If Thor throws his axe horizontally at a velocity of 50 m/s at and a height of 20 m, how long does it take before it hits the ground? (gravity is 9.8 m/s^2)

To prevent the motor speed from increasing until it fails mechanically, a load should always be connected to the motor.

A motor is designed to operate under a specific load. Without a load connected to the motor, it can spin freely and reach dangerously high speeds. This can lead to mechanical failures such as bearing damage or rotor imbalance, which can ultimately cause the motor to fail. By connecting a load to the motor, it creates a resistance that limits the speed and keeps it within a safe operating range.

The load acts as a counterforce to the motor's rotational motion, balancing the power output. It provides the necessary friction and resistance to control the motor speed. Without a load, the motor can experience a phenomenon called "overspeeding," where it exceeds its designed RPM (rotations per minute). This can result in excessive wear and tear, heat buildup, and potential damage to the motor components.

By always connecting a load to the motor, it ensures that the motor operates within its intended parameters and prevents it from reaching speeds that could lead to mechanical failure. The appropriate load for a motor depends on its design and application, and it should be chosen carefully to match the motor's specifications and requirements.

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Answer:

34.45m

Explanation:

Magnitude of a vector is equal to the square root of sum of squares of x & y vectors.

Magnitude = \(\sqrt({x^2} + {y^2})\)

= \(\sqrt({19.5^2} + {28.4^2})\)

=34.45m

Answer:

I know its not A or D so its B or C and the more logical answer would be B. gravity

Explanation:

Explanation:

F = ma

F = (60.0 kg) (250 m/s²)

F = 15,000 N

During a crash, a dummy with a mass of 60 kg hits an airbag, then the airbag will exert 15,000 N force on the dummy.

The rate of change in an object's velocity concerning time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.

Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.

There are several types of acceleration :

According to the question, the given values are :

Mass, m = 60 kg

Acceleration, a = 250 m/s²

F = ma

F = (60.0 kg) × (250 m/s²)

F = 15,000 N

Hence, the force exerted by the airbag will be 15,000 N.

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Answer:

'Wave' is a common term for a number of different ways in which energy is transferred: In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels.

The period of pendulum is still the same at 1.4 seconds.

We need to know about pendulum experiment to solve this problem. The pendulum is a simple experiment to calculate gravitational acceleration. The gravitational acceleration can be calculated by

g = 4π² . L / T²

where g is gravitational acceleration, L is the length of the string and T is the period.

From the question above, we know that:

L = 0.5 meters

m1 = 1 kg

θ = 12⁰

m2 = 2 . m1

T1 = 1.4 seconds

Find the period of pendulum

g = 4π² . L / T²

T² = 4π² . L / g

T = √(4π² . L / g)

The period of a pendulum does not depend on the mass of the object, hence the period is still the same at 1.4 seconds.

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The equivalent resistance of the circuit is 0.67 ohms. The current through the circuit is 7.46 amps.

1/Req = 1/R1 + 1/R2 + 1/R3 + ...

In this case, we have three resistors connected in parallel, so:

1/Req = 1/R1 + 1/R2 + 1/R3

1/Req = 1/2.00 + 1/2.00 + 1/2.00

1/Req = 1.5

Req = 0.67 ohms

the equivalent resistance of the circuit is 0.67 ohms.

I = V/R

In this case, the voltage is 5V and the resistance is 0.67 ohms, so:

I = 5/0.67

I = 7.46 amps

Resistance is the measure of an object's ability to impede the flow of electric current through it. It is measured in ohms (Ω). Resistance is determined by the physical properties of an object, such as its dimensions, material, and temperature. When electric current flows through a conductor, it encounters resistance that slows down its flow. This resistance is caused by the collisions between electrons and the atoms in the conductor. The greater the number of collisions, the higher the resistance.

Resistance can be affected by changes in the physical properties of the conductor, such as length, cross-sectional area, or temperature. A longer or narrower conductor will have higher resistance, while a wider conductor will have lower resistance. The resistance of most materials increases with temperature. Understanding resistance is important for designing and operating electrical circuits. By controlling the resistance of a circuit, engineers can ensure that the correct amount of current flows to power the devices connected to it.

