If this regular decagon is rotated counterclockwise by 3 times the smallest angle of rotation, which vertex will be in the top position?.

Answer:

a = 35

Step-by-step explanation:

\(a^2+b^2=c^2\\a^2+12^2=37^2\\a^2+144=1369\\a^2=1225\\a=35\)

Answer:

A, B and E

Step-by-step explanation:

Answer:

dteps

Step-by-step explanation:

answer

Answer:

Try 300

Step-by-step explanation:

Because one full order would be 20 dollars and 20 times 15 equals 300

Answer:

your answer is option C $188

Answer:

I tried A.

Step-by-step explanation:

It's all like a fraction & multiplication type answer im if wrong correct me!

Answer:

i feel like it would be B

Step-by-step explanation:

Hopefully this helps!!!

Answer:

- 43t - 22s - 3

Step-by-step explanation:

(–45t + 53s) + (–3 – 75s + 2t)

Opening the brackets

-45t + 53s -3 - 75s + 2t

Collecting like terms

-45t + 2t + 53s - 75s -3

Simplify the expression

-43t -22s - 3

The statement "f(x) <= g(x) for all x > 0" does not necessarily imply that f(x) is always less than or equal to g(x) for all x > 0. This statement is false.

To demonstrate this, consider the following counterexample:

Let's assume f(x) = x and g(x) = x^2. Both f(x) and g(x) are continuous functions for all x > 0.

Now, if we examine the interval (0, 1), for any value of x within this interval, f(x) = x will always be less than g(x) = x^2. However, if we consider values of x greater than 1, f(x) = x will become greater than g(x) = x^2.

In this counterexample, we have f(x) <= g(x) for all x > 0 within the interval (0, 1), but the inequality is reversed for x > 1. Therefore, the statement "f(x) <= g(x) for all x > 0" is false.

It's important to note that the validity of the statement depends on the specific functions f(x) and g(x). There may be cases where f(x) <= g(x) holds true for all x > 0, but it cannot be generalized without further information about the functions.

In general, comparing the behavior of two continuous functions requires a more comprehensive analysis, taking into account the specific properties and characteristics of the functions involved.

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Answer:

144 days

Step-by-step explanation:

160 · 0.9

The density of tulips for the area of the bed is approximately 10.1667 tulips per square meter.

The area of the square flower bed can be found by taking the square of its side length:

Area = side^2

Area = 6^2

Area = 36 square meters

The density of tulips is the number of tulips per unit area. In this case, the unit area is 1 square meter.

So, the density of tulips = Total number of tulips / Area of the bed

Density = 366/36

Density = 10.1667 tulips per square meter (approx)

Therefore, the density of tulips for the area of the bed is approximately 10.1667 tulips per square meter.

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a. The greatest possible distance from  Austin to san Antonio is 335.77 mi, b. the Least possible distance to Austin to san Antonio is 120.03 mi.

Distance refers to the physical length or space between two points or objects. It is an important concept in mathematics, physics, and everyday life. Distance can be measured in various units such as meters, feet, kilometers, miles, or light-years, depending on the context and scale of the measurement.

In mathematics, distance is often measured using the Euclidean distance formula, which calculates the distance between two points in a plane or in three-dimensional space. The formula is given by:

d = √((x2 - x1)² + (y2 - y1)²)

where d is the distance between the two points, (x1, y1) and (x2, y2).

In physics, distance is often used to describe the separation between two objects or particles. The distance between two objects can affect the strength of gravitational or electromagnetic forces between them. Distance is also an important concept in special relativity, where it is affected by the relative motion of observers and the distortion of spacetime.

a. Greatest possible distance from  Austin to san Antonio= Distance from Austin →Houston → san Antonio.

Austin - Houston = 146.43 mi

Houston - San Antonio = 189.34 mi

Total  distance= 146.43+ 189.34= 335.77 mi

b. Least possible distance to Austin to San Antonio = the shortest distance = x

By Pythagoras theorem

(189.34)² = (146.43)²+ x²

x² = (189.34)²- (146.43)²

x² = 35849.63- 21441.744

x² = 14407.89

x =√14407.89

x = 120.03

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The complete question is:

Answer: it’s c.) y= 5/4x +10

Step-by-step explanation:i took the quiz:)

Answer:

its c

Step-by-step explanation:

i just took the quiz

Answer:

Step-by-step explanation:

P=8/13≈0.62

The expression ((t − 9) · (t² − 9) · (t³ − 9) · (t⁴ − 9) · (t⁵ − 9) · (t⁶ − 9) · (t⁷ − 9) can be written in terms of product notation as Π⁷k=1 \((t^k - 9)\).

