The measure of the missing length "u" is 45 miles.
To find the measure of the missing length "u" in the similar shapes, we can set up a proportion based on the corresponding sides of the shapes. Let's denote the given lengths as follows:
20 mi corresponds to 25 mi,
36 mi corresponds to u.
The proportion can be set up as:
20 mi / 25 mi = 36 mi / u
To find the value of "u," we can cross-multiply and solve for "u":
20 mi * u = 25 mi * 36 mi
u = (25 mi * 36 mi) / 20 mi
Simplifying:
u = (25 * 36) / 20 mi
u = 900 / 20 mi
u = 45 mi
Therefore, the measure of the missing length "u" is 45 miles.
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What is the area of a sector with a central angle of 131° and a
radius of 7.2 ft?
Use 3.14 for TT and round your final answer to the nearest hundredth.
Enter your answer as a decimal in the box.
Rounding this to the nearest hundredth, the area of the sector is approximately 28.88 f\(t^2\).
To find the area of a sector, we can use the formula:
Area = (θ/360) × π × \(r^2\)
where θ is the central angle in degrees, π is approximately 3.14, and r is the radius.
Given a central angle of 131° and a radius of 7.2 ft, we can plug in these values into the formula to find the area:
Area = (131/360) × 3.14 × (7.2\()^2\)
Calculating this expression:
Area = (0.3639) × 3.14 × (7.2\()^2\)
Area ≈ 28.879 f\(t^2\)
Rounding this to the nearest hundredth, the area of the sector is approximately 28.88 f\(t^2\).
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2. Solve:
a. -32 + 17 =
b.86 + (-27) =
c. -12 + (-37) =
d. -1/6 + 5/6 =
Answer:
a. -32 + 17 = -15
b.86 + (-27) = 59
c. -12 + (-37) = -49
d. -1/6 + 5/6 = 2/3
The balance in a company's Cash account on August 31 was $18,800 before the bank reconciliation was prepared. After examining the August bank statement and items included with it, the company's accountant found:
After examining the August bank statement and associated items, the company's accountant discovered discrepancies that affected the balance in the Cash account. The initial balance was $18,800 before the bank reconciliation was conducted.
Bank reconciliations are essential to ensure the accuracy of a company's financial records. In this case, the accountant found variances between the company's records and the bank statement. These variances could be classified into two categories: outstanding checks and deposits in transit
Outstanding checks are checks that have been issued by the company but have not yet been presented to the bank for payment. These checks reduce the company Cash account balance since they have not been deducted from it. The accountant would need to identify the outstanding checks and subtract their total amount from the initial balance.
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please help before tomorrow
write an equation of the line that passes through the given point and is perpendicular to the given line
(0,3), y = -5x + 2
Answer:
y = 1/5x + 3
Step-by-step explanation:
start by finding the opposite-sign reciprocal of the slope, which is 1/5 in this case. then, find the y-intercept, which is 3 in this case because of the point it gave us.
11. What is the sign of the product of any odd number of
negative integers? Explain your reasoning.
Explanation:
The sign of the product of any odd number of negative integers is positive because when two minuses are multiplied with each other, it will result in a positive number.
For example:
-3 x -5=> -1 x -1 x (3 x 5)=> 1 x (3 x 5)=> 15 (Which is positive)Hoped this helped!
The enrollment at high school R has been increasing by 20 students per year. Currently high school R has 200 students attending. High School T currently has 400 students, but it's enrollment is decreasing in size by an average of 30 students per year. If the two schools continue their current enrollment trends over the next few years, how many years will it take the schools to have the same enrollment?
The number of years it will take the schools to have the same enrollment is 4 years.
We are given that;
The enrollment at high school R has been increasing by 20 students per year.
Currently high school R has 200 students attending.
High school T currently has 400 students, but it’s enrollment is decreasing in size by an average of 30 students per year.
Let x be the number of years from now, and y be the enrollment of the schools. Then we have:
y=200+20x
for high school R, and
y=400−30x
for high school T. To find when the schools have the same enrollment, we set the two equations equal to each other and solve for x:
200+20x=400−30x
Adding 30x to both sides, we get:
50x=200
Dividing both sides by 50, we get:
x=4
At that time, they will both have y = 200 + 20(4) = 280 students.
