if there is $0.85 for 8 oz, how much would 1 oz cost?

The option that is not a statistical question is D. how tall are the corn plants?

A statistical question is one that may be answered by gathering data and for which the data will vary. Questions answered with a single data point are not statistical questions since the data utilized to answer the question is not variable.

A statistical question is one that can be answered by gathering varying amounts of data. A statistical inquiry is one that yields varying responses and outcomes (data). It must be collected on more than one person and there must be room for the facts to vary.

Therefore, based on the information illustrated, the correct option is D. It was too general and not specific

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well, let's take a look at the tickmarks on the triangle, the tickmarks mean that AC = CB, both AC and CB stemming out of vertex C, and both twin sides will make twin angles at the "base" or namely ∡A = ∡B, that means that 34 = x - 5, let's also recall that the sum of all interior angles in a triangle is 180°, so

\(34=x-5\implies \boxed{39=x} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\measuredangle A}{34}~~ + ~~\stackrel{\measuredangle B}{34}~~ + ~~\stackrel{\measuredangle C}{4y}~~ = ~~180\implies 68+4y=180 \\\\\\ 4y=112\implies y=\cfrac{112}{4}\implies \boxed{y=28}\)

Answer:

y = 28

Step-by-step explanation:

The dashes on line segments AC and BC indicate that the line segments are equal in length.

Therefore, as the triangle has two sides of equal length, it is an isosceles triangle.

The base angles of an isosceles triangle are equal, therefore ∠A = ∠B.

Interior angles of a triangle sum to 180°.  

Therefore:

⇒ ∠A + ∠B + ∠C = 180°

⇒ 34° + 34° + 4y° = 180°

⇒ 68° + 4y° = 180°

⇒ 4y° = 112°

⇒ y = 112° ÷ 4°

⇒ y = 28

The value of dfbetween in the analysis of variances is 2. Thus option D is correct option.

According to the statement

we have given that the df total = 29 and df within = 27. And we have to find the value of the df between.

So, For this purpose, we know that the

Analysis of variance (ANOVA) is an analysis tool used in statistics that splits an observed aggregate variability found inside a data set into two parts.

So, Df between values are the values between the value of dftotal and dfwithin.

Here df total = 29 and df within = 27

So, df between = df total - df within

Substitute the values in it then

df between = df total - df within

df between = 29 - 27

df between = 2.

So, The value of dfbetween in the analysis of variances is 2. Thus option D is correct option.

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Answer: 77

Step-by-step explanation:

Multiply both sides of the equation by  

Simplify both sides of the equation.

x =  77

Answer:

\(x - 7 > - 11 \\ x > 7 - 11 \\ \boxed{x > - 4}\)

Answer:

Divide the numerator by the denominator. 78 ÷ 5 = 15 with a remainder of 3.

Write down the whole number 15 and then write down the remainder as new numerator (3) above the denominator (5), As below : 15 35.

Answer:

\(15\frac{3}{5}\)

Step-by-step explanation:

to prove the answer:

\(15\frac{3}{5}\)

15*5+3/5

75+3/5

78/5

therefore ,\(15\frac{3}{5}\) = 78/5

The expression that can be added to both sides of the given quadratic equation to change it to a perfect square trinomial is \(\frac{b^2}{4a^2}\) .

The standard form of perfect square trinomial is given as:

\(ax^2 + bx + c\)

here,

a = coefficient of x² .

b = coefficient of x.

c = constant .

Given the quadratic equation:

\(x^2 + \dfrac{b}{a}x\ +\ ?= -\dfrac{c}{a}\ +\ ?\)

The above equation is needed to be changed to a perfect square trinomial.

To change the quadratic equation into the perfect square, the squared of half the value of the coefficient of degree one variable can be added to both sides of the equation.

Therefore, the term to be that is needed to be added to the given quadratic equation is \(\frac{b^2}{4a^2}\) .

Now, the quadratic equation can be written as:

\(x^{2} + \frac{b}{a} x + \frac{ b^{2}}{4a^{2}} = \frac{-c}{a} + \frac{ b^{2}}{4a^{2}}\)

Therefore, \(\dfrac{b^2}{4a^2}\) should be added to both sides to convert it into the perfect polynomial.

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The given question is incomplete. Probably the complete question is:

When deriving the quadratic formula by completing the square what expression can be added to both sides of the given equation to create a perfect square trinomial?

