It is true that if the tank is a reusable tank, there are no check valves and system refrigerant can enter the tank as long as the system pressure is higher than the pressure in the tank.
A fundamental valve type dispersed generously all through a modern refrigeration framework is a manual shutoff valve. In the totally vacant position, this valve ought to permit a free progression of refrigerant and when shut totally block the stream. The standard capability of the shutoff valve is to confine a part or a segment of the framework.
Air conditioning Valves are such parts without which we have no control over stream in pipes .Valves are required for each medium whether it is water, gas, air or some other fluid. Valves would have been required for solids in the event that they could have capacity to stream. Like different regions, valves track down its broad use in air conditioning.
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What is the purpose of using an ammeter to demonstrate that a moving
magnet causes an electric current to flow in a wire coil?
A. It detects any current in the wire.
B. It protects the investigators from receiving an electric shock.
C. It increases the strength of the permanent magnet.
D. It takes the place of the battery needed for an electromagnet.
Answer: A
Explanation:
Answer:
The answer is A. It detects any current in the wire.
Explanation:
I took the quiz.
Why are protists difficult classify?
Answer:
Protists are difficult to characterize because of the great diversity of the kingdom. These organisms vary in body form, nutrition, and reproduction. They may be unicellular, colonial, or multicellular.
Answer:
There are many varying characteristics and exceptions to each type of protist.
They have been previously categorized based on what they are not
Recent studies show that protists have not descended from one common ancestor.
Explanation:
its right i took test :)
please help me with this physics problem
Answer:
It says the answer. (5 marks.)
Explanation:
The FitnessGram Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. A single lap should be completed each time you hear this sound. Remember to run in a straight line, and run as long as possible.
Conveyor belts are often used to move packages around warehouses. The conveyor shown below moves packages at a steady 4.0 m/s. A 500 N employee decides to catch a ride by sitting on a 1,000 N box for a 50 m trip as shown below:
What is the work done by the employee on the box?
Answer:
0 j
Explanation:
The work done by the employee on the box at the given zero displacement is 0 J.
The given parameters;
Constant velocity of the conveyor, v = 4 m/sWeight of the employee, W = 500 NWeight of the box, W = 1,000 NDistance of the trip, h = 50 mThe work done by the employee on the box is calculated as follows;
W = Fd
where;
F is the applied force on the box by employee = weight of the employeed is the distance through which the box is movedSince the employee sits on the box without moving it, the distance moved by the box = 0
W = 500 x 0
W = 0 J
Thus, the work done by the employee on the box is 0 J.
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One litre of oxygem combines with one litre of hydrogen to produce one litre of hydrogen
peroxide.Given that the molecules of oxygen and hydrogen contain two atoms each, determine the
number of atoms in a molecule of hydrogen peroxide. Show your work.
The molecule of hydrogen peroxide contains four atoms.
Number of atoms calculation.The chemical equation for the reaction between oxygen and hydrogen to form hydrogen peroxide is:
O2 + 2H2 → 2H2O2
This equation shows that one molecule of oxygen (O2) reacts with two molecules of hydrogen (H2) to produce two molecules of hydrogen peroxide (H2O2).
We are given that one liter of oxygen (O2) combines with one liter of hydrogen (H2) to produce one liter of hydrogen peroxide (H2O2). Since one mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters, we can assume that one mole of oxygen (O2) reacts with one mole of hydrogen (H2) to produce one mole of hydrogen peroxide (H2O2) at STP.
Using Avogadro's number (6.022 x 10^23), we can calculate the number of molecules of each substance in one mole:
Oxygen (O2): 1 mole = 6.022 x 10^23 molecules
Hydrogen (H2): 1 mole = 6.022 x 10^23 molecules
Hydrogen peroxide (H2O2): 1 mole = 6.022 x 10^23 molecules
From the balanced chemical equation, we know that two molecules of hydrogen peroxide (H2O2) are produced for every one molecule of oxygen (O2) that reacts. Therefore, the number of molecules of hydrogen peroxide (H2O2) produced is equal to the number of molecules of oxygen (O2) that react.