Therefore, by the linear equation the answer will be 4 years.
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y’all please help me with my 8th grade math homework
Answer:
the answer to the riddle is a rectangle
Step-by-step explanation:
Answer:
Your answer is A rectangle and that should help you figure out which answer is which...
Step-by-step explanation:
a candy bar box is in the shape of a triangular prism. the volume of the box is 1,200 cubic centimeters. a triangular prism is shown with base of triangle labeled 10 cm, sides of the triangles labeled 13 cm, and length of the box equal to 20 cm. part a: what is the height of the base? show your work.
Height of the base = 10cm
The definition of triangular volume?
The formula Area = Half of Base by Altitude is used to determine the area of a triangle. A = 0.5 X b X a . The formula for determining a triangular prism's volume is V = 0.5 X b X an X h.Given a candy box is in the shape of triangular prism
Volume of the box = 1200 cm³
Base of the triangle = 10cm
Side of the triangle = 13cm
Length of the box = 20 cm
Let the height of the base = h cm
Volume of the triangular prism = 1/2×(Base of triangle)×(Height of triangle)×(length of prism)
1200 = (1/2)×10×h×20
1200 = 100h
h = 1200/100
h = 12 cm
So, height of the triangle = 10cm
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I'll give brainiest
A trapezoid is a parallelogram true a false
pls explain why
Answer:
True
Explanation:
Niko and Carlos are studying parallelograms and trapezoids. They agree that a parallelogram is a quadrilateral with two pairs of parallel sides. ... A trapezoid has one pair of parallel sides and a parallelogram has two pairs of parallel sides. So a parallelogram is also a trapezoid.
Answer:
Trapezoids have only one pair of parallel sides; parallelograms have two pairs of parallel sides. so no
Step-by-step explanation:
A bowling ball weighs 15 pounds on earth and weighs 4 pounds on the planet saturn. you could determine a 100–pound earthling's weight on saturn using the proportion: a. startfraction 15 over 4 endfraction = startfraction b over 100 endfraction c. startfraction 4 over 15 endfraction = startfraction 100 over b endfraction b. startfraction 15 over 4 endfraction = 100 over b endfraction d. either a or c
100–pound earthling's weight on Saturn using the proportion is (B)
15/4 = 100/x.
What is proportion?The size, number, or quantity of one object or group of things in comparison to another thing or group of things In our class, the ratio of guys to girls is two to one (2:1).To find the 100–pound earthling's weight on Saturn using the proportion:
Weight of ball on Earth = 15 poundsWeight of ball on Saturn= 4 poundsLet 100 pounds of earthling weight on Saturn be x pounds.Thus, the proportion is 15:4 = 100:x15/4 = 100/xTherefore, 100–a pound earthling's weight on Saturn using the proportion is (B) 15/4 = 100/x.
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The correct question is given below:
A bowling ball weighs 15 pounds on earth and weighs 4 pounds on the planet Saturn. you could determine a 100–pound earthling's weight on Saturn using the proportion:
a. start fraction 15 over 4 end fraction = start fraction x over 100 end fraction
b. startfraction 15 over 4 endfraction = 100 over x endfraction
c. startfraction 4 over 15 endfraction = startfraction 100 over x endfraction
d. either a or c
Simplify to create an equivalent expression. 8-4(-x+5)
Answer:= -12+4x
Step-by-step explanation:
Distribute -4 through the parentheses
8+4x=20
Calculate the difference
-12+4x
3 3/5 times (-8 1/3)
Answer:
-30
Step-by-step explanation:
3 3/5 × -8 1/3
Turn to improper fractions.
18/5 × -25/3
Multiply.
-450/15
Divide.
= -30
HELLPPPPPPPPPPPPPPPPPPPPPPPPP If you get this right you get branilest
Answer:
D.
Step-by-step explanation:
-1 + 1 = 0
x-2=6
answer it!!!!!!!!!
Answer:
x = 8
Step-by-step explanation:
x - 2 = 6 ( add 2 to both sides )
x = 8
Nathan is building a toolshed with a rectangular floor. The area of a rectangle is given by the formula / - w, where I represents the length,
and w represents the width. The floor of the shed will have measurements of either / = 9 and w = 5 or 1 = 7 and w=7. What is the area
of the larger floor?