\(x^2 + \dfrac{b}{a}x\ +\ ?= -\dfrac{c}{a}\ +\ ?\)

Answer:

-5

Step-by-step explanation:

Answer:

dotted

Step-by-step explanation:

when there is a line underneath the less than or equal to sign, it is solid, when there is not a line it is dotted.

Answer:

x ≈ 41.4°

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Pre-Calculus

Step-by-step explanation:

Step 1: Identify Variables

C° = x°

c = 12

a = 15

b = 18

Step 2: Solve for x

Answer:

X = 3.25

Step-by-step explanation:

273 - 10 = 263

263 divided by 81 = 3.25

Answer Check: 3.25 times 81 + 10 = 273

Hope this helps :)

Answer:

Row n ---> 27th term is 27.

Row T ---> 27th term is 80.

Step-by-step explanation:

To find the 27th term for the top row, row n, you will use this formula:

an = a1 + f × (n-1)

The first number = 1

The common difference (f) = 1

a27 = 1 + 1 × (27-1)

a27 = 1 + 27 - 1

a27 = 28 - 1

a27 = 27

So, the 27th term is 27.

We will do the same for the row T.

an = a1 + f × (n-1)

The first number = 2

The common difference (f) = 3

a27 = 2 + 3 × (27-1)

a27 = 2 + 81 - 3

a27 = 83 - 3

a27 = 80

So, the 27th term is 80.

Answer:

\( {x}^{2} - 12x + 23 = 0\)

\( {x}^{2} - 12x = - 23\)

\( {x}^{2} - 12x + 36 = 13\)

\( {(x - 6)}^{2} = 13\)

x - 6 = +√13

x = 6 + √13

Answer:

Answer is (10,1)

Step-by-step explanation:

in photo

The most goals the team scored in a game is 8

From the question, we have the following parameters that can be used in our computation:

The box plot

The most goals the team scored in a game is the maximum of the box plot

From the box plot, we have

Maximum = 8

Using the above as a guide, we have the following:

Most goal = 8

Hence, the most goal is 8

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Answer:

Step-by-step explanation:

I think the answer C x=42 y=30, correct me if i'm wrong

Answer:for a graph u use rise over run. If u just have the points u use the formula which is m=y2-y1/x2-x1

Step-by-step explanation:

The probability that the Mandrogora produces an aneuploid gamete is 0.750, and the probability of producing an aneuploid offspring is also 0.750.

To calculate the probability of the Mandrogora producing an aneuploid gamete, we need to consider the number of possible combinations that result in aneuploidy. Aneuploidy occurs when there is an abnormal number of chromosomes in a gamete.

In this case, the Mandrogora is triploid with 12 total chromosomes, which means it has 3 sets of chromosomes. The haploid number can be calculated by dividing the total number of chromosomes by the ploidy level, which in this case is 3:

Haploid number = Total number of chromosomes / Ploidy level

Haploid number = 12 / 3

Haploid number = 4

Since each gamete has an equal probability of receiving one or two copies of each chromosome, we can calculate the probability of producing an aneuploid gamete by considering the number of ways we can choose an abnormal number of chromosomes from the total number of chromosomes in a gamete.

To produce aneuploidy, we need to have either 1 or 3 chromosomes of a particular type, which can occur in two ways (1 copy or 3 copies). There are 4 types of chromosomes, so the total number of ways to have an aneuploid gamete is \(2^4\) - 4 - 1 = 11 (excluding euploid combinations and the all-normal combination).

The total number of possible combinations of chromosomes in a gamete is\(2^4\) = 16 (each chromosome can have 1 or 2 copies).

Therefore, the probability of producing an aneuploid gamete is 11 / 16 = 0.6875.

Now, if the Mandrogora self-fertilizes, the probability of producing an aneuploid offspring is the square of the probability of producing an aneuploid gamete. Therefore, the probability of aneuploid offspring is \(0.6875^2\) = 0.4727, rounded to three decimal places.

To summarize, the probability that the Mandrogora produces an aneuploid gamete is 0.6875, and the probability of producing an aneuploid offspring through self-fertilization is 0.4727.

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The system with impulse response g(t, t) = e^(-2|t|^-|t|) is not BIBO stable, while the system with impulse response g(t, t) = sin(t)e^(-(-t^2)) is BIBO stable.

To determine if a system is BIBO (Bounded-Input Bounded-Output) stable, we need to analyze the impulse response of the system.

