if the time set for trial for ignition (tfi) is exceeded, the ignition control module places the furnace in lockout.

A digital multimeter can not be used to test charging system voltage,So Technician A and Technician B is not correct.

Neither technician is entirely correct.

Technician A is partially correct in that it is generally recommended to have a battery that is at least 75% charged before testing the charging system. However, this is not an absolute requirement, and some testing can still be performed with a battery that has a lower charge.

Technician B is incorrect in stating that a digital multimeter cannot be used to test charging system voltage. In fact, a digital multimeter is one of the most commonly used tools for this purpose, and it can provide accurate readings of the voltage output from the alternator.

Therefore, the correct answer is neither A nor B.

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Error message, update the game and Steam client, verify game files, and reinstall the game if necessary.

To fix the "procedure entry point Steam Controller could not be located in the dynamic link library" error, you can try the following steps:

If none of these steps work, you may need to contact the program's support team for further assistance.

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In the system life cycle, if you address item OP-1 (in the NIST 800-160 v1), then you are in the Design and Development phases. Thus, the correct answer is A. Design Phase and B. Development Phase.

The system life cycle is the process of developing and maintaining a system from conception to retirement. It consists of five stages: planning, analysis, design, implementation, and maintenance. The system development life cycle (SDLC) is another term for the system life cycle. The five phases of the system life cycle are as follows:1. Planning Phase: In this stage, the requirements are analyzed and defined, and the feasibility of the project is assessed.2. Analysis Phase: In this stage, the current system is studied to determine its strengths and weaknesses. The requirements are gathered and analyzed.3. Design Phase: In this stage, the system's design is created, including hardware, software, and procedures.4. Implementation Phase: In this stage, the system is installed and tested.5. Maintenance Phase: In this stage, the system is monitored and maintained to ensure that it continues to function properly.What is the NIST 800-160?The National Institute of Standards and Technology's (NIST) "Systems Security Engineering: An Integrated Approach to Building Trustworthy Resilient Systems" is a security engineering guide. This is a security engineering process reference guide that was first published in 2016. This guide is used by organizations to develop and build secure and trustworthy systems.

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Although in practice this is very challenging to achieve, the cold fluid can exit the heat exchanger at a temperature higher than the temperature of the hot fluid outlet.

There are numerous ways to transmit heat, including evaporative cooling, thermal radiation, convection, and conduction.

Heat transfer is any or all of a variety of processes that are thought to function as mechanisms to move energy and entropy from one place to another. Common names for the specific mechanisms include convection, heat radiation, and conduction (see thermal conduction).

Every time there is a temperature difference between states of matter, heat transfer takes place. Heat transfer only happens in the direction of decreasing temperature, or from a hot object to a cold item.

Conduction of heat through solids, convection of liquids and gases, and electromagnetic waves.

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The needed values of dy/dt and dx/dt are [(-28)/3] and 4, respectively, for the given equation: x2 + y2 = 400.

Dy/dt is equal to -52/x2. What is implicit discrimination, exactly? Symbolizing the derivative of a dependent variable, solving the resulting expression for the symbol, and differentiating each term separately to find the derivative of a dependent variable in an implicit function. The following equation is used to calculate the value of dy/dx: xy = 4, y = 4, x/x, y = 4x1, and dy/dx is either -4x2 or -4/x2. value of dy/dt. "dx/dt" = "dy/dt" = "dy/dx,", Dy/dt = x2(4/13) = x2(52/x2). Consequently, dy/dt equals -52/x2. dx/dt = 13. F(x) is said to be differentiable at the point x = an if the derivative f '(a) exists at each point in its domain.  Assuming two functions g and h, where y = g(u) and u = h, respectively (x).

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Answer:

The correct response is "821.88". A further explanation is given below.

Explanation:

According to the question,

The largest amount unresolved after five years would have been:

= \(35000\times (\frac{F}{P}, 4 \ percent,5 )\)

= \(35000\times 1.216 7\)

= \(42584.50\)

Now,

time (t) will be:

= \(5\times 12\)

= \(60 \ monthly \ payments\)

So, monthly payment will be:

= \(42582.85\times (\frac{A}{P}, 0.5 \ percent,60 )\)

= \(42584.50\times 0.0193\)

= \(821.88\)

Answer:

Explanation:

The forward-biased voltage drop of a semiconductor diode depends on the material it is made of and the method of fabricating the junction.