49
O
35
63
45
Answer:
45
Step-by-step explanation:
if l=9 , w is 5
then area is 9*5=45
if l=7 , w is 7
then area is 7*7=49
49 is greater than 45
but it is not a rectangle. It is a square.
Therefore the correct answer is 45.
Find the original price of a pair of gloves that is $16 after a 20% discount.
Answer:
original price was 64 dollars
Step-by-step explanation:
Answer:
$15.80
Step-by-step explanation:
20% of 16, or 1/5 of 16, is 3.2. So we subtract 3.2 from 16
16 - 3.2 = 15.8
So, in dollar form, it is $15.80
So the final cost of the pair of gloves is $15.80
Given a group of 100 people, at least X share the same first initial (assuming the English alphabet). What is the largest value of X that can be guaranteed
The largest value of X that can be guaranteed is 1.
To determine the largest value of X that can be guaranteed, we need to consider the worst-case scenario where each person has a unique first initial. In this case, X would be 1 for each initial. Since there are 26 letters in the English alphabet, the largest value of X that can be guaranteed is 1 for each initial.
Therefore, we can guarantee that at least one person in the group of 100 people will share the same first initial. In other words, X = 1 is the largest value that can be guaranteed in this scenario.
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Help me please with this question:)
Answer:
it's the second one.
option 2
Madison wants to earn at least $90 at her sales job. She makes $40 per week plus $5 per sale. Which inequality would represent the number of sales Madison must make.
Answer:
1232342
Step-by-step explanation:
1233435
Fifteen more than three times a number is
at most 7 in equation form.
Answer:
3x+15\(\leq\)7
Step-by-step explanation:
The equation form of the given statement would be 3n + 15 ≤ 7.
What is inequality?Inequality is defined as the relation which makes a non-equal comparison between two given functions.
The given statement is "Fifteen more than three times a number is
at most 7"
Let the unknown number be n.
So, the equation form;
3n + 15 ≤ 7
Where n =unknown number
Hence, the equation form of the given statement would be 3n + 15 ≤ 7.
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if the spinner was spun 50 times and landed on 11 fifteen times, which statement is true?
Answer:
The last one.Because the experimental probability is 11 ÷ 50, which is 22%, and the theoretical probability is 1 ÷ 8, which is 12.5%
From a table of integrals, we know that for ,≠0a,b≠0,
∫cos()=⋅cos()+sin()2+2+.∫eatcos(bt)dt=eat⋅acos(bt)+bsin(bt)a2+b2+C.
Use this antiderivative to compute the following improper integral:
∫[infinity]01cos(3)− = limT→[infinity]∫0[infinity]e1tcos(3t)e−stdt = limT→[infinity] if ≠1s≠1
or
∫[infinity]01cos(3)− = limT→[infinity]∫0[infinity]e1tcos(3t)e−stdt = limT→[infinity] if =1.s=1. help (formulas)
For which values of s do the limits above exist? In other words, what is the domain of the Laplace transform of 1cos(3)e1tcos(3t)?
help (inequalities)
Evaluate the existing limit to compute the Laplace transform of 1cos(3)e1tcos(3t) on the domain you determined in the previous part:
()=L{e^1t cos(3)}=
"From a table of integrals, we know that for \(\(a \neq 0\)\) and \(\(b \neq 0\):\)
\(\[\int \cos(at) \, dt = \frac{1}{a} \cdot \cos(at) + \frac{1}{b} \cdot \sin(bt) + C\]\)
and
\(\[\int e^a t \cos(bt) \, dt = \frac{e^{at}}{a} \cdot \cos(bt) + \frac{b}{a^2 + b^2} \cdot \sin(bt) + C\]\)
Use this antiderivative to compute the following improper integral:
\(\[\int_{-\infty}^{0} \cos(3t) \, dt = \lim_{{T \to \infty}} \int_{0}^{T} e^t \cos(3t) \, e^{-st} \, dt = \lim_{{T \to \infty}} \text{ if } s \neq 1, \, \text{ or } \lim_{{T \to \infty}} \text{ if } s = 1.\]\)
For which values of \(\(s\)\) do the limits above exist? In other words, what is the domain of the Laplace transform of \(\(\frac{1}{\cos(3)} \cdot e^t \cos(3t)\)\)?