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The telescope has better resolution when observing in violet light (λ = 400 nm).

The resolution of a telescope is determined by its ability to distinguish two closely spaced objects as separate entities. The formula used to calculate the resolution of a telescope is given by Rayleigh's criterion:

θ = 1.22 * (λ / D),

where θ is the angular resolution in radians, λ is the wavelength of light, and D is the diameter of the telescope's aperture.

For the given telescope with a 1-meter aperture, we can calculate the resolutions at two different wavelengths:

\(For λ = 1000 nm: \theta = 1.22 * (1000 nm / 1 m) = 1.22 * 10^(-6) radians.\)

\(For λ = 400 nm: \theta = 1.22 * (400 nm / 1 m) = 4.88 * 10^(-7) radians.\)

Comparing the two resolutions, we find that the telescope has a better resolution when observing in violet light (λ = 400 nm) than when observing in infrared light (λ = 1000 nm). The smaller the angular resolution, the better the telescope can distinguish fine details and separate closely spaced objects. In this case, the telescope can resolve smaller details when observing in violet light due to the shorter wavelength. Thus, the resolution is better in violet light.

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Answer:

there is no picture :o?

Explanation:

:oo

The energies at different locations are:-

First = PE = 75J and KE = 0

Second = PE = 50J and KE = 25 J

Third = KE = 50 J and PE = 25 J

Fourth = PE = 0 and KE = 75 J

Potential energy is the energy that is stored in any object or system as a result of its position or component arrangement.

The environment outside of the object or system, such as air or height, has no impact on it. In contrast, kinetic energy refers to the energy of moving particles within a system or an object.

The total energy is defined as the sum of the kinetic energy and the potential energy.

TE = PE + KE

Here the total energy is 75 J. The value of the energies at different locations will be calculated as:-

First position:-

TE = PE + KE

75J = PE + 0

PE = 75 J

Second position:-

TE = PE  + KE

75J = 50J + KE

KE = 75 - 50 = 25 J

Third position:-

TE = PE  + KE

75J = PE + 50

PE = 75 - 50 = 25 J

Fourth position:-

TE = PE  + KE

75J = 0  + KE

KE = 75 J

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Answer:

the north and south pole

Explanation:

this should be the correct answer

Comparing the pulses traveling through these three materials, we can see that the speed of the pulse can vary greatly depending on the medium. The coiled spring toy will slow down the pulse, the rope will have a moderate speed, and the metal rod will have a very fast speed due to its ability to conduct sound waves efficiently.

When a pulse is sent through a medium, it travels at a certain speed. However, the speed at which the pulse travels can differ depending on the type of medium it is traveling through.
If you pull on one end of a coiled spring toy, the pulse will not reach the other end instantaneously. This is because the pulse must travel through the coiled spring, which can cause the pulse to slow down or speed up depending on the tightness of the coils.
If you pull on a rope, the pulse will travel through the rope at a certain speed. The speed at which the pulse travels will depend on the material of the rope and the tension of the pull.
If you hit the end of a metal rod, the pulse will travel through the rod at a much faster speed than the previous examples. This is because metals are better conductors of sound waves than other materials.

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Answer:

\(559\).

Explanation:

Integrate \(a(t)\) with respect to time \(t\) to find an expression for velocity:

\(\begin{aligned} v(t) &= \int a(t)\, d t \\ &= \int (6\, t + 8)\, d t && (\text{power rule}) \\ &= 3\, t^{2} + 8\, t + C_{v} \end{aligned}\).

Note that since this integral is indefinite, the expression for \(v(t)\) includes a constant \(C_{v}\).

Find the value of \(C_{v}\) using the fact that \(v(0) = 2\). Specifically, substitute \(t = 0\) into the expression \(v(t) = 3\, t^{2} + 8\, t + C_{v}\) and solve for \(C_{v}\!\):

\(v(0) = 3\, (0)^{2} + 8\, (0) + C_{v} = C_{v}\).