Since we are given that one liter of oxygen (O2) reacts with one liter of hydrogen (H2) to produce one liter of hydrogen peroxide (H2O2), we can say that the volumes of the gases are proportional to their number of molecules. Therefore, the number of molecules of hydrogen peroxide (H2O2) produced is also equal to the number of molecules of hydrogen (H2) that react.
So, we can start with one mole of hydrogen (H2) and use the balanced chemical equation to find the number of moles of hydrogen peroxide (H2O2) produced:
1 mole H2 → 2 moles H2O2
Since one molecule of hydrogen peroxide (H2O2) contains two hydrogen atoms and two oxygen atoms, we can find the total number of atoms in a molecule of hydrogen peroxide:
2 hydrogen atoms + 2 oxygen atoms = 4 atoms
Therefore, a molecule of hydrogen peroxide contains four atoms.
In summary:
The chemical equation for the reaction between oxygen and hydrogen to form hydrogen peroxide is: O2 + 2H2 → 2H2O2
One mole of oxygen (O2) reacts with two moles of hydrogen (H2) to produce two moles of hydrogen peroxide (H2O2).One liter of oxygen (O2) reacts with one liter of hydrogen (H2) to produce one liter of hydrogen peroxide (H2O2).Using Avogadro's number, we can calculate the number of molecules of each substance in one mole.Since the number of molecules of hydrogen peroxide (H2O2) produced is equal to the number of molecules of hydrogen (H2) that react, we can find the number of atoms in a molecule of hydrogen peroxide by considering the atoms in a molecule of hydrogen. Therefore, a molecule of hydrogen peroxide contains four atoms (two hydrogen atoms and two oxygen atoms).
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which of the following describe potential energy?? A. Energy of Motion B. Energy of Change C. Energy of Mass D. Stored Energy
Answer:
D. Stored Energy
Explanation:
Think of it this way, potential energy is the energy dependant on the objects position (PE=mgh). Say you are on a diving board (my fave example), when you are standing on the edge about to jump you have the potential to fall or move because you can go from a) the top to b) the pool. When you are in the pool you're already there, so there is no more potential. Remember that, once you jump, you have kinetic energy (KE=1/2mv^2), or the energy of motion and no longer PE.
An object is 70 micrometer long and 47.66 micrometer wide. How long and wide is the object in km
Answer:
The length of the object in kilometer (km) is 70 x 10⁻⁹ km
The width of the object in kilometers (km) is 47.66 x 10⁻⁹ km
Explanation:
Given;
length of the object = 70 micrometer = 70 μm
the width of the object = 47.66 micrometer = 47.66 μm
The length of the object in meter:
70 micrometer = 70 μm = 70 x 10⁻⁶ m
The length of the object in kilometer (km):
70 x 10⁻⁶ m = 70 x 10⁻⁹ km
The width of the object in meters:
47.66 micrometer = 47.66 μm = 47.66 x 10⁻⁶ m
The width of the object in kilometers (km):
47.66 x 10⁻⁶ m = 47.66 x 10⁻⁹ km
The musician from the previous question runs at you with a velocity of 10 m/s. What frequency do you hear?
The previous question:
A frantic musician runs at you while holding a detuned guitar and accidentally plucks the 6th string of their guitar. What is the unfretted pitch and frequency (to the nearest integer) of the string when it is plucked?
Answer: E2 - 82 Hz
Consider the system of two blocks shown in Fig. P6.81, but with a different friction force on the 8.00 kg block. The blocks are released from rest. While the two blocks are moving, the tension in the light rope that connects them is 37.0 N. (a) During a 0.800 m downward displacement of the 6.00 kg block, how much work has been done on it by gravity? By the tension T in the rope? Use the work–energy theorem to find the speed of the 6.00 kg block after it has descended 0.800 m. (b) During the 0.800 m displacement of the 6.00 kg block, what is the total work done on the 8.00 kg block? During this motion how much work was done on the 8.00 kg block by the tension T in the cord? By the friction force exerted on the 8.00 kg block? (c) If the work–energy theorem is applied to the two blocks con- sidered together as a composite system, use the theorem to find the net work done on the system during the 0.800 m downward displacement of the 6.00 kg block. How much work was done on the system of two blocks by gravity? By friction? By the tension in the rope?
a) The speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.
b) We cannot calculate the work done by the friction force.
c) The net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.