Evaluate the existing limit to compute the Laplace transform of on the domain you determined in the previous part:
\(\[L\{e^t \cos(3t)\\).
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Help plzz I think it is 1 or 2 ..... By The square root property, if k is a real number and x^2=k, then what is x equal to? 1. √k 2. =| √k 3. -√k 4. k^2
Answer:
\(\Large \boxed{2. \ x=\pm \sqrt{k}}\)
Step-by-step explanation:
\(x^2 =k\)
k is a real number.
We take the square root of both sides of the equation.
\(\sqrt{x^2 } =\pm \sqrt{k}\)
Simplifying the equation.
\(x=\pm \sqrt{k}\)
Answer:
x = ±√k
Step-by-step explanation:
If:
\(x^2 = k\)
We'll take square root on both sides
=> \(\sqrt{x^2} = +/- \sqrt{k}\)
=> x = ±√k
based on the histogram above, what numerical measure of central location would you recommend to use to describe this variable? mean/average median standard deviation covariance
Based on the histogram above, we will use median to describe this variable.
Hence, option (b) is correct choice.
A histogram is a graphical depiction of data distribution in statistics. The histogram is represented by a series of neighbouring rectangles, with each bar representing a different type of data. Statistics is a branch of mathematics that is used in a variety of areas.
The frequency distribution is represented graphically by a histogram.
The histogram may be analysed as a representation of frequencies and classes as linked rectangles.
Option B is the correct answer to this question.
Because the median is unaffected by big observations, we use it as a measure of central tendency while analysing the left skewed distribution.
The required image/ histogram is attached below:
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Round 383.52 to the nearest tenth.
I just need this one answer from something, I'll give BRAINLY a lot to
Answer:
383.5
Step-by-step explanation:
We want to round 383.52 to the nearest tenth.
The tenth would be the 5.
To round we look at the number after the one we want to round ( so 2 )
If the number is greater than 4 so ( 5, 6, 7, 8 or 9 ) then we raise the number that we want to round but if its less than 5 ( 4, 3, 2, 1 , 0 ) we keep the number as it is.
2 is less than 5 so we keep 5 as it is to get 383.5
A survey asked people of different ages whether they get their news by reading the paper. What is the probability that a person surveyed gets the news by reading the paper, given that he or she is under 40? If necessary, round your answer to the nearest percent.
A.10%
B.14%
C.5%
D.90%
Answer:
It is 10%.
Show answer:
I need this answer ASAP!!
Answer:
It is either 7.62m or 10m
Step-by-step explanation:
Eduphoria
Answer:
7.62 m
Step-by-step explanation:
Pythagorean theorem, 3^2+7^2=58
√58 is 7.62
If a scatterplot of standardized, bivariate data displays data that are mostly lying in the upper left and lower right-hand quadrants, then the Pearson correlation is typically going to be negative. True
False
If a scatterplot of standardized, bivariate data displays data that are mostly lying in the upper left and lower right-hand quadrants, then the Pearson correlation is typically going to be negative. The above statement is false.
Bivariate data:Bivariate data involves studying and comparing two separate variables. For example, a researcher may record how long it takes people to complete a crossword puzzle while measuring the stress levels of the participants. In this example, the two variables that the researcher is examining are time and stress.
Scatterplots:Scatterplots display these bivariate data sets and provide a visual representation of the relationship between variables. In a scatterplot, each point represents a paired measurement of two variables for a specific subject, and each subject is represented by one point on the scatterplot.
When the points on a scatterplot graph produce a lower-left-to-upper-right pattern, we say that there is a positive correlation between the two variables. This pattern means that when the score of one observation is high, we expect the score of the other observation to be high as well, and vice versa.
When the points on a scatterplot graph produce a upper-left-to-lower-right pattern, we say that there is a negative correlation between the two variables. This pattern means that when the score of one observation is high, we expect the score of the other observation to be low, and vice versa.
In statistics, the Pearson correlation coefficient ― also known as Pearson's r, the Pearson product-moment correlation coefficient (PPMCC), the bivariate correlation or colloquially simply as the correlation coefficient ― is a measure of linear correlation between two sets of data. It is the ratio between the covariance of two variables and the product of their standard deviations; thus, it is essentially a normalized measurement of the covariance, such that the result always has a value between −1 and 1. As with covariance itself, the measure can only reflect a linear correlation of variables, and ignores many other types of relationships or correlations. As a simple example, one would expect the age and height of a sample of teenagers from a high school to have a Pearson correlation coefficient significantly greater than 0, but less than 1 (as 1 would represent an unrealistically perfect correlation).
