algae and some prokaryotes. These organisms capture sunlight, convert it into chemical energy, which will be used to produce organic compounds, based on water and carbon dioxide.
Trees, like other plants, in the process called photosynthesis, absorb carbon dioxide from the air and release oxygen. They also make the air wetter and cooler. In this way, plants contribute to the good quality of the air we breathe.
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What is a volume of a 200 gram sample of gold if its density is known to be 20.5g/cm3?
Describe the four-step process that is required for an internal combustion engine to function. Use details to support your answer.
An internal combustion engine is an engine in which combustion takes place inside the engine and is used to generate mechanical power.
Step 1: Intake: During the intake stroke, the engine takes in air (if it is naturally aspirated) or a mixture of air and fuel (if it is fuel-injected) and compresses it. In the combustion chamber, this mixture is drawn in through the intake valve. The carburetor mixes the fuel and air, while the fuel injectors inject fuel directly into the combustion chamber.
Step 2: Compression: During the compression stroke, the piston moves back up to compress the mixture of air and fuel. The spark plug fires, igniting the compressed mixture of air and fuel, and generating a tremendous amount of heat.
Step 3: Combustion: When the spark plug ignites the fuel-air mixture, the mixture ignites and burns, causing a rapid expansion of the hot gases and the expulsion of the piston. This energy is used to generate power by pushing the piston down, which turns the crankshaft. This energy is then transmitted to the wheels via the transmission.
Step 4: Exhaust:During the exhaust stroke, the exhaust valve opens, and the piston moves up to push the hot gases out of the combustion chamber. The exhaust system then takes the hot gases away from the engine and discharges them into the atmosphere.
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What has increased the concentration of atmospheric carbon dioxide (CO2)?
Answer:
Carbon dioxide concentrations are rising mostly because of the fossil fuels that people are burning for energy.
if the same-sized force is made to act over a smaller area, the pressure is
When a same-sized force is applied over a smaller area, the pressure increases.
Pressure is defined as the force acting per unit area (P = F/A). Here, F represents the force and A represents the area. When the area (A) decreases, and the force (F) remains constant, the overall pressure (P) increases according to the formula.
This concept can be easily understood by imagining a person standing on the ground wearing regular shoes versus standing on the ground wearing high heels. In both cases, the person's weight (force) remains the same, but the area of contact with the ground is much smaller with high heels. As a result, the pressure exerted on the ground by high heels is much higher than that of regular shoes.
Understanding the relationship between force, area, and pressure is crucial in various applications, such as hydraulic systems, pneumatic systems, and even in our daily lives. Increasing pressure by reducing the area can enhance the efficiency of certain processes while decreasing pressure by increasing the area can help distribute force more evenly and reduce potential damage or stress on surfaces.
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Is there any difference in the way the electric field strength varies along the y-axis? Explain.
Yes, The electric field strength varies along the y-axis as the electric field intensity and electric potential gradient vary in different regions of the y-axis.
Explanation:
The electric field is a vector quantity that describes the strength and direction of the electric field surrounding a charged object. It is defined as the force per unit charge experienced by a small test charge placed in the electric field. In a uniform electric field, the electric field strength is constant and does not vary with the position in the field. However, in non-uniform electric fields, the electric field strength varies with position.The electric field strength is directly proportional to the electric potential gradient. In a uniform electric field, the electric potential gradient is constant and does not vary with position. However, in non-uniform electric fields, the electric potential gradient varies with position.In regions of the y-axis where the electric potential gradient is high, the electric field strength is high. Conversely, in regions of the y-axis where the electric potential gradient is low, the electric field strength is low. This means that the electric field strength varies along the y-axis in non-uniform electric fields.
So, the answer is Yes, there is a difference in the way the electric field strength varies along the y-axis.
