If two atoms are the same element, which statement can never be true?

1: they can have different number of protons.

2:they can have different number of electrons.

3:they can have different number of neutrons

Answer:

the more sun there is, the taller the plant

Explanation:

Answer:

Kp = 1.41 x 10⁻⁶

Explanation:

We have the chemical equation:

2 A(g) + 3 B(g)⇌ C(g)

In which A and B are the reactants and C is the product. We calculate first the change in the number of moles of gas (Δn or dn):

dn= (sum moles products - sum moles reactants)

   = (moles C - (moles A + moles B))

   = (1 - (2+3))

   = 1 - 5

   = -4

We have also the following data:

Kc = 63.2

T= 81∘C + 273 = 354 K

R = 0.082 L.atm/K.mol (it is a constant)

Thus, we introduce the data in the mathematical expression for the relation between Kp and Kc:

\(Kc = (RT)^{dn}\)= (0.082 L.atm/K.mol x 354 K)⁻⁴ = 1.41 x 10⁻⁶

Answer:

208.125g

Explanation:

Given parameters:

 Number of moles of HCl = 3.75moles

Unknown:

 Mass of CaCl₂ that will be produced = ?

Solution:

The reaction equation is given as:

  2HCl  + Ca(OH)₂   →   CaCl₂ + 2H₂O

Now, to find the mass of CaCl₂, we have to work from the known to the unknown.

The known specie here is the number of moles of HCl;

        2 mole of HCl will produce 1 mole of  CaCl₂

       3.75moles of HCl will produce \(\frac{3.75}{2}\)   = 1.875moles

The mass of  CaCl₂;

  Mass of  CaCl₂ = number of moles of  CaCl₂ x molar mass

Molar mass of  CaCl₂ = 40 + 2(35.5) = 111g/mol

  Mass of  CaCl₂ = 1.875 x 111 = 208.125g

According to the given statement The mass of the aluminium sample is 8.1 grams.

The amount of matter that makes up every object or body is the greatest way to understand mass. Everything that we can see has mass. Examples of objects with mass include a table, a chair, your bed, a football, a glass, and even air. Whether anything is light or heavy depends on its mass.

Aluminium sample's mass is equal to m.

Volume of the aluminium = V

Density of the aluminium = d = 2.7 g/mL

Initial level of water mark in cylinder = 10.5 mL

Final level of water after sample is immersed = 13.5 mL

Volume occupied by the sample = V = 13.5 mL - 10.5 mL = 3 mL

Density = mass/volume

Mass = density * volume = d * v

m =2.7g/mL * 3m/L

m = 8.1 g

The mass of the aluminium sample is 8.1 grams.

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Answer:

yes

Explanation:

because it will keep them entertained and will learn new things

Answer:

1. C) Hydrogen of water is separated from oxygen.

2. A) Carbon dioxide

3. D) Mechanical energy to chemical energy

4. B) Glucose

5. B) Respiring while swimming underwater

6. A) Oxygen

7. B) Photosynthesis depends on the carbon dioxide released during cellular respiration.

8. A) It is affected by social concerns.

9. D) Chlorophyll stores chemical energy needed for photosynthesis.

10. Cellular respiration is the process by which organisms use oxygen to break down food molecules to get chemical energy for cell functions.

Brainlist Pls!

1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

Answer:

1 K

2 P

3 P

4 P

5 K

6 K

7 K

8 P

9P

10 K

Answer:

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Due to the fact that electrons are delocalized in graphite, it is a good conductor of electricity. Carbon atoms in graphite form hexagonal layers and are in covalent bonds with three other carbon atoms. Due to this non-bond electron configuration, each carbon atom conducts electricity in the form of a delocalized electron.

From the solution that we have in the question;

The equilibrium constant, denoted as K, is a value that quantitatively represents the ratio of the concentrations of products to reactants at equilibrium in a chemical reaction.

It is a fundamental concept in chemical equilibrium.

The value of the equilibrium constant provides valuable information about the position of equilibrium and the relative concentrations of species involved in a chemical reaction.

Kc = [X] [Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\)

\(0.25(0.5 - x) = (0.1 + x)^2\)

\(0.125 - 0.25x =0.01 + 0.2x + x^2\\ x^2 + 0.45x - 0.115 = 0\)

x = 0.18 M

The equilibrium amount of X and Y=  0.28 M and the equilibrium concentration of XY = 0.32 M

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Based on the answer to the question that we have;

The ratio of the product to reactant concentrations in a chemical reaction at equilibrium is represented quantitatively by the equilibrium constant, abbreviated as K.