As per the question, we can write the expression as:

(t − 9) · (t² − 9) · (t³ − 9) · (t⁴ − 9) · (t⁵ − 9) · (t⁶ − 9) · (t⁷ − 9)

Using product notation, we can write this as:

Π⁷k =1 \((t^k - 9)\)

where Π represents the product of terms, k is the index of the product, and the subscript 7 indicates that the product runs from k = 1 to k = 7.

Therefore, the expression ((t − 9) · (t² − 9) · (t³ − 9) · (t⁴ − 9) · (t⁵ − 9) · (t⁶ − 9) · (t⁷ − 9) can be written in terms of product notation as Π⁷k=1 \((t^k - 9)\).

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Answer:

9.3 ft

Step-by-step explanation:

Answer:

The answer is B.

Using the information provided in the table, The total holding cost is  $547.50, the total setup cost is $600 and the total cost is  $1,147.50.

To develop a POQ (Periodic Order Quantity) solution use a lot-for-lot solution, which means that we will order exactly what we need for each period.

The missing values can be found on the attached table.

From the table, the total holding cost which is the sum of the holding costs for all periods is $547.50 while the total setup cost which is the sum of the setup costs for all periods is $600.

Therefore, the total cost is the sum of the holding cost and the setup cost and it is calculated as $1,147.50.

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Answer:

Step-by-step explanation:

42 + 8 = R

50 = R

Reece is 50 inches tall

OR

R - 8 = 42

r = 50

Answer:

The answer is 50 inches for solution

Step-by-step explanation:

for equation it would be 42+8=50

Answer:

Step-by-step explanation:

Since the side lengths are proportional, the ratio of the width to length in the old phone will be equal to the ratio of the width to length in the new phone. That is:

(width of old phone) / (length of old phone) = (width of new phone) / (length of new phone)

We know the length of the old phone is 1.41.4 inches, and the width is 2.82.8 inches, so we can use that information to solve for the width of the new phone:

(2.82.8 inches) / (1.41.4 inches) = (width of new phone) / (1.611.61 inches)

Cross multiplying, we get:

(width of new phone) = (2.82.8 inches) * (1.611.61 inches) / (1.41.4 inches)

Using a calculator, we can find that the width of the new phone is approximately 3.23.2 inches.

The interquartile range of the number of jumps of the 10 students during the competition is 38.

The interquartile range is the difference between the third quartile and the first quartile. The interquartile range is used to determine the variation of a data set.

Th first step is to determine the median of the first half of the dataset. The median of the first half is the first quartile.

First half of the data set: 30, 36, 38, 45, 57

Median = first quartile =  38

The next step is to determine the median of the second half of the dataset. The median of the second half is the third quartile.

Second half of the data set: 60, 77, 86, 88, 88

Median : third quartile =  86

Interquartile range = third quartile - first quartile

86 - 38 = 48

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Answer:

4

Step-by-step explanation:

√64 = 8

√4 = 2

8/2 = 4

Answer:4

Step-by-step explanation:

\(\sqrt{64\) = 8

\(\sqrt{4\)  = 2

8÷2=4

The number of spanning trees of a connected graph can be proven to be the product of the number of spanning trees of each of its blocks.

Here are the steps-

1. Consider a connected graph G with blocks B1, B2, ..., Bk. Each block is a maximal connected subgraph with no cut-vertex.

2. The number of spanning trees of G can be denoted as T(G), and the number of spanning trees of each block Bi can be denoted as T(Bi).

3. To prove the given statement, we need to show that\(T(G) = T(B1) * T(B2) * ... * T(Bk).\)

4. We can start by considering a single block B1. Since B1 is a maximal connected subgraph with no cut-vertex, it is a connected graph on its own.

5. The number of spanning trees of B1, T(B1), can be calculated using any method such as Kirchhoff's theorem or counting the number of spanning trees directly.

6. Now, consider the original graph G. We can remove block B1 from G, which leaves us with a graph G' that consists of the remaining blocks B2, B3, ..., Bk.

7. G' is still a connected graph, but it may have cut-vertices. However, the removal of B1 does not affect the connectivity between the other blocks, as each block is a maximal connected subgraph.

8. The number of spanning trees of G', denoted as T(G'), can be calculated using the same method as step 5.

9. Since G' is the remaining part of G after removing B1, the number of spanning trees of G can be expressed as T(G) = T(B1) * T(G').

10. We can repeat this process for the remaining blocks B2, B3, ..., Bk. For each block Bi, we remove it from G and calculate the number of spanning trees of the remaining graph.

11. By repeating steps 6-10 for all blocks, we can express the number of spanning trees of G as-

\(T(G) = T(B1) * T(G')\)

\(= T(B1) * T(B2) * T(G'')\)

= ...

\(= T(B1) * T(B2) * ... * T(Bk).\)

12. Therefore, we have proved that the number of spanning trees of a connected graph G is the product of the number of spanning trees of each of its blocks.