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Two slits spaced 0. 0720 mm apart are 0. 800 m from a screen. Coherent light of wavelength λ passes through the two slits. In their interference pattern on the screen, the distance from the center of the central maximum to the first minimum is 3. 00 mm. The intensity at the peak of the central maximum is 0. 0700 W/m2. What is the intensity at point on the screen that is 2. 00 mm from the center of the central maximum? What is the intensity at point on the screen that is 1. 50 mm from the center of the central maximum?
The intensity at a point on the screen 2.00 mm from the center of the central maximum is approximately 0.034 W/m². The intensity at a point on the screen 1.50 mm from the center of the central maximum is approximately 0.024 W/m².
I = Imax cos² (πd sin θ / λ),
where Imax is the intensity at the center of the interference pattern, d is the distance between the two slits, θ is the angle between the line connecting the point on the screen to the center of the interference pattern and the line perpendicular to the screen, and λ is the wavelength of the light.
To find the angle θ, we can use the small angle approximation:
sin θ ≈ θ ≈ y/L,
where y is the distance from the center of the interference pattern to the point on the screen, and L is the distance between the slits and the screen.
We are given d = 0.0720 mm, λ = unknown, L = 0.800 m, Imax = 0.0700 W/m², and the distance from the center of the central maximum to the first minimum y = 3.00 mm.
Using the given distance y, we can find the value of sin θ:
y/L = sin θ,
3.00 mm / 0.800 m = sin θ,
sin θ = 0.00375.
Now we can solve for the wavelength λ:
Imax cos² (πd sin θ / λ) = I,
0.0700 W/m² cos² (π(0.0720 × 10⁻³ m)(0.00375) / λ) = I,
cos² (π(0.0720 × 10⁻³ m)(0.00375) / λ) = I / 0.0700 W/m²,
π(0.0720 × 10⁻³ m)(0.00375) / λ = ± cos⁻¹ (√(I / 0.0700 W/m²)),
λ = π(0.0720 × 10⁻³ m)(0.00375) / cos⁻¹√(I / 0.0700 W/m²)),
λ = 5.70 × 10⁻⁷ m (for the positive root).
Now we can find the intensities at the given distances from the center of the central maximum.
For y = 2.00 mm:
sin θ = y/L = 2.00 mm / 0.800 m = 0.00250,
I = Imax cos² (πd sin θ / λ)
I = 0.0700 W/m² cos² (π(0.0720 × 10⁻³m)(0.00250) / (5.70 × 10⁻⁷ m))² ≈ 0.034 W/m².
So the intensity at a point on the screen 2.00 mm from the center of the central maximum would be approximately 0.034 W/m².
For y = 1.50 mm:
sin θ = y/L = 1.50 mm / 0.800 m = 0.001875,
I = Imax cos² (πd sin θ / λ)
I= 0.0700 W/m² cos² (π(0.0720 × 10⁻³m)(0.001875) / (5.70 × 10⁻⁷ m))² ≈ 0.034 W/m².
I ≈ 0.024 W/m².
So the intensity at a point on the screen 1.50 mm from the center of the central maximum would be approximately 0.024 W/m².
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Which statement describes the way in which energy moves between a
system of reacting substances and the surroundings?
OA. The thermal energy of the system and its surroundings increases.
B. Molecular collisions create energy that is then released into the
surroundings.
C. The potential energy of the system and its surroundings
increases.
D. Molecular collisions transfer thermal energy between the system
and its surroundings.
The statement describes the way in which energy moves between a system of reacting substances is Molecular collisions transfer thermal energy between the system and its surroundings. Option D
what are Molecular collisions?In a chemical reaction, energy is either released or absorbed. This energy is transferred through molecular collisions. In other words, When molecules collide, they exchange energy.
If the reaction is exothermic, meanng it releases heat, the thermal energy is transferred from the system to the surroundings.
If the reaction is endothermic, what this means is that it absorbs heat, thermal energy is transferred from the surroundings to the system.
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Explain why using a ladder or plank will help to prevent damage to the
roof.
