If the voltage, V, in an electric circuit is held constant, then the current, I, is inversely proportional to the resistance, R.
If the voltage, V, in an electric circuit is held constant, then the current, I, is inversely proportional to the resistance, R.
A) If the current is 210 amperes when the resistance is 4 ohms, find the constant of proportionality, K.
B) Find the current when the resistance is 12 ohms

5/4 m/s^{2} would be its new acceleration .

What is centrifugal acceleration ?

The simplest case of circular motion is uniform circular motion, where an object moves in a circular trajectory with constant velocity. Note that the linear velocity of an object in circular motion is constantly changing because, unlike velocity, it is constantly changing direction. From kinematics we know that acceleration is a change in velocity, either in magnitude or direction, or both. Therefore, an object in uniform circular motion will always be accelerated even if the magnitude of its velocity is constant. You can feel this acceleration every time you get in the car while cornering. Keeping the handle steady while turning and moving at a constant speed creates a smooth circular motion. What you will notice is a feeling of skidding (or skidding depending on speed) out of the center of the turn.

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Answer:

The correct answer is B) X Plane

Explanation:

Polarisation Direction that is the oscillation of electric field for both the antennas that are transmitting and receiving antenna must be same.  

The polarization of the antenna is the orientation of the radio wave electric field emitted by it, which is determined by the mechanical arrangement and alignment of the antenna. Vertical polarization would be created by an antenna whose conductor is structured linearly and oriented vertically.

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Answer:

The force each one experienced

Explanation:

Hope this helps :)

Answer:

The velocity of the box is related to the angular velocity of the spool, which is given by the equation:

v = r * ω

where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:

τ = I * α

where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.

The tension in the string is equal to the weight of the box, which is given by:

T = m * g

Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:

First, we can find the angular acceleration of the spool using the torque equation:

τ = I * α

T = m * g = τ

m * g = I * α

α = (m * g) / I

α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2

α = 86.53 rad/s^2

Next, we can find the angular velocity of the spool using the kinematic equation:

ω^2 = ω_0^2 + 2 * α * θ

where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:

ω^2 = 2 * α * θ

ω = sqrt(2 * α * θ)

ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))

ω = 166.6 rad/s

Finally, we can find the time it takes for the box to reach the floor using the equation:

v = r * ω

v = 0.10 m * 166.6 rad/s

v = 16.66 m/s

t = d / v

t = 3.50 m / 16.66 m/s

t = 0.21 s

Using a scale of 1 centimeter = 1 newton, the following displacement vector is

(a) 5 newtons west 5 centimeter.

(b) 3 newtons, 270° 3 centimeter.

(c) 4 newtons, 0°, 4 centimeter.

The International System of Units (SI) uses the centimetre (cm) as a measure of length. It is a handy unit for measuring short distances because its definition is one tenth of a metre. 0.01 metres or 0.3937 inches make up one centimetre.

In the SI system, a newton (N) is a unit of force. It is described as the amount of pressure necessary to accelerate a mass of one kilogramme at a speed of one metre per second squared (m/s2). The force required to accelerate a mass of one kilogramme by one metre per second squared is comparable to one newton, in other words.

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The acceleration of the mass in terms of {m} is -

a = 2F/m.

The force acting on a body is given by -

Force {F} = mass {m} x acceleration {a}

Given is that a net force of {F} is applied to half the mass {m/2}.

We know that -

Force {F} = mass {m} x acceleration {a}

F = {m/2} x a

a = 2F/m

Therefore, the acceleration of the mass in terms of {m} is -

a = 2F/m.

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Wind energy is converted to electrical energy using a device called a wind turbine.

Wind turbines are typically composed of three main parts: the rotor blades, the rotor hub, and the nacelle.

Here's a brief outline of the process:

1. Wind hits the rotor blades, causing them to spin. The rotor blades are shaped like airfoils, similar to airplane wings, and are designed to maximize the amount of energy that can be extracted from the wind.

2. The rotor blades are connected to the rotor hub, which is in turn connected to a shaft. As the rotor blades spin, they turn the shaft, which rotates a generator in the nacelle.

3. The generator uses the rotational energy from the shaft to produce electrical energy. The electrical energy is typically in the form of alternating current (AC) electricity.

4. The AC electricity from the generator is sent through a transformer, which increases the voltage of the electricity to make it suitable for transmission over long distances.

5. The electricity is then sent through power lines to homes and businesses, where it can be used to power electrical devices and appliances.