A silicon diode will have a voltage drop that can be estimated as 0.7 V. The actual value will depend on current and temperature.

A germanium diode will have a voltage drop closer to 0.3 V, again depending on current and temperature.

A Schottky diode may have a voltage drop between 0.2 and 0.3 V, so may be difficult to distinguish from a germanium diode.

If it measures 0.3 V, the diode is probably made of germanium, and is forward biased.

__

The reverse-biased voltage reading will generally match the open-circuit voltage of the testing device.

Answer: False

Explanation:The correct two parts of the SERVQUAL survey are as follows: Customer expectations. Customer perception.

A NAAQS exceedance refers to temporary levels exceeding the established standard, while a NAAQS violation indicates a persistent or recurring non-compliance with the standard.

NAAQS (National Ambient Air Quality Standard), set by regulatory agencies to protect public health and the environment, establish maximum allowable levels for pollutants in the ambient air. The terms "exceedance" and "violation" are used to describe different scenarios of non-compliance:

1. NAAQS Exceedance: A NAAQS exceedance refers to a temporary event where pollutant concentrations surpass the standard. It may occur due to short-term spikes in pollution levels caused by localized sources, unusual weather conditions, or specific events. Exceedances are typically evaluated and addressed on a case-by-case basis and may not immediately trigger regulatory actions.

2. NAAQS Violation: A NAAQS violation signifies a sustained or recurring non-compliance with the established standard. It occurs when pollutant levels consistently exceed the NAAQS over a specified timeframe, such as an averaging period (e.g., 24 hours or annual). Violations trigger regulatory consequences and the implementation of corrective measures, such as emission controls, enforcement actions, or mandated pollution reduction plans.

Differentiating between exceedances and violations is crucial in regulatory decision-making and prioritizing resources for air quality management. While exceedances may warrant investigation and localized actions, violations indicate the need for more significant and sustained efforts to achieve and maintain compliance with the NAAQS.

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Answer:

Bulk modulus: ß = - ∆p/(∆V/V)

∆p = (3039 - 1520)x10³ = 1519 kPa

∆V = 1231 - 1232 = -1 m³

V = 1232 m³

ß = - 1519/(-1/1232) = 1.87x10^6 kPa = 1.87 GPa

Explanation:

a.The average bulk modulus of elasticity of the liquid is 1.87 GPa

b. Coefficient of compressibility 0.5437 GPa-¹

c Velocity of sound 1.87 x 10^9P

a. Bulk modulus of elasticity

ß = - ∆p/(∆V/V)

First step  is to determine ∆p

∆p = (3039 kpa - 1520 kpa)x10³

∆p  = 1519 kPa

Second step is to determine ∆V

∆V = 1231 litres - 1232 litres

∆V = -1 m³

Now let determine the Bulk modulus of elasticity

Bulk modulus of elasticity= - 1519/(-1/1232)

Bulk modulus of elasticity= 1.87x10^6 kPa

Bulk modulus of elasticity= 1.87 GPa

b. The coefficient of compressibility

Coefficient of compressibility=β =1/K

Coefficient of compressibility=β =1/1.87

β =0.5437 GPa-¹

C. Velocity of sounds  in the medium with a density of 1593 kg/m3

V=√K/ρ

V=√1.87×10^9/ 1593

V=1083m/s

V = 1.87 x 10^9P

Inconclusion:

a.The average bulk modulus of elasticity of the liquid is 1.87 GPa

b. Coefficient of compressibility 0.5437 GPa-¹

c Velocity of sound 1.87 x 10^9P

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The economic advantage of selecting steel over aluminum is Rs. 246 - Rs. 217.25 = Rs. 28.75 per unit.