It is a cornerstone of the theory of chemical equilibrium.

A chemical reaction's equilibrium position and the relative concentrations of the species involved can both be learned from the equilibrium constant's value.

Kc = [X][Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\\0.25(0.5 - x) = (0.1 +x)^2\\0.125 - 0.25x = 0.01 +0.2x +x^2\\= 0.18 M\)

The equilibrium concentration of;

XY =0.5 - 0.18

=0.32 M

Then the equilibrium amount of

X and Y is

0.1 + 0.18= 0.28 M.

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The concentration of H₂SO₄ solution is equal to 0.0480 M.

A neutralization reaction is described as a chemical reaction where acid and base react to produce respective salt and water. When a strong acid reacts with a strong base then the salt can be neutral.

When H₂SO₄ (a strong acid) reacts with NaOH, the resulting salt is Na₂SO₃  and water.

H₂SO₄  +  2 NaOH   →   Na₂SO₄  +   2H₂O

Given, the concentration of NaOH = 0.146 M

The volume of the NaOH = 14.85 ml = 0.01485 L

The number of moles of NaOH, n = M × V = 0.146 × 0.01485 = 0.00216 M

The volume of the  H₂SO₄ = 22.55 ml = 0.02255 L

The number of moles of  H₂SO₄, n = 0.00216/2 = 0.00108 mol

The concentration of H₂SO₄ =0.00108/0.02255 = 0.0480 M

Therefore, the molarity of  H₂SO₄ is 0.0480 M.

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Answer: iodine is oxidised and Chlorine is reduced

Explanation: iodine is oxidised, in I2 oxidation number sim 0,

in HIO oxidation number is +I.

Chlorine is reduced, oxidation number changes from 0 to -I

Answer:

Oxidation number:

3*1+ oxidation number of J+2*-2= -1

Oxidation number of J = 0

A change in the size of the moon jellies' resource population can change the number of births in the moon jelly population because the big size of the resources can produce more births.

When there is more energy storage molecules present in the moon jellies, they can reproduce more, in more births. Fewer deaths would also lead to the jelly population increasing. The sea turtle population, and the moon jellies consumer population is also decreased.

There must be a change to the birth rate or the death rate in the moon jelly population. Within a population, organisms are born and dying continuously. If the number of births and deaths in a given time interval are equal, then the population size will remain stable.

So we can conclude that a large population of resources will lead to more births.

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The heat used to change the temperature of 30 grams of water from 45K to 50 K is equal to 627.6 J.

The specific heat capacity of a material can be defined as the heat required to raise the temperature by one degree Celcius in one unit of substance.

Whenever the heat energy is lost or supplied the temperature of the substance will be changed:

Q = mCΔT

Given, the mass of the water, m = 30 g = 0.030 kg

The change in the temperature = 50 - 45 = 5 K

ΔT = 5 K

The specific heat capacity of the water, C = 4184 J/Kg K

The heat required for the given change in temperatures can be calculated as:

Q = 0.03 × (4184) × 5

Q = 627.6 J

Therefore, the heat required is equal to 627.6 J.

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Answer:

Option B. pentan-1-ol

Explanation:

We'll begin by writing the name of the compound.

The name of the compound above is pentylpropanoate.

From the name of the compound and the structure, we can suggest the following equation:

CH3CH2COOH + HOCH2CH2CH2CH2CH3 —> CH3CH2COOCH2CH2CH2CH2CH3 + H2O

Thus,

Propanoic acid + pentan-1-ol —> pentylpropanoate + water.

Therefore, the alcohol used in the reaction is pentan-1-ol

When investigative officers get to a crime scene, they do not need to collect water samples.

A crime scene is a place where an offence has been committed. It is usually cordoned off to enable investigation of the crime and the collection of samples.

When investigative officers get to a crime scene, they do not need to collect water samples.

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Answer:A

Explanation:.

Answer:

22.25 °C

Explanation:

Determine the final temperature when a 25.0 g piece of iron at 85.0 °C is placed into 75.0 grams of water at 20.0 °C.

The volume of the tank is approximately 130.75 m³.

To solve this problem, we need to use the concept of air and water vapor mixture. The given data includes the mass of dry air and water vapor, temperature, and total pressure. We can calculate the specific humidity, relative humidity, and volume of the tank using the following steps:

(a) Specific humidity:

The specific humidity (ω) is defined as the ratio of the mass of water vapor (m_w) to the total mass of the air-water vapor mixture (m_t):

ω = m_w / m_t

Given that the mass of water vapor is 0.17 kg and the total mass of the mixture is 15 kg + 0.17 kg = 15.17 kg, we can calculate the specific humidity:

ω = 0.17 kg / 15.17 kg ≈ 0.0112

So, the specific humidity is approximately 0.0112.