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Based on the given information, we know that a new hair cream was tested on a random sample of people who were either bald or currently losing their hair.

The results of the test showed that a certain percentage of people either started growing back hair or stopped losing their hair, but there was a margin of error of which means that the results could vary by that amount. Unfortunately, we do not have the specific percentage of people who saw an improvement in their hair growth, but we do know that the margin of error is . This means that if the test were to be repeated with another sample of people, the results could vary by that amount in either direction. Therefore, we cannot give an exact number of people who are expected to see an improvement in their baldness if the new hair cream is administered to people. However, we can estimate that between [dropdown1] and [dropdown2] people are predicted to see an improvement in their hair growth based on the results of the test and the margin of error.

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Answer:

drop down 1: 2226

drop down 2: 3241

Step-by-step explanation:

The area of the field is 10,765.44 square meters.

Given that:

Diameter, d = 72 m

Width, W = 72 m

Length, L = 93 m

The area of a two - dimensional figure is the area that its perimeter encloses. The quantity of unit squares that occupy a closed figure's surface is its region.

The area of the field is calculated as,

A = (π/4)d² + W·L

A = (3.14 / 4) x 72² + 72 x 93

A = 4,069.44 + 6,696

A = 10,765.44 square meters

The area of the field is 10,765.44 square meters.

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Answer:

The number of

Single scoop cones = s = 9

Double scoop cones = d = 6

Step-by-step explanation :

Let t he number of

Single scoop cones = s

Double scoop cones = d

A single-scoop cone was $3 and a double-scoop cone was $5. The coach bought 15 cones and paid $57.

The system of equation

= s + d = 15.. Equation 1

s = 15 - d

3s + 5d = 57.... Equation 2

We substitute 15 - d for s

3(15 - d) + 5d = 57

45 - 3d + 5d = 57

Collect like terms

- 3d + 5d = 57 - 45

2d = 12

d = 12/2

d = 6

Solving for s

s = 15 - d

s = 15 - 6

s = 9

Therefore,

The number of

Single scoop cones = s = 9

Double scoop cones = d = 6

The two column proof is completed as follows

Statement                                     Reason

1  DE bisects /BDC                       Given

DE bisects angle BEC                Given

2. angle BDE ≅ angle CDE         An angle bisector divides an angle into

                                                     two  congruent angles                                

3.  angle BED ≅ angle CED        An angle bisector divides an angle into                                                        

                                                     two  congruent angles                      

4. line DE ≅ line DE                    Reflexive Property

5. Δ BDE ≅ Δ CDE                     ASA

6. line BE  ≅ line CE                   Corresponding Parts of Congruent                  

                                                   Triangles are Congruent (CPCTC)

7. line AE ≅ line AE                   Reflexive Property

8. Δ AEB ≅ Δ AEC                     SAS

9. ∠ ABE ≅ ∠ ACE                     Corresponding Parts of Congruent

                                                   Triangles are Congruent (CPCTC)

In geometry, ASA stands for "angle-side-angle" and refers to a method of proving that two triangles are congruent.

To prove that two triangles are congruent using the ASA postulate, you need to show that:

In the problem the included side is line DE

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Answer:

Step-by-step explanation:

I got 22 my friend hope i helped.

Answer:

$18

Step-by-step explanation:

50% of 40 is 20, so 40-20=20

10% of 20 is 2, so 20-2=18

total price=$18

Answer:

How do you write a perpendicular equation?

Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6. Rearranged, it is –x/2 + y = 6.

Step-by-step explanation:

from google can I have brainliest

To obtain the sampling distribution (likelihood) and the posterior distribution for this scenario, we can use Bayesian inference.

The sampling distribution (likelihood) can be represented as:

p(y|u,02) = (1/sqrt(2*pi*02)^n) * exp(-(1/(2*02)) * sum((yi-u)^2))

where y is the observed data, u is the mean of the normal distribution, and 02 is the variance of the normal distribution.

The non-informative prior for 02 can be represented as:

p(02) « 1/02

Using Bayes' theorem, we can obtain the posterior distribution:

p(u,02|y) = p(y|u,02) * p(02) / p(y)

where p(y) is the marginal likelihood. To simplify the calculation, we can integrate out u from the joint distribution:

p(02|y) = (p(y|02) * p(02)) / p(y)

where p(y|02) is the marginal likelihood for 02:

p(y|02) = (1/sqrt(2*pi*02)^n) * exp(-(n-1)/2)

We can then obtain the posterior distribution for 02:

p(02|y) « 1/02 * exp(-(n-1)/2)

This is a gamma distribution with shape parameter (n-1)/2 and scale parameter 1/2. Therefore, the posterior distribution for 02 is:

02|y ~ Gamma((n-1)/2, 1/2)

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