6. After the electricity has been used, it returns to the power grid and may be reused or stored for later use.

Overall, this process allows for the mechanical energy of the wind to be transformed into electrical energy, which can then be used to power homes and businesses.

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In this lab, you observed how different factors such as velocity, gradient, and , or amount of water in a stream, affect the rate of , the transport of materials from one area to another by water.

Volume, Erosion

How did changing from a light drizzle to a downpour affect the river and the sediment in it? Check all that apply.

3.The velocity of the river increased.

4.There was more erosion in the stream.

5.The type of sediment that moved changed.

Answer:

a) 500 N

b) 250 J

c) 0.87 m

d) 1.58 m/s, at 0.6 m from the wall

Explanation:

The mass of the object m = 100 kg

the spring constant k = 1000 N/m

length of the the spring = 1 m

extension of the string = 50 cm = 0.5 m

a) Force used to pull the mass is gotten from Hooke's law equation

F = -kx

where F is the force used to pull = ?

k is the spring constant = 1000 N/m

x is the extension = 0.5 m

substituting, we have

F = 1000 x 0.5 = 500 N  this force is used to pull the mass

b) The work done in moving the mass = Fx

==> 500 x 0.5 = 250 J

c) The energy stored up in the spring U = \(\frac{1}{2}kx^{2}\)

U = \(\frac{1}{2}*1000*0.5^{2}\) = 125 J

energy available for the mass from its equilibrium position = 250 - 125 = 125 J

this energy is equivalent to the work done by the spring on the mass by moving it closer to the wall

Work W = (weigh of the mass) x distance moved

weight = mg

where m is the mass = 100 kg

g is acceleration due to gravity = 9.81 m/s^2

substituting, we have

W = mgd

where d is the distance the mass moves closer to the wall

W = 100 x 9.81 x d

but W = 125 J

125 = 981d

d = 125/981 = 0.13 m

closeness to the wall = L - d

where L is the natural length of the spring = 1 m

closeness to the wall = 1 - 0.13 = 0.87 m

d) The maximum kinetic energy of the object  will be halfway between the extended length and the final resting place.

extended length = 1 + 0.5 m = 1.5 m

distance from resting place = 1.5 - 0.87 = 0.63 m from the wall

At this point, all the mechanical energy on the mass and spring system is converted to kinetic energy of motion.

KE = \(\frac{1}{2}mv^{2}\)

substituting,

125 = \(\frac{1}{2}*100*v^{2}\) = \(50v^{2}\)

\(v^{2}\) = 125/50 = 2.5

v = \(\sqrt{2.5}\) = 1.58 m/s

Answer:

v = 0.5 m/s.

Explanation:

Total distance, d = 20 m + 20 m = 40 m

Total time taken, t = 30 s + 50 s = 80 s

The average speed of an object is the total distance divided by time taken. So,

\(v=\dfrac{40}{80}\\\\=0.5\ m/s\)

So, the average speed of the object is 0.5 m/s.

The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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Based on Newton's first  and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.

Newton's first law of motion is also called law of inertia because it depends on mass of the object.

An object with a greater mass will require greater force to be stopped or get moving.

Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.

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The minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

The orbital speed of Earth or a natural satellite is the speed at which it orbits around the center of the system.

The minimum horizontal velocity required for an object to orbit the earth just above the surface is calculated as follows;

V(min) = √GMR

where;

Substitute the given parameters and solve for the minimum orbital speed of the earth.

V(min) = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 6.38 x 10⁶)

V(min) = 5.04 x 10¹⁰ m/s

Thus, the minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

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Quaynisha Perry's strategy was interesting: ask everyone in the room to be part of the decision-making process.

The statement has been corrected of the capitalization error.

Capitalization errors is said to take place when the writer capitalizes a word that does not require a capital letter or when the writer does not capitalize a word the requires one.

In all cases, Capitalization errors hinder the reader's experience with the writing and must  be avoided at all cost.

It is pertinent to note that you should always capitalize the first letter of the first word in a sentence, no matter what the word is.