(b) Relative humidity:

Relative humidity (RH) is the ratio of the partial pressure of water vapor (P_w) to the saturation vapor pressure of water (P_ws) at the given temperature, multiplied by 100:

RH = (P_w / P_ws) * 100

To find the relative humidity, we need to determine the saturation vapor pressure at 30°C. Using a vapor pressure table or equation, we can find that the saturation vapor pressure at 30°C is approximately 4.246 kPa.

Given that the total pressure is 100 kPa, the partial pressure of water vapor is 0.17 kg / 15.17 kg * 100 kPa = 1.119 kPa.

Now we can calculate the relative humidity:

RH = (1.119 kPa / 4.246 kPa) * 100 ≈ 26.34%

So, the relative humidity is approximately 26.34%.

(c) Volume of the tank:

To find the volume of the tank, we can use the ideal gas law equation:

PV = nRT

Where P is the total pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to calculate the number of moles of dry air and water vapor in the tank. The number of moles (n) can be obtained using the equation:

n = m / M

Where m is the mass and M is the molar mass.

The molar mass of dry air is approximately 28.97 g/mol, and the molar mass of water vapor is approximately 18.015 g/mol.

For dry air:

n_air = 15 kg / 0.02897 kg/mol ≈ 517.82 mol

For water vapor:

n_water = 0.17 kg / 0.018015 kg/mol ≈ 9.43 mol

Now we can calculate the volume using the ideal gas law:

V = (n_air + n_water) * R * T / P

Given that R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (30°C + 273.15 = 303.15 K), and P is the total pressure (100 kPa), we can calculate the volume:

V = (517.82 mol + 9.43 Mol) * 8.314 J/(mol·K) * 303.15 K / (100,000 Pa) ≈ 130.75 m³

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Answer:

mostly due to heat or any outside substance for example if u add radio waves to heat you can get plasma or if u melt ice u get water witch is a solid turning into liquid

1.1 mol Ne

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 6.5 × 10²³ atoms Ne

[Solve] moles Ne

Step 2: Identify Conversion

Avogadro's Number

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

1.07938 mol Ne ≈ 1.1 mol Ne

Answer:

1. Cu(s) 2. Cu(NO3)2 (aq) 3. Cu(OH)2 (s) 4. CuO (s) 5. CuSO4 (aq)  6. Cu(s)

Explanation:

Answer:

+2

Explanation:

Because the charge of the chloride ion is negative, that means that the charge of the magnesium ion must be positive since cations and anions go together, not cation and cation nor anion and anion. Using the "reverse criss-cross method", since the subscript of Mg is 1, that means that this is the lowest whole number ratio so we don't need to worry about simplifying. Therefore, since the charge of Cl is 2, the answer is +2.

As the class is of 1 hour and  and each student uses for 6 minutes so in 1 hour 10 students will use the balance.

A scale or balance is a device used to measure weight or mass. These are also known as mass scales, weight scales, mass balances, and weight balances.

The traditional scale consists of two plates or bowls suspended at equal distances from a fulcrum. One plate holds an object of unknown mass (or weight), while known masses are added to the other plate until static equilibrium is achieved and the plates level off, which happens when the masses on the two plates are equal.

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a. Balanced equation for the decomposition of sodium bicarbonate by heating is:

2 NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g)

b. To heat the mixture, the student can use a Bunsen burner or a hot plate in a fume hood to prevent the release of any harmful gases. The mixture should be heated until there is no more mass loss. To determine the mass loss, the student can weigh the vial and its contents before and after heating. The difference between the two weights will be the mass loss.

c. The student can know that all the sodium bicarbonate has been decomposed when there is no more mass loss. The heating should be continued until the mass of the vial and its contents remains constant.

d. The mass loss of 2.28 g is due to the decomposition of 1 mol of NaHCO3, which has a molar mass of 84 g/mol. Therefore, the original mixture contained 2.28/84 = 0.027 mol of NaHCO3. The mass of Na2CO3 in the mixture can be calculated as follows:

mass of Na2CO3 = mass of mixture - mass loss = 14.00 g - 2.28 g = 11.72 g

The molar mass of Na2CO3 is 106 g/mol, so the number of moles of Na2CO3 in the mixture is:

moles of Na2CO3 = mass of Na2CO3/molar mass of Na2CO3 = 11.72 g/106 g/mol = 0.111 mol