In the design of a jet engine part, the designer has a choice of specifying either an aluminium alloy casting or a steel casting. Either material will provide equal service, but the aluminium casting will weigh 1.2 kg as compared with 1.35 kg for the steel casting. The aluminium can be cast for Rs. 80.00 per kg. and the steel one for Rs. 35.00 per kg. The cost of machining per unit is Rs. 150.00 for aluminium and Rs. 170.00 for steel. Every kilogram of excess weight is associated with a penalty of Rs. 1,300 due to increased fuel consumption. Which material should be specified and what is the economic advantage of the selection per unit?The weight of the aluminum casting is 1.2 kg while the weight of the steel casting is 1.35 kg. Therefore, the weight of the aluminum casting is less than that of the steel casting.Cost of manufacturing per kg for aluminum = Rs. 80.00Cost of manufacturing per kg for steel = Rs. 35.00Cost of machining per unit of aluminum = Rs. 150.00Cost of machining per unit of steel = Rs. 170.00Now, let's calculate the cost of a unit of aluminum:Cost of casting = 1.2 x 80 = Rs. 96.00Cost of machining = Rs. 150.00Total cost of aluminum = Rs. 150 + Rs. 96 = Rs. 246.00Similarly, let's calculate the cost of a unit of steel:Cost of casting = 1.35 x 35 = Rs. 47.25Cost of machining = Rs. 170.00Total cost of steel = Rs. 170 + Rs. 47.25 = Rs. 217.25

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Since Technician A says that a steering column may be designed to absorb energy and Technician B says that vehicle seats may be designed to absorb energy. The both of them ( Tech A and B) are right.

The rod that the steering wheel is mounted to is known as the steering column of a vehicle. On a shaft inside the steering column, the steering wheel is mounted. The steering inputs are delivered to the steering rack or box by the steering column.

A shaft that passes through the steering column is used to link the steering wheel to the shaft.

Therefore, The purpose of bumper reinforcements, which are often made of highly strong materials like UHSS or aluminum, is to spread the crash energy.

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WiFi: The carrier frequency used for WiFi depends on the specific standard. The most commonly used WiFi standard, 802.11n/ac, operates in the 2.4 GHz and 5 GHz frequency bands. The corresponding quarter-wave lengths for these frequencies are approximately 31.25 cm and 14.5 cm, respectively.

Bluetooth: Bluetooth operates in the 2.4 GHz frequency band. The corresponding quarter-wave length is approximately 31.25 cmLTE cellular: LTE cellular networks utilize various frequency bands depending on the region and service provider. Common LTE frequency bands include 700 MHz, 850 MHz, 1800 MHz, 1900 MHz, 2100 MHz, and 2600 MHz. The corresponding quarter-wave lengths vary depending on the specific frequency bandGPS: GPS operates in the L1 band, which has a carrier frequency of approximately 1575.42 MHz. The corresponding quarter-wave length is approximately 4.77 cm WYKS 105.3 FM: WYKS 105.3 FM operates on a carrier frequency of 105.3 MHz. The corresponding quarter-wave length is approximately 71.4 cm.

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Using dividend discount model, the investor would place a valuation of $187.50 on the preferred stock.

To calculate the valuation of a preferred stock, we can use the dividend discount model (DDM) formula. The DDM values a stock based on the present value of its expected future dividends.

The formula for the valuation of a preferred stock is:

Valuation = Dividend / (Required Rate of Return - Dividend Growth Rate)

Given the following values:

Dividend = $15

Dividend Growth Rate = 2%

Required Rate of Return = 10%

Dividend Growth Rate = 2% = 0.02

Required Rate of Return = 10% = 0.10

Substituting these values into the formula:

Valuation = $15 / (0.10 - 0.02)

Valuation = $15 / 0.08

Valuation = $187.50

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The critical cooling rate of steels refers to the minimum rate at which a steel alloy must be cooled to achieve a fully martensitic structure during quenching. The addition of certain alloying elements can enhance the hardenability and reduce the critical cooling rate, allowing for the formation of martensite during quenching.

The critical cooling rate is influenced by several factors, including the chemical composition of the steel and the presence of alloying elements. The addition of alloying elements can significantly affect the critical cooling rate. Increasing the carbon content in steel increases the hardenability, which is the ability of the steel to form martensite upon quenching. Alloying elements such as chromium, molybdenum, and nickel can also enhance the hardenability of steel.

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Answer:

true

I hope it helps mate

I will always help you understanding your assingments

enjoy your day

#Captainpower:)

Note that  the magnitudes of the two forces are F1 = √6 N and F2 = 2 N.