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Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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We are given:

Homer the Astronaut:

Mass of Homer the astronaut(m1) = 200 kg

initial velocity of Homer the astronaut(u1) = 5 m/s

Larry the Pal:

Mass of Larry the Pal (m2) = 150 kg

initial velocity of Larry the Pal (u2) = 0 m/s

Since they will move together after the collision, they will have the same velocity:

v1 = v2 = V

Solving for the Final velocity:

from the law of conservation of momentum:

m1u1 + m2u2 = m1v1 + m2v2

since v1 = v2 = V:

m1u1 + m2u2 = V(m1 + m2)

replacing the variables with the given values

200 * 5 + 150 * 0 = V(200 + 150)

1000 = 350V

V  = 1000 / 350

V = 2.86 m/s

Answer:

Tycho Brahe

Explanation:

Tycho Brahe's accurate observations of planetary positions provided the data used by Johannes Kepler to derive his three fundamental laws of planetary motion.

Answer:

A. Tycho Brahe

Explanation:

the person above is correct :)

The statement that describes the net force on an object is the sum of all forces acting on an object (option A).

Net force is sum of all forces acting on an object in a single plane.

When a force is applied to a body, not only is the applied force acting, there are many other forces like gravitational force, frictional force and the normal force that balances the other force.

The sum of all these forces acting on the object whether in the same or opposite direction is regarded as the net force.

Therefore, the statement that describes the net force on an object is the sum of all forces acting on an object.

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According to Newton's third law

So

\(\\ \rm\dashrightarrow F_{A}=-F_A\)

As car is pushed forward so the opposing force is less than 8000N

Answer:It is less than 8,000 N and greater than zero.

Explanation:

The buoyant force acting on the cylinder is, \(Fb = \rho Ahg\). Here A is the cross-sectional area of the cylinder, h is the height of the cylinder, ρ is the density of the cylinder, and g is the acceleration due to gravity.

This buoyant force is also equal to the volume of the fluid displaced. \(Fb = \sigma h(A-x)g\). Here σ is the density of the fluid.

Equate the above two equations and solve for x.

\(\rho Ahg = \sigma A(h-x)g\\\rho h = \sigma h - \sigma x\\x = \frac{(\sigma - \rho)h}{\sigma}\)

So, the distance x depends on the density of the fluid, density of the cylinder and the height of the cylinder.

1. The density of the cylinder is same and distance x is independent of the diameter of the cylinder. Therefor, there will be no change in the distance x. Hence, the correct answer is No change.

2. Now the height is changing keeping the density same. As the distance x is directly proportional to the height, the distance x will increase.

3. The density of the added liquid is greater than of the water and it does not mix with the water. So, the liquid will settle down and there will be no change in the distance x.

4. The density of the added liquid is less than that of the water and it does not mix with the water. So, the liquid will not settle down and the distance x will change. The change in distance x can be determined as follow:

\(\rho Agh = \sigma' Axg + \sigma A(h-x)g\\\rho h=\sigma' x + \sigma h - \sigma x\\x=(\frac{\sigma - \rho}{\sigma - \sigma'})h\)

Here, σ' is the density of the added liquid.

From the above relation it is clear, that on adding the liquid of the density less than that of water, the denominator term become small ando so the value of x will increase.  

5. On removing some of the water inside the glass, the height of the water column will decrease, but the value of x does not depend on the height of the water column. So, there will be no change in the distance x.

6. The density of the new cylinder is smaller than that of the earlier one. So, the numerator term will increase. Therefore, the value of x will increase.

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Answer:

126

Explanation:

Answer:

Explanation:

A) The apparent depth of the fish when viewed at normal incidence to the water can be calculated using Snell's law:

n1 * sin(θ1) = n2 * sin(θ2)

where n1 and n2 are the indices of refraction of the first and second media, respectively, and θ1 and θ2 are the angles of incidence and refraction, respectively.

Since the fish is floating motionless, the angle of incidence is zero.

n1 = 1 (air)

n2 = 1.33 (water)

θ1 = 0

Solving for θ2, we have:

sin(θ2) = (n1/n2) * sin(θ1) = (1/1.33) * sin(0) = 0

Since sin(θ2) = 0, θ2 = 0, meaning that the light passes through the water without refraction. The apparent depth of the fish is simply its actual depth, 7.10 cm.

B) The apparent depth of the reflection of the fish in the bottom of the tank can be calculated using the same method as above, but with θ1 equal to the angle of reflection instead of incidence.

Since the bottom of the tank is a mirror, the angle of incidence is equal to the angle of reflection, which we can call θ.