The percentage of Na2CO3 in the original mixture is:

% Na2CO3 = (moles of Na2CO3/total moles of carbonate) x 100% = (0.111/0.138) x 100% = 80.4%

e. To determine which is the limiting reactant, we need to compare the number of moles of NaHCO3 and Na2CO3 in the mixture. We know that the mixture contained 0.027 mol of NaHCO3 and 0.111 mol of Na2CO3. Since the balanced equation shows that 2 moles of NaHCO3 produce 1 mole of Na2CO3, the number of moles of Na2CO3 that can be produced from 0.027 mol of NaHCO3 is:

moles of Na2CO3 = 0.027 mol NaHCO3 x (1 mol Na2CO3/2 mol NaHCO3) = 0.0135 mol Na2CO3

Since the actual amount of Na2CO3 in the mixture is greater than 0.0135 mol, we can conclude that NaHCO3 is the limiting reactant, and Na2CO3 is in excess.

d.

Mass of NaHCO3 = 2.28 g / 84 g/mol = 0.027 mol NaHCO3

Mass of Na2CO3 = 14.00 g - 2.28 g = 11.72 g

Moles of Na2CO3 = 11.72 g / 106 g/mol = 0.111 mol Na2CO3

Total moles of carbonate = moles of NaHCO3 + moles of Na2CO3 = 0.027 mol + 0.111 mol = 0.138 mol

% Na2CO3 = (moles of Na2CO3 / total moles of carbonate) x 100% = (0.111 mol / 0.138 mol) x 100% = 80.4%

e.

Moles of Na2CO3 that can be produced from 0.027 mol of NaHCO3 = 0.027 mol NaHCO3 x (1 mol Na2CO3 / 2 mol NaHCO3) = 0.0135 mol Na2CO3

Since the actual amount of Na2CO3 in the mixture (0.111 mol) is greater than 0.0135 mol, NaHCO3 is the limiting reactant, and Na2CO3 is in excess.

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Answer:

The correct answer is C. None of the above.

Explanation:

To determine how long the black bear will run, the distance it will travel must first be determined. Thus, the proposed calculation must be solved.

1.95 x 10 ^ 4

1.95 x 10 x 10 x 10 x 10

19.5 x 10 x 10 x 10

195 x 10 x 10

1950 x 10

19500

Thus, the bear will run 19,500 miles, so, running at 35 mph, it will take about 557 hours to run that distance (19,500 / 35).

Answer: Its A nucleic acids

Explanation:

Nucleic acids, and DNA in particular, are key macromolecules for the continuity of life. DNA bears the hereditary information that's passed on from parents to children, providing instructions for how (and when) to make the many proteins needed to build and maintain functioning cells, tissues, and organisms.

Nucleic acids carry genetic information from parents to their children.

Nucleic acids are biopolymers, macromolecules, essential to all known forms of life.[1] They are composed of nucleotides, which are the monomers made of three components: a 5-carbon sugar, a phosphate group and a nitrogenous base. The two main classes of nucleic acids are deoxyribonucleic acid (DNA) and ribonucleic acid (RNA). If the sugar is ribose, the polymer is RNA; if the sugar is the ribose derivative deoxyribose, the polymer is DNA.

Nucleic acids are naturally occurring chemical compounds that serve as the primary information-carrying molecules in cells and make up the genetic material. Nucleic acids are found in abundance in all living things, where they create, encode, and then store information of every living cell of every life-form on Earth. In turn, they function to transmit and express that information inside and outside the cell nucleus to the interior operations of the cell and ultimately to the next generation of each living organism. The encoded information is contained and conveyed via the nucleic acid sequence, which provides the 'ladder-step' ordering of nucleotides within the molecules of RNA and DNA. They play an especially important role in directing protein synthesis.

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Answer:

double replacement

Explanation:

The reaction shown is a double replacement reaction.

It is also known as double decomposition or metathesis reaction.

In such a reaction, there is an actual exchange of partners to form new compounds.

One of the following is the driving force for such reaction:

Concerning the distribution of marine benthic biomass, the following statement or claims about primary production are accurate.

Primary productivity is indeed the process through which organisms transform inorganic elements into straightforward organic materials. Autotrophs, or primary producers, are in charge of this phenomenon. Typical primary examples of producers include coccolithophores, dinoflagellates, and diatoms.

Water in which production is to be assessed is sealed in sealed white as well as dark containers that are painted dark to prevent light from entering. Rating scale can be estimated by the quantity of oxygen utilized by a size of water in a defined amount of time.

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