For the first system with impulse response g(t, t) = e^(-2|t|^-|t|), let's examine its behavior. The function e^(-2|t|^-|t|) decays rapidly as |t| increases. However, it does not decay fast enough to satisfy the condition for BIBO stability, which requires the integral of |g(t, t)| over the entire time axis to be finite. Since the integral of e^(-2|t|^-|t|) diverges, the first system is not BIBO stable.

For the second system with impulse response g(t, t) = sin(t)e^(-(-t^2)), the term e^(-(-t^2)) represents a Gaussian function that decays exponentially. The sinusoidal term sin(t) can oscillate, but it is bounded between -1 and 1. As the exponential decay ensures that the impulse response is bounded, the second system is BIBO stable.

In summary, the system with impulse response g(t, t) = e^(-2|t|^-|t|) is not BIBO stable, while the system with impulse response g(t, t) = sin(t)e^(-(-t^2)) is BIBO stable.

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Answer:

arun has about 66 marbles in total, in my calculations

Answer:

\( GH = 6.3 \) (nearest tenth)

Step-by-step explanation:

Given:

G(-2, -3)

H(0, 3)

Required:

Distance between point G and H = GH

Solution:

Distance between G(-2, -3) and H(0, 3):

\( GH = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)

Let,

\( G(-2, -3) = (x_1, y_1) \)

\( H(0, 3) = (x_2, y_2) \)

\( GH = \sqrt{(0 - (-2))^2 + (3 - (-3))^2} \)

\( GH = \sqrt{(2)^2 + (6)^2} \)

\( GH = \sqrt{4 + 36} = \sqrt{40} \)

\( GH = 6.3 \) (nearest tenth)

Answer:

m∠A 60°, m∠B= 120°, m∠C =60°, m∠D=120°

Step-by-step explanation:

\( In\: ||^{gm} \: ABCD, \: BK\perp AD... (given) \\

\therefore \angle BKA = 90\degree \\

In\:\triangle BKA, \\\\

\cos \angle A = \frac{AK}{AB}\\\\

\cos \angle A = \frac{3}{6}\\\\

\cos \angle A = \frac{1}{2}\\\\

\cos \angle A = \cos 60\degree.. (\because \cos 60\degree = \frac{1}{2}) \\\\

\huge \red {\boxed {\therefore \angle A = 60\degree}} \\\)

Since, adjacent angles of a parallelogram are Supplementary.

\( \therefore \angle A + \angle B = 180\degree \\

\therefore 60\degree + \angle B = 180\degree \\

\therefore \angle B = 180\degree - 60\degree\\

\huge \purple {\boxed {\therefore \angle B = 120\degree}} \\\)

Since, opposite angles of a parallelogram are congruent.

\( \therefore \angle C = \angle A

\\

\huge \red{\boxed {\therefore \angle C = 60\degree}} \\\\

\therefore \angle D = \angle B

\\

\huge \purple {\boxed {\therefore \angle D = 120\degree}} \\\)

The next terms of the sequences 1; 2; 4; 7; 11; ... and -3; 0; 3; 6; ... are 16, 22 and 9, 12.

The given sequence is: 1; 2; 4; 7; 11; ...

To get the next term, we need to observe the differences between consecutive terms:

2-1 = 1; 4-2 = 2; 7-4 = 3; 11-7 = 4

The differences are increasing by 1 in each step. So, to get the next term, we add 5 to the last term:

11 + 5 = 16

Similarly, to get the term after that, we add 6 to the previous term:

16 + 6 = 22

Therefore, the next two terms of the sequence are 16 and 22, and the term-to-term rule is to add consecutive integers starting from 1 to the previous term.

The given sequence is: -3; 0; 3; 6; ...

To get the next term, we add 3 to the previous term:

6 + 3 = 9

Similarly, to get the term after that, we add 3 to the previous term:

9 + 3 = 12

Therefore, the next two terms of the sequence are 9 and 12, and the term-to-term rule is to add 3 to the previous term.

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The exercise involves finding the product C = AB, where matrix A is given by [2 9] and matrix B is given by [3 6 1]. We need to perform the matrix multiplication to obtain the resulting matrix C.

Let's calculate the matrix product C = AB step by step:

Matrix A has dimensions 2x1, and matrix B has dimensions 1x3. To perform the multiplication, the number of columns in A must match the number of rows in B.

In this case, both matrices satisfy this condition, so the product C = AB is defined.