Let F1 and F2 be the magnitudes of the two forces. If they act at right angles, their resultant R is given by:

R = √(F1^2 + F2^2)

If they act at 60 degrees, their resultant R' is given by:

R' = √(F1^2 + F2^2 + 2F1F2cos60°) = √(F1^2 + F2^2 + F1F2)

We can set up a system of equations to solve for F1 and F2:

√(F1^2 + F2^2) = √10 ...(1)

√(F1^2 + F2^2 + F1F2) = √13 ...(2)

Squaring both sides of equation (1), we get:

F1^2 + F2^2 = 10

Squaring both sides of equation (2), we get:

F1^2 + F2^2 + F1F2 = 13

Substituting F1^2 + F2^2 = 10 from equation (1), we get:

10 + F1F2 = 13

F1F2 = 3

Now, we can solve for F1 and F2 using the equations:

F1^2 + F2^2 = 10

F1F2 = 3

Multiplying the second equation by 4, we get:

4F1F2 = 12

Substituting F1F2 = 3, we get:

12 = 3(F1^2 + F2^2)

Simplifying, we get:

F1^2 + F2^2 = 4

Using this equation and F1F2 = 3, we can solve for F1 and F2:

F1^2 + F2^2 = 4

F1F2 = 3

Multiplying the first equation by F1F2, we get:

F1^2F2 + F1F2^2 = 12

Substituting F1F2 = 3, we get:

F1^2 + 3F2^2 = 12

Substituting F1^2 = 4 - F2^2 from the first equation, we get:

4 - F2^2 + 3F2^2 = 12

Simplifying, we get:

2F2^2 = 8

F2^2 = 4

F2 = 2

Substituting F2 = 2 in F1^2 + F2^2 = 10, we get:

F1^2 + 4 = 10

F1^2 = 6

F1 = √6

Therefore, the magnitudes of the two forces are F1 = √6 N and F2 = 2 N.

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Solution :

It is given that :

Thermal coefficient = 0.0045/K

Ambient temperature, \($T_a = 25 - 40^\circ$\)

air velocity, v = 0-5 m/s

Solar radiation, \($G= 400-100 \ W/m^2$\)

\($P=50 \ W$\)

Model calculations :

Cell temperature (\($T_c$\))

\($T_c = T_a + \left(\frac{0.25}{5.7+3.8 \ v_w}\right) G$\)

where \($ v_w - v_a = $\) wind speed / air speed

∴ \($T_c = 2 \pi + \left(\frac{0.25}{5.7+3.8 \times 1}\right) \times 400$\)

   \($T_c = 35.526 ^\circ$\)

\($\Delta T = T_c -25$\)

      = 35.526 - 25

      = 10.526 K

Thermal coefficient = 0.0045 x 10.526

                                = 0.04737

Pv power = \($(1 -C_T) \times P \times \frac{G}{1000}$\)

                \($=(1 -0.04737) \times 50 \times \frac{400}{1000}$\)

                = 17.0526 W

Answer:

To document your work and projects.

Explanation:

I hope I got the right meaning. :)

Answer:

a) specific work output of the actual turbine is 73.14 Btu/lbm

b) the amount of specific entropy generation during the irreversible process is 0.050416 Btu/lbm°R

c) Isentropic efficiency of the turbine is  70.76%

Explanation:

Given the data in the question;

For an adiabatic turbine; heat loss Q = 0

For Initial State;

p₁ = 120 psia

T₁ = 500°F = 959.67°R

from table; { Gas Properties of Air }

At T₁ = 959.67°R

\(s_1^0\) = 0.74102 Btu/lbm°R

\(h_1\) = 230.98 Btu/lbm

For Finial state;

p₂ = 15 psia

T₂ = 200°F = 659.67°R

\(s^0_{2a\) = 0.64889 Btu/lbm°R

\(h_{2a\) = 157.84 Btu/lbm

we know that R for air is 0.06855 Btu/lbm.R

a)

The specific work output of the actual turbine Wₐ is;

W\(_a\) = \(h_1\)  - \(h_{2a\)

we substitute

W\(_a\) = 230.98 - 157.84

W\(_a\) = 73.14 Btu/lbm

Therefore, specific work output of the actual turbine is 73.14 Btu/lbm

b)

amount of specific entropy generation during the irreversible process.