\(v(0) = 2\).

\(C_{v} = 2\).

In other words, \(v(t) = 3\, t^{2} + 8\, t + 2\).

Similarly, integrate \(v(t)\) with respect to \(t\) to find an expression for position:

\(\begin{aligned} s(t) &= \int v(t)\, d t \\ &= \int (3\, t^{2} + 8\, t + 2)\, d t\\ &= t^{3} + 4\, t^{2} + 2\, t + C_{s} \end{aligned}\).

Similarly, find the value of constant \(C_{s}\) using the fact that \(s(0) = 6\):

\(s(0) = (0)^{3} + 4\, (0)^{2} + 2\, (0) + C_{s} = C_{s}\).

\(s(0) = 6\).

\(C_{s} = 6\).

In other words, \(s(t) = t^{3} + 4\, t^{2} + 2\, t + 6\). Substitute in \(t = 7\) and evaluate to find the position of the particle at that moment:

\(s(7) = 7^{3} + 4\, (7)^{2} + 2\, (7) + 6 = 559\).

The pοsitiοn of the particle at time t = 7 is 559 units.

Tο find the pοsitiοn at time t = 7, we need tο integrate the given acceleratiοn functiοn tο οbtain the velοcity functiοn and then integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn.

Given:

Acceleratiοn functiοn: a(t) = 6t + 8

Initial pοsitiοn: s(0) = 6

Initial velοcity: v(0) = 2

First, let's integrate the acceleratiοn functiοn tο οbtain the velοcity functiοn:

v(t) = ∫(a(t)) dt

= ∫(6t + 8) dt

= 3t^2 + 8t + C

Tο find the cοnstant οf integratiοn (C), we can use the initial velοcity v(0) = 2:

2 = 3(0)² + 8(0) + C

C = 2

Sο, the velοcity functiοn becοmes:

v(t) = 3t² + 8t + 2

Next, let's integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn:

s(t) = ∫(v(t)) dt

= ∫(3t² + 8t + 2) dt

= t³ + 4t² + 2t + C'

Tο find the cοnstant οf integratiοn (C'), we can use the initial pοsitiοn s(0) = 6:

6 = (0)³ + 4(0)² + 2(0) + C'

C' = 6

Sο, the pοsitiοn functiοn becοmes:

s(t) = t³ + 4t² + 2t + 6

Finally, we can find the pοsitiοn at time t = 7:

s(7) = (7)³+ 4(7)² + 2(7) + 6

= 343 + 196 + 14 + 6

= 559

Therefοre, the pοsitiοn at time t = 7 is 559 units.

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Answer:

6.5

Explanation:

Because 1.5+5=6.5

A spherical ball of lead has a diameter of 7. 0 cm. Therefore, the mass of the lead sphere is approximately 2036.37 grams. To find the mass of the lead sphere, one need to calculate its volume first using the formula for the volume of a sphere.

Volume = (4/3) × π × \(r^3\)

Given that the diameter of the sphere is 7.0 cm, one can find the radius (r) by dividing the diameter by 2:

Radius (r) = Diameter / 2 = 7.0 cm / 2 = 3.5 cm

Now one can substitute the radius value into the volume formula:

Volume = (4/3) ×π ×(3.5 cm\()^3\)

Volume ≈ 179.594 c\(m^3\)

Next, one can calculate the mass using the density of lead. The formula for mass is:

Mass = Density × Volume

Given that the density of lead is 11.34 g/c\(m^3\), one can substitute the values into the formula:

Mass = 11.34 g/c\(m^3\) × 179.594 c\(m^3\)

Mass ≈ 2036.367 g or approximately 2036.37 g

Therefore, the mass of the lead sphere is approximately 2036.37 grams.

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Answer:

Explanation: Correct on Edg 2020/2021 for my school.

Plug in the coordinates (1, 2, 3) into the expressions for E1, E2, and E3, and calculate the values of E1, E2, and E3. Then add them up to find E_net at P(1, 2, 3).

a. To find the electric field at an arbitrary point, we need to calculate the contribution from each point charge and then sum them up.