(a) The work done on the 6.00 kg block by gravity can be calculated using the formula:
Work_gravity = force_gravity * displacement * cos(theta),
where force_gravity is the weight of the block, displacement is the downward displacement of the block, and theta is the angle between the force and displacement vectors (which is 0 degrees in this case).
The weight of the block is given by:
force_gravity = mass * acceleration_due_to_gravity = 6.00 kg * 9.8 m/s^2 = 58.8 N.
Plugging in the values, we get:
Work_gravity = 58.8 N * 0.800 m * cos(0) = 47.04 J.
The work done on the 6.00 kg block by the tension in the rope is given by:
Work_tension = tension * displacement * cos(theta).
Plugging in the values, we get:
Work_tension = 37.0 N * 0.800 m * cos(180) = -29.6 J.
The negative sign indicates that the tension is in the opposite direction of the displacement.
Using the work-energy theorem, we can find the speed of the 6.00 kg block after descending 0.800 m:
Work_net = change_in_kinetic_energy.
Since the block starts from rest, its initial kinetic energy is zero. Therefore:
Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * mass * velocity^2.
Solving for velocity, we get:
velocity = sqrt(2 * Work_net / mass).
The net work done on the block is the sum of the work done by gravity and the tension:
Work_net = Work_gravity + Work_tension = 47.04 J - 29.6 J = 17.44 J.
Plugging in the values, we get:
velocity = sqrt(2 * 17.44 J / 6.00 kg) = 2.07 m/s.
Therefore, the speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.
(b) The total work done on the 8.00 kg block during the 0.800 m displacement can be calculated using the work-energy theorem:
Work_net = change_in_kinetic_energy.
Since the 8.00 kg block is not moving vertically, its initial and final kinetic energies are zero. Therefore:
Work_net = Final_kinetic_energy - Initial_kinetic_energy = 0.
The work done on the 8.00 kg block by the tension in the rope is given by:
Work_tension = tension * displacement * cos(theta).
Plugging in the values, we get:
Work_tension = 37.0 N * 0.800 m * cos(0) = 29.6 J.
The work done on the 8.00 kg block by the friction force can be calculated using the formula:
Work_friction = force_friction * displacement * cos(theta),
where force_friction is the frictional force on the block. However, the problem statement does not provide the value of the friction force. Therefore, we cannot calculate the work done by the friction force.
(c) The net work done on the system of two blocks during the 0.800 m displacement of the 6.00 kg block can be found using the work-energy theorem:
Work_net = change_in_kinetic_energy.
Since the system starts from rest, the initial kinetic energy of the system is zero. Therefore:
Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * (6.00 kg + 8.00 kg) * velocity^2.
Simplifying, we get:
Work_net = 1/2 * 14.00 kg * velocity^2.
Using the value of velocity calculated in part (a), we get:
Work_net = 1/2 * 14.00 kg * (2.07 m/s)^2 = 29.13 J.
The work done on the system of two blocks by gravity is the sum of the work done on the individual blocks by gravity:
Work_gravity_system = Work_gravity_6kg + Work_gravity_8kg = 47.04 J + 0 J = 47.04 J.
The work done on the system of two blocks by the tension in the rope is the sum of the work done on the individual blocks by the tension:
Work_tension_system = Work_tension_6kg + Work_tension_8kg = -29.6 J + 29.6 J = 0 J.
Therefore, the net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.
Note: The calculations for part (b) and (c) were based on the given information, but the value of the friction force was not provided in the problem statement.