Answer:
it reduces pressure
Explanation:
use of ladder / plank makes the pressure applied to uniformly distributed to all part hence increase surface area
What is density? Write a formula by showing the relation of mass density and volume
Answer: below
Explanation: Density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume
Answer:
Density is defined as the amount of matter contained in unit volume of body
A snowball rolls off a barn roof that slopes downward at an angle of α= 44.0∘ . (See the figure below) The edge of the roof is H= 14.0 m above the ground, and the snowball has a speed of v = 4.00 m/s as it rolls off the roof. Ignore air resistance.
The horizontal distance traveled by the snowball is 4.11 m.
your question is not complete, it seems to be missing the following information;
how far does the ball travel horizontally ?
The given parameters;
angle of inclination, α = 44.0∘height of the roof, H = 14 mvelocity of the ball, v = 4 m/sThe time of flight of the snowball is calculated as;
\(h_y = v_0_yt + \frac{1}{2} gt^2\\\\14 = (4\times sin(44))t + 0.5\times 9.8t^2\\\\14 = 2.78t + 4.9t^2\\\\4.9t^2 +2.78t - 14 = 0\\\\solve \ the \ quadratic \ equation \ using \ formula \ method;\\\\a = 4.9, \ b = 2.78 ,\ c = -14\\\\t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-2.78 \ \ +/- \ \ \sqrt{(2.78)^2 - 4(4.9\times -14)} }{2\times 4.9}\\\\t = 1.43 \ s\)
The horizontal distance traveled by the snowball is calculated as;
\(X = v_0_x \times t\\\\X = (4 \times cos(44) ) \times 1.43\\\\X = 4.11 \ m\)
Thus, the horizontal distance traveled by the snowball is 4.11 m.
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What can occur when air rises in a low pressure system?
When air rises in a low-pressure system, it can lead to the formation of clouds and precipitation, such as rain or snow. The rising air also cools and condenses, releasing latent heat, which can further contribute to the development of the storm.
What happens in a low-pressure system?A low-pressure system is a weather pattern characterized by a region of lower atmospheric pressure compared to the surrounding areas. It is often associated with unsettled and stormy weather.
How are clouds formed?Clouds are formed when moist air rises and cools, causing water vapour to condense into tiny water droplets or ice crystals. This process occurs when the temperature of the air decreases, either because it is rising, or because it is mixing with cooler air.
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Daylon's family just bought a new puppy, and Daylon decided to take him for a walk. He put the puppy in a wagon and pulled the wagon along the sidewalk. From which of these reference points does the puppy appear to be moving? 1. Daylon 2. The wagon 3. The sidewalk 4. The puppy's collar
The puppy was not moving relative to Daylon, the wagon, or his collar.
He was moving relative to a point on the sidewalk.
Note that the puppy did NOT get his walk.
To find velocity, you need to know the total:
A.distance of the motion
b.distance, time and direction of the motion
C.time of the motion
d.distance and time of the motion
Answer:
distance and time of the motion
The temperature of an object is 15 degrees Celsius. What will be its temperature on the Fahrenheit scale? F= (C x 1.8) + 32.
Answer:
59F
Explanation:
Given parameters:
Temperature in °C = 15°C
Unknown:
Temperature in Fahrenheit scale = ?
Solution:
To solve this, we use the conversion equation below;
F = (C x 1.8) + 32
C is the temperature in celcius;
F = (15 x 1.8) + 32 = 59F
If a balloon is charged with static electricity and you rip small pieces of tissue paper. Will it stick to the balloon?
Answer:
Yes
Explanation:
Rubbing a balloon with wool cloth will create static electricity charges. If you place small pieces of tissue paper near the balloon in Picture 2, they would probably stick to the balloon.