Calculating AB:

AB = [23 + 912 26 + 94 21 + 95]

[103 + 612 106 + 64 101 + 65]

Simplifying the calculations:

AB = [6 + 108 12 + 36 2 + 45]

[30 + 72 60 + 24 10 + 30]

AB = [114 48 47]

[102 84 40]

Therefore, the product C = AB is:

C = [114 48 47]

[102 84 40]

In summary, the matrix product C = AB, where A = [2 9] and B = [3 6 1], is given by:

C = [114 48 47]

[102 84 40]

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The values of all sub-parts have been obtained.

(1). The option B is correct answer which is 65.

(2). The option A is correct answer which is $1315.

What is EOQ model?

Economic order quantity (EOQ) refers to the optimal number of units that a business should buy to satisfy demand while reducing inventory costs including holding costs, shortage costs, and order costs.

(1). Evaluate the safety stock:

As given,

Demand during lead time = 90 units, and standard deviation = 40 units.

Service level = 95%, and its value is 1.64.

Safety stock = Service level × standard deviation

                     = 1.64 × 40

                     = 65.

Hence, the option B is correct.

(2). Evaluate the Annual carrying cost:

As given,

Co = $120, Cc = $15, Cs = $40, and demand (D) = 5000 units.

φopt = √ [(2CoD/Cc) {(Cs + Cc) /Cs}]

Substitute values,

φopt = √ [(2*120*5000/15) {(40 + 15) /40}]

φopt = 331.66

φopt ≈ 332 units.

Now,

Sopt = φopt {Cc/(Cc + Cs)}

Substitute values,

Sopt = 332 {15/(15 + 40)}

Sopt = 90.5454

Sopt ≈ 91 units.

Now calculate Annual carrying cost,

Annual carrying cost = (Cc/2φopt)*(φopt - Sopt)²

Substitute values,

Annual carrying cost = [15/(2 × 332)]*[332 - 91]²

Annual carrying cost = (15/664)*(241)²

Annual carrying cost ≈ 1315 units.

Hence, the Annual carrying cost is $1315.

Hence, the values of all sub-parts have been obtained.

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Answer:

the answer is C

Step-by-step explanation:

The negative graph has

So the equetion for the negative slop is y= -m + b

from the given 3 equetion C fulfill all the requirment .

So the answer is C

Derek needs to make contributions of approximately $21,038.34 per year from his 26th birthday to his 65th birthday in order to accumulate $2,742,310.00 in his retirement account by the time he fully retires.

To determine the amount Derek needs in his retirement account on his 65th birthday, we can use the concept of present value. Since he plans to withdraw $184,036.00 per year, starting from his 66th birthday until his 90th, the cash flows can be treated as an annuity. The interest rate is 5.00%, and the time period is 25 years (from 66 to 90). Using the formula for the present value of an annuity, we can calculate the required amount. The formula is:

PV = PMT * (1 - \((1 + r)^(-n)\)) / r

where PV is the present value, PMT is the annual withdrawal amount, r is the interest rate per period, and n is the number of periods.

Plugging in the values, we get:

PV = $184,036.00 * (1 - \((1 + 0.05)^(-25)\)) / 0.05 ≈ $2,744,607.73

Therefore, Derek needs approximately $2,744,607.73 in his retirement account on his 65th birthday to cover his desired annual withdrawals.

Moving on to the second part, Derek plans to make contributions to his retirement account from his 26th birthday to his 65th birthday. To reach his goal of having $2,742,310.00 in his retirement account after fully retiring, we can calculate the necessary contributions using the formula for the future value of an ordinary annuity:

FV = PMT * \(((1 + r)^n\) - 1) / r

Rearranging the formula, we can solve for the required contributions (PMT):

PMT = FV * (r / (\(((1 + r)^n\) - 1))

Plugging in the values, we get:

PMT = $2,742,310.00 * (\(\frac{0.05} {((1+0.05)^{39}-1 )}\))≈ $21,038.34

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The sum of the measures of an exterior angle of a polygon is 360°.

If the given angle divides 360 evenly, then it can be a measure of an exterior angle of a polygon. If otherwise, then it cannot be.

Out of the given angles, only 50 does not divide 360 evenly. Therefore, a regular polygon cannot have an exterior angle measuring 50°. (Option B)

Answer:

A.) Paul

B.) Plain

C.) Paul

Step-by-step explanation:

Paul: Shirt - Striped; Jumper - Spotted; Towel - Plain

Kerry: Shirt - Plain; Jumper - Striped; Towel - Spotted

Sandra: Shirt - Spotted; Jumper - Plain; Towel - Striped

Hope this helps! Have a nice dayy! :)