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why the deflection layer is narrow and the current is large in forward bias
This is because the depletion zone has very high resistance since it lacks free charge carriers.
What are voltage and current?Simply put, voltage—also known as electromotive force—is the amount of energy in one charge. Voltage, then, is the variation in electric potential between two places. Simply put, current is the pace at which electric charge flows.
What would you say about electric current?Electric current is a term used to describe how much electricity flows across a circuit and how it flows in an electronic circuit. Amperes are used to measure it (A). The more electricity flowing across the circuit, the higher the ampere value.
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A tennis ball with a mass of 51g has a sig what is the kinetic energy of velocity of 9.7m/s, the tennis ball?
Answer:
2399.295
Explanation:
kinetic energy= \(\frac{1}{2}\)mv² (m stands for mass and v for velocity)
= \(\frac{1}{2}\)×51×9.7²
=2399.295 J
2.A man drags a 100 kg crate up the ramp of a truck. The ramp is inclined at 20° and the
man pulls at an angle of 30° above the ramp. The coefficient of friction between the crate
and the ramp is 0.2.
a) What is the normal force on the crate in terms of the applied force, F? (Hint: The
normal force does not just balance the perpendicular component of gravity)
b) What is the minimum force the man would have to apply to pull the crate up the ramp
(Hint: minimum force would be the force required to pull the crate up the ramp at
constant velocity)
a ) The normal force on the crate in terms of the F = 921.2 - 0.5 F N
b ) The minimum force the man would have to apply to pull the crate up the ramp = 533.44 N
W = m g
m = 100 kg
g = 9.8 m / s²
W = 100 * 9.8
W = 980 N
Resolving the force of gravity into its horizontal and vertical components,
Wx = W sin θ
Wx = 980 * sin 20°
Wx = 333.2 N
Wy = W cos θ
Wy = 980 * cos 20°
Wy = 921.2 N
Resolving F into its vertical and horizontal components,
Fx = F cos θ
Fx = F cos 30°
Fx = 0.87 F N
Fy = F sin θ
Fy = F sin 30°
Fy = 0.5 F N
Since there is no acceleration in y-direction,
N - Wy + Fy = 0
N = 921.2 - 0.5 F
Ff = μ N
If the crate is being pulled with the minimum force, velocity would be constant. So acceleration will be zero.
∑ \(F_{x}\) = 0
Fx - Ff - Wx = 0
0.87 F - 0.2 ( 921.2 - 0.5 F ) - 333.2 = 0
0.87 F - 184.24 + 0.1 F - 333.2 = 0
0.97 F = 517.44
F = 533.44 N
Therefore,
a ) The normal force on the crate in terms of the F = 921.2 - 0.5 F N
b ) The minimum force the man would have to apply to pull the crate up the ramp = 533.44 N
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3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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Why is the Falcon 9 rocket so important in today's space exploration world?
It's the first rocket to have been built by robots, saving money for labor costs.
Carbon fiber is used on the outside, making it much more lightweight, requiring less fuel to launch it.
It was invented with the ability to recharge itself by using solar panels.
It's a reusable rocket and has saved money by being reused over 60 times already.
The Falcon 9 rocket is so important in today's space exploration world because It's a reusable rocket and has saved money by being reused over 60 times already.
option D.
Why is the Falcon 9 rocket so important in today's space exploration world?The Falcon 9 rocket, is developed by SpaceX, and it holds a significant importance in today's space exploration world due to several key features and achievements, and some of the importance include the following;
ReusabilityCost-effectivenessAdvancements in rocket technologyPayload capacity and versatilityInnovation and competitionFrom the given options, we can conclude that the Falcon 9 rocket is so important in today's space exploration world because It's a reusable rocket and has saved money by being reused over 60 times already.
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If an electron vibrates up and down 1000 times each second, it generates an electromagnetic wave having aa. wavelength of 1000 mb. frequency of 1000 Hzc. speed of 1000 m/sd. period of 1000 s
The correct answer is frequency of 1000 Hz. The frequency of an electromagnetic wave is determined by the number of times the electron oscillates in a given amount of time.