θ1 = θ

Solving for θ2, we have:

sin(θ2) = (n1/n2) * sin(θ1) = (1/1.33) * sin(θ) = sin(θ) / 1.33

Next, we use the fact that the angle of incidence and the angle of refraction are related by the law of reflection:

θ1 = θ2

Setting these two equations equal to each other and solving for sin(θ), we find:

sin(θ) = 1.33 * sin(θ)

sin(θ) = 0.75

Taking the arcsine of both sides, we find:

θ = sin^-1(0.75) = 53.13 degrees

Finally, using the fact that the apparent depth is equal to the actual depth divided by the cosine of the angle of incidence, we find:

apparent depth = 7.10 cm / cos(θ) = 7.10 cm / cos(53.13 degrees) = 19.4 cm.

The initial velocity of the cart.

Newton, There can be a mass is four.080, So acceleration might be equal to 2.50 m in step with cent within the rectangular. Initial is that amount that relies upon total mass. The greater mass the more inertia. So Mass is 2000 kg and acceleration is 3 ms square. So this offers us an internet pressure identical to 6000 newtons or 6.0 and 210 to the power

In case you roll a ball, it initially will keep rolling except friction or something else stops it by means of pressure. you could also think about the way that your body maintains transferring ahead when you hit the brake on your bike. Translational Inertia = ma, in which m is the mass, and a is the acceleration of the object. Calculate the rotational inertia or the instant of inertia velocity by way of multiplying the mass of the object with a square of the gap between the item and the axis, the radius of rotation.

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Answer:

the arrow symbol ⇒ in irreversible reactions and doble arrow symbol in reversible reactios⇔

Explanation:

i hope this will help you

Answer:

85

Explanation:

soln

given that;

frequency=17Hz

wavelength=5m

speed?

formula for wavelength is;

wavelength= speed/frequency

then ; making v the subject formula

we have that v=wavelength*frequency

v=17*5=>85ms

Increased driving can lead to higher vehicle maintenance and repair expenses, increased fuel costs, potential increases in auto insurance premiums, and additional parking fees, all of which should be considered when estimating the overall impact on your expenses.

The expenses that are likely to change based on how much you drive can be broadly categorized into two main areas: vehicle-related expenses and fuel-related expenses.

1. Vehicle-related expenses: The more you drive, the more wear and tear your vehicle will experience, leading to increased maintenance and repair costs. Regular oil changes, tire replacements, brake pad replacements, and other routine maintenance tasks will be required more frequently.

2. Fuel-related expenses: It's intuitive that the more you drive, the more fuel you'll consume, resulting in higher fuel expenses. Fuel prices can vary, but regardless of fluctuations, increased mileage will directly impact your fuel budget. Fuel-efficient vehicles may mitigate some of these costs, but the overall impact on your expenses will still be noticeable.

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Changing the green sum of forces arrow involves manipulating applied forces, frictional forces, and normal forces, allowing for adjustments in magnitude and direction through various means.

To change the green sum of forces arrow, you can employ the following three strategies:

Adjusting Applied Forces: By modifying the magnitude or direction of the applied forces, you can alter the green sum of forces arrow. If the applied forces are increased or directed in a different way, the green sum of forces arrow will change accordingly. For instance, increasing the magnitude of a pushing force will result in a larger green sum of forces arrow in that direction.

Modifying Frictional Forces: Frictional forces play a crucial role in determining the green sum of forces. By changing the coefficient of friction or applying lubricants, you can affect the magnitude of frictional forces acting on an object. Reducing friction will decrease the green sum of forces arrow, while increasing friction will have the opposite effect.

Varying Normal Forces: The green sum of forces arrow can be influenced by adjusting the normal forces acting on an object. Normal forces are perpendicular to the surface and counteract the weight of an object. By changing the angle or surface on which an object rests, you can modify the normal forces. This alteration will subsequently impact the green sum of forces arrow.

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Answer:

Explanation:

Pressure on the hydraulic system is expressed as;

Pressure = Force/Area

Given

Force on the fluid = 400N

Area = 0.001m²

Pressure in the fluid = 400/0.001

Pressure in the fluid = 400,000N/m²

1N/m² = 0.001kPa

400,000N/m² = x

x = 400,000 × 0.001

x = 400kPa

Hence the pressure in kPa is 400kPa

b) Using the formula;

Pa = Pb

Fa/Aa = Fb/Ab

Pa = Fb/Ab

Fb = PaAb

Fb = 400,000(0.2)

Fb = 80,000N

Hence the magnitude of the force exerted on the load bearing piston by the hydraulic fluid is 80,000N