To determine the entropy generation \(S_{gen\);

\(S_{gen\) = ΔS = \(s_{2a\) - \(s_1\) =  \(s^0_{2a\)  - \(s_1^0\) - R ln(\(\frac{p_2}{p_1}\))

we substitute in our values

\(S_{gen\) = 0.64889 - 0.74102 - 0.06855 ln(\(\frac{15}{120}\))

\(S_{gen\) = 0.64889 - 0.74102 + 0.1425457

\(S_{gen\) = 0.050416 Btu/lbm°R

Therefore, the amount of specific entropy generation during the irreversible process is 0.050416 Btu/lbm°R

c)

Isentropic efficiency of turbine η\(_{is\)

η\(_{is\) = {actual work output] / [ ideal work output ] = (\(h_1\)  - \(h_{2a\) ) / ( \(h_1\)  - \(h_{2s\) )

Now, for an ideal turbine;

ΔS = 0 = \(s_{2s\) - \(s_1\)

so, \(s_{2s\) - s₁  = \(s^0_{2s\) - \(s_1^0\) - R ln(\(\frac{p_2}{p_1}\))

0 =  \(s^0_{2s\) - \(s_1^0\) - R ln(\(\frac{p_2}{p_1}\))

\(s^0_{2s\)  = \(s_1^0\) + R ln(\(\frac{p_2}{p_1}\))

we substitute

\(s^0_{2s\)  = 0.74102 + 0.06855 ln(\(\frac{15}{120}\))

\(s^0_{2s\)  = 0.74102 - 0.1425457

\(s^0_{2s\)  = 0.59847 Btu/lbm°R

Now, from table; { Gas Properties of Air }

At \(s^0_{2s\)  = 0.59847 Btu/lbm°R; \(h_{2s\)  = 127.614 Btu/lbm

η\(_{is\)  = [( \(h_1\)  - \(h_{2a\) ) / ( \(h_1\)  - \(h_{2s\)  )] × 100%

we substitute

η\(_{is\)  = [( 230.98 - 157.84 ) / ( 230.98 - 127.614 )] × 100%

η\(_{is\)  = [ 73.14 / 103.366] × 100%

η\(_{is\)  = 0.70758 × 100%

η\(_{is\)  = 70.76%

Therefore, Isentropic efficiency of the turbine is  70.76%

a. This is because an increase in pressure raises the boiling point of a substance by increasing the energy required for its molecules to overcome the external pressure and change from a liquid to a gas state.

b. The critical point represents the highest temperature and pressure at which a substance can exist as a distinct liquid and gas phase. The triple point, on the other hand, is the temperature and pressure at which the three phases (solid, liquid, and gas) of a substance coexist in equilibrium.

a. When pressure is increased, it compresses the gas phase and makes it more difficult for molecules to escape into the gas phase. This increases the energy required for the liquid to overcome the external pressure and change into a gas. As a result, the boiling point of water increases at higher pressures. For example, at sea level (normal atmospheric pressure), water boils at 100 degrees Celsius. However, if the pressure is increased, such as in a pressure cooker, the boiling point can rise above 100 degrees Celsius.

b. The critical point of a substance is the temperature and pressure at which the distinction between the liquid and gas phases disappears. At this point, the substance exhibits unique properties and is in a supercritical fluid state. The triple point, on the other hand, is the temperature and pressure at which the three phases (solid, liquid, and gas) of a substance coexist in equilibrium. It is the only combination of temperature and pressure at which all three phases can exist together. The triple point is used as a reference point in thermodynamics to define the temperature scale.

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This question is related to MySQL query and what results it can give.

MySQL provides information on the number of rows returned and the query's execution time, which helps you get a general sense of the server's performance.

Because they reflect wall clock time rather than CPU or machine time and are influenced by things like server load and network latency, these figures are not exact.

Based on Structured Query Language, MySQL is an open source relational database management system (RDBMS) sponsored by Oracle (SQL).Almost every platform, including Linux, UNIX, and Windows, supports MySQL.

Any command used to get data from a table in MySQL is known as a query. Querying, filtering, sorting, joining tables, grouping data, and editing data are all possible with MySQL.

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a) To determine X[k], the Discrete Fourier Transform (DFT) of x[n] = [0 1 2 0], we can use the Decimation in Time 4 point butterfly diagram.