What is electromagnetic wave?An electromagnetic wave is a type of energy wave that is composed of electric and magnetic fields and propagates through space. Electromagnetic waves are created when an electric field couples with a magnetic field. This happens when a charged particle accelerates, causing a disturbance in the electric and magnetic fields. Electromagnetic waves can be described in terms of their frequency, which is the number of times the wave oscillates per second, and their wavelength, which is the distance between two successive peaks of the wave. The frequency and wavelength of an electromagnetic wave determine its type. Different types of electromagnetic waves include radio waves, microwaves, infrared waves, ultraviolet waves, x-rays, and gamma rays.
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Electricity is the result of moving electrons, so it's classified as
A. Kinetic Energy
B. Gravitational Energy
C. Potential Energy
D. Elastic Energy
Can you help with this question please
Answer:
First answer to the first question is Two people pulling a rope with the same force in a opposite direction. The other one would be 2.72N
Explanation:
Hope this helps you :)
What is sound waves
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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Applying an AC voltage v = V√2 cos(ωt) (where V and ω are constants) to the two ends of the circuit AB connected in series, which includes a variable inductor with self-inductance L, a resistor with resistance R, and a capacitor with capacitance C. Let vₗ and Vₗ be the instantaneous voltage and the effective voltage across L, respectively. When L = L₁, Vₗ = V₁, and vₗ leads v by an angle β₁. When L = L₂, Vₗ = V₂, and v₂ leads v by an angle β₂. When L = L₀, Vₗ is maximum and equal to Vₗₘₐₓ, and vₗ leads v by an angle β₀. If V₁ = V₂ = b and sinβ₁ + sinβ₂ = b/Vₗₘₐₓ, then what is sinβ₀?
When L = L₁, the circuit is a series RL circuit. The voltage across the inductor is given by Vₗ = XL₁i, where XL₁ = ωL₁ is the inductive reactance and i is the current flowing through the circuit. The voltage across the resistor is given by VR = Ri. The voltage across the capacitor is zero since it is connected in series with the inductor and the resistor.
The total voltage across the circuit is given by v = V√2 cos(ωt). By Kirchhoff's voltage law, we have v = Vₗ + VR,
V√2 cos(ωt) = XL₁i + Ri
The current i can be written as i = (1/Z) V√2 cos(ωt - φ), where Z = √(R² + XL₁²) is the impedance of the circuit and φ is the phase angle between the current and the voltage. Substituting i into the equation above, we get:
V√2 cos(ωt) = XL₁/Z V√2 cos(ωt - φ) + R/Z V√2 cos(ωt - φ)
Equating the coefficients of cos(ωt) and cos(ωt - φ), we get:
1 = XL₁/Z cos φ + R/Z sin φ
XL₁ sin φ = Z - R cos φ
tan φ = XL₁ / (Z - R cos φ)
The voltage across the inductor is given by:
Vₗ = XL₁ i = XL₁/Z V√2 cos(ωt - φ)
Vₗ/V = XL₁/Z cos φ
Substituting tan φ into this equation, we get:
Vₗ/V₁ = XL₁/Z₁ √[1 - (XL₁/Z₁)²] ... (1)
When L = L₂, the circuit is a series RC circuit. The voltage across the capacitor is given by VC = XC₂i, where XC₂ = 1/(ωC₂) is the capacitive reactance. The total voltage across the circuit is given by v = V√2 cos(ωt). By Kirchhoff's voltage law, we have v = VC + VR, which gives:
V√2 cos(ωt) = XC₂i + Ri
Following the same steps as in the previous case, we can show that:
Vₗ/V₂ = XC₂/Z₂ √[1 - (XC₂/Z₂)²] ... (2)
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A player kicks a soccer ball.
What is the reaction force?
A. The ball pushes back on the player's
foot.