What is specific heart What does it mean if the specific toat is high? Low? b. What is a calorimeter and what about yoer eup make if a closed system" C. What is the law of conservation of energy and bow was it applsed in your experiment? d. What is your calculated akerage speciffe beat of aluminum and hose does it compare to the literature value of 0.8973 g∘C ? Hoth of these values should be stated in the eext of your discussion. 5. What is your ealculated eyperizental percent cror for the alumieary? If your specific beat (c) valoe does not inatch exactly the literature valse, yoa need to discuss why your experiment did not yield the exact result you expocted. What data poiat that you measured might be a bet off and why? What art socne ermors you cen account for? f. What major assumption is made regarting the itinal temperafure of the metal rod? This would be good to mention when discussire ponsible sources of error. Do not simply atate "human error." Describe what types of haman crot 9. Don't forget 10 wne a coeclusion yuragnpb that fectates yoar reailt in a succinct way (you should re-state yoar specific beat of the metal rud). Ahso include a useful application of specific beat in chemistry and in lifs. There is no length requiremacnt for a discissice a heg as you thit all the above points. However. to do so, it usually takes at least it paye Gramamar and spelling count 1 won't tako off points for a minat mistake but if there are mege than 2.3 mistakes in a paragraph, it mems yoe did not prootread your work. Anotbet person (outside of our lab class) shoald be able fo read and undertand a bat you cid and the meaning of your renulfs: If you write your discussion 30 min beforeour class tame. you will not get a good grade. Please tak. the time to write, prootread, make cocrectiom, cte. The soal as to improve your writing skils! if yot need belo writing you can take your discossa in bo the teaming Center or to me duriag office bourto get it edited.
The answer to all the questions is discussed below.
(a)GoKJ is the unit of measurement for specific heat. A high score thus means that it takes more energy to raise (or lower) its temperature. A low number means that heating or cooling something doesn't use a lot of energy.
(b) Calorimeter, a tool for estimating a material's heat capacity and measuring the heat produced during a mechanical, electrical, or chemical reaction. bomb thermometer.
An illustration of a closed system is a calorimeter. It is a sealed container, which means that tests involving the energy transfer between the System and its surroundings are performed inside it. The exchange of energy but not matter is possible in a calorimeter.
(c) Since energy is transferred rather than created or destroyed, the law of conservation of energy is present all around us.
A white precipitate of barium sulphate will appear when the conical flask is tilted to combine the two solutions, indicating that the reaction has taken place.
(d) The specific heat of aluminum is 897 J/kg K. This value is almost 2.3 times the specific heat of copper. You can use this value to estimate the energy required to heat a 500 g of aluminum by 5 °C, i.e., Q = m x Cp x ΔT = 0.5 * 897* 5 = 2242.5 J.
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The correct question is: a. What is a specific heat What does it mean if the specific toat is high? Low? b. What is a calorimeter and what about your up make if a closed system" C. What is the law of conservation of energy and how was it applied in your experiment? d. What is your calculated average specific beat of aluminum and hose does it compare to the literature value of 0.8973 g
∘
C ? Hoth of these values should be stated in the text of your discussion. 5. What is your calculated experimental percent error for the luminary? If your specific beat (c) value does not match exactly the literature value, you need to discuss why your experiment did not yield the exact result you expected. What data point that you measured might be a bet off and why? What art some errors you can account for? f. What major assumption is made regarding the initial temperature of the metal rod? This would be good to mention when discussing possible sources of error. Do not simply state "human error." Describe what types of the human cross 9. Don't forget 10 wine a conclusion that pectates your reality in a clear way (you should re-state your specific beat of the metal rod). Also, include a useful application of specific beat in chemistry and in life. There is no length requirement for a discussion of a hedge as you think all the above points. However. to do so, it usually takes at least it pays Grammar and spelling count 1 won't take off points for a minute mistake but if there are more than 2.3 mistakes in a paragraph, it mems you did not proofread your work. Another person (outside of our lab class) should be able to read and understand a bat you cited and the meaning of your results: If you write your discussion 30 min before our class tame. you will not get a good grade. Please take. the time to write, proofread, make corrections, etc. The soal as to improve your writing skills! if you need belo writing you can take your discuss in to the teaming Center or to me during office hours to get it edited.