The electric field at a point due to a point charge is given by Coulomb's Law:

E = k * (q / r^2) * r_hat

where E is the electric field vector, k is the electrostatic constant (k = 9 × 10^9 Nm^2/C^2), q is the charge of the point charge, r is the distance from the point charge to the point of interest, and r_hat is the unit vector in the direction from the point charge to the point of interest.

Let's calculate the electric field due to each point charge and sum them up:

For q1 at P1(7, 3, 5):
r1 = sqrt((x - 7)^2 + (y - 3)^2 + (z - 5)^2)
r1_hat = ((x - 7) / r1, (y - 3) / r1, (z - 5) / r1)
E1 = k * (q1 / r1^2) * r1_hat

Similarly, for q2 at P2(12, 4, 3):
r2 = sqrt((x - 12)^2 + (y - 4)^2 + (z - 3)^2)
r2_hat = ((x - 12) / r2, (y - 4) / r2, (z - 3) / r2)
E2 = k * (q2 / r2^2) * r2_hat

And for q3 at P3(6, -3, 2):
r3 = sqrt((x - 6)^2 + (y + 3)^2 + (z - 2)^2)
r3_hat = ((x - 6) / r3, (y + 3) / r3, (z - 2) / r3)
E3 = k * (q3 / r3^2) * r3_hat

The net electric field, E_net, is the sum of E1, E2, and E3:
E_net = E1 + E2 + E3

b. To find the electric field at P(1, 2, 3), substitute the values of x, y, and z into the expressions for E_net that we derived in part a.:

E_net = E1 + E2 + E3

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Answer:

-1.24 m/s

Explanation:

Total momentum before collision = total momentum after collision

Total momentum before collision = (mass of full back * velocity of fullback) + (mass of lineman * velocity of line man).

Mass of full back = 112 kg, mass of line bag = 120 kg, velocity of full back  6 m/s (east), velocity of line back = -8 m/s (west). Hence:

Total momentum before collision = (112 * 6) + (120 * -8) = 672 - 960 = -288 kgm/s

The total momentum after collision = (mass of full back + mass of line back) * velocity after collision.

Let velocity after collision be v, hence:

The total momentum after collision = (112 + 120)v = 232v

Total momentum before collision = total momentum after collision

-288 = 232v

v = -288 / 232

v = -1.24 m/s

Therefore after collision, the two players would move at a velocity 1.24 m/s west (the same direction as the lineman).

Answer:

A

Explanation:

KE = 1/2 mv^2

=1/2(30kg)( 3.4 m/s)^2

=173.4 joules

=1.7×10^2 joules

Answer:

A kangaroo hops 60 m to the east in 5 s. What is the kangaroo's average velocity? ... The kangaroo stops at a lake for a drink of water and then starts hopping again to the south. Each second, the kangaroo's velocity increases 2.5 m/s.

To determine how long (in seconds) it will take the ball to rise to its maximum height, we need to use the formula for vertical motion with constant acceleration.

The formula is given as follows:h = v0t + 1/2at²`Where `h` is the height, `v0` is the initial velocity, `a` is the acceleration, and `t` is time. Since the ball is thrown vertically upward, we take the upward direction as positive. When the ball reaches the maximum height, its final velocity `v` is zero. Therefore, we can use the following equation to find the time it takes to reach the maximum height:       `v = v0 + at`    When the ball reaches the maximum height, the velocity will become zero. 0 = 96 - 32t  => t = 3s Hence, it will take the ball 3 seconds to reach its maximum height.  b) To determine the time after which the velocity of the ball is one-half the initial velocity, we need to use the following equation:             `v = v0 + at`         Initially, the velocity `v0` of the ball is 96 feet per second. We want to find the time `t` at which the velocity of the ball is one-half the initial velocity.