B. The ground pushes back on the player.
C. The ground pushes back on the ball.
Answer:
the ground pushes back on the player
Answer:
c
Explanation:
force is every where so anything that goes up must come down
A sample of an unknown gas begins at a temperature of 320.0 K, a pressure of 4.00´105 Pa, and a volume of 2.00 L
(recall 1 L = 10-3 m3). The gas then undergoes the following cyclic process.
i) The gas expands adiabatically to a volume of 10.0 L doing 1030 J of work. In this process the temperature of the gas decreases to 202K.
ii) The gas is compressed isothermally until the pressure returns to 4.00´105 Pa.
iii) The gas is returned to its initial volume isobarically.
Assume that for the range of temperatures given, the gas obeys the ideal gas law.
(a) (6 pts) Draw a PV diagram for this cycle.
(b) (4 pts) Determine the molar heat capacity at constant volume of the gas. Hint: There is enough information given for the adiabatic expansion to find this. Also, you can answer parts (c)-(g) below without answering this part.
(c) (4 pts) Determine the work done by the gas in the isothermal and isobaric steps.
(d) (6 pts) Determine the change in internal energy in each step.
(e) (6 pts) Determine the heat absorbed by the gas in each step.
(f) (4 pts) Can this process be used as a heat engine? If so, what is its efficiency? Compare your answer to the efficiency of a Carnot engine operating between the same highest and lowest temperatures. Does this violate the Second Law of Thermodynamics?
(g) (2 pts) Can this cycle be used as a refrigerator? If so, what is its coefficient of performance?
(a) Cycle consists of an adiabatic expansion (1-2), (b) 20.8 J/molK (c) -3.20×10³ J (d) 4900 J.
Describe Thermodynamics?Thermodynamics is a branch of physics that deals with the relationships between heat, work, and energy in systems that undergo changes in temperature, pressure, and other variables. The subject has its roots in the study of heat engines and the optimization of their performance, but it has since grown to encompass a wide range of phenomena, including chemical reactions, phase transitions, and the behavior of materials under extreme conditions.
(a) The cycle consists of an adiabatic expansion (1-2), an isothermal compression (2-3), and an isobaric compression (3-1).
(b) Since the adiabatic expansion is reversible and adiabatic, we can use the relation:
Cv = (γ / (γ-1)) R
where γ = Cp / Cv is the ratio of specific heats, R is the gas constant, and Cv is the molar heat capacity at constant volume. We know that the gas obeys the ideal gas law, so we can use PV = nRT to find the initial number of moles n, and then use the work done during the adiabatic expansion to find γ:
γ = 1 + (Cp / Cv) = 1 + (2/3) = 5/3
Then, we can find Cv:
Cv = (γ / (γ-1)) R = (5/3) * (8.31 J/molK) / (2/3) = 20.8 J/molK
(c) The work done by the gas in the isothermal step (2-3) is:
W23 = -nRT ln(V3/V2)
where V2 = 10 L, V3 = 2 L, and T = 202 K. We can use the ideal gas law to find the final number of moles n:
n = PV / RT = (4.00×10⁵ Pa) * (2.00×10⁻³ m³) / (8.31 J/mol*K * 320.0 K) = 3.08 mol
Then, we can find the work done:
W23 = -nRT ln(V3/V2) = -(3.08 mol) * (8.31 J/mol*K) * (202 K) * ln(2/10) = 1730 J
The work done by the gas in the isobaric step (3-1) is:
W31 = -PΔV = -(4.00×10⁵ Pa) * (10.0×10⁻³ m³ - 2.00×10⁻³ m³) = -3.20×10³ J
(d) The change in internal energy of the gas in each step can be found using the first law of thermodynamics:
ΔU = Q - W
where Q is the heat absorbed by the gas and W is the work done by the gas.
For the adiabatic step (1-2), we have ΔU12 = -W12 = -1030 J, since Q12 = 0.
For the isothermal step (2-3), we have ΔU23 = 0, since the temperature is constant and therefore there is no change in internal energy.