The Pearson correlation method is the most common method to use for numerical variables; it assigns a value between − 1 and 1, where 0 is no correlation, 1 is total positive correlation, and − 1 is total negative correlation. This is interpreted as follows: a correlation value of 0.7 between two variables would indicate that a significant and positive relationship exists between the two. A positive correlation signifies that if variable A goes up, then B will also go up, whereas if the value of the correlation is negative, then if A increases, B decreases.
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Solve for p: 3+ 10p - 8p = 17
In Exercises 7-12, describe all solutions of Ax = 0 in parametric vector form, where A is row equivalent to the given matrix.
The parametric form can be written as -
\(x = x_2 \left[ \begin{array}{c} -3 \\ 1 \\ 0 \\ 0 \\ \end{array} \right] + x_3 \left[ \begin{array}{c} 0 \\ 0 \\ 1 \\ 0 \\ \end{array} \right] + x_4 \left[ \begin{array}{c} 4 \\ 0 \\ 0 \\ 1 \\ \end{array} \right]\)
What are homogeneous and non - homogeneous matrix form?A matrix equation of the form \($A\overrightarrow x=0\) is called homogeneous matrix equation.
A matrix equation of the form \($A\overrightarrow x=\overrightarrow b\) is called non - homogeneous matrix equation.
Given is to find the solution in parametric vector form.
If there are {m} free variables in the homogeneous equation, the solution set can be expressed as the span of {m} vectors :
\($\overrightarrow x=s_{1} \overrightarrow v_{1} + s_{2} \overrightarrow v_{2}+......+s_{m} \overrightarrow v_{m}\)
We have a matrix where {A} is the row equivalent to that matrix -
\(\begin{bmatrix} 1&3&0&-4 \\ 2&6&0&-8 \end{bmatrix}\)
Given matrix can be written in Augmented form as -
\(\left[ \begin{array}{cccc|c} 1&3&0&-4 & 0\\2&6&0&-8&0\\ \end{array} \right]\)
Row Reduced Echelon Form can be obtained using the following steps -
{ 1 } - Interchanging the rows R{1} and R{2}.
\(\left[ \begin{array}{cccc|c} 2&6&0&-8&0 \\ 1&3&0 &-4 & 0 \\ \end{array} \right]\)
{ 2 } - Applying the operation R{2} -> 2R{2} - R{1}, to make the second 0.
\(\left[ \begin{array}{cccc|c} 2&6&0&-8&0\\1&3&0&-4&0 \\ \end{array} \right] \;\;\;\;\;\;R_2 \rightarrow 2R_2 - R_1\)
\(\left[ \begin{array}{cccc|c} 2 & 6 & 0 & -8 & 0 \\ 0 & 0 & 0 & 0 & 0 \\ \end{array} \right]\)
{ 3 } - Using R{1} -> R{1}/2
\(\left[ \begin{array}{cccc|c} 2&6&0&-8&0\\0&0&0&0&0\\ \end{array} \right] \;\;R_1 \rightarrow \dfrac{1}{2} R_1\)
{ 4 } - Following equation can be deducted as
\(x_1 + 3x_2 - 4x_4 =0\)
{ 5 } - We can write the parametric form as -
\(x = x_2 \left[ \begin{array}{c} -3 \\ 1 \\ 0 \\ 0 \\ \end{array} \right] + x_3 \left[ \begin{array}{c} 0 \\ 0 \\ 1 \\ 0 \\ \end{array} \right] + x_4 \left[ \begin{array}{c} 4 \\ 0 \\ 0 \\ 1 \\ \end{array} \right]\)
Therefore, the parametric form can be written as -
\(x = x_2 \left[ \begin{array}{c} -3 \\ 1 \\ 0 \\ 0 \\ \end{array} \right] + x_3 \left[ \begin{array}{c} 0 \\ 0 \\ 1 \\ 0 \\ \end{array} \right] + x_4 \left[ \begin{array}{c} 4 \\ 0 \\ 0 \\ 1 \\ \end{array} \right]\)
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