Hence, `v = 1/2(96) = 48`. We now substitute these values in the equation above: 48 = 96 - 32t => 32t = 96 - 48 => 32t = 48 => t = 1.5s  Therefore, after 1.5 seconds, the velocity of the ball is half the initial velocity. c) We can determine the height of the ball when the velocity is half the initial velocity using the formula for vertical motion with constant acceleration, i.e.          `h = v0t + 1/2at²`We have already determined the time at which the velocity of the ball is half the initial velocity as 1.5 seconds. Therefore, we substitute the values into the formula above to obtain the height of the ball: h = 96(1.5) - 1/2(32)(1.5)² => h = 144 - 18 => h = 126 feet.  Hence, the height of the ball when the velocity is half the initial velocity is 126 feet. Answer: 3s, 126 ft, 1.5s, 126 ft.

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To determine the number of liters of gasoline that is needed to travel 76.9 kilometers with a car having a mileage of 46 miles per gallon of gasoline, the following steps should be followed:

1. Convert the distance of 76.9 kilometers to miles.

1 kilometer is approximately equal to 0.621371 miles

Therefore, 76.9 kilometers = (76.9) × (0.621371) miles = 47.822999 miles (approx)

2. Determine the number of gallons required to travel 47.822999 miles if the car's mileage is 46 miles per gallon of gasoline.

Using the given mileage, one gallon of gasoline will be used to travel 46 miles.

Thus, the number of gallons required to travel 47.822999 miles is calculated as follows:

Number of gallons = (Distance to be covered) / (Mileage) = (47.822999 miles) / (46 miles per gallon) = 1.03943 gallons

3. Finally, convert the number of gallons to liters, where one gallon is approximately equal to 3.78541 liters.

Number of liters required = (Number of gallons) × (3.78541 liters per gallon) = (1.03943 gallons) × (3.78541 liters per gallon) = 3.93703834363 liters (approx)

Therefore, it requires approximately 3.937 liters of gasoline to travel 76.9 kilometers.

The car's mileage is 46 miles per gallon of gasoline. Thus, to determine the amount of liters of gasoline that is needed to travel 76.9 kilometers, the distance should be converted from kilometers to miles since the given mileage is in miles per gallon of gasoline.

The number of gallons required to travel 47.822999 miles is calculated by dividing the distance by the mileage. Finally, the number of gallons is converted to liters since the final answer is required in liters.

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The average acceleration of the helicopter, given that it changes its velocity from 22.0 m/s to 10.0 m/s is –1.5 m/s²

We understood that acceleration is defined as the change in velocity with time i.e

a = (v – u) / t

With the above formula, we can determine the average acceleration of the helicopter. Details below

The following data were obtained from the question:

a = (10 – 22) / 8

a = –12 / 8

a = –1.5 m/s²

Thus, we can conclude that the average acceleration is –1.5 m/s²

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Answer:

Pb =- Lead    No.  82   Wt 206   N = 206 - 82 = 124   Rat = 124/82 = 1.5`1

U = Uranium No. 92    Wt 238   N = 238 - 92 = 146    Rat = 146/92 = 1.59

3:2 = 1.50        Pb is closer to 3:2

Explanation:

work done is equals to force into displacement in the direction of force

Ans: D

Answer:

Hi there!

There are many possible answers!

My best guesses are:

1) Knowing how they work will prevent injury! For example, knowing that the gears twist will stop you from putting your finger in it!

2) Allowing you to use it! Knowing how to line up the edge of the can with the tool will let you use it properly!

Hope this helps

Contacting the tractor-trailer truck's driver who was operating it when the accident occurred.

When responding to any incident, first responders must be on the lookout for dangerous chemicals. The dispatcher may give details like odd indications and symptoms (such a strong stench or itchy eyes) or the address may hint that the call may entail a chemical release. When unpleasant odors, gasoline, or corrosive liquid spills are present, it may be easy to see that hazardous items are present. When dealing with odorless yet toxic and/or combustible vapors and liquids, radioactive materials, or other circumstances, the dangerous character of the chemical(s) may not always be obvious. It is safe to presume that the cargo is dangerous if a vehicle has a diamond-shaped placard or an orange-numbered panel on the side or back.

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