Step 1: Calculate the butterfly outputs for the first stage:
- Apply the twiddle factor (W) to the second input: W^0 = 1
- Calculate the butterfly output for the first stage:
 - B0 = x[0] + W^0 * x[1] = 0 + 1 * 1 = 1
 - B1 = x[0] - W^0 * x[1] = 0 - 1 * 1 = -1
- Apply the twiddle factor (W) to the fourth input: W^0 = 1
- Calculate the butterfly output for the second stage:
 - B2 = x[2] + W^0 * x[3] = 2 + 1 * 0 = 2
 - B3 = x[2] - W^0 * x[3] = 2 - 1 * 0 = 2

Step 2: Calculate the butterfly outputs for the second stage:
- Apply the twiddle factor (W) to the second input: W^0 = 1
- Calculate the butterfly output for the third stage:
 - Y0 = B0 + W^0 * B2 = 1 + 1 * 2 = 3
 - Y2 = B0 - W^0 * B2 = 1 - 1 * 2 = -1
- Apply the twiddle factor (W) to the fourth input: W^0 = 1
- Calculate the butterfly output for the fourth stage:
 - Y1 = B1 + W^0 * B3 = -1 + 1 * 2 = 1
 - Y3 = B1 - W^0 * B3 = -1 - 1 * 2 = -3

Therefore, X[k] = [Y0, Y1, Y2, Y3] = [3, 1, -1, -3]

b) To validate the answer, we can compute the energy of the signal using x[n] and X[k].
Energy of the signal x[n]:
- Calculate the magnitude squared of each element:
 - |0|^2 = 0
 - |1|^2 = 1
 - |2|^2 = 4
 - |0|^2 = 0
- Sum up the squared magnitudes: 0 + 1 + 4 + 0 = 5

Energy of the DFT X[k]:
- Calculate the magnitude squared of each element:
 - |3|^2 = 9
 - |1|^2 = 1
 - |-1|^2 = 1
 - |-3|^2 = 9
- Sum up the squared magnitudes: 9 + 1 + 1 + 9 = 20

The energy of the signal x[n] is 5, while the energy of the DFT X[k] is 20, validating our answer.

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The elemental semiconductor germanium has  covalent type of bonding.

Germanium is an elemental semiconductor with a diamond crystal structure, where each atom forms covalent bonds with four neighboring atoms. This type of bonding is known as covalent bonding, where electrons are shared between atoms to form a strong bond. Germanium has four valence electrons, so each germanium atom shares one electron with each of its four neighboring germanium atoms to form a stable crystal lattice. This covalent bonding is responsible for the semiconducting properties of germanium, which makes it useful in electronic applications.

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Answer:

they are fictional characters featured in video games etc

Answer: Mario and Luigi are game characters, which feature in the Super Mario Maker series, the Paper Mario series, but most notably, the Super Mario Bros. series. Mario debuted in Donkey Kong (1981), while Luigi debuted in Mario Bros (1983, not to be confused with Super Mario Bros, which released two years after Mario Bros).

Answer:

an ability to identify, formulate, and solve engineering problems. an understanding of professional and ethical responsibility. an ability to communicate effectively. the broad education necessary to understand the impact of engineering solutions in a global, economic, environmental, and societal context

The sexagesimal system angles for 125 is 2.18 and for 12 is 0.209

What is the sexagesimal system?

We know that 180 = π

Therefore,

(i) 125  = 125 *  π / 180

                         = 125 * 22/ 7 * 180

                         = 2750 / 1260

                          = 2.18

(ii) 180 = π

12 = 12*  π /180

   = 12* 22/ 7 *  180

    = 264/ 1260

  = 0.209

Therefore, The sexagesimal system angle for 125 is 2.18 and for 12 is 0.209.

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Answer:

none

Explanation:

because it doesnt turn kinetic energy into electricity a

Kinetic energy turbines, also called free-flow turbines, generate electricity from the kinetic energy present in flowing water rather than the potential energy from the head. The systems can operate in rivers, man-made channels, tidal waters, or ocean currents. Because kinetic systems utilize a water stream's natural pathway, they do not require diversion of water through man-made channels, riverbeds, or pipes, although they might have applications in such conduits. Kinetic systems do not require large civil works because they can use existing structures, such as bridges, tailraces, and channels. so it doesnt

A crack in a brittle material adds a lot of stress to its tip. one way to prevent such a crack from progressing is to drill a hole. at the end of the crack to increase its radius and thus reduce the stress. fracture occurs in a brittle material when the stress concentration exceeds the reduction in strength of the material.

Brittle materials are characterized by low deformation, poor resistance to  impact and load-vibration, high compressive strength and low tensile strength. Most  inorganic non-metallic materials are brittle materials.

Brittle materials include glass, ceramics, graphite, and some alloys that have very low ductility and where cracks can form without plastic deformation and can soon develop into brittleness.

A material is considered brittle  when  it breaks under tension with little elastic deformation and no significant plastic deformation.

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