For the isobaric step (3-1), we have ΔU31 = Q31 - W31. Since the process is isobaric, the heat absorbed by the gas is simply the product of the pressure, volume change, and molar heat capacity at constant pressure Cp:
Q31 = nCpΔT = nCvΔT + nRΔT = (3.08 mol) * (20.8 J/molK) * (320.0 - 202.0) K + (3.08 mol) * (8.31 J/molK) * (320.0 - 202.0) K = 4900 J
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Does light travel faster in seawater or in fresh water? Does light travel faster in seawater or in fresh water? Light travels faster in seawater, because the index of refraction is smaller in seawater. Light travels faster in fresh water, because the index of refraction is smaller in fresh water. Light travels faster in fresh water, because the index of refraction is larger in fresh water. Light travels faster in seawater, because the index of refraction is larger in seawater.
No
because that is a light
The light travel faster in fresh water as compare to sea water.
When light goes from denser to rare medium the speed of light is increases.When light travel from rare to denser medium the speed of light is decreases.The reflective index of denser medium is more as compare to rare medium.The reflective index of sea water is more as compare to fresh water.Hence, the light travel faster in fresh water as compare to sea water.
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If a nucleus had a diameter of 8.0 fm, what would be its expected mass, in atomic mass units?
The atomic mass unit is 37.04unit
The size of a nexus is generally expressed in terms of its compass, not periphery. The compass of a nexus is related to its mass number( A) by a general empirical formula known as the" nuclear compass formula"
\(R = R_o(A\frac{1}{3}) ,\)
where R is the compass of the nexus,
R ₀ is a constant( roughly1.2 fm),
and A is the mass number.
To determine the anticipated mass of the nexus in infinitesimal mass units( u), we can use the following equation
Mass = A × mass of a single nucleon,
where the mass of a single nucleon is roughly 1 infinitesimal mass unit( 1 u).
Given that the periphery of the nexus is8.0 fm, we can calculate the compass
R = \(\frac{8.0fm}{4.0}\)= 4.0 fm.
Now, we can use the nuclear compass formula to estimate the mass number( A)
fm = R ₀ A(1/3).
By rearranging the formula and working for A,
we have A = ((4.0 fm/ R ₀))
Substituting the value of R ₀( roughly1.2 fm) into the equation
A = ((4.0 fm/1.2 fm))
A ≈(3.33) 3
A ≈37.04.
Thus, the anticipated mass of the nexus in infinitesimal mass units would be roughly37.04u.
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A phase change is when a substance changes from one state of mind to nother because of the adding or removal of thermal energy
True
False
Answer:
true it all changes
Explanation:
________________________
8. The Earth orbits the Sun at a distance of 1.46x1011 m from center to center. What is the strength of the Sun’s gravitational field at this distance?
The strength of the Sun's gravitational field at this distance is \(0.622m/s^2\)
What is Gravitational field?A gravitational field is defined as the model used to explain the effects that a massive body exerts in the space around it exerts a force on another massive body. Therefore, a gravitational field is used to explain gravitational phenomena, and it is measured in newtons per kilogram.
The acceleration due to gravity on the surface of the earth is given by;
\(g = GM/R^2\)
Where, g is the acceleration due to gravity
G is Gravitational constant \((6.673 * 10^-^1^1 Nm^2 kg^-^2)\)
M is the mass of the planet \((1.99* 10^3^0 kg)\)
R is the radius of planet
So, for above given information, \(g= \frac{6.022 * 10^-^1^1* 1.99* 10^-^3^0}{(1.46* 10^1^1)^2}\)= \(0.622m/s^2\)
Thus, the strength of the Sun's gravitational field at this distance is \(0.622m/s^2\).
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A rigid body is rotating with constant angular speed 3 radians per second about a fixed axis through the points A. (4, 1, 1), B. (2, -1; 0), distances being measured in centimeters. The rotation is in the left-handed sense relative to the direction AB
1, Determine the unit vector pointing in the direction BA.
2, What is the angular velocity () of the of the body?
3, Write the position vector of point P: P .
Find the instantaneous velocity of particle P [hint v = w×r)
4, What is meant by left-handed rotation (left-handed coordinate system)?
5, Write the position vectors of points A and B The rotation axis AB has direction BA. Write the direction BA in terms of the components given above.
1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.
5.Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA = (-2, -2, -1)
1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.
The direction vector BA is given by:
BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)
To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:
|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3
Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.
5.The position vectors of points A and B are:
Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:
BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)
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In which quadrant will the sun set may 15 for places in the northern hemisphere?A.NEB.NWC.SED.SW
Since may 15 is after the spring equinox (march 21) but before the autum equinox (september 22), then the Sun will set in the northern celestial hemisphere. Since the sun sets by the west, then on may 15 it will set in the northwestern quadrant.
Therefore, the answer is:
\(B\text{. NW}\)How does the Law of Conservation of Matter apply to you when you eat food? Why do you not continuously gain exactly the amount of mass you consume with each meal? Help meh explain this!
Explanation:
You cannot gain exact amount of mass you consume because some of the food particles will trap in the mouth or teeth
And some food will not digest ex fiber
And some food particles will stay in the plate
When one eats food, some of the food is excreted in solid form or in its liquid form; As such, it is impossible to gain exactly the amount of mass consumed.
The law of conservation of mass states that matter can neither be created nor destroyed by chemical reactions or physical transformations.
On this basis; it is impossible to gain exactly the amount of mass one consumes with each meal because some of the food consumed are given off and are therefore responsible for the deficit in mass gain.
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Given the following data, determine how long it will take your space ship
to travel from Earth to Mars in years.
Distance from Earth to Sun: 150,000,000 km
Distance from Mars to Sun: 230,000,000 km
Maximum Speed of ship: 3,050 km/hr
365 days/year
24 hours/day
It will take our ship 3 year to travel from Earth to Mars if the speed is 3,050 km/hr.
What is speed?The distance travelled per unit of time is most commonly known as speed. It describes how quickly an object moves. The magnitude of the velocity vector is represented by speed, which is a scalar quantity. It's aimless. A faster moving object has a higher speed. It is moving slower if it has a lower speed. It has no speed if it is not moving at all.
The following formula is used to calculate the constant velocity of an object moving in a straight line:
S = d / t
Distance from Earth to Mars = Distance from Mars to Sun - Distance from Earth to Sun
Distance from Earth to Mars = 230,000,000 km - 150,000,000 km
= 2.3 × 10⁸ - 1.5 × 10⁸
= (2.3-1.5) × 10⁸
= 0.8 × 10⁸
= 8 × 10⁷ km
Time = Distance ÷ Speed
Given speed = 3,050 km/hr
Distance = 8 × 10⁷ km
Putting the values,
Time = 80,000,000 ÷ 3,050
Time = 26229.51
24 hours a day, so
26229.51/24
= 1092.9
365 days a year, so
1092.9/365
= 2.99 ≈ 3 years
Thus, It will take our ship 3 year to travel from Earth to Mars if the speed is 3,050 km/hr.
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How much mechanical work is required to catch a 14.715N ball traveling at a velocity of 37.5m/s?
To catch a 14.715N ball traveling at a velocity of 37.5m/s, required mechanical work is 1056.10 joule.
What is work?Physics' definition of work makes clear how it is related to energy: anytime work is performed, energy is transferred.
In a scientific sense, a work requires the application of a force and a displacement in the force's direction. Given this, we can state that
Work is the product of the component of the force acting in the displacement's direction and its magnitude.
Weight of the ball = 14.715 N.
Mass of the ball = 14.715 N ÷ (9.8 m/s²) = 1.502 kg.
Velocity of the ball = 37.5 m/s
Kinetic energy of the ball = 1/2 × 1.502 × 37.5² Joule = 1056.10 Joule.
Hence, to catch a 14.715N ball traveling at a velocity of 37.5m/s, required work is 1056